A seal swims on a bearing of 055 degrees for 4km. How far north is the seal from its starting point?

Therefore, the component form of vector v is (7.7551, 2.0664) (rounded to four decimals).

To find the component form of a vector v given its magnitude and the angle it makes with the positive x-axis, we can use trigonometric functions to determine the x-component (v_x) and y-component (v_y) of the vector. In this case, we are given the magnitude of the vector ‖v‖ = 8 and the angle θ = 15°. The formulas for finding the components are:

v_x = ‖v‖ * cos(θ)

v_y = ‖v‖ * sin(θ)

Plugging in the given values, we have:

v_x = 8 * cos(15°)

v_y = 8 * sin(15°)

By evaluating these trigonometric functions, we can calculate the values:

v_x ≈ 8 * cos(15°) ≈ 7.7551

v_y ≈ 8 * sin(15°) ≈ 2.0664

These values represent the x-component and y-component of the vector v, respectively. So, the component form of vector v is approximately (7.7551, 2.0664) (rounded to four decimals).

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Step-by-step explanation:

From distance formula

(x

2

−x

1

)+(y

2

−y

1

)+(z

2

−z

1

)

AB=

1+4+1

=

6

AC=

36+5+9

=

56

=3

6

AC

AB

=

EC

BE

⇒

3

6

6

=

EC

BE

⇒

EC

BE

=

3

1

So now we can find point E

E=(

m

1

+m

2

x

1

x

2

+m

2

m

1

),(

m

1

+m

2

m

1

y

2

+m

2

y

1

),(

m

1

m

2

m

1

z

2

+m

2

z

1

)

E=(

4

−5+6

,

4

2+3

,

4

−6−6

)=E(

4

1

,

4

5

,−3)

Now we can find distance AE

AE=

(1−

4

1

)

2

+(1−

4

5

)

2

+(−3+3)

2

AE=

16

9

+8

16

1

+0

AE=

4

3

10

To solve 4222 - 2451 using the left-to-right algorithm, we start with the thousands place and subtract 2 from 4, which gives us 2. Then we move to the hundreds place and realize that we cannot subtract 4 from 2, so we need to borrow from the thousands place.

We start by subtracting the thousands place digits, then the hundreds, the tens, and finally the ones.

Starting with the thousands place, we have:

4 - 2 = 2

So we write down 2 as the leftmost digit of the answer.

Moving to the hundreds place, we have:

2 - 4 = -2

Since we cannot subtract 4 from 2, we need to "borrow" from the thousands place. We can do this by subtracting 1 from the 2 in the thousands place, making it a 1, and adding 10 to the hundreds place, making it 12.

Now we have:

12 - 4 = 8

So we write down 8 as the second digit of the answer.

Moving to the tens place, we have:

2 - 5 = -3

Again, we need to borrow. We can subtract 1 from the 1 in the thousands place, making it 0, and add 10 to the tens place, making it 12.

Now we have:

12 - 5 = 7

So we write down 7 as the third digit of the answer.

Finally, we move to the ones place:

2 - 1 = 1

So we write down 1 as the last digit of the answer.

Putting it all together, we have:

4222 - 2451 = 1771

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The probability of choosing a green tile and then a blue tile is given as follows:

1/7.

The parameters that are needed to calculate a probability are listed as follows:

Then the probability is then calculated as the division of the number of desired outcomes by the number of total outcomes.

For each outcome, the probabilities are given as follows:

Hence the probability is given as follows:

2/7 x 1/2 = 1/7.

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The general solution of this differential equation is y(t) = c1 cos(5t) + c2 sin(5t), where c1 and c2 are constants determined by the initial conditions.

Differentiating the second equation with respect to t, we get: d^2y/dt^2 = -5 dx/dt, Substituting dx/dt from the first equation, we get: d^2y/dt^2 = -5(-5y) = 25y.

This is a second order differential equation in y. The general solution of this differential equation is y(t) = c1 cos(5t) + c2 sin(5t), where c1 and c2 are constants determined by the initial conditions.

To find x as a function of t, we can substitute y(t) into the first equation and solve for x: dx/dt = -5y = -5(c1 cos(5t) + c2 sin(5t)) , Integrating both sides with respect to t, we get: x(t) = -c1 sin(5t) + c2 cos(5t) + k

where k is a constant of integration. Using the initial conditions x(0) = 4 and y(0) = 1, we can solve for the constants c1, c2, and k: x(0) = -c1 sin(0) + c2 cos(0) + k = c2 + k = 4, y(0) = c1 cos(0) + c2 sin(0) = c1 = 1

Substituting c1 = 1 and c2 + k = 4 into the equation for x, we get:

x(t) = -sin(5t) + 4

So the solution to the system of differential equations with initial conditions x(0) = 4 and y(0) = 1 is x(t) = -sin(5t) + 4 and y(t) = cos(5t).

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In the triangle, value of n is,

n = 16

We have to given that;

In triangle KMN,

MN = 24 yards

KL = 30 yards

LM = 15 yards

Hence, By proportionality theorem we get;

⇒ MN / KM = OL / KL

⇒ 24 / 45 = n / 30

Solve for n;

⇒ 24 × 30 / 45 = n

⇒ n = 16

Thus, In the triangle, value of n is,

n = 16

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We can rewrite x = 4 sec a in terms of sine and cosine as x = 4/cos(a) = 4(1/cos(a)) = 4/[(1-sin^2(a))^0.5].

To understand why we can rewrite secant as a combination of sine and cosine, we can start with the definition of the secant function. The secant of an angle a is defined as the reciprocal of the cosine of a, or sec(a) = 1/cos(a). Using the Pythagorean identity, 1 = sin^2(a) + cos^2(a), we can solve for cos(a) to get cos(a) = (1 - sin^2(a))^0.5. Substituting this into the definition of secant, we get sec(a) = 1/[(1 - sin^2(a))^0.5]. Finally, multiplying both the numerator and denominator by 4, we get x = 4/[(1 - sin^2(a))^0.5], which is the desired form of x in terms of sine and cosine.

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The height of the trapezoid is H = 10 units

Given data ,

A trapezoid has bases of lengths 30 and 50

Now , the area of the trapezoid is A = 400 units²

where Area of Trapezoid = ( ( a + b ) h ) / 2

On simplifying , we get

400 = ( 30 + 50 ) ( H ) / 2

Multiply by 2 on both sides , we get

800 = 80 H

Divide by 80 on both sides , we get

H = 10 units

Hence , the height is H = 10 units

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The linear regression equation for the data is y=0.47x+23.3 and the projected test grade for a student with a homework grade of 62 is 63.

The linear regression equation for the data is y=0.47x+23.3.

The projected test grade for a student with a homework grade of 62 is:

y = 0.47(62)+23.3

y = 63.

The correlation coefficient is r=0.78, which indicates a strong positive correlation between homework grade and test grade. This means that students who do well on their homework tend to also do well on their tests.

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In order to construct a confidence interval for the population mean when the population standard deviation is known, two assumptions must be met. Firstly, the sample data must be a simple random sample from the population being studied.

Secondly, the variable being measured must have a normal distribution or the sample size must be sufficiently large. The first assumption of a simple random sample ensures that the sample is representative of the population being studied, which is necessary for valid statistical inference. The second assumption is necessary because the confidence interval calculation relies on the assumption that the sample mean follows a normal distribution. When the variable being measured has a normal distribution, the sample mean will also have a normal distribution regardless of the sample size. When the variable being measured does not have a normal distribution, the sample size must be large enough (typically at least 30) in order for the sample mean to follow a normal distribution due to the central limit theorem. By meeting these two assumptions, we can be confident in the accuracy of the resulting confidence interval for the population mean.

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Percentage of Mrs. smith's students scored at or above a 92% for given mean and standard deviation using standard normal distribution is equal to 15.87%.

Mean = 80

Standard deviation = 12

To find the percentage of Mrs. Smith's students who scored at or above a 92%,

Find the area under the normal distribution curve to the right of 92%.

Use a standard normal distribution table or a calculator ,

Find the corresponding z-score for a raw score of 92 in a normal distribution with mean 80 and standard deviation 12.

z = (92 - 80) / 12

  = 1

This means that a score of 92 is one standard deviation above the mean.

From a standard normal distribution table,

Attached table.

Find that the area to the right of a z-score of 1 is approximately 0.1587.

This means that approximately 15.87% of Mrs. Smith's students scored at or above a 92%.

Therefore, about 15.87% of Mrs. Smith's students scored at or above a 92% on the psychology test using standard normal distribution .

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Answer: 30/40

Step-by-step explanation: 10 blue marbles - 40 = 30

The overall main text structure of "How Archaeologists Found the Lost City of Troy" is best described as a description. The Option D is correct.

This article titted "How Archaeologists Found the Lost City of Troy" is focused on providing a detailed description of how archaeologists were able to locate the ancient city of Troy.

The author uses descriptive language and provides a chronological account of the excavation process as well as detailing the various methods and techniques used by archaeologists to uncover the city's remains.

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The height of the tower is 969 feet.

Let CD be the tower and A be the point from a window in the building, a person determines that the angle of elevation to the top of the tower is 42 degrees.

In triangle AED

tan42° = ED/AE

tan42° = h₁/615

h₁ = tan42° × 615

= 553.74

Rounding to the nearest integer

h₁ = 554

In triangle AEC

tan34° = EC/AE

tan34° = h₂/615

h₂ = tan34° × 615

= 414.82

Rounding to the nearest integer

h₂ = 415

Height of tower = EC + ED

= h₁ + h₂

= 554 + 415

= 969

Therefore, the height of the tower is 969 feet.

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Answer:

Step-by-step explanation:

2.807 km × 3280.84 ft/km ≈ 9203.2 ft

Rounding this to the nearest foot, we get:

The amount of fencing needed to enclose the semi-circle is approximately 9203 feet.

The defined sets are as follows:

U = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10....25}

A = {3, 6, 9, 12, 15, 18}

A' = {1, 2, 4, 5, 7, 8, 10, 11, 13, 14, 16, 17, 19, 20, 21, 22, 23, 24, 25}

The universal set contains natural numbers that are at most 25. Natural numbers are counting numbers.

Therefore,

universal set = U = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10....25}

A is the set of multiples of 3 that are less than 20. Therefore,

A = {3, 6, 9, 12, 15, 18}

A'(A prime) is the number that is not in the A set but is present in the universal set.

Therefore,

A' = {1, 2, 4, 5, 7, 8, 10, 11, 13, 14, 16, 17, 19, 20, 21, 22, 23, 24, 25}

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The general solution of the differential equation
y''(t) = 28e^(4t)sin(6t) is y(t) = c1e^(4t)sin(6t) + c2e^(4t)cos(6t).

To find the general solution of the differential equation
y''(t) = 28e^(4t)sin(6t), we can solve the homogeneous equation y''(t) = 0 and then find a particular solution for the non-homogeneous equation.

The homogeneous equation is y''(t) = 0, which has the general solution y(t) = c1 + c2t, where c1 and c2 are arbitrary constants.

To find a particular solution for the non-homogeneous equation, we can use the method of undetermined coefficients. Since the non-homogeneous term is of the form e^(4t)sin(6t), we can assume a particular solution of the form y_p(t) = Ate^(4t)sin(6t) + Bte^(4t)cos(6t). After taking the first and second derivatives, we can substitute them back into the original equation and solve for the coefficients A and B.
We obtain A = -7/200 and B = 3/100.

Therefore, the general solution of the differential equation
y''(t) = 28e^(4t)sin(6t) is y(t) = c1e^(4t)sin(6t) + c2e^(4t)cos(6t) - (7/200)te^(4t)sin(6t) + (3/100)te^(4t)cos(6t), where c1 and c2 are arbitrary constants.

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To calculate the number of arrangements of the given letters (aabbccdefg) with no pair of consecutive letters the same, we can use the concept of permutations with restrictions.

Let's consider the letters a, b, c, d, e, f, and g as distinct elements. We need to arrange these elements in such a way that no two consecutive letters are the same.

We can start by arranging the distinct elements (a, b, c, d, e, f, g) in a line, which can be done in 7! (7 factorial) ways.

Now, we need to consider the arrangements where the same letters are together. In this case, we have two pairs of repeated letters: (a, a) and (b, b).

We can treat each pair as a single entity. So, we have 6 elements to arrange: (aabb, c, d, e, f, g).

The 6 elements can be arranged in 6! ways.

Therefore, the total number of arrangements is 7! * 6!.

Note: If the repeated letters were not together, we would have to consider more cases and the calculation would be more complex.

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The words that describe probability that he will land on white is impossible. The Option D.

Probability is math branch that deals with finding out the likelihood of the occurrence of an event.

Here, the spinner is divided into four equal-sized sections, the probability of landing on any specific color will be:

= Either of red, green, yellow or blue / 4

= 1/4.

it is mentioned that if Luke lands on a line between the colors, he keeps spinning until he lands on a color. This means that there is no chance of landing on white directly.

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The scale factor from ABC to DEF is 2/5

From the question, we have the following parameters that can be used in our computation:

The triangles

From the triangles, we have the following parameters

Side length of ABC = 40

Corresponding side length of DEF = 16

Using the above as a guide, we have the following:

Scale factor of the dilation = Corresponding side length of DEF / Side length of ABC

So, we have

Scale factor of the dilation = 16/40

Evaluate

Scale factor of the dilation = 2/5

Hence, the scale factor of the dilation is 2/5

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Check the picture below.

[tex]\sin(A )=\cfrac{\stackrel{opposite}{2\sqrt{2}}}{\underset{hypotenuse}{4}}\implies \sin(A )=\cfrac{\sqrt{2}}{2} \\\\\\ \cos(A )=\cfrac{\stackrel{adjacent}{2\sqrt{2}}}{\underset{hypotenuse}{4}}\implies \cos(A )=\cfrac{\sqrt{2}}{2} \\\\\\ \tan(A )=\cfrac{\stackrel{opposite}{2\sqrt{2}}}{\underset{adjacent}{2\sqrt{2}}}\implies \tan(A)=1[/tex]

The complement of the event "both of the marbles are blue" is the event "one or more of the marbles are not blue".

The complement of an event refers to all the outcomes that are not part of that event. In this case, the complement of the event "both of the marbles are blue" would include all outcomes where at least one of the marbles is not blue.

Let's analyze the given options:

A. Both of the marbles are green:

This option describes an event that is different from the complement.

It implies that both marbles are green, which is not the opposite of "both marbles are blue."

B. One or more of the marbles are blue:

This option correctly describes the complement of the event.

It includes all outcomes where at least one marble is not blue, which covers situations where one or both marbles are green.

C. One or more of the marbles are green:

This option is the same as option B.

It describes the complement of the event "both marbles are blue" accurately.

D. Exactly one marble is blue and one marble is green:

This option describes a specific outcome rather than the complement of the event.

It specifies a scenario where one marble is blue and the other is green, but it does not cover other possibilities.

Based on the analysis, the statement that best describes the complement of the event "both of the marbles are blue" is B.

One or more of the marbles are blue (or equivalently,

C. One or more of the marbles are green).

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In polar coordinates, the equation for (a) is r = 10sinθ, the equation for (b) is r = √10, the equation for (c) is r = 6cosθ, and the equation for (d) is r = 10sinθ / (cos^2θ - sin^2θ).

In polar coordinates, a point (r, θ) represents the distance r from the origin and the angle θ measured counterclockwise from the positive x-axis. To express each equation in polar coordinates, we can substitute x = rcosθ and y = rsinθ, then simplify using trigonometric identities and algebraic manipulations.

(a) y = 10

Substituting y = rsinθ, we get rsinθ = 10, or r = 10sinθ.

(b) x^2 + y^2 = 10

Substituting x = rcosθ and y = rsinθ, we get r^2 = 10, or r = √10.

(c) x^2 + y^2 - 6x = 0

Substituting x = rcosθ and y = rsinθ, we get r^2 - 6rcosθ = 0, or r = 6cosθ.

(d) x^2(x^2 + y) = 10y^2

Substituting x = rcosθ and y = rsinθ, we get r^2cos^2θ(r^2cos^2θ + rsinθ) = 10r^2sin^2θ, or r = 10sinθ / (cos^2θ - sin^2θ).

Therefore, in polar coordinates, the equation for (a) is r = 10sinθ, the equation for (b) is r = √10, the equation for (c) is r = 6cosθ, and the equation for (d) is r = 10sinθ / (cos^2θ - sin^2θ).

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Answer:

(10,13)

Step-by-step explanation:

the distance from A to D is 8. you can see that from subtracting the x coordinates 10-2=8.

This is a square so all the sides are equal. To find C, add 8 to the Y coordinate from point B.

5+ 8 = 13

so c is at (10,13)

The length of the curve is:

[tex]=\frac{(68)^\frac{3}{2}-8 }{3}[/tex]

Using the arc length formula in terms of polar coordinates [tex]\int\limits\sqrt{r^2+(\frac{dr}{d\theta})^2 }[/tex]

To find the length of the curve we will use the formula:

[tex]\int\limits\sqrt{r^2+(\frac{dr}{d\theta})^2 }[/tex]

Now, Let us put it in the expression:

[tex]r = \theta^2\\\\\frac{dr}{d\thera} =2\theta[/tex]

Now the integral becomes:

[tex]=\int\limits^8_0 \sqrt{(\theta)^4+(2\theta)^2} \, d\theta\\ \\=\int\limits^8_0\theta \sqrt{(\theta)^2+4} \, d\theta\\[/tex]

Now using the substitution method:

[tex]\theta^2+4=t\\\\2\thetad\theta=dt\\\\=\int\limits\frac{\sqrt{t}dt }{2}\\ \\=\frac{t^\frac{3}{2} }{3}\\ \\=\frac{(\theta^2+4)^\frac{3}{2} }{3}[/tex]

Now, Let us plug in the values:

[tex]=\frac{(68)^\frac{3}{2}-8 }{3}[/tex]

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The best method for solving X² - 8x + 16=0 is the factor method. This is because the given quadratic equation has two identical factors.

Using the factor method, we can factorize the quadratic expression as (X-4)² =0. This can be solved easily by taking the square root of both sides, which gives us X - 4 = 0 or X = 4.

The square root method would also work in this case since the quadratic expression is a perfect square trinomial. However, it is more efficient to use the factor method since it only involves factoring and solving a linear equation, while the square root method requires taking square roots of both sides of the equation.

The quadratic formula method would also work for solving this equation, but it is more complicated and time-consuming compared to the factor method.

Therefore, the factor method is the best method for solving X²- 8x + 16=0

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Answer:c

Step-by-step explanation::Add all the absolute deviations and divide by number of swimmers. Step-by-step explanation:

Answer:

0

Step-by-step explanation:

Given

f ( x ) = - x² - 10x - 9

To find : f ( - 1 )

x = 1

f ( 1 ) = - ( - 1 )² - 10 ( - 1 ) - 9

       = - 1 + 10 - 9

       = 10 - 9 - 1

       = 10 - 10

f ( 1 ) = 0

Answer:

11.5

Step-by-step explanation:

65=10x-50
+50.     +50
=115=10x