Answer:
c I do believe good luck with the answer
1) For the following molecules: - Draw the Lewis structures/dots - Determine the polarity (polar or non-polar). - List all intermolecular forces. a) CF4 b) CH2Br2 c) H2CO3 d) N2 e) PCl3 f) XeF2 g) NH4
Answer:
ed
Explanation:
ed
If the fan and power source are not connected to anything else, the amount of electrical energy is the same as the amount of mechanical energy. What is this rule known as?
1. transference of energy
2. conversion of energy
3. adaptation of energy
4. conservation of energy
Answer:
not B
Explanation:
my friend got it wrong
What is the oxidation state of nitrogen in Nz?
Answer:
the oxidation state of nitrogen is +5
What are the missing coefficients for H3PO4 + HCl = PCl5 + H2o
Answer:
H3PO4 + 5 HCl → PCl5 + 4 H2O
Explanation:
The given equation is
H3PO4 + HCl = PCl5 + H2O
The above chemical equation has one P atom on both the sides, hence phosphorus is balanced
There are 5 Cl on the RHS but only one Cl on the LHS. On balancing the chlorine, we get -
H3PO4 + 5HCl = PCl5 + H2O
Now, there are 8 hydrogen atom on the LHS but only two on the RHS. On balancing the hydrogen on both the sides, the new equation become
H3PO4 + 5HCl = PCl5 + 4H2O
Let us check for oxygen
Oxygen on LHS = 4 and oxygen on RHS = 4
Thus, the balanced equation is H3PO4 + 5HCl = PCl5 + 4H2O
A 0.125 g sample of unknown hydrocarbon is prepared for combustion analysis. After the hydrocarbon undergoes complete combustion, 0.4225 g of CO2 and 0.0865 g of H2O are produced. What is the empirical formula of the unknown
Answer:
Empirical formula is CH
Explanation:
A hydrocarbon, CₐHₓ reacts with oxygen in the combustion reaction as follows:
CₐHₓ + O₂ → a CO₂ + x/2 H₂O
That means we can find the moles of C and H from the moles of CO2 and H2O. As empirical formula is defined as the simplest whole-number ratio of atoms in a molecule, we can determine it as follows:
Moles CO2 = Moles C -Molar mass: 44.01g/mol:
0.4225g * (1mol / 44.01g) = 0.0096 moles C
Moles H2O -Molar mass: 18.01g/mol:
0.0865g H2O * (1mol / 18.01g) = 0.0048moles H2O * (2mol H / 1mol H2O) =
0.0096 moles H
The ratio of atoms of C:H is:
0.0096moles C / 0.0096moles H = 1
That means empirical formula is CH
What frequency corresponds to an absorption line at 460 nm?
A. 1.53 x 1014 Hz
B. 6.88 x 1014 Hz
C. 6.52 x 1014 Hz
D. 4.32 x 1014 Hz
Answer:
C. 6.52 x 10^14 Hz
Explanation:
hope this helps
200.0g of a 3.0% NaF solution, how much distilled water do we weigh out?
197g of distilled water
194g of distilled water
140g of distilled water
170g of distilled water
Answer:
194g of distilled water.
Explanation:
Hello there!
In this case, according to the given information for this problem, it turns out possible for us to use the given mass of the solution and the percent by mass of NaF to firstly calculate the grams of this solute as shown below:
[tex]\%m=\frac{m_{solute}}{m_{solution}} *100\%\\\\m_{solute}=\frac{\%m*m_{solution}}{100\%} \\\\m_{solute}=\frac{3.0\%*200.0g}{100\%} \\\\m_{solute}=6g[/tex]
And finally, since the mass of solution is calculated by adding mass of solute and mass of solvent we obtain the mass of water (solvent) as follows:
[tex]m_w=200g-6g=194g[/tex]
Therefore, the answer is 194g of distilled water
Regards!
What is the molar mass of Ca(NO3)2?
Answer:
The molar mass is 40.1+2×(14+3(16))=40.1+2×(62)=164.1g/mol.
How does the water cycle show precision in God's creation?
HELP ME!!
Explanation:
He used just the right amount of matter in water to get it to evaporate at a normal temperature and to condense into clouds for rain.
To cause water evaporate at a regular temperature and condense in clouds for rain, God has employed precisely the proper amount of substance in the water.
What is water cycle?Water is constantly circulated throughout the Earth-atmosphere system throughout the water cycle, also known as the hydrologic cycle. The five key stages of the water cycle—evaporation, transpiration, condensate, precipitation, and runoff—are the most crucial. Water is used by all of the processes in the cycle, but its distribution changes over time even while the overall amount of water is largely constant.
Water is converted from its liquid state to its gaseous, or smoke, state through evaporation. This transfer happens when some water molecules have accumulated enough kinetic energy to launch themselves off the water's surface. To cause water evaporate at a regular temperature and condense in clouds for rain, God has employed precisely the proper amount of substance in the water.
Therefore, to cause water evaporate at a regular temperature and condense in clouds for rain, God has employed precisely the proper amount of substance in the water.
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1. Which individuals are most likely to die before reproducing, those with adaptive traits or
nonadaptive traits? Why? (Hint: You may use the newt population as an example in your
explanation.)
Which of the following would result in being able to dissolve a greater amount of gas in a solution?
Answer:
Lower the temperature of the solution
What is the hypothetical van't Hoff factor of magnesium nitrate, Mg(NO3)2?
Answer:
The hypothetical van't Hoff factor of magnesium nitrate,[tex]Mg(NO_3)_2[/tex] is 3 .
Explanation:
Lets calculate -
[tex]Mg(NO_3)_2\rightarrow Mg^2^+ +2NO_3^-[/tex]
We know that ,
[tex]i=\alpha n+(1-\alpha )[/tex]
Dissociation should be 100% for the hypothetical vant hoff factor , that is
[tex]\alpha =1[/tex] and [tex]n=3[/tex] for [tex]Mg(NO_3)_2[/tex]
Therefore , putting the given values ,
[tex]i=1\times3+(1-1 )[/tex]
[tex]i=3+0[/tex]
[tex]i=3[/tex]
Hence , the answer is 3.
The hypothetical van't Hoff factor of magnesium nitrate is 3.
Van't Hoff factor is a measure of the deviation of a solution from ideal behavior. It depends on the number of particles in the solution. The more the particles in solution, the greater the Van't Hoff factor and the greater the deviation from ideal behavior.
For Mg(NO3)2, the hypothetical van't Hoff factor is 3 since there are three particles in solution when magnesium nitrate is dissolved in water.
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For a reaction that has reactant A in its rate law, select which factor(s) affect the reaction rate of reactant A. Choose one or more: A. temperature B. change in concentration of a reactant C. catalyst D. change in concentration of a product E. physical state of the reactants
Answer:
Option B
Explanation:
The rate law is represented as
Rate of the reaction = [tex]k [A^x][B^y][/tex]
Here K is the rate constant
A is the concentration of substance A
B is the concentration of substance B
Hence, If reactant A is in the rate law equation, then if its concentration varies then it will impact the rate of the reaction
Hence, option B is correct
How many molecules are present in 4.5
moles of H2O?
Answer:
Mole of the H2O = 4.5
Number of molecules =4.5 multipled by avogadro's number.
A __ is a solid that forms in a liquid when a chemical reaction takes place.
Answer:
A precipitate is a solid that forms in a liquid when a chemical reaction takes place.
What is one movement that liquid water CANNOT do while on or at the Earth's surface? (GIVE RIGHT ANSWER OR I DELETE 100 POINTS)
Answer:
One movement that i can't do is float in mid air
Explanation:
10 ml of a 0.25M solution is diluted to make exactly 250 ml of solution. What's the concentration of the diluted solution?
Answer:
0.01 M
Explanation:
As this problem deals with a dilution process, we can solve it by using the following formula:
C₁V₁=C₂V₂Where subscript 1 stands for the initial concentration and volume, while 2 stands for the final conditions.
That means that in this case:
C₁ = 0.25 MV₁ = 10 mLC₂ = ?V₂ = 250 mLWe input the given data:
0.25 M * 10 mL = C₂ * 250 mLC₂ = 0.01 MHl Weakly dissociates in water according to the chemical equation below. H20+ Hl <-> H3O^+ + l- What is a conjugate acid-base pair in this reaction?
Answer:
https://www.clutchprep.com/chemistry/practice-problems/70217/hi-aq-h2o-l-h3o-aq-i-aq-identify-each-as-either-a-bronsted-lowry-acid-bronsted-l
Explanation:
https://www.clutchprep.com/chemistry/practice-problems/70217/hi-aq-h2o-l-h3o-aq-i-aq-identify-each-as-either-a-bronsted-lowry-acid-bronsted-l
The enthalpy of formation of water is -285.8 kJ/mol. What can be inferred from this statement? O The enthalpy of the products is equal to the enthalpy of the reactants. O Heat is absorbed during the process. O Heat is released during the process. The enthalpy of the products is more than the enthalpy of the reactants.
Answer:
the answer is c
Explanation:
i did the test
The enthalpy of the formation of water is -285.8 kJ/mol. The information that can be made by the statement is heat is released during the process. The correct option is C.
What is enthalpy?Enthalpy is the volume times the pressure times the internal energy of the system. It is an entity of thermodynamics. It is the measurement of the energy in a thermodynamic system. The enthalpy totals the internal energy plus pressure and volume.
The statement that is given here is given that enthalpy is -285.8 kJ/mol. The value is negative, so the energy is released here. When energy is gained the energy will be positive and when the energy is released it is negative.
Thus, the correct option is C, heat is released during the process regarding the given statement of enthalpy.
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omg posting takes away point WHAT.
Answer:
yep
Explanation:
that why I have someone else post questions for me. But its a good incentive to help others to help you to help me to you to help others.
What would the products be for the reaction between Na3PO4 + MgSO4?
MgSO4 + Na3PO4 = Na2SO4 + Mg3(PO4)2
Answer: The products of Na3PO4 + MgSO4 are Na2SO4 + Mg3(PO4)2
Explanation:
in an expirement a scientist should
Is it dangerous to remove gunpowder from firecracker
Spread your smarts while you wait.
Answer:
lol ok 1+1=2 2 x 2=4
have a good day :)
Explanation:
Answer: oke
Explanation: have a goood day!
A car traveling at 30 m/s comes to a stop in 5 seconds. What is the acceleration of this car?
Answer:
6m/s brainliest?
Explanation:
Answer:
6 m/s
Explanation:
Will give brainliest
In the following acid-base reaction
H2O is the
HCl(g) + H2O(l) →H30+(aq) + Cl-(aq)
В
acid
base
conjugate
acid
CONJUGATE ACID
the acid's conjugate base because it can theoretically reform the acid by aaccepting a proton.
I hope this is correct >.<
Solve (2 x 10^3) + (7 x 10^5) *
Answer:
702000
Explanation:
(2 x 10^3) + (7 x 10^5)
=> 2 x 1000 + 7 x 100000
=> 2000 + 700000
=> 702000
A 0.150-kg sample of a metal alloy is heated at 540 Celsius an then plunged into a 0.400-kg of water at 10.0 Celsius, which is contained in a 0.200-kg aluminum calorimeter cup. The final temperature of the system is 30.5 Celsius. What is the specific heat of the metal alloy in J/Kg.Celsius
Answer:
[tex]C_{alloy}=0.497\frac{J}{g\°C}[/tex]
Explanation:
Hello there!
In this case, according to this calorimetry problem on equilibrium temperature, it is possible for us to infer that the heat released by the metal allow is absorbed by the water for us to write:
[tex]Q_{allow}=-(Q_{water}+Q_{Al})[/tex]
Thus, by writing the aforementioned in terms of mass, specific heat and temperature, we have:
[tex]m_{alloy}C_{alloy}(T_{eq}-T_{alloy})=-(m_{water}C_{water}(T_{eq}-T_{water})+m_{Al}C_{Al}(T_{eq}-T_{Al})[/tex]
Then, we solve for specific heat of the metallic alloy to obtain:
[tex]C_{alloy}=\frac{-(m_{water}C_{water}(T_{eq}-T_{water})+m_{Al}C_{Al}(T_{eq}-T_{Al})}{m_{alloy}(T_{eq}-T_{alloy})}[/tex]
Thereby, we plug in the given data to obtain:
[tex]C_{alloy}=\frac{-(400g*4.184\frac{J}{g\°C} (30.5\°C-10.0\°C)+200g*0.900\frac{J}{g\°C}(30.5\°C-10.0\°C)}{150g(30.5\°C-540\°C)} \\\\C_{alloy}=0.497\frac{J}{g\°C}[/tex]
Regards!
Use the equations below to calculate the enthalpy of formation for propane gas, C3H8, from its elements, hydrogen gas and solid carbon. Please hurry!!
Answer: I got -4542.9kg/mol
Explanation:
Using the enthalpy relation, the enthalpy of formation of propane gas in the given equation is 4542.9 kJ/mol
[tex] △H_{f} = Product [/tex]Using the enthalpy value of [tex] CO_{2} [/tex] and[tex] H_{2}0[/tex] given :
Product = [tex] 3CO_{2} + 4H_{2}0[/tex] Product = 3(-393.5) + 4(-285.8) = - 2323.70Reactant = [tex] C_{3}H_{8} + 5H_{2}0[/tex] Water, H20 has △H = 0Reactant = [tex] C_{3}H_{8} + 0[/tex]
Enthalpy of formation = product - Reactant
2219.2 = -2323.70 - (propane + 0)
2219.2 = - 2323.70 - propane
Propane = - 2323.70 - 2219.2
[tex] C_{3}H_{8} = - 4542.9 [/tex]
Therefore, the entalphy of formation of propane gas is - 4542.9 kJ/mol.
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The heat of combustion per mole for acetylene, C2H2(g), is -1299.5 kJ/mol. Assuming that the combustion products are CO2(g) and H2O(l), and given that the enthalpy of formation is -393.5 kJ/mol for CO2(g) and -285.8 kJ/mol for H2O(l), find the enthalpy of formation of C2H2(g).
Answer: The heat of combustion per mole for acetylene is 227.7 kJ/mol.
Explanation:
The combustion equation of acetylene is as follows.
[tex]C_{2}H_{2} + \frac{5}{2}O_{2} \rightarrow 2CO_{2} + H_{2}O[/tex]
Formula to calculate enthalpy of formation for a reaction is as follows.
[tex]\Delta H^{o}_{rxn} = \sum \Delta H_{products} - \sum \Delta H_{reactants}\\\Delta H^{o}_{rxn} = [2\Delta H^{o}_{f}(CO_{2}) + \Delta H^{o}_{f} (H_{2}O)] - [\Delta H^{o}_{f}(C_{2}H_{2}) + \frac{5}{2} \Delta H^{o}_{f} O_{2}]\\-1299.5 = 2(-393.5) + (-285.8) - \Delta H^{o}_{f} (C_{2}H_{2})\\\Delta H^{o}_{f} (C_{2}H_{2}) = 227.7 kJ/mol[/tex]
Thus, we can conclude that heat of combustion per mole for acetylene is 227.7 kJ/mol.