A silver cube with an edge length of 2.28 cm and a gold cube with an edge length of 2.75 cm are both heated to 82.8 ∘C and placed in 111.5 mL of water at 20.2 ∘C . What is the final temperature of the water when thermal equilibrium is reached?

Answers

Answer 1

Solution :

Given :

length of silver cube = 2.28 cm

length of gold cube = 2.75 cm

Initial temperature = 82.8°C

Volume of silver cube is

Volume [tex]$=(\text{edge length})^3$[/tex]

               =    [tex]$(2.28)^3$[/tex]

                [tex]$= 11.8 \ cm^3$[/tex]

mass of silver cube

Mass, [tex]$m_s = \text{density} \times \text{volume} $[/tex]

                = 10.5 x 11.8

                = 123.9 g

Similarly, the volume of gold cube is

Volume [tex]$=(\text{edge length})^3$[/tex]

               =    [tex]$(2.75)^3$[/tex]

                [tex]$= 20.79 \ cm^3$[/tex]

mass of gold cube

Mass, [tex]$m_g = \text{density} \times \text{volume}$[/tex]

                = 19.3 x 20.79

                = 401.247 g

Now

heat lost by silver and gold cube = heat gained by water

∴[tex]$m_g .c_g \Delta T + m_s .c_s \Delta T = m_w.c_w \Delta T$[/tex]

[tex]$m_g .c_g (82.8- T) + m_s .c_s (82.8- T) = m_w.c_w (T - 20.2)$[/tex]

[tex]$401.247 \times 0.1264 (82.8- T) + 123.9 \times 0.2386 (82.8- T) = 111.5 \times 4.184 (T - 20.2)$[/tex]

Now solving the equation

[tex]$50.71 (82.8- T) + 29.56 (82.8- T) = 466.51 (T - 20.2)$[/tex]

Final temperature, T = 31.27°C


Related Questions

what type of reaction is Au2S+H2---> 2Au+H2S

Answers

Answer:

single replacement reaction is type of reaction is Au2S+H2---> 2Au+H2S.

why is polarity an important factor when determining how molecules interact?​

Answers

Answer:

Water's polarity allows it to dissolve other polar substances very easily. When a polar substance is put in water, the positive ends of its molecules are attracted to the negative ends of the water molecules, and vice versa.

Explanation:

Answer/Explanation:

When a polar substance is put in water, the positive ends of its molecules are attracted to the negative ends of the water molecules, and vice versa.  Because molecular polarity results from the VECTOR sum of the individual bond dipoles. Water's polarity allows it to dissolve other polar substances very easily.

The specific branch of chemistry that focuses on molecules such as salts and water that constitute non-living matter, but are still important to living things, is termed

Answers

Answer: Inorganic chemistry

Explanation:

Inorganic chemistry can be defined as the branch of chemistry which studies the behavior of the inorganic compounds. Inorganic compounds are those compounds which lack carbon hydrogen bonding. The carbon monoxide, carbon dioxide, sodium chloride and water are the examples of inorganic compounds. This branch also studies the effect of these chemical compounds on the living things. The water and salts are chemicals which regulate the chemical and physiological reactions in the body.

What is the product of the unbalanced combustion reaction below?

Answers

Answer: A

Explanation:

Answer:

C

Explanation:

because the combustion reaction produce vapor water and CO2

Which activity is an example of a scientist using creativity?
a scientist exploring evidence from other fields of science to support findings
a scientist transferring data from one experiment into the data analysis from a second experiment
a scientist repeating an older experiment with the latest technology to verify the original findings
a scientist using the latest graphing software to analyze and present the research

Answers

A scientist exploring evidence from other fields of science to support findings is an example of a scientist using creativity.

What is creativity?

Creativity is a mental cognitive ability that involves the creation and/or discovery of a hidden process.

In science, creativity refers to the application of mental skills to create new experimental designs and extrapolate findings.

In conclusion, a scientist exploring evidence from other fields of science to support findings is an example of a scientist using creativity.

Learn more about creativity here:

https://brainly.com/question/26061350

#SPJ1

How can you find the amount of valence electrons an atom of an element contains?

Answers

Answer:

For neutral atoms, the number of valence electrons is equal to the atom's main group number. The main group number for an element can be found from its column on the periodic table. For example, carbon is in group 4 and has 4 valence electrons. Oxygen is in group 6 and has 6 valence electrons.

Explanation:

16.A mixture of carbon dioxide and hydrogen gases contains carbon dioxide at a partial pressure of 217 mm Hg and hydrogen at a partial pressure of 703 mm Hg. What is the mole fraction of each gas in the mixture?

XCO2 =

XH2 =

Answers

x CO₂  = 0.236

x H₂  = 0.764

Further explanation

Given

P CO₂ = 217 mmHg

P H₂ = 703 mmHg

Required

The mole fraction

Solution

Dalton's law :

The total pressure of a mixture of gases is equal to the sum of the partial pressures of the component gases  

Can be formulated:  

P tot = P1 + P2 + P3 ....  

P tot for the mixture :

= 217 mmHg + 703 mmHg

= 920 mmHg

Mole fraction of each gas :

x CO₂ = 217 mmHg/920 mmHg = 0.236

x H₂ = 703 mmHg/920 mmHg = 0.764

what is the percent composition of (NH4)2S?
if you can, include the problem shown pls
extra.
Mg(NO3)2
please don't just take the points please :(, do the problem
thank you <333

Answers

(NH₄)₂S

%N=  41.18%

%H =11.76%

%S=47.06%

Mg(NO₃)₂

%Mg=32.43%

%N=18.92%

%O=(64.86%

Further explanation

Given

(NH₄)₂S

Mg(NO₃)₂

Required

The percent composition

Solution

(NH₄)₂S MW=68 g/mol

%N=2. Ar N  / MW (NH₄)₂S x 100%

%N= (2.14/68) x 100% = 41.18%

%H =(8.1/68) x 100%=11.76%

%S=(32/68)x 100%=47.06%

Mg(NO₃)₂ MW=148 g/mol

%Mg=(2.24/148)x100%=32.43%

%N=(2.14/148)x100%=18.92%

%O=(6.16/148)x100%=64.86%

Base your answer on the information below. The hydrocarbon 2-methylpropane reacts with iodine as represented by the balanced equation below. At standard pressure, the boiling point of 2-methylpropane is lower than the boiling point of 2-iodo-2-methylpropane. Explain the difference in the boiling points of 2-methylpropane and 2-iodo-2-methylpropane in terms of both molecular polarity and intermolecular forces.

Answers

Answer:

See explanation

Explanation:

The boiling point of a substance is affected by the nature of bonding in the molecule as well as the nature of intermolecular forces between molecules of the substance.

2-methylpropane has only pure covalent and nonpolar C-C and C-H bonds. As a result of this, the molecule is nonpolar and the only intermolecular forces present are weak dispersion forces. Therefore, 2-methylpropane has a very low boiling point.

As for 2-iodo-2-methylpropane, there is a polar C-I bond. This now implies that the intermolecular forces present are both dispersion forces and dipole interaction. As a result of the presence of stronger dipole interaction between 2-iodo-2-methylpropane molecules, the compound has a higher boiling point than  2-methylpropane.

Please help me.
Thank you!

Answers

Answer: Positive

Explanation: Just a guess

Answer:

Positive

Explanation:

Which type of reaction is always spontaneous?

A. an exothermic reaction that has an increase in disorder

B. an exothermic reaction that has a decrease in disorder

C. an endothermic reaction that has an increase in disorder

D. an endothermic reaction that has a decrease in disorder​

Answers

I don’t really know , maybe it’s B

Answer:

A.) an exothermic reaction that has an increase in disorder.

Explanation:

got it correct (unit review test)

17.Oxygen gas can be prepared by heating potassium chlorate according to the following equation:

2KClO3(s)2KCl(s) + 3O2(g)

The product gas, O2, is collected over water at a temperature of 25 °C and a pressure of 755 mm Hg. If the wet O2 gas formed occupies a volume of 6.22 L, the number of grams of O2 formed is ________
g. The vapor pressure of water is 23.8 mm Hg at 25 °C.

Answers

Mass of O₂ formed = 7.84 g

Further explanation

Given

Reaction

2KClO₃(s) ⇒2KCl(s) + 3O₂(g)

P water = 23.8 mmHg

P tot = 755 mmHg

V = 6.22 L

T = 25 + 273 = 298 K

Required

mass of O₂

Solution

P tot = P O₂ + P water

P O₂ = P tot - P water

P O₂ = 755 - 23.8

P O₂ = 731.2mmHg = 0.962 atm

Moles O₂ :

Ideal gas law :

n = PV/RT

n = 0.962 x 6.22 / 0.082 x 298

n = 0.245

Mass O₂ :

= mol x MW

= 0.245 x 32

= 7.84 g

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