Answer:
a 1.26 km b 10.5 m/s
Explanation:
A. Distance travelled by the schooterist
Since the schooterist travels in a circular path, the distance moved is the circumference of a circle, C with radius r = 0.2 km
C = 2πr
= 2π(0.2 km)
= 1.26 km
So, the distance travelled by the schooterist is 1.26 km
B. The velocity of the schooterist
The velocity of the schooterist v = distance travelled/time
distance travelled = 1.26 km = 1260 m
time = 2 minutes = 2 × 60 s = 120 s
So, V = 1260 m/120 s
= 10.5 m/s
So, the velocity of the schooterist is 10.5 m/s
A right triangle ABC has sides /AB/ =9cm, /BC/=12cm find /AC/ and angles ACB and ABC if angle BAC= 90°
fdi9bn 08989089089008i uuuuuuri9ij
HELLLP PLEASE || the graph below shows a conversion of energy for a skydive jumping out of a plane and landing safely on the ground. which energy is represented by line A? A) Potential B) Thermal C) Kinetic D) Total Energy
Answer: I maybe wrong but i'm pretty sure its C) Kinetic energy
Find the average velocity if the takeoff velocity of an airplane on a runway is 300 km/hr with an acceleration of 1 m/s2 . A) 30 sec B) 41.7 sec C) 72.2 sec D) 83.33 sec
Answer:
83.33s
Explanation:
velocity=300km/hr ,acceleration =1m/s2
But before we can make this calculation,we have to make sure that both the acceleration and velocity are in the same units.So I decided to Chang the velocity to m/s.
Converting 300km/hr into m/s;
Changing 300km into m=300000m
Changing 1hr into secs=3600sec
Velocity in m/s=83.33m/s
But Time =velocity/acceleration
=83.33/1
=83.33sec
You have to decide what you want. Your question says "Find the average velocity", but the choices you listed are all times, not velocities.
(300 km/hr) x (1 hr / 3600 sec) = 83.33 meters/sec
-- If the airplane starts from rest and accelerates uniformly at 1 m/s², it'll take 83.33 seconds to reach takeoff speed.
-- If it starts from rest and accelerates uniformly to 83.33 m/s, then its average speed is 41.67 m/s no matter what its acceleration may be.
Calculate the volume of the part of the sphere that will be immersed in the mercury when the density of the sphere is 7800kg/metre cubic and volume of 136centrimetre cubic and the density of the mercury is 13600kg/metre cubic
Answer:
78 cm³
Explanation:
The Volume Immersed = (density of object/ density of fluid) x Volume of Object
Vi = (7800/13600) x 136 = 78 cm³