Answer:
Hello From your question you already have the answers for ( a ) and ( b ) hence I will provide the solution to option ( c )
answer :
a) 5.88 N
b) 0.452 s
c) 27.68 rad/s
Explanation:
Hoop radius ( R ) = 0.08 m
mass of hoop = 1.2 kg
height hoop descended ( h ) = 0.5 m
Calculate The angular velocity of the rotating hoop after it descends 0.5 m
since it is released from rest we will apply the law of conservation
mgh = 1/2 mv^2 + 1/2 * Ic * ω^2 ----- ( 1 )
where : Ic (moment of inertia ) = m*R^2 , ω = angular velocity , v = Rω
Back to equation 1 above
mgh = m*R^2*ω^2 ------- ( 2 )
therefore angular velocity ( ω ) = [tex]\sqrt{\frac{gh}{R^2} }[/tex] , h = 0.5 m, g = 9.81, R = 0.08 m
∴ ω = 27.68 rad/s
Darcy is going to make raspberry jam for the county fair.
• Her recipe calls for exactly 55 raspberries per jar.
Darcy has 1,700 raspberries.
Answer:
She can make have 30 jars with raspberries in them with 50 left over.
Explanation:
1,700 divided by 55
30 equally
but 50 left over
This means that she can make have 30 jars with raspberries in them with 50 left over.
Electric current is a measure of
Group of answer choices
a. the amount of resistance provided by the circuit.
b. the amount of electric charge that passes within a certain amount of time.
c. the amount of electric potential an electron gains passing through a battery
d. the amount of protons that pass through a resistor.
Answer:
b. the amount of electric charge that passes within a certain amount of time
Answer:
The answer is B which is the amount of electric charge that passes within a certain amount of time in my opinion.
What is the frequency of a wave traveling at 300,000,000 m/s with a wavelength of .0025 m/cycle ? Please explain good thank you
Answer:
The frecuency is 1.2*10¹¹ Hz.
Explanation:
Wavelength is the minimum distance between two successive points on the wave that are in the same state of vibration. It is expressed in units of length (m).
Frequency is the number of vibrations that occur in a unit of time, that is, how many peaks or valleys are repeated in a unit of time. Its unit is s – 1 or hertz (Hz).
The propagation speed is the speed with which the wave propagates in the medium, that is, it is the magnitude that measures the speed at which the wave disturbance propagates along its displacement. It relates the wavelength (λ) and the frequency (f) inversely proportional using the following equation:
v = f * λ.
In this case:
v= 300,000,000 m/sf= ?λ= 0.0025 mReplacing:
300,000,000 m/s= f* 0.0025 m
Solving:
f= 300,000,000 m/s ÷0.0025 m
f= 1.2*10¹¹ [tex]\frac{1}{s}[/tex] = 1.2*10¹¹ Hz
The frecuency is 1.2*10¹¹ Hz.
what is the process that creates wind.
Answer:
Winds are caused by differences in air pressure. Unequal heating of Earth’s surface creates areas of different pressure. Cooler areas have higher air pressure. Warmer areas have lower pressure. This causes air to move from high pressure to low pressure. This movement is the wind we feel.
plz mark me as brainliest.
How far are two protons if they exert a force of 0.5 N on one another?
Answer:
5.08 metres
Explanation:
The both protons should be 5.08 meters apart so that force between them is equal to the weight of electron
The two protons will exert a repulsive force of 0.5 N when they are at a distance of [tex]2.146625 \times10^{-14} \,m[/tex] away from each other.
As protons have very little mass the gravitational force will be negligible. So here we will consider the electrostatic force between them.
According to Coulomb's law in electrostatics, the electrostatic force between two charges can be given by;[tex]F=k\frac{q_{1}q_{2} }{r^2}[/tex]Where [tex]k \approx 9 \times 10^9 \, Nm^2 /C^2[/tex]Here, since both the particles are protons;[tex]q_1 = q_2 = 1.6 \times 10^{-19}\,C[/tex]Given that F = 0.5 NSubstituting the known values in the Coulomb's law equation, we get;[tex]0.5\, N = 9\times 10^{9} Nm^2 /C^2 \times\frac{(1.6\times 10^{-19}\,C)\times(1.6\times 10^{-19}\,C)}{r^2}[/tex]
ie; [tex]r= \sqrt{9\times 10^{9} Nm^2 /C^2 \times\frac{(1.6\times 10^{-19}\,C)\times(1.6\times 10^{-19}\,C)}{0.5\, N} } = 2.146625 \times 10^{-14}\,m[/tex]
Learn more about Coulomb's Law here:
https://brainly.com/question/1698562
1. Which of these can be used to observe the field of the
magnet?
A. bits of paper
C. small pieces of cloth
B. iron fillings
D. saw dust
2
Irgeckich of thon
g
Answer:
B. iron fillings
Explanation:
The data points you have taken on your lab graphs roughly form a straight line. How do you interpret the slope of this line?
Steeper slopes mean higher speeds.
Steeper slopes mean lower speeds.
Steeper slopes mean higher error.
Steeper slopes mean lower error.
The slope has no relation to speed or error
Answer: Steeper slopes mean lower speeds.
Explanation:
What is responsible for the amount of current in a circuit?
Will mark as Brainliest!!!
Answer:
Voltage is required for there to be a current but resistance can effect the amount of current.
Answer:
the answer is voltage
Explanation:
we just finished this unit in class
Use the simulation to determine the relationship between the distance from the magnet and the strength of the magnetic field at that point. Use a ruler to measure distance on the screen. Use a power fit to determine the B vs. r relationship for each location. To simplify your data collection, chose a data-collection axis where either Bx or By = 0. Measure the distance from the nearest edge of the magnet. You will need to obtain a ruler for collecting data.
Explanation:
give me more detail and i well help you out
A child is pushing a merry-go-round. The angle through which the merry-go-round has turned varies with time according to θ(t)=γt+βt3θ(t)=γt+βt3, where γ=γ= 0.450 rad/srad/s and β=β= 1.10×10−2 rad/s3rad/s3. Part A Calculate the angular velocity of the merry-go-round as a function of time. Express your answer in terms of the variables ββ, γγ, and tt. ωz(t)ωz(t) = nothing rad/srad/s SubmitRequest Answer Part B What is the initial value of the angular velocity? ωzωz = nothing rad/srad/s SubmitRequest Answer Part C Calculate the instantaneous value of the angular velocity ωzωz at t=t= 5.25 ss . ωzωz = nothing rad/srad/s SubmitRequest Answer Part D Calculate the average angular velocity ωav−zωav−z for the time interval t=0t=0 to t=t= 5.25 ss .
Answer:
hufiui
fihgpfghlfikgergkfkjhfkhjgkffhhh
Explanation:
jjgzgcjxhgygueyuufhfugkhkckgijljhgxjgjgffhgkgjxhxjgjcjckvjgghkhkgjgjfhfhfhffrusufsflslrsyfhldufñlñudtoqdyhjjxkgsgjfktwlyfñujxjxhlxlhdktstedoyñfuyñflldytidoyeyljjcñcjluffñui5woyepurñfuñufldyrajuñdlydstdyñudñydktshñxjcñydiw5uñfitwoyeoyeñufñfuñifjñufhlsyñeifññydoysitaiwtuñdyñdlsyltslsyoyeylsuñdñjjcyldlyslatlysñudidñjdñfjñjjxlhsmzhmzjjdjdlhdñhjdñjdñjddñhflhuñfhxltkds4urayraylraluarularuñstuñtsuñtsultsuñtsuñstñitsñktssistustlulsrustlularyralultalutslutajltsñgskjlgzljg?g o uguhxputxipyfugxiñhxiñhfuñdguldthgksjmgdjmgkhdjlgdjlgd
pduoyditsyafylrayoraourauptautospustistiptsñitsñitsñitsiptsiteitdustuñtsuñtsñitwiñstñitwñitsñstuuñrsoursurosoustjlsrlutejlgsjlstjfsjlgsultsjgzjñgsññkdylfhkñdgjlfshkadmjgsuñstñkydñkydñiykdhiñstñitsuñtsisñtñtieñietñietñiteñiwtñitskñgsiñteuñwrkñsturaluglsuñtwjlfalfjalhadoyfutdllgdñitswtkgsñktjrajtsurwñwñutiñtsiwñtuwñturqlñitwualtayoryarluarlietite
Which of the following is NOT an event in track and field?
A: 110 meter hurdles
B: Dressage
C: Pole Vault
D: Discus
Answer:
B
Explanation:
Dressage is a horse racing sport.
Give a definition of the positive work.
Answer and I will give you brainiliest
Explanation:
The work that leads towards the open mindness of people without any discrimination that contribute to a moral development is positive work
Quantum mechanics is used to describe the vibrational motion of molecules, but analysis using classical physics gives some useful insight. In a classical model the vibrational motion can be treated as SHM of the atoms connected by a spring. The two atoms in a diatomic molecule vibrate about their center of mass, but in the molecule HIHI, where one atom is much more massive than the other, we can treat the hydrogen atom as oscillating in SHM while the iodine atom remains at rest.
Part A
A classical estimate of the vibrational frequency is f = 7.0 x 1015 Hz. The mass of a hydrogen atom differs little from the mass of a proton. If the HI molecule is modeled as two atoms connected by a spring, what is the force constant of the spring? Express your answer to two significant figures and include the appropriate units. k= 320 N
Part B
The vibrational energy of the molecule is measured to be about 5 x 10-20 J. In the classical model, what is the maximum speed of the H atom during its SHM? Express your answer to one significant figure and include the appropriate units. v = 8000
Part C
What is the amplitude of the vibrational motion? Express your answer to one significant figure and include the appropriate units. • Ea ? I HÀ A = 3.4.1018 • • m
Part D
How does your result compare to the equilibrium distance between the two atoms in the HI molecule, which is about 1.6 x 10-10 m? Express your answer using one significant figure. IVO AQ R O 2 ? equilibrium distance = 2.25 • 10-2
Answer:
o my god how big is the question
can someone help? NO LINKS OR IM REPORTING
Answer:
BjsjsjsiisudujdgjkkgywuuuyyyuwuA 1 kg block of wood is attached to a spring, of force constant 200 N/m, which is attached to an immovable support. The block rests on a frictional surface with a coefficient of kinetic friction of 0.2. A 20 g bullet is fired into the block horizontally compressing the spring a maximum distance of 15 cm. Find the original velocity of the bullet before the collision.
Answer:
[tex]v=15.9499m/s[/tex]
Explanation:
From the question we are told that:
Mass of wood [tex]m=1kg[/tex]
force constants [tex]k= 200N-m[/tex]
Coefficient of kinetic friction [tex]\mu= 0.2[/tex]
Bullet mass [tex]m_b= 20 \approx 0.02kg[/tex]
Spring compresion [tex]y=15cm \approx 0.15 m[/tex]
Generally the equation for kinetic energy of bullet [tex]K>E_b[/tex] is mathematically given by
Complete Question
[tex]K.E_b=spring potential energy+work done against friction[/tex]
[tex]K.E_b=\frac{1}{2} mbv^2[/tex]
[tex]\frac{1}{2} m_b v^2=\frac{1}{2} ky^2+\mu my[/tex]
[tex]\frac{1}{2} (0.02)v^2=\frac{1}{2} (0.2)(0.15)^2+0.2(1)(0.15)[/tex]
[tex]v=15.9499m/s[/tex]
[tex]v\approx16m/s[/tex]
A ball weighing 100 g is attached to a string and swung around with a speed of 2 m/s. If the centripetal force exerted by the string is
0.5 N, what is the length of the string?
A) 0.08 m
B) 0.8 cm
C) 8 m
D) 80 cm
Assuming the ball is swung around in a circle parallel to the ground, it has a centripetal acceleration a of
a = v ² / R
where v is the tangential speed of the ball and R is the length of the string.
The tension in the string is 0.5 N, so by Newton's second law, the ball has acceleration
F = m a → a = F / m = (0.5 N) / (0.1 kg) = 5 m/s²
where m is the ball's mass.
Solve for R :
a = v ² / R → R = v ² / a = (2 m/s)² / (5 m/s²) = 0.8 m = 80 cm
A disk has 128 tracks of 32 sectors each, on each surface of eight platters. The disk spins at 3600 RPM and takes 15 ms to move between adjacent tracks. What is the longest time needed to read an arbitrary sector located anywhere on the disk
Answer:
the longest time needed to read an arbitrary sector located anywhere on the disk is 2971.24 ms
Explanation:
Given the data in the question;
first we determine the rotational latency
Rotational latency = 60/(3600×2) = 0.008333 s = 8.33 ms
To get the longest time, lets assume the sector will be found at the last track.
hence we will access all the track, meaning that 127 transitions will be done;
so the track changing time = 127 × 15 = 1905 ms
also, we will look for the sectors, for every track rotations that will be done;
128 × 8.33 = 1066.24 ms
∴The Total Time = 1066.24 ms + 1905 ms
Total Time = 2971.24 ms
Therefore, the longest time needed to read an arbitrary sector located anywhere on the disk is 2971.24 ms
A proton moves with a speed of 1.00 x 106 m/s perpendicular to a magnetic field, B. As a result, the proton moves in circle of radius 20.0 m. If an electron were moving at the same speed perpendicular to the same magnetic field, what would be the radius of the circle the electron would move in
Answer:
0.0109 m ≈ 10.9 mm
Explanation:
proton speed = 1 * 10^6 m/s
radius in which the proton moves = 20 m
determine the radius of the circle in which an electron would move
we will apply the formula for calculating the centripetal force for both proton and electron ( Lorentz force formula)
For proton :
Mp*V^2 / rp = qp *VB ∴ rp = Mp*V / qP*B ---------- ( 1 )
For electron:
re = Me*V/ qE * B -------- ( 2 )
Next: take the ratio of equations 1 and 2
re / rp = Me / Mp ( note: qE = qP = 1.6 * 10^-19 C )
∴ re ( radius of the electron orbit )
= ( Me / Mp ) rp
= ( 9.1 * 10^-31 / 1.67 * 10^-27 ) 20
= ( 5.45 * 10^-4 ) * 20
= 0.0109 m ≈ 10.9 mm
The visible spectrum of sunlight shows a range of colors from red to violet. This spectrum has numerous dark lines spread throughout it. Noting that the surface of the Sun is much cooler than the interior, so that the surface is comparable to a cool gas through which light passes, which of the following statements correctly explains the dark lines?
a. The cooler, denser surface material scatters certain wavelengths of light, forming dark lines.
b. The atoms at the surface absorb certain wavelengths of light, causing the dark lines at those wavelengths.
c. The atoms in the Sun’s interior emit light of specific wavelength, so that parts of the spectrum are dark.
d. The atoms at the surface are excited by the high interior temperatures, so that the dark lines are merely wavelengths at which those atoms don’t emit energy.
Light with a wavelength of 725 nm passes through the slits of a double-slit experiment. The slits of the experiment are a distance 0.0335 mm apart. What angle does the light make for the third dark fringe?
100 points
Answer:
3.10°
Explanation:
I took the test
Answer:
Explanation:
Angle for the nth dark fringe of light = n * wavelength of light / slit distance
So the angle for the 3rd fringe = 3 * 725 nm / 0.0335 mm
= 3 * 725*10^(-9) / 0.0335*10^(-3)
= 0.0649 rad
= 0.0649 * 360 / 2pi degree
= 3.72 degree
Three points A, B and C are located along a horizontal line. A positive test charge is released from rest at C and accelerates towards B. Upon reaching B, the test charge continues to accelerate toward A. Assuming that only motion along the line is possible,
a) Which point has the highest potential; A, B or C?
b) What will a negative test charge do when it is released from rest at B?
Two small metallic spheres with equal mass are suspended as pendulums by strings of length L. The sphereshave the same electric charge and come to equilibrium with each string at an angle of Θ = 10.00° with the vertical. What happens if the electric charges are decreased?
A) Θ decrease
B) Θ increase
C) Θ remains the same
D) distant between spheres increases
Answer:
Two small metallic spheres with equal mass are suspended as pendulums by strings of length L. The sphereshave the same electric charge and come to equilibrium with each string at an angle of Θ = 10.00° with the vertical. What happens if the electric charges are decreased?(D)
Explanation:
please click the heart and rate excellent and brainleist to ❤☺️☻♨️♨️☻☺️❤
Suppose that the collector is held at a small negative voltage with respect to the grid. Will the accelerated electrons reach the collecting plate?
A) Yes, but only those electrons with energy less than the potential difference established between the grid and the collector will reach the collector.
B) Yes, but only those electrons with energy greater than the potential difference established between the grid and the collector will reach the collector.
C) Yes; all the accelerated electrons will reach the collector.
D) No, none of the electrons will reach the collector
Answer:
B) Yes, but only those electrons with energy greater than the potential difference established between the grid and the collector will reach the collector.
Explanation:
In the case when the collector would held at a negative voltage i.e. small with regard to grid So yes the accelerated electrons would be reach to the collecting plate as the kinetic energy would be more than the potential energy that because of negative potential
so according to the given situation, the option b is correct
And, the rest of the options are wrong
Two children are sitting on a see-saw, as shown. Calculate the distance the 500-N chid should sit from the fulcrum (pivot) to balance the sew-saw.
We have that for the Question "Calculate the distance the 500-N chid should sit from the fulcrum (pivot) to balance the sew-saw"
It can be said that
The distance = [tex]1.8m[/tex]From the question we are told
weights are = 300 N and 500 N
length l = 6 m
take x distance from the 300 N
total torque is zero
[tex]300*3 = 500x\\\\x = 1.8 m[/tex]
For more information on this visit
https://brainly.com/question/23379286
A glass bottle of soda is sealed with a screw cap. The absolute pressure of the carbon dioxide inside the bottle is 1.50 x 105 Pa. Assuming that the top and bottom surfaces of the cap each have an area of 4.40 x 10-4 m2, obtain the magnitude of the force that the screw thread exerts on the cap in order to keep it on the bottle. The air pressure outside the bottle is one atmosphere
Answer:
[tex]F \approx 19.5 N[/tex]
Explanation:
From the question we are told that:
Pressure of [tex]P_{CO_2}=1.50 * 105 Pa.[/tex]
Bottle cap area [tex]A_b= 4.40 * 10-4 m^2[/tex]
Generally the equation for Resultant pressure [tex]P_r[/tex] is give as is mathematically given by
[tex]P_r=P_{CO_2}-P_a[/tex]
Where
[tex]P_a=atmospheric\ pressure = 1.013*10^5 pa[/tex]
[tex]P_r=1.50 * 105 Pa-1.013*10^5 pa[/tex]
[tex]P_r=0.487*10^5 pa[/tex]
Generally the equation for Force exerted by screw F is give as is mathematically given by
[tex]F = P*A\\F = 0.487*10^5*4.00*10^-4\\ F = 19.48 N[/tex]
[tex]F \approx 19.5 N[/tex]
[TG.05H]A geothermal plant has been built in a location. Which of these is the most likely impact of the plant on the location?
depletion of fossil fuels like coal
damage to hot springs and geysers
decrease in average annual temperature
increase in emission of greenhouse gases
The environmental impact that is most likely to occur in an area where there is a geothermal plant is decrease in average annual temperature.
What is a geothermal plant?A geothermal plant makes use of both heat and water in the generation of electricity.
The environmental impact that is most likely to occur in an area where there is a geothermal plant is decrease in average annual temperature.
Learn more about geothermal plant:https://brainly.com/question/27442707
#SPJ2
People with schizophrenia are most likely to have delusions that reflect the theme of
Answer:
llogical or bizarre ideas or fantasies.
Explanation:
A freight train car is moving at a constant speed with respect to the ground of Vcg. A man standing on a flatbed car throws a ball into the air and catches it as it falls. Relative to the flatbed car, the initial velocity of the ball is Vibc straight up. a. What are the magnitude and direction of the initial velocity of the ball as seen by a second man standing on the ground next to the track
Answer:
chiicken
Explanation:
When turning from your path onto a perpendicular path your speed
SHOULD BE at a STEADY
DRIVERS ED PLEASE HELP
Answer: 5-15MPH
Explanation: Trust me
35. What would a ship's position be if that ship started at
point B and traveled at an average velocity of 35 km/h
west to point D in a time period of 1.2 h?
Answer:
The final position of the ship after the given time period is 42 km West of B.
Explanation:
Given;
average velocity of the ship, v = 35 km/h
time taken for the ship to reach point D, t = 1.2 hours
The position of the ship after the given time period is calculated as follows;
x = v x t
x = (35 km/h) x 1.2 h = 42 km
x = 42 km West of B.
Therefore, the final position of the ship after the given time period is 42 km West of B.