Force acting on the wire is 0.243N
What is magnetic Force ?One of the four fundamental forces of nature, the electromagnetic force, results in the magnetic force, which is brought about by the motion of charges. When two charge-containing objects move in the same direction, a magnetic attraction pulls them together.
According to the given information
We are given that
Current in, the segment is [tex]$I=1.8$[/tex] amps
Length of segment is[tex]$l=0.3 \mathrm{~m}$[/tex]
Magnetic field [tex]$B=0.45 T^2$[/tex]
In vector form
[tex]$I \vec{l}=1.8 \times 0.3 \hat{j}$[/tex]
[tex]=0.54 \hat{\jmath} \mathrm{A} \cdot \mathrm{m}$[/tex]
[tex]B$\vec{B}=0.45 \hat{k} T$[/tex]
So
Magnetic force on wire is
[tex]& \vec{F}=\overrightarrow{I l} \times \vec{B}=(0.54 \hat{\jmath} \times 0.45 \hat{k}) \mathrm{N} \\[/tex]
[tex]& \vec{F}=0.54 \times 0.45 \hat{\jmath} \times \hat{k} \mathrm{~N} \\[/tex]
[tex]& \vec{F}=(0.243 \mathrm{~N}) \hat{\imath}[/tex]
So
[tex]$F=0.243[/tex] in the positive x - axis direction
Force acting on the wire is 0.243N
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use the 1st law of thermodynamics to derive a simplified equation for a turbine that explains its performance based on inlet (1) and outlet (2) conditions.
Energy can neither be created nor destroyed, but it can be transferred. First law of thermodynamics.
What is energy?This is the ability or capacity to do work. we know that the first law of thermodynamics explains energy conservation. thus, energy can neither be created nor destroyed.
Also, Zeroth's law of thermodynamics talks about the thermal equilibrium of two or more bodies. thus, if body A and Body B are in thermal equilibrium with body C. that body A, B, and C are all in thermal equilibrium with each other.
Again, the second law of thermodynamics says more about heat direction.
Therefore, the thermodynamics supports that the heat cannot be transferred from a colder to a hotter body.
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A liquid of density 1330 kg/m3 flows steadily through a pipe of varying diameter and height. at location 1 along the pipe, the flow speed is 9.85 m/s and the pipe diameter ????1 is 10.1 cm. at location 2, the pipe diameter ????2 is 17.5 cm. at location 1, the pipe is δy=9.15 m higher than it is at location 2. ignoring viscosity, calculate the difference δP between the fluid pressure at location 2 and the fluid pressure at location 1.
The difference between the fluid pressure at location 2 and the fluid pressure at location 1 is 119 kPa.
What is the equation of continuity?The mass balance of a fluid moving through a stationary volume element is all that the equation of continuity is about. It says that the rate of mass inflow less outflow equals the rate of mass buildup in this volume element.
According to equation of continuity:
[tex]A_{1} v_{1} =A_{2} v_{2} \\[/tex]
A₁ = Region 1 cross-sectional area
v₁ = flow velocity of region 1
A₂ = Region 2 cross-sectional area
v₂ = flow velocity of region 2
Here, [tex]A_{1} =\frac{\pi d_{1}^{2} }{4}[/tex] , [tex]A_{2} =\frac{\pi d_{2}^{2} }{4}[/tex]
Now, putting the values in the above equation we get,
[tex]v_{2} =\frac{A_{1} }{A_{2} } v_{1} \\[/tex]
[tex]=\frac{\frac{\pi d_{1}^{2} }{4}}{\frac{\pi d_{2}^{2} }{4}} v_{1}[/tex]
[tex]v_{2} =\frac{d_{1}^{2} }{d_{2}^{2} } v_{1}[/tex]
Using Bernoulli's equation, we get,
[tex]P_{2} + \rho gz_{2} +\frac{\rho v_{2 }^{2} }{2}= P_{1} + \rho gz_{1} +\frac{\rho v_{1 }^{2} }{2}[/tex]
The difference between the location 2 fluid pressure and the location 1 fluid pressure is :
[tex]P_{2}-P_{1} =\rho g(z_{1}-z_{2} )+\frac{\rho (v_{1}^{2}-v_{2}^{2}) }{2} =\rho g(z_{1}-z_{2} )+\frac{1}{2}\rho v_{1} ^{2} (1-(\frac{d_{1} }{d_{2} } )^{4} )[/tex]
[tex]P_{2}-P_{1} = 1330*9.81*9.15+\frac{1}{2} *1330*9.85^{2} (1-(\frac{10.1}{17.5} )^{2} )[/tex]
[tex]P_{2}-P_{1} = 1.19*10^5} Pa\\P_{2}-P_{1} = 119 kPa[/tex]
Hence, the difference between the fluid pressure at location 2 and the fluid pressure at location 1 is 119 kPa.
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when tuning his guitar, a music student notices that the string is not vibrating at the desired frequency of 195 hz, so he tightens the string by 16.4% to get this frequency. at what frequency was the string vibrating when he first started the tuning process?
When he started the tuning process the string vibrating frequency was 180Hz.
Frequency in a stretched string as a function of Tension(T) and linear mass density μ is given as:
f = [tex]\frac{1}{2L}[/tex] [tex]\sqrt{\frac{T}{} }[/tex]μ
where L is the length of string
Now in first case let f be the frequency
f = [tex]\frac{1}{2L}[/tex] [tex]\sqrt{\frac{T}{} }[/tex]μ (i)
After the string was tightened by 16.4% the tension in string will increase by 16.4% while all the other parameter will remain same. The new frequency which is equal to 195Hz is given by:
⇒ f₂ = 195 = [tex]\frac{1}{2L}[/tex] [tex]\sqrt{1.164T[/tex] / μ
⇒ 195 = [tex]\frac{1}{2L}[/tex] [tex]\sqrt{1.164T}[/tex]/μ (ii)
Dividing equation (i) by equation (ii), we get;
⇒[tex]\frac{f}{195}[/tex] = [tex]\sqrt{\frac{T}{1.164T} }[/tex]
⇒f = 195 [tex]\sqrt{\frac{1}{1.164} }[/tex]
⇒ f ≈ 180Hz
What is a string's natural frequency?
The length, mass, and degree of stretching a string is used to calculate its natural frequency. Giving a system a brief shock and seeing (or listening to) its reaction is the quickest technique to establish its natural frequency.
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assume that a rod-drawing operation can be carried out either in one pass or in two passes in tandem. if all die angles are the same and the total reduction is the same, will the drawing forces be different?
Unless the rod surface changes while it is between the two dies as a result of external factors like the environment or extra lubrication, the pulling forces will remain constant.
What is the physics illustration for pulling force?
In physics, tension is defined as the pulling force that is transmitted axially by a string, rope, chain, or similar object, or by each end of a rod, truss member, or other comparable three-dimensional object. Tension can also be defined as the action-reaction pair of forces acting at each end of the aforementioned elements.
The pulling force stands for what?
Every neodymium magnet has a draw force that indicates its exact strength. The draw force, which is expressed in pounds or kilograms, is the amount of force needed to remove a magnet from a steel plate that is 1/8 inch (3.175 mm) thick.
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a 20 kg child is on a swing that hangs from 2.2-m-long chains. for general problem-solving tips and strategies for this topic, you may want to view a video tutor solution of car rolling down a hill. part a what is her maximum speed if she swings out to a 40 ∘ angle?
The maximum speed of the swing at an angle of 45° is 4.15 m/s
Potential Energy, P. E = mgh
Kinetic Energy, K. E = 0.5mv^2
P.E = K.E
mgh = 0.5mv^2
The vertical component of the swing =
hCosθ
mghCosθ = 0.5mv^2
20 x 9.8 × 3 × cos45° = 0.5 x 20 x v²
20 x 9.8 x 0.88 = 10v²
172.48 = 10v^2
Divide both sides by 10 to isolate v²
v² = 172.48/10
v² = 17.248
V = √17.248
v = 4.15 m/s
Hence, maximum speed if she swings out to a 40 ∘ angle is 4.15 m/s
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In Figure, a climber leans out against a vertical ice wall that has negligible friction. The distance a is 0.914 m and distance L is 2.10 m. His center of mass is distance d=0.940 m from the feet–ground contact point. If he is on the verge of sliding, what is the coefficient of static frition is?
The static friction is the frictional force applied on the opposite of the direction of body to keep it from sliding.
We know that the weight of the body will be mg.
The force F(N) from x-axis will be vertically upwards.
mgd cos θ = F.L Sinθ
F = mgd cosθ / L.sinθ = f
F(not) = 0
F(N) = mg
F = f
Then the frictional force is
f = μ.F(N)
μ = f / F(N)
μ = [ (mgd cosθ / L.sinθ ) / mg ]
= d cosθ/ L sinθ
μ = 1.85/ 2.1 = 0.88
Therefore, the coefficient of static friction is 0.88.
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In a typical body of fresh water there exists a diversity of aquatic animal species. Consider the following scenario. A freshwater lake, ph of the water ranging between 5. 5 and 6. 5, falls prey to acid rain. Over several decades the ph of the lake water declines to 4. 5. What are the consequences of such a change on the aquatic animal populations? choose all that apply.
In the given scenario of a fresh water lake, the pH of water ranges between 5.6 and 6.5 and falls prey to acid rain. Over several decades, the pH of the lake declined to 4.5. The answers are C and E.
The term population contain a group of organisms of a single species that can interbreed and live in the same time in the same environment. For example, a population of deer includes all individuals in a particular forest.
Thus, the option C) according to the graph of pH sensitivity, biodiversity of animal species will decrease, and option E) because pH tolerance varies, only species with a tolerance level 4.5 and below will survive are correct.
This is because the prey survive in that condition.
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Suppose we replacebothhover pucks with pucks that are the same size as the originals but twice as massive. Otherwise, we keep the experiment thesame. Compared to the pucks in the video, this pair of pucks will rotateHint 1.How to approach the problemThis question asks you to relate the mass of a rotating object to the object’s angular speed(rate of rotation).You can do that using angular momentum:. In this equation, the moment of inertiais the "mass" term, equivalent toin the equation forlinear momentum.So, how does the pucks moment of inertiarelate to their mass? Is the relationship linear ()? Or is it quadratic () or inverse square()? To see the answer, try writing the general equation that defines.Now, how will doubling the mass of the pucks affect,, and?
When the mass of an object is doubled, the moment of inertia of the object is also doubled. This is because the moment of inertia of an object is proportional to the mass of the object. In the equation for angular momentum, $L = I\omega$, the moment of inertia $I$ is the "mass" term, and it is proportional to the mass of the object.
If we double the mass of the pucks in the experiment, the moment of inertia of the pucks will also be doubled. This means that the angular momentum of the pucks will be doubled, since $L = I\omega$.
However, the angular speed $\omega$ of the pucks will remain the same, since it is not directly affected by the mass of the pucks.
Therefore, the pair of pucks that are twice as massive as the original pucks will have the same angular speed but a higher angular momentum. This means that the pucks will rotate at the same rate but with more momentum, making them harder to stop or change direction.
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a flatbed truck is carrying a heavy crate the coefficient of static friction between the crate and the bed of the truck 0.75 what is the maximum rate at which the driver can decelerate and still avoid having the crate slide agaainst the cab of the truck
The box must not slide, thus it is crucial for us to determine when the force of deceleration and the force of friction are equal. ma = mg, a = 0.75 * 9.8 m/s2, which is 7.35 m/s2. The driver may therefore safely decelerate at around 7.2 m/s2.
Friction is a type of force.The force produced when two surfaces glide against and touch one another is referred to as frictional force. There are a few things that impact the frictional force: The surface roughness of these forces and the amount of force pressing them together have the biggest impact.
Exactly what generates friction?Friction is believed to be created by the interactions between the microscopic bumps on surfaces when they rub against one other, however scientists are still unsure of its exact mechanism.
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question 3 if you are on earth and you would like to send a space probe to an asteroid that is in a circular orbit with a radius of 7 au, how many years would the journey take using the minimum energy direct trajectory?
It would take the probe minimum 8.5 years to reach a distance of 7 AU (1 AU = 150 million km).
The answer to this question depends on many factors, such as the probe's speed, the asteroid's mass, and the asteroid's size. Assuming that the probe is traveling at a speed of 10 km/s and that the asteroid's mass is 5x10^15 kg, the journey will take approximately 8.5 years.
However, this assumes a minimum energy direct trajectory, meaning that the probe would need to make a few course corrections to ensure it stays on the correct trajectory. This could cause the journey to take much longer than 8.5 years. Additionally, the size of the asteroid could impact the journey time, as a larger asteroid could cause the probe to need to make more course corrections.
In conclusion, the journey time for a space probe to travel to an asteroid with a radius of 7 AU using a minimum energy direct trajectory will depend on several factors. However, the journey time could be significantly increased if the probe requires more course corrections or if the asteroid is larger.
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g what is the magnitude of the tension ta in rope a? a. 500 n b. 3200 n c. 370 n d. 130 n e. 100 n f. 400 n value: 10 if the axis of rotation is placed on rope a, then the torques of f
To find the magnitude of the tension in rope A, we need to consider the forces and torques acting on the system.
In this problem, the forces acting on the system are the weight of the block and the tensions in ropes A and B. The torques are the forces acting on the ropes multiplied by their distances from the axis of rotation.
We can use the concept of equilibrium to solve this problem. When an object is in equilibrium, the sum of the forces and the sum of the torques must be zero. In this case, the forces on the system are balanced, so the sum of the forces is zero. We can write this as:
$$T_A + T_B - W = 0$$
where $T_A$ and $T_B$ are the tensions in ropes A and B, and $W$ is the weight of the block. We are given that $T_B = 3200 \text{ N}$ and $W = 500 \text{ N}$.
Next, we need to consider the torques on the system. If the axis of rotation is placed on rope A, the only torque acting on the system will be the torque due to the tension in rope B.
The torque due to the tension in rope B is given by the equation $\tau = rT$, where $\tau$ is the torque, $r$ is the distance from the axis of rotation to the point where the force is applied, and $T$ is the force.
In this case, the distance from the axis of rotation to the point where the force is applied is $r = 10 \text{ m}$, and the force is the tension in rope B, $T = 3200 \text{ N}$. The torque due to the tension in rope B is therefore $\tau = 10 \text{ m} \times 3200 \text{ N} = 32000 \text{ Nm}$.
Since the system is in equilibrium, the sum of the torques must be zero. We can write this as:
$$\tau = 0$$
Substituting the value of the torque due to the tension in rope B, we get:
$$32000 \text{ Nm} = 0$$
This equation is satisfied, so the system is in equilibrium.
Finally, we can use the equation for the sum of the forces to solve for
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when a wave strikes a new medium, three things can happen: reflection, transmission, and absorption. consider a wave propagates in air and is transmitted through a piece of paper. does increasing the frequency increase the amplitude of a sound wave transmitted through the piece of paper
A wave propagates in the air and is transmitted through a piece of paper. If the frequency increased, the amplitude of the sound wave transmitted through the paper is: not increased (decreased).
Why does the increase in frequency not increase the amplitude of sound waves?Frequency is the number of complete waves that passed by a medium per second. Meanwhile, the amplitude is the maximum distance the medium’s particle moves from its resting position when a sound wave passes. The correlation between frequency and amplitude is inversely proportional. That means, when the frequency increases, the sound wave’s amplitude will go down. Hence, the correct answer is: not increased (decreased).
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an object is hung from a spring scale while it is immersed in water. the scale reads 5.6 n. the mass of the object is 0.75 kg. what is the density in [x103 kg/m3] of the object?
The density of object is 3.33*10³
How to calculate density of object ?The gravitational force draws any two mass-containing objects together. The gravitational force is referred to. According to the formula F=Gm1m2r2, the force will always be applied along the line connecting the two masses in the direction of the other mass. It is a force of attraction in nature.
Given,
gravitational force = 5.00N
Mass of the object = 0.5kg
reading when submerged in water = 3.5 N
The loss in weight = 5 - 3.5
= 1.5 N
This loss in water due to buoyancy in water
Loss in weight of water = weight of displaced water
So ww = 1.5 N
Weight of displaced water = w *v * g
Density of water = 10³kg/m³
Thus , 1.5=10³ * v* 10
V = 1.5/10³ * 10 m³
Let density be m/v
=0.5/1.5*10*10³
= 3.33*10³
Therefore density of object is 3.33*10³
The complete question is : The gravitational force exerted on a solid object is 5.00 N. When the object is suspended from a spring scale and submerged in water, the scale reads 3.50 N. Find the density of the object.
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jennifer hits a stationary 0.20-kg ball, and it leaves her racket at 40 m/s. time-lapse photography shows that the ball was in contact with the racket for 40 ms. (a) what average force did the ball exert on the racket? (b) what is the ratio of this force to the weight of the ball?
The average force the ball exerts on the racket is 200 N and the ratio of this force to the weight of the ball is 102.04.
What do you mean by force?
A force is a push or pull that an object feels as a result of interacting with another thing. Each time two things come into contact, a force is applied to each one of them. When the interaction is finished, the force is no longer sensed by the two objects.
As given in the question,
The weight of the ball = 0.200 kg
Initial velocity = 40 m/s
Time in contact = 40 ms = 0.04 s
a) From the formula of impulse, we can write as:
Impulse (J) = The change in momentum
{since, Impulse (J) = Ft}
Ft = P
Ft = mv
Here, F = force, t = time, P = momentum, m = mass, v = velocity
So, the average force was exerted on the racket can be calculated as:
F(avg) = mv/t
putting the value from the question,
F(avg) = (0.200 kg)(40 m/s)/(0.04 s)
F (average) = 200 N
b) The weight of the ball can be calculated as:
W = mg
Here, W = weight, m = mass, g = gravitational constant
W = (0.200 kg)(9.8 m/s2)
W = 1.96 N
The ratio between the force and weight of the ball can calculated as: F(avg)/W = 200 N/1.96 N
= 102.04
Hence, the answers for a and b are 200 N and 102.04 respectively.
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a constant magnetic field of 7 7 t passes through a square with side 3 3 m at an angle of 55 ∘ 55∘ from the surface. calculate the magnetic flux that passes through the square. round your answer to two decimal places
The magnetic flux that passes through the square is 51.60wb.
What is magnetic flux?
The total magnetic field that flows through a specific area is measured by magnetic flux. It serves as a useful tool for describing the effects of the magnetic force on objects occupying a specific space.
The total magnetic flux through a closed surface is equal to zero, according to Gauss's law of magnetism, one of the four Maxwell's equations. (A "closed surface" is a surface that completely and without any openings encloses a volume or volumes.)
According to the given information:
Side length [tex]$=a=3 \mathrm{~m}$[/tex]
Area [tex]$=A=a^2=(3)^2=9 m^2$[/tex]
Magnetic field [tex]$B=7 \mathrm{~T}$[/tex]
Angle [tex]$\theta=55^{\circ}$[/tex]
[tex]$\Rightarrow$[/tex] Angle with area vector [tex]$=\alpha=90^{\circ}-55^{\circ}=35^{\circ}$[/tex]
Now, magnetic flux is given as
[tex]$$\begin{aligned}\phi & =B \cdot A=B A \cos \alpha \\& =7 \times 9 \times \cos 35^{\circ} \\& =51.60 \mathrm{\omega b} .\end{aligned}$$[/tex]
Magnetic flux [tex]$\phi=51.60 \mathrm{wb}$[/tex]
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calculate the moment of inertia of a thin, uniform rod of length l and mass m that rotates about a pivot at distance l/3 from one end.
The mass moment of inertia (ML²/9) is a measurement of a body's degree of inertia for rotational motion.
Explain about the moment of inertia?In physics, the term "moment of inertia" refers to the quantitative measurement of a body's inertia with respect to rotation, or the resistance that a body shows when a torque is applied to change its speed of rotation around an axis (turning force).
An engine's flywheel is a large mass that is positioned on the crankshaft. The flywheel's MOI is extremely high and aids in energy storage. In comparison to a solid shaft, a hollow shaft transmits more power (both of same mass). Because it resists rotational motion, the moment of inertia is referred to as such and not as a moment of force.
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The operating voltage of a power line is increased from 300 kV to 600 kV. If the amount of power delivered to customers over the power line remains constant, how does the power loss in the power line at 300 kV compare to the power loss at 600 kV? Explain.
As the voltage is increased, the power losses would decrease.
What is the power loss?We now that the term power loss has to do with the loss that occurs as a result of the heating effect of current. The transmission of power at high voltage tends to reduce the power losses that accompanies the transmission of power at a lower voltage and a high current.
As such, when we have the operating voltage of a power line is increased from 300 kV to 600 kV we can see that the voltage has doubled and this would mean that the transmission is now at a much higher voltage which would reduce the power losses even further.
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(b) at what time is the mechanical energy of the bucket-earth system at a minimum? explain your reasoning.
Plants are promoting both mechanical energy and chemical watering process but inhibit erosion of soil always of to the roots.
What is mechanical energy?
Mechanical energy (kinetic energy or potential energy) is one of the energy that is either an object in the motion or to the energy that is very stored in to the objects by their own position. Mechanical energy is also vary the driver of renewable of the energy. Many forms of the renewable energy is rely on mechanical energy to the adequately produce power or the convert energy. As we all know roots of the plant grow Deep its undergoes rock causing mechanical watering process so the mechanical watering process is the important for plants. When when plants roots undergoes the soil through The rocks mechanical watering process is must needed for growth of the plants.
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if a car takes a banked curve at less than the ideal speed, friction is needed to keep it from sliding toward the inside of the curve (a real problem on icy mountain roads). (a) calculate the ideal speed to take a 85 m radius curve banked at 15 degrees.
The ideal speed is 14.71 m/s. The result is obtained by using the trigonometric formula for tan θ.
What is tan θ when a car takes a banked curve?When a car takes a banked curve, the value of tan θ would be
[tex]tan \: \theta = \frac{v_{i}^{2} }{r \times g}[/tex]
Where
θ = bangking anglevi = ideal speed (m/s)r = radius of the curve (m)g = acceleration due to gravity (9.8 m/s²)If the car takes a banked curve below the ideal speed, the friction is needed to hold it from sliding inwards of the curve. We have
radius of the curve banked, r = 85 mbanking angle, θ = 15°To find the ideal speed, we use the trigonometric formula for tan θ.
[tex]tan \: \theta = \frac{v_{i}^{2} }{r \times g}[/tex]
[tex]v_{i}^{2} = r g \times tan \: \theta[/tex]
[tex]v_{i} = \sqrt{r g \times tan \: \theta}[/tex]
[tex]v_{i} = \sqrt{85 \times 9.8 \times tan \: 15}[/tex]
[tex]v_{i} = \sqrt{223.2}[/tex]
vi = 14.94 m/s
Hence, the ideal speed to take a 85 m radius of the curve banked at 15 degrees is 14.94 m/s.
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a principle of design in which the visual weight of the forms achieves equilibrium despite being distributed unevenly throughout the picture plane is called:
Answer- Asymmetrical equilibrium Due to unequal visual weight on either side of the composition, the equilibrium is asymmetrical. There could be a dominant element on one side of the composition, which is balanced by one or more weaker focal points on the other.
Explanation: What design principle brings up equilibrium?
Balance. Visual equilibrium and our feeling of balance are related concepts in the field of balancing. Visual stability is the result of a composition's reconciling conflicting forces. The two methods that the majority of effective compositions attain balance are either symmetrically or asymmetrically.
What design tenet is characterized by the distribution of visual weight on either side of the vertical axis?
Balance. Both sides of the visual field's weight distribution are equal.
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A pure tone with a frequency f1 = 800 Hz is modulated by a frequency f2 = 160 Hz. The primary sidebands are______ Hz and ______Hz. The virtual pitch heard will be the related fundamental, _______Hz.
A pure tone with frequency f1 = 800 Hz is modulated by frequency f2 = 160 Hz. The primary sidebands are 960 Hz and 640 Hz. The virtual pitch heard will be the related fundamental, 800 Hz.
In physics, the term frequency refers to the number of waves passing through a fixed point in unit time. It also represents the number of cycles or oscillations an object undergoes per unit time in periodic motion.
The wave frequency (f,) is the number of waves passing through a point in one second. Frequency is measured in Hertz (Hz). One hertz equals one wave per second. Frequency is also called cycles per second or time frequency. The usual symbol for frequency is the Latin letter f or the Greek letter ν (nu).
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If gravity is the only force that plays a role in the evolution of the universe, and the mass density is less than the critical mass density, which plot correctly shows the evolution of the universe?.
Plot B correctly shows the evolution of the universe because it shows a steady/constant incline.
The correct option is B.
Evolution of the universe?
Our universe has been known to begin with an explosion of space itself called the Big Bang. Starting from extremely high density and temperature, space expanded, the universe cooled, and the simplest elements formed. Gravity gradually drew matter together to form the first stars and the first galaxies.
The nature of the universe is such that it underwent several stages of evolution, during its lifetime. These major stages include :
the radiation era, recombination eraepoch era and reionization eraOverall, a steady/constant incline will represent the various steady changes the universe has undergone in its development.
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complete question:
If gravity is the only force that plays a role in the evolution of the universe, and the mass density is less than the critical mass density, which plot correctly shows the evolution of the universe?
Plot A: a curved incline
Plot B: a steady/constant incline
Plot C: a very curved decline
a gust of wind creates ripples on the ocean that have a wavelength of 4.7\;\mathrm{cm}4.7cm and propagate at a speed of 6.5\;\mathrm{cm/s}6.5cm/s. what is the frequency of these ocean waves?
A gust of wind creates ripples in the ocean, then the frequency of these ocean waves will be 1.4 Hz.
What is Frequency?The percentage of waves that transfer a fixed point in a unit of time is known as the frequency in physics. It is the frequency or vibrations that a body in periodic motion perceptions in a unit of time. When a body in periodic motion moves through a sequence of incidents or positions before returning to its initial state, it is believed to have experienced one cycle or one vibration.
As per the given data mentioned in the question,
Frequency = speed/wavelength
Speed = 6.65 cm/s
Wavelength = 4.7 cm
F = (6.5 × 10⁻²)/(4.7 × 10⁻²)
F = 1.4 Hz
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what is another way to say 'the force due to gravity'? applied force air resistance normal force weight friction next
Normal force: The force that an object exerts on another object in a direction perpendicular to the surface of contact. It is the force that balances the force of gravity and prevents objects from being crushed.
What is force?
A force is an external cause that, when applied, alters or has the potential to alter a body's state. The body comes to rest when it is moving, and it moves when it is at rest. The body's direction, form, size, etc. may also change as a result. An illustration would be to push or forcefully push a door. Force has both a magnitude and a direction because it is a vector quantity. Force is described as the "product of the a body's acceleration and mass in Newton's second law. As an illustration, you should emphasise that a push or even a pull is referred as a force as the main point of your guidance at this level.
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once the person gets half way around, they decide to simply let go of the merry-go-round to exit the ride. what is the magnitude of the linear velocity of the person right as they leave the merry-go-round?
The linear velocity during leaving merry-go-round is 1.25 m/s
We define the rate of change in position over a time period as velocity. Linear velocity is simply an object's velocity in a straight line, whereas Angular Velocity is how much an object spins, rotates, or turns.
The linear velocity during leaving merry- go-round is,
v' = w' x R
v' = 0.77 x 1.63
v' = 1.25 m/s
Hence, linear velocity during leaving merry-go-round is 1.25 m/s
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Technician a says that rotary motion of the pistons is converted to reciprocating motion of the crankshaft. Technician b says that rotary motion is up and down or back and forth. Who is correct?.
Technician A says that rotary motion of the pistons is converted to reciprocating motion of the crankshaft which is correct.
Using the composite material gets converted this same reciprocating motion of such a piston to rotary motion.The connecting rod seems to be the intermediary between some of the piston and perhaps the crankshaft.Whenever the piston would be reciprocated from TDC instead to BDC, perhaps the crankshaft moves clockwise somewhere throughout the primary wheels Piston would be directly linked to the connecting rod to that same gudgeon pin as well as the crankshaft has been associated with the connecting rod to something like the crank.To know more about motion visit:
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A container with volume 1.61 L is initially evacuated. Then it is filled with 0.246 g of N2. Assume that the pressure of the gas is low enough for the gas to obey the ideal-gas law to a high degree of accuracy. of the root-mean-square speed of the gas molecules is 192 m/s, what is the pressure of the gas? Express your answer in pascals.
The pressure of the gas is 0.018 atm if the gas obeys the ideal gas law.
What is the reason for this?
We know that;
√ 3RT/M
For N2;
vrms = 192 m/s
R = 8.314 J/K.mol
T = ?
M = 28 g/mol or 0.028 Kg/mol
So;
T = vrms² M/ 3R
T = 192² * 0.028 / 3* 8.314
T = 41.3K
From PV = nRT
n = 0.246 g/28 g/mol = 0.0087 moles
P = nRT/V
P = 0.0087 moles × 0.082 atmLK-1mol-1 × 41.3K/1.61 L
P = 0.018 atm
Therefore, the pressure of gas is 0.018 atm.
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What intermolecular force is present for ne to form a liquid at low temperatures?.
For ne to form a liquid at low temperatures, an intermolecular force known as London dispersion forces must be present.
What are intermolecular forces ?
Different sections of a molecule may have a positive or negative charge, which can lead them to arrange into particular forms in a solid. These intermolecular forces are what draw molecules together. The melting and boiling points of a substance depend on the strength of intermolecular forces.
Neon is a noble gas, an inert gas. The London dispersion force exists between them as an intermolecular force. Think of two Ne atoms that are close to one another. Due to their rapid speed, electrons eventually become asymmetrical in their distribution. London dispersion forces, which are transient dipoles caused by unequal electron distributions, are the only intermolecular forces it is capable of showing. The ensuing London dispersion forces can provide weak attractions between neon atoms because neon has electrons. Neon is a monatomic gas that exists. In other words, each neon atom is self-contained and does not interact chemically with any other atoms. As a result, neon's electron distribution can be said to be symmetrically undisturbed, making it nonpolar.
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explain why lasers can be used to perform surgery and cut through metal while incandescent light cannot.
The phrase LASER is an acronym of mild Amplification by way of stimulated Emission of Radiation. it's miles a device to provide a sturdy, monochromatic, collimated and tremendously coherent beam of mild. it really works in the phenomenon of 'stimulated emission'.
Laser light is exceptionally monochromatic.
The laser light is a beam of monochromatic mild due to the fact all photons in the laser light have identical power, big hnu = E_2-E_1, identical frequency, large nu = frac{E_2-E_1}{h} and additionally same wavelength, big lambda = frac{hc}{E_2-E_1}.
(ii) Laser light is fairly coherent.
since the emission of all photons are in section, the laser beam is coherent.
(iii) Laser mild is relatively extreme
The depth of laser beam may be very high due to the fact all the photons within the beam are coherent.
(iv) Laser light is highly directional.
A laser beam is fantastically directional. mild from other assets can be made parallel beam by using a lens or a reflect,but the beam divergance is an awful lot more than that for laser light.
Those properties of laser mild enables it for use in surgical treatment and cut via metals.
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Two power lines run parallel for a distance of 270 m and are separated by a distance of 40.0 cm. If the current in each of the two lines is 140 A and if they run in opposite directions, determine the magnitude and direction of the force each wire exerts on the other.
Answers:
magnitude: _____ N
direction: towards eachother, or away from eachother
The force exerted by each wire on the other is 2.646N and it is away from each other.
The distance between the parallel power lines is 40cm and they are of a length of 270m each.
The current in the power line is 140A.
The force on each power line due to another can be given by,
F = uI₁I₂L/2πr
Where,
I₁ and I₂ are the current in the line,
L is the length of the wire,
r is the distance between them,
Putting values,
F = 4 x π x 10⁻⁷ x 140 x 140 x 270/2 x π x 0.4
Solving further,
F = 2.646 N.
The force will be away from each other because the current is in same direction. The magnitude of the force will remain same, whatever direction of the current may be.
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