Answer:
39.8°
Step-by-step explanation:
We know slope is rise over run. That would mean our right triangle would have a horizontal leg of 6 and a vertical leg of 5. From there we use tan∅ to help solve ∅:
tan∅ = 5/6
∅ = tan⁻¹(5/6)
∅ = 39.8056
Simple and easy question
please help
Answer:
Volume of a sphere = 4/3πr³
π = 3.14
r = radius which is 3in
Volume = 4/3 × 3.14 × 3²
= 37.68
= 38 cubic inches to the nearest hundredth
Hope this helps
Answer:
38 cubic inches
Step-by-step explanation:
y=(x+9)÷(x-3)
Find the value of y when x=5
solution,
X=5
[tex]y = \frac{x + 9}{x - 3} \\ = \frac{5 + 9}{5 - 3} \\ = \frac{14}{2} \\ = 7[/tex]
hope this helps...
Good luck on your assignment..
Answer:
When x=5
Y=(5+9)÷(5-3)
= 14 ÷2
= 7
Avery wants to buy a car and has a choice between two different banks. One bank is offering a simple interest rate of 3.2% and the other bank is offering a rate of 3% compounded annually. If Avery decides to deposit $7,000 for 5 years, which bank would be the better deal? 1. a simple interest rate of 3.2% 2. a compound interest rate of 3%
Answer: a simple interest rate of 3.2% will be the better deal.
Step-by-step explanation:
Hi, to answer this question we have to apply the compounded interest formula:
A = P (1 + r/n) nt
Where:
A = Future value of investment (principal + interest)
P = Principal Amount
r = Nominal Interest Rate (decimal form, 3/100= 0.03)
n= number of compounding periods in each year (1)
Replacing with the values given
A = 7000 (1+0.03/1)^(1x5)
A = 7000( 1.03)^5 = $8,114.92
For simple interest:
I = p x r x t
Where:
I = interest
Replacing with the values given:
I = 7000 x (3.2/100) x 5 = $1,120
Adding the principal amount: 7000+1120 = $8,120
Since 8,120 (simple) >8,114.92(compound)
a simple interest rate of 3.2% will be the better deal.
A company rounds its losses to the nearest dollar. The error on each loss is independently and uniformly distributed on [–0.5, 0.5]. If the company rounds 2000 such claims, find the 95th percentile for the sum of the rounding errors.
Answer:
the 95th percentile for the sum of the rounding errors is 21.236
Step-by-step explanation:
Let consider X to be the rounding errors
Then; [tex]X \sim U (a,b)[/tex]
where;
a = -0.5 and b = 0.5
Also;
Since The error on each loss is independently and uniformly distributed
Then;
[tex]\sum X _1 \sim N ( n \mu , n \sigma^2)[/tex]
where;
n = 2000
Mean [tex]\mu = \dfrac{a+b}{2}[/tex]
[tex]\mu = \dfrac{-0.5+0.5}{2}[/tex]
[tex]\mu =0[/tex]
[tex]\sigma^2 = \dfrac{(b-a)^2}{12}[/tex]
[tex]\sigma^2 = \dfrac{(0.5-(-0.5))^2}{12}[/tex]
[tex]\sigma^2 = \dfrac{(0.5+0.5)^2}{12}[/tex]
[tex]\sigma^2 = \dfrac{(1.0)^2}{12}[/tex]
[tex]\sigma^2 = \dfrac{1}{12}[/tex]
Recall:
[tex]\sum X _1 \sim N ( n \mu , n \sigma^2)[/tex]
[tex]n\mu = 2000 \times 0 = 0[/tex]
[tex]n \sigma^2 = 2000 \times \dfrac{1}{12} = \dfrac{2000}{12}[/tex]
For 95th percentile or below
[tex]P(\overline X < 95}) = P(\dfrac{\overline X - \mu }{\sqrt{{n \sigma^2}}}< \dfrac{P_{95}- 0 } {\sqrt{\dfrac{2000}{12}}}) =0.95[/tex]
[tex]P(Z< \dfrac{P_{95} } {\sqrt{\dfrac{2000}{12}}}) = 0.95[/tex]
[tex]P(Z< \dfrac{P_{95}\sqrt{12} } {\sqrt{{2000}}}) = 0.95[/tex]
[tex]\dfrac{P_{95}\sqrt{12} } {\sqrt{{2000}}} =1- 0.95[/tex]
[tex]\dfrac{P_{95}\sqrt{12} } {\sqrt{{2000}}} = 0.05[/tex]
From Normal table; Z > 1.645 = 0.05
[tex]\dfrac{P_{95}\sqrt{12} } {\sqrt{{2000}}} =1.645[/tex]
[tex]{P_{95}\sqrt{12} } = 1.645 \times {\sqrt{{2000}}}[/tex]
[tex]{P_{95} = \dfrac{1.645 \times {\sqrt{{2000}}} }{\sqrt{12} } }[/tex]
[tex]\mathbf{P_{95} = 21.236}[/tex]
the 95th percentile for the sum of the rounding errors is 21.236
The play director spent 190190190190 hours preparing for a play. That time included attending 35353535 rehearsals that took varying amounts of time and spending 933493 \dfrac{3}{4}934393, start fraction, 3, divided by, 4, end fraction hours on other responsibilities related to the play. What question does the equation 35x+9334=19035x+93\dfrac{3}{4}=19035x+9343=19035, x, plus, 93, start fraction, 3, divided by, 4, end fraction, equals, 190 help answer?
Answer:
The equation above represents the total time the play director spent preparing for a play.
Step-by-step explanation:
The time spent by the play director for preparing for a play is, 190 hours.
Of these 190 hours, the director spent varying amounts of time attending 35 rehearsals for the play.
Let the varying amounts of time be denoted by, x.
The director also spent 3/4th of an hour, i.e. 45 minutes, on other responsibilities related to the play.
The equation provided is:
[tex]35x+\frac{3}{4}=190[/tex]
The equation above represents the total time the play director spent preparing for a play.
If you are given the graph of h(x) = log6x, how could you graph M(x) = log6(x+3)?
Answer:
Translate 3 units to the left
Step-by-step explanation:
Together, Dante and Mia have a total of 350 pennies in their piggy banks. After Dante lost ½ of his pennies and Mia lost ⅓ of her pennies, they both had an equal number of pennies. Altogether, how many pennies did they lose?
Answer:
Altogether they lost 150 pennies.
Step-by-step explanation:
X = Dante's pennies
Y = Mia's pennies
X + Y = 350 1/2 X = 2/3 Y
X = 4/3 Y
4/3 Y + Y = 350
7/3 Y = 350
Y = 350 * 3/7
Y = 50 * 3
Y = 150
X + 150 = 350
X = 200
1/2 * 200 = 2/3 * 150
100 . = 100
1/2 * 200 = 100 -> Dante lost 100 pennies
1/3 * 150 = 50 -> Mia lost 50 pennies
Altogether they lost 150 pennies.
CD=17 AM=5 CD=? I've tried everything but I can't figure it out.
Answer:
We can prove that ΔTMB ≅ ΔTMD and ΔTMA ≅ ΔTMC by ASA. This means that BM = MD = BD / 2 = 8.5 and that AM = CM = 5 which means that CD = MD - CM = 8.5 - 5 = 3.5.
Solve I=PRT for P if I=312.50, r=25%, and T=0.25
Answer: I = $ 19.53
Step-by-step explanation:
First, converting R percent to r a decimal
r = R/100 = 25%/100 = 0.25 per year,
then, solving our equation
I = 312.5 × 0.25 × 0.25 = 19.53125
I = $ 19.53
The simple interest accumulated
on a principal of $ 312.50
at a rate of 25% per year
for 0.25 years is $ 19.53.
Answer:
P = 5000
You need to multiply r and T together, then divide 312.50 by that.
ASAP! A boat travelling at top speed upstream moves at 15km/hr. When it travels downstream, again at top speed< it moves at 25km/hr. What is the boat's top speed in still water?
Answer: 20km/h
Step-by-step explanation:
20km/h. Simply average 15 and 25 by doing (15+25)/2
Hope it helps <3
Please answer this question in two minutes
Answer:
work is shown and pictured
SNOG HELP OR SOMEONE THANK YOUUUU
Which unit rate is equivalent to 14 miles per gallon?
two gallons over thirty two miles
thirty two miles over two gallons
three gallons over forty two miles
forty two miles over three gallons
Answer:
forty two miles over three gallons
Step-by-step explanation:
2 gallons over 32 miles simplifies to 1 gallon over 16 miles, or 1 gallon per 16 miles. This is not the desired result, so we know the first choice is incorrect.
32 miles over 2 gallons simplifies to 16 miles over 1 gallon, or 16 miles per gallon. Again, this is not the desired result, so we know the second choice is also incorrect.
3 gallons over 42 miles simplifies to 1 gallon over 14 miles, or 1 gallon per 14 miles. While this may look correct, note that 1 gallon per 14 miles and 14 miles per gallon are not the same thing, so we know that the third answer is also incorrect.
By process of elimination, we know that the correct answer must be the last option, but let's still simplify it. 42 miles over 3 gallons simplifies to 14 miles over 1 gallon, or 14 gallons per mile. This is in fact the desired result, so we know that the correct answer is the last option. Hope this helps!
What are the solutions to the quadratic equation below? x^2+34x-72=0
Answer:
( x + 36 ) ( x - 2 ) = 0
Step-by-step explanation:
x^2 + 36x - 2x -72 = 0
x ( x + 36 ) - 2 ( x + 36 ) = 0
( x + 36 ) ( x - 2 ) = 0
How is it that it is (-11/4,-1/2) ?
Answer:
Choice 3
Step-by-step explanation:
A(-5,-1) and B(4, 1)
Distance AB is calculated as x²+y², where x= 4-(-5)=9 and y= 1-(-1)=2
Point P is at 1/4 of distance from point A, so its coordinates will be at 1/4 of full distance from A to B in term of both coordinates:
-5 + 9/4= (-20+9)/4= -11/4-1 +2/4= (-4+2)/4= -2/4= -1/2So P= (-11/4, -1/2) and choice 3
The tape diagram represents an equation. Write an equation to represent the image.
Answer:
5n = 1.75
Step-by-step explanation:
The 2 bars are equal thus lower equals upper, that is
5n = 1.75
What are the solutions to the equation x minus StartFraction 7 Over x EndFraction = 6
The solutions to the equation x minus StartFraction 7 Over x EndFraction is equal to 6 is -1 and 7
What is a quadratic equation ?Any equation of the form [tex]\rm ax^2+bx+c=0[/tex] Where x is variable and a, b, and c are any real numbers where a ≠ 0 is called a quadratic equation.
We have equation:
[tex]\rm x-\dfrac{7}{x}=6[/tex]
After simplifying:
[tex]\rm x^2 -7 = 6x\\\\x^2-6x-7=0[/tex]
[tex]\rm x^2 +x-7x-7=0[/tex]
(x + 1)(x - 7) = 0
x = -1 or x = 7
Thus, the solutions to the equation x minus StartFraction 7 Over x EndFraction is equal to 6 is -1 and 7
Learn more about quadratic equations here:
brainly.com/question/2263981
#SPJ2
Answer:
C) x= -1 and x=7
Step-by-step explanation:
I do not understand this/ help me answer these
Answer:
-6b -6c3w -122x -246 + 3r8y - 16xStep-by-step explanation:
Find the product of 2x and 3.
Answer:
6x
Step-by-step explanation:
Product is multiplication.
2x × 3
Multiply.
2 × x × 3
= 6x
What is the range? Explain
Answer:
Range = [5, ∞)
Step-by-step explanation:
The initial number of snakes is 5 and it is increasing at a high rate so the maximum number is infinite. The population is increasing exponentially according to the equation P = 5(2)^t where t = the number of years.
17. The length of a swing is 2.1 m. If the length
of the arc that is made by the swing
4.4 m, calculate the angle swept by the
swing
Answer:
dose it tell you want angle the arc is at?
Step-by-step explanation:
Which of the following can be represented by the inequality below? 69h + 126 > 540 A. Yvonne is driving more than 540 miles on a trip. She has already driven 126 miles and drives 69 miles each hour. B. Yvonne is driving less than 540 miles on a trip. She has already driven 126 miles and drives 69 miles each hour. C. Yvonne is driving less than 126 miles on a trip. She has already driven 69 miles and drives 540 miles each hour. D. Yvonne is driving more than 540 miles on a trip. She has already driven 69 miles and drives 126 miles each hour.
Answer:
The answer is A.
Step-by-step explanation:
The inequality states that the amount that Yvonne drives is more than 540 miles. Since h represents the number of hours, we know that 69 probably means the number of miles Yvonne can drive per hour. Finally, 126 shows the amount of miles that Yvonne has already driven.
The measure of major arc ACB is _____ degrees. (Enter only a number as your answer)
Answer:
Step-by-step explanation:
measure of angles of a circle=360
angle ACB=360-82=278 degrees
Help me please thanks must be accurate
Answer:
Answer B (The cost of fabric compared to its length)
Step-by-step explanation:
The cost of fabric is directly proportional to the length of fabric one is buying. That constant of proportionality is telling you that there is a constant rate of change in units of cost per length.
The other options are much more randomly varying.
factorise this expression as fully as possible 2x^2+6x
Answer:
(Factor out 2x from the expression)
2x (x +3)
WILL GIVE BRAINLEIST!!!
Answer:
40
Step-by-step explanation:
Once you plot the data, the middle values will be 39 and 41. To calculate the median, you add them up and divide by two, which will result in 40!
Median is the middle value.
Write the numbers out from smallest to largest:
35, 38, 38, 39, 39, 41, 42, 43, 43, 44
There are 10 total numbers, find the middle two:
39 and 41
Add them Together and divide by 2:
39 + 41 = 80
80/2 = 40
Median = 40
write the monomial in standard form. name it's coefficient and identify its degree.
2/3m^2 n *4.5n^3
Answer:
[tex]Standard\ Form = {3n^2} m^{-2}[/tex]
Step-by-step explanation:
Given
[tex]\frac{2}{3m^2n} * 4.5n^3[/tex]
Required
Write in Standard Form
To start with; the two monomials have to be multiplied together;
[tex]\frac{2}{3m^2n} * 4.5n^3[/tex]
[tex]Standard\ Form = \frac{2 * 4.5n^3}{3m^2n}[/tex]
Split the numerator and the denominator
[tex]Standard\ Form = \frac{2 * 4.5 * n^3}{3 * m^2 * n}[/tex]
Multiply Like terms
[tex]Standard\ Form = \frac{9 * n^3}{3 * m^2 * n}[/tex]
Divide 9 by 3 to give 3
[tex]Standard\ Form = \frac{3 * n^3}{m^2 * n}[/tex]
Divide n³ by n to n²
[tex]Standard\ Form = \frac{3 * n^2}{m^2 }[/tex]
Split fraction
[tex]Standard\ Form = {3 * n^2} * \frac{1}{m^2 }[/tex]
From laws of indices;
[tex]\frac{1}{a^n} = a^{-n}[/tex]
[tex]Standard\ Form = {3 * n^2} * \frac{1}{m^2 }[/tex] becomes
[tex]Standard\ Form = {3 * n^2} * m^{-2}[/tex]
Multiply all together
[tex]Standard\ Form = {3n^2} m^{-2}[/tex]
Suppose the lengths of the pregnancies of a certain animal are approximately normally distributed with mean mu equals 247 days and standard deviation sigma equals 16 days. Complete parts (a) through (f) below.
Answer:
The answer is given below
Step-by-step explanation:
a) What is the probability that a randomly selected pregnancy lasts less than 242 days
First we have to calculate the z score. The z score is used to determine the measure of standard deviation by which the raw score is above or below the mean. It is given by:
[tex]z=\frac{x-\mu}{\sigma}[/tex]
Given that Mean (μ) = 247 and standard deviation (σ) = 16 days. For x < 242 days,
[tex]z=\frac{x-\mu}{\sigma}=\frac{242-247}{16}=-0.31[/tex]
From the normal distribution table, P(x < 242) = P(z < -0.3125) = 0.3783
(b) Suppose a random sample of 17 pregnancies is obtained. Describe the sampling distribution of the sample mean length of pregnancies.
If a sample of 17 pregnancies is obtained, the new mean [tex]\mu_x=\mu=247,[/tex] the new standard deviation: [tex]\sigma_x=\sigma/\sqrt{n} =16/\sqrt{17} =3.88[/tex]
c) What is the probability that a random sample of 17 pregnancies has a mean gestation period of 242 days or less
[tex]z=\frac{x-\mu}{\sigma/\sqrt{n} }=\frac{242-247}{16/\sqrt{17} }=-1.29[/tex]
From the normal distribution table, P(x < 242) = P(z < -1.29) = 0.0985
d) What is the probability that a random sample of 49 pregnancies has a mean gestation period of 242 days or less?
[tex]z=\frac{x-\mu}{\sigma/\sqrt{n} }=\frac{242-247}{16/\sqrt{49} }=-2.19[/tex]
From the normal distribution table, P(x < 242) = P(z < -2.19) = 0.0143
(e) What might you conclude if a random sample of 49 pregnancies resulted in a mean gestation period of 242 days or less?
It would be unusual if it came from mean of 247 days
f) What is the probability a random sample of size 2020 will have a mean gestation period within 11 days of the mean
For x = 236 days
[tex]z=\frac{x-\mu}{\sigma/\sqrt{n} }=\frac{236-247}{16/\sqrt{20} }=-3.07[/tex]
For x = 258 days
[tex]z=\frac{x-\mu}{\sigma/\sqrt{n} }=\frac{258-247}{16/\sqrt{20} }=3.07[/tex]
From the normal distribution table, P(236 < x < 258) = P(-3.07 < z < 3.07) = P(z < 3.07) - P(z < -3.07) =0.9985 - 0.0011 = 0.9939
The two lines graphed below are not parallel.How many solutions are there to system of equations
we need the graph/ lines,
but just remember
wherever 2 lines intersect, that is a solution
if they are paralell, no solutions
if they cross, 1 solution
if they are the same line/ the lines are on top of each other exactly, infinite solutions
PLEASE HELP ASAP SHOE YOUR WORK!!!! Best answer gets brainliest :)
Answer:
Height = 3cm
Volume = 50.27cm^3
Step-by-step explanation:
Well to solve for the height with slant height and radius we can use the Pythagorean Theorem,
Which is [tex]a^2 + b^2 = c^2[/tex].
So we have c and a, so we have to fill those in.
(4)^2 + b^2 = (5)^2
16 + b^2 = 25
-16
b^2 = 9
[tex]\sqrt{b} \sqrt{9}[/tex]
b = 3cm
So to find the volume of a cone we use the following formula [tex]\pi r^2 \frac{h}{3}[/tex].
So we have the radius and height so we just fill those in.
(pi)(4)^2(3)/3
(pi)16(1)
pi*16
About 50.27cm^3
Find the missing side length