Answer:
30w
Explanation:
7. The binary addition 1 + 1 + 1 gives
11 [2-bit]
011 [3-bit]
0011 [4-bit]
________
1 + 1 + 1 = 3
________
3 = 2 + 1
2¹ 2⁰
3 = (.. × 0) + (2¹ × 1) + (2⁰ × 1)
3 = ..011
Since 2³, 2⁴, 2⁵, .. are not used, they are represented as 0.
[ 2⁷ 2⁶ 2⁵ 2⁴ 2³ 2² 2¹ 2⁰ ]
[ 128 64 32 16 8 4 2 1 ]
After adding refrigerant to a nonpressurized container used with a system-dependent recovery
device, the pressure of the container will:
Select one:
A. Increase to the saturation point.
B. Remain at 0 psig.
C. Increase in proportion to the amount of refrigerant added.
D. Decrease in proportion to the refrigerant added.
There are different aspect to system-dependent recovery equipment. The pressure of the container will Increase to the saturation point.
System-dependent is known to be a passive recovery system. It is known as the recovery of refrigerant from a system by using the refrigeration system's internal pressure and/or compressor so as to simulate the recovery process.
System-dependent equipment is not used used with appliances that has more than 15 pounds of refrigerant.
When refrigerant pressure increases, saturation temperature is known to also increases and as pressure decreases, the saturation temperature will also decrease. Saturation is known to have a pressure-temperature relationships for all refrigerants.
Learn more about saturation from
https://brainly.com/question/4529762
La fuerza necesaria para girar los birlos de una llanta es de 40 N, si se tiene una cruceta de 0.5m. ¿Cuál es el torque del birlo?
To Find :
The torque of the stud.
Solution :
We know, torque can be calculated by force and distance between the center and force applied.
So,
[tex]\tau = F\times R\\\\\tau = 40 \times 0.5 \ N .\ m\\\\\tau = 20 \ N .\ m[/tex]
Therefore, the torque on the stud is 20 N m .
A steel plate of width 120mm and thickness of 20mm is bent into a circular arc radius of 10. You are required to calculate the maximum stress induced and the bending moment which will give the maximum stress. You are given that E=2*10^5
Answer:
Hence the magnitude of the pure moment m will be [tex]2\times 10^5.[/tex]
Explanation:
Width of steel fleet = 120 mm The thickness of steel fleet = 10 mm Let the circle of radius = 10 mNow,
We know that,
[tex]\frac{M}{I} = \frac{E}{R}[/tex]
Thus, [tex]M =\frac{EI}{R}[/tex]
Here
R = 10000 mm
[tex]I=\frac{1}{12}\times 120\times 10^{3}\\= 10^{4} mm^{4}[/tex]
[tex]E=2\times 10^{5}n/mm^{2}\\\\E=2\times 10^{5}n/mm^{2}\\\\M={(2\times 10^{5}\times 10^{4})/{10000}}\\\\M=2\times 10^{5}[/tex]
Hence, the magnitude of the pure moment m will be [tex]2\times 10^5.[/tex]