Answer:
1.619
Step-by-step explanation:
We have the formulas for the volume of the sphere and the cylinder:
Vs = (4/3) * pi * (r ^ 3)
Vc = pi * h * (r ^ 2)
Thus:
(4/3) * pi * (r ^ 3) + pi * h * (r ^ 2) = 10
Now, the formula for the surface area of the cylinder and sphere are:
As = 4 * pi * (r ^ 2)
Ac = 2 * pi * r * h + 2 * pi * r ^ 2
Using this equation for the total surface area of the solid, we can see that as "h" increases, so will the surface area. Therefore, the smallest surface area will occur at h = 0.
Thus:
(4/3) * pi * (r ^ 3) + pi * 0 * (r ^ 2) = 10
(4/3) * pi * (r ^ 3) = 10
r ^ 3 = 4 * 10 / (3 * 3.14)
r ^ 3 = 4.24
r = 1.619
so the radius is 1.619
Mario writes the equation (x+y ) 2 = z 2 +4( 1 2 xy) (x+y)2=z2+4(12xy) to begin a proof of the Pythagorean theorem. Use the drop-down menus to explain why this is a true equation.
Answer:
For the drop down menu:
i) x + y
ii) z²
iii) ½ xy
The complete question related to this found on brainly (ID:16485977) is stated below:
Mario writes the equation (x+y)² = z² +4( 1/2 xy) to begin a proof of the Pythagorean theorem. Use the drop-down menus to explain why this is a true equation.
_____finds the area of the outer square by squaring its side length.
_____finds the area of the outer square by adding the area of the inner square and the four triangles.
These expressions are equal because they both give the areas of outer space.
Find attached the diagram of the question.
Step-by-step explanation:
Pythagoras theorem is a formula that shows the relationship between the sides of a right angled triangle.
Pythagoras theorem
Hypotenuse ² = opposite ² + adjacent ²
From the diagram of the question.
Hypotenuse = z
Opposite = y
Adjacent = x
z² = x² + y²
Area of outer square = area of inner square + 4(area of triangles)
area of inner square = length² = (x+y)²
Expanding area of the outer square:
(x+y)² = (x+y)(x+y) = x²+xy+xy+y²
(x+y)² = x²+y²+2xy
= z² + 2xy
Area of inner square = length² = z²
Area of triangle = ½ base × height
= ½ × x × y = ½ xy
Area of outer square = area of inner square + 4(area of triangles)
(x + y)² = z² + 4(½xy )
Therefore, it is a true equation.
( x + y )² finds the area of the outer square by squaring its side length.
z² + 4( 1/2xy ) finds the area of the outer square by adding the area of the inner square and the four triangles.
These expressions are equal because they both give the areas of outer space.
So for the drop down menu:
i) x + y
ii) z²
iii) ½ xy
Please help me ASAP!
Answer:
Exponential growth
Step-by-step explanation:
This is not a negative so it is growing.
Hope this helps!
what is -5c plus 2 less than or equal to 27. I need this for very difficult homework if anyone can help :)
Answer:
c ≥ -5
Step-by-step explanation:
-5c +2 ≤ 27
Subtract 2 from each side
-5c +2-2 ≤ 27-2
-5c ≤25
Divide by -5, remembering to flip the inequality
-5c/-5 ≥25/-5
c ≥ -5
Answer: [tex]x\geq 5[/tex]
Step-by-step explanation:
[tex]-5x+2\leq 27\\Subtract\\-5x\leq 25\\Divide\\x\geq 5[/tex]
It's important to remember that when you divide both sides of an inequality by a negative number to flip the sign.
Hope it helps <3
Please help!! Tamar is measuring the sides and angles of Triangle TUV to determine whether it is congruent to the triangle below.
Answer:
Measure of angle T = 25 degrees and TU = 12
Step-by-step explanation:
Tamar is measuring the sides and angles of Triangle T U V to determine whether it is congruent to the triangle below. For triangle K L M, side K M is 27 millimeters, side L M is 20 millimeters, and side K L is 12 millimeters. Angle K is 45 degrees, angle M is 25 degrees, angle L is 110 degrees. Which pair of measurements would eliminate the possibility that the triangles are congruent? Measure of angle T = 25 degrees and Measure of angle U = 45 degrees Measure of angle T = 110 degrees and Measure of angle V = 25 degrees Measure of angle T = 25 degrees and TU = 12 Measure of angle T = 110 degrees and UV = 27
Answer: Two triangles are congruent to each other if they have the same shape and size (i.e the same sides and angles).
The ways used to find congruence are:
1) Angle-side-angle: If two angles and an included side of a triangle is equal to the two angles and corresponding side of another triangle, then they are equal.
2) Side-side-side: If all three sides of a triangle is equal to the three sides of another triangle, then the two triangles are congruent.
3) Side angle side: If two sides and an included angle of a triangle is equal to the two sides and corresponding angle of another triangle, then they are equal.
4) Hypotenuse - leg: If the hypotenuse and one leg of a triangle is equal to the hypotenuse and leg of another triangle then they are equal.
5) Angle angle side: If two angles and an non included side of a triangle is equal to the two angles and corresponding side of another triangle, then they are equal.
Measure of angle T = 25 degrees and TU = 12 would eliminate the possibility that the triangles are congruent because if T = 25°, then the side opposite angle T (UV) is suppose to be 12
Answer:
the answer is C
Step-by-step explanation:
I got it right on my final exam on edge
USE THE IMAGE ATTACHED BELOW please help me with my work answer it correctly I HAVE SO MUCH WORK DURING QUARANTINE
Answer:
Question 1:
a. The answer is B because the graph inclined really quickly and then it inclined at a much slower pace, suggesting that the person was running and then walking.
b. The answer is C because you can see on the graph that after a while, the distance from the starting point goes back to 0, indicating that the person forgot something at home.
Question 2:
a. The dashed line reaches the bottom at 15:30 so the answer is C.
b. Siobhan travels 8 km to go from home to school so the answer is 2 * 8 = 16 which is option D.
Question 3:
The answer is C because after the distance from the starting point increased, it then decreased and came back to the original point suggesting that he walked, turned around and walked back to the starting point.
Answer:
first page : a) A because it is the shortest time with no stop
b) C the graph goes up and return to the start point after a while
second page : it is at 3:30 0r 15:30
b): 8 km going to schools and 8 coming back is 16
third page it is C because he walk up a certain distance and come back to the starting point
which situation is most likely to show a constant rate of change
Answer:
B. The amount spent on grapes compared with the weight of the purchase.
Step-by-step explanation:
A: The shoe size of a young girl compared with her age in years. For the first few years of a girl's life, her shoe size is relatively the same. When she goes through a growth spurt, her shoe size increases exponentially. So, that is not a constant rate of change.
B: The amount spent on grapes compared with the weight of the purchase. In most grocery stores, grapes are sold based on their weight, like $2.50 per pound. With each increase in 1 pound, the cost increases by $2.50. That is a constant rate of change.
C: The number of people on a city bus compared with the time of day. This value widely changes throughout the day. For example, during rush hour, there will be many people. But during times at, say, 2 to 3 AM, there will not be many people. So, this is not a constant rate of change.
D: The number of slices in a pizza compared with the time it takes to deliver it. The number of slices in a pizza never changes, so it does not depend on the time it takes to deliver. There is no rate of change.
So, B is your answer.
Hope this helps!
Answer:
B
Step-by-step explanation:
i just did it
the triangle ADE
BC is parallel to DE
AB = 9cm, AC = 6cm, BD = 3cm, BC = 9cm
Answer:
a) DE is 12 cm
b) CE is 2 cm
Step-by-step explanation:
In the two triangles [tex]\triangle ABC[/tex] and [tex]\triangle ADE[/tex].
[tex]\angle A[/tex] is common.
BC || DE
[tex]\Rightarrow \angle B = \angle D\ and \\ \Rightarrow \angle C = \angle E[/tex]
[tex]\because[/tex] two parallel lines BC and DE are cut by BD and CE respectively and the angles are corresponding angles.
All three angles are equal hence, the triangles:
[tex]\triangle ABC[/tex] [tex]\sim[/tex] [tex]\triangle ADE[/tex].
Ratio of corresponding sides of two similar triangles are always equal.
[tex]\dfrac{AB}{AD} = \dfrac{BC}{DE}\\\Rightarrow \dfrac{9}{9+3} = \dfrac{9}{DE}\\\Rightarrow \dfrac{9}{12} = \dfrac{9}{DE}\\\Rightarrow DE = 12\ cm[/tex]
[tex]\dfrac{AB}{AD} = \dfrac{AC}{AE}\\\Rightarrow \dfrac{9}{9+3} = \dfrac{6}{AC+CE}\\\Rightarrow \dfrac{9}{12} = \dfrac{6}{6+CE}\\\Rightarrow 6+CE = \dfrac{4\times 6}{3}\\\Rightarrow 6+CE = 8\\\Rightarrow CE = 2\ cm[/tex]
So, the answers are:
a) DE is 12 cm
b) CE is 2 cm
A projectile is fired straight up from ground level with an initial velocity of 112 ft/s. Its height, h, above the ground after t seconds is given by h = –16t2 + 112t. What is the interval of time during which the projectile's height exceeds 192 feet?
A. 3
B. t<4
C. t>4
D. 3>t>4
Answer: 3 < t < 4
Step-by-step explanation:
Given the following information :
Initial Velocity of projectile = 112 ft/s
Height (h) above the ground after t seconds :
h = –16t2 + 112t
To calculate the time when h exceeds 192 Feets (h >192)
That is ;
-16t^2 + 112t = > 192
-16t^2 + 112t - 192 = 0
Divide through by - 16
t^2 - 7t + 12 = 0
Factorizing
t^2 - 3t - 4t + 12 =0
t(t - 3) - 4(t - 3) = 0
(t-3) = 0 or (t-4) =0
t = 3 or t=4
Therefore, t exist between 3 and 4 for height in excess of 192ft
–16(3)^2 + 112(3) = 192 feets
–16(4)^2 + 112(4) = 192 feets
3 < t < 4
There are two cube-shaped tanks. One of the tank has a 3 m side, while the other one has a side measuring half of the first one. Which tank can store more water and why
Answer: The tank which has 3 m side.
Step-by-step explanation: A cube is a form that has equal sides. To calculate the volume of it, multiply all three sides:
V = length*width*height
Since they are all the same, volume will be:
V = s³
One tank has a 3 m side, so its volume is:
V = 3³
V = 27 m³
The other has half of the first one side, then s = [tex]\frac{3}{2}[/tex] and volume will be:
V = [tex](\frac{3}{2})^{3}[/tex]
V = [tex]\frac{27}{8}[/tex] m³
As you can see, the volume of the second tank is [tex]\frac{1}{8}[/tex] smaller than the first one. Therefore, the tank which has 3 m side can store more water than the tank with side measuring half of the first.
Bottle A contains more soda than Bottle B. Pour from Bottle A into Bottle B as much soda as B already contains. Now pour from B into A as much soda as A now contains. Then pour from A into B as much soda as B now contains. Each bottle now contains 64 ounces. How many more ounces of soda were in Bottle A than Bottle B at the beginning?
Answer:
Bottle A started with 88 and bottle B started with 40
Step-by-step explanation:
To find out what they started with I got the ounces they finished with an the equation they did to get there.
Ended in 64 oz.
To get there:
A => B
B => A
A => B
Every time a pour is made the bottle to the right is doubled so I got 64 and divided it by 2 to see what B had before the pour of bottle A.
B had 32 oz. and A had 96 oz. before the last pour. I got 96 oz. because for them to end up with 64 oz. A has to have 32 oz. + 64 oz. since you are pouring 32 oz. into bottle B.
Now you have this equation:
A => B
B => A
96 oz. => 32 oz.
64 oz.
I then do the same thing I did to find 96 and 32. Since B is giving to A now it has to have more then A but it has to end up with 34 oz. for this is got 96 oz. and I divided it by 2 which got me 48. So on the second pour A started with 48 and B had to have given A 48 plus have 32 so it could end up with 34 therefore making it have 80 oz.
Now you have this equation:
A => B
80 oz. => 48 oz.
96 oz. => 32 oz.
64 oz.
For the last part to get the first ounces to answer the question you will do the same steps. Get half of 80 to see what B had before the 2nd pour which will be 40 and then you have to get 48 + 40 sine bottle A has to have the same amount of soda as B plus 48 oz. that it ends up with. This will have bottle A as 88 oz.
The Answer:
88 oz. => 40 oz.
80 oz. => 48 oz.
96 oz. => 32 oz.
Both will end up with 64 oz.
PLEASE HELP ME! can someone explain this to me pls?
CAN SOMEONE TUTOR ME PLSSSSS ????
Answer:
[tex] \frac{105}{4} [/tex]
please see the attached picture for full solution..
hope it helps...
Good luck on your assignment..
helppppppppppppppppppppppppppppppp plz
The answer is the second image from left to right (B). Examples of direct and inverse variations are showed in the image below. :)
Multiple the polynomials (3x^2+4x+4) (2x-4)
Answer:
6x³ - 4x² - 8x - 16
Step-by-step explanation:
Step 1: Distribute the 2x
6x³ + 8x² + 8x
Step 2: Distribute the -4
-12x² - 16x - 16
Step 3: Combine the 2 distributions
6x³ + 8x² + 8x - 12x² - 16x - 16
Step 4: Combine like terms
6x³
8x² - 12x² = -4x²
8x - 16x = -8x
-16
Step 5: Rewrite
6x³ - 4x² - 8x - 16
━━━━━━━☆☆━━━━━━━
▹ Answer
6x³ - 4x² - 8x - 16
▹ Step-by-Step Explanation
(3x² + 4x + 4) (2x - 4)
Distribute
3x²(2x - 4) + 4x(2x - 4) + 4(2x - 4)
Remove parentheses
6x³ - 12x² + 4x(2x - 4) + 4(2x - 4)
Collect like terms
6x³ - 12x² + 8x² - 16x + 8x - 16
6x³ - 4x² - 16x + 8x - 16
Solve
6x³ - 4x² - 8x - 16
Hope this helps!
CloutAnswers ❁
Brainliest is greatly appreciated!
━━━━━━━☆☆━━━━━━━
SOMEONE HELPPP PLEASEEEE
Answer:
a. Domain = All real numbers
Range = y ≥ 2
b. Domain = -4 < x ≤ 4
Range = 0 ≤ y < 4
A football team carried out a report to see the impact of stretching on preventing injury. Of the 32 footballers in the squad 25 stretch regularly. Of those who stretch, 3 got injured last year. There was a total of 8 injured players last year. The results can be presented in a frequency tree. What fraction of players are not stretching regularly?
Answer:
1/16
Step-by-step explanation:
Total = 32 footballers
25 stretch regularly.
3 injure last year
now, 22 stretch regularly.
out of 32, 8 are injured. Therefore, 32-8=24 should stretch regularly but only
22 stretch regularly. Therefore, 24-22 =2 are not stretching regularly.
fraction of players are not stretching regularly = 2/32 =1/16
Amad was curious if triangles \triangle ABC△ABCtriangle, A, B, C, and \triangle EDF△EDFtriangle, E, D, F were congruent. He was able to map one figure onto the other using a reflection and a rotation. Amad concluded: "I was able to map \triangle ABC△ABCtriangle, A, B, C onto \triangle EDF△EDFtriangle, E, D, F using a sequence of rigid transformations, so the figures are congruent."
Answer:
There is no error, Amad is correct.
Step-by-step explanation:
Khan Academy Checked.
Amad had done no error. His conclusion is true.
What is Congruency?Two triangles are said to be congruent if their sides are equal in length, the angles are of equal measure, and they can be superimposed on each other.
For example,
In the figure given above, Δ ABC and Δ PQR are congruent triangles. This means that the corresponding angles and corresponding sides in both the triangles are equal.
Sides: AB = PQ, BC = QR and AC = PR;
Angles: ∠A = ∠P, ∠B = ∠Q, and ∠C = ∠R.
Therefore, Δ ABC ≅ Δ PQR
The following are the congruence theorems or the triangle congruence criteria that help to prove the congruence of triangles.
SSS (Side, Side, Side)SAS (side, angle, side)ASA (angle, side, angle)AAS (angle, angle, side)RHS (Right angle-Hypotenuse-Side or the Hypotenuse Leg theorem)As, from the given cases the prediction of congruency of two triangles is correct. There is no error he made.
Hence, Amad had not made any error.
Learn more about congruency here:
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A jacket is on sale for 10% off including the discount and 7% tax the sales price of the jacket is $115.56 what is the price of the jacket before the discount and tax
Answer:
120.00
Step-by-step explanation:
Let x be the original price
The price is 10% off, or we pay 90% of the original price
.9 x
Then we have to pay 7% sales tax
.9x * 7%
.9x * .07
.063x is the tax
Add this to the .9x we have to pay for the jacket
.9x + .063x = .963x
This is the cost of the jacket
.963x = 115.56
Divide each side by.963
.963x/.963 = 115.56/.963
x =120.00
The cost of the jacket before discount and tax is 120.00
Solve: 3/x-4 >0 A.x -4 C.x>4 D.x<-4
Answer:
C. x>4
Step-by-step explanation:
3/(x-4) > 0
3>0, so
x-4 >0
x > 4
A dilation has center (0, 0). Find the image of each point for the given scale factor. A(3,4);D7(A)
Answer:
6,8
Step-by-step explanation:
Question is down below
Answer:
a ) [tex]2 / n[/tex],
b ) [tex]15[/tex]
Step-by-step explanation:
This is a nice and short question we have here.
Given that a bag has n counters, and that one counter is blue, respectively the rest is red, if two counters are taken at random there isn't a definite percentage that one of the counters chosen is red or blue, but there is a fractional representation of this.
We could express n ( number of counters ) to form a probability of 2 / n. As you can see, two counters are taken at random over n counters, and thus we derived this fraction.
a ) [tex]2 / n[/tex]
____
Now we have this second part -
[tex]2 / n = 2 / 16,\\16 - 1 = 15[/tex]
Therefore, there are 15 red counters. Hope that helps!
identify the variable expression that is not a polynomial.
A. y+23
B. 3\sqrt(x)-2
C. x^3
D. 13
Answer:
B. 3\sqrt(x)-2
Step-by-step explanation:
A polynomial cannot have a variable in the denominator
A constant is a polynomial
3\sqrt(x)-2 and this cannot be simplified to get rid of the variable in the denominator so it is not a polynomial
There are nuts in three boxes. In the first box, there are 6 fewer pounds of nuts than in the other two boxes combined. In the second box, there are 10 fewer pounds of nuts than in the other two boxes combined. How many pounds of nuts are there in the third box?
Answer:
8 pounds
Step-by-step explanation:
Let a, b, c represent the number of pounds of nuts in the first, second, and third boxes, respectively. We can write the equations ...
a = b +c -6 . . . . . first box has 6# fewer than the total of the others
b = a +c -10 . . . . second box has 10# fewer than the total of the others
Substituting the second equation into the first, we find ...
a = (a +c -10) +c -6
0 = 2c -16 . . . . subtract a
0 = c -8 . . . . . . divide by 2
8 = c . . . . . . . . . add 8
There are 8 pounds of nuts in the third box.
if y varies inversely as x and y=6 when x=8 find y when x=7
Answer:
y = 5 1/4
Step-by-step explanation:
For direct or inverse variation relation
relation between two variable and y can be expresses in form of
y = kx where k is constant of proportionality .
Only thing happens in inverse relation is that when x increases then y decreases and vice versa. That is care by constant of proportionality
__________________________________
Thus, let the inverse relation be
y = kx
given
when y = 6 then x = 8
we will plug this value in y = kx
6 = k*8
=>k = 6/8 = 3/4
Thus,
relation is
y = 3/4 x
we have to find y when x = 7 ,
lets put x = 7 in y = 3/4 x
y = 3/4 *7 = 21/4 = 5 1/4
Thus, when x = 7 then y = 5 1/4
25 POINTS! The graph shows two lines, M and N. A coordinate plane is shown with two lines graphs. Line M has a slope of 1 and passes through the y axis at negative 2. Line N has a slope of 1 and passes through the y axis at negative 2. How many solutions are there for the pair of equations for lines M and N? Explain your answer. PLS ANSWER AS SOON AS POSSIBLE
Answer:
Infinite solutions
Step-by-step explanation:
Both lines have the same slope and y-intercept, therefore they are the same line and intersect at all points, resulting in infinite solutions.
The equation of a line is y = 4x + 15. what is the y-intercept of the line.
Answer:
15
Step-by-step explanation:
[tex]y = 4x + 15 \\ equating \: it \: with \\ y = mx + b \\ we \: find \\ b = 15 \\ \implies \: y - intercept = 15[/tex]
Answer:
Y intercept = 15
Step-by-step explanation:
Formula we use,
→ y = mx + b
→ b = y intercept
Then the y intercept will be,
→ y = mx + b
→ y = 4x + 15
→ [ b = 15 ]
Thus, required answer is 15.
PLEASE HELP ME I WILL MAKE YOU THE FAMOUS
Which description matches the graph of the inequality y<-1/2x+5 A.a shaded region above a dashed boundary line B.a shaded region below a dashed boundary line C.a shaded region below a solid boundary line D.a shaded region above a solid boundary line
Answer:
B
Step-by-step explanation:
dashed line above the shaded area, shaded area below dashed boundary line
write a function that represents the situation: A population of 210,000 increases by 12.5% each year
Answer
y= 12.5x + 210,000
Step-by-step explanation:
This is a linear function because it is increasing constantly by 12.5 percent so it will me written as y=mx+b
The value of function that represents the situation is,
⇒ P = 210,000 (1.125)ⁿ
Where, n is number of years.
What is an expression?Mathematical expression is defined as the collection of the numbers variables and functions by using operations like addition, subtraction, multiplication, and division.
We have to given that;
The situation is,
⇒ A population of 210,000 increases by 12.5% each year.
Now, Let number of years = n
Hence, The value of function that represents the situation is,
⇒ P = 210,000 (1 + 12.5%)ⁿ
⇒ P = 210,000 (1 + 0.125)ⁿ
⇒ P = 210,000 (1.125)ⁿ
Learn more about the mathematical expression visit:
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Examine the diagram of circle C. Points Q, V, and W lie on circle C. Given that m∠VCW=97∘, what is the length of VW⌢?
Answer:
[tex] \frac{97pi}{18} m [/tex]
Step-by-step Explanation:
==>Given:
radius (r) = 10 m
m<VCW = 97°
==>Required:
Length of arc VW
==>Solution:
Formula for length VW is given as 2πr(θ/360)
Using the formula, Arc length = 2πr(θ/360), find the arc length VW in the given circle
Where,
θ = 97°
r = radius of the circle = 10 m
Thus,
Arc length VW = 2*π*10(97/360)
Arc length VW = 20π(97/360)
Arc length VW = π(97/18)
Arc length VW = 97π/18 m
Our answer is,
[tex] \frac{97pi}{18} m [/tex]
Find the area and perimeter of shape ABCD with vertices A = (-1,-1), B = (2,3), C = (5,3), D = (8,-1).
Answer:
Perimeter = 22
Step-by-step explanation:
To find the perimeter, we will follow the steps below:
A = (-1,-1), B = (2,3), C = (5,3), D = (8,-1).
First, we will find the distance AB
A = (-1,-1), B = (2,3)
|AB| = √(x₂-x₁)²+(y₂-y₁)²
x₁ = -1 y₁=-1 x₂=2 y₂=3
we can now proceed to insert the values into the formula
|AB| = √(x₂-x₁)²+(y₂-y₁)²
= √(2+1)²+(3+1)²
= √(3)²+(4)²
= √9 + 16
=√25
= 5
|AB| = 5
Next, we will find the distance BC
B = (2,3), C = (5,3),
|BC| = √(x₂-x₁)²+(y₂-y₁)²
x₁ = 2 y₁=3 x₂=5 y₂=3
we can now proceed to insert the values into the formula
|BC| = √(x₂-x₁)²+(y₂-y₁)²
= √(5-2)²+(3-3)²
= √(3)²+(0)²
= √9 + 0
=√9
= 3
|BC|=3
Next, we will find the distance CD
C = (5,3), D = (8,-1).
|CD| = √(x₂-x₁)²+(y₂-y₁)²
x₁ = 5 y₁=3 x₂=8 y₂=-1
we can now proceed to insert the values into the formula
|CD| = √(x₂-x₁)²+(y₂-y₁)²
= √(8-5)²+(-1-3)²
= √(3)²+(-4)²
= √9 + 16
=√25
= 5
|CD|=5
Next, we will find the distance DA
D = (8,-1) A = (-1,-1)
|DA| = √(x₂-x₁)²+(y₂-y₁)²
x₁ = 8 y₁=-1 x₂=-1 y₂=-1
we can now proceed to insert the values into the formula
|DA| = √(x₂-x₁)²+(y₂-y₁)²
= √(-1-8)²+(-1+1)²
= √(-9)²+(0)²
= √81 + 0
=√81
= 9
|DA|=9
PERIMETER = |AB|+|BC|+|CD|+|DA|
=5 + 3+5 +9
=22
Perimeter = 22