The magnitude of accelration is 0.23 m/s^2 and the distance is 8.7 m
final speed , v = 2 m/s
time taken , t = 8.6 s
a)
Let the magnitude of accelartion be a
v = u + a * t
2 = 0 + a * 8.6
solving for a
a = 0.23 m/s^2
b)
The distance travelled in this time , s = v^2 /2a
s = 2^2 /( 2 * 0.23) m
s = 8.7 m
Magnitude refers to the size or extent of something, and it is often used in physics and mathematics to describe the strength or intensity of a physical quantity or phenomenon. Magnitude can be measured using various units, depending on the type of quantity being measured.
For example, in physics, the magnitude of a force is the strength or intensity of the force, and it is typically measured in units such as newtons (N) or pounds-force (lbf). The magnitude of a vector quantity, such as velocity or acceleration, is the length of the vector and is measured in units such as meters per second (m/s) or meters per second squared (m/s^2).
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Complete Question: -
A snowboarder on a slope starts from rest and reaches a speed of 2.0 m/s after 8.6 s.
(a) What is the magnitude of the snowboarder's average acceleration?
_____ m/s2
(b) How far does the snowboarder travel in this time?
_____ m
Describe the basic conditioning necessary to produce a current in a circuit without a voltage source and list the three methods of meeting this condition
To produce a current in a circuit without a voltage source, it is necessary to induce a voltage in the circuit by changing the magnetic field passing through it.
This is achieved through a process called electromagnetic induction. According to Faraday's law of electromagnetic induction, a voltage is induced in a circuit when there is a change in the magnetic flux through the circuit. To meet this condition, there are three basic methods: Moving a magnet relative to a coil of wire: When a magnet is moved close to a coil of wire or away from it, the magnetic flux through the coil changes and induces a voltage in the coil. This is the basic principle behind generators. Changing the current in a nearby coil: When the current in a coil of wire is changed, the magnetic field surrounding the coil changes, inducing a voltage in a nearby coil of wire. This is the basic principle behind transformers. Moving a coil of wire in a magnetic field: When a coil of wire is moved in a magnetic field, the magnetic flux through the coil changes, inducing a voltage in the coil. This is the basic principle behind electric motors. By using one of these methods, it is possible to produce a current in a circuit without a voltage source.
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An object has a potential energy of 19,000 J at a height of 2.75 m. What is the objects mass?
Answer:m = 0.7
Explanation:
Answer:
m = 705 kg
Explanation:
PE = m * g * h
m = PE / (g * h)
m = 19,000 (J) kg m/s² / (9.8 m/s² * 2.75 m)
m = 19,000 / (9.8 * 2.75 )
m = 19000 / 26.95
m = 705.009276438 kg
chatGPT
when there is zero voltage across an ideal photocell, the amount of current that flows from the photocell is:
When there is zero voltage across an ideal photocell, the amount of current that flows from the photocell is zero.
What is a photocell? A photocell is a transducer that converts light energy into electrical energy. It is also known as a photoresistor or light-dependent resistor (LDR). It is a sensor that detects light and converts it into electricity.
A photocell is a component that senses light levels and reacts to them. It is a semiconductor device that has an electrical resistance that changes depending on the amount of light it receives.
The amount of light received by a photocell is proportional to the current generated. As the light intensity decreases, the resistance of the cell increases.
The current through the circuit and the voltage across the circuit decrease when the resistance of the cell increases.The current that flows from an ideal photocell when there is zero voltage across it is zero.
The photocell produces a current proportional to the amount of light it receives. As a result, the ideal photocell has zero current when there is zero voltage across it. The photoelectric effect is responsible for the current generated by a photocell.
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Difference between Magma and Lava ? (Please note that this question is based on grade 4 question )
Answer: The difference between lava and magma is if they have breached the surface yet. If the molten rock is still inside the earth, it is considered magma. once the volcano or opening erupts and the molten rock is on the surface, it is lava.
a balloon with an internal pressure of 300. torr rises to a height of 30,000 feet, where the pressure is 15. torr. assuming temperature remains constant, by what ratio did the volume change?
The volume of the balloon increased by a factor of 20 or increased by 20 times.
We can use Boyle's Law to solve this problem, which states that the pressure and volume of a gas are inversely proportional, as long as the temperature remains constant.
Boyle's Law: P1V1 = P2V2
Where P1 and V1 are the initial pressure and volume, and
P2 and V2 are the final pressure and volume.
Also we know that P1 = 300 torr, P2 = 15 torr, and V1 = V
Therefore, after substituting
300 V = 15 (V2)
V2 = 300/15
V2 = 20 V1
Therefore, the volume changed by a factor of 20 or increased by 20 times.
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Two identical beakers each contain 250 mL of water. The temperature of the water is 85C in one beaker and 15C in the
other beaker. A drop of red food coloring is placed in each beaker at the same time. During the first minute, which of the
following is most likely to happen?
As comparison to 15°C water, 85°C water allows the food coloring to spread out more quickly. Due to convection currents, the food coloring will only disperse halfway through the water in each beaker.
What happens to the food dye drop?Adding a few drops of food coloring to a glass of water causes it to spread out and eventually color the water. Diffusion, a process, is typically to blame for this. The blending of components in a liquid is caused by diffusion.
Water osmosis or diffusion while adding food coloring?The food coloring spreads slowly through cold water as it diffuses. Food coloring diffuses more quickly in hot water. Particles travel more quickly when temperatures are higher.
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1. What accounts for the aircraft carrier having a greater kinetic energy than the orbiting satellite?
A. Mass
B. Speed
C. Mass and speed
2. What accounts for the pitched baseball having a greater kinetic energy than the falling nickel?
A. Mass
B. Speed
C. Mass and speed
3. What accounts for the bumblebee having more kinetic energy than the snail?
A. Mass
B. Speed
C. Mass and speed
4. How much do work would have to be done to the truck starting from rest to give it half the listed kinetic energy.
A. 0 J
B. 2.2*10^3 J
C. 5.7 * 10^5 J
D. 1.1 * 10^6 J
5. How fast would the truck be moving? If it had half the listed kinetic energy?
A. -52km/h
B. 0 km/h
C. 71 km/h
D. 118 km/h
1. C. Mass and speed
2. B. Speed
3. B. Speed
4. C. 5.7 * 10^5 J
5. C. 71 km/h
Calculate the work W done from x = 5 m to x = 10 m by the one-dimensional force depicted in the graph
The work W done from x = 5 m to x = 10 m by the one-dimensional force depicted in the graph is 250 J
What is the work done by the force?The work done by the force is the product of the force and distance traveled.
The product of the force and distance traveled is the sum of the area of the two triangles that are formed from x = 5 to x = 10
The area of the first triangle = 1/2 * 100 * 1
The area of the first triangle = 50 J
The area of the second triangle = 1/2 * √(100² + 1²) * 4
The area of the second triangle = 0.5 * √10001 * 4
The area of the second triangle = 200 J
Therefore, the work done = 200 + 50 J
Work done = 250 J
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Estimate the terminal speed of a wooden sphere (density 0. 830 g/cm3) falling through air, if its radius is 8. 50 cm and its drag coefficient is 0. 500. (The density of air is 1. 20 kg/m3. )
The estimated terminal speed of the wooden sphere falling through air is approximately 8.68 m/s.
To estimate the terminal speed of the wooden sphere falling through air, we can use the following equation:
[tex]V_{terminal}[/tex] = [tex](2mg) / (p_{air} \times Cd \times A \times v^2)[/tex]
Where:
[tex]V_{terminal}[/tex] is the terminal velocity (m/s)
m is the mass of the sphere (kg)
g is the acceleration due to gravity (9.81 m/[tex]s^2[/tex])
[tex]p_{air}[/tex] is the density of air (1.20 kg/[tex]m^3[/tex])
[tex]C_d[/tex] is the drag coefficient (0.500)
A is the cross-sectional area of the sphere ([tex]m^2[/tex])
v is the velocity of the sphere relative to the air (m/s)
First, we need to calculate the mass of the sphere:
[tex]m = (4/3) \times \pi \times r^3 \times p[/tex]
where:
r is the radius of the sphere (m)
ρ is the density of the sphere (kg/[tex]m^3[/tex])
Substituting the given values, we get:
[tex]m = (4/3) \times \pi \times (0.0850 m)^3 \times 830 kg/m^3\\m = 0.980 kg[/tex]
Next, we need to calculate the cross-sectional area of the sphere:
[tex]A = \pi \times r^2\\A = \pi \times (0.0850 m)^2\\A = 0.0228 m^2[/tex]
Now, we can substitute the values into the equation for terminal velocity and solve for [tex]V_{terminal}[/tex] :
[tex]V_{terminal}[/tex] = [tex](2mg) / (p_{air} \times Cd \times A \times v^2)[/tex]
[tex]V_{terminal}[/tex] =[tex](2 \times 0.980 kg \times 9.81 m/s^2) / (1.20 kg/m^3 \times 0.500 \times 0.0228 m^2 \times v^2)[/tex]
[tex]V_{terminal}[/tex] = 8.68 m/s
Therefore, the estimated terminal speed of the wooden sphere falling through air is approximately 8.68 m/s.
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if a force of 50 newton stretches a wire from 20m to 20.01m what is the amount of force required to stretch the same material from 20m to 20.05m
250N is the amount of force required to stretch the same material from 20m to 20.05m
What is a force in science?A force is an effect in physics that causes the motion of a mass object to alter its velocity (e.g., moving from a state of rest), i.e., to accelerate. It can be a shove or a draw, with magnitude and direction always present, rendering it a vector quantity. It is measured in newtons (N) and is denoted by the sign F. (formerly P).
Newton's second law, in its initial version, says that the total force operating on an object is equivalent to the rate at which its momentum varies with time.
Original length = 20m
first new length = 20.01m
first increase in length = 20.01m - 20m = 0.01m
Second new length = 20.05m
second increase in length = 20.05 - 20m = 0.05m
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Full Question: If a force of 50N stretches a wire from 20m to 20.01m, what is the amount of force required to stretch the same material from 20m to 20.05m?
A. 250N
B. 200N
C. 100N
D. 50N
One design feature to ensure that the thermometer measured the desired range of temperature
Answer:
tube (sufficiently) long / not too short.
How does Mowgli develop in the excerpt?
Mowgli becomes fearful of Messua.
Mowgli forgets the ways of the jungle.
O Mowgli begins to learn the ways of men.
0 Mowgli despises his previous life and family.
The correct option is C.In the excerpt, Mowgli begins to learn the ways of men, forgetting the ways of the jungle, beginning to learn the ways of men, and despising his previous life and family.
Mowgli struggles with his in-betweenness, his liminal status, his sense of belonging to two worlds. He loves the jungle but despairs being kicked out of the pack. He rues the fact that he cannot smell as well as the animals can, that he does not know all the stories of the jungle, and that he does not participate in the Time of New Talk.
Conversely, while he likes Messua, he hates the greedy and superstitious villagers as well as many of their customs, and chafes at life in the village. Thus, Mowgli's identity takes a long time to develop because he is constantly torn between these two worlds. He chooses the life of man at the end.Thus,the correct option is C.
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Question:
How does Mowgli develop in the excerpt?
a)Mowgli becomes fearful of Messua.
b)Mowgli forgets the ways of the jungle.
c) Mowgli begins to learn the ways of men.
d) Mowgli despises his previous life and family.
Why is it a good laboratory skill to make multiple trials and average them?
Making multiple trials and averaging them is a good laboratory skill for several reasons such as, it reduces random error, increases precisions, increases accuracy and confidence in the result.
Why should multiple trials necessary as a good laboratory skill?Why multiple trials necessary as a good laboratory skill is that Random errors can occur in any laboratory experiment due to small variations in measurement or other factors that are beyond the experimenter's control. By conducting multiple trials and averaging the results, these random errors are minimized, since they will be averaged out across the different trials.
Also by averaging multiple trials, the overall precision of the measurement is increased. This is because averaging reduces the effect of outliers or other anomalous results that may occur in individual trials
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a uniform rope hangs from a ceiling. without tugging on the rope, you give the bottom of the rope a wiggle and a wave travels upward along the rope. what can you say about the speed of the wave as the wave travels up the rope?
When a uniform rope hangs from a ceiling and you give the bottom of the rope a wiggle, the speed of the wave as the wave travels up the rope will remain constant.
A wave is a transfer of energy in which energy travels through a medium without the medium itself traveling. When the medium is influenced, this energy transmission can either be a mechanical wave, such as sound waves, or an electromagnetic wave, such as radio waves or light waves.
The way that waves transmit energy determines the characteristics of the wave.
The speed of the wave as it travels up the rope will remain constant due to the transverse nature of the wave that travels along a rope.
When a wave travels along a rope, the particles in the rope move perpendicular to the wave's direction. This is because the wave travels along a transverse plane, which means that it oscillates up and down at right angles to its propagation direction.
As a result, the rope will experience both compression and rarefaction, which will cause the wave to travel along the length of the rope in a manner that will maintain the speed of the wave constant.
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Consider a simple, ideal Rankine cycle modified with reheating. For constant mass flow rate, what is the affect on:
(a) pump power input,
(b) turbine power output,
(c) heat input required,
(d) waste heat rejected,
(e) thermal efficiency, and
(f) steam quality at the turbine exit
(a) Increasing the reheat in a simple, ideal Rankine cycle with a constant mass flow rate will result in an increase in pump power input. (b) Increasing the reheat in a simple, ideal Rankine cycle with a constant mass flow rate will result in a decrease in turbine power output.
(c) Heat input required increases due to the addition of reheat stages.
(d) Waste heat rejected increases due to the additional heat input required for reheating.
(e) Thermal efficiency slightly decreases due to the lower steam temperature after reheating.
(f) Steam quality at the turbine exit decreases slightly due to the lower steam temperature after reheating.
The Rankine cycle or Rankine Vapor Cycle is the process widely used by power plants such as coal-fired power plants or nuclear reactors. In this mechanism, a fuel is used to produce heat within a boiler, converting water into steam which then expands through a turbine producing useful work.
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a 56.2-gram tennis ball is loaded into a 1.27-kg homemade cannon. the cannon is at rest when it is ignited. immediately after the impulse of the explosion, a photogate timer measures the cannon to recoil backwards a distance of 6.1 cm in 0.0218 seconds. determine the post-explosion speed of the cannon and of the tennis ball.
A photogate timer measures the cannon to recoil backward at a distance of 6.1 cm in 0.0218 seconds. The post-explosion speed of the cannon and of the tennis ball is: 599.9 m/s
The post-explosion speed of the cannon and of the tennis ball can be determined using the impulse-momentum theorem. This theorem states that the impulse (change in momentum) is equal to the product of the average force and the time interval during which it acts.
The impulse is equal to the mass of the cannon times the change in velocity of the cannon. The mass of the cannon and the tennis ball is the sum of the mass of the cannon and the mass of the tennis ball, which is 1.326 kg. The time interval is 0.0218 seconds.
We can calculate the change in velocity of the cannon and the tennis ball using the equation impulse = mass x change in velocity. This gives us:
change in velocity = impulse / mass = (1.326 kg) x (6.1 cm) / (0.0218 s) = 599.9 m/s.
Therefore, the post-explosion speed of the cannon and the tennis ball is 599.9 m/s.
This calculation is based on the assumption that the impulse of the explosion is the same for both the cannon and the tennis ball. Therefore, the post-explosion speed of the cannon and the tennis ball is the same and equal to 599.9 m/s.
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If a planet had twice the earth's radius, but only one-third its mass, the acceleration due to gravity at its surface would be
The acceleration due to gravity at the surface of the planet would be one-twelfth (1/12) of the acceleration due to gravity at the surface of the Earth.
The acceleration due to gravity at the surface of a planet is given by the formula:
g = G * M / R^2
Where:
g is the acceleration due to gravity
G is the gravitational constant
M is the mass of the planet
R is the radius of the planet
we are given that the planet has twice the Earth's radius (2R) and one-third of its mass (1/3M).
now, the acceleration due to gravity at the surface of the planet would be:
g = G * (1/3M) / (2R)^2
= G * (1/3M) / 4R^2
= (1/12) * (G * M / R^2)
= (1/12) * gEarth
where gEarth is the acceleration due to gravity at the surface of the Earth.
Hence, the acceleration due to gravity at the surface of the planet would be one-twelfth (1/12) of the acceleration due to gravity at the surface of the Earth.
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A uniform stick has length l. The moment of inertia about the center of the stick is io. A particle of mass m is attached to one end of the stick. The moment of inertia of the combined system about the center of the stick is
A uniform stick has length l, The combined moment of inertia with mass M at one end of the rod is I₀ + M(L² ÷ 4).
The stick is I₀. The particle is MR² about the point of rotation but R = 1/2 the stick length so for the particle,
I = M × (L ÷ 2)²
I = M × L² × (1 ÷ 2)²
I = (1/4) × M × L²
Therefore, The total I is the sum of the separate is I₀ + (1/4) M L².
Then the combined moment of inertia with mass M at one end of the rod is:
I₀ = (mL²) ÷ 12
I = (mL²) ÷ 12 + M(L ÷ 2)²
I = I₀ + M(L ÷ 2)²
I = I₀ + M(L² ÷ 4)
Therefore, the combined moment of inertia with mass M at one end of the rod is I₀ + M(L² ÷ 4).
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Solve it fast pleaseeee.
1. The horizontal component of the force on the box, given that at force of 18 N was applied at angle of 34° to the horizontal is 15 N
2. The vertical component of the force on the box is 10 N
1. How do I determine the horizontal component of force?From the question given above, the following data were obtained:
Force applied (F) = 18 NewtonsAngle (θ) = 34 °Horizontal component of force (Fx) =?The horizontal component of the force can be obtained as illustrated below:
Horizontal component of force (Fx) = F × Cosθ
Horizontal component of force (Fx) = 18 × Cos 34
Horizontal component of force (Fx) = 15 N
2. How do I determine the vertical component of force?From the question given above, the following data were obtained:
Force applied (F) = 18 NewtonsAngle (θ) = 34 °Vertical component of force (Fy) =?The vertical component of the force can be obtained as illustrated below
Vertical component of force (Fy) = u × Sine θ
Vertical component of force (Fy) = 18 × Sine 34
Vertical component of force (Fy) = 10 N
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a horizontal rope is tied to a 50 kg box on frictionless ice. what is the tension in the rope if: a. the box is at rest? b. the box moves at a steady 5.0 m/s? c. the box has vx
A- The tension of the rope is 490.5N, when box is at rest , B- when box moves 5m/s tension is 500N, C- when the box has vx tension is 10Vx² N..
a)The tension in the rope when the box is at rest is equal to the weight of the box. Thus, the tension in the rope would be 50 kg x 9.81 m/s= 490.5 N.
b)When the box is moving at a steady 5.0 m/s, we need to use the equation of motion to find the tension in the rope. The equation of motion for a steady velocity is: F= ma+maF=2m(F=2m) (Since acceleration is zero)F=2(50kg)(0m/s²+5m/s²)F= 500N
c)When the box has a velocity component in the x-direction (Vx), the tension in the rope can be calculated as follows: F=ma+maF=2m(F=2m) (Since acceleration is zero)F=2(50kg)(Vx²/10m/s²)F= 10Vx² NThe tension in the rope when the box has a velocity component in the x-direction (Vx) is F = 10Vx² N.
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i have to teach (as a student) HOW A STEAM ENGIN WORKS
TELL ME ALL THE RESEARCH TOPICS FOR IT PLS
The steam engine moves a piston back and forth inside a cylinder using the force created by the pressure of the steam. A connecting rod and crank can convert this pushing force into a rotational force for wo
Why aren't steam engines used anymore?Because electric and diesel locomotives are faster, more effective, and simpler to operate, steam locomotives are no longer utilized to transport people or goods. The locomotives that are still in operation are historical artifacts from the 1800s that serve as a great reminder of how far we've come.
In what way do steam engines generate heat?Simply explained, steam engines generate heat energy by boiling water and producing steam using fire and coal (chemical energy). This heat energy is then used to push the cylinder and piston, which in turn moves the wheels (kinetic).
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6. Since the angular velocity is currently 360o/s, the period T is 1 rotation/s. A) Using v = 2r/T, calculate the tangential velocity the beetle would have if you moved him to the edge of the turntable (a radius of 4 m from the axis). B) Move the beetle to r = 4 m and record his tangential velocity
The required value to determine the value of the tangential velocity of the beetle is 25.13 m/s.
Write the provided data with suitable variables.
[tex]\omega = 360^o s^-1\\r = 4m[/tex]
Here, [tex]\omega[/tex] is the angular velocity and r is the radius.
Write the expression for the angular velocity and substitute the required values to determine the value of the period.
[tex]\omega = 2\pi / T\\360^o s^{-1}[/tex]× [tex]2\pi / 360^o =2\pi / T[/tex]
[tex]2\pi s^{-1} = 2\pi / T[/tex]
T = 1 s
Write the provided expression for the tangential velocity and substitute the required values to determine the value of the tangential velocity of the beetle.
[tex]\nu = 2r / T\\\nu = 2(4m) / 1 s\\\nu = 8m / s[/tex]
Write the expression for the tangential velocity when the beetle is moved to r = 4 m and substitute the required values to determine the value of the tangential velocity of the beetle.
[tex]\nu = 2\pi r/T\\\nu = 2\pi (4m) / 1 s\\\nu = 25.13 m/s[/tex]
B. If the beetle were moved to a radius of 4 m, its tangential velocity would still be given by v = 2r/T, where T is still 1 rotation/s. So, we can calculate the tangential velocity as:
v = 2r/T
v = 2(4 m)/(1 rotation/s)
v = 8 m/s
Tangential velocity is the component of an object's velocity that is perpendicular to its radial vector. In other words, it is the velocity of an object moving along a circular path, perpendicular to the radius of that circle.
When an object is moving in a circular path, it experiences a constant change in direction, and thus, its velocity is constantly changing. Tangential velocity measures the speed at which the object is moving along this circular path. The magnitude of the tangential velocity is equal to the object's speed, which is the distance covered by the object per unit time. The direction of the tangential velocity is always tangent to the circle at the point where the object is located.
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Catching a wave a 77 kg suffer starts with a speed of 1. 3 m/s
The amount of non-conservative work done on the sofa is 3833.83 Joules .
The total work done by the wave is expressed as;
Workdone = Potential energy + Kinetic energy
Workdone = mgh + 1/2mv²
m is the mass = 77kg
g is the acceleration due to gravity = 9.8m/s²
v is the velocity = 8.2m/s
h is the height = 1.65m
Substitute into the formula;
Workdone = 77(9.8) (1.65) + 1/2(77)8.2²
Workdone = 1245.09 + 2588.74
Workdone = 3833.83 Joules
It is a scalar quantity that depends on both the mass and velocity of an object. The formula for calculating kinetic energy is KE = 0.5 * m * v^2, where KE is the kinetic energy, m is the mass of the object, and v is its velocity.
When an object is in motion, it possesses kinetic energy because it has the ability to do work on other objects when it interacts with them. For example, a moving ball has the potential to do work when it collides with another ball, causing it to move and potentially change its direction or speed.
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4x10^-15C charged experiences a 5x10^-16N force. What is the strength of the electric field in that region of space?
Answer:
Explanation:
The electric force F exerted by the field on the positive charge is F = qE
where q is electric charge and E is electric field.
E=F/q=5 *10^-16/4*10^-15=1.25*10^-1 = 0.125N/C
The switch in a series RL circuit with a resistance of 6. 2 Ω , inductance of 3. 5 H, and
voltage of 38. 2 V is closed at t = 0. 3 s. What is the maximum current in the circuit?
Answer in units of A
The maximum current in the circuit is 17.46 A.
To find the maximum current in the circuit, we need to find the time at which the current reaches its maximum value. This occurs when the derivative of the current with respect to time is zero:
di/dt = (V/L) e^(-Rt/L) = 0
Solving for t, we get:
t = (L/R) ln(V/I)
where I is the maximum current.
Substituting the given values, we get:
t = (3.5/6.2) ln(38.2/I) = 0.3
Solving for I, we get:
I = 17.46 A
Inductance is a property of an electrical circuit that describes the ability of a component to store energy in a magnetic field. It is measured in henries (H) and is denoted by the letter L. Inductors are components that are specifically designed to have high inductance.
If the current is changing, then the magnetic field also changes, and this change induces a voltage in nearby conductors. This is known as electromagnetic induction, and it is the basis for many important electrical devices, including transformers and electric motors. The inductance of a component depends on several factors, including the number of turns in the coil, the size of the coil, and the material from which the coil is made.
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Convert this decimal into its fractional
form simplified completely.
0.350
Answer:
7/20
Explanation:
0.35 as a fraction =35/100
35/100 can b divided by 5 so =7/20
0.350 simplified as a fraction is 7/20
Answer:
7/20
Explanation:
how does changing the direction of the applied force change the amount of the force that is doing work?
The component of the force acting in the direction of an object's motion determines how much force is doing work on that object. The "parallel component" of the force is referred to as this.
Applied forceA force that is applied perpendicular to an object's motion has no effect since it does not add to the object's kinetic energy.
It follows that the force exerted on the item will increase if the applied force's direction is adjusted to make it more parallel to the direction of motion.
The amount of force accomplishing work will decrease, on the other hand, if the direction of the applied force becomes increasingly perpendicular to the direction of motion.
Take the movement of a box across a rough surface as an illustration.
Only a fraction of the force will be parallel to the surface of the force delivered at a 45-degree angle to the surface, contributing to the motion of the box.
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Tres participantes en un concurso de TV están colocados en el centro
de un campo plano grande. A cada uno se le proporciona una regla
graduada de un metro, un compás, una calculadora, una pala
y (en diferente orden para cada concursante) los siguientes tres desplazamientos:
A: 72. 4 m, 32. 0° al este del norte
B: 57. 3 m, 36. 0° al sur del oeste
C: 17. 8 m al sur
Los tres desplazamientos llevan al punto donde están enterradas las
llaves de un Porsche nuevo. Dos concursantes comienzan a medir de inmediato; sin embargo, el ganador calcula
primero a donde debe ir. Con tres cifras
significativas exprese la resultante
Para encontrar el punto donde están enterradas las llaves del Porsche nuevo, debemos sumar los tres desplazamientos dados en el problema.
Primero, el desplazamiento de A tiene una magnitud de 72.4 m y una dirección de 32.0° al este del norte. Usando trigonometría, podemos descomponer este desplazamiento en sus componentes vertical y horizontal: Componente vertical = 72.4 m sin(32.0°) ≈ 38.9 m hacia el norte. Componente horizontal = 72.4 m cos(32.0°) ≈ 61.5 m hacia el este. Por lo tanto, el desplazamiento de A se puede representar como un vector de 61.5 m hacia el este y 38.9 m hacia el norte. Segundo, el desplazamiento de B tiene una magnitud de 57.3 m y una dirección de 36.0° al sur del oeste. De manera similar, podemos descomponer este desplazamiento en sus componentes vertical y horizontal: Componente vertical = 57.3 m sin(36.0°) ≈ 34.4 m hacia el sur. Componente horizontal = 57.3 m cos(36.0°) ≈ 46.0 m hacia el oeste. Por lo tanto, el desplazamiento de B se puede representar como un vector de 46.0 m hacia el oeste y 34.4 m hacia el sur. Finalmente, el desplazamiento de C tiene una magnitud de 17.8 m hacia el sur. Este desplazamiento solo tiene una componente vertical. Ahora, podemos sumar los tres vectores de desplazamiento para obtener la resultante. Podemos hacer esto sumando las componentes horizontal y vertical por separado: Componente horizontal total = 61.5 m - 46.0 m = 15.5 m hacia el este
Componente vertical total = 38.9 m - 34.4 m - 17.8 m = -13.3 m hacia el norte. La magnitud de la resultante se puede encontrar usando el teorema de Pitágoras: |magnitud resultante| = sqrt((15.5 m)^2 + (-13.3 m)^2) ≈ 20.2 m. Por lo tanto, el concursante ganador debería ir en una dirección de aproximadamente 29.7° al este del norte para encontrar las llaves del Porsche nuevo.
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consider the following statement made by a student regarding a star's temperature and its corresponding absorption line spectrum. student: if i am looking at a star's absorption line spectrum and see that it has a lot of lines at the blue end of the spectrum, then the star must be hot because the blue lines are higher energy lines. do you agree or disagree with the student, and why?
I agree with the student's statement that if we look at a star's absorption line spectrum and see that it has many lines at the blue end of the spectrum, the star must be hot because the blue lines are higher energy lines.
This is because hotter stars have more energy than cooler ones, which means that their atoms are more excited and have a higher probability of emitting photons of higher energy levels. When a star emits light, it passes through a cloud of gas before reaching Earth, and as the light passes through this cloud, it interacts with the gas atoms. The photons of light with just the right amount of energy will be absorbed by the atoms, causing the electrons to jump up to higher energy levels, and this is what creates the absorption lines in the spectrum. The amount and position of these lines can provide useful information about the chemical composition, temperature, and other properties of the star.
As a result, a star's temperature is proportional to the energy of the photons it emits, which are responsible for creating the lines in its absorption spectrum. Since blue lines have higher energy than red lines, a star with many blue lines will be hotter than one with more red lines. In conclusion, the student's statement is correct because the blue lines represent higher energy levels, which are found in hotter stars, and thus, a star with many blue lines in its absorption spectrum will be hotter.
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A car wheel of radius 0.3 m has an angular acceleration of 2.45 rad/s2
. Calculate
the linear acceleration of wheel.
The linear acceleration of the car wheel is 0.735 m/s².
What is the the linear acceleration of car wheel?The linear acceleration of a point on the rim of a wheel is related to the angular acceleration of the wheel by the equation:
a = rα
Where "a" is the linear acceleration, "r" is the radius of the wheel, and "α" is the angular acceleration.
Given the data in the question;
angular acceleration of α = 2.45 rad/s² radius r = 0.3 m. linear acceleration a = ?Plug the given values into the above formula and solve for the linear acceleration of wheel.
a = r × α
a = 0.3 m × 2.45
a = 0.735 m/s²
Therefore, the linear acceleration is 0.735 m/s².
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