A solid, uniform cylinder with mass 8.35kg and diameter 15.0cm is spinning with angular velocity 250rpm on a thin, frictionless axle that passes along the cylinder axis. You design a simple friction-brake to stop the cylinder by pressing the brake against the outer rim with a normal force. The coefficient of kinetic friction between the brake and rim is 0.338. What must the applied normal force be to bring the cylinder to rest after it has turned through 5.05 revolutions?

Complete question:

It is measured that 3/4 of a body's volume is submerged in oil of density 800kg/m³. What is the specific gravity of oil?

Answer:

The specific gravity of the oil is 0.8.

Explanation:

Given;

density of the oil, [tex]\rho_o[/tex] = 800 kg/m³

density of water, [tex]\rho_w[/tex] = 1000 kg/m³

The specific gravity of any substance is the ratio of the substance density to the density of water.

Specific gravity of the oil = density of the oil / density of water

Specific gravity of the oil = 800/1000

Specific gravity of the oil = 0.8

Therefore, the specific gravity of the oil is 0.8.

Answer: C. Ribosome

Explanation: Ribosome is responsible for protein synthesis. I got it right on khan academy :) hope this helps have a blessed day.

The structure which is represented by the letter C is known as free ribosomes. Thus, the correct option for this question is C.

Ribosomes may be defined as a type of cell organelle which is spherical and glandular in shape. They occur freely in the matrix or remain bound with ER.

The major components of ribosomes may include RNA and protein. Ribosomes were first discovered by Palade in 1953. There are two types of ribosomes, ie. the 70s and 80s.

Ribosomes play an important function in the process of protein synthesis. The structure which is represented by the letter A is known as the cell membrane. The structure which is represented by the letter B is known as Cytosol.

Therefore, the structure which is represented by the letter C is known as free ribosomes. Thus, the correct option for this question is C.

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Given the information on the graph, we can confirm that this profile represents the Ocean floor profile.

Therefore, we can confirm that the profile belongs to the ocean floor profile, firstly because of the information provided, as well as it being consistent with the irregularities in the depth of the ocean floor.

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we know that,

Frequency = 1/ time period

hence, Feq = 1/5 ===> 0.2 Hz

hence, wave velocity = freq * wavelength

hence,

V = 0.2 * 100

==> Wave velocity = 20 m/s

Answer:

I cheated on

Spanish

ELA

history

Explanation:

Answer:

thx

Explanation:

Answer:

Displacement and Velocity

Answer:

v = 1.48 m / s

Explanation:

This is an exercise in conserving the moment. Let's define a reference system made up of the student, the scooter and the collected mass. For this system the forces during the collection are internal and element and conserves

initial interim. Before picking up the merchandise

       p₀ = M v₀

final instant. After picking up the object

       p_f = (M + m ') v

how the moment was created

        p₀ = p_f

       M v₀ = (M + m) v

let's calculate

       v = [tex]\frac{M}{m+ M}[/tex]  vo

       v = 78.2 / (6.4 +78.2) 1.60

       v = 1.48 m / s

Answer: I like your profile picture

Explanation:

As a liquid is cooled its molecules lose kinetic energy and their motion slows. When they've slowed to where intermolecular attractive forces exceed the collisional forces from random motion, then a phase transition from liquid to solid state takes place and the material freezes

Hope it helps u

FOLLOW MY ACCOUNT PLS PLS

Answer:

A point on the outside rim will travel 157.2 meters during 30 seconds of rotation.

Explanation:

We can find the distance with the following equation since the acceleration is cero (the disk rotates at a constant rate):

[tex] d = v*t [/tex]

Where:

v: is the tangential speed of the disk

t: is the time = 30 s  

The tangential speed can be found as follows:

[tex] v = \omega*r [/tex]

Where:

ω: is the angular speed = 100 rpm

r: is the radius = 50 cm = 0.50 m

[tex] v = \omega*r = 100 \frac{rev}{min}*\frac{2\pi rad}{1 rev}*\frac{1 min}{60 s}*0.50 m = 5.24 m/s [/tex]    

Now, the distance traveled by the disk is:

[tex] d = v*t = 5.24 m/s*30 s = 157.2 m [/tex]

Therefore, a point on the outside rim will travel 157.2 meters during 30 seconds of rotation.

I hope it helps you!

Answer:

720N

Explanation:

180+(40×10)+140=720 remember we can only add with same units ;1kg=10N therefore 40 kg=(40×10)N=400N

The net force would be the summation of all the forces in addition to the weight force of the 40 kg weight, thus the net force of all the forces would come out to be 712.4 Newtons.

Newton's Second Law states that The resultant force acting on an object is proportional to the rate of change of momentum.

F = ma

As given in the problem we have to find the net force,

Let us assume the acceleration due to gravity would be 9.81 m/s².

The force generated by the 40-kilogram weight =40 ×9.81 Newtons.

The force generated by the 40-kilogram weight = 392.4 Newtons

Net force = 180 + 140 +392.4

                =712.4 Newtons

Thus, the net force of all the forces would come out to be 712.4 Newtons.

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Answer:

The magnitude of the angular acceleration of the wheel is 14.53 rad/s².

Explanation:

The angular acceleration can be found by using the following equation:

[tex] \omega_{f}^{2} = \omega_{0}^{2} + 2\alpha \Delta \theta [/tex]  (1)

Where:

[tex] \omega_{f}[/tex]: is the final angular velocity = 18 rad/s

[tex]\omega_{0}[/tex]: is the initial angular velocity

α: is the angular acceleration =?

Δθ = 19 rev*(2π/1 rev) = 119.4 rad

The initial angular velocity can be found knowing that the wheel turns through 19 revolutions during a 3 s time interval:

[tex] \omega_{f} = \omega_{0} + \alpha t [/tex]

Where:  

t: is the time = 3 s

By solving the above equation for ω₀ we have:

[tex] \omega_{0} = \omega_{f} - \alpha t [/tex]   (2)

Now, by entering equation (2) into (1) we have:

[tex] \omega_{f}^{2} = (\omega_{f} - \alpha t)^{2} + 2\alpha \Delta \theta [/tex]                        

[tex] \omega_{f}^{2} = \omega_{f}^{2} - 2\omega_{f} \alpha t + (\alpha t)^{2} + 2\alpha \Delta \theta [/tex]                              

[tex](9\alpha)^{2} + 130.8 \alpha = 0[/tex]  

By solving the above equation for "α" we have:

α = -14.53    

The minus sign means that the wheel is decelerating.

Hence, the angular acceleration of the wheel is -14.53 rad/s².                                                                                            

I hope it helps you!

Answer:

60mph=26.8224meters per second

Explanation:

Answer:

I am calculating the total area of a solar panel for a particular load demand by ... designing according to energy demand for a day then how will it affect total solar area? ... Total Power Output=Total Area x Solar Irradiance x Conversion Efficiency ... would need is a 1 m2 solar panel to produce 1000 Watts of electrical energy.

Explanation:

Answer:

True

Explanation:

I’m not 100% sure

Answer:

Gases - Water vapor, Nitrogen, Oxygen etc. Describe what happens to air pressure as you rise upwards in the atmosphere. What causes this change in air pressure? As altitude increases, air pressure will decrease As altitude increases the gas molecules that make up the air spread further apart

Answer: As you rise upwards in the atmosphere, air pressure decreases

Explanation: Because there are fewer molecules in the air, the air has a lower density, which results in a drop in air pressure. At different altitudes, the air is not the same. The area close to the earth is denser. As we rise, it continues to thin out. As a result of more air nearby, there is also increased air pressure. The weight and pressure of the air also continue to reduce as the volume of air does.

Answer:

B . Second law

Explanation:

According to second law:

Net Force acting on the body produce acceleration. The magnitude acceleration of the body is directly proportional to net force and inversly proportional to the mass.

Mathematically:

                   a = [tex]\frac{F}{m}[/tex]

and

                   F = ma

So according to the given condition Waldo should use Second law.

Answer:

The force holding you down is gravity.

Explanation:

Gravity is a force between two objects with mass. It pulls things together. You have mass, and the Earth has mass, so gravity tries to pull you and the Earth together. The gravitational force is much bigger for more massive objects.

Answer:

Gravitational Force

Explanation:

Gravitational Force holding everything down

-TheUnknownScientist

Answer:

2.72*10^-7m

Explanation:

Using the formula

v = fλ

v is the speed

f is the frequency

λ is the wavelength

Substitute for λ

λ = v/f

λ = 2.05 x 10^8/7.55 x 10^14

λ = 2.05/7.55 * 10^{8-14}

λ = 0.272 * 10^-6

λ = 2.72*10^-7m

Hence the wavelength of the wave in carbon tetrachloride is 2.72*10^-7m

Answer:

The Earth's magnetic field intensity is roughly between 25,000 - 65,000 nT (.25 -.65 gauss).

Explanation:

To measure the Earth's magnetism in any place, we must measure the direction and intensity of the field. The Earth's magnetic field is described by seven parameters. These are declination (D), inclination (I), horizontal intensity (H), the north (X), and east (Y) components of the horizontal intensity, vertical intensity (Z), and total intensity (F). The parameters describing the direction of the magnetic field are declination (D) and inclination (I). D and I are measured in units of degrees, positive east for D and positive down for me. The intensity of the total field (F) is described by the horizontal component (H), vertical component (Z), and the north (X) and east (Y) components of the horizontal intensity. These components may be measured in units of gauss but are generally reported in nanoTesla (1nT * 100,000 = 1 gauss). The Earth's magnetic field intensity is roughly between 25,000 - 65,000 nT (.25 - .65 gauss). Magnetic declination is the angle between magnetic north and true north. D is considered positive when the angle measured is east of true north and negative when west.  The magnetic inclination is the angle between the horizontal plane and the total field vector, measured positive into Earth. In older literature, the term “magnetic elements” is often referred to as D, I, and H.

Answer:

The distance traveled by the tuning fork is 9.37 m

Explanation:

Given;

source frequency, [tex]f_s[/tex] = 683 Hz

observed frequency, [tex]f_o[/tex] = 657 Hz

The speed at which the tuning fork fell is calculated by applying Doppler effect formula;

[tex]f_o = f_s [\frac{v}{v + v_s} ][/tex]

where;

[tex]v[/tex] is speed of sound in air = 343 m/s

[tex]v_s[/tex] is the speed of the falling tuning fork

[tex]657 = 683[\frac{343}{343 + v_s} ]\\\\\frac{657}{683} = \frac{343}{343 + v_s}\\\\0.962 = \frac{343}{343 + v_s}\\\\0.962(343 + v_s) = 343\\\\343 + v_s = \frac{343}{0.962} \\\\343 + v_s = 356.55\\\\v_s = 356.55 - 343\\\\v_s = 13.55 \ m/s[/tex]

The distance traveled by the tuning fork is calculated by applying kinematic equation as follows;

[tex]v_s^2 = v_o^2 + 2gh[/tex]

where;

[tex]v_o[/tex] is the initial speed of the tuning fork = 0

g is acceleration due to gravity = 9.80 m/s²

[tex]v_s^2 = 0 + 2gh\\\\h = \frac{v_s^2}{2g} \\\\h = \frac{13.55^2 }{2\times 9.8} \\\\h = 9.37 \ m[/tex]

Therefore, the distance traveled by the tuning fork is 9.37 m

The complete options are;

A. The average kinetic energy of their particles is the same.

B. The total kinetic energy of their particles is equal.

C. Heat flows from the larger object to the smaller object.

D. Heat flows from the object with higher potential energy to the object with lower potential energy.

Answer:

Explanation:

From the relationship between average kinetic energy and temperature, we have the formula;

E_k = (3/2)kT

Where;

k is a constant known as boltzmann constant.

T is known as temperature

We can see that at the same temperature (T), kinetic energy will remain the same because from the formula, E_k depends km only the temperature.

Thus, average kinetic energy of their particles saying that.

Pulling on the cord, exerting a force of 15 N for 2 s and then 25 N for 3 s, and measuring the final angular velocity of the disk.

[tex]\tau = \frac{dL}{dt} \\\\[/tex]

[tex]Fr = \frac{\Delta L}{\Delta t} \\\\Fr = \frac{\Delta m\omega ^2r}{\Delta t} \\\\F = \frac{\Delta m\omega ^2}{\Delta t}[/tex]

[tex]F = \frac{m\Delta \omega ^2}{\Delta t} \\\\F = \frac{m(\omega _f^2 - \omega _i^2)}{t_2 - t_1}[/tex]

where;

[tex]\omega _i[/tex] is the initial angular velocity

[tex]\omega _f[/tex] is the final angular velocity

Since the disk is initial at rest, applying a force such as 15 N gives the disk its first angular velocity and applying 25 N force for 3 seconds gives the disk its final angular velocity.

Thus, the best procedure to determine the relationship between applied torque and the resulting change in angular momentum of the disk is

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Answer:

Explanation:

Given that:

[tex]mass \ m_ 1 = 11.0 \ kg[/tex]

[tex]mass \ m_2 = 19.0 \ kg[/tex]

[tex]mass \ of \ the \ pulley\ M = 7.90 \ kg[/tex]

[tex]Radius \ of \ the \ pulley = 0.200\ m[/tex]

1) Provided that the mass in [tex]m_2[/tex] is greater than the mass we have in [tex]m_1[/tex], then likewise the tension we have in [tex]T_2[/tex] will be greater than the tension in [tex]T_1[/tex]

Using Newton's second law to mass [tex]m_1[/tex], we have:

[tex]m_2g - T_2 = m_2 a \\ \\ T_1 = m_1 g +m_1 a \\ \\ T_1= m_1 (g+a) --- (1)[/tex]

By using the second law, we have:

[tex]m_2g - T_2 = m_2a \\ \\ T_2 = m_2 (g-a)---(2)[/tex]

For the pulley, let's use the torque equation, so we have:

[tex]T_2 r -T_1 r = I \alpha \\ \\ T_2r -T_1r = \Big ( \dfrac{Mr^2}{2}\Big) \dfrac{a}{r} \\ \\ T_2 -T_1 = \dfrac{Ma}{2} ---- (3)[/tex]

Altogether, from equation (1)(2) and (3), we have:

[tex]m_2(g-a) -m_1 (g+a) = \dfrac{Ma}{2} \\ \\ m_2g -m_2a -m_1g-m_1a = \dfrac{Ma}{2} \\ \\ a = \dfrac{(m_2 -m_1) g}{(m_1 + m_2 + \dfrac{M}{2})} \\ \\ a = \dfrac{(19.0 \ kg - 11.0 \ kg ) ( 9.8 \ m/s^2)}{(19.0 \ kg + 11.0 \ kg + \dfrac{7.90 \ kg }{2} )}[/tex]

[tex]a = 2.31 \ m/s^2[/tex]

Also; from equation (1), the tension in the string is:

[tex]T_1[/tex] = (11.0 kg ) ( 9.8 + 2.31) m/s²

[tex]T_1[/tex] = 133.21 N

[tex]T_1[/tex] ≅ 133 N

From equation (2):

[tex]T_1[/tex] = m_2(g-a)

[tex]T_1[/tex] = (19.0 kg) ( 9.8 - 2.31) m/s²

[tex]T_1[/tex] = 142.31 N

[tex]T_1[/tex]  = 142 N

Answer:

Carbon dioxide

Explination:

I remember it from biology.

I hope this helps ^-^

In a chemical reaction, carbon combines with oxygen to form carbon dioxide gas.

A chemical reaction can be defined as a process that causes the chemical transformation of one chemical substance to another. The chemical reactions accompany chemical changes that involve the rearrangement of electrons in the forming and breaking of bonds between atoms, with no change to the nuclei.

The substances which are primarily involved in a reaction are known as reactants or reagents. Chemical reactions are commonly characterized by a chemical change, and yield products, which exhibit properties different from the reactants.

Chemical reactions take place at a characteristic rate of reaction at a given temperature, pressure, and chemical concentration. The rates increase with the increasing temperature of the reaction when more thermal energy is available to achieve the activation energy for breaking bonds between atoms.

The combustion reaction takes place when carbon combines with oxygen to produce carbon dioxide gas.

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Answer:

B. As gravity increases weight increases and as gravity decreases weight decreases

Explanation:

Option B is the correct answer.

From the information given, we can deduce that as the gravity increases, the weight also increases and as the gravity decreases, the weight decreases as well.

This is true from the  given table. On earth, the gravity of the man was 9.8m/s² and his weight 588N. But get to space, moon precisely, the gravity reduced to 1.62m/s². Then we discover that such decrease in his gravity also led to the sharp decrease in the weight. The weight decreased from 588N on earth to 96N on the moon.

This actually reveals that weight and gravity are related in a way. Weight of an object is known to be the force of gravity on the object. The weight actually vary as a result of varying gravity.

Answer: b

since the pull of gravity on the moon is less we weigh less.

Answer:

R = (18 ± 2) 10¹ Ω

ΔR = 2 10¹ Ω

Explanation:

Ohm's law relates voltage to current and resistance

           V = i R

            R = [tex]\frac{V}{i}[/tex]V / i

the absolute error of the resistance is

           ΔR = | [tex]| \frac{dR}{DV} | \ \Delta V + | \frac{dR}{di} | \ \Delta i[/tex]

the absolute value guarantees the worst case, maximum error

           ΔR = [tex]\frac{1}{i} \Delta V+ \frac{V}{i^2} \Delta i[/tex]

The error in the voltage let be approximate, if we use a scale of 10 V, in general the scales are divided into 20 divisions, the error is the reading of 1 division, let's use a rule of direct proportion

          ΔV = 1 division = 10 V / 20 divisions

          ΔV = 0.5 V

The current error must also be approximate, if we have the same number of divisions

           Δi = 50 mA / 20 divisions

           Δi = 2.5 mA

let's calculate

          ΔR = [tex]\frac{1}{45.5 \ 10^{-3}} \ 0.5 + \frac{8.2}{(45.5 \ 10^{-3})^2 } \ 2.5 \ 10^{-3}[/tex]

          ΔR = 10.99 + 9.9

          ΔR = 20.9 Ω

The absolute error must be given with a significant figure

          ΔR = 2 10¹ Ω

the resistance value is

          R = 8.2 / 45.5 10-3

          R = 180 Ω

the result should be

          R = (18 ± 2) 10¹ Ω

Answer:

by radiation

by heating

electrically

mechanically