Answer: 317.52
Explanation:
I'm just him, so I just know
The centrifuge at NASA Ames Research Center has a radius of 8.8 m and can produce forces on its payload of 20 gs or 20 times the force of gravity on Earth. (a) What is the angular momentum of a 20-kg payload that experiences 10 gs in the centrifuge? (b) If the driver motor was turned off in (a) and the payload lost 10 kg, what would be its new spin rate, taking into account there are no frictional forces present?
(a) The angular momentum of a 20-kg payload experiencing 10 gs in a centrifuge with a radius of 8.8 m is 5,483 kg m^2/s. (b) If the payload loses 10 kg, the new spin rate taking into account no frictional forces present is 7.54 rad/s.
(a) The angular momentum of a rotating object is given by:
L = Iω
where L is the angular momentum, I is the moment of inertia, and ω is the angular velocity.
The moment of inertia for a point mass rotating in a circle is given by:
I = mr^2
where m is the mass of the object and r is the radius of the circle.
To calculate the angular momentum of the 20-kg payload that experiences 10 gs in the centrifuge, we first need to calculate the angular velocity of the payload. The force on the payload is 10 times the force of gravity on Earth, so the net force on the payload is:
F = ma
F = (10 × 9.8 m/s^2) × 20 kg
F = 1960 N
The net force on the payload is the centripetal force, which is given by:
F = mv^2/r
where v is the velocity of the payload.
Rearranging this equation to solve for v:
v = sqrt(Fr/m)
v = sqrt((1960 N) × (8.8 m) / (20 kg))
v = 33.2 m/s
The angular velocity of the payload is:
ω = v/r
ω = 33.2 m/s / 8.8 m
ω = 3.77 rad/s
Finally, we can calculate the angular momentum of the payload:
L = Iω
L = (mr^2)ω
L = (20 kg) × (8.8 m)^2 × 3.77 rad/s
L = 5,483 kg m^2/s
(b) When the payload loses 10 kg, its new moment of inertia becomes:
I' = m'r^2
I' = (10 kg) × (8.8 m)^2
I' = 774.4 kg m^2
Conservation of angular momentum tells us that:
L = Iω = I'ω'
where ω' is the new angular velocity of the payload.
Solving for ω':
ω' = (I/I')ω
ω' = ((20 kg) × (8.8 m)^2 × 3.77 rad/s) / ((10 kg) × (8.8 m)^2)
ω' = 7.54 rad/s
So, the new spin rate of the payload is 7.54 rad/s.
Therefore,(a) For a 20-kg payload experiencing 10 gs in a centrifuge with an 8.8 m radius, the angular momentum is 5,483 kg m^2/s. (b) If the payload's mass reduces by 10 kg without any frictional forces present, the new spin rate is 7.54 rad/s.
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A block with mass 0.50 kg
is forced against a horizontal spring of negligible mass, compressing the spring a distance of 0.20 m
(Figure 1). When released, the block moves on a horizontal tabletop for 1.00 m
before coming to rest. The spring constant k
is 100 N/m
What is the coefficient of kinetic friction μk
between the block and the tabletop?
Answer:100
Explanation:
A certain rigid aluminum container contains a liquid at a gauge pressure of P0 = 2.02 × 105 Pa at sea level where the atmospheric pressure is Pa = 1.01 × 105 Pa. The volume of the container is V0 = 2.45 × 10-4 m3. The maximum difference between the pressure inside and outside that this particular container can withstand before bursting or imploding is ΔPmax = 2.35 × 105 Pa.
For this problem, assume that the density of air maintains a constant value of ρa = 1.20 kg / m3 and that the density of seawater maintains a constant value of ρs = 1025 kg / m3.
A) The container is taken from sea level, where the pressure of air is Pa = 1.01 × 105 Pa, to a higher altitude. What is the maximum height h in meters above the ground that the container can be lifted before bursting? Neglect the changes in temperature and acceleration due to gravity with altitude.
B)What is the maximum depth dmax in meters below the surface of the ocean that the container can be taken before imploding?
The maximum height the container can be lifted before bursting is 970 meters above sea level, and the maximum depth the container can be taken before imploding is 35 meters below the surface of the ocean.
Gauge pressure is the pressure measured relative to the atmospheric pressure at a particular location. It does not take into account the atmospheric pressure and only represents the pressure above or below the atmospheric pressure.
A) To find the maximum height h in meters above the ground that the container can be lifted before bursting, we need to find the new gauge pressure at this higher altitude. We can use the relationship between pressure and altitude:
P = P0 + ρgh
where P is the gauge pressure at the new altitude, ρ is the density of air, g is the acceleration due to gravity (assumed constant), and h is the height above sea level. Solving for h, we get:
h = (P - P0) / (ρg)
We know that the maximum pressure difference the container can withstand is ΔPmax = 2.35 × 105 Pa, so the new gauge pressure at the higher altitude can be found by adding this to the sea level pressure:
P = Pa + ΔPmax = 1.01 × 105 Pa + 2.35 × 105 Pa = 3.36 × 105 Pa
Substituting this into the equation above, along with the given values for ρ and g, we get:
h = (3.36 × 105 Pa - 2.02 × 105 Pa) / (1.20 kg/m3 × 9.81 m/s2) ≈ 970 meters
So, the maximum height the container can be lifted before bursting is approximately 970 meters above sea level.
B) To find the maximum depth dmax in meters below the surface of the ocean that the container can be taken before imploding, we need to find the new gauge pressure at this depth. We can use a similar equation to the one used above, but with the density of seawater instead of the density of air:
P = P0 + ρsgd
where g is the acceleration due to gravity (assumed constant), d is the depth below the surface of the ocean, and ρs is the density of seawater. Solving for d, we get:
d = (P - P0) / (ρsg)
We know that the maximum pressure difference the container can withstand is ΔPmax = 2.35 × 105 Pa, so the new gauge pressure at the maximum depth can be found by subtracting this from the sea level pressure:
P = P0 - ΔPmax = 2.02 × 105 Pa - 2.35 × 105 Pa = -0.33 × 105 Pa
(Note that this gives a negative value for pressure, which means the container will implode rather than burst.)
Substituting this into the equation above, along with the given values for ρs and g, we get:
d = (-0.33 × 105 Pa - 1.01 × 105 Pa) / (1025 kg/m3 × 9.81 m/s2) ≈ -35 meters
So, the maximum depth the container can be taken before imploding is approximately 35 meters below the surface of the ocean.
Therefore, The container can be lifted to a maximum height of 970 meters above sea level without bursting, and it can be submerged to a maximum depth of 35 meters without imploding.
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Which part of the Scientific Method is in the right order?
Answer:
Below
Explanation:
since I’m in biology, here are he exact steps from my textbook:
The Scientific Method:
A scientific method is a series of steps for investigating questions and testing ideas. There are several versions of the scientific method, but all versions are based on rational thinking, inquiry, and experimentation. The scientific method includes five main steps. Review the steps of the overall system before diving into each one.
1. Ask a Question:
The purpose of a scientific investigation is what you are trying to find out or the question you are trying to answer. An empirical observation (e.g., the sky is blue) will prompt an appropriate question (e.g., why is the sky blue?).
2. Do Background Research:
You have learned that science is a body of knowledge. It is important that you research what other scientists have already observed and discovered. Previous investigations into your topic may lead you to new questions that need answers. If the farmer wishes to know why his plants are dying, he would research reasons why that type of plant might not grow. The farmer might conduct this research at the library or a local garden center or on the Internet.
3. Form a Hypothesis:
A hypothesis is an explanation for a specific observation, phenomenon, or scientific problem that is based on scientific knowledge and can be tested by further investigation. After researching what other scientists already know, the farmer will need to form a hypothesis about what he thinks will happen. Forming a hypothesis involves an understanding of current scientific knowledge and creativity to look at the problem or question in a way that will lead to the predicted outcome. For instance, the farmer notices that the dying plants seem to be yellow and brown, so he could conclude that there are not enough nutrients in the soil. He would form the hypothesis, ”The lack of nutrients in the soil is causing the plants to die.”
4. Test with an Experiment:
An experiment allows you to test your hypothesis to determine if it is a correct or incorrect prediction of the outcome. There are many ways to test a hypothesis, but every experiment should have at least one variable that changes while the others stay the same or are controlled. This allows the experimenter to determine if a selected change will affect a specific factor in the way their hypothesis predicts. The farmer would then design and carry out a test to try to get an answer to the original question and observation. The farmer would record the data on a data sheet. He would also want to write down the steps he used to carry out his experiment in case it needs to be repeated. This is called the procedure. The farmer would make sure his procedure and data are accurately reported, so that he could share the information with others or repeat the procedure at a later time.
5. Analyze Data:
The analysis of data from an experiment compares known and unknown values in the data. The experiments are always repeated several times to make sure the results are valid. When an experiment is valid, it means that the results are consistent over time and reproducible by you or by another scientist, following the same procedure. Based on the results of the farmer’s experiment, he would analyze the data by creating charts or graphs of the growth of the plants over time.
6. Draw Conclusions:
Based on the analysis of the collected data, a scientist will refer back to the hypothesis and ask: Was the hypothesis correct or incorrect? Sometimes this is very simple and the conclusion is obvious. On occasion, finding that the hypothesis is incorrect will lead to new discoveries. Sometimes, the results are inconclusive, and the scientist must design a new experiment or complete further research. If the farmer finds that the data supports the original hypothesis, he may conclude that the lack of soil nutrients caused the plants to poorly grow (i.e., analysis shows that changing the amount of nutrient causes the plants to grow faster). On the other hand, the data might not support the original hypothesis (i.e., analysis shows that changing the amount of nutrient does not keep the plants from dying). In this case, he would try to change a different variable in the experiment, such as the amount of water, in order to retest his hypothesis.
The drawing shows four situations in which two very long wires are carrying the samecurrent, although the direction of the currents may be different. The point P in the drawings is equidistant from each wire. Which one (or more) of these situations gives rise to a zero net magnetic field at P?
Situation (a) results in a zero net magnetic field at point P. Option 1 is correct.
In situation (a), the two wires are carrying currents in opposite directions. At point P, the magnetic field due to one wire will be in the opposite direction of the magnetic field due to the other wire. Since the two fields are equal in magnitude and opposite in direction, they cancel each other out, resulting in a net magnetic field of zero at point P.
In situations (b), (c), and (d), the currents are either in the same direction or the wires are at different distances from point P. In these situations, the magnetic fields due to the wires do not cancel each other out at point P, resulting in a nonzero net magnetic field. Therefore, only situation (a) gives rise to a zero net magnetic field at point P. Option 1 is correct.
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2. You are traveling along a highway at night at a speed of 100 km/h when you spot an object directly in front of you in the road at the limit of your headlights. (10 Marks)
a) If the maximum braking deceleration that your car can provide is 7 m/s2, and if your headlights extend out to a range of 30 m, will you hit the object before coming to a stop?
b) How long will it take to stop?
a) To determine if the car will hit the object before coming to a stop, we need to calculate the distance required to stop the car, assuming maximum braking deceleration. We can use the following formula:
d = (v^2) / (2a)
where:
d = distance required to stop
v = initial velocity
a = acceleration/deceleration
In this case, v = 100 km/h = 27.78 m/s (converted from km/h to m/s)
a = -7 m/s^2 (negative sign indicates deceleration)
We know that the car's headlights extend out to a range of 30 m, so if the distance required to stop the car is greater than 30 m, the car will hit the object before coming to a stop.
Plugging in the values to the formula, we get:
d = (27.78^2) / (2 x -7) = 108.61 m
Since 108.61 m is greater than 30 m, the car will hit the object before coming to a stop.
b) To calculate the time required to stop, we can use the following formula:
t = v / a
where:
t = time required to stop
v = initial velocity
a = acceleration/deceleration
Plugging in the values, we get:
t = 27.78 / 7 = 3.97 s
Therefore, it will take 3.97 seconds to stop the car.
An object that is 0.5 m above the ground has the same
amount of potential energy as a spring that is stretched
0.5 m. Each distance is then doubled.
How will the potential energies of the object and the
spring compare after the distances are doubled?
O The gravitational potential energy of the object will be
two times greater than the elastic potential energy of
the spring.
O The elastic potential energy of the spring will be four
times greater than the gravitational potential energy of
the object.
O The elastic potential energy of the spring will be two
times greater than the gravitational potential energy of
the object.
O The potential energies will remain equal to one
another.
The gravitational potential energy of the object will be two times greater than the elastic potential energy of the spring after the distances are doubled. The correct option is A.
The gravitational potential energy of an object is given by the formula:
PE = mgh
Where m is the mass of the object, g is the acceleration due to gravity and h is the height of the object above the reference point.
In this case, the height of the object is doubled, so the potential energy will also be doubled. Therefore, when the distance is doubled, the gravitational potential energy of the object will be two times greater than before.
The elastic potential energy of a spring is given by the formula:
PE = 1/2 kx^2
Where k is the spring constant and x is the displacement of the spring from its equilibrium position.
In this case, the displacement of the spring is doubled, so the potential energy will be four times greater than before. Therefore, option B is not correct.
Option C is also not correct because the potential energy of the spring will be four times greater than the gravitational potential energy of the object.
Option D is not correct because the potential energies of the object and the spring are not equal to one another when the distances are doubled.
Therefore, The correct answer is option A.
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At what time t2 will the water be completely frozen so the temperature can begin to fall below 0∘C ?
Express your answer numerically in seconds.
The time taken by the water to freeze and the temperature falls below 0°C is approximately 2940 s.
When the liquid(water) is changed to solid (ice), this process is called melting. The freezing point is a point at which the liquid changes into a liquid. The freezing point of water is 0°C.
From the given,
time taken by the water to freeze below 0°C in the graph (ie: -10°C and -20°C ) = 49 minutes.
1 minute = 60 seconds
49 min = 49×60 seconds = 2940 seconds.
The time taken (t₂) by the water to freeze below 0°C is 2940 seconds.
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A roller-coaster car with a mass of 900 kg starts at rest from a point 22 m above the ground. At point B, it is 8 m above the ground. [Express your answers in kilojoules (kJ).]
If the initial kinetic energy was zero and the work done against friction between the starting point and point B is 30,000 J (30 kJ), what is the kinetic energy of the car at point B?
Answer: 317.52
Explanation:
I'm just better
What is the gravitational force acting on a 83.4-kg person due to a 65.6-kg person standing 1.21 m away?
The gravitational force acting on the 83.4-kg person due to the 65.6-kg person is approximately 3.14 x 10^-8 N.
What is gravitational force ?The gravitational force is an attraction between any two mass-containing objects.
The following formula determines the gravitational force between two objects:
F = G * (m1 * m2) / r2.
where
F represents forceG stands for gravity constantThe two objects' masses are m1 and m2 r is the separation between their centers of massPlugging in the given values, we have:
F = (6.67 x 10^-11 N * m^2 / kg^2) * (83.4 kg) * (65.6 kg) / (1.21 m)^2
F = 3.14 x 10^-8 N
Therefore, the gravitational force acting on the 83.4-kg person due to the 65.6-kg person is approximately 3.14 x 10^-8 N.
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Two moles of helium gas initially at 170 K
and 0.23 atm are compressed isothermally to
1.78 atm.
1): Find the final volume of the gas. Assume
that helium behaves as an ideal gas. The
universal gas constant is 8.31451 J/K · mol.
Answer in units of m3
2): Find the work done by the gas.
Answer in units of kJ.
3): Find the thermal energy transferred.
Answer in units of kJ.
The final volume of the gas is 9.16 × 10⁻³ m³, the work done by the gas is -0.0147 kJ, and the thermal energy transferred is 0.0147 kJ.
We can use the following equations to solve this problem:
Boyle's Law: PV = constant at constant temperature (isothermally)
Work done by a gas: W = -P∆V
Thermal energy transferred: Q = -W (assuming no heat transfer between the gas and its surroundings)
1. Given:
n = 2 mol (number of moles of helium gas)
T = 170 K (initial temperature)
P1 = 0.23 atm (initial pressure)
P2 = 1.78 atm (final pressure)
R = 8.31451 J/K·mol (universal gas constant)
Using Boyle's Law, we can write:
P1V1 = P2V2
V2 = (P1V1) / P2
V1 = (nRT) / P1 (using PV = nRT)
Substituting the given values:
V2 = (0.23 mol/m3 × 2 mol × 8.31451 J/K·mol × 170 K) / 1.78 atm
V2 ≈ 9.16 × 10⁻³ m³
Therefore, the final volume of the gas is approximately 9.16 × 10⁻³ m³.
2. The work done by the gas can be calculated using the equation:
W = -P∆V
Substituting the given values:
W = -(1.78 atm - 0.23 atm) × (9.16 × 10⁻³ m³)
W ≈ -0.0147 kJ
Therefore, the work done by the gas is approximately -0.0147 kJ.
3. The thermal energy transferred can be calculated using the equation:
Q = -W
Substituting the value of W obtained in part 2:
Q = -(-0.0147 kJ)
Q ≈ 0.0147 kJ
So, the thermal energy transferred is approximately 0.0147 kJ.
Hence, The gas has a final volume of 9.16 × 10⁻³ m³, does work of -0.0147 kJ, and transfers thermal energy of 0.0147 kJ.
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Victoria ran around a circular field 3 times. If she ran a total
distance of 750 meters, what are the diameter and radius of
the field?
The diameter of the field is 79.62 m and the radius is 39.81 m.
What is diameter?A diameter of a circle is any straight line segment that passes through the center of the circle and whose endpoints lie on the circle.
To calculate the diameter and the radius of the field, we use the formula below.
Formula:
P = nπD..........................Equation 1Where:
P = Total distance covered by the girlD = Diameter of the fieldn = Number of times she ran through the fieldπ = PieFrom the question,
Given:
n = 3P = 750 meterπ = 3.14Substitute these values into equation 1 and solve for D
750 = 3×3.14×DD = 750/(3×3.14)D = 79.62 mThe radius of the field = D/2 = 79.62/2 = 39.81 m.
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In a 'keep-fit' exercise, a student of mass 45 kg steps 40 times on and off a box of height 0.50 m. How much work does the student do to raise her body each time she steps on the box
Answer:Calculate the work done using:
work done (in joules) = force (in newtons) x distance moved (in metres)
To practice calculations involving force, distance and work done.
Explanation: I hope this helps srry if I'm wrong
1. In order to generate a current from a magnet, which of the following would generate a current?
a. Spinning a magnet near a wire
b. Placing the north end of a magnet near a wire
c. Place the south end of a magnet near a wire
2. In order for a circuit to function, which of the following must be true?
a. The circuit cannot have more than 3 bulbs attached
b. The circuit must have an switch placed in the circuit in the open position
c. The circuit must make a complete loop and must have all parts connected to that loop
Spinning a magnet near a wire would generate a current.
The circuit must make a complete loop and must have all parts connected to that loop.
What is the spinning magnet?When a magnet approaches a conductor, such as a wire, the magnetic field changes, causing the wire to conduct electricity. Electromagnetic induction is a process that underlies the operation of electric motors and generators.
Electromagnetic induction and is the basis for how generators and electric motors work and it explains the fact that current is generated by a spinning a magnet near a wire.
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Question 2 of 10
X-ray technology can be used to do which of the following?
O A. Photograph through solid objects
B. Monitor human activity at night
OC. Speed up the process of hardening paint
O D. Communicate across long distances
SUBMIT
X-ray technology can be used to do Photograph through solid objects. option A
What is X-ray technology about?X-ray technology includes the utilize of high-energy electromagnetic radiation to make pictures of the interior of objects, counting the human body. X-rays are a sort of electromagnetic radiation with wavelengths shorter than unmistakable light, but longer than gamma beams.
X-ray innovations includes the use of high-energy electromagnetic radiation to make pictures of the interior of objects, counting the human body. X-rays are a sort of electromagnetic radiation with wavelengths shorter than visible light, but longer than gamma beams.
Lastly, X-ray innovation is utilized in a assortment of other applications, such as air terminal security scanners, which utilize X-rays to form pictures of gear and other objects to distinguish potential dangers.
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In a non-uniform electric field, an electric dipole experiences ___ .
In a non-uniform electric field, an electric dipole experiences both a torque and a net force.
What more should you know about a non-uniform electric field?In a non-uniform electric field, the electric field lines are not parallel nor are they evenly spaced out. What this translates to is different parts of an electric dipole experience uneven magnitudes and directions of the electric field.
An electric dipole is a pair of opposite charges separated by a distance, which creates a dipole moment.
When there is a non-uniform electric field, the charges in the dipole have different forces in opposite directions.
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Which description accurately describes the tide represented by the image below? (4 points)
Image of the sun and moon at a 90 degree angle to Earth. An oval is around Earth that points toward and away from the moon to show the tidal bulges.
High tides occur when the sun and moon are at right angles to one another.
Low tides occur when the sun and moon are at right angles to one another.
The gravitational pull of the sun and moon combined creates larger than normal tides.
The gravitational pull of the sun reduces the moon's gravitational pull to create moderate tides.
High tides occur when the sun and moon are at right angles to one another. This is because the gravitational pull of the moon and the sun combine to create larger-than-normal tides, known as spring tides. The correct option is A.
Gravitational pull is the force of attraction that exists between two objects with mass. The greater the mass of an object, the greater its gravitational pull.
Option B, "Low tides occur when the sun and moon are at right angles to one another," is incorrect. Low tides occur when the sun and moon are at a 90-degree angle (or "quarter moon") to each other, but this position also results in high tides on the opposite side of the Earth.
Option C, "The gravitational pull of the sun and moon combined creates larger than normal tides," is partially correct. The gravitational pull of both the sun and moon does contribute to the tides, but the specific position depicted in the image (sun and moon at right angles to each other) does not necessarily create larger than normal tides.
Option D, "The gravitational pull of the sun reduces the moon's gravitational pull to create moderate tides," is also incorrect. The sun's gravitational pull does have an effect on the tides, but it does not reduce the moon's gravitational pull. Rather, the combined gravitational pull of the sun and moon creates the tides we observe.
Therefore,The accurate description of the tide represented by the image below is option A: "High tides occur when the sun and moon are at right angles to one another."
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A strip of lead metal initially with a length of 35cm is heated so that its temperature changes by 80°c. Find the change in length of the lead and its new length at the new temperature.
Answer:
The new length at the new temperature is approximately 35.0812cm.
Explanation:
Let's use the coefficient of linear expansion of lead, which is approximately 0.000029 per degree Celsius.
The change in length can be calculated using the formula:
ΔL = αLΔT
where:
ΔL = change in length
α = coefficient of linear expansion
L = initial length
ΔT = change in temperature
In this case, ΔT = 80°C, L = 35cm and α = 0.000029/°C.
ΔL = (0.000029/°C) x (35cm) x (80°C)
ΔL = 0.0812 cm
Therefore, the change in length is 0.0812 cm.
To find the new length, we add the change in length to the original length:
New length = 35cm + 0.0812cm
New length = 35.0812cm
So
Do you think Kepler will be able to detect Earth-sized planets in transit?
Answer: Less than 1% of the stars that Kepler will be looking at are closer than 600 light years. Stars farther than 3,000 light years are too faint for Kepler to observe the transits needed to detect Earth-size planets.
Explanation:
The period of a wave is 25 seconds. What is the webs frequency in Hz
Answer:
0.04 Hz
Explanation:
The formula for calculating frequency is f = 1/T, and T = the period of the wave. If the wave period is 25 seconds then the formula would be f = 1/25. 1/25 =0.04
Help! Offering Brainliest & Points!
Match Letter's with image.
The correct match is A - trough, B - amplitude, C - crest, and D - wavelength.
A - A trough is the lowest point on a wave, where the displacement of the medium or the amplitude of the wave is at its minimum.
B - Amplitude refers to the maximum displacement or distance moved by a point on a vibrating body or wave, from its equilibrium position.
C - A crest is the highest point on a wave, where the displacement of the medium or the amplitude of the wave is at its maximum.
D - Wavelength is the distance between two corresponding points on a wave, such as the distance between two consecutive crests or troughs. It is often measured in meters or other units of length.
Hence, A - trough, B - amplitude, C - crest, and D - wavelength.
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The femur of a human leg (mass 10 kg,
length 0.9 m
) is in traction, as shown in the figure. The center of gravity of the leg is one-third of the distance from the pelvis to the bottom of the foot. Two objects, with masses 1
and 2,
are hung at the ends of the leg using pulleys to provide upward support. A third object of 8 kg
is hung to provide tension along the leg. The body provides tension as well.
Write a mathematical relationship relating 1
to 2
in terms of 2
and numerical coefficients.
The mathematical relationship between m₁ and m₂ is that m₁ is twice the value of m₂.
Length of the femur, L = 0.9 m
Mass of the femur, M = 10 kg
Centre of gravity = L/3
m₁ + m₂ = M
T₁ + T₂ = Mg
m₁g + m₂g = Mg
T₁ + T₂ = m₁g + m₂g
T₁(L/3) = T₂(2L/3)
m₁g(L/3) = 2m₂mg(L/3)
Therefore,
m₁ = 2m₂
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If light goes through a single slit, what will be the pattern that will appear on the target screen?
a. A large bright band will appear directly across from the slit, that gets dimmer farther away from the center
b. Two large bright bands will appear on the target screen, with less bright bands in between them
c. Two large bright bands appear very distant from each other on the target with nothing but dark bands in between them
If the light goes through a single slit, the pattern that will appear on the target screen is: "A large bright band will appear directly across from the slit, that gets dimmer farther away from the center." The correct option is option A.
When light passes through a single slit, it diffracts and spreads out. This means that the light waves bend and interfere with each other as they pass through the slit, creating a pattern of bright and dark fringes on a screen behind the slit.
The central fringe is bright, with the maximum intensity of the light, and is surrounded by smaller and dimmer fringes on either side. These fringes are the result of constructive and destructive interference between the light waves passing through the slit.
The width of the slit plays an important role in determining the pattern of the fringes. If the slit is narrow, the diffraction of light will be more pronounced, resulting in a wider central fringe and smaller, more numerous side fringes. If the slit is wider, the central fringe will be narrower and the side fringes will be wider.
The distance between the slit and the screen also affects the pattern of the fringes. The closer the screen is to the slit, the wider the fringes will be, and the farther away the screen is from the slit, the narrower the fringes will be.
The diffraction of light through a single slit is an important phenomenon in physics and is used in various applications such as optical spectroscopy and the study of crystal structures.
Option B, "Two large bright bands will appear on the target screen, with less bright bands in between them," is incorrect. This pattern is actually the interference pattern that occurs when light passes through two parallel slits. When light passes through a single slit, the pattern is a central bright band with smaller, dimmer bands on either side.
Option C, "Two large bright bands appear very distant from each other on the target with nothing but dark bands in between them," is also incorrect. This pattern is the interference pattern that occurs when light passes through multiple slits, such as in a diffraction grating. When light passes through a single slit, the pattern is a central bright band with smaller, dimmer bands on either side.
Therefore, The correct answer is option A.
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13. A solid has a mass of 200 g in air and when partly immersed in a certain liquid it has a mass of 160 g. Given that the relative density of the liquid is 0.80, calculate the volume of the solid immersed in the liquid.
The volume of the solid immersed in the liquid is 5 x 10⁻⁵ m³.
What is the volume of the solid?The volume of the solid is calculated as follows;
V = (Ws - Wa) / (ρg)
where;
Ws is the weight of the solid in airWa is the weight of the solid in liquidρ is the density of the solidg is gravityWs = 0.2 kg x 9.8 m/s²
Ws = 1.96 N
Wa = 0.16 kg x 9.8 m/s²
Wa = 1.568 N
ρ = 0.8 x 1000 g/km³ = 800 kg/m³
The volume is calculated as;
V = (1.96 - 1.568 )/(800 x 9.8)
V = 5 x 10⁻⁵ m³
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Joey rolls several objects down a grassy hill. Which force is acting on the objects which cause the objects to slow down?
A. Friction
B. Normal
C. Applied
D Magnetic
friction
Friction is what causes moving objects to slow down and eventually stop.
A racing car has a mass of 1530 kg. What is its kinetic energy if it has a speed of 120 km/h? Assume that air resistance is negligible.
The kinetic energy of the racing car is approximately 849952.4 J joules.
What is its kinetic energy of the car?Kinetic energy is simply a form of energy a particle or object possesses due to its motion.
It is expressed as;
K = (1/2)mv²
Where m is mass of the object and v is its velocity.
Convert the speed from kilometers per hour to meters per second since the units of mass and velocity need to be consistent.
We know that 1 km/h = 0.27777 m/s, so:
120 km/h x (0.27777 m/s/km/h) = 33.3336 m/s (rounded to 4 decimal places)
Now we can substitute the values into the formula:
Kinetic Energy = (1/2) × 1530 kg x (33.3336 m/s)²
Kinetic Energy = 849952.4 J
Therefore, the kinetic energy is approximately 849952.4 joules.
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A bowling ball 0.005 kg moves at 100m/s. How much kinetic energy does the bowling ball have?
The kinetic energy of the bowling ball is 25 J (joules).
What is the kinetic energy of the bowling ball?
Kinetic energy is simply a form of energy a particle or object possesses due to its motion.
It is expressed as;
K = (1/2)mv²
Where m is mass of the object and v is its velocity.
Given that the mass of the bowling ball is 0.005 kg and its velocity is 100 m/s.
We can use the formula to calculate its kinetic energy:
K = (1/2)mv²
KE = (1/2) × 0.005kg × (100m/s)²
KE = (1/2) × 0.005kg × 10000 m²/s²
KE = 25 J
Therefore, the kinetic energy is 25 joules.
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why does liquid candle wax flow but solid candle wax does not?
Answer:
Because the matter in solid objects doesn't move
Explanation:
Logic
A satellite with a mass of 120kg fires its rocket thrusters, which give an impulse of 7440kg•m/s . What was the total change in the velocity of the satellite- that is, what was the total v
1. Which of the following makes Light waves unique compared to sound waves?
a. Light travels can move without a medium, unlike sound
b. Light's velocity is calculated with frequency and wavelength, unlike sound
c. Light can carry energy, unlike sound
d. Light's frequency can be altered, unlike sound
2. If a incident light ray approachs a mirror at an angle of 37 degrees from the perpendicular. What will be the angle of the reflected ray?
a. 18.5 degrees
b. 37 degrees
c. 53 degrees
d. 143 degrees
3. If light goes through a single slit, what will be the pattern that will appear on the target screen?
a. An alternating set of bright and dark bands of light will appear on the target screen
b. A large bright band will appear directly across from the slit, that gets dimmer farther away from the center
c. Two large bright bands will appear on the target screen, with less bright bands in between them
d. Two large bright bands appear very distant from each other on the target with nothing but dark bands in between them