a solution is prepared by mixing 529.0 ml of ethanol with 594.0 ml of water. the molarity of ethanol in the resulting solution is 8.407 m. the density of ethanol at this temperature is 0.7893 g/ml. calculate the difference in volume between the total volume of water and ethanol that were mixed to prepare the solution and the actual volume of the solution.

One potential source of error could be a measurement error, either in the volume of water added or in the temperature of the water. Another potential source of error could be a problem with the calibration of the thermometer used to measure the temperature of the water.

However, one of the most likely sources of error in this case is the presence of air bubbles in the erlenmeyer flask during the experiment. Air bubbles can act as an insulator, trapping heat and preventing the water from reaching the same temperature as the rest of the water in the flask. This can result in an inaccurate measurement of the water's temperature and ultimately affect the calculation of the experimental data.

To reduce the impact of air bubbles in future experiments, it is recommended to ensure that the erlenmeyer flask is thoroughly cleaned and free of any debris or contaminants that may trap air bubbles. Additionally, carefully swirling the flask during the heating process can help to dislodge any trapped air bubbles and ensure that the water is evenly heated.

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Answer:

Explanation:

The reactant with the higher mass in grams is the limiting reactant. NO. [What counts is the numbers of molecules, not their mass.  For example In the reaction of oxygen and hydrogen to form water:

2H2 + O2 = 2H2O

We need twice as many H2 molecules than O2 molecules.  We need two moles of H2 and 1 mole of O2 (or anything with that 2:1 ratio).  But a mole of H2 only has a mass of 2 grams, so 2 moles is 4 grams.  A balanced reaction in thias case would consist of 2 grams of H2 for every 32 grams of O2.  If there were only 31 grams of O2, it would be the limiting reagent, despite the fact it's mass is still greater than that of H2O]

Calculate the amount of product that can be made with each reactant, then choose the reactant that produces the least amount of product.  YES  [Once the reactant is consumed in producing the least amount of product, no more product will be produced, desoppite the fact that the other reactant reamins.]

Calculate the amount of product that can be made with each reactant, then choose the reactant that produces the most amount of product. NO

[This ignores the fact that the reaction stops when the other reactant is depleted.]

The reactant with the lower mass in grams is the limiting reactant.  NO, for the same reasons as in 1).

When the temperature of a reaction is lowered during the decomposition reaction of calcium carbonate to calcium oxide and carbon dioxide, the equilibrium will shift towards the reactants.

Exothermic reactions release heat energy into the surroundings, which means that the temperature of the reaction is lowered when it is proceeding from reactants to products. So, when the temperature is reduced, the system will try to increase the temperature by shifting the equilibrium towards the endothermic side, which means towards the reactants side.

Here, we know that decomposing heated calcium carbonate into calcium oxide, and carbon dioxide is an endothermic reaction because it requires heat. As a result, the equilibrium will shift towards the left (reactants side) to compensate for the decrease in temperature. This will increase the concentration of reactants and decrease the concentration of products, ultimately, it will cause the equilibrium to shift in the direction of reactants.

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With added heated calcium carbonate decomposes to form calcium oxide and carbon dioxide, the equilibrium will shift towards the reactant side if the temperature of the reaction is lowered.

According to Le Chatelier's principle, if any change is applied to a system at equilibrium, the system reacts in such a way as to counteract that change.

The principle explains that an increase in temperature causes equilibrium to shift in the endothermic direction, while a decrease in temperature causes it to shift in the exothermic direction.

When [tex]CaCO_3[/tex] is heated, it decomposes to form CaO and [tex]CO_2[/tex].

The balanced chemical equation is:

[tex]CaCO_3 (s)\rightarrow CaO (s) + CO_2 (g)[/tex]

The given reaction is an endothermic reaction as it absorbs heat.

Therefore, when the temperature increases, the equilibrium shifts towards the product side to counteract the change. On the other hand, when the temperature is decreased, the equilibrium shifts towards the reactant side to counteract the change.

In this case, the equilibrium will shift in the backward direction to produce more [tex]CaCO_3[/tex].

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The molarity of the acetic acid, when it is titrated with 0.50M NaOH, and 15.6 ml of it is required to reach the equivalence point, is 0.78 M.

The molarity of the acetic acid can be calculated using the following formula:
Molarity (M) = (Moles of Acid) / (Volume of Acid)

First, the moles of acetic acid must be determined. To do this, the moles of sodium hydroxide (NaOH) used to titrate the acetic acid must be determined.

Moles of NaOH = (Molarity of NaOH) x (Volume of NaOH)
Moles of NaOH = (0.50 mol/L) x (0.0156 L)
Moles of NaOH = 0.0078 mol

Since one mole of NaOH is needed to neutralize one mole of acetic acid, the moles of acetic acid are equal to the moles of NaOH, or 0.0078 mol.

Next, the volume of the acetic acid must be determined. Since 10.0 mL of vinegar was used, the volume of acetic acid is also 10.0 mL.

Now that the moles of acetic acid and the volume of acetic acid have been determined, the molarity of the acetic acid can be calculated.

Molarity (M) = (Moles of Acid) / (Volume of Acid)
Molarity (M) = (0.0078 mol) / (0.010 L)
Molarity (M) = 0.78 mol/L

Therefore, the molarity of the acetic acid is 0.78 mol/L.

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The experiment would produce 102.18 g of ammonia. The answer is closest to 102 g NH₃.

The balanced chemical equation for the reaction is:

N₂(g) + 3H₂(g) → 2NH₃(g)

In this equation, the stoichiometric ratio of nitrogen gas to ammonia gas is 1:2. Accordingly, 2 moles of ammonia gas are created for every 1 mole of nitrogen gas that reacts.

As a result of using 3 moles of nitrogen gas, Brett will generate 2 x 3 = 6 moles of ammonia gas.

From the equation, we can see that for every 1 mole of nitrogen gas (N₂) used, 2 moles of ammonia (NH₃) will be produced. Therefore, if 3 moles of N₂ is used, the number of moles of NH₃ produced will be:

moles of NH₃ = (3 moles N₂) x (2 moles NH₃ / 1 mole N₂) = 6 moles NH₃

To calculate the mass of NH₃ produced, we need to use its molar mass, which is 17.03 g/mol. Therefore:

mass of NH₃ = (6 moles NH₃) x (17.03 g/mol) = 102.18 g NH₃

So, the experiment would produce 102.18 g of ammonia. The answer is closest to 102 g NH₃.

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Dimethylglyoxime is a chemical that is present in this kit (in solution). KIT The solution will turn pink when used to clean a metal object with such a cotton swab when nickel is present in the Penelope's 14k white gold ring.

White gold was first created to mimic platinum (a white metal). White gold is typically an alloy containing around 75% gold or around 25% nickel and zinc. It would be approximately 75% pure gold if it had an 18 karat stamp.

The question:

Joe, a friend of Penelope's, presents her with a 14k white gold ring on Valentine's Day. Daksha, a friend of Penelope's, believes it is truly made of nickel. Penelope may use the following procedure or experiment to determine this for sure:

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Answer:

Explanation:

Molarity = moles /liters

M= 1/1 = 1M

B) 2moles/0.5 L = 4.0 M

Answer:

So the correct answer is option (C) 7.2 moles.

Explanation:

According to the balanced chemical equation for the combustion of C2H6:

C2H6 + O2 → CO2 + H2O

The stoichiometric coefficients tell us that 1 mole of C2H6 reacts with 3 moles of O2 to produce 2 moles of CO2.

To determine how many moles of CO2 are produced from 3.6 moles of C2H6, we need to use stoichiometry. We can set up a proportion using the stoichiometric coefficients from the balanced equation:

3.6 mol C2H6 / 1 x 2 mol CO2 / 1 mol C2H6 = 7.2 mol CO2

Therefore, 7.2 moles of CO2 are produced during the complete combustion of 3.6 moles of C2H6.

So the correct answer is option (C) 7.2 moles.

A chemical equation is said to be balanced when the number of atoms of each element on both sides of the equation are the same.

According to this question, a reaction occured between ammonia gas and oxygen gas to produce nitrogen gas and water.

Based on the equation, 4 moles of ammonia requires 3 moles of oxygen gas to react.

This means that 3.53 moles of ammonia will require 3.53 × ¾ = 2.65 moles of oxygen gas.

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Answer:

the balanced chemical equation for the reaction between aluminum (Al) and copper(II) sulfate (CuSO4) is:

2Al + 3CuSO4 → Al2(SO4)3 + 3Cu

This equation tells us that two moles of Al react with three moles of CuSO4 to produce one mole of Cu, and also produces one mole of Al2(SO4)3.

To determine the mass of Cu produced, we need to use the given masses of Al and CuSO4 to calculate how many moles of each reactant are present, and then use the mole ratios from the balanced equation to determine the moles of Cu produced. Finally, we can convert the moles of Cu to grams using its molar mass.

First, we calculate the moles of Al and CuSO4:

moles of Al = 1.08 g / 26.98 g/mol = 0.0400 mol

moles of CuSO4 = 9.58 g / 159.61 g/mol = 0.0600 mol

Next, we use the mole ratios from the balanced equation to determine the moles of Cu produced:

moles of Cu = (0.0400 mol Al) × (3 mol Cu / 2 mol Al) = 0.0600 mol Cu

Finally, we convert the moles of Cu to grams using its molar mass:

mass of Cu = 0.0600 mol × 63.55 g/mol = 3.81 g

Therefore, the total mass of Cu produced when 1.08 grams of Al reacts completely with 9.58 grams of CuSO4 is 3.81 grams.he balanced chemical equation for the reaction between aluminum (Al) and copper(II) sulfate (CuSO4) is:

2Al + 3CuSO4 → Al2(SO4)3 + 3Cu

This equation tells us that two moles of Al react with three moles of CuSO4 to produce one mole of Cu, and also produces one mole of Al2(SO4)3.

To determine the mass of Cu produced, we need to use the given masses of Al and CuSO4 to calculate how many moles of each reactant are present, and then use the mole ratios from the balanced equation to determine the moles of Cu produced. Finally, we can convert the moles of Cu to grams using its molar mass.

First, we calculate the moles of Al and CuSO4:

moles of Al = 1.08 g / 26.98 g/mol = 0.0400 mol

moles of CuSO4 = 9.58 g / 159.61 g/mol = 0.0600 mol

Next, we use the mole ratios from the balanced equation to determine the moles of Cu produced:

moles of Cu = (0.0400 mol Al) × (3 mol Cu / 2 mol Al) = 0.0600 mol Cu

Finally, we convert the moles of Cu to grams using its molar mass:

mass of Cu = 0.0600 mol × 63.55 g/mol = 3.81 g

Therefore, the total mass of Cu produced when 1.08 grams of Al reacts completely with 9.58 grams of CuSO4 is 3.81 grams.

Explanation:

Answer:2Al + 3CuSO4 → Al2(SO4)3 + 3Cu

Explanation:

The factor which is not likely to affect how quickly a person-to-person disease spreads through a group of people is The color of the people's clothing that is Option A.

Infectious diseases are illnesses caused by organisms like bacteria, viruses, fungus, or parasites. Numerous creatures inhabit and dwell on human body. They are usually innocuous or even beneficial. Yet, certain microbes can cause illness under particular conditions.

Certain infectious illnesses are transmissible from person to person. Some are spread by insects and other animals. You can get others by eating contaminated food or drinking polluted water, or by being exposed to organisms in the environment.

Infectious disorders are usually transmitted from person to person by the direct transmission of bacteria, viruses, or other germs. This can happen when an infected person touches, kisses, coughs, or sneezes on someone who isn't affected.

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Answer:

One reaction that can be used to show the difference between a weak acid and a strong acid is the reaction with magnesium. When magnesium is added to hydrochloric acid, a vigorous reaction occurs, releasing hydrogen gas and forming magnesium chloride:

2HCl(aq) + Mg(s) → MgCl2(aq) + H2(g)

In contrast, when magnesium is added to ethanoic acid, a slow reaction occurs, releasing hydrogen gas and forming magnesium ethanoate:

2CH3COOH(aq) + Mg(s) → Mg(CH3COO)2(aq) + H2(g)

The reason for the difference in reaction rate between the two acids is due to their different levels of dissociation in water. Hydrochloric acid is a strong acid and completely dissociates in water, releasing a high concentration of hydrogen ions (H+) in solution. In contrast, ethanoic acid is a weak acid and only partially dissociates in water, releasing a low concentration of hydrogen ions in solution. As a result, the reaction between magnesium and hydrochloric acid is more vigorous because of the high concentration of hydrogen ions in solution, whereas the reaction between magnesium and ethanoic acid is slower due to the lower concentration of hydrogen ions in solution.

Explanation:

Answer:

correct comparative pH, such as, 0-3 (strong) 4-6 (weak) • named reaction, such as, with a reactive metal or a named carbonate • comparative results or observations of the named reaction, such as, faster reaction (strong) or greater volume of gas produced in a given time (strong) 

Explanation:

Explanations of different results • weak acids are only partially ionised in aqueous solution • strong acids are completely ionised in aqueous solution/ greater concentration of H+ ions • aqueous solutions of acids at the same concentration/ powder, same temperature

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Answer:

c) Put it in a bag and properly label it with the chain of custody information.

Step by step explanation:-

Tasting it might kill the investigator.

Drug test would not be appropriate during the crime scene.

Having the knowledge to identify the drug by smelling is quite rare in people.

Answer:

C2H3O2 (acetate)

Explanation:

61.05 g C x 1 mol C / 12.01 g C = 5.083 mol C

7.65 g H x 1 mol H / 1.01 g H = 7.57 mol H

81.30 g O x 1 mol O / 16.00 g O = 5.081 mol O

Divide by lowest number

5.083 / 5.081 = approx. 1 mol C

7.57 / 5.081 = approx. 1.5 mol H

5.081 / 5.081 = 1 mol O

so ratio of moles in this compound are 1 mol C : 1.5 mol H : 1 mol O

Multiply by 2 to get whole number mol ratios

--> empirical formula is C2H3O2 (acetate)

Gasoline can have potential energy because it is stored in a container, chemical energy because of the energy stored in its molecular bonds, and thermal energy because of the heat produced when it is burned.

Gasoline is a fuel that contains potential, chemical, and thermal energy.

Potential energy is the energy that an object has due to its position or configuration. In the case of gasoline, it has potential energy because it is stored in a tank or container and has the potential to be used as fuel for a car or other combustion engine.

Chemical energy is the energy that is stored in the bonds between atoms and molecules. Gasoline has chemical energy because it is made up of molecules that contain stored energy in the form of chemical bonds. When gasoline is burned in an engine, the chemical energy is released and converted into thermal energy.

Thermal energy is the energy that is related to the temperature of a substance. When gasoline is burned in an engine, it produces thermal energy as a result of the chemical reactions that take place. This thermal energy is then converted into mechanical energy that powers the car's engine.

In summary, gasoline can have potential energy because it is stored in a container, chemical energy because of the energy stored in its molecular bonds, and thermal energy because of the heat produced when it is burned. These three forms of energy are all interrelated and can be converted from one form to another.

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A hydrocarbon comprises 92.3% carbon by mass and 7.7% hydrogen by mass. The compound's empirical formula will be oose answer: CH CH5, CH CH3, CH CH4.

Octanoic acid is a straight-chain saturated fatty acid derived from heptane in which one of the terminal methyl group's hydrogens has been replaced by a carboxy group. Caprylic acid is another name for octanoic acid. It functions as an antibiotic agent, a human metabolite, and an E. coli metabolite.

Along the chain of saturated fatty acids, there are no double bonds or any functional groups. In the sense that all carbons are "saturated," the term "saturated" refers to hydrogen (apart from the carboxylic acid [-COOH] group)

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H-H: 432 kJ/mol,C-H: 413 kJ/mol,∆H = -451 kJ/mol.The rection is H-H + C-H => H + H + H- Therefore,this reaction is exothermic since the enthalpy change is negative.

Enthalpy is a thermodynamic property that is a measure of the total energy content. It is the sum of the internal energy and the product of its pressure and volume. It is expressed in units of energy per unit mass, such as joules per kilogram (J/kg) or kilocalories per kilogram (kcal/kg).It is an important factor in the study of thermodynamics.

For reactants, two hydrogen molecules must be broken down into two hydrogen atoms (H-H bond energy = 432 kJ/mol).For products, one molecule of carbon monoxide must be formed from one carbon and oxygen atom (C-O bond energy = 799 kJ/mol). Therefore, the enthalpy change for this reaction is calculated as follows:ΔH = (799 kJ/mol) - (2 x 432 kJ/mol) = -5 kJ/mol.

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The aluminum bar is cooling through an exothermic process, which means that heat is being released from the bar and being transported to the surroundings. This is indicated by the negative sign of the heat change.

The aluminum bar is cooling through an exothermic process, which means that heat is being released from the bar and being transported to the surroundings. This is indicated by the negative sign of the heat change (-14.2 kJ). This is due to the metal bar losing heat as it cooled down because the ultimate temperature (25.0°C) is lower than the initial temperature (70.0°C).

we can use the formula:

Q = m * c * ΔT

where Q = heat change, m = mass of the aluminum bar, c = specific heat capacity of aluminum, and ΔT = change in temperature.

The specific heat capacity of aluminum is 0.903 J/g·°C.

So, plugging in the values, we get:

Q = (350.0 g) * (0.903 J/g·°C) * (25.0°C - 70.0°C)

Q = -14,175 J

The negative sign indicates that heat is being lost by the aluminum bar,

To convert -14,175 J to kJ, we divide by 1000:

-14,175 J = -14.175 kJ

Rounding to one decimal place, we get:

-14.175 J ≈ -14.2 kJ

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option a is the answer

10

An animal's internal stimulus to feed in order to get the food needed for survival is called hunger.

Hunger is a natural drive that motivates animals to search for and consume food in order to meet their nutritional needs and maintain their health and well-being.

This internal stimulus is regulated by the hypothalamus, a region of the brain that controls a variety of bodily functions, including hunger and satiety. When an animal's energy levels drop or its stomach is empty, the hypothalamus sends signals to the rest of the body to increase the desire for food.

Once the animal has eaten enough to satisfy its nutritional needs, the hypothalamus sends signals to decrease the desire for food and the animal stops eating. This process helps to ensure that animals get the nutrients they need to survive and maintain their health.

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The percent mass of H is 3.3%. This can be found from the data of the elements that we have in the problem.

To find the percent mass of an element in a compound, you need to follow these steps:

Determine the molar mass of the compound: This is the sum of the atomic masses of all the elements in the compound. You can find the atomic masses of elements on the periodic table.

Determine the molar mass of the element: This is the atomic mass of the element as it appears in the compound.

Calculate the moles of the element in the compound: This can be done using the formula: Moles = Mass of element / Molar mass of element.

Calculate the percent mass of the element in the compound: This can be done using the formula: Percent mass = (Moles of element x Molar mass of element / Molar mass of compound) x 100%.

Molar mass of the compound = 239 g/mol

Mass of H present = 8 (1) = 8

Percent of H = 8/239* 100/1

= 3.3%

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According to a first-order rate law with a rate constant of 0.0058 min1, the reaction requires a concentration of iodide of about 4.83 mM before the color changes after 12 minutes.

The demonstration in the movie shows that larger iodide ion concentrations accelerate the first reaction, hastening the depletion of thiosulfate. Because of this, the reaction's end-signaling color shift happens faster.

rate = k[I-]

[I-] = rate / k

Plugging in the given rate (0.028 mM/12 min), we get:

[I-] = (0.028 mM/12 min) / k

[I-] = (0.028 mM/12 min) / (0.0058 min⁻¹)

[I-] ≈ 4.83 mM

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When Wegener was working, scientists were not aware of plate tectonics, the theory that explains how continents can shift.

The scientific community was not aware of the mechanism underlying the migration of the continents during the time of Wegener. Both the ideas of a solid Earth and plate tectonics had not yet gained widespread acceptance. Initially, scientists were sceptical of Wegener's idea of continental drift because they thought the Earth's surface was permanent and unchanging. The theory's development was hampered by the inability to collect and analyse data on a worldwide scale due to a lack of technology. The scientific world didn't completely embrace the idea of plate tectonics and the part it plays in sculpting the Earth's surface until decades later, with technological breakthroughs and the collection of more evidence.

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The atomic radius, Pauling ionic radius, and first ionization energy of Bromine (Br), Chlorine (Cl), Magnesium (Mg), and Sodium (Na) are given in the attachment.

A chemical element's atomic radius, which is typically the average or normal distance between the nucleus's center and the outermost isolated electron, serves as a gauge for the size of its atom.

Only by measuring the separation between the centers of two adjacent atoms and halving that distance can one determine the radius of an atom.

The ionic radius is the size of an ion.

The first ionization energy is the energy required to remove the first electron from an atom

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If you have 3.45 mol sample of iron, how many grams of Fe₂O₃ will there be after the iron has rusted completely is 193.2 g Fe₂O₃.

Rust is a multi-paradigm, general-purpose programming language developed by Mozilla Research. It is designed to be a safe, concurrent, practical language that supports functional and procedural programming. Rust is syntactically similar to C++, but its memory safety features make it safer and more secure. It also provides better performance than many other languages. Rust provides memory safety by using a type system and a borrowing system to ensure that memory is only accessed when it is valid.

The balanced equation for the rusting of iron is:
Fe + O₂ -> Fe₂O₃
To calculate the grams of Fe2O₃ produced, we must first convert 3.45 mol Fe to grams.
Molar mass of Fe = 56.0 g/mol
Therefore, 3.45 mol Fe x 56.0 g/mol = 193.2 g Fe
Now, according to the balanced equation, 1 mol Fe produces 1 mol Fe₂O₃.
So, 193.2 g Fe will produce 193.2 g Fe₂O₃.
Therefore, the answer is 193.2 g Fe₂O₃.

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Answer:

Explanation:

The total number of atoms in the reactants can be determined by counting the atoms on each side of the equation.

On the left side, there are:

6 carbon atoms (C)

12 hydrogen atoms (H)

6 oxygen atoms (O)

On the right side, there are:

6 carbon atoms (C)

12 hydrogen atoms (H)

18 oxygen atoms (O)

Therefore, the reactants contain a total of:

6 + 12 + 6 = 24 atoms (of carbon, hydrogen, and oxygen)

Answer: 24 atoms

In order to create 2,4-dinitrobenzene and 2,6-dinitrobenzene, respectively, nitrobenzene can be nitrated in either the ortho or para positions.

A nitro group (-NO2) is substituted for a hydrogen atom (-H) on the benzene ring during the nitration process. The nitrobenzene resonance structures demonstrate that the electrons are distributed between the nitro group and the benzene ring. Due to the partial negative charge they have as a result of the nitro group's electron-withdrawing effect, the ortho and para positions are more vulnerable to electrophilic attack as a result of this delocalization.

The following diagram depicts the resonance structures for the ortho and para nitration products:

Ortho nitrification

      H                             H

      |                             |

  H---C---NO2        H---C---NO2

      |                             |

      H                             NO2

Para nitration:

      H                             H

      |                             |

  H---C---NO2        NO2---C---H

      |                             |

     NO2                            H

The nitro group is situated on the 2 and 4 positions of the benzene ring in the ortho nitration product, whereas it is situated on the 2 and 6 positions in the para nitration product.

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Momentum-

[tex] \:\:\:\:\:\:\:\:\:\:\:\:\star\sf \underline {P = mv}\\[/tex]

Where-

As per question, we are given -

Convert 20 minutes to hour-

Therefore, 20 minutes = 20/60 = 1/3 hour

[tex] \:\:\:\:\:\:\longrightarrow \sf\underline{Speed _{(car)} = \dfrac{Distance }{ time}}\\[/tex]

[tex] \:\:\:\:\:\:\longrightarrow \sf Speed_{(car)} = \dfrac{12}{\dfrac{1}{3}}\\[/tex]

[tex] \:\:\:\:\:\:\longrightarrow \sf Speed_{(car)}=12 \times 3 \\[/tex]

[tex] \:\:\:\:\:\:\longrightarrow \sf Speed_{(car)}= 36 km/h \\[/tex]

[tex] \:\:\:\:\:\:\longrightarrow \sf Speed_{(car)}= \dfrac{36 \times 1000}{3600}\\[/tex]

[tex] \:\:\:\:\:\:\longrightarrow \sf Speed_{(car)}= \dfrac{\cancel{36} \times 10\cancel{0}\cancel{0}}{\cancel{36}\:\cancel{0}\cancel{0}}\\[/tex]

[tex] \:\:\:\:\:\:\longrightarrow \sf \underline{Speed_{(car)} = 10 m/s }\\[/tex]

No that we have obtained the velocity of the car is 10 m/s and the mass of the car is 30 kg,so we can put all the values and find for momentum of car -

[tex] \:\:\:\:\:\:\longrightarrow \sf \underline{Momentum_{(car)} = mv}\\[/tex]

[tex] \:\:\:\:\:\:\longrightarrow \sf Momentum_{(car)} = 30 \times 10\\[/tex]

[tex] \:\:\:\:\:\:\longrightarrow \sf\underline{ Momentum_{(car)} =300 kgms^{-1}}\\[/tex]