A stone is dropped from rest at an initial height h above the surface of the earth. Show that the speed with which it strikes the ground is v= 2gh.
Let x(t) be the position of the stone above the ground.
The differential equation x'= - g relates the position of the stone to the acceleration due to gravity.
Differential Equation DefinitionA differential equation is an equation which contains one or more terms and the derivatives of one variable (i.e., dependent variable) with respect to the other variable (i.e., independent variable)
dy/dx = f(x)
Here “x” is an independent variable and “y” is a dependent variable
For example, dy/dx = 5x
A differential equation contains derivatives which are either partial derivatives or ordinary derivatives. The derivative represents a rate of change, and the differential equation describes a relationship between the quantity that is continuously varying with respect to the change in another quantity. There are a lot of differential equations formulas to find the solution of the derivatives.
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A bullet of mass 10 g strikes a ballistic pendulum of mass 2.0 kg. the center of mass of the pendulum rises a vertical distance of 12 cm. assuming that the bullet remains embedded in the pendulum, calculate its initial speed
a. 425 ms
b. 256 ms
c. 321 ms
d. 308 ms
It's initial speed is 308 m/s.
The kinetic energy of the bullet is converted to potential energy for the whole system therefore we have:
[tex]\frac{1}{2}(m_{1} + m_{2} )V^{2} = (m_{1} + m_{2} )gh[/tex]
i.e. [tex]V = \sqrt{2gh}[/tex]
Now by conservation of momentum,
[tex]m_{1} v = (m_{1}+ m_{2} )V[/tex]
[tex]v = (m_{1}+ m_{2} )V / m_{1}[/tex]
[tex]v = (m_{1}+ m_{2} )\sqrt{2gh} / m_{1}[/tex]
Where,
v = initial speed
m1 = mass of pendulum = 2 kg
m2 = mass of bullet = 10 g = 0.01 kg
h = vertical distance = 12 cm = 0.12m
Putting these values in above equation we get : V = 308 m/s
Conservation of momentum is a crucial law of physics. It expresses that the total momentum of a detached or isolated system/framework is conserved. As such, the total momentum of a system of objects stays steady during any interaction, if no external force follows up on the system.To know more about kinetic energy visit:
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Which of the following agents or mechanisms are not testable, and therefore cannot provide a scientific explanation:
Earth's magnetic field
Global warming
Birth rates
*Spiritual beliefs
Genetic code
The agents or mechanisms which are not testable, and therefore cannot provide a scientific explanation are spiritual beliefs.
Spiritual beliefs pertain to an existentialist view of life, death, and the essence of existence and involve a connection to a higher power. These beliefs also include ceremonies and behaviours like meditative practices or prayer as well as interaction with other believers.
Global warming is the gradual heating of the Earth's surface that has been seen ever since pre-industrial era (between 1850 and 1900), and is attributed to human activity, particularly the combustion of fossil fuels, which raises the concentrations of heat-trapping greenhouse gases.
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The basketball passed through the hoop even though it barely cleared the hands of the player B who attempted to block it Suppose that s 4.5 ft . Neglect the size of the ball. (Figure 1) Part A Determine the magnitude vA of its initial velocity Express your answer to three significant figures and include the appropriate units Value Units Submit Request Answer ▼ Part B Determine the height h of the ball when it passes over player B Express your answer to three significant figures and include the appropriate units
A) The initial velocity of the ball is 20.14 m/s, B) the height of the ball when it passes over player B is 11.36 ft.
Let the initial velocity of the basketball, = v
Horizontal component, = vcos30 = 0.866 v
Vertical component, = vsin30 = 0.5 v
Horizontal distance travelled by the ball, H = 25 + 4.5 = 29.5 ft
We know vcos30 × t = 29.5
vt = 29.5/0.866 = 34.06 ft
vt = 34.06
Now by the third equation of motion, vertical height(10 - 7 =3 ft) travelled by the vertical component of the ball
(10 - 7) = vsin30 × t - 0.5gt²
3 = 0.5vt - 0.5 × 9.81 × t²
we know vt = 34.06
3 = 0.5 × 34.06 - 4.9t²
t = 1.69 sec
So, v = 34.06/1.69 = 20.14 m/s
Now part B,
Height of the ball above the player B, = h
horizontal range, R = 25 ft
Time taken to reach 25 ft = 25/(20.14 cos30)
= 25/17.44 = 1.43 sec
vertical distance travelled by the ball in 1.43 sec,
d = 20.14×sin30×1.43 - 0.5 × 9.81 × 1.43²
d = 4.37 ft
Total height above the ground, H = 7 + 4.37 = 11.34 ft.
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A constant net force, F net is applied to a cart with mass,m, causing an acceleration,a. If the mass of the cart is doubled, but the net force remains the same, what will the acceleration of the car be?
The acceleration of the car if the mass of the cart is doubled is ½a (option A).
How to calculate acceleration?Acceleration refers to change of velocity with respect to time (can include deceleration or changing direction).
Newton's first law of motion explains the relationship between the mass, force and acceleration of a body using the following expression;
Force = mass × acceleration
Mass and acceleration of a body are indirectly related. This means that if mass increases, acceleration decreases, hence, the acceleration in this question will decrease by half i.e. ½a.
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the shaft is supported by a smooth thrust bearing at b and a journal bearing at c. determine the resultant internal loadings acting on the cross section at e. suppose that p1
Determine the normal force, shear force and moment at a section passing through (a) point C, which is just to right of bearing at A, and (b) point D, which is just to the left of the Force F2.
What is thrust bearing ?
Thrust bearings support the axial thrust of both horizontal and vertical shafts. The functions are to prevent the shaft from drifting in the axial direction and to transfer thrust loads applied on the shaft.A thrust bearing is a bearing which allows parts to rotate with little friction whilst absorbing an axial thrust. The single plate dry clutch, with ball thrust bearing, is assembled with the engine and three-speed gearbox. A thrust bearing must be used to control end thrust.These thrust bearings are located at a specific main bearing location, generally at the center main or rear main, depending on engine design. A thrust bearing is either integrated with a specific main bearing assembly or independent of the main journal bearing.To learn more about shaft refers to:
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demonstrate a voltage measurement across one of the leds using the digital multimeter (dmm). to make this measurement, turn the dial on the dmm to voltage. place the dmm black test lead on the led cathode terminal and the red lead on the led anode terminal. if this is done correctly, your dmm should display the threshold value of your led.
To measure the voltage across an LED using a digital multimeter (DMM), follow these steps:
1. Turn the dial on the DMM to the voltage measurement setting.
2. Place the DMM black test lead on the LED cathode terminal and the red lead on the LED anode terminal.
3. The DMM should display the threshold voltage of the LED.
It is important to note that the cathode is the negative terminal, and the anode is the positive terminal of the led.
What is electric potential difference?Electric potential energy per unit charge in an electrical circuit is measured by voltage, sometimes referred to as electric potential difference. It is commonly measured in units of volts (V). Voltage is the force that causes electric current to flow in a circuit, and it can be thought of as the "pressure" that pushes the electrons through the circuit.
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the 10 ib weight is supported by the cord ac and roller and by a spring. if the spring has an unstreftched length of 8 in. and the weight is in equilibrium when d
The Spring constant k (Stiffness ) will be 6.8 Ib/in for the spring which has an unstretched length of 8 in for 10 lb when d = 4in as given in the problem.
As shown in the picture attached the net force on the y-axis is 0. And Fab*4/[tex]\sqrt{160\\}[/tex]} = 10
Fab = 31.61 Ib.
Fab = K(L-L0)
31.62 = k ([tex]\sqrt{160}[/tex] -8 => 6.8 Ib/in
As spring force is a conservative force where each spring has its own k(Spring constant ) which depends upon the material, Turns, and Size of the spring. To calculate Spring force F = -kx, where k is constant and x, is the length displayed by the force (Stretched or unstretched). The Force might be affected by the temperature around as of material used for making the spring.
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a point charge of 0.06 c is located at coordinate (0, 0). which of the following statements is true about the components of the electric field at coordinate (2.3, -4.1) produced by this charge? select the correct answer
A point charge of 0.06 c at coordinates (0, 0) will create an electric field at coordinates (2.3, -4.1), which will be directed away from the charge and whose magnitude will decrease as distance from the charge rises.
A point charge generates an electric field that is inversely proportional to the square of the distance from the charge. The electric field at that location will have non-zero x and y components because the point charge is at coordinate (0, 0) and the field is being assessed at coordinate (2.3, -4.1). As the distance from the charge grows, the magnitude of the electric field will diminish. The vector pointing from charge to the location where we wish to locate the E-field may be used to calculate the direction of the electric field at (2.3,-4.1).
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5. A cue ball with mass m = 0.25 kg moves with a velocity v = 66 m/s. It strikes a stationary eight ball (mass = 0.25 kg) and
projects it into a comer pocket. At what speed does the eight ball leave the collision?
Answer:
66 m/s
Explanation:
Since momentum of the body is conserved
mv=mv
0.25 kg×66m/s=0.25 kg×v
v =0.25kg×66m/s
0.25 kg
v =66m/s
which of the labeled parts of the microscope would you adjust to move your specimen left, right, forward, and backward?
The labeled parts of microscope that you would adjust to move the specimen left, right, forward, and backward are called the stage controls.
What is microscope?Microscope is an instrument that is used to observe small objects, even the cells. The lens bends light toward the eye and makes object appear larger than it actually is.
The stage controls consist of two knobs, one for moving the specimen left and right (x-axis), and one for moving specimen forward and backward (y-axis). The knobs are located on the lower part of the microscope's base, near stage where the specimen is placed. These controls allow you to position specimen correctly under the objective lens for observation.
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which statement shows that the newly diagnosed astham patient understands how to use a peak expiratory flow meter (pefm)? hesi
"I understand how to properly use the PEFM to measure my peak expiratory flow and will use it daily to track my lung function," the newly diagnosed asthmatic states in the statement.
Option B is correct.
What is a PEFM (peak expiratory flow meter)?A peak flow meter measures how quickly you can expel air from your lungs by blowing as forcefully and quickly as you can. This is what peak flow means.
This drop indicates the possibility of an asthma attack. You can figure out what "triggered" the drop in blood pressure by measuring your peak flow, which medications to add or take off, and when you might need emergency care.
A peak flow meter is simple to use. How to figure out your peak flow:
either sit down or stand tall. Regardless of your choice, ensure that you always follow this procedure.Make sure the red marker is at the base of the meter.Breathe deeply until your lungs are full to the brim.Place the mouthpiece in your mouth. Seal your lips tightly onto the peak flow meter mouthpiece.Expel all of the air with one blow as quickly and forcefully as possible.Make a note of the number by the red marker on the meter.Returning the red marker to the peak flow meter's bottom after performing these actions three timesThe reading that is the highest of these three is your daily peak flow.Question incomplete:which statement shows that the newly diagnosed asthma patient understands how to use a peak expiratory flow meter (pefm)?
A. Wear gloves during blood glucose monitoring and during any other procedure that involves potential exposure to blood or body fluids.
B. "I understand how to properly use the PEFM to measure my peak expiratory flow and will use it daily to track my lung function."
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Can anyone please help me answer this question?
A body of mass 5 kg, projected at an angle 60 degrees from the ground at an initial velocity of 25 m/s, acceleration due to gravity is 10 m/s^2. What is the maximum horizontal range covered?
a.) 54.13 m b.) 49 m c.) 49.16 m d.) 60 m. Explain.
Answer:
a) 54.13m
Explanation:
The formula for horizontal range is R = v2 (sin 2θ)/g. Here, v = 25, θ = 60°, g = 10. Hence, on solving we will get range as 54.13 m.
determine the average normal stress developed in rod ab if the load has a mass of 56 kg . the diameter of rod ab is 8 mm .
The gratis diagram idea, force equilibrium, arrive at a solution. To find the stress in rod AB, first design a model of the free items but then apply equilibria. Next, calculate the stress using the rod's diameter and force.
Definition of diametera straight line that cuts through the middle of a body or figure. especially: the distance along a line passing thru the center of the circle and having its endpoints on the circumference.
Definitions of diameter and circumferenceA circle's circumference is indeed the width of one full "lap," and its diameter is indeed the length of line segment that divides it in half. Imagine that diameter is an interior measurement, whereas circumference is an outside measurement.
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Suppose we imagine the Sun to be about the size of a grapefruit. Which of the following describes the size and distance of Earth on the same scale? Select the right answer A. Earth is the size of a marble about 25 miles away from the Sun. B. Earth is the size of a tip of a ballpoint pen about 15 meters away from the Sun.
C. Earth is the size of a tip of a ballpoint pen about 1 meter away from the Sun. D. Earth is the size of a golf ball about 15 meters away from the Sun. E. Earth is the size of a golf ball about 1 meter away from the Sun.
The correct option is B. Earth is the size of the tip of the ballpoint pen about 15 metres away from the Sun.
Radius of the sun = 7× 10⁸ m
Radius of the earth = 6.37 × 10⁶ m
Radius of the grape fruit = 7.6 × 10⁻² m
As the sun is said to be the size of the grapefruit, scale = (7.6 × 10⁻²)/(7× 10⁸) = 10⁻¹⁰
This means the scale is approximately, 1: 10⁻¹⁰
So, the size of the earth = 6.37× 10⁶ ×10⁻¹⁰ = 6.37×10⁻⁴ m (size of ballpoint)
As we know that the distance between the sun and the earth = 14.9 × 10¹⁰ m
So, in our scale, distance between the sun and the earth = 14.9× 10¹⁰× 10⁻¹⁰ = 14.9 m
which is approximately 15 meters.
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the apparatus above is used to study conservation of mechanical energy. a spring of force constant 40 n/m is held horizontal over a horizontal air track, with one end attached to the air track. a light string is attached to the other end of the spring and connects it to a glider of mass m . the glider is pulled to stretch the spring an amount x from equilibrium and then released. before reaching the photogate, the glider attains its maximum speed and the string becomes slack. the photogate measures the time t that it takes the small block on top of the glider to pass through. information about the distance x and the speed v of the glider as it passes through the photogate are given below.
The reason for the modest preference for 1/2 kx2 is that you only need to measure one variable—the displacement x—in order to identify the stored energy. Utilizing 1/2 F/x necessitates measuring both displacement and force, which is frequently difficult to do.
Do kinetic and potential energy in a spring have the same value?When a spring is stretched x distances from its equilibrium point and its mass is moving with velocity v, the spring's kinetic energy and elastic potential energy are equal, or 1/2mv2 = 1/2kx2.The restoring force indicated by Hooke's Law is propelled by spring potential energy, a store of energy. When calculating the spring potential energy, U=1/2kx2—the equation for the potential energy function—instead of Hooke's Law—is essentially utilized.The reason for the modest preference for 1/2 kx2 is that you only need to measure one variable—the displacement x—in order to identify the stored energy. Utilizing 1/2 F/x necessitates measuring both displacement and force, which is frequently difficult to do.To learn more about displacement refer to:
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a small block of mass m slides on a horizontal frictionlesssurface as it travels around the inside of a hoop of radiusr. the coefficient of friction between the block and the wallis u; therefore, the speed v of the block decreases. in termsof m, r, u, and v, find expressions for each of thefollowing.
The expressions are [tex]F = m g[/tex] , [tex]F = \frac{m v^{2} }{r}[/tex].
The frictional force: This force opposes motion and is created as a result of friction between two surfaces.
[tex]F = m g[/tex]
where m is the object's mass and g is the acceleration brought on by gravity, is a formula for expressing the frictional force.
The centripetal force: To keep an object moving in a circular path, the centripetal force, which is directed toward the centre of the path, must be present.
[tex]F = \frac{m v^{2} }{r}[/tex]
where m is the object's mass, v is its speed, and r is its circular path's radius, is a formula for the centripetal force.
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when rotating the device 360 degrees, as long as the does not extend outside the base of stability, the apparatus should remain stable. group of answer choices aerial device gravity circle box stabilizer jackknifed trailer
When rotating the device 360 degrees, as long as the does not extend outside the base of stability, the apparatus should remain stable: gravity circle.
What is the Centre of GravityThe Centre of gravity is a theoretical point in the body where the body’s total weight is thought to be concentrated. It is important to know the centre of gravity because it predicts the behaviour of a moving body when acted on by gravity. It is also useful in designing static structures such as buildings and bridges.
In a uniform gravitational field, the centre of gravity is identical to the centre of mass. Yet, the two points do not always coincide. For the Moon, the centre of mass is very close to its geometric centre. However, its centre of gravity is slightly towards the Earth due to the stronger gravitational force on the Moon’s near side.
In a symmetrically shaped object formed of homogenous material, the centre of gravity may match the body’s geometric centre. However, an asymmetrical object composed of various materials with different masses is likely to have its centre of gravity located at some distance away from its geometric centre. In hollow bodies or irregularly shaped bodies, the centre of gravity lies at a point external to the physical material.
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A long distance runner has an average speed of 3.4 m/s. How far (in m) does the runner travel in 20 min?
imagine you looked up the accelerations of the following objects: snails, humans, thomson's gazelles, the space shuttle, formula one race cars, and f-16 fighter jets. which of the following statements about the acceleration of a cheetah would you expect to be true?
The acceleration of a cheetah is higher than that of a Thomson's gazelle but lower than that of the space shuttle during takeoff.
What is the most straightforward explanation of acceleration?The amount upon which velocity decreases is known as accelerate. Acceleration typically indicates that the speed is changing, but not necessarily. An item that is moving in a circle while maintaining a constant speed is still accelerating because the direction of its motion is shifting.
What exactly is acceleration?The measurement of a change in an object's velocity is known as acceleration. A car accelerates faster and quicker when the gas pedal is depressed. Acceleration is indicated by this change in velocity.
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The Earth's orbit around the Sun is almost circular. Therefore, Earth receives about the same amount of year-round _______. a. heat and light
b. heat and precipitation
c. light and precipitation
The Earth's orbit around the Sun is almost circular, therefore, Earth receives about same amount of year-round a.) heat and light
What is meant by earth's orbit?Earth's orbit defines a two-dimensional plane which we call the ecliptic. It takes almost 365 days for the Earth to go around the Sun once.
The Earth's orbit around the Sun is almost circular, Thus, Earth receives about the same amount of year-round sunlight (or known as solar energy).
Earth's orbit is not a perfect circle and is elliptical, or slightly oval-shaped. This means that there is one point in the orbit where Earth is closest to the Sun, and one where Earth is farthest from the Sun.
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calculate the power required of a 60- kg person climbs a tree 5 meters high in 10 seconds. Acceleration due to gravity is 10 m/s 2.
The Power is equal to 300 J/s or 300 Watts.
A force that causes a displacement is what the term "quantity work" refers to. The duration of this force's action to produce the displacement has nothing to do with work or power. Sometimes the task is completed quite fast, and other times it is completed fairly slowly. For instance, it takes an unusually long time for a rock climber to raise her body a few meters up the cliff's edge. A trail hiker, on the other hand, could quickly raise her body a few meters if she chooses the simpler route up the mountain. Even though they both perform the same amount of labor, the hiker completes it in a lot less time than the rock climber.
The formula for power is ( P = [tex]\frac{W}{t}[/tex] ) or ( P = [tex]\frac{m \times a \times d}{t}[/tex] )
m ( mass ) = 60 kg
a ( acceleration ) = 10 m/s²
d ( distance ) = 5 m
t ( time ) = 10 s
P ( Power ) = ?
P = [tex]\frac{m \times a \times d}{t}[/tex]
= [tex]\frac{60\times 10 \times 5}{10}[/tex]
= [tex]\frac{3000}{10}[/tex]
= 300 J/s
= 300 Watts
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assume that a person skiing high in the mountains at an altitude of 15,000 ft takes in the same volume of air with each breath as she does while walking at sea level. determine the ratio of the mass of oxygen inhaled for each breath at this high altitude compared to that at sea level.
The ratio of the mass of oxygen inhaled for each breath at high altitude and at sea level is 0.629.
Let the mass of oxygen inhaled at sea level, = m₀
Let the mass of oxygen inhaled at 15000 ft, = m₁₅
The volume of air inhaled is same for both case, = v
Density of the air at mean seal level, ρ₀ = 2.337 × 10⁻³ sl/m³
Density of the air at 15000 ft, ρ₁₅ = 1.469 × 10⁻³ sl/m³
m₀ = ρ₀V, m₁₅ = ρ₁₅V
m₁₅/m₀ = ρ₁₅V/ρ₀V
m₁₅/m₀ = (1.469 × 10⁻³)/(2.337 × 10⁻³)
m₁₅/m₀ = 0.629
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A car weighs 15,000 n and its tires are I flared to a pressure of 190 kPa. How large is the area of the cars tires that are in contact with the road
From pressure definition, the area of the car tires that are in contact with the road is 0.079 m
What is Pressure ?Pressure can be defined as the ratio of force to area. It is measured in Pascal.
Given that a car weighs 15,000 N and its tires are I flared to a pressure of 190 kPa. How large is the area of the cars tires that are in contact with the road ?
From the definition of Pressure, P = F/A
Where
P = 190 KPaF = 15,000 NA = ?190000 = 15000/A
A = 15000/190000
A = 0.079 m
A car will have 4 tires. The area of one in contact with the road will be
A = 0.079/4
A = 0.02 m
Therefore, the area of the car tire that is in contact with the road is 0.02 m
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find an expression for the oscillation frequency of an elec tric dipole of dipole moment 17 and rotational inertia i for small amplitudes of oscillation about its equilibrium position in a uni form electric field of magnitude e.
The frequency would be 1/2pi [tex]\sqrt{\frac{pE}{I}}[/tex].
We know that,
Tau=-pEsinФ captures the sense
and the size of the effect.
This is the restoring torque to return the tilted dipoles to their aligned equilibrium position.
If the amplitude of movement is small,
we may replace sinθ with θ in radians.
Thus τ≈−pEθ.
Since this has a simple negative proportionality to the angle of rotation, the dipole oscillates in a simple harmonic motion,
like a torsion pendulum with a torsion constant
κ=pE. In this case, angular frequency ω is given by
ω² = [tex]\frac{k}{I}[/tex] = [tex]\frac{pE}{I}[/tex]
where I denotes thee rotational inertia of the particular dipole. The frequency of oscillation is
f= ω/ 2pi
= 1/2pi [tex]\sqrt{\frac{pE}{I}}[/tex]
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Distance and Displacement Worksheet
Answer:
two hunnid fornd qlojm qksil coo looo woo
Explanation:
foe nem
Which subatomic particles contribute to the mass of an atom
Answer:
Only protons and neutrons contribute to the mass of an atom.
Explanation:
Can anyone please help me answer this question?
An object moving in a straight line has a velocity v in m/s that varies with time t in s according to the following function.
v = 8 + 2.5 t2
11. The instantaneous acceleration of the object at t = 2 s is
(A) 2 m/s2 (B) 4 m/s2 (C) 6 m/s2 (D) 8 m/s2 (E) 10 m/s2
12. The displacement of the object between t = 0 and t = 6 s is
(A) 120 m (B) 180 m (C) 228 m (D) 242 m (E) 260 m
Show working
A researcher wants to see if alcohol consumption will enhance driving performance. One group of participants drinks no
alcohol during the study, one group drinks 3 shots of alcohol, and another group receives 6 shots of alcohol. Participants are
tested in a driving simulator after and get a score for accuracy. The amount of alcohol consumed is the
a. dependent variable
b. independent variable
c. correlated variable
d. control variable
The amount of alcohol consumed will be b. independent variable when participants are tested in a driving simulator after and get a score for accuracy.
What is an Independent variable?
An independent variable is a variable that is manipulated or changed by the researcher in an experiment in order to observe its effect on the dependent variable. In other words, it is a variable that the researcher has control over and changes to test its impact on the outcome.
In this case, the independent variable is the amount of alcohol consumed, as the researcher is manipulating this variable to see how it affects driving performance (the dependent variable).
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base your answer to the following question on the cross section below, which shows the type of seismic waves recorded at various locations after an earthquake has occurred. point a is a location on earth's surface and x is the epicenter of the earthquake. syvum
The P-waves are the primary waves that are the fastest and the first to arrive at the seismometer.
Seismic waves, which are vibrations caused by the movement of the Earth's crust, are recorded at various locations after an earthquake has occurred. The type of seismic waves recorded at a particular location depends on its distance from the epicenter (point X) of the earthquake.
There are two main types of seismic waves: body waves and surface waves. Body waves, such as P-waves and S-waves, travel through the Earth's interior and can be recorded at any location. Surface waves, such as Love waves and Rayleigh waves, travel along the Earth's surface and are typically recorded closer to the epicenter.
The P-waves are the primary waves that are the fastest and the first to arrive at the seismometer. The S-waves are the secondary waves that are slower and arrive later than P-waves.
In general, the closer a location is to the epicenter, the stronger and more frequent the seismic waves will be.
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A crane uses 19000 watts of power to lift a 6200 kg chunk of metal in a certain amount of time, how much
power will he use to do the same amount of work in three times the time?
er
Power (in watt) will he use to do the same amount of work in three times the time:
m=100 kgg=10 m/sh=10 m
W=mgh=100×10×10=10000 J
P= t/W
10000/20
=500 W
What is watt?Watt is a unit of power or radiant flux in the International System of Units, equivalent to 1 joule/second or 1 kg⋅m²⋅s⁻³. It is used to quantify the energy transfer rate. The watt (abbreviated W) is the standard International System of Units (SI) unit of power (energy per unit of time) equal to one joule per second. Watts are used to indicate the rate at which electrical energy is dissipated, or electromagnetic energy is radiated, absorbed, or dissipated.Watt is defined as 1 watt = 1 joule per second (1W = 1 J/s), meaning 1 kW = 1000 J/s. A watt is the amount of energy (in joules) that an electrical device (such as a light) consumes per second while in operation. So a 60W light bulb consumes 60 Joules of energy per second.To learn more about watt from the given link:
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