A solution was made in a 200.00 mL volumetric flask consisting of 18.00 mL of 2.125 M HCl and 0.4104 grams of CaCO3, followed by adding enough water to bring the final volume up to the mark on the flask. A 15.00 mL sample of the solution was titrated with 0.1111 M NaOH to the equivalence point. How many mL of NaOH are used

Answers

Answer 1

Answer:

16.2mL of 0.1111M NaOH are used

Explanation:

volumetric flask of 250.0mL

As first, the HCl reacts with CaCO3 as follows:

2HCl + CaCO3 → H2O + CaCl2 + CO2

Where 2 moles of HCl react with 1 mole of CaCO3

To solve this question we must find the moles of each reactant in order to determine the moles of HCl that remains:

Moles HCl:

0.01800L * (2.125mol / L) = 0.03825 moles HCl

Moles CaCO3 -Molar mass: 100.09g/mol-

0.4104g * (1mol / 100.09g) = 0.00410 moles CaCO3

Moles HCl that reacts:

0.00410 moles CaCO3 * (2 mol HCl / 1 mol CaCO3) =

0.00820 moles HCl

Moles HCl that remains:

0.03825 moles HCl - 0.00820 moles HCl:

0.03005 moles HCl remains

The HCl reacts with NaOH as follows:

HCl + NaOH → H2O + NaCl

That means, to reach the equivalence point, the moles of NaOH that must be added = Moles HCl, in a sample of 15.00mL, the moles of HCl are:

0.03005 moles HCl * (15.0mL / 250.0mL) = 0.001803 moles HCl = Moles NaOH. The volume of 0.1111M NaOH is:

0.001803 moles NaOH * (1L / 0.1111moles) = 0.016L 0.1111M NaOH are required, that is:

16.2mL of 0.1111M NaOH are used

Related Questions

7 organic compounds of plant origin​

Answers

Answer:

carbohydrates, lipids, proteins and nucleic acids

1) ____C3H8 + ____O2 → ____CO2 + ____H2O

Answers

C3H8 + 5O2 → 3CO2 + 4H2O

what charge does copper have?

Answers

Answer: 1+charge

Explanation: hoped this helped:)

How many lone pairs are on the central atom of a molecule of RnCl4?
A. 0
B. 2
C. 3
D. 1

Answers

My teacher said it is c

How can you tell if an atom has a positive charge? What type of ion is this?

Answers

Answer:i love you

Explanation:

Answer: An atom can acquire a positive charge or a negative charge depending on whether the number of electrons in an atom is greater or less then the number of protons in the atom.  If the atom has more electrons than protons, it is a negative ion, or ANION. If it has more protons than electrons, it is a positive ion.

Explanation:

2) Using the following equation:

Water is added to iron and over time iron (III) oxide along with hydrogen gas is produced.

a. How many grams of iron (III) oxide will be produced when 15.5g of iron reacts with excess water?
b. Calculate the percent yield if your team produced 14.5g of iron (III) oxide.
c. If the reaction takes place under STP then how many liters of hydrogen gas are produced?

Answers

the answer is 133

because thats how the water is

What is the difference between 13.254 m/s and 7.7 m/s? Round your answer to the correct number of significant digits.

Answers

Answer:

5.6 m/s

Explanation:

Given,

First number = 13.254 m/s

Second number = 7.7 m/s

We need to find the difference between these two numbers. First we round off 13.254 to one decimal place i.e. 13.254 = 13.3 m/s

The difference between them is given by :

D = 13.3 - 7.7

= 5.6 m/s

Hence, the difference of the two numbers is 5.6 m/s.

In order to determine the magnetic properties of phosphorus atom we need to find out the number of unpaired electrons present in the ground state of phosphorus atom! Select one of the answers below that represents this number.
Group of answer choices

1

4

3

0

2

Answers

Answer:

Think of it this way If you have a phosphorus atom whats its oposites once you found that out you may be able to find the answer

Explanation:

Hope this helps :)

4 methyl 2 pentanone structural formula​

Answers

Answer:

(CH3)2CHCH2COCH3

Explanation:

An acetate buffer solution is prepared by combining 50. mL of 0.20 M acetic acid,
HC2H3O2(aq), and 50. mL of 0.20 M sodium acetate, NaC2H3O2(aq). A 5.0 mL sample of 0.10 M NaOH(aq) is added to the buffer solution.
Which of the following is a correct pairing of the acetate species present in greater concentration and of the pH of the solution after the NaOH(aq) is added? (The pKa of acetic acid is 4.7.)
Acetate Species -- pH
(A) HC2H3O2 -- < 4.7
(B) HC2H3O2 -- > 4.7
(C) C2H3O2 -- < 4.7
(D) C2H3O2 -- > 4.7

Answers

Answer:

The answer is "Option B".

Explanation:

[tex]\to CH_3COOH + NaOH \longleftrightarrow CH_3COONa + H_2O\\\\\to CH_3COONa + NaOH\longleftrightarrow CH3COONa\\\\\therefore \ mol\ NaOH = (5 \ E-3\ L)\times(0.10 \ \frac{mol}{L}) = 5 \ E-4\ mol\\\\[/tex]

[tex]\to mol\ CH_3COOH = (0.05 \ L)\times(0.20 \frac{mol}{L}) = 0.01 \ mol\\\\\to C \ CH_3COOH = \frac{(0.01 \ mol - 5 \ E-4\ mol) }{(0.105 \ L)}\\\\\to C \ CH_3COOH = 0.0905 \ M\\\\\therefore \ mol \ CH_3COONa = (0.05\ L )\times (0.20 \ \frac{mol}{L}) = 0.01 \ mol\\\\[/tex]

[tex]\to C \ CH_3COONa = \frac{(0.01\ mol + 5 \ E-4\ mol)}{(0.105\ L )}\\\\\to C \ CH_3COONa = 0.1 \ M\\\\\therefore Ka = ([H_3O^{+}]\times \frac{(0.1 + [H_3O^+]))}{(0.0905 - [H_3O^+])} = 1.75\ E-5\\\\\to 0.1[H_3O^+] + [H_3O^+]^2 = (1.75 E-5)\times (0.0905 - [H_3O^+])\\\\[/tex]

[tex]\to [H_3O^+]^2 \ 0.1[H_3O^+] = 1.584\ E-6 - 1.75\ E-5[H_3O^+]\\\\\to [H_3O^+]^2 + 0.1000175[H_3O^+] - 1.584 \ E-6 = 0\\\\\to [H_3O^+] = 1.5835\ E-5 \ M\\\\\therefore pH = - \log [H_3O^+]\\\\\to pH = - \log (1.5835 \ E-5)\\\\ \to pH = 4.8004 > 4.7[/tex]

If a gas is cooled from 343.0 K to 283.15 K and the volume is kept constant what final pressure would result if the original pressure was 760.0 mm HG?

Answers

Answer:

627.4 mmHg

Explanation:

From Gay-Lussac law:

[tex] \frac{p1}{t1} = \frac{p2}{t2} [/tex]

p1 = 760 mmHg

t1 = 343 K

t2=283.15 K

[tex]p2 = p1 \times \frac{t2}{t1} [/tex]

[tex]p2 = 760 \times \frac{283.15}{343.0} [/tex]

[tex]p2 = 627.4 \: mmhg[/tex]

If a gas is cooled from 343.0 K to 283.14 K and the volume is kept constant the final pressure would be 627.4 mm Hg if the original pressure was 760.0 mm Hg.

Gay-Lussac's Law

Gay-Lussac's law states that the pressure of a given mass of gas at a constant volume varies directly with the temperature of the gas.  Gay-Lussac's law defined the relationship between pressure and temperature of a gas when kept at a constant volume.

According to the Gay-Lussac's Law

P ∝ T       (When V = constant)

or, P = kT

or, [tex]\frac{P_1}{T_1} = \frac{P_2}{T_2}[/tex]

Here,

[tex]P_{1}[/tex] = 760.0 mm Hg,

[tex]T_{1}[/tex]= 343.0 K

[tex]T_{2}[/tex] = 283.15 K

Now put the values in above formula, we get

[tex]\frac{P_1}{T_1} = \frac{P_2}{T_2}[/tex]

[tex]\frac{760.0\ \text{mm Hg}}{343.0K} = \frac{P_2}{283.15\ K}[/tex]

[tex]P_{2} = \frac{760.0\ \text{mm Hg} \times 283.15\ K}{343.0\ K}[/tex]

[tex]P_{2} = \frac{215194\ \text{mm Hg}}{343}[/tex]

[tex]P_{2}[/tex] = 627.4 mm Hg

Thus, we can say that if a gas is cooled from 343.0 K to 283.14 K and the volume is kept constant the final pressure would be 627.4 mm Hg if the original pressure was 760.0 mm Hg.

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A piece of copper has a density of 8.96 g/cm3, what is the volume of a 4.2 g piece?

Answers

Answer:

0.47 cm³

Explanation:

[tex]Volume=Mass/Density\\[/tex]

Plug in the mass (4.2 grams) and the density (8.96 g/cm³)

[tex]Volume=4.2/8.96\\Volume=0.47[/tex]

Therefore, the volume of a 4.2 g piece of copper is approximately 0.47 cm³.

I hope this helps!

what do you mean by antibodies​

Answers

Ans: a blood protein produced in response to and counteracting a specific antigen. Antibodies combine chemically with substances which the body recognizes as alien, such as bacteria, viruses, and foreign substances in the blood.

Consider a iron-silver voltaic cell that is constructed such that one half-cell consists of the iron, Fe, electrode immersed in a Fe(NO3)3 solution, and the other half-cell consists of the silver, Ag, electrode immersed in a AgNO3 solution. The two electrodes are connected by a copper wire. The Fe electrode acts as the anode, and the Ag electrode acts as the cathode. To maintain electric neutrality, you add a KNO3 salt bridge separating the two half-cells. Use this information to solve Parts B, C, and D. Part B The half-cell is a chamber in the voltaic cell where one half-cell is the site of the oxidation reaction and the other half-cell is the site of the reduction reaction. Type the half-cell reaction that takes place at the anode for the iron-silver voltaic cell. Indicate the physical states of atoms and ions using the abbreviation (s), (l), or (g) for solid, liquid, or gas, respectively. Use (aq) for an aqueous solution. Do not include phases for electrons. Express your answer as a chemical equation.

Answers

Answer:

See explanation

Explanation:

In the voltaic cell, energy is produced by spontaneous chemical reaction. One half cell functions as the anode (in this case it is the Fe/Fe^2+ half cell) while the other half cell functions as the cathode (in this case it is the the Ag/Ag^+ half cell).

At the anode;

Fe(s) -----> Fe^2+(aq) + 2e

At the anode;

2Ag^+(aq) + 2e ------> 2 Ag(s)

Overall cell equation;

Fe(s) + 2Ag^+(aq)  ------> Fe^2+(aq) + 2 Ag(s)

What is the % Yield if 3.8 g of Cu was produced?

Answers

83.9 is the answer i’m pretty sure

If 18.0 g of CO2 is produced in the reaction of C2H2 with O2 to form CO2 and
H2O, how many grams of H20 are produced in this reaction?
O 3.68 g
9.0 g
14.7 g
None of the above
7.37 g

Answers

Answer:

3.68 g

Explanation:

[tex]n_{CO2}[/tex] = 18 ÷ 44 = 0.4

2C2H2 + 5O2 → 4CO2 + 2H2O

   2       :    5      :    4      :    2  

                             0.409                 (moles)

⇒ [tex]n_{H2O}[/tex] = 0.409 × 2 ÷ 4 = 0.2045 moles

⇒ [tex]m_{H2O}[/tex] = 0.2045 × 18 = 3.68 grams

Express the Following number in scientific notation with 3 significant figures:

450,000


[ ? ] x 10 to the power of ?

Answers

Answer:

4.50x10^5

Explanation:

dont forget the zero on the 4.50

a gas has a pressure of 0.470 atm at 60.0 C. What is the pressure at standard temperature?

Answers

Answer:

P2=0.385atm

Explanation:

step one:

Given that the temperature T1=  60 Celcius

we can convert this to kelvin by adding 273k to 60 Celcius

we have T1= 333k

pressure P1= 0.470 atm

step two:

we know that the standard temperature is T2= 273K

Applying the temperature and pressure relationship we have

P1/T1=P2/T2

substituting our given data we have

0.47/333=P2/273

cross multiply we have

P2= (0.47*273)/333

P2= 128.31/333

P2=0.385 atm

if u mix 10ml of 70%ethanol with 20ml of 80% ethanol with 50ml water what is the concentration of the resulted solution

Answers

Answer:

29% is the final concentration

Explanation:

To solve this question we must find the volume of ethanol added and the volume of the whole solution. The concentration will be:

Volume ethanol / Total volume * 100

Volume ethanol:

10mL * 70% = 7mL ethanol

+

20mL * 80% = 16mL ethanol

= 23mL ethanol

Total volume:

10mL + 20mL + 50mL = 80mL

Concentration:

23mL / 80mL * 100

= 29% is the final concentration

what are the isomers of hexane​

Answers

Physical properties

Isomer M.P. (°C) B.P. (°C)

n-hexane −95.3 68.7

3-methylpentane −118.0 63.3

2-methylpentane (isohexane) −153.7 60.3

2,3-dimethylbutane −128.6 58.0

1 more row

What type of matter do alloys fall under?
a) Element
b) Compound
c) Heterogeneous mixture
d) Homogeneous mixture

Answers

Answer:

An alloy is a homogeneous mixture

Explanation:

D

An alloy, a metallic substance composed of two or more elements, as either a compound or a solution is a homogeneous mixture. The correct option is d.

What is an alloy?

An alloy is a mixture of chemical elements of which at least one is a metal. Unlike chemical compounds with metallic bases, an alloy will retain all the properties of metal in the resulting material, such as electrical conductivity, ductility, opacity, and lustre, but may have properties that differ from those of pure metals, such as increased strength or hardness.

In some cases, an alloy may reduce the overall cost of the material while preserving important properties. In other cases, the mixture imparts synergistic properties to the constituent metal elements such as corrosion resistance or mechanical strength. Alloys are defined by a metallic bonding character. The alloy constituents are usually measured by mass percentage for practical applications, and in atomic fraction for basic science studies.

Alloys are usually classified as substitutional or interstitial alloys, depending on the atomic arrangement that forms the alloy.

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Draw the atomic structure with electronic configuration of Potassium​

Answers

Answer:

Explanation:

i try to help you

✧Kindly see the attached picture! ☄

♪ Hope I helped! ♡

[tex] \star[/tex] Best regards! ツ

☞ [tex] \underbrace{ \overbrace{ \mathfrak{Carry \: On \: Learning}}}[/tex] ✎

A cation with a +4 charge has 26 neutrons and 18 electrons. What is the identity of the element?

Answers

Answer: Titanium has 22 protons

Explanation:  If an atoms donates 4 electrons, it forms cation with charge +4. So original atom have 22 electrons and because atom is neutral, it has 22 protons. Number of neutrons does not matter, there are more neutrons than protons  in heavier atoms.

During the age of the dinosaurs, most mammals grew no bigger than a?

Answers

Answer:

T-rex

Explanation:

What is the pH of a solution that has a hydrogen ion concentration of 6.9*10^-4?

Answers

The pH would be 3.16 because the formula for finding the pH from a H± ion is pH = -log [H±]

So with that formula, you first have to substitute the H± with your numbers which in this case is 6.9 × 10^-4.

It should like this:

pH = -log (6.9 × 10^-4)

And lastly, just calculate.

pH = 3.16

Hope that helps, do let me know if you need more help in understanding this!

Calculate the pH and pOH of a solution of sodium hypoiodite NaOI, with a formal concentration of 0.05784 mol L-1. Note that the compound is soluble, dissolves into sodium and hypoiodite ions, and these react with water. The p K a of hypoiodous acid at 298 K is 10.64. Calculate the pH and the pOH of the resulting solution. Use all the approximations you can, be sure to verify them.

Answers

Answer:

pH = 11.70

pOH = 2.298

Explanation:

As we know

NaOI + H2O  NaOH + HOI

pH = 7 + ½ (pKa + log (HOI))

Substituting the given values, we get –

pH = 7 + ½ (10.64 + log (0. 0.05784))

pH = 7 + ½ (10.64 -1.2377)

pH = 11.70

pOH = 14 – pH  

pOH = 14 -11.70

pOH = 2.298

URGENT PLEASE HELP! Given 3.4 grams of x element with a molar mass of 24 g/mol and 4.2 grams of y element with a molar mass of 35 g/mol. How much of compound xy2 can be generated?
x + 2y -> xy2

Answers

4.4 g XY

I'm not sure but that's the closest I can get or try

Calculate the molar mass of PbSo3

Answers

Answer:

Lead sulfite is the inorganic compound with the formula PbSo3 or O3PbS.

Explanation:

How many moles in 2.5 x 10^24 atoms of calcium

Answers

There are 6.02*10 ^23 atoms in one mole of any substance according to avogadros law. Therefore in 2.41*10 ^25 calcium atoms, there are (2.41*10 ^25/6.02*10 ^23) moles of calcium, which is 40.03322259 or approximately 40 moles of calcium.

What will increased temperature in a reaction cause
1 Particles in a reaction to move more slowly
2 Particles in a reaction to move faster
3 Particles in a reaction to generate more electrical ions
4 Particles in a reaction to lose more electrical ions

Answers

I think your answer is 2 because the temperature will rise so the particles will move faster
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