A SOUND WAVE WITH ITS CHARACTERISTIC PATTERN OF COMPRESSIONS AND
RAREFACTIONS IS SHOWN BELOW. A CENTIMETER RULER IS INCLUDED BELOW THE
PATTERN THE WAVELENGTH OF THIS SOUND WAVE IS HOW MANY cm?
A 2 cm
B 3 cm
C 35 cm
D. 85 cm
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Answers

Answer 1

Answer:

The wavelength is 1.7cm

Explanation:

Given

See attachment for wave pattern

Required

What is the wavelength

To do this, we simply calculate the distance between successive waves (see attachment 2 for point A and B)

Using the ruler, points A and B are at:

[tex]A = 0.6cm[/tex]

[tex]B = 2.3cm[/tex]

So, the wavelength is:

[tex]\lambda = B - A[/tex]

[tex]\lambda = 2.3cm - 0.6cm[/tex]

[tex]\lambda = 1.7cm[/tex]

If approximated, the wavelength is:

[tex]\lambda \approx 2cm[/tex]

A SOUND WAVE WITH ITS CHARACTERISTIC PATTERN OF COMPRESSIONS ANDRAREFACTIONS IS SHOWN BELOW. A CENTIMETER
A SOUND WAVE WITH ITS CHARACTERISTIC PATTERN OF COMPRESSIONS ANDRAREFACTIONS IS SHOWN BELOW. A CENTIMETER

Related Questions

how dose storing waste underground can be effected by ground water in aquifers

Answers

Answer:

it can contaminate the water

Explanation:

I hope this helps ;)

I REALLY NEED HELP!!

The velocity of a car increases from +4.0 m/s to +16.0 m/s
in a time period of 4.0 s. What was the average
acceleration?

Answers

Answer:

Explanation:

Although we do have an equation for this in terms of one-dimensional motion, it's easy enough just to use the mathematical definition of acceleration:

[tex]a=\frac{v_f-v_0}{t}[/tex]  which says, in words, the acceleration of an object is equal to the objects final velocity minus its initial velocity, divided by the change in time. Since everything is given in m and s, our answer will be in m/s/s:

[tex]a=\frac{16.0-4.0}{4.0}[/tex] and

[tex]a=\frac{12.0}{4.0}[/tex] so

a = 3.0 m/s/s

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Answers

Answer:

im confused

Explanation:

wdym I am answering rn
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