A string that passes over a pulley has a 0.341 kg mass attached to one end and a 0.625 kg mass attached to the other end. The pulley, which is a disk of radius 9.00 cm , has friction in its axle.What is the magnitude of the frictional torque that must be exerted by the axle if the system is to be in static equilibrium? (Answer should be in N m)

Answer:

THE ANSWER IS C

Explanation:

the net force applied to the car is zero

Answer: evaporation

Explanation:

Refrigerators work by causing the refrigerant circulating inside them to change from a liquid into a gas. This process, called evaporation, cools the surrounding area and produces the desired effect.

Answer:

mass 20 times of an amazing and all its motion

Answer:

it changes into liquid

Answer:

It changes in to liquids

Explanation:

This is because the water vapor cools down and condenses it attaches it self to dust forming water droplets. Those water droplets are water.

Answer: Part 1: Propellant Fraction (MR) = 8.76

Part 2: Propellant Fraction (MR) = 1.63

Explanation: The Ideal Rocket Equation is given by:

Δv = [tex]v_{ex}.ln(\frac{m_{f}}{m_{e}} )[/tex]

Where:

[tex]v_{ex}[/tex] is relationship between exhaust velocity and specific impulse

[tex]\frac{m_{f}}{m_{e}}[/tex] is the porpellant fraction, also written as MR.

The relationship [tex]v_{ex}[/tex] is: [tex]v_{ex} = g_{0}.Isp[/tex]

To determine the fraction:

Δv = [tex]v_{ex}.ln(\frac{m_{f}}{m_{e}} )[/tex]

[tex]ln(MR) = \frac{v}{v_{ex}}[/tex]

Knowing that change in velocity is Δv = 9.6km/s and [tex]g_{0}[/tex] = 9.81m/s²

Note: Velocity and gravity have different measures, so to cancel them out, transform km in m by multiplying velocity by 10³.

Part 1: Isp = 450s

[tex]ln(MR) = \frac{v}{v_{ex}}[/tex]

ln(MR) = [tex]\frac{9.6.10^{3}}{9.81.450}[/tex]

ln (MR) = 2.17

MR = [tex]e^{2.17}[/tex]

MR = 8.76

Part 2: Isp = 2000s

[tex]ln(MR) = \frac{v}{v_{ex}}[/tex]

ln (MR) = [tex]\frac{9.6.10^{3}}{9.81.2.10^{3}}[/tex]

ln (MR) = 0.49

MR = [tex]e^{0.49}[/tex]

MR = 1.63

Answer:

The wavelength is  [tex]\lambda = 886 \ nm[/tex]

Explanation:

From the question we are told that

   The  energy band gap is  [tex]E = 1.4 eV[/tex]

Generally the energy of  a single photon of light emitted for an electron jump in a GaAS solar cell is mathematically represented as

      [tex]E = \frac{hc}{\lambda }[/tex]

Where  h is the Planck's  constant with values

     [tex]h = 4.1357 * 10^{-15} eV[/tex]

and  c is  the speed of light with values  [tex]c = 3*10^{8} \ m/s[/tex]

So  

     [tex]\lambda = \frac{hc}{E}[/tex]

substituting values

    [tex]\lambda = \frac{4.1357 *10^{-15} * 3.0 *10^{8}}{1.4}[/tex]

  [tex]\lambda = 886 \ nm[/tex]

Answer:

(a) B = 2.85 × [tex]10^{-6}[/tex] Tesla

(b) I =  I = 0.285 A

Explanation:

a. The strength of magnetic field, B, in a solenoid is determined by;

r = [tex]\frac{mv}{qB}[/tex]

⇒ B = [tex]\frac{mv}{qr}[/tex]

Where: r is the radius, m is the mass of the electron, v is its velocity, q is the charge on the electron and B is the magnetic field

B = [tex]\frac{9.11*10^{-31*1.0*10^{4} } }{1.6*10^{-19}*0.02 }[/tex]

  = [tex]\frac{9.11*10^{-27} }{3.2*10^{-21} }[/tex]

B = 2.85 × [tex]10^{-6}[/tex] Tesla

b. Given that; N/L = 25 turns per centimetre, then the current, I, can be determined by;

B = μ I N/L

⇒    I = B ÷ μN/L

where B is the magnetic field,  μ is the permeability of free space = 4.0 ×[tex]10^{-7}[/tex]Tm/A, N/L is the number of turns per length.

I = B ÷ μN/L

 = [tex]\frac{2.85*10^{-6} }{4*10^{-7} *25}[/tex]

I = 0.285 A

Explanation:

Radius of a charged particle is given by

r=mv / Bq

= k/ q

where   k   =   m v / B         is a constant.

i.e.   more is the magnitude of  charge, less is the radius. (inversely proportional)

From the diagram  r_3   >   r_2   >   r_1  (more the curvature, less is the radius)

( although drawing is not given i am assuming the above order, however, one can change the order as per the diagram. The concept used remains the same)

therefore,    q_1   >   q_2   >   q_3 .

Answer:

μ_k = 0.1773

Explanation:

We are given;

Initial velocity;u = 20 m/s

Final velocity;v = 0 m/s (since it comes to rest)

Distance before coming to rest;s = 115 m

Let's find the acceleration using Newton's second law of motion;

v² = u² + 2as

Making a the subject, we have;

a = (v² - u²)/2s

Plugging relevant values;

a = (0² - 20²)/(2 × 115)

a = -400/230

a = -1.739 m/s²

From the question, the only force acting on the puck in the x direction is the force of friction. Since friction always opposes motion, we see that:

F_k = −ma - - - (1)

We also know that F_k is defined by;

F_k = μ_k•N

Where;

μ_k is coefficient of kinetic friction

N is normal force which is (mg)

Since gravity acts in the negative direction, the normal force will be positive.

Thus;

F_k = μ_k•mg - - - (2)

where g is acceleration due to gravity.

Thus,equating equation 1 and 2,we have;

−ma = μ_k•mg

m will cancel out to give;

-a = μ_k•g

μ_k = -a/g

g has a constant value of 9.81 m/s², so;

μ_k = - (-1.739/9.81)

μ_k = 0.1773

The coefficient of kinetic friction between the hockey puck and ice is equal to 0.178

Given the following data:

Scientific data:

To determine the coefficient of kinetic friction between the hockey puck and ice:

First of all, we would calculate the acceleration of the hockey puck by using the third equation of motion.

[tex]V^2 = U^2 + 2aS\\\\0^2 =20^2 + 2a(115)\\\\-400=230a\\\\a=\frac{-400}{230}[/tex]

Acceleration, a = -1.74 [tex]m/s^2[/tex]

Note: The negative signs indicates that the hockey puck is slowing down or decelerating.

From Newton's Second Law of Motion, we have:

[tex]\sum F_x = F_k + F_n =0\\\\F_k =- F_n\\\\\mu mg =-ma\\\\\mu = \frac{-a}{g}\\\\\mu = \frac{-(-1.74)}{9.8}\\\\\mu = \frac{1.74}{9.8}[/tex]

Coefficient of kinetic friction = 0.178

Read more: https://brainly.com/question/13821217

Answer:

a. i. applied force

ii. gravitational force

iii. normal force of reaction

b. net force is zero

c. we move forward

d. frictional force

e. opposite dirction of force applied

Explanation:

Answer: 192 ft/s

Explanation:

The initial height of the object is:

576ft above the ground.

The position equation is:

p(t) = -16*t^2 + 576

in the position equation, we only can see the therm of the initial height and the term of the acceleration (that is equal to the gravitational acceleration g = 32 ft/s^2 over 2)

So we have no initial velocity, this means that at the beginning we only have potential energy:

U = m*g*h

where m is the mass of the object, g = 32m/s^2 and h = 576 ft.

Now, as the object starts to fall down, the potential energy is transformed into kinetic energy, and when the object is about to hit the ground, all the potential energy has become kinetic energy.

The kinetic energy equation is:

K = (m/2)*v^2

where v is the velocity of the object, then the maximum kinetic energy (when the object reaches the ground) is equal to the initial potential energy:

m*g*h = (m/2)*v^2

now we can solve this for v.

v = √(2*g*h) = √(2*32ft/s^2*576ft) = 192 ft/s

Answer:

Corresponding raft speed = -0.875 m/s (the minus sign indicates that the raft moves in the direction opposite to the diver)

Explanation:

Law of conservation of momentum gives that the momentum of the diver and the raft before the dive is equal to the momentum of the diver and the raft after the dive.

And since the raft and the diver are initially at rest, the momentum of the diver after the dive is equal and opposite to the momentum experienced by the raft after the dive.

(Final momentum of the diver) + (Final momentum of the raft) = 0

Final Momentum of the diver = (mass of the diver) × (diving velocity of the diver)

Mass of the diver = 73 kg

Diving velocity of the diver = 5.54 m/s

Momentum of the diver = 73 × 5.54 = 404.42 kgm/s

Momentum of the raft = (mass of the raft) × (velocity of the raft)

Mass of the raft = 462 kg

Velocity of the raft = v

Momentum of the raft = 462 × v = (462v) kgm/s

404.42 + 462v = 0

462v = -404.42

v = (-404.42/462) = -0.875 m/s (the minus sign indicates that the raft moves in the direction opposite to the diver)

Hope this Helps!!!

Answer:

we see that the lights with the most extreme wavelength are blue and red

we see that the separation between the interference lines (y) increases linearly with the wavelength for which the phenomenon is best observed in the RED response 2

Explanation:

In Young's double-slit experiment, constructive interference is written by the equation

       d sin θ = m λ

where you give the gap separation, lam the length of the donda used and m the order of interference

in many he uses trigonometry to express the synth in confusing the distances on a very distant screen

so θ = y / L

in this experiment the angles are generally very small, so

     tan θ = sin θ / cos θ = sin θ

     sint θ = y / L

let's replace

      d y / L = mλ

      y = (m L / d) λ

now let's examine the effect of changing the wavelength

1 yellow lam = 600 10⁻⁹ m

2) red lam = 750 10⁻⁹m

3) blue lam = 450 10⁻⁸ nm

4) green lam = 550 10⁻⁹ nm

we see that the lights with the most extreme wavelength are blue and red

we see that the separation between the interference lines (y) increases linearly with the wavelength for which the phenomenon is best observed in the RED response 2

Answer :):):):):):):):):):):):):):):):):):):):):);):):):):):):):):)

Explanation:

Complete question:

The exit nozzle in a jet engine receives air at 1200 K, 150 kPa with negligible kinetic energy. The exit pressure is 80 kPa, and the process is reversible and adiabatic. Use constant specific heat at 300 K to find the exit velocity.

Answer:

The exit velocity is 629.41 m/s

Explanation:

Given;

initial temperature, T₁ = 1200K

initial pressure, P₁ = 150 kPa

final pressure, P₂ = 80 kPa

specific heat at 300 K, Cp = 1004 J/kgK

k = 1.4

Calculate final temperature;

[tex]T_2 = T_1(\frac{P_2}{P_1})^{\frac{k-1 }{k}[/tex]

k = 1.4

[tex]T_2 = T_1(\frac{P_2}{P_1})^{\frac{k-1 }{k}}\\\\T_2 = 1200(\frac{80}{150})^{\frac{1.4-1 }{1.4}}\\\\T_2 = 1002.714K[/tex]

Work done is given as;

[tex]W = \frac{1}{2} *m*(v_i^2 - v_e^2)[/tex]

inlet velocity is negligible;

[tex]v_e = \sqrt{\frac{2W}{m} } = \sqrt{2*C_p(T_1-T_2)} \\\\v_e = \sqrt{2*1004(1200-1002.714)}\\\\v_e = \sqrt{396150.288} \\\\v_e = 629.41 \ m/s[/tex]

Therefore, the exit velocity is 629.41 m/s

Answer:

404.3 J

Explanation:

Given that

Weight of the merry go round = 790 N

Radius if the merry go round = 1.6 m

Horizontal force applied = 45 N

Time taken = 4 s

To find the mass of the merry go round, we divide the weight by acceleration due to gravity. Thus,

m = F/g

m = 790 / 9.8

m = 80.6 kg

We know that the moment of inertia is given as

I = ½mr², on substitution, we have

I = ½ * 80.6 * 1.6²

I = 103.17 kgm²

Torque = Force applied * radius, so

τ = 45 * 1.6

τ = 72 Nm

To get the angular acceleration, we have,

α = τ / I

α = 72 / 103.17

α = 0.70 rad/s²

Then, the angular velocity is

ω = α * t

ω = 0.7 * 4

ω = 2.8 rad/s

Finally, to get the Kinetic Energy, we have

K.E = ½ * Iω², on substituting, we get

K.E = ½ * 103.17 * 2.8²

K.E = 404.3 J

Therefore, the kinetic energy is 404.3 J

Answer:

a. 6.41 m/s

b. 120.85 m/s^2

Explanation:

The computation is shown below:

a. Pebble speed is

As we know that according to the tangential speed,

[tex]v = r \times \omega[/tex]

[tex]= \frac{0.68}{2} \times 18.84[/tex]

= 6.41 m/s

The 18.84 come from

[tex]= 2 \times 3.14 \times 3[/tex]

= 18.84

b. The pebble acceleration is

[tex]a = \frac{v^2}{r}[/tex]

[tex]= \frac{6.41^2}{0.34}[/tex]

= 120.85 m/s^2

We simply applied the above formulas so that the pebble speed and the pebble acceleration could come and the same is to be considered

Answer:

0.1 sec

Explanation:

frequency of the clicks produced = 55 kHz = 55000 Hz

depth of the bottom of ocean from the dolphin = 75 m

we know that the speed of sound  in water is generally accepted to be ≅ 1480 m/s.

the total distance traveled by the sound from the dolphin, to the bottom of the ocean, and then back to the dolphin = 2 x 75 = 150 m

time elapsed will then be

time = distance traveled ÷ speed of sound

time = 150/1480 ≅0.1 sec

-- As she lands on the air mattress, her momentum is (m v)

Momentum = (60 kg) (5 m/s down) = 300 kg-m/s down

-- As she leaves it after the bounce,

Momentum = (60 kg) (1 m/s up) = 60 kg-m/s up

-- The impulse (change in momentum) is

Change = (60 kg-m/s up) - (300 kg-m/s down)

Magnitude of the change = 360 km-m/s

The direction of the change is up /\ .

The direction of a body or object's movement is defined by its velocity.In its basic form, speed is a scalar quantity.In essence, velocity is a vector quantity.It is the speed at which distance changes.It is the displacement change rate.

Solve the problem ?

      To learn more about magnitude refer

       https://brainly.com/question/24468862

      #SPJ2

Answer:

The difference is height is [tex]\Delta h =6.92 \ m[/tex]

Explanation:

From the question we are told that

     The distance of ball  from the goal is [tex]d = 36.0 \ m[/tex]

    The height of the crossbar is  [tex]h = 3.05 \ m[/tex]

       The speed of the ball is [tex]v = 21.6 \ m/s[/tex]

       The angle at which the ball was kicked is [tex]\theta = 50 ^o[/tex]

The height attained by the ball is mathematically represented as

      [tex]H = v_v * t - \frac{1}{2} gt^2[/tex]

Where [tex]v_v[/tex] is the vertical component of  velocity which is mathematically represented as

     [tex]v_v = v * sin (\theta )[/tex]

substituting values

     [tex]v_v = 21.6 * (sin (50 ))[/tex]

     [tex]v_v = 16.55 \ m/s[/tex]

Now the time taken is  evaluated as

       [tex]t = \frac{d}{v * cos(\theta )}[/tex]

substituting value

     [tex]t = \frac{36}{21.6 * cos(50 )}[/tex]

    [tex]t = 2.593 \ s[/tex]

So

     [tex]H = 16.55 * 2.593 - \frac{1}{2} * 9.8 * (2.593)^3[/tex]

     [tex]H = 9.97 \ m[/tex]

The difference  in height is mathematically evaluated as

      [tex]\Delta h = H - h[/tex]

substituting value

    [tex]\Delta h = 9.97 - 3.05[/tex]

    [tex]\Delta h =6.92 \ m[/tex]

Answer:

 Torque = 1191.68 N-m

Explanation:

Given data

mass m = 76 kg

standingdistance r  = 1.6 m

Solution

we get here torque  that si express as

torque  = force × distance ................1

torque  = r × F sin(theta)

and we know that

F = mg   .........2

and g = 9.8 m/s²

put here value in equation 1 we get

Torque = 76 × 1.6 × 9.8 × sin(90)

 Torque = 1191.68 N-m

Answer:

-67 m/s

Explanation:

We are given that

Mass of ball,m=0.4 kg

Initial speed,u=14 m/s

Impulse,I=-32.4 N-s

Time,t=27 ms=[tex]27\times 10^{-3} s[/tex]

We have to find the mass's velocity in the x- direction.

We know that

[tex]Impulse=mv-mu[/tex]

Substitute the values

[tex]-32.4=0.4v-0.4(14)[/tex]

[tex]-32.4+0.4(14)=0.4 v[/tex]

[tex]-26.8=0.4v[/tex]

[tex]v=\frac{-26.8}{0.4}=-67m/s[/tex]

Answer:

[tex]F_g=461lb_f[/tex]

Explanation:

First calculate the mass of the asteroid. To do so, you need to find the volume and know the density of iron.

If r = d/2 = 645ft, then:

[tex]V = \frac{4}{3} \pi r^3[/tex]

[tex]V = \frac{4}{3} \pi r^3\\V = 1.124\times10^{9}ft^3\delta_{iron}=m/V=491lb/ft^3m=V\times\delta=5.519\times10^{11}lb[/tex]

In order to find force, use Newton's universal law of gravitation:

[tex]F_g=G\frac{m_1m_2}{d^2}[/tex]

Where,

G= the gravitational constant:

[tex]G= 1.068846 \times10^{-9} ft^3 lb^{-1} s^{-2}[/tex]

[tex]F_g=461lb_f[/tex]

Answer:

The bottom two lines.

Explanation:

They need their own line of voltage quantity. A parallel circuit has the definition of 'two or more paths for current to flow through.' The voltage does stay the same in each line.

Answer:

this is the required pressure transmitted in the hydraulic system.

Complete Question

The complete question is shown on the first uploaded image

Answer:

a

[tex]\theta_{max} =18.38^o[/tex]

b

New  [tex]n_{cladding} =1.491[/tex]

Explanation:

 From the question we are told that

          The refractive index of the core is  [tex]n_{core} = 1.497[/tex]

         The refractive index of the cladding  is   [tex]n_{cladding} = 1.421[/tex]

Generally according to Snell's law

      [tex]n_{core} * sin(90- \theta) = n_{cladding} * sin (90)[/tex]

Where [tex]\theta_{max}[/tex] is the largest angle a largest angle a ray will make with respect to the interface of the fiber and experience total internal reflection

      [tex]\theta_{max} = 90 - sin^{-1} [\frac{n_{cladding}}{n_{core}} ][/tex]

       [tex]\theta_{max} = 90 - sin^{-1} [\frac{1.421}{1.497}} ][/tex]

      [tex]\theta_{max} =18.38^o[/tex]

Given from the question the the largest angle is  5°

Generally the refraction index of the cladding is mathematically represented as

           [tex]n_{cladding} = n_{core} * sin (90 - 5)[/tex]

          [tex]n_{cladding} =1.491[/tex]

Answer:

B = 0.024T positive z-direction

Explanation:

In this case you consider that the direction of the motion of the electron, and the direction of the magnetic field are perpendicular.

The magnitude of the magnetic force exerted on the electron is given by the following formula:

[tex]F=qvB[/tex]     (1)

q: charge of the electron = 1.6*10^-19 C

v: speed of the electron = 1.6*10^7 m/s

B: magnitude of the magnetic field = ?

By the Newton second law you also have that the magnetic force is equal to:

[tex]F=qvB=ma[/tex]       (2)

m: mass of the electron = 9.1*10^-31 kg

a: acceleration of the electron = 7.0*10^16 m/s^2

You solve for B from the equation (2):

[tex]B=\frac{ma}{qv}\\\\B=\frac{(9.1*10^{-31}kg)(7.0*10^{16}m/s^2)}{(1.6*10^{-19}C)(1.6*10^7m/s)}\\\\B=0.024T[/tex]

The direction of the magnetic field is found by using the right hand rule.

The electron moves upward (+^j). To obtain a magnetic forces points to the positive x-direction (+^i), the direction of the magnetic field has to be to the positive z-direction (^k). In fact, you have:

-^j X ^i = ^k

Where the minus sign of the ^j is because of the negative charge of the electron.

Then, the magnitude of the magnetic field is 0.024T and its direction is in the positive z-direction

Answer:

A. a (-321.393, 383.022) b (-76.40, -64.278)

B. (-397.991, 318.744)

C. a. resulting speed 509.9mph  b. bearing of the plane = 51.6°

Explanation:

Answeri believe it is the first one but not sure

Explanation:

Answer:

The answer is sensorimotor.

Explanation: