Answer:
Critical Flaw Length=17.08 mm
The Critical flaw Length > 4mm, It means it is detectable.
Explanation:
Given Data:
Fracture Toughness=[tex]K_{tc}[/tex]=88MPa
Yield Strength=σ=710 MPa
Y=1.07
Solution:
Formula:
[tex]Critical\ Length=\frac{1}{\pi } *(\frac{K_{tc}}{Y*\sigma} )^2[/tex]
Since yield Strength is half, Critical Length will be:
[tex]Critical\ Length=\frac{1}{\pi } *(\frac{K_{tc}}{\frac{\sigma}{2} *Y} )^2\\Critical\ Length=\frac{1}{\pi } *(\frac{88MPa}{\frac{710MPa}{2} *1.07} )^2\\\\Critical\ Length=0.01708\ m[/tex]
Critical Flaw Length=17.08 mm
The Critical flaw Length > 4mm, It means it is detectable.
Guess the output of this code: print( (3**2)//2)
the answer is 2
kids simple just multiply 3 by 2 which gets the answer as 6 then divide 6 by 2 then it comes to again 2 and that is a simple answer...
The output of the given code, i.e., print( (3**2)//2) will be 4.
What is coding?Coding, also known as computer programming, is the method by which we communicate with computers.
Code tells a computer what to do, and writing code is similar to writing a set of instructions. You can tell computers what to do or how to behave much more quickly if you learn to write code.
When you choose an instructional programming language, coding is simple to learn. It can be difficult to learn to code if you begin with a more complex coding language.
The ** operator is used to multiply a number by a power.
The // operator calculates how many times the right number can fit into the left.
Here it is given that
[tex]print(3^2)/2[/tex]
So, the round division will be 4.
Thus, the output will be 4.
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If a soil has e=0.72, moisture content = 12% and Gs=2.72, find the weight of water in KN/m3 to be added to make the soil saturated.
Answer:
453 KN/m^3 of water should be added make the soil saturated.
Explanation:
As we know
Gs * w = S*e
S = Gs * w/e
S = 2.72 * 0.12/0.72 = 0.453
The amount of water to be added
0.453 *1000/10 = 453 KN/m^3
A piece of corroded steel plate was found in a submerged ocean vessel. It was estimated that the original area of the plate was 5 in.2 and that approximately 2.3 kg had corroded away during the submersion. Assuming a corrosion penetration rate of 200 mpy for this alloy in seawater, estimate the time of submersion in years. The density of steel is 7.9 g/cm3.
Answer:
the estimated time of submersion is 17.7 years
Explanation:
Given the data in the question;
estimate the time of submersion in years.
we write down the relation between time of submersion and corrosion penetration as follows;
CPR(mpy) = K × W(mg) / [ A(in²) × p(g/cm³) × t(hr) ]
we solve for t
t = (K × W) / ( AP × CPR )
given that;
Area A = 5 in²
W = 2.3 kg = 2.3 × 10⁶ mg
density of steel p = 7.9 g/cm³
CPR = 200
we know that K is 534
so we substitute
t = (534 × 2.3 × 10⁶ mg) / ( 5 in² × 7.9 g/cm³ × 200 mpy )
t = 1,228,200,000 / 7900
t = 155468.3544 hr
t = 155468.3544 hr × ( 1 yrs / ( 365 × 24 hrs )
t = 17.7 years
Therefore, the estimated time of submersion is 17.7 years
"Como define al ser Humano, la Religión, la biología y la filosofía." y es religion Y urgenteeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeee
Explanation:
Los seres humanos siempre han tenido la necesidad de explicar y comprender los hechos sobre el mundo, ellos mismos y la naturaleza. La religión se configura como un conjunto de creencias comunes a una comunidad, que busca conectar al hombre con una fe en una divinidad superior que explique una visión y construcción del mundo. En sentido antropológico, la religión es una construcción evolutiva de parámetros sociales y dogmáticos como búsqueda de la creación de un sentido de pertenencia social, además de la búsqueda de la comprensión de uno mismo y del desarrollo espiritual.
La biología y la filosofía surgen como conceptos amplios que buscan explicar otros conceptos sobre la ciencia de manera sistemática, diferente a buscar una comprensión del mundo a través de la religión. La filosofía como concepto de que el hombre puede comprender el mundo a través de sus propias visiones y descubrimientos, desarrollando el pensamiento crítico y la búsqueda del conocimiento, que desarrolló las ciencias, entre ellas la biología que ayudó en la comprensión de parámetros esenciales para la calidad de vida humana, como la medicina por ejemplo.
Entonces hay una convergencia de los conceptos de religión, biología y filosofía, y es posible que el hombre crea en cada uno sin que el otro concepto se vea afectado.
What's a major difference between a construction drawing and a schematic diagram
Answer:
Explanation:
When used as nouns, schematic diagram means a plan, drawing, sketch or outline to show how something works, or show the relationships between the parts of a whole, whereas schematic means a simplified line-drawing generally used by engineers and technicians to describe and understand how a system works at an abstract level.
Hope this helped!!!
The 150 mm thick wall of a gas fired furnace is constructed of fireclay brick (k=1.5 W/m.K) , tho=2600 kg/m3, and cp=1000 J/kg.K ) and is well insulated at its outer surface. The wall is at a uniform initial temperature of 20 degree C, when the burners are fired and inner surface is exposed to products of combustion for which T infinity=950 degree C and h=100 W/ m2.K.
(A) How long does it take for the outer surface of the wall to reach a temperature of 750 degree C?
(B) plot the temperature distribution in the wall at the foregoing time.
Answer:
I am thick but I dont know the anwser
The time that it will take for the outer surface of the wall to reach a temperature of 750 degree C will be 33800 seconds.
How to calculate the time?Using the approximation methods, Fo will be;
= In(0.215/1.262)/(1.4289)²
= 0.867
Then, the time taken will be:
= 0.867(0.15)²/(1.5/2600 × 1000)
= 33800 seconds.
In conclusion, the time taken is 33800 seconds.
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energy.
49 As your vehicle crumples in a crash, it
Reflects
Rejects
Absorbs
Deflects
Answer:
modern vehicles are made to crunch up a little bit so they that absorbe some of the impact instead of you
Explanation:
A fuel oil is burned with air in a furnace. The combustion produces 813 kW of thermal energy, of which 65% is transferred as heat to boiler tubes that pass through the furnace. The combustion products pass from the furnace to a stack at 6500C. Water enters the boiler tubes as a liquid at 200C and leaves the tubes as saturated steam at 20 bar absolute. Calculate the rate (kg/h) at which steam is produced.
The rate at which steam is produced is equal to 701 kg/hour.
What is a Boiler?A Boiler may be characterized as a type of device or instrument that significantly transforms water into steam. There are two types of boiler are found. They are water tube boilers and fire tube boilers.
According to the question,
The power generated by combustion, W = 813kW.
The efficiency of the boiler, η = 65% = 0.65.
Temperature, To = 650°C.
Water enters the boiler tubes as a liquid, T1 = 20°C.
Water leaves the tubes as saturated steam, P2 = 20 bar.
The enthalpy of water at 20°C, [tex]h_1[/tex] = 83.9kJ/kg.
The enthalpy of water at 20 bar pressure, [tex]h_2[/tex] = 2797.29kJ/kg.
Enthalpy change can be calculated by ΔH = [tex]h_2-h_1[/tex]
= 2797.29kJ/kg - 83.9kJ/kg = 2713.3 kJ/kg.
The total energy that can be developed can be calculated by the formula:
Q = W × η = 813 × 0.65 = 528.45 kW.The mass of the flow rate of the rate at which steam is produced is calculated by the following formula:
[tex]m^.[/tex] = Q/ΔH= 528.45 kW/2713.3 kJ/kg.
= [tex]\frac{528.45kW }{2713.3kJ/kg} *\frac{3600kJ/h}{1kW}[/tex] = 701 kg/hour.
Therefore, the rate at which steam is produced is equal to 701 kg/hour.
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What distinguishes the research, investigation, and analysis phase from later phases of the historical preservation process?
It involves careful attention to the history of the structure.
It is the only phase that does not involve construction.
It is primarily involved with fact finding.
It is the only phase that does not involve design.
Answer:
c
Explanation:
A balanced bank of delta-connected capacitors is connected in parallel with the load which complex power associated with each phase of a balanced load is 146 191j kVA. The effect is to place a capacitor in parallel with the load in each phase. The line voltage at the terminals of the load thus remains at 2460 V . The circuit is operating at a frequency of 65 Hz . The capacitors are adjusted so that the magnitude of the line current feeding the parallel combination of the load and capacitor bank is at its minimum.
What is the size of each capacitor?
Answer:
77.2805 μF
Explanation:
Given data :
V = 2460 V
Q = 191 Kva
Calculate the size of Each capacitor
first step : calculate for the value of Xc
Q = V^2/ Xc
Xc ( capacitive reactance ) = V^2 / Q = 2460^2 / ( 191 * 10^3 ) = 31.683 Ω
Given that 1 / 2πFc = 31.683
∴ C ( size of each capacitor ) = [tex]\frac{1}{2\pi *65 *31.683}[/tex] = 77.2805 μF
If a nurse does not agree to the discipline set due to a complaint made against this nurse, after reviewing the proposed agreed order, they can request a
4. Oil system cleaning products should not use solvents because:
A) O Solvents smell bad
B) Solvents are completely removed during the service
CO Solvents have no impact on dirt and debris
DO Solvents can damage certain plastics and rubbers found in the engine
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Answer:
Solvents can damage certain plastics and rubbers found in the engine
Explanation:
1. Pump extracts energy from a flowing fluid. _______
2. The flow within a boundary layer can be considered inviscid flow. _______
3. Laminar boundary layer velocity profile has more mixing than the velocity profile in a turbulent boundary layer. ________
4. Flow within the log-law region is considered laminar. ________
5. In a physical modeling of air flow over a aircraft, Froude number is important._______
Answer:
FALSE FALSEFALSEFALSEFALSEExplanation:
1) Pump does not extract energy from a flowing fluid instead is converts mechanical energy to fluid energy ( i.e. initial statement is FALSE )
2) Flow within a boundary layer cannot be considered an inviscid flow because flow within a boundary layer is considered a viscid flow ( i.e. initial statement is FALSE )
3) Laminar boundary layer velocity profile does not have more mixing than the velocity profile in a turbulent boundary layer because in a turbulent boundary layer the mixing of velocity profile is higher/more ( i.e. initial statement is FALSE )
4 ) Flow within the log-law region is considered Turbulent and not Laminar( i.e. initial statement is FALSE )
5) In a physical modeling of air flow over an aircraft the Reynold number is more important than the Froude number ( i.e. initial statement is FALSE )
Can anyone tell me all the corrects answers to these? I’m sorry if this is the wrong subject I’m not sure what to put it under but I really need help!
Answer:
Crankshaft position sensor - F I can't quite make out the letter but it's the thing at the bottom almost touching the notched wheel.
Coil Module - B
Knock Sensor - D
Coil Pack -E
Fuse Block - A
Powertrain Control Module - C
Air expands through a turbine from 8 bar, 960 K to 1 bar, 450 K. The inlet velocity is small compared to the exit velocity of 90 m/s. The turbine operates at steady state and develops a power output of 2500 kW. Heat transfer between the turbine and its surroundings and potential energy effects are negligible. Modeling air as an ideal gas, calculate the mass flow rate of air and the exit area.
This question is incomplete, the missing diagram is uploaded along this answer below.
Answer:
- The mass flow rate of air is 4.59 kg/s
- Area of the exit turbine is 0.066 m²
Explanation:
Given the data in the question;
Using air as an ideal gas.
Turbine;
state 1: p₁ = 8 bar, T₁ = 960 K
state 2: p₂ = 1 bar, T₂ = 450 K
The inlet velocity is small compared to the exit velocity of 90 m/s
V₁ < V₂ = 90 m/s
Power of turbine W' = 2500 kW
Now, lets assume Q = 0 and ΔPE = 0
we know that; R = 0.2870 kJ/kg-K
Also. [tex]C_p[/tex] at 700K = 1.075 kJ/kg-K
Now, using ideal gas law;
STATE1
v₁ = RT₁/p₁
so we substitute
v₁ = [(0.2870 kJ/kg-K)(960 K)/(8 bars )]|[tex]\frac{bar}{10^5N/m^2}[/tex]||[tex]\frac{1000N.m}{kJ}[/tex]| = 0.344 m³/kg
STATE2
v₂ = RT₂/p₁
we substitute
v₂ = [(0.2870 kJ/kg-K)(450 K)/(1 bars )]|[tex]\frac{bar}{10^5N/m^2}[/tex]||[tex]\frac{1000N.m}{kJ}[/tex]| = 1.2915 m³/kg
Now, from energy balance steady state;
0 = Q" - W" + [tex]m"_i[/tex]( [tex]h_i[/tex] + [tex]\frac{V_i^2}{2}[/tex] + [tex]gz_i[/tex]) - [tex]m"_B[/tex]( [tex]h_B[/tex] + [tex]\frac{V_B^2}{2}[/tex] + [tex]gz_B[/tex])
since we initially assume Q = 0 and ΔPE = 0
hence;
0 = [tex]-\frac{W"}{m"}[/tex] + h₁ + [tex]\frac{V_1^2}{2}[/tex] - h₂ + [tex]\frac{V_2^2}{2}[/tex]
[tex]\frac{W"}{m"}[/tex] = h₁ + [tex]\frac{V_1^2}{2}[/tex] - h₂ + [tex]\frac{V_2^2}{2}[/tex]
⇒ [tex]\frac{W"}{m"}[/tex] = [tex]C_p[/tex](T₁ - T₂) + [tex]\frac{1}{2}[/tex]( V₁² - V₂²)
we solve for m"
m" = W" / ([tex]C_p[/tex](T₁ - T₂) + [tex]\frac{1}{2}[/tex]( V₁² - V₂²))
so we substitute;
m" = {[2500 kW] / [(1.075kJ/kg-K(960K - 450k) + [tex]\frac{1}{2}[/tex]( (0)² - (90 m/s)²)) |kJ/1000N.m| |N/kg.m/s²|]} | kJ/s / kW|
m" = 4.59 kg/s
Therefore, the mass flow rate of air is 4.59 kg/s
From the mass body steady state;
0 = m"₁ - m"₂
so
m"₁ = m"₂ = 4.59 kg/s
now, the volumetric flow rate V"₂ will be;
V"₂ = m" × v₂
we substitute
V"₂ = 4.59 kg/s × 1.2915 m³/kg = 5.93 m³/s
and
the volumetric flow rate V"₂ = A₂V₂
so;
Exit Area A = V"₂ / V₂
we substitute
A = (5.93 m³/s ) / (90 m/s)
A = 0.06589 ≈ 0.066 m²
Therefore, Area of the exit turbine is 0.066 m²
Refrigerant 134a vapor in a piston-cylinder assembly undergoes a process at constant pressure from an initial state at 8 bar and 50°C to a final state at which the refrigerant is saturated vapor. For the refrigerant, determine the work and heat transfer, per unit mass, each in kJ/kg. Any changes in kinetic and potential energy are negligible.
Answer:
- Work done is 2.39 kJ
- heat transfer is 20.23 kJ/kg
Explanation:
Given the data in the question;
First we obtain for specific volumes and specific enthalpy from "Table Properties Refrigerant 134a;
Specific Volume v₁ = 0.02547 m³/kg
Specific enthalpy u₁ = 243.78 kJ/kg
Specific Volume V₂ = 0.02846 m³/kg
Specific enthalpy u₂ = 261.62 kJ/kg
p = 8 bar = 800 kPa
Any changes in kinetic and potential energy are negligible.
So we determine the work done by using the equation at constant pressure
]Work done W = p( v₂ - v₁ )
we substitute
W = 800 kPa( 0.02846 m³/kg - 0.02547 m³/kg )
W = 800 kPa( 0.00299 m³/kg )
W = 2.39 kJ
Therefore, Work done is 2.39 kJ
Heat transfer;
using equation at constant pressure
Heat transfer Q = W + ( u₂ - u₁ )
so we substitute
Q = 2.392 kJ + ( 261.62 kJ/kg - 243.78 kJ/kg )
Q = 2.392 kJ + 17.84 kJ/kg )
Q = 20.23 kJ/kg
Therefore, heat transfer is 20.23 kJ/kg
What invention of the Middle Ages contributed to making books easily available?
A total knee replacement experiences a spectrum of loading events, some rapid and some nearly steady state (but for a limited duration). Estimate the duration of the possible loading events, and compute the Deborah number for each, assuming a transition time for the polymer bearing of one day. Are any of these expected to occur in a fluid-like regime
Answer: your question is quite vague hence i will just give you the general answer regarding your question
answer : Deborah number = time of relaxation / time of observation
Explanation:
Estimate of the duration of the possible loading events
to estimate the duration of the possible loading events will first determine the Deborah number as shown
Deborah number = time of relaxation / time of observation
lets assume; Time of observation = 1 and time of relaxation = 1 day
Deborah number is dimensionless and it is used to determine viscoelastic behavior of a material hence the viscoelastic response during observation time is proportional to Deborah number
One of the personality traits listed for a cement mason is attention to detail.
True
False
Answer:
True
Explanation:
They have to be sure to keep cement smooth and keep an eye out for imperfections
The top surface of an L = 5mmthick anodized aluminum plate is irradiated with G = 1000 W/m2 while being simultaneously exposed to convection conditions characterized by h = 50 W/m2 ⋅ K and T[infinity] = 25°C. The bottom surface of the plate is insulated. For a plate temperature of 400 K as well as α = 0.14 and ε = 0.76, determine the radiosity at the top plate surface, the net radiation heat flux at the top surface, and the rate at whic
Answer:
[tex]J=1963W/m^2[/tex]
[tex]q_{rad}=963w/m^2[/tex]
[tex]\triangle T= -0.378k/s[/tex]
Explanation:
From the question we are told that:
[tex]L=5mm => 5*10^{-3}\\Irradiation G=1000W/m^2\\h=50W/m^2\\T_{infinity} = 25C.\\Plate\ temperature\ T_p= 400 K\\\alpha=0.14\\E=0.76[/tex]
at Temp=400K
[tex]E=2702kg/m^2,c=949J/kgk[/tex]
Generally the equation for Radiosity is mathematically given by
[tex]J=eG+\in E_p[/tex]
[tex]J=(1-\alpha)G+\in \sigma T^4[/tex]
[tex]J=(1-0.14)1000+0.76 (5.67*10^_{8}) (400)^4[/tex]
[tex]J=1963W/m^2[/tex]
Generally the equation for net radiation heat flux [tex]q_{rad}[/tex] is mathematically given by
[tex]q_{rad}=J-G\\q_{rad}=1963-1000[/tex]
[tex]q_{rad}=963w/m^2[/tex]
Generally the equation for and the rate of plate temp [tex]\triangleT[/tex] is mathematically given by
[tex]\triangle T= -\frac{q_{con} +q_{rad}}{Ecl}[/tex]
[tex]\triangle T= \frac{45(400)-(30+273+963)}{(2702*949*0.005)}[/tex]
[tex]\triangle T= -0.378k/s[/tex]
A CUSTOMER BRINGS HER CAR INTO THE
SHOP WITH A COMPLAINT THAT BOTH
HEADLIGHTS ARE NOT WORKING.
TECHNICIAN A SAYS TO CHECK THE CONDITION OF THE BULBS FIRST. TECHNICIAN B CHECKS THE FUSE IN THE HEADLIGHT CIRCUIT & THEN TESTS THE OPERATION OF THE HEADLIGHT SWITCH WHO IS CORRECT AND WHY ?
HELP ME ASAP
a bc if the bulbs are in a bad conditio. than u know that u dont have to remove it but only repair it.
The atomic weights of C and H are 12 and 1, respectively. The chemical formula of polyethylene is (C2H4)n. The number average mean molecular weight of polyethylene with a degree of polymerization of 12,000 is:_____.
a. 120,000.
b. 336,000.
c. 280,000.
d. 296,000.
Answer:
b. 336,000.
Explanation:
Step 1: Calculate the molecular weight of the monomer
Polyethilene is a polymer with the formula (C₂H₄)ₙ, where C₂H₄ is the monomer and n is the number of monomers in the polymer. We can calculate the molecular weight of the monomer by addition of the weights of the atoms that form it.
MC₂H₄ = 2 × MC + 4 × MH
MC₂H₄ = 2 × 12 + 4 × 1 = 28
Step 2: Calculate the average molecular weight of polyethylene
The average degree of polymerization (DP) of polyethylene is 12,000. We can calculate the average molecular weight of polyethylene using the following expression.
DP = M(C₂H₄)ₙ/MC₂H₄
M(C₂H₄)ₙ = DP × MC₂H₄
M(C₂H₄)ₙ = 12,000 × 28 = 336,000
In an advanced lab, students set up an experiment in which streams of electrons and protons are separated by a very short distance and generated parallel to each other. The electrons and protons are moving in the same direction. Which of the following statements is a correct analysis about the motions of the electrons and protons and provides a supporting principle?
(A) The moving electrons and protons represent currents in opposite directions; thus, they will exert a magnetic force that will be in the opposite direction of their electrostatic force.
(B) The moving electrons and protons represent currents in opposite directions; thus, they will exert a magnetic force that will be in the same direction of their electrostatic force.
(C) The moving electrons and protons represent currents in the same direction; thus, they will exert a magnetic force that will be in the opposite direction of their electrostatic force.
(D) The moving electrons and protons represent currents in the same direction; thus, they will exert a magnetic force that will be in the same direction of their electrostatic force.
(E) The moving electrons and protons exert no magnetic force on each other.
Answer:
Option B is correct
Explanation:
Electron and protons represent current in opposite direction as they have opposite charges on it. Due to motion of electron and proton in electric field they will produce the magnetic field. As both are moving parallel it means they generate the magnetic field which is in the same direction as of their electrostatic force.
Option B is correct:
The moving electrons and protons represent currents in opposite directions; thus, they will exert a magnetic force that will be in the same direction of their electrostatic force.
Consider steady flow of air through the device shown below (assume inviscid,
incompressible flow). The exit velocity is 100 ft/s and the differential pressure across the
nozzle upstream is 6 lb/ft?. Based on this information, determine (a) the height H of the water
in the manometer attached to the Pitot tube, and (b) the diameter d of the nozzle.
Answer:
im not for sure
Explanation:
Taking the convection heat transfer coefficient on both sides of the plate to be 860 W/m2 ·K, deter- mine the temperature of the sheet metal when it leaves the oil bath. Also, determine the required rate of heat removal from the oil to keep its temperature constant at 45°C.
Answer:
Hello your question is incomplete attached below is the complete question
answer :
a) 95.80°C
b) 8.23 MW
Explanation:
Convection heat transfer coefficient = 860 W/m^2 . k
a) Calculate for the temp of sheet metal when it leaves the oil bath
first step : find the Biot number
Bi = hLc / K ------- ( 1 )
where : h = 860 W/m^2 , Lc = 0.0025 m , K = 60.5 W/m°C
Input values into equation 1 above
Bi = 0.036 which is < 1 ( hence lumped parameter analysis can be applied )
next : find the time constant
t ( time constant ) = h / P*Cp *Lc --------- ( 2 )
where : p = 7854 kg/m^3 , Lc = 0.0025 m , h = 860 W/m^2, Cp = 434 J/kg°C
Input values into equation 2 above
t ( time constant ) = 0.10092 s^-1
Determine the elapsed time
T = L / V = 9/20 = 0.45 min
∴ temp of sheet metal when it leaves the oil bath
= (T(t) - 45 ) / (820 - 45) = e^-(0.10092 * 27 )
T∞ = 45°C
Ti = 820°C
hence : T(t) = 95.80°C
b) Calculate the required rate of heat removal form the oil
Q = mCp ( Ti - T(t) ) ------------ ( 3 )
m = ( 7854 *2 * 0.005 * 20 ) = 26.173 kg/s
Cp = 434 J/kg°C
Ti = 820°C
T(t) = 95.80°C
Input values into equation 3 above
Q = 8.23 MW