A stone is dropped from the edge of a roof, and hits the ground with a velocity of -150 feet per second. How high (in feet) is the roof

Answer:

Explanation:

If we assume the rod and sphere are of uniform construction so that their individual centers of mass are at their geometric centers, and that the rod end is attached to the surface of the sphere.

Balance moments about the rod free end of the assembly with its parts

(M + m)Cx = M(L/2) + m(L + R)

Cx = (M(L/2) + m(L + R)) / (M + m)

Answer:

4600kg

Explanation:

Density=mass÷volume

920=m/5

m=920×5=4600kg

Hi there!

With the work-energy theorem for oscillating springs:

ME = KE + PE

[tex]ME = \frac{1}{2}mv^2 + \frac{1}{2}kx^2[/tex]

Where:

m = mass (kg)

v = velocity (m/s)

k = Spring Constant (N/m)

x = displacement from equilibrium (m)

If the object is at the equilibrium position, there is NO potential energy since:

[tex]\frac{1}{2}k(0^2) = 0 J[/tex]

Thus:

[tex]ME = \frac{1}{2}mv^2[/tex]

Plug in the given values:

[tex]ME = \frac{1}{2}(0.50)(1.5^2) = \boxed{0.5625 \text{ J}}[/tex]

Answer: here you go i have to put 20 letters in so just ignore this and look at the link.

Answer:

D

Explanation:

Answer:

Explanation:

s = s₀ + v₀t + ½at²

ASSUMING the acceleration is in the direction of initial motion.

s = 0 + 3.3(10) = ½(3.7)(10²)

s = 218 m

Answer:

D = 25g/cm³

Explanation:

1ml = 1cm³

D = m/V

D = 500g/20cm³

D = 25g/cm³

Answer:

20 m/s at -35°

Explanation:

Ignoring air resistance, the initial vertical velocity will be reversed and the initial horizontal velocity will remain constant.

The force constant k of the spring, if The oscillation of the 2 kg mass of spring is described by x = 3.0 cos (4.0 t) is 32 N / m.

Force is the influence of either pull or pushes in the body. Basically, gravitation forces, nuclear forces, and friction forces are the types of forces. For e.g. when the wall is hit by a hand then a force is exerted by the hand on the wall as well as the wall also exerts a force on the hand. There are different laws given to Newton to understand force.

Newton is a unit of force used by physicists that is part of the International System (SI). The force required to move a body weighing one kilogram one meter per second is known as a newton.

Given:

The mass of the block, m = 2 kg,

The oscillation of spring, x  = 3 cos 4t,

Calculate the omega  by comparing the standard equation given below,

[tex]x = A cos \omega t[/tex]

ω = 4

Calculate the spring constant by the formula given below,

[tex]\omega = \sqrt{\frac{k}{m} }[/tex]

4² = k / 2

k = 32 N / m

Therefore, the force constant k of the spring, if The oscillation of the 2 kg mass of spring is described by x = 3.0 cos (4.0 t) is 32 N / m.

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Answer:

Heterotrophic requiring complex organic compounds of nitrogen and carbon (such as that obtained from plant or animal matter) for metabolic synthesis.

Answer -:

⟹ It is a mode of nutrition in which organism are unable to synthesize organic substance by themselves and obtain part of whole of organic substance from external environment. the organism that obtain their food by this method are called heterotphs.

On the basis of types of food and feeding habit's nutrition classified into following group -:

(1) Holozoic Nutrition -:

nutrition and animal consumes a plant or an animal us whole or a part of it in solid or liquid form most of free living a cellular protist and all animal show Holozoic Nutrition

(2) Herbivores -:

animal eating grass or other plant material are called Herbivores.

(3) Carnivorous

flesh eating animal are called carnivorous.

(4) Omnivorous

animal eating food or plant us well us animal origin are called omnivorous.

(5) Insectivorous

insect eating animal are calledinsectivorous .

(6) Frugivores

animal which mainly depend on fruit are called frugivores.

Explanation:

The initial kinetic energy [tex]KE_0[/tex] is

[tex]KE_0 = \frac{1}{2}mv_0^2 = \frac{1}{2}(400\:\text{kg})(10\:\text{m/s})^2[/tex]

[tex]\:\:\:\:\:\;\:= 2×10^4\:\text{J} = 20\:\text{kJ}[/tex]

The final kinetic energy [tex]KE[/tex] is

[tex]KE = \frac{1}{2}mv^2 = \frac{1}{2}(400\:\text{kg})(30\:\text{m/s})^2[/tex]

[tex]\:\:\:\:\:\:\:= 1.8×10^5\:\text{J} = 180\:\text{kJ}[/tex]

The work done W on the car is

[tex]W = \Delta{KE} = KE - KE_0[/tex]

[tex]\:\:\:\:\:\:\:= 180\:\text{kJ} - 20\:\text{kJ} = 1.6×10^5\:\text{J}[/tex]

The power expended P is

[tex]P = \dfrac{W}{t} = \dfrac{1.6×10^5\:\text{J}}{15\:\text{s}} = 10667\:\text{Watts}[/tex]

[tex]\:\:\:\:\:= 10.7\:\text{kW}[/tex]

The equation of the progressive wave is y = 12 cos(40t - 4x)

The general wave equation is given by:

y = A sin(ωt - kx)

Where A is the amplitude, ω is the angular frequency = 2πf, f is the frequency, k is the wave number and y, x is the displacement.

Given the equation for a progressive wave is y=6 cos⁡(20t-4x). Hence:

The amplitude A = 6,

ω = 20 = 2πf

f = 20/2π = 3.183 Hz

Twice the amplitude = 2 * 6 = 12, twice the frequency = 2 * 3.183.

ω = 2π(3.183*2) = 40

Therefore the other progressive wave has an equation of:

y = 12 cos(40t - 4x)

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Answer:

Planck postulated that the energy of light is proportional to the frequency, and the constant that relates them is known as Planck's constant (h). His work led to Albert Einstein determining that light exists in discrete quanta of energy, or photons.

Explanation:

Answer:

Energy does not occur in continuous amounts but in discrete amounts described by:

E = N h ∨   where N is the number of quanta (energy units), ∨ the frequency of the energy, and h Planck's constant (6.63E-34 J-sec)

The magnitude of the total initial velocity of the rocket is determined as 9.82 m/s.

The magnitude of the total initial velocity of the rocket is calculated as follows;

V = D/T

where;

V = (54)/(5.5)

V = 9.82 m/s

Thus, the magnitude of the total initial velocity of the rocket is determined as 9.82 m/s.

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Answer:

Explanation:

Initial velocity 25 m/s

final velocity 0 m/s

The ratio of the two is undefined as dividing by zero is wonky.

Answer:

If the observer is stationary but the source moves toward the observer at a speed vs, the observer still intercepts more waves per second and the frequency goes up. This time it is the wavelength of the wave received by the observer that is effectively shifted by the motion, rather than the speed.

Answer:

Explanation:

v = √(25² + 8.5²) = 26.40549... = 26 m/s

θ = arctan(8.5/25) = 18.77803... = 19° S of E

Explanation:

Di -. 2

Tetra. -3

deca. -. 10

Hepta. -- 7

Answer:

0.80 kN

Explanation:

Hope you understood it

Answer:

c.

Explanation:

If the two plates that meet at a convergent plate boundary both are of oceanic crust, the older, denser plate will subduct beneath the less dense plate. The older plate subducts into a trench, resulting in earthquakes. Melting of mantle material creates volcanoes at the subduction zone.

When two oceanic plates converge, the denser plate will end up sinking below the less dense plate, leading to the formation of an oceanic subduction zone. Old, dense crust tends to be subducted back into the earth. An example of a subduction zone formed from a convergent boundary is the Chile-Peru trench….

Answer:

a divergent plate boundary

Explanation:

Fgravity = G*(mass1*mass2)/D²

G is the gravitational constant, which has the same value throughout our universe.

D is the distance between both objects.

so, now some numbers change

Fgravitynew = G*((1/3)*mass1*2*mass2)/(2D)² =

= G*((2/3)*mass1*mass2)/(4D²) =

= (2/3)* (G*(mass1*mass2)/D²) / 4 =

= ((2/3)/4) * G*(mass1*mass2)/D² =

= (2/12) * Fgravity = Fgravity/6

the new gravitational force will be 16/6 = 8/3 units.

Answer:

Explanation:

If 2×2 is 4 so 1 kg can be 1 gram if it belive on it self some people change

This question involves the concepts of the law of conservation of momentum, velocity, and mass.

The two quantities, the students should multiply before and after the collision are "A. mass and velocity".

According to the law of conservation of momentum, In an isolated system, the total momentum of the system before the collision is always equal to the total momentum of the system after the collision.

To prove the law of conservation of momentum, consider two balls of masses ‘m₁’ and ‘m₂’, moving with velocities ‘u₁’ and ‘u₂’, respectively, such that u₁ is greater than u₂. After some time, these balls collide with each other and their velocities become ‘v₁’ and ‘v₂’, respectively.

This situation is illustrated in the attached picture.

So, according to the law of conservation of momentum:

Total Momentum Before Collision = Total Momentum After Collision

m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

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Sorry this is a year late, but here it is for those of you who are stuck on the same thing.

NOTE: Please Check and Confirm That You Are On The Same Assignment with The Same Questions and Number of Questions. Thank You and Good Luck!

1. Mass & velocity

2. The total momentum after the collision is the same as the total momentum before the collision.

3. 0.54 kg⋅m/s

4. The system has external forces, such as friction and air resistance, acting on it.

5. 3.0 m/s

Answer:

10.83 Amperes

Explanation:

if   A ⇒ current

W = VA

1300 = 120 x A

1300 / 120 = A

10.83 = A

The moment of inertia of the wheel is 4.27 kg.m²

The kinematics equation explains the variables associated and related of motion.

From the information given, applying the kinematic equation of motion to determine the acceleration of the block, we have:

[tex]\mathbf{y = ut + \dfrac{1}{2}at^2}[/tex]

[tex]\mathbf{y = (0)t + \dfrac{1}{2}at^2}[/tex]

[tex]\mathbf{y = \dfrac{1}{2}at^2}[/tex]

Making acceleration (a) the subject, we have:

[tex]\mathbf{a = \dfrac{2y}{t^2}}[/tex]

where;

[tex]\mathbf{a = \dfrac{2\times 1.5 }{2.0^2}}[/tex]

a = 0.75 m/s²

The angular acceleration of the wheel can be estimated by the formula:

[tex]\mathbf{\alpha = \dfrac{a}{r}}[/tex]

[tex]\mathbf{\alpha = \dfrac{0.75 \ m/s^2}{0.40 \ m}}[/tex]

[tex]\mathbf{\alpha = 1.875 \ rad/s^2}[/tex]

Finally, the torque acting on the wheel is:

[tex]\mathbf{\tau = I \alpha}[/tex]

[tex]\mathbf{Tr = I \alpha}[/tex]

where;

∴

[tex]\mathbf{I =\dfrac{T\times r}{\alpha} }[/tex]

[tex]\mathbf{I =\dfrac{20 \ N\times 0.40 \ m}{1.875 \ rad/s^2} }[/tex]

I = 4.27 kg.m²

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