A solution of is found to have 37% transmittance at 447 nm. If the molar absorption coefficient (ε) is 4400 at 477 nm, what is the concentration of in the solution? (Assume the path length is 1 cm) Please insert the answer according to the following example: 1.0 x 10^-1 M.

Answers

Answer 1

Answer:

The concentration of the solution is 1.068×10⁻⁴M

Explanation:

Hello,

To find the concentration of the solution, we'll have to use Beer-Lambert law which states absorption is directly proportional to the concentration of the solution.

Beer-Lambert law = A = εCL

A = absorption = 2 - log₁₀%T = 2 - log₁₀(34)

A = 2 - 1.5314 = 0.47

A = 0.47

ε = molar absorption coefficient = 4400

C = concentration of the solution

L = path length = 1cm

A = εcl

C = A / εl

C = 0.47 / 4400 × 1

C = 1.068×10⁻⁴M

The concentration of the solution is 1.068×10⁻⁴M


Related Questions

A sample of magnesium ribbon is ignited in a crucible to form magnesium oxide. Determine the empirical formula of magnesium oxide from the following data:

mass of crucible and cover + magnesium metal
33.741 g

mass of crucible and cover
33.500 g

mass of crucible and cover + magnesium oxide
33.899 g

Answers

Answer:

MgO

Explanation:

The following data were obtained from the question:

mass of crucible and cover + magnesium metal = 33.741 g

mass of crucible and cover = 33.5 g

mass of crucible and cover + magnesium oxide = 33.899 g

Next, we shall determine the mass of magnesium metal. This can be obtained as follow:

mass of crucible and cover + magnesium metal = 33.741 g

mass of crucible and cover = 33.5 g

Mass of magnesium metal =..?

Mass of magnesium metal = (mass of crucible and cover + magnesium metal) – (mass of crucible and cover)

Mass of magnesium metal = 33.741 – 33.5

Mass of magnesium metal = 0.241g

Next, we shall determine the mass of magnesium oxide. This can be obtained as follow:

mass of crucible and cover + magnesium oxide = 33.899 g

mass of crucible and cover = 33.5 g

Mass of magnesium oxide =?

Mass of magnesium oxide = (mass of crucible and cover + magnesium oxide) – (mass of crucible and cover)

Mass of magnesium oxide = 33.899 –. 33.5

Mass of magnesium oxide = 0.399g

Next, we shall determine the mass of oxygen. This can be obtained as follow:

Mass of magnesium oxide = 0.399g

Mass of magnesium metal = 0.241g

Mass of oxygen =..?

Mass of oxygen = (Mass of magnesium oxide) – (Mass of magnesium metal)

Mass of oxygen = 0.399 – 0241

Mass of oxygen = 0.158g

Now, we can obtain the empirical formula for the magnesium oxide as follow:

Mg = 0.241g

O = 0.158g

Divide by their molar mass

Mg = 0.241 / 24 = 0.01

O = 0.158 / 16 = 0.0099

Divide by the smallest

Mg = 0.01 / 0.0099 = 1

O = 0.0099 / 0.0099 = 1

Therefore, the empirical formula for the magnesium oxide is MgO

Resources Use the exothermic and endothermic interactive to classify the solution process for each solute. Exothermic solution process Endothermic solution process
KOH CaCl, NaCT NaOH NaNO, NH NO,

Answers

Answer:

Exothermic interractive are the following: NaOH, KOH, CaCl₂

Endothermic interactive are the following: NaCl, NH₄NO₃, NaNO₃

Explanation:

NaOH, KOH, and CaCl2 are exothermic reactants. NaCl, NH4NO3, and NaNO3 are endothermic interacting substances.

Endothermic reactions: what are they?

Chemical processes that can release or absorb energy are referred to as endothermic. In endothermic reactions, more energy is used when bonds in the reactants are broken than is released when new bonds are formed in the products.

How do endothermic processes take place?

When the temperature of the an isolated system drops while the surroundings of the a non-isolated system warm up, this is known as an endothermic response. The heat of reaction is generally positive in endothermic processes (qrxn>0).

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As lead chemist for a pharmaceutical manufacturing company, you need to inform the purchasing office of a supply order for the next batch of cisplatin, PtCl2(NH3)2. If you intend to make a 500kg batch, how many kg chlorine gas do you need to order?

Answers

Answer:

mass of chlorine gas required is 118 kg.

Explanation:

Total mass of the drug (Cisplatin) required = 500 kg

For the drug PtCl2(NH3)2, we first find the molar mass of the compound.

The molar mass of the drug is the total of all the molar mass of the elements in the drug

molar mass of Pt (platinum) in the drug = 195.078 g/mol

molar mass of chlorine (Cl) in the drug = 2 x (35.453 g/mol) = 70.908 g/mol

molar mass of ammonia (NH3) in the drug = 2 x (17.031 g/mol) = 34.062 g/mol

Total molar mass of the drug = 195.078 g/mol + 70.908 g/mol + 34.062 g/mol = 300.048 g/mol

fractional composition of chlorine in the drug = 70.908/300.048 = 0.236

mass of chlorine required for 500 kg of the drug = 0.236 x 500 = 118 kg

calculate the amount of carbon dioxid gas in 1.505x10^23 molecules of the gas.
[L=6.02x10^23 mol^-1] ​

Answers

Explanation:

We need to find the amount of carbon dioxide gas in [tex]1.505\times 10^{23}[/tex] molecules of the gas. We know that, 1 mole weighs 44 gram of carbon dioxide which contains [tex]6.022\times 10^{23}[/tex] number of molecules. It means that, [tex]6.022\times 10^{23}[/tex] number of molecules present in 44 grams of carbon dioxide molecule. So,[tex]1.505\times 10^{23}[/tex]  number of molecules present in :

[tex]=\dfrac{1.0505\times 10^{23}}{6.022\times 10^{23}}\times 44\\\\=7.675\ \text{grams}[/tex]

Hence, 7.675 grams of carbon dioxide is present in [tex]1.505\times 10^{23}[/tex] molecules of the gas.

What would the cathode be in a nickel and copper electrolytic cell

Answers

Answer:

d

Explanation:

What is the molarity of a solution that is 7.00% by mass magnesium sulfate and has a density of 1.071 g/mL?

Answers

Answer:

0.623 M

Explanation:

Step 1: Given data

Percent by mass (%m/m): 7.00 %Density of the solution (ρ): 1.071 g/mLMolar mass of magnesium sulfate: 120.37 g/mol

Step 2: Calculate the percent by volume (%m/v)

We will use the following expression.

[tex]\%m/v = \%m/m \times \rho = 7.00\% \times 1.071g/mL = 7.50g\%mL[/tex]

Step 3: Calculate the molarity

7.50 g of magnesium sulfate are dissolved in 100 mL of the solution. The molarity is:

[tex]M = \frac{7.50g}{120.37g/mol \times 0.100L } = 0.623 M[/tex]

How many water molecules are in a block of ice containing 1.25 mol of water (H2O)

Answers

Answer:

Molecules = 7.5 × 10²³ molecules

Explanation:

Given:

Moles = 1.25 mol

Avogadro's No. = [tex]N_{A}[/tex] = 6.022 * 10²³

Required:

Molecules = ?

Formula:

Molecules = Moles × [tex]N_{A}[/tex]

Solution:

Molecules = 1.25 × 6.022 × 10²³

Molecules = 7.5 × 10²³ molecules

A gas contained in a steel tank has a volume of 1.5 L at a temperature of 390 K. What will be the volume when the temperature changes to 1470C? Group of answer choices

Answers

Answer:

1.5 L  

Explanation:

If the gas is contained in a steel tank, the volume will remain constant when the temperature changes.

The volume will be 1.5 L.

the iupac name this compound​

Answers

Answer:

It's HYDROXIDE

Explanation:

You do not call it as hydroxide ion because ion always have + or -

I hope this helps

HAVE A GOOD DAY!

Answer:

Tetranol

Explanation:

Since it consist of 4 carbons So the prefix is "Tetra"

=> It has an "OH" group attached to it so the functional group is "ALCOHOL".

For alcohols, the suffix is "-ol" so the name becomes

=> Tetranol

If an electromagnetic wave has a frequency of 4.5 x 10^18 Hz, what is its wavelength? The speed of light is 3 x 108 m/s.

Answers

Answer:

Wavelength, λ  = 6.7 x 10^-11 m

Explanation:

Frequency and wavelength are inversely proportional to each other.

In this problem;

f =  4.5 x 10^18 Hz

wavelength, λ = ?

Speed of light, c = 3 x 108 m/s.

These variables are related by the following equation;

c = λ * f

Making λ subject of focus, we have;

λ = c / f

λ = 3 x 10^8 / 4.5 x 10^18

λ  = 0.67 x 10^-10

λ  = 6.7 x 10^-11 m

The basic function of a carburetor of an automobile is to atomize the gasoline and mix it with air to promote rapid combustion. As an example, assume that 30 cm3 of gasoline is atomized into N spherical droplets, each with a radius of 2.0 × 10−5 m. What is the total surface area of these N spherical droplets? Answer: [A] m2.

Answers

Answer:

The total surface area of these N spherical droplets is 4.4929 m²

Explanation:

From the information given :

assuming that :

30 cm³ of gasoline is atomized into N spherical droplets &

each with a radius of 2.0 × 10−5 m

We are tasked to determine the total surface area of these N spherical droplets

We all known that:

[tex]1 \ cm^3 = 10 ^{-6} m^3[/tex]

Therefore

[tex]30 \ cm^3 = 30 * 10 ^{-6} m^3 = 3 *1 0^{-5} \ m^3[/tex]

For each droplet; there is a required volume which is = [tex]\dfrac{4}{3} \pi r ^3[/tex]  since it assumes a sphere shape .

Thus;

replacing radius(r) with 2.0 × 10−5 m; we have:

[tex]= \dfrac{4}{3} \pi * (2.0 *10^{-5} m) ^3[/tex]

= [tex]3.35 * 10^{-14} \ m^3[/tex]

However; there are [tex]3*10^{-5} \ m^3[/tex] gasoline atomized into N spherical droplets with each with radius 2.0 × 10−5 m

For N ; we have ;

[tex]=\dfrac{3*10^{-5} \ m^3}{3.35 * 10^{-14} \ m^3/ droplet}[/tex]

= [tex]8.95*10^8 \ droplet s[/tex]

So; each droplet have a surface area = [tex]4 \pi r^2[/tex]

= [tex]4 \pi (2.0*10^{-5}m) ^2[/tex]

= [tex]5.02*10^{-9} \ m^2/droplets[/tex]

The surface area per droplet is equivalent to [tex]5.02*10^{-9} \ m^2/droplets[/tex]

Thus;

The total surface area of these N spherical droplets will be :

= [tex]8.95*10^8 \ droplet s * 5.02*10^{-9} \ m^2/ droplets[/tex]

= 4.4929 m²

The total surface area of these N spherical droplets is 4.4929 m²

The mathematics of combining quantum theory with wave motion of atomic particles is known as _____.


Answers

Combining quantum theory with wave motion of atomic particles is: Wave Mechanics

The following ions contain the same number of electrons. Rank them in order of decreasing ionic radii. Rank from largest to smallest radius. To rank items as equivalent, overlap them.K^+,Sc^3+,Cl^-,S^2-,P^3-

Answers

Answer:

P^3-  >  S^2-  >  Cl^- > K^+ >  Sc^3+

Explanation:

Ionic radii is an example of physical properties of Periodicity.

The size of an atom's ion is difficult to estimate because of the electronic distribution and arrangement. This is due to the fact that the atom' ion have no definite outer boundary. In order to circumvent this problem, the atom's ion is estimated in a crystal lattice in terms of its ionic radii.

Ionic radii is taken as half the distance between atomic ions in a crystal lattice. Across a period in the periodic table , ionic radii decreases progressively from left to right.

Down the group, the ionic radius increases from top to bottom.

So the arrangement of the given elements from largest to smallest radius in the decreasing order of ionic radius will be:

P^3-  >  S^2-  >  Cl^- > K^+ >  Sc^3+

The ranging from largest to smallest should be P^3-  >  S^2-  >  Cl^- > K^+ >  Sc^3+.

What are ionic radii?

It represents an example of the physical properties of Periodicity. It is considered to be half of the distance that lies between the atomic ions in a crystal lattice. It should be decreased progressively from left to right.

The ionic radius rises from top to bottom. It contains similar no of electrons, there should be the size difference because of the strength of the nuclear attraction.

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7.2 litters of an ideal gas are contained at 4.0 atm and 27•C. Using the ideal gas law, calculate how many moles of this gas are present.

Answers

Answer:

The correct answer is 1.17 moles

Explanation:

The ideal gas equation combines the pressure (P), volume (V), temperature (T) and number of moles of a gas (n):

PV= nRT

R is the gas constant (0.082 L.atm/K.mol)

In this case, we have:

V= 7.2 L

P= 4.0 atm

T= 27ºC + 273 = 300 K

We calculate the number of moles (n) of gas as follows:

n= (PV)/(RT)= (4.0 atm x 7.2 L)/(0.082 L.atm/K.mol x 300 K) = 1.17 mol

20. Which of the following statements regarding subshell filling order for a neutral atom is/are CORRECT? 1. Electrons are assigned to the 4f subshell before they are assigned to the 6s subshell. 2. Electrons are assigned to the 5d subshell before they are assigned to the 6p subshell. 3. Electrons are assigned to the 4p subshell before they are assigned to the 4s subshell. a. 1 only b. 2 only c. 3 only d. 1 and 3 e. 1, 2, and 3

Answers

Answer:

2 only

Explanation:

Electrons are filled in atoms according to the Aufbau principle. Electrons are filled into lower energy orbital before the filling of higher energy orbitals and this sequence must be followed in filling electron orbitals.

The order of arrangement of energy levels may be shown as follows; 1s 2s 2p 3s 3p 4s 3d 4p 5s 4d 5p 6s 4f 5d 6p 7s 5f 6d 7p. This implies that 4f>6s, hence 6s is filled before 4f.

Also, the 6p level > 5d level hence this is the correct option. You must fill the 5d level before you feel the 6p level.

If 175mL of oxygen is produced at STP, how many grams of hydrogen peroxide, H2O2
were decomposed? At STP, 1 mole of gas occupies 22.4L. Be sure to balance first.
2 H202 > H202 + O2
what's the
Mass of H2O2​

Answers

Answer:

0.53g

Explanation:

We'll begin by converting 175mL to L. This is illustrated below:

1000mL = 1L

Therefore 175mL = 175/1000 = 0.175L

Next, we shall calculate the number of mole of O2 that occupy 0.175L. This is illustrated below:

1 mole of O2 occupy 22.4L at stp.

Therefore, Xmol of O2 will occupy 0.175L i.e

Xmol of O2 = 0.175/22.4

Xmol of O2 = 7.81×10¯³ mole

Therefore, 7.81×10¯³ mole of O2 occupy 175mL.

Next, we shall determine the number of mole of H2O2 that decomposed to produce 7.81×10¯³ mole of O2. This is illustrated below:

2H2O2 —> 2H2O + O2

From the balanced equation above,

2 moles of H2O2 decomposed to produce 1 mole of O2.

Therefore, Xmol of H2O2 will decompose to produce 7.81×10¯³ mole of O2 i.e

Xmol of H2O2 = 2 x 7.81×10¯³

Xmol of H2O2 = 1.562×10¯² mole

Therefore, 1.562×10¯² mole of H2O2 decomposed in the reaction.

Finally, we shall convert 1.562×10¯² mole of H2O2 to grams. This is illustrated below:

Molar mass of H2O2 = (2x1) + (16x2) = 34g/mol

Mole of H2O2 = 1.562×10¯² mole

Mass of H2O2 =..?

Mole = mass /Molar mass

1.562×10¯² = mass /34

Cross multiply

Mass of H2O2 = 1.562×10¯² x 34

Mass of H2O2 = 0.53g

Therefore, 0.53g of Hydrogen peroxide, H2O2 were decomposition in the reaction.


What is the product(s) of the reaction below?
2Al(s) + Fe2O3(s) Al2O3(s) + 2Fe(s)
A. Solid aluminum oxide and solid iron
B. Solid aluminum
C. Saturated aluminum oxide and saturated iron
D. Iron(III) oxide and aluminum oxide

Answers

Answer:

I would put A

Explanation:

A new substance is produced as a result of a chemical reaction in which bonds between the molecules of the reactant and product are broken and new bonds are formed. Here the products are Al₂O₃ and Fe. The correct option is A.

Chemical reactions are interactions between two or more molecules that result in the production of new products. Products, as opposed to reactants, are compounds that result from an interaction between two other substances.

The reactants are on the left, while the products that are created are on the right. A one-headed or two-headed arrow connects the reactants and products.

Thus the correct option is A.

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Think about it: Gold is one of the densest substances known, with a density of 19.3 g/cm3. If the gold in the crown was mixed with a less-valuable metal like bronze or copper, how would that affect its density?

Answers

Answer:

If gold has a rare, high density then it would sink quickly. If mixed substances that are less-valued, are added to the gold crown (remember that gold is rare and very dense which makes it special) then we can assume the cheap substances are less dense, thus making the crown FLOAT more rather than sink (I say more, because unless the crown was extremely mixed with cheap material then it could possibly float but it depends on how much is in the crown). Summary: The crown would either be lighter and float, or barely be sunken due to the less-dense substance.

*Hint to think about: People consider cheaper things lighter such as plastic ring/less dense  for example, compared to a silver ring which is heavier/more dense (btw heavy does not always mean high density, it depends on the liquid density )

Hope this actually helps!

Explanation:

High-Desnity=Sink

Low Density=Float

If the same amount of heat is added to 25.0 g of each of the metals, which are all at the same initial temperature, which metal will have the highest final temperature

Answers

Answer:

The metal with the lowest specific heat capacity

Explanation:

Hello, this question can be solved when we compare their specific heat capacities.

Specific heat capacity of a metal /substance is the heat required to raise it's temperature by one degree Celsius.

Mathematically,

Q = mc∇θ

Q = heat energy applied

M = mass of the metal

C = specific heat capacity of the metal

∇θ = (θ₂ - θ₁) which corresponds to the change in temperature of the metal.

In a given experiment of different metals with different specific heat capacities, assuming they're of equal mass and same amount of energy is applied with the same amount of initial temperature, the metal with the lowest specific heat capacity would have the highest final temperature likewise the metal with the highest specific heat capacity would have the lowest final temperature.

The is due to the energy required to raise the temperature of the metal by 1°C

At a temperature of 393 K, the pressure of a sample of nitrogen is 1.07 atm. What will the pressure be at a temperature of 478 K? (Assume constant volume)

Answers

Answer:

1.30atm

Explanation:

P1/T1 = P2/T2

1.07/393 = P2/478

Answer: the first one is correct

Explanation:

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What volume (mL) of a concentrated solution of sodium hydroxide (6.00 M) must be diluted to 187 mL to make a 1.53 M solution of sodium hydroxide

Answers

Answer:

47.68 mL

Explanation:

In this case, we have a dilution problem. So, we have to start with the dilution equation:

[tex]C_1*V_1=C_2*V_2[/tex]

We have to remember that in a dilution procedure we go from a higher concentration to a lower one. With this in mind, We have to identify the concentration values:

[tex]C_1~=~6.00~M[/tex]

[tex]C_2~=~1.53~M[/tex]

The higher concentration is C1 and the lower concentration is C2. Now, we can identify the volume values:

[tex]V_1~=~X[/tex]

[tex]V_2~=~187~mL[/tex]

The V2 value has "mL" units, so V1 would have "mL" units also. Now, we can include all the values into the equation and solve for "V1", so:

[tex]6.00~M*V_1=1.53~M*187~mL[/tex]

[tex]V_1=\frac{1.53~M*187~mL}{6.00~M}=47.68~mL[/tex]

So, we have to take 47.68 mL of the 6 M and add 139.31 mL of water (187-47.68) to obtain a solution with a final concentration of 1.53 M.

I hope it helps!

Look up and record the boiling point of acetic acid, and explain why only some of it evaporates from the reaction mixture.

Answers

Answer:

Heating the mixture to a temperature above the boiling point of acetic acid, but below 100°C (the boiling point of water). The vapours from the acetic acid rise, and go into a tube. They are then condensed within the tube, and run off into a separate storage area. Because water can exist as a gas at pretty much any temperature above 0°C, it will result in an impure mixture, but repeatedly doing this will get the acetic acid to the desired purity.

Morphine, C 17H 19NO 3, is often used to control severe post-operative pain. What is the pH of the solution made by dissolving 25.0 mg of morphine in 100. mL of water? (For morphine, K b = 1.62 × 10 –6.)

Answers

Answer:

pH = 9.58

Explanation:

First of all, we need to determine the molarity of the solution.

We determine the molar mass of morphine:

12g/m . 17 + 1 g/m . 19 + 14 g/m + 16 g/m . 3 = 285.34 g/m

molar mass g/m, is the same as mg/mm

25 mg . 1 mmol / 285.34 mg = 0.0876 mmoles / 100 mL = 8.76×10⁻⁴ M

In diltuted solution, we must consider water.

Mass balance for morphine = [Morphine] + [Protonated Morphine]

8.76×10⁻⁴ M = [Morphine] + [Protonated Morphine]

As Kb is too small, I can skipped, the [Protonated Morphine]

8.76×10⁻⁴ M = [Morphine]

In the charge balance I will have:

[OH⁻] = [H⁺ morphine] + [H⁺]

Let's go to the Kb expression

Morphine + H₂O  ⇄  MorphineH⁺  +  OH⁻        Kb

Kb = [MorphineH⁺]  [OH⁻] / [Morphine]

Kb = [MorphineH⁺]  [OH⁻] / 8.76×10⁻⁴ M

So now, we need to clear [MorphineH⁺] to replace it in the charge balance

Kb  . 8.76×10⁻⁴ M / [OH⁻] = [MorphineH⁺]

Now, the only unknown value is the [OH⁻]

[OH⁻] = Kb .  8.76×10⁻⁴ M / [OH⁻]  + Kw/[OH⁻]

Remember that Kw = [H⁺] . [OH⁻]

[H⁺] = Kw/[OH⁻]

[OH⁻]² = 1.62×10⁻⁶ . 8.76×10⁻⁴ + 1×10⁻¹⁴

[OH⁻] = √(1.62×10⁻⁶ . 8.76×10⁻⁴ + 1×10⁻¹⁴)

[OH⁻] = 3.76×10⁻⁵  →  - log [OH⁻] = pOH = 4.42

pH = 14 - pOH  →  14 - 4.42 = 9.58

A compound consisting of atoms of small atomic mass is more likely to require what

Answers

Answer:

a lower temperature to liquefy

Explanation:

The complex [Ni(CN)4]2- is diamagnetic and the complex [NiCl4]2- is paramagnetic. What can you conclude about their molecular geometries

Answers

Answer:

[Ni(CN)4]2- square planar

[NiCl4]2- tetrahedral

Explanation:

For a four coordinate complex such as [Ni(CN)4]2- and [NiCl4]2-, we can decide its geometry by closely considering its magnetic properties. Both of the complexes are d8 complexes which could be found either in the tetrahedral or square planar crystal field depending on the nature of the ligand.

CN^- being a strong field ligand leads to the formation of a square planar diamagnetic d8 complex of Ni^2+. Similarly, Cl^- being a weak field ligand leads to the formation a a tetrahedral paramagnetic d8 complex of Ni^+ hence the answer given above.

At a certain temperature this reaction follows second-order kinetics with a rate constant of 0.00317sâ1: 2N2O5(g) â2N2O4(g) + O29(g) Suppose a vessel contains SO3 at a concentration of 1.44M . Calculate the concentration of SO3 in the vessel 0.240 seconds later. You may assume no other reaction is important.Round your answer to 2 significant digits.

Answers

Answer:

[A] = 1.438M = 1.4M (Two s.f)

Explanation:

Rate constant, k =  0.00317

Initial Concentration, [A]o = 1.44M

Final Concentration, [A] = ?

Time, t = 0.240 s

Since this is a second order reaction, the formula for this is given as;

1 / [A] = 1 / [A]o + kt

1 / [A] = 1 / 1.44 + (0.00317 * 0.240)

1 / [A] = 0.6944 + 0.0007608

1 / [A] = 0.6952

[A] = 1.438M = 1.4M (Two s.f)

If 500 mL of 2.0 M HCl is diluted with water to a volume of 1 liter, what is the molarity of the new solution?

Answers

Answer: 1 mole per L

Explanation:

(2M)(500mL)=(M)(1000mL)

1000=(M)(1000mL)

M=1

Taking into account the definition of dilution, if 500 mL of 2.0 M HCl is diluted with water to a volume of 1 liter, the molarity of the new solution is 1 M.

Dilution

When it is desired to prepare a less concentrated solution from a more concentrated one, it is called dilution.

Dilution is the process of reducing the concentration of solute in solution, which is accomplished by simply adding more solvent to the solution at the same amount of solute.

In a dilution the amount of solute does not change, but as more solvent is added, the concentration of the solute decreases, as the volume (and weight) of the solution increases.

A dilution is mathematically expressed as:

Ci×Vi = Cf×Vf

where

Ci: initial concentrationVi: initial volumeCf: final concentrationVf: final volume

Final molarity

In this case, you know:

Ci= 2.0 MVi= 500 mLCf= ?Vf= 1 L= 1000 mL

Replacing in the definition of dilution:

2.0 M× 500 mL= Cf× 1000 mL

Solving:

(2.0 M× 500 mL)÷ 1000 mL= Cf

1 M= Cf

In summary, if 500 mL of 2.0 M HCl is diluted with water to a volume of 1 liter, the molarity of the new solution is 1 M.

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Select the chemical equation that represents an acid base reaction??? Please help

Answers

Answer:

HCl + AgNO3 ------ AgCl + HNO3

Explanation:

HCl is an acid called hydrochloric acid, while AgNO3 is a base called Silver Nitrate.

Hope it helps.

What energy transfer happens when wood is burning?

Answers

Answer:

Mechanical to Heat

explanation:

The wood itself can make mechanical energy but when it's on fire it makes heat energy

Answer: Chemical to heat and light

Explanation: The energy transforms from chemical energy to heat and light energy. Because when the candle burns a chemical reaction occurs and produces heat and light.

An unknown monoprotic acid HA with a concentration of 0.050 M has a pH of 2.3. Which of the following can we conclude?
A) It must be a strong acid.
B) It must be a weak acid.
C) A salt of its conjugate base would have no pH effect in solution.
D) Both A and C
E) None of the above

Answers

Answer:

B) It must be a weak acid.

Explanation:

If HA is a strong acid

[tex]HA\rightleftharpoons H^++A^-[/tex]

Now the pH value can be written as follows

[tex]pH=-log[H^+]\\pH=-log(5\times 10^{-2})\\pH=2\times log5\\pH=1.4[/tex]

But given that acid HA has 2.3 pH value.

Therefore we can say that HA is weak acid.

Thus the answer will be option (B).

B) It must be a weak acid.

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