A schooterist move along a circular path for radius 0.2km for 2 minutes
A ) what is the distance travelled
B) what is the velocity of the schooterist

Answers

Answer 1

Answer:

a 1.26 km b 10.5 m/s

Explanation:

A. Distance travelled by the schooterist

Since the schooterist travels in a circular path, the distance moved is the circumference of a circle, C with radius r = 0.2 km

C = 2πr

= 2π(0.2 km)

= 1.26 km

So, the distance travelled by the schooterist is 1.26 km

B. The velocity of the schooterist

The velocity of the schooterist v = distance travelled/time

distance travelled = 1.26 km = 1260 m

time = 2 minutes = 2 × 60 s = 120 s

So, V = 1260 m/120 s

= 10.5 m/s

So, the velocity of the schooterist is 10.5 m/s


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A right triangle ABC has sides /AB/ =9cm, /BC/=12cm find /AC/ and angles ACB and ABC if angle BAC= 90°​

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fdi9bn 08989089089008i uuuuuuri9ij

HELLLP PLEASE || the graph below shows a conversion of energy for a skydive jumping out of a plane and landing safely on the ground. which energy is represented by line A? A) Potential B) Thermal C) Kinetic D) Total Energy

Answers

Answer: I maybe wrong but i'm pretty sure its C) Kinetic energy

Find the average velocity if the takeoff velocity of an airplane on a runway is 300 km/hr with an acceleration of 1 m/s2 . A) 30 sec B) 41.7 sec C) 72.2 sec D) 83.33 sec

Answers

Answer:

83.33s

Explanation:

velocity=300km/hr ,acceleration =1m/s2

But before we can make this calculation,we have to make sure that both the acceleration and velocity are in the same units.So I decided to Chang the velocity to m/s.

Converting 300km/hr into m/s;

Changing 300km into m=300000m

Changing 1hr into secs=3600sec

Velocity in m/s=83.33m/s

But Time =velocity/acceleration

=83.33/1

=83.33sec

You have to decide what you want.  Your question says "Find the average velocity", but the choices you listed are all times, not velocities.

(300 km/hr) x (1 hr / 3600 sec) = 83.33 meters/sec

-- If the airplane starts from rest and accelerates uniformly at 1 m/s², it'll take 83.33 seconds to reach takeoff speed.

-- If it starts from rest and accelerates uniformly to 83.33 m/s, then its average speed is 41.67 m/s no matter what its acceleration may be.

Calculate the volume of the part of the sphere that will be immersed in the mercury when the density of the sphere is 7800kg/metre cubic and volume of 136centrimetre cubic and the density of the mercury is 13600kg/metre cubic

Answers

Answer:

78 cm³

Explanation:

The Volume Immersed = (density of object/ density of fluid) x Volume of Object

Vi = (7800/13600) x 136 = 78 cm³

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