A Sonometer wire of length
l vibrates at a
frequency of
350 Hz. when the length of the
wire is increased by 15cm, the
Wire Vibrates at 280 H₂ under
constant tension. Determine l
​

Answer:

dude the answer is upright

Answer:

Dakota moves a magnetic toy train toward a magnet that cannot move. What happens to the potential energy in the system of magnets during the movement? The potential energy increases because the train moves against the magnetic force. The potential energy decreases because the train moves against the magnetic force.

I hope this helps you :)

Answer:

Gravitational

Tension

Normal

Friction.

Explanation:

The forces acting on the sled are:

Tension: the tension from the rope, this is the force that "moves" the sled.

Friction: kinetic friction between the sled and the ground as the sled moves.

There are another two forces that also act on the sled, but that "has no effect"

Gravitational force: This force pulls the sled down, against the floor.

Normal force: This force "opposes" to the gravitational one, so they cancel each other.

These two forces cancel each other, so they have no direct impact on the movement of the sled. BUT, the friction force depends on the weight of the moving object, and the weight of the moving object depends on the gravitational force, so we need gravitational force in order to have friction force.

Then we can conclude that the forces acting on the sled are:

Gravitational

Tension

Normal

Friction.

Answer:

[tex]-18.43^{\circ}[/tex]

Explanation:

Let [tex]\theta[/tex] be the polar angle of −3i + j. We can find it using the formula as follows :

[tex]\tan\theta=\dfrac{y}{x}\\\\\tan\theta=\dfrac{1}{-3}\\\\\theta=\tan^{-1}(\dfrac{1}{-3})\\\\\theta=-18.43^{\circ}[/tex]

So, the required polar angle is [tex]-18.43^{\circ}[/tex].

Answer:

1920Joules

Explanation:

The formula for calculating the kinetic energy of a body is expressed as;

KE = 1/2 mv²

m isthe mass

V is the speed

For the two masses, the combined KE is expressed as;

KE  = 1/2(m1+m2)v²

KE = 1/2(45+15)(8)²

KE  = 1/2 * 60 * 64

KE  = 30 * 64

KE  = 1920J

Hence the combined kinetic energy of the boy and the bicycle is 1920Joules

The combined kinetic energy of the boy and the bicycle is of 1920 J.

Given data:

The mass of boy is, m = 45.0 kg.

The mass of bicycle is, M = 15.0 kg.

The speed of bicycle is, v = 8.00 m/s.

The kinetic energy of an object is defined as the energy possessed by an object by virtue of motion of object. The combined kinetic energy of the boy-bicycle system is given as,

[tex]KE = \dfrac{1}{2}(m+M)v^{2}[/tex]

Solve by substituting the values as,

[tex]KE = \dfrac{1}{2}(45+15) \times 8^{2}\\\\KE = 1920 \;\rm J[/tex]

Thus, we can conclude that the combined kinetic energy of the boy and the bicycle is of 1920 J.

Learn more about the concept of kinetic energy here:

https://brainly.com/question/12669551

Answer:2m/s^2

Explanation:

a=f/m

I think the answer would be A.

After all, it is 0 which is technically a dead center number meaning that the net should be balanced and still.

Hope this helps and have a nice day.

-R3TR0 Z3R0

Answer:

They will fall at the same time.  This is because gravity accelerates all objects at the same speed, Earth's gravity being approximately 9.8m/s²

They'll both fall at the same time. This is because gravity accelerates everything at the same rate, with Earth's gravity being approximately 9.8 m/s2.

To learn more about gravity, refer to:

https://brainly.com/question/16275567

#SPJ2

Answer:

Ocean-floor sediments can also be used to determine past climate. ... Ice cores contain more 16O than ocean water, so ice cores have a lower 18O/ 16O ratio than ocean water or ocean-floor sediments. Water containing the lighter isotope 16O evaporates more readily than 18O in the warmer subtropical regions

Explanation:

Answer:

conduction is the correct answer

Answer:

C. Nucleic Acids.

Explanation:

Nucleic acids are thus uniquely capable of directing their own self-replication, allowing them to function as the fundamental informational molecules of the cell. The information carried by DNA and RNA directs the synthesis of specific proteins, which control most cellular activities.

Did some simple research, if that's fine and I hope this is correct as it says on the sites. Have a good one :)

Answer:

water vapor

Explanation:

did assignment on edge

Answer:

Explanation:

because it is godhood

Answer:

12164.4 Nm

Explanation:

CHECK THE ATTACHMENT

Given values are;

m1= 470 kg

x= 4m

m2= 75kg

Cm = center of mass

g= acceleration due to gravity= 9.82 m/s^2

The distance of centre of mass is x/2

Center of mass(1) = x/2

But x= 4 m

Then substitute, we have,

Center of mass(1) = 4/2 = 2m

We can find the total torque, through the summation of moments that comes from both the man and the beam.

τ = τ(1) + τ(2)

But

τ(1)= ( Center of m1 × m1 × g)= (2× 470× 9.81)

= 9221.4Nm

τ(2)= X * m2 * g = ( 4× 75 × 9.81)= 2943Nm

τ = τ(1) + τ(2)

= 9221.4Nm + 2943Nm

= 12164.4 Nm

Hence, the magnitude of the torque about the point where the beam is bolted into place is 12164.4 Nm

Answer:

Mass = 18 kg

Explanation:

Formula for force in centripetal motion is;

F = mv²/r

We have;

Mass; m.

Speed; v = 3 m/s

radius; r = 1.8 m

Force; F = 90 N

Thus;

Making m the subject;

m = Fr/v²

m = 90 × 1.8/3²

m = 18 kg

Answer:

Break down small pebbles and sediments, like sand

Break down large rocks like mountains

Explanation:

Answer:

Kindly check explanation

Explanation:

Given the data:

Trial V (volts) I (mA)

1 1.00 7.2

2 2.10 14.0

3 3.10 20.7

4 4.00 27.2

5 4.90 32.2

Slope = Rise / Run

Rise = y2 - y1 = 32.2 - 7.2 = 25

Run = x2 - x1 = 4.9 - 1.0 = 3.9

Slope = 25 / 3.9 = 6.410

y = mx + c

The intercept, c

Take the point ( 1; 7.2)

Put x = 0

7.2 = 6.410(1) + C

7.2 - 6.410 = C

C = 0.79

Answer:

M = 0.31 kg

Explanation:

This exercise must be done in parts, let's start by finding the speed of the set arrow plus apple, for this we define a system formed by the arrow and the apple, therefore the forces during the collision are internal and the moment is conserved

let's use m for the mass of the arrow with velocity v₁ = 20.4 m / s and M for the mass of the apple

initial instant. Just before the crash

          p₀ = m v₁ + M 0

instant fianl. Right after the crash

          p_f = (m + M) v

          p₀ = p_f

          m v₁ = (m + M) v

          v =[tex]\frac{m}{m+M} \ v_1[/tex]                          (1)

now we can work the arrow plus apple set when it leaves the child's head with horizontal speed and reaches the floor at x = 8 m. We can use kinematics to find the velocity of the set

          x = v t

          y = y₀ + [tex]v_{oy}[/tex] t - ½ g t²

when it reaches the ground, its height is y = 0 and as it comes out horizontally, [tex]v_{oy} = 0[/tex]

          0 = h - ½ g t²

          t² = 2h / g

For the solution of the exercise, the height of the child must be known, suppose that h = 1 m

            t = [tex]\sqrt{ \frac{ 2 \ 1}{9.8} }[/tex]

            t = 0.452 s

let's find the initial velocity

             v = v / t

             v = 8 / 0.452

             v = 17.7 m / s

From equation 1

              v = m / (m + M) v₁

              m + M = [tex]m \ \frac{v_1}{v}[/tex]

              M = m + m \  \frac{v_1}{v}

we calculate

              M = 0.144 + 0.144  [tex]\frac{20.4}{17.7}[/tex]

              M = 0.31 kg

Answer:

you have to times them all ti get the answer

Answer:

1.B, 2.A

Explanation:

Answer:

[tex]\boxed{\text{\sf \Large 2.0 m/s^2 $}}[/tex]

Explanation:

Use acceleration formula

[tex]\displaystyle \text{$ \sf acceleration=\frac{change \ in\ velocity}{change \ in \ time} $}[/tex]

[tex]\displaystyle a=\frac{65-47}{12.0-3.0} =2.0[/tex]

Answer: 52 kg skydiver: 9.09 m/s and 522.55 s

              95 kg skydiver: 12.3 m/s and 386.2 s

Explanation: Drag Force is an opposite force when an object is moving in a fluid.

For skydivers, when falling through the air, the forces acting on it are gravitational and drag forces. At a certain point, drag force equals gravitational force, which is constant on any part of the planet, producing a net force that is zero. Since there is no net force, there is no acceleration and, consequently, velocity is constant. When that happens, the person reached the Terminal Velocity.

Drag Force and Velocity are proportional to the squared speed. So, terminal velocity is given by:

[tex]F_{G}=F_{D}[/tex]

[tex]mg=\frac{1}{2}C \rho Av_{T}^{2}[/tex]

[tex]v_{T}=\sqrt{\frac{2mg}{\rho CA} }[/tex]

where

m is mass in kg

g is acceleration due to gravitational force in m/s²

ρ is density of the fluid in kg/m³

C is drag coefficient

A is area of the object in the fluid in m²

Calculating:

The 52kg skydiver has terminal velocity of:

[tex]v_{T}=\sqrt{\frac{2(52)(9.8)}{(1.21)(0.7)(0.14)} }[/tex]

[tex]v_{T}=[/tex] 9.09

The 95kg skydiver's terminal velocity is

[tex]v_{T}=\sqrt{\frac{2(95)(9.8)}{(1.21)(0.7)(0.14)} }[/tex]

[tex]v_{T}=[/tex] 12.3

The 52 kg and 95kg skydivers' terminal velocity are 9.09m/s and 12.3m/s, respectively.

The time each one will reach the floor will be:

52 kg at 9.09 m/s:

[tex]t=\frac{4750}{9.09}[/tex]

t = 522.5

95 kg at 12.3 m/s:

[tex]t=\frac{4750}{12.3}[/tex]

t = 386.2

The 52 kg and 95kg skydivers' time to reach the floor are 522.5 s and 386.2 s, respectively.

Answer:

* roller skates and ice skates.

* roller coaster

Explanation:

One of the best examples for this situation is when we are skating, in the initial part we must create work with a force, it compensates to move, after this the external force stops working and we continue movements with kinetic energy, if there are some ramps, we can going up, where the kinetic energy is transformed into potential energy and when going down again it is transformed into kinetic energy. This is true for both roller skates and ice skates.

Another example is the roller coaster, in this case the motor creates work to increase the energy of the car by raising it, when it reaches the top the motor is disconnected, and all the movement is carried out with changes in kinetic and potential energy. In the upper part the energy is almost all potential, it only has the kinetic energy necessary to continue the movement and in the lower part it is all kinetic; At the end of the tour, the brakes are applied that bring about the non-conservative forces that decrease the mechanical energy, transforming it into heat.

Answer:

Absorbed sunlight is balanced by heat radiated from Earth's surface and atmosphere. ... The atmosphere radiates heat equivalent to 59 percent of incoming sunlight; the surface radiates only 12 percent. In other words, most solar heating happens at the surface, while most radiative cooling happens in the atmosphere

Answer:

 K_a = 8,111 J

Explanation:

This is a collision exercise, let's define the system as formed by the two particles A and B, in this way the forces during the collision are internal and the moment is conserved

initial instant. Just before dropping the particles

          p₀ = 0

final moment

          p_f = m_a v_a + m_b v_b

          p₀ = p_f

          0 = m_a v_a + m_b v_b

tells us that

          m_a = 8 m_b

           0 = 8 m_b v_a + m_b v_b

           v_b = - 8 v_a                    (1)

indicate that the transfer is complete, therefore the kinematic energy is conserved

starting point

           Em₀ = K₀ = 73 J

final point. After separating the body

          Em_f = K_f = ½ m_a v_a² + ½ m_b v_b²

           K₀ = K_f

           73 = ½ m_a (v_a² + v_b² / 8)

we substitute equation 1

           73 = ½ m_a (v_a² + 8² v_a² / 8)

           73 = ½ m_a (9 v_a²)

           73/9 = ½ m_a (v_a²) = K_a

            K_a = 8,111 J

Answer:

a) [tex]W=9810\: N[/tex]

b) [tex]F_{1}=251.14\: N[/tex]        

c) [tex]V_{g}=0.012\: m^{3}[/tex]

Explanation:

a)

El peso del cuerpo es:

[tex]W=mg[/tex]

g es la gravedad (9.81 m/s²)

[tex]W=1000*9.81[/tex]

[tex]W=9810\: N[/tex]

b)

Usando el principio de Pascal tenemos:

[tex]P_{1}=P_{2}[/tex]

y la presion es la fuerza sobre el area.

[tex]\frac{F_{1}}{A_{1}}=\frac{F_{2}}{A_{2}}[/tex]

Despejando F(1):

[tex]F_{1}=F_{2}\frac{A_{1}}{A_{2}}[/tex]

el area del plato es: [tex]A=\pi R^{2}[/tex]

[tex]F_{1}=F_{2}\frac{\pi R_{1}^{2}}{\pi R_{2}^{2}}[/tex]

[tex]F_{1}=F_{2}\frac{R_{1}^{2}}{R_{2}^{2}}[/tex]

F(2) es el peso del cuerpo de 1000 kg (W)

[tex]F_{1}=9810\frac{8^{2}}{50^{2}}[/tex]

Por lo tanto, la fuerza que se debe hacer es:

[tex]F_{1}=251.14\: N[/tex]          

c)

Como tenemos un sistema cerrado el volumen de agua que desciende por el embolo pequeño debe ser igual al que sube por el grande, por lo tanto:

[tex]V_{p}=V_{g}[/tex]

Vp es el volumen de agua en el émbolo pequeño

Vg es el volumen de agua en el émbolo grande

Como sabemos que son cilindros (V=πR²h)

[tex]\pi R^{2}h=V_{g}[/tex]

Entonces el volumen del émbolo mayor será:

[tex]V_{g}=\pi 0.08^{2}0.6[/tex]

[tex]V_{g}=0.012\: m^{3}[/tex]

Espero te haya sido de ayuda!

Answer: Closer to the Roche limit, the body is deformed by tidal forces. Within the Roche limit, the mass' own gravity can no longer withstand the tidal forces, and the body disintegrates. hope this helps can u give me brainliest

Explanation:

Answer:

The correct answer is:

(a) 0

(b) 0.5 m/s

(c) 7740 N

(d) 0

Explanation:

The given values are:

mass,

m = 3000 kg

Tension,

T = 7,200 N

Angle,

= 30°

(a)

Even as the block speed becomes unchanged, the kinetic energy (KE) will adjust as well:

⇒ [tex]\Delta K =0[/tex]

By using the theorem of energy, the net work done will be:

⇒  [tex]\Delta K =0[/tex]

(b)

According to the question, After 0.25 m the block is moving with the constant speed

= 0.5 m/s.

(c)

The given kinetic friction coefficient is:

u = 0.3

The friction force will be:

= [tex]u(mg-Tsin30^{\circ})[/tex]  

On substituting the values, we get,

= [tex]0.3[(3000\times 9.8)-(7200\times 0.5)][/tex]

= [tex]0.3[29400-3600][/tex]

= [tex]0.3\times 25800[/tex]

= [tex]7,740 \ N[/tex]

(d)

On including the friction,

The net work will be:

⇒ [tex]\Delta K=0[/tex]