The flow rate (in mm3/s) through the artery is [tex]7.031 * 10^-^1^1 m^3/s[/tex]
What is Poiseuille's Law?
Poiseuille's Law can be used to explain the fluid flow through an IV catheter. According to this, the viscosity (μ), pressure gradient (P), length (L), and diameter (r) of the tubing are all important variables that affect fluid flow (Q).
It is given by equation
Δp = 8μLQ / π[tex]R^4[/tex]
where,
Δp = pressure difference between the two ends
μ = dynamic viscosity
L = length of pipe
Q = volumetric flow rate
π = pi
R = pipe radius
Given,
Length of artery L = [tex]1.6 * 10^-^3m[/tex]
Radius R = [tex]2.4 * 10^-^5m[/tex]
Pressure Δp = 1.8 kPa = [tex]1.8 * 10^3 Pa[/tex]
Viscosity μ = [tex]2.084 * 10^-^3 Pa. s[/tex]
Subsituting the values in equation,
Δp = 8μLQ / π[tex]R^4[/tex]
Q = Δp × π[tex]R^4[/tex] / 8μL
Q = [tex]\frac{(1.8 * 10^3) (3.14)(2.4 * 10^-^5)^4}{8 * (2.084* 10^-^3)(1.6 * 10^-^3)}[/tex]
Q = [tex]7.031 * 10^-^1^1 m^3/s[/tex]
The flow rate (in mm3/s) through the artery is [tex]7.031 * 10^-^1^1 m^3/s[/tex]
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the transfer of electrical energy from one circuit to another without the aid of a conductor is called:
Answer:
Inductance or mutual inductance
Energy produced in one circuit induces energy in another
(such as high voltage produced by a coil from input by say, a 12V battery)
suppose you observe a star-like object in the sky. how can you determine whether it is actually a star or a quasar?
Consider the light spectrum. The maximum Doppler shift for spectral lines from stars is a few hundred km/s. The lines of even the nearest quasars are significantly more redshifted.
Describe the spectrum of light.
The term "light spectrum" refers to the range of various wavelengths that a light source emits. Light is measured in nanometers (nm). Each nanometer corresponds to a wavelength of light or a band of light energy. Visible light is the portion of the spectrum between 380 and 780 nanometers (nm).
What kind of light spectrum does that entail?
The frequency of the light determines the hue of the light in the visible spectrum. A rainbow or the split light from a prism always has the same visible spectrum.
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does the pa-28 have an alternate static source? if so, how is it activated and what actions are necessary to acquire the most accurate reading?
Optional equipment includes an alternate static source.
What is alternate static source?When the alternate static source is used, the instrument indications should differ as follows: The altimeter will show a higher altitude than the actual altitude, and the airspeed will show a higher speed than the actual airspeed.The airspeed will be higher than the actual speed. The altimeter will show a marginally higher altitude.Whenever the primary source of static air pressure is unavailable, use the alternate static air source.The most important rule to remember when using an alternate static air source is to always consult the owner's manual, POH, or AFM for information and limitations.The alternate static air source is simple to test. Activate the system with the appropriate control and monitor the VSI and altimeter for changes. As the lower static air pressure enters the system, the VSI will rise briefly and the altimeter will rise a few feet.To learn more about alternate static source refer to :
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how was the third law of motion discovered
Answer:
how was the third law of motion discovered
Explanation:
Isaac Newton discovered this law by exerting pressure on one object against another. The first object's force is felt and equally replicated by the second body. Thus, Isaac Newton proved that it's impossible to exert pressure on a single object without a similar reaction from the second object.
a plane flying with a constant speed of 300 km!h passes over a ground radar station at an altitude of 1 km and climbs at an angle of 30 . at what rate is the distance from the plane to the radar station increasing a minute later?
The rate of the distance from planar to radar is 150m.
A 300 mph aircraft will have traveled 300 miles in 30 minutes. The distance between the plane and the interceptor, which takes off a half-hour later, is 500 miles if we deduct the 300 miles from the 800 miles. The combined speeds of the two aircraft are what we need to look at next. 600 mph multiplied by 400 mph equals 1000 mph. Flying the remaining 500 miles will only take 30 minutes at those combined speeds.[tex]Distance= S\alpha sin\beta[/tex]=300 sin30
= 300 x 0.5
=150m
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A tradesman sharpens a knife by pushing it against the rim of a grindstone. The 45 cmcm diameter stone is spinning at 200 rpmrpm and has a mass of 25 kgkg . The coefficient of kinetic friction between the knife and the stone is 0.20.If the stone loses 10% of its speed in 10 ss of grinding, what is the force with which the man presses the knife against the stone?N = ?
The force with which the man presses the knife against the stone is 2.96 N.
Given that,
Diameter of the stone d = 45 cm = 0.45 m
Radius r = 45/2 cm = 22.5 cm = 0.225 m
Initial angular velocity ω₀ = 200 rpm = 200* 2π/6 rad/s = 20.94 rad/s
Final angular velocity ωf = (1 - 0.1)* 200 rpm = 180 rpm = 180* 2π/6 rad/s = 18.85 rad/s
Mass of the stone m = 25 kg
Coefficient of kinetic friction μ*k = 0.2
Time t = 10 s
Part a:
By using the equation of motion with uniform angular acceleration we will find out the angular acceleration of grindstone:
ω* f = ω₀ + α*t
⇒ α = ( ω* f - ω₀) / t = (18.85 rad/s - 20.94 rad/s)/ (10s) = -0.21 rad/s²
Negative sign shows that the wheel is decelerating.
Part b:
Consider the rim of grindstone as a solid disk, therefore the moment of inertia
I = 0.5*m*r² = 0.5*25* (0.225)²
We know that, Torque = Force* perpendicular distance
τ = (μ*k*F)*r ----(1)
Also:
τ = I* α = 0.5*25* 0.225²* 0.21 = 0.133 N-m
F = 0.133/(0.2*0.225) = 2.96 N
Thus, the force with which the man presses the knife against the stone is 2.96N.
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estimate the amount of mass that is converted to energy when a proton combines with a deuterium nucleus to form 3he.
Answer:7.99
Explanation:
During soccer practice one of your teammates sprains her ankle. You take an instant cold pack from the first aid kit to use on her ankle. It is not at all cold when you take it out. The instructions on the cold pack tell you to punch the pack so that you break open a sake of chemicals inside it. When you do that, you notice that the cold pack rapidly becomes quite cold. What happened?.
When you punch the pack of ice, you notice that cold pack rapidly becomes quite cold. This is because, chemical reaction took place absorbing thermal energy from the pack.
What is the absorption of thermal energy?Chemical reactions that absorb energy are called endothermic. In an endothermic reactions, more energy is absorbed when the bonds in the reactants are broken than it is released when new bonds are formed.
The process in making the cold pack is the physical act of dissolving. When ammonium nitrate is dissolved in water, that process is endothermic and thus producing the cold pack. All the reaction absorb energy, for example thermal energy from heat for its activation.
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a dulcimer string is supposed to vibrate at 247 hz. instead it is vibrating at 260 hz. ef picup part description answer save status a. determine the percent decrease in tension in the dulcimer string so that it vibrates at the correct frequency. (include units with answer) format check click here to check your answer 7.14 pts.100% 2% try penalty
The percentage decrease in the tension of the dulcimer string vibration is 99.09%.
Current vibration = 247 Hz
Required vibration = 260 Hz
We know that'
= V = vμ
= √ (T/μ)
Combining the two equations of two different vibrations'
= (T₁ / T₂) = (v₁/v₂)²
The percentage decrease is =
= [ 1 - (T₁ / T₂) ] X 100%
= [ 1 - (v₁/v₂)² ] X 100%
= [ 1 - (247/260)² ] X 100%
= [ 1 - 0.009025] X 100 %
= 99.09 %
The string with is supposed to vibrate at 260 Hz is vibrating at 247 Hz, thus the percentage decrease required to reduce the tension so that it vibrates at correct frequency is 99.09%.
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deep in the forest a 0.017kg leaf falls from a tree and drops straight to the ground. if its initial height was 5.3 m and its speed on landing was 1.3 m/s, how much nonconservative work was done on the leaf? what force does this nonconservative work?
So work done by non-conservative forces = -0.868 joules.
As per the data given in the question,
It is given that:
Weight of leaf = 0.017 Kg = 17 grams.
Initial height was 5.3 m
Speed on landing was 1.3 m/s,
So, to find the total non conservative work we will apply the work-energy theorem
The work-energy theorem states that the net work done on a system is equal to the change in kinetic energy, or that the work done by the sum of all forces acting on a particle equals the change in kinetic energy of the particle.
So, the value of energy lost [tex]=-\left(mgh-\frac{1}{2} m v^2\right)[/tex]
[tex]=-\left(17 \times 10^{-3} \times 9.8 \times 5.3-\frac{1}{2} \times 17 \times 10^{-3} \times(1-3)^2\right) \\& =-\left(882.98 \times 10^{-3}-14.365 \times 10^{-3}\right) \\& =-0.868 \mathrm{~J}[/tex]
Forces = -0.868 joules.
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1. A 50 kg carton slides at 4 m/s across an icy surface.
The sliding carton skids onto a rough surface and
stops in 3 seconds. Calculate the force of friction it
encounters.
Answer:
A carton of mass 50-kg slides across an icy surface at a speed of 4 m/s. Conclusion : The momentum of a carton of given mass moving with a particular velocity is 200 kg−m/s .
the mass of earth is 5.972 * 1024 kg, and the radius of earth is 6,371 km. a 750 kg satellite orbits 35,800 km above earth in a perfectly circular orbit. if the gravitational force is acting as the centripetal force to keep the satellite in orbit, what is the tangential velocity of the satellite in its orbit?
The speed or the tangential velocity of the satellite to keep it in its orbit is 3,073.5 meters per second.
The gravitational force between two objects is given by:
F = GMm/r²
Where:
G = constant of gravity = 6.674 x 10⁻¹¹ N.m²/kg²
M, m = mass of each object
r = distance between objects
Parameters given in the problem:
M = 5.972 x 10²⁴ kg
m = 750 kg
r = 6371 + 35,800 = 42,171 km = 42,171,000 m
Hence,
F = 6.674 x 10⁻¹¹ x 5.972 x 10²⁴ x 750 / 42,171,000²
= 168.1 N
This is equal to centripetal force:
F = m . v² / r
168.1 = 750 . v² / 42,171,000
v² = 9,446,304
v = 3,073.5 m/s
Hence, the tangential velocity of the satellite to keep it in its orbit is 3,073.5 m/s
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a 4 lb b ball is traveling around a circle of radius r1 = 3 feet quickly v1 = 6 ft/s. if the attached rope is pulled down the hole with constant speed vr = 2 ft/s
Answer:
ur gay
Explanation:
i said so
PLEASE HURRY
Part A:Two football players run at each other. One has a mass of 75 kg and is moving at 6 m/s.
The second has a mass of 100 kg and is moving at 8 m/s. Calculate the momentum of each
football player.
Part B:The two football players collide. What is the total momentum of the football players?
Part C:What is the velocity of the football players after the collision?
A: The momentum of the first player be 450 kg.m/s.
The momentum of the second player be 800 kg.m/s.
B: The total momentum of the football players be 1250 kg.m/s.
C: The velocity of the football players after the collision be 7.14 m/s.
What is velocity?The rate at which a body's displacement changes in relation to time is known as its velocity. Velocity is a vector quantity with both magnitude and direction. SI unit of velocity is meter/second.
Given that:
One has a mass of 75 kg and is moving at 6 m/s.
The second has a mass of 100 kg and is moving at 8 m/s
So, momentum of the first player = mass * velocity
= 75×6 kg.m/s
= 450 kg.m/s.
The momentum of the second player = mass * velocity
= 100×8 kg.m/s
= 800 kg.m/s.
If the two football players collide, the total momentum of the football players be = 450 kg.m/s + 800 kg.m/s = 1250 kg.m/s.
The velocity of the football players after the collision be = total momentum/total mass = 1250 kg.m/s./(75+100)kg = 7.14 m/s.
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which type or types of motion is particle motion in surface waves?
In surface waves, circular motion refers to particle motion. The particles that make up the majority of the medium are present in both transverse and longitudinal waves.
And travel both perpendicularly to the direction of the transported energy and parallel to it. Surface waves have particle motion that is neither longitudinal wave nor transverse waves. Motion is the phenomenon whereby an item shifts in relation to time. Motion is quantitatively characterized in terms of the body's change in position with respect to the observer's frame of reference as well as the velocity, acceleration, and speed of the body. Each material particle vibrates in a longitudinal wave about its usual rest position.
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a metal sphere of radius 15 cm has a net charge of 7.0 10-8 c. (a) what is the electric field at the sphere's surface?
Answer:
Electric field on the surface of the ball 28 kV/m
Explanation:
Given:
R = 15 cm = 0.15 m
q = 7.0·10⁻⁸ C
________________
E - ?
Electric field on the surface of the ball:
E = k·q / R²
E = 9·10⁹·7.0·10⁻⁸ / (0.15)² ≈ 28 000 V/m or E = 28 kV/m
block a has weight of 40 lb and vlock b has weight of 8 lb.the coefficient of kinetic friction between all surfaces of contact is u_k = 0.15. Knowing theta = 20 and P = 50 lb, determine (a) the acceleration of block B, (b) the tension in the cord.
The acceleration of block B is 0.5 and tension is 42.8 lb.
Acceleration is the rate of change of the velocity of an item with appreciation to time. Accelerations are vector portions. The orientation of an item's acceleration is given by the orientation of the net pressure appearing on that object.
Calculation:-
mass = 40 lb
u_k = 0.15.
P = 50 lb
theta = 10
Length of the rope
L=s + s+ Constant + s,
differentiate with respect to time
0=2a,+a,
a = 2a, (magnitude only)
a=0.5
At equilibrium, V = 0
N =40 + 8
N = 48 lb
K=μk
f, =0.15%48 = 7.2 1b
D Alembert principle
Σ F x = ma
P-T-T-f₁ = (40+8/32.2)a
50 - 2T - 7.2 = 1.4907a
2T +1.4907a, = 42.8
2T +1.4907x0.5a, = 42.8 lb
Acceleration is the charge at which velocity modifications with time, in terms of each speed and route. A factor or an object moving in a straight line is accelerated if it quickens or slows down. movement on a circle is extended despite the fact that the rate is consistent because the course is continually changing.
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uniform circular motion what is the direction of the force that acts on the clothes in the spin cycle of a washing machine? what exerts the force?
The direction of the force that acts on clothes in the spin cycle of a washing machine is inwards. if the force would have been acting outwards then the clothes would have flown off, but this is not the case.
What is uniform circular motion?
when an object moves in a circle at a consistent speed in a motion, it is said to be in a uniform circular motion.
What is an example of uniform circular motion?
A satellite made by man is an example of uniform circular motion. Apart from that another example of uniform circular motion is a rotating ceiling fan, also a wheel of a moving car is an example of uniform circular motion.
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what is the frequency of the second overtone if the fundamental frequency is 308 hz
A. 154hz
B. 924hz
C. 308hz
D 616hz
The frequency of the second overtone if the fundamental frequency is 308 Hz is equal to 1540 Hz.
What is overtone?An overtone can be described as any resonant frequency above the fundamental frequency of a sound. Overtones can be defined as all pitches higher than the lowest pitch within an individual sound. While the fundamental can be described as usually heard most prominently, overtones are present in any pitch except a true sine wave.
The lowest normal frequency is called the fundamental frequency, while the higher frequencies are known as overtones.
Given, the fundamental frequency, f₀ = 30 8 Hz
The relationship between the fundamental frequency and the second overtone is given by
f₂ = 5 f₀
f₂ = 5 × 308 = 1540 Hz
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an object of mass m rests on a frictionless surface and is attached to a horizontal ideal spring with spring constant k . the system oscillates with amplitude a . the oscillation frequency of this system can be increased by
A horizontal ideal spring with a spring constant of k is linked to a mass m object that is at rest on a frictionless surface. By lowering m, the system's oscillation frequency can be raised.
What is an example of frequency?
The number of times that a specific data value occurs is its frequency. A data value's frequency is represented by the letter f. In the event that five students achieve The grade A was said to have a frequency of five, much like in science.
What does frequency serve to accomplish?
The frequency, a crucial factor in science and engineering, describes the temporal rate of change observed in oscillatory and periodic phenomena, including mechanical vibrations, audio signals (sound), radio waves, and light.
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a girl is skipping stones across a lake. one of the stones accidentally ricochets off a toy boat that is initially at rest in the water (see the drawing). the 0.072-kg stone strikes the boat at a velocity of 13 m/s, 15° below due east, and ricochets off at a velocity of 11 m/s, 12° above due east. after being struck by the stone, the boat's velocity is 2.1 m/s, due east. what is the mass of the boat? assume the water offers no resistance to the boat's motion.
The precept of the conservation of momentum dictates that because the stone enters the water and pushes a number of the water downwards, the stone is compelled upwards.
There are 3 unique axes in any delivery, known as longitudinal, transverse, and vertical axes. The movements around them are called the roll, pitch, and yaw respectively.in order for the boat to move, the force of the wind pushes at the sail and reasons the boat to move.
Start something shifting, deliver impetus to something, as in A press convention set the brand new assignment in motion. it is also put as set the wheels in motion, as in permit's set the wheels in motion for the brand new library wing. This idiom dates from approximately 1800.
The answer is C, the force is a result of the interaction between the oars and the water the boat is visiting. that is the force that actions the boat forward.
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an object is to the left of a thin lens. the lens forms an image on a screen that is 2.70 mm to the right of the object. the height of the image is 2.60 times the height of the object. part a is the image upright or inverted? is the image upright or inverted? the image is inverte
The image is inverted and real because the question tells us that the image was formed on a screen.
How to know if an image is real and inverted?When the rays come together, a true image is created. A virtual image is always formed above the principal axis, therefore it is always upright, as opposed to a real image, which is always formed below the principal axis and is always inverted.
An image that can be projected onto a screen is a real image. Behind the lens, a virtual image appears to emerge.
The image is inverted, magnified, and real for an object that is between one and two focal lengths from the lens.
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comets travel around the sun in elliptical orbits with large eccentricities. if a comet has speed 2.0×104 m/s when at a distance of 2.4×1011 m from the center of the sun, what is its speed when at a distance of 5.2×1010 m . express your answer in meters per second.
Comets are small asteroid-like bodies when they are far from the Sun, traveling in highly ellipical orbits about the Sun. Comets go around the Sun in a highly elliptical orbit
How to find speed of a comet?
Speed of the comet can be determined by using conversation of energy = initial kinetic energy + initial potential energy of comet = final kinetic energy + final potential energy of comet
We know,
M = mass of sun = 1.989 x 1030 kg
m = mass of comet
vi = initial speed of comet = 20000 m/s
ri = initial distance from center of sun = 2.4 x 1011 m
vf = final speed of comet = ?
rf = final distance from center of sun = 5.2x 1010 m
Using conservation of energy
initial kinetic energy + initial potential energy of comet = final kinetic energy + final potential energy of comet
(0.5) m vi2 - GMm/ri = (0.5) m vf2 - GMm/rf
(0.5) vi2 - GM/ri = (0.5) vf2 - GM/rf
(0.5) (20000)2 - (6.67 x 10-11)(1.989 x 1030)/(2.4 x 1011) = (0.5) vf2 - (6.67 x 10-11)(1.989 x 1030)/(5.2x 1010)
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what is the escape speed on a spherical asteroid whose radius is 823 km and whose gravitational acceleration at th surface is 1.38 m/s^2.
A spherical asteroid with a radius of 823 km has an escape speed of 4 103 m/s.
Explain about the gravitational acceleration?Gravitational acceleration is the acceleration that an object experiences as a result of the gravitational force acting on it. Its symbol is "g," and its unit is m/s2. Gravitational acceleration is a vector quantity, having a magnitude and a direction.
(a) The given values are
[tex]$$r=500 \mathrm{~km}$$[/tex]
[tex]$$\Rightarrow a=3.0 \mathrm{~ms}^{-2}$$[/tex]
[tex]$$\Rightarrow v=1000 \mathrm{~ms}^{-1}$$[/tex]
[tex]$$\Rightarrow h=1000 \mathrm{~km}$$[/tex]
We know that the formula for gravitational acceleration is given as
[tex]$$a_g=\frac{G M}{r^2}$$[/tex]
And the formula for the escape velocity is given by
[tex]$$v=\sqrt{\frac{2 G M}{r}}$$[/tex]
Substituting for gravitational acceleration in the above formula we get
[tex]& \Rightarrow v=\sqrt{\frac{2 a_g r^2}{r}} \\[/tex]
[tex]& \Rightarrow v=\sqrt{2 a_g r}[/tex]
Substituting the given values for the radius and gravitational acceleration.
[tex]$$\Rightarrow v=\sqrt{2(3.0)\left(500 \times 10^3\right)}$$[/tex]
[tex]& \therefore v=1.732 \times 10^3 \mathrm{~ms}^{-1}[/tex]
The complete question is,
(a) What is the escape speed on a spherical asteroid whose radius is 5 (lind whose gravitational acceleration at the surface is 3.0 [tex]\mathrm{~ms}^{-2}$[/tex]
(b) How far from the surface will a particle go if it leaves the asteroid's surface with a radial speed of[tex]$1000 \mathrm{~ms}^{-1}$[/tex]
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calculate the angle, in degrees, for the fourth-order maximum (counting the center bright region) of 580-nm wavelength yellow light falling on double slits separated by 0.100 mm.
Hence there exist no solution for such angular position, in other words there is no fourth order maximum fringe.
What does a wavelength mean in plain English?The distance between the two consecutive peaks or troughs of a wave is known as its wavelength. It is calculated in the wave's direction.
The angular position of the bright fringes in the double slit interference is given by the following relation
[tex]m\lambda=d\sin\funcapply\left(\theta_m\right)[/tex]
Where,
m: Is the dazzling fringe's order, m.
[tex]\lambda :[/tex]580-nm (Is the wavelength of the incident light on the double slit.)
d: 0.100mm (Is the distance between the centers of the two slits.)
[tex]\theta_m:[/tex] is the angle at which the mth fringe is located.
[tex]\begin{aligned}\theta_4 & =\sin ^{-1}\left(\frac{4 \lambda}{d}\right) \\& =\sin ^{-1}\left(\frac{4 \times 580 \times 10^{-9}}{1.00 \times 10^{-4}}\right)\end{aligned}[/tex]
[tex]=\sin ^{-1}(0.02)\\=1.14[/tex]
Where, the sine function can never have a value greater than 1 , hence there exist no solution for such angular position
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two 1-kg stationary cue balls are struck by cue sticks. the cues exert the forces shown. which ball has the greater final speed?
Both balls have the same final speed.
What is speed?The distance traveled by an object per unit time is defined as its speed. Speed is a scalar quantity because it has no direction and only magnitude. The SI unit is meter/second.Based on Newton's second law of motion,
Second Law of Motion of Newton (Force) The acceleration of an object is determined by its mass and the amount of force applied.force = momentum/time change
Momentum change = force time
(force time)/mass = change in speed
When two 1.0 kg stationary cue balls are struck by cue sticks with equal force and time.
Therefore both stationary cube balls will have the same final speed.
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a hammer taps on the end of a 5.0-m-long metal bar at room temperature. a microphone at the other end of the bar picks up two pulses of sound, one that travels through the metal and one that travels through the air. the pulses are separated in time by 9.00 ms .
The time it takes for it to travel through the air is 5m / 343 m/s = 14.57 msec.
We know that it travels faster through the metal, so if the difference is 11, then tm = 11–14.57 ms
which means the speed through the metal is 5/0.00066 = 7575 m/s
But this is not a good answer, as the speed of sound in the air can vary over a large range. And the difference between 11 and 11.66 ms is small.
For example, the 343 number is at 20ºC. At 25ºC it is 346 m/s, which has a travel time of 11.55 ms, and when you subtract, you get 0.55 ms, or a speed of 7330 m/s. So it depends on the exact temperature, which you did not define.
Temperature is a measure of hot or cold expressed on one of several scales including Fahrenheit and Celsius. Temperature indicates the direction in which heat energy spontaneously flows. Temperature is a measure of how hot or cold something is Specifically.
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a force of 20n is applied toa screwdriver to pry the lid off a paint can. the screwdriver applies 65n of force to the lids. what is the mechanical advantage of the screwdriver
The screwdriver being described above has a mechanical advantage of 65 N. Accordingly, this straightforward device would exert 65N of force on the can's lid for every 20N of force applied to the screwdriver.
How can you improve a screwdriver's mechanical advantage?A screwdriver's handle can have its torque increased by increasing the diameter of the handle. The force exerted by a person's hand on the handle must be farther away from the screwdriver's shaft in order to increase the torque that is applied to the screw by the tool.
The mechanical advantage and force that a screw can exert for a given applied force increase as the distance between its threads decreases. However, since most real screws have high levels of friction, the mechanical advantage they provide is less than that predicted by the previous equation.
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The amount of air drag on an 0. 8n flying squirrel dropping vertically at terminal velocity is.
The amount of air drag on an 0. 8n flying squirrel dropping vertically at terminal velocity is.terminal velocity is 0.8 N .
Simply put, what is terminal velocity?As a result, a object achieves terminal velocity when its acceleration (or deceleration) are zero and its speed is no longer increasing or decreasing.
What is the Earth's terminal velocity?around 53 m/s Unaffected by its mass, an item in free fall inside a vacuum would accelerate at a velocity of about 9.8 m/s2 close to the Earth's surface.When an object is dropped, air resistance causes it to finally achieve its terminal velocity, which for a human skydiver is about 53 m/s (190 km/h or 118 mph).
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a bucket full of sand has a mass of 30 kg (including the bucket and the sand). the bucket is to be lifted to the top of a building 15 meters tall by a rope of negligible weight. however, the bucket has a hole in it, and leaks 0.1 kgs of sand each meter it is lifted. find the work done lifting the bucket to the top of the building.
The Total work done lifting the bucket to the top of the building is 405 kg m
What is work?
Work in physics is the energy that is transmitted to or from a object when a force is applied along a displacement. In its simplest form, it equals the goods of the force's magnitude and the distance travelled for a constant force directed in the same direction as the motion. When a force is applied, it is said to have a component that points inside the direction of a displacement of the application point.
The work done lifting the bucket to the top of the building can be calculated by multiplying the force of the weight of the bucket by the distance it is moved. In this case, the force is equal to the mass of the bucket and sand, which is 30 kg, and the distance is 15 m. So, the work done is:
Work = Force x Distance
= 30 kg x 15 m
= 450 kg m
However, as the bucket is leaking sand, the mass of the bucket and sand is decreasing as it is being lifted. The mass of the bucket and sand at the top of the building will be less than 30 kg and the amount of work done will be less than 450 kg m.
To calculate the work done lifting the bucket to the top of the building, we need to calculate the mass of the bucket and sand at the top of the building. We can do this by subtracting the amount of sand lost from the initial mass of the bucket and sand. As the bucket leaks 0.1 kg of sand each meter it is lifted, the mass of the bucket and sand at the top of the building can be calculated as:
Mass at top of building = 30 kg - 0.1 kg x 15 m
= 27 kg
Now, we can calculate the work done lifting the bucket to the top of the building by multiplying the force of the weight of the bucket and sand at the top of the building by the distance it is moved. In this case, the force is equal to the mass of the bucket and sand at the top of the building, which is 27 kg, and the distance is 15 m. So, the work done is:
Work = Force x Distance
= 27 kg x 15 m
= 405 kg m
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