Answer:
It is 26600 because 400 x66 is 26600 meters
Which of the following is form of energy:
a) Power
b) Light
C) pressure
d) None
Answer:
Explanation:
b) light
An electron that has an instantaneous velocity of is moving through the uniform magnetic field (a) Find the force on the electron due to the magnetic field. (b) Repeat your calculation for a proton having the same velocity
Answer:
Explanation:
From the given information:
The missing value are as follows:
The velocity [tex]v ^{\to} = (2.0 \times 10^6 \ m/s) \hat i + (3.0 \times 10^6 \ m.s) \hat j[/tex]
The uniform magnetic field [tex]B^{\to} = (0.030 T)\hat i -(0.15 T) \hat j[/tex]
The force on electron as a result of the Magnetic field is:
[tex]F^\to = q(v^\to \times B^\to)[/tex]
here;
Change of electron [tex]q = -1.6 \times 10^{-19} C[/tex]
Then,
[tex]v^{\to} \times B^{\to} = \left|\begin{array}{ccc}2\times10^6&3\times 10^6&0\\0.03&-0.15&0\end{array}\right|[/tex]
[tex]= \hat i(0-0) -\hat j ( 0-0) +\hat k (-3\times 10^5 -0.9\times 10^5) \\ \\ =-3.9 \times 10^5 \ k[/tex]
∴
[tex]F^\to = q(v^\to \times B^\to)[/tex]
[tex]F^{\to} = -1.6 \times 10^{-19} \times -3.9 \times 10^5 \\ \\ F^{\to} = 6.24 \times 10^{-14 } \ N[/tex]
For the proton with the same velocity:
[tex]q = 1.6 \times 10^{-19 } \ C \\ \\ F = q (v^\to * B^\to) \ \\ \\ F^\to = q(-3.9 \times 10^5) \\ \\ F = (1.6 \times 10^{-19}) (-3.9 \times 10^5) \\ \\ \mathbf{F ^{\to} = -6.24 \times 10^{-14} \ N}[/tex]
what is the difference between impulse and momentum
Answer:
The momentum of the object is given by the product of mass and velocity while the impulse is the change of momentum when a large force is applied on an object for a short interval of time.
I would reword it
Hope this helps!!
Please helpppppppppp!!!!!!!!!!!
What is the speed of a wave if it has a wavelength of
42 m and a frequency of 7 hertz?
Answer:
♕ [tex]\large{ \red{ \tt{Step - By - Step \: Explanation}}}[/tex]
☃ [tex] \underline{ \underline{ \blue{ \large{ \tt{G \: I \: V \: E\: N}}}}} : [/tex]
Frequency ( f ) = 7 HertzWavelength ( λ ) = 42m♨ [tex] \underline {\underline{ \orange{ \large{ \tt{T \: O \: \: F \: I \: N\: D}}}} }: [/tex]
Wave velocity ( v )☄ [tex]\underline{ \underline{ \large{ \pink{ \tt{S\: O \: L \: U \: T\: I \: O \: N}}}}}: [/tex]
✧ [tex] \red{ \boxed{ \large{ \purple{ \sf{Wave \: velocity(v) = Frequency(f) \times Wavelength(λ)}}}}}[/tex]
~Plug the known values and then multiply!
↦ [tex] \large{ \tt{7 \times 42}}[/tex]
↦ [tex] \boxed{ \boxed{ \large{ \bold{ \tt{294 \: m {s}^ {- 1} }}}}}[/tex]
☥ [tex] \large{ \boxed{ \boxed{ \large{ \tt{Our \: Final \: Answer : \underline{ \large{ \tt{294 \: m {s}^{ - 1}}}}}}}}} [/tex]
---------------------------------------------------------------
❁ [tex] \underline{ \large{ \red{ \tt{D\: E\: T \: A \: I \: L\: E \: D \: \: I\: N \: F \: O}}}} : [/tex]
Frequency ( f ) : The number of complete waves , set up in a medium in one second is called frequency of the wave. The SI unit of frequency is Hertz ( Hz ). For example : if a sound wave completes 15 compressions and 15 rarefactions in one second , it's frequency is 15 Hz.Wavelength ( λ ) : The distance between two consecutive troughs or crests in a transverse wave or the distance between two consecutive compressions or rarefactions in a longitudinal wave us called wavelength. It is the distance travelled by a wave in a time equal to it's time period. It's SI unit is metre ( m ).Wave velocity ( v ) : The velocity with which a wave propagates in a medium is called wave velocity. It's SI unit is m/s.# KILL : Excuses
KISS : Opportunities
MARRY : Goals
♪ Hope I helped! ♡
☂ Have a wonderful day / night ! ツ
✎ [tex] \underbrace{ \overbrace{ \mathfrak{Carry \: On \: Learning}}}[/tex] ✔
▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁
4- What force must be applied to a surface area of 0.0025m , to create a pressure ol
200.000Pa?
A vertical spring with a spring constant of 450 N/m is mounted on the floor. From directly above the spring, which is unstrained, a 0.30-kg ball is dropped from rest. It collides with and sticks to the spring, which is compressed by 2.5 cm in bringing the block to a momentary halt. Assuming air resistance is negligible, from what height (in cm) above the uncompressed spring was the block dropped
Answer:
h = 1.91 m
Explanation:
From the law of conservation of energy, we know that:
[tex]Potential\ Energy\ of\ Ball = Elastic\ Petential\ Energy\ of\ Spring\\mgh = \frac{1}{2}kx^2[/tex]
where,
m = mass of ball = 0.3 kg
g = acceleration due to gravity = 9.81 m/s²
h = height of ball = ?
k = spring constant = 450 N/m
x = compressed length = 2.5 cm = 0.025 m
Therefore,
[tex](0.3\ kg)(9.81\ m/s^2)h = \frac{1}{2} (450\ N/m)(0.025\ m)^2\\\\h = \frac{(450\ N/m)(0.025\ m)^}{(2)(0.3\ kg)(9.81\ m/s^2)}[/tex]
h = 1.91 m
A Young’s double-slit apparatus is set up where a screen is positioned 0.80 m from the double slits. If the distance between alternating bright fringes is 0.95 cm, and the light source has a wavelength of 580 nm, what is the separation of the double slits?
Answer: 0.0488 mm
Explanation:
Given
The position of the screen is [tex]D=0.80\ m[/tex]
Distance between alternating bright fringes is [tex]0.95\ cm[/tex]
The wavelength of the light source is [tex]\lambda =580\ nm[/tex]
Distance between successive bright fringes is [tex]\frac{\lambda D}{d}[/tex]
Distance between alternating bright fringes is half of the distance between successive fringes i.e. [tex]\frac{\lambda D}{2d}[/tex]
Insert the values for alternating fringes
[tex]\Rightarrow 0.95\times 10^{-2}=\dfrac{580\times 10^{-9}\times 0.8}{d}\quad [\text{d=separation of the doubleslits}]\\\\\Rightarrow d=\dfrac{464\times 10^{-9}}{0.95\times 10^{-2}}\\\\\Rightarrow d=488.42\times 10^{-7}\ m\\\Rightarrow d=0.0488\ mm[/tex]
Walk 150.0 m , turn 90 degrees and walks additional 70.0 m why’s the magnitude of displacement
Answer:
you can use Pythagorean theorem to solve for the last side. it is simply
_/ 150^2+70^2 which equals 165.5
Atoms are composed of protons, ______, and electrons.
Atoms are composed of protons, [tex]\sf\purple{neutrons}[/tex]and electrons. ✅
The [tex]\sf\blue{protons}[/tex] (positively charged) and the [tex]\sf\pink{neutrons}[/tex] (no charge) are in the centre of the atom, making up the nucleus.[tex]\sf\red{Electrons}[/tex] (negatively charged) are present in the outermost shell of the atom.[tex]\bold{ \green{ \star{ \orange{Hope\:it\:helps.}}}}⋆[/tex]
A 5.0-m radius playground merry-go-round with a moment of inertia of 1,630 kg m2 is rotating freely with an angular speed of 1.6 rad/s. Two people, each having a mass of 69.5 kg, are standing right outside the edge of the merry-go-round and step on it with negligible speed. What is the angular speed of the merry-go-round right after the two people have stepped on
Answer:
The right solution is "0.511".
Explanation:
Given:
Initial moment of inertia,
= 1630 kg.m²
Radius,
= 5 m
Angular speed,
= 1.6 rad/s
Now,
The moment of inertia after stepping on will be:
= [tex]1630+2\times (69.5\times (5)^2)[/tex]
= [tex]1630+2\times (69.5\times 25)[/tex]
= [tex]5105 \ Kg.m^2[/tex]
hence,
As per the question, the angular speed is conserved, then
⇒ [tex]1630\times 1.6=5105\times \omega'[/tex]
[tex]2608=5105\times \omega'[/tex]
[tex]\omega'=\frac{2608}{5105}[/tex]
[tex]=0.511[/tex]
At the Olympics, high-diving competition,a diver from the top board curves her body in order to?
A. Dive clearly into the water
B. Spin more
C. Increase her energy
D. Spin more slowly
E. Increase her speed
The correct option is E. Increase her speed
High-diving is the process or way in which a person jump into water or swimming pool from a higher heights.
A Diver is a person who dive or Fall into a water from a top board or diving board .
Therefore she was curving her body from the top board in order to Increase her speed which will enable her to spin or flip more faster.
Inconclusion The correct option is E. Increase her speed.
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An old fashioned string of 80 Christmas lights is wired in series. Each bulb has a resistance of 2 Ohms and the entire string is plugged into a 120V outlet. What is the current passing through each of the bulbs?
The sum of the resistance = 2 ohms x 80 lights = 160 ohms.
Current = Total voltage / total resistance:
Current = 120V / 160 ohms
Current = 0.75 Amps
A copper wire has a diameter of 4.00 x 10-2 inches and is originally 10.0 ft long. What is the greatest load that can be supported by this wire without exceeding its elastic limit
Complete question is;
A copper wire has a diameter of 4.00 × 10^(-2) inches and is originally 10.0 ft long. What is the greatest load that can be supported by this wire without exceeding its elastic limit? Use the value of 2.30 × 10⁴ lb/in² for the elastic limit of copper.
Answer:
F_max = 28.9 lbf
Explanation:
Elastic limit is simply the maximum amount of stress that can be applied to the wire before it permanently deform.
Thus;
Elastic limit = Max stress
Formula for max stress is;
Max stress = F_max/A
Thus;
Elastic limit = F_max/A
F_max is maximum load
A is area = πr²
We have diameter; d = 4 × 10^(-2) inches = 0.04 in
Radius; r = d/2 = 0.04/2 = 0.02
Plugging in the relevant values into the elastic limit equation, we have;
2.30 × 10⁴ = F_max/(π × 0.02²)
F_max = 2.30 × 10⁴ × (π × 0.02²)
F_max = 28.9 lbf
Two blocks are connected by a massless rope that passes over a 1 kg pulley with a radius of 12 cm. The rope moves over the pulley without slipping. The mass of block A is 2.1 kg and the mass of block B is 4.1 kg. Block A is also connected to a horizontally-mounted spring with a spring constant of 358 J/m2. What is the angular frequency (in rad/s) of oscillations of this system
Answer:
[tex]F=1.159[/tex]
Explanation:
From the question we are told that:
Mass of pulley [tex]M=1kg[/tex]
Radius [tex]r=12cm[/tex]
Mass of block A [tex]M_a=2.1kg[/tex]
Mass of block B [tex]m_b=4.1kg[/tex]
Spring constant[tex]\mu= 358 J/m2[/tex]
Generally the equation for Torque is mathematically given by
Since [tex]\sumF=ma[/tex]
At mass A
[tex]T_2-f_3=2.1a[/tex]
At mass B
[tex]4.8-T_1=4.1a[/tex]
At Pulley
[tex]R(T_1-T_2)=\frac{1*1*R^2}{2}\frac{a}{R}[/tex]
[tex]R(T_1-T_2)=0.55a[/tex]
Therefore the equation for total force F
At mass A+At mass B+At Pulley
[tex](T_2-f_3+4.8-T_1+R(T_1-T_2)=2.1a+4.1a+0.55a[/tex]
[tex](T_2-f_3+4.8-T_1+R(T_1-T_2)=2.7a+4.8a+0.55a[/tex]
[tex]-f_3+4.1=6.75a[/tex]
[tex]-f_3=6.75a+4.8[/tex]
Since From above equation
[tex]M_{eff}=6.7kg[/tex]
Therefore
[tex]T=2\pi \sqrt{{\frac{M_{eff}}{k}}[/tex]
[tex]T=2\pi \sqrt{{\frac{6.75}{\mu}}[/tex]
[tex]T=0.862s[/tex]
Generally the equation for frequency is mathematically given by
[tex]F=\frac{1}{T} \\F=\frac{1}{0.862}[/tex]
[tex]F=1.159[/tex]
does an object which is positively charged contains all protons and no electrons?
Answer:
Positively charged objects have electrons; they simply possess more protons than electrons.
Explanation:
2. An object that is electrically neutral contains only neutrons. Electrically neutral atoms simply possess the same number of electrons as protons.
Information:If an atom has an equal number of protons and electrons, its net charge is 0. If it gains an extra electron, it becomes negatively charged and is known as an anion.
Tips:If it loses an electron, it becomes positively charged and is known as a cation.
I hope this answers help you! :>Answer:
The contain both protons and electrons, but they have more protons than electrons making it a positively charged object.
differences between static friction and dynamic friction
Answer:
Static friction acts on stationary objects while kinetic friction acts on those in motion. Static friction is always greater or equal to kinetic friction. This can explain why objects often take more force to get in motion than it takes to continue their motion.
uses of generator
pls in points
if you answer correct i will mark you as brainliest
Answer:
Electric generator, also called dynamo, any machine that converts mechanical energy to electricity for transmission and distribution over power lines to domestic, commercial, and industrial customers. Generators also produce the electrical power required for automobiles, aircraft, ships, and trains.
Answer:
Electric motors are used in a broad range of industrial, commercial, and residential, applications, such as fans, pumps, compressors, elevators, and refrigerators. ... DC motors are used for variable speed control applications such as industrial machinery and motor vehicles.
In electricity generation, a generator is a device that converts mechanical energy to electrical energy for use in an external circuit. Generators provide nearly all of the power for electric power grids.
Hope it helps
An irrigation canal has a rectangular cross section. At one point where the canal is 18.2 m wide and the water is 3.55 m deep, the water flows at 2.55 cm/s . At a second point downstream, but on the same level, the canal is 16.3 m wide, but the water flows at 11.6 cm/s . How deep is the water at this point
Answer:
Explanation:
Rate of volume flow at two points will be same at two points .
A₁ V₁ = A₂V₂
A₁ and A₂ are area of cross section at two points and V₁ and V₂ are velocities .
A₁ = 18.2 x 3.55 = 64.61 m²
V₁ = 2 .55 x 10⁻² m/s
A₂ = 16.3 x d = 16.3 d m²
d is depth at second point .
V₂ = 11.6 x 10⁻² m/s
64.61 m² x 2 .55 x 10⁻² m/s = 16.3 d m² x 11.6 x 10⁻² m/s
d = .87 m
so canal is .87 m deep.
A boat travels at 15 m/s in a direction 45° east of north for an hour. The boat then turns and travels at 18 m/s in a
direction 5° north of east for an hour.
What is the magnitude of the boat's resultant velocity? Round your answer to the nearest whole number.
I mis
What is the direction of the boat's resultant velocity? Round your answer to the nearest whole degree.
north of east
Done
Intro
Answer:
v = 31 m, / s; θ = 1 north- east
Explanation
One of the easiest ways to solve these problems is to work with the components of vectors.
Let's set a reference system where the x axis coincides with the West - East direction
Let's use trigonometry
cos 45 = v₁ₓ / v₁
sin 45 = v_{1y} / v₁
v₁ₓ = v1 cos 45
v_{1y} = v₁₁ sin 5
v₁ₓ = 15 cos 45 = 10.6 m / s
v _{1y} = 15 sin 45 = 10.6 m / s
sin 5 = v₂ₓ / v₂
cos 5 = v_{2y} / v₂
v₂ₓ = v2 sin 5
v_{2y}= v2 sin 5
v₂ₓ = 18 sin 5 = 1.569 m / s
v_{2yₓ} = 18 cos 5 = 17.93 m / s
Let's look for the speed in each axis
vₓ = v₁ₓ + v₂ₓ
vx = 10.6 + 1.569
vx = 12.17 m / s
v_y = v_{1y} + v_{2y}
v_y = 10.6 + 17.93
v_y = 28.53 m / s
to find the velocity let's use the Pythagorean theorem
v = [tex]\sqrt{v_x^2 +v_2^2 }[/tex]
v = √ (12.17² + 28.53²)
v = 31.02 m / s
approaching the nearest ether
v = 31 m / s
b) we use trigonometry
tan θ = vy / vx
θ = tan -1
θ = tan vy / vx
θ = tan-1 17.93 / 12.17
θ= 1.47
the closeΕst integer is
θ = 1 north- east
Grace is playing with her dolls and decides to give them a ride on a merry-go-round. She places one of them on an old record player turntable and sets the angular speed at 33.3 rpm. What is their angular speed in rad/s
Answer: [tex]3.48\ rad/s[/tex]
Explanation:
Given
Angular speed in rpm is 33.3 rpm
To convert it into rad/s, multiply it with [tex]\frac{2\pi}{60}[/tex]
Angular speed(rad/s)
[tex]\Rightarrow \dfrac{2\pi \times 33.3}{60}\\\\\Rightarrow 3.48\ rad/s[/tex]
ADHD is triggered ________ by genetic and neurological factors and ________ by social or environmental ones.
A. less; more
B. somewhat; somewhat
C. little; mostly
D. more; less
Answer:
D More: Less
Explanation:
ADHD is triggered more by genetic and neurological factors and less by social or environmental ones.
What is ADHD?ADHD is one of the most common neurodevelopmental disorders of childhood. It is usually first diagnosed in childhood and often lasts into adulthood. Children with ADHD may have trouble paying attention, controlling impulsive behaviors (may act without thinking about what the result will be), or be overly active.
Moreover, ADHD tends to run in families and, in most cases, it's thought the genes you inherit from your parents are a significant factor in developing the condition. Research shows that parents and siblings of someone with ADHD are more likely to have ADHD themselves.
Therefore, adults with attention deficit hyperactivity disorder (ADHD or ADD) lead anxious lives. The nature of ADHD often makes day-to-day life stressful, creating situations and environments fraught with uncertainty – anxiety's primary fuel.
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paano matutugunan o matutulungan ng pamahalaan at ng mga guro yubg mga estudyanteng nakararanas nag stress at anxiety.
Answer: how the government and teachers can address or help students experiencing stress and anxiety.
Explanation:
You have two flashlights that have 0.500-A currents flowing through them. One flashlight has a single 1.50-V battery in its circuit, and the second flashlight has three 1.50-V batteries connected in a chain that provides 4.50 V. How much power is the battery in the first flashlight providing
Answer: 0.75 W
Explanation:
Given
Current flowing [tex]I=0.5\ A[/tex]
The first flashlight has a single 1.5 V battery
The second flashlight has three 1.5 V batteries connected to provide 4.5 V
Power is the product of voltage and current.
For the first flashlight
[tex]\Rightarrow P=1.5\times 0.5\\\Rightarrow P=0.75\ W[/tex]
Thus, the first flashlight providing 0.75 W of power.
Copper zinc and magnesium do not contain any iron. What word is used to describe these types of
metals?
Answer:
Metals that do not contain traces or large proportions of iron in them are called Non-Ferrous metals.
Deimos's Orbit. Deimos orbits Mars at a distance of 23,460 km from the center of the planet and has a period of 1.263 days. Assume that Deimos's orbit is circular. Calculate the mass of Mars. Express your answer in units of kg. (Hint: Use the circular orbit velocity formula ; remember to use units of meters, kilograms, and seconds.) Please round the answer to four significant digits.
Answer:
M = 5.882 10²³ kg
Explanation:
Let's use Newton's second law to analyze the satellite orbit around Mars.
F = m a
force is universal attraction and acceleration is centripetal
a = v²/ R
the modulus of velocity in a circular orbit is constant
v= d/T
the distance of the cicule is
d =2pi R
a = 2pi R/T
we substitute
- G m M / R² = m ( [tex]- \frac{4\pi^2 R^2 }{T^2 R}[/tex])
G M = [tex]\frac{ 4\pi ^2 R^3 }{T^2 }[/tex]
M = [tex]\frac{4 \pi ^2 R^3 }{ G T^2 }[/tex]
the distance R is the distance from the center of the planet Mars to the center of the satellite Deimos
R = 23460 km = 2.3460 10⁷ m
the period of the orbit is
T = 1,263 days = 1,263 day (24 h / 1 day) (3600s / h)
T = 1.0912 10⁵ s
let's calculate
M = [tex]\frac{4 \pi ^2 ( 2.3460 \ 10^7)^3 }{5.67 10^{-11} \ (1.0912 \ 10^5)^2 }[/tex]
M = 509.73418 10²¹ /8.66640 10⁻¹
M = 58.817 10²² kg
M = 5.882 10²³ kg
5. Stopping a fast-moving object is harder than stopping a slow-moving
one.
True
False
A bullet with a mass of 12 g moving horizontally strikes a fixed block of wood and penetrates a distance of 5.2 cm. The speed of the bullet just before the collision is 640 m/s. What is the average force that the wood exerted on the bullet
Answer:
F = 47261.5 N = 47.26 KN
Explanation:
First, we will calculate the deceleration of the bullet by using the third equation of motion:
[tex]2as = v_f^2-v_i^2[/tex]
where,
a = deceleration = ?
s = distace covered = 5.2 cm = 0.052 m
vf = final speed = 0 m/s
vi = initial speed = 640 m/s
Therefore,
[tex]2(a)(0.052\ m) = (0\ m/s)^2-(640\ m/s)^2\\\\a = -\frac{409600\ m^2/s^2}{0.104\ m}\\\\a=-3938461.5\ m/s^2[/tex]
negative sign shows deceleration.
Now for the force, we will use Newton's Second Law of Motion:
F = ma
where,
F = Force = ?
m = mass of bullet = 12 g = 0.012 kg
Therefore,
F = (0.012 kg)(3938461.5 m/s²)
F = 47261.5 N = 47.26 KN
A car with a mass of 1.1 x10 to the third power killograms hits a stationary truck with a mass of 2.3kg x10 to the third power from the rear ean. The initial velocity of the car is +22.0 meters/second. After the collision the velocity of the car is -11.0 meters/second. What is the velocity of the truck after this elastic collision.
Answer:
v2f = +15.8 m/s
Explanation:
Conservation law of linear momentum:
m1v1i + m2vi2 = m1v1f + m2v2f
Given:
m1 = 1.1 × 10^3 kg
m2 = 2.3 × 10^3 kg
v1i = +22.0 m/s
v2i = 0
v1f = -11.0 m/s
v2f = ?
Re-arranging the conservation law, we get
m1v1i = m1v1f + m2v2f
Solving for v2f,
m2v2f =m1(v1i - v1f)
or
v2f = m1(v1i - v1f)/m2
= (1.1 × 10^3 kg)(22.0 m/s - (-11.0 m/s))/(2.3 m/s)
= (1.1 × 10^3 kg)(33.0 m/s)/(2.3 × 10^3 kg)
= +15.8 m/s
g you slide a toy car to see the loop the loop physics. the radius of the loop 0.5 m. The acceleration of gravity what is the minimal height h you need to release the car from so that it makes the loop
Answer:
h = 1.5 m
Explanation:
This exercise must be solved using the concepts of energy.
Starting point. Place where the car leaves
Em₀ = U = m g h
Final point. Highest part of the loop, r = 2R
Em_f = K + U
Em_f = ½ m v² + mg (2R)
the energy is preserved
Em₀ = Em_f
m g h = ½ m v² + m g 2R (1)
the car must have a minimum velicate so that it does not fall, let's use Newton's second law.
∑ F = m a
N + W = m a
acceleration is centripetal
a = v²/ r
the normal is the reaction of the surface to the support of the car, as the speed decreases, the normal decreases until reaching zero
0 + m g = m v² / r
v² = rg
we substitute
v² = 2Rg
we substitute in equation 1
g h = ½ 2Rg + 2Rg
h = 3R
let's calculate
h = 3 0.5
h = 1.5 m