A small truck has a mass of 2085 kg. How much work is required to decrease the speed of the vehicle from 22.0 m/s to 13.0 m/s on a level road?

Answers

Answer 1

Answer:

Work required is 328387.5 Joules.

Explanation:

Given the following data;

Mass = 2085kg

Initial velocity, Vi = 13m/s

Final velocity, Vf =22m/s

To find the workdone;

We know that from the workdone theorem, the workdone by an object or a body is directly proportional to the kinetic energy possessed by the object due to its motion.

Mathematically, it is given by the equation;

W = Kf - Ki

Where;

W is the work required.

Kf is the final kinetic energy possessed by the object.

Ki is the initial kinetic energy possessed by the object.

But Kinetic energy = ½MV²

W = ½MVf² - ½MVi²

Substituting into the equation, we have;

W = ½(2085)*22² - ½(2085)*13²

Simplifying the equation, we have;

W = 1042.5 * 484 - 1042.5 * 169

W = 504570 - 176182.5

W = 328387.5J

Therefore, the work required to decrease the speed of the vehicle is 328387.5 Joules.


Related Questions

as an object falls:
a) both velocity and acceleration increase
b) velocity increases and acceleration decreases
c) velocity increases and acceleration is unchanged

Answers

Answer:

c it is not accelerating on it's on but gravity pulls it there for velocity increases.

As an object falls, velocity increases and acceleration is unchanged. Therefore, option C is correct.

What do you mean by velocity ?

The term velocity is defined as the direction of the movement of the body or the object.

Speed is fundamentally a scalar quantity. Velocity is, in essence, a vector quantity. It is the rate at which distance changes. It is the displacement rate of change.

The velocity of something is the rate at which it moves in a specific direction. For example, the speed of a car driving north on a highway or the speed of a rocket after launch. The scalar denotes that the absolute magnitude of the velocity vector is always the speed of motion.

Thus, it is not accelerating on it's on, but gravity pulls it there as velocity increases.

To learn more about velocity, follow the link:

https://brainly.com/question/18084516

#SPJ2

can someone help im not sure of my answer

Answers

Answer:

Yes

Explanation:

But I feel also 2 is correct but your answer is right

A car travels at a constant speed up a ramp making an angle of 28 degrees with the horizontal component of velocity is 40 kmh^-1, find the vertical and horizontal component of velocity.

Answers

Answer:

Vx = 35.31 [km/h]

Vy = 18.77 [km/h]

Explanation:

In order to solve this problem, we must decompose the velocity component by means of the angle of 28° using the cosine function of the angle.

[tex]v_{x} = 40*cos(28)\\V_{x} = 35.31 [km/h][/tex]

In order to find the vertical component, we must use the sine function of the angle.

[tex]V_{y}=40*sin(28)\\V_{y} = 18.77 [km/h][/tex]

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