a rock with mass of 5kg is carried up a small hill 10 meters high. how much work had to be done in carrying the rock up hill

Answer:

V is greater

Explanation:

because v intial at that time V final is the that speed which it is going at that time

Answer:

yes, the density of ice is less than the density of water. Ice floats on water.

Explanation:

Answer:Adolescent chastity can be defined as the absolute abstinence from sex and anything related to sex, such as, kissing, touching, fondling

Explanation:

Answer:

Explanation:

a) From the diagram, the load will be expressed in newton. The load will be the weight of the box on the inclined plane.

Load = mass * acceleration due to gravity.

Given the mass of the object = 100kg

acceleration due to gravity = 9.8m/s²

Load (in Newton) = 100*9.8

Load (in Newton) = 980N

b) The formula for calculating the velocity ratio of an inclined plane is expressed as VR = 1/sinθ where θ is the angle of inclination.

Given θ = 30°,

VR = 1/sin30°

VR = 1/0.5

VR = 1/(1/2)

VR = 1* 2/1

VR = 2

The velocity ratio is 2.

c) Length of the inclined plane can be calculated using the SOH, CAH, TOA trigonometry identity.

According to SOH, sinθ = opposite/hypotenuse

sin30°  = 1/2 = opp/hyp

This shows that the opposite side of the triangle is 1 and the hypotenuse is 2. The length if the inclined is the length of the longest side i.e the hypotenuse. Hence the length of the inclined plane is 2m

d) Mechanical Advantage is the ratio of the load to the effort applied on an object.

Given the Load = 980N and the effort applied to the load on the incline plane = 400N

MA = Load/Effort

MA = 980/400

MA = 2.45

e) Efficiency = MA/VR * 100

Efficiency = 2.45/2 * 100

Efficiency  = 122.5%

Explanation:

Given that,

Initial speed of the bus, u = 0

Acceleration of the bus, a = 0.5 m/s²

Let v is the velocity at the end of 2 minutes. The change in velocity divided by time equals acceleration.

So,

[tex]a=\dfrac{v-u}{t}\\\\v=u+at\\\\v=0+0.5\times 120\\\\v=60\ m/s[/tex]

Let d is the distance cover during that time. So,

[tex]v^2-u^2=2ad\\\\d=\dfrac{v^2-u^2}{2a}\\\\d=\dfrac{(60)^2}{2\times 0.5}\\\\d=3600\ m[/tex]

So, the final speed is 60 m/s and the distance covered during that time is 3600 m.

Answer:

If the force applied on the object is in the direction of its motion, the speed of the object increases. If the force is applied in the direction opposite to the direction of motion, then it results in a decrease in the speed of the object.

Explanation:

We need to find the quantum state of a particle can be specified by giving a complete set of quantum numbers (n,l, ml,ms).

We have the principal quantum number, n = 3

The value of l = n-1

l = 0,1,2,3

The value of [tex]m_l[/tex]

[tex]m_l=-l\ \text{to}\ +l\\\\m_l=-3,-2,-1,0,1,2,3[/tex]

The value of [tex]m_s[/tex]

[tex]m_s=\dfrac{-1}{2},\dfrac{+1}{2}[/tex]

Hence, this is the required solution.

Answer:

Stroke has two emissions it could either be the meaning of lightly passing over something with the sense of touch for example stroking a dog/cat

And the medical term stroke where either a person has lost facial features of can't lift their arms up and keep them up or speak properly and their speech would be slurred

Hope this helps

If anything didn't meet your question please comment what you are looking for and I may change my answer thank you :)

Explanation:

Answer:

A: 15 m/s

B: 900 Meters

Explanation:

A. Average speed is equal to final velocity plus initial velocity divided by two

Va= (20+10)/2 = 15 m/s

B.

distance = speed × time

D= 15 m/s * 60s = 900 Meters

Answer:

Answer is in the attachment.

Explanation:

Hope this helps.

Please mark me as Brainliest.

[tex] \large{ \underline{ \underline{ \bf{ \purple{Given}}}}}[/tex]

[tex] \large{ \underline{ \underline{ \bf{ \green{To \: find}}}}}[/tex]

[tex] \large{ \underline{ \underline{ \red{ \bf{Now, \: What \: to \: do?}}}}}[/tex]

We can solve the above question using the three equations of motion which are:-

So, Here a is acceleration of the body, u is the initial velocity, v is the final velocity, t is the time taken and s is the displacement of the body.

[tex] \large{ \bf{ \underline{ \underline{ \orange{Solution:}}}}}[/tex]

We are provided with,

By using 1st equation of motion,

⇛ v = u + at

⇛ v = 250 + (-3)45

⇛ v = 250 - 135 m/s

⇛ v = 115 m/s

✤ Final velocity of mobile = 115 m/s

━━━━━━━━━━━━━━━━━━━━

The frequency of the wave for the stone thrown in the pond is 0.5Hertz.

The question does not specify what to calculate but we can look for the frequency of the wave.

Frequency is the number of oscillations completed in one second. This is interpreted as:

x oscillations = 1second

If Five waves were made from the same source in 10 seconds for a stone that is thrown inside the pond, then:

5 oscillations = 10seconds

Divide both expressions to get x (the required frequency)

x/5 =1/10

Cross multiply

10x = 5

Divide both sides by 10

10x/10 = 5/10

x = 1/2

x = 0.5Hertz

Hence the frequency of the wave is 0.5Hertz.

NB: The period of the wave is simply the reciprocal of the frequency.

Learn more here: https://brainly.com/question/13728731

The answer is:

-5846.75

Answer:

OK well

Explanation:

where's the question bring it first

Answer:

ExplanationjakkJXJAKGKXAHLKHQHL:

Answer:

Don't Forget To Follow, Brainliest, And Give Me Heart :)

The change in the frequency of the sound, due to the relative motion of the source of sound and the observer, is determined by the Doppler's Effect.

The speed of the ambulance (source) is "6517 m/s"

The equation of Doppler's Effect is given as follows:

[tex]f_o = \frac{v+v_o}{v+v_s}f_s[/tex]

where,

[tex]f_o\\[/tex] = frequency of sound measure by observer  = 100 Hz

v = speed of sound = 343 m/s

[tex]v_o[/tex] = speed of observer = 0 m/s

[tex]v_s[/tex] = speed of ambulance (source) = ?

[tex]f_s[/tex] = actual frequency = 2000 Hz

Therefore, using the values, we get:

[tex]100\ Hz = \frac{343\ m/s + 0\ m/s}{343\ m/s + v_s}(2000\ Hz)\\\\(100\ Hz)(343\ m/s + v_s) = (343\ m/s)(2000\ Hz)\\\\v_s = \frac{686000\ Hz.m/s - 34300\ Hz.m/s}{100\ Hz}[/tex]

v_s = 6517 m/s

Learn more about Doppler's Effect here:

https://brainly.com/question/1330077?referrer=searchResults

Answer:

C. Meter

Explanation:

The International System of Unit (SI) is gotten from the french word Systeme international is a modern form of metric measurement. It is the system of measurement that is universally accepted. It is from this SI units that all other system of units are derived. There are seven basic SI units which are:

1) Length in Meter (m)

2) Time in Seconds (s)

3) Amount of Substance in mole (m)

4) Electric current in ampere (A)

5) Temperature in kelvin (k)

6) Luminous intensity in candela (cd)

7) Mass in kilogram (kg)

Answer:

Lò xo (từ tiếng Pháp: ressort) là các vật thể đàn hồi được sử dụng trong các hệ thống cơ học. Lò xo được phân thành hai loại:

biến dạng theo ý muốn

có lực đàn hồi theo ý muốn

lực kế, cân trọng lượng... trong khoa đo lường.

giảm xóc xe cộ

phát âm (chuông, loa phóng thanh...)

lưu trữ năng lượng (dây cót đồng hồ)

công tắc điện.

bám giữ vật (kẹp quần áo)

bút bi.

The hydro power plant consists of a (artificial) dam that builds gravitational potential energy, P.E. from natural flowing water sources, by locating the dam along the water path. The stored potential energy, P. is converted into kinetic energy, K.E. as the water falls from the dam, down to the turbines, located at a much lower level according to the following principle of conservation of energy equation;

Total Mechanical Energy, M.E. = The potential energy of the water, P.E. + The kinetic energy of the water, K.E. = Constant

M.E. = P.E. + K.E. = Constant

Where;

P.E. = m·g·h

K.E. = (1/2)·m·v²

m = Mass

g = The acceleration due to gravity

h = The height of the dam

v = The velocity

The charts can be explained as follows;

Given that the potential energy P.E. = m·g·h, we have that the potential energy is directly proportional to the height of the dam, and therefore, at mid height, the potential energy would be half the maximum value, and we have;

At mid height, P.E. = (1/2)·[tex]\mathbf{P.E._{max}}[/tex]

At the top of the dam, the (vertical) velocity of the water = 0, therefore, the kinetic energy = 0

Therefore, at the top of the dam, we get;

M.E. = [tex]P.E._{max}[/tex] + 0 =

M.E. = [tex]\mathbf{P.E._{max}}[/tex]

Similarly, at the bottom of the dam, the height, h = 0, therefore, being proportional to the height, P.E. = 0, and the velocity is maximum, and at the bottom, we have;

M.E. = 0 + [tex]K.E._{max}[/tex]

The first chart, water is halfway down the dam

At the halfway down therefore, we have;

P.E. = (1/2)·[tex]\mathbf{P.E._{max}}[/tex]

M.E. = [tex]P.E._{max}[/tex] = (1/2)·

∴ K.E. = [tex]P.E._{max}[/tex] - (1/2)·

Therefore the first chart, water is halfway down the dam;

Halfway, K.E. = (1/2)·[tex]\mathbf{P.E._{max}}[/tex] = P.E.

∴ K.E. = P.E.  as shown on the chart

The second chart, water has reached the turbine

Water reaches the turbine at the bottom, and as explained above, we get;

M.E. = 0 + [tex]K.E._{max}[/tex]

∴ M.E.≈ [tex]K.E._{max}[/tex]

Therefore, when water has reached the turbine at the bottom of the dam, the kinetic energy is approximately proportional to the total mechanical energy as shown in the chart

The third chart, water is at the top of the dam

Here as shown above, we have;

The total mechanical energy, M.E. ≈ [tex]\mathbf{P.E._{max}}[/tex] as shown on the chart

Learn more about potential and kinetic energy here;

https://brainly.com/question/18683052

Answer:1860g

Explanation:The force would have to be greater than 1580g, which is when the student is pulling the sliding book with the spring scale

Answer:

The answer is either 47 or 23. Most likely 47

Answer:

1.  to relate the type of box material to the temperature of the air within the box

2. Question is incomplete

3. scatterplot

Explanation:

1. The only thing done differently in this experiment is the type of material used in making the boxes, hence the experiment must be about that. Before proceeding to answering this question, we must have this at the back of our minds.

We can gather from the experiment that the boxes are of the same size and were subjected to sunlight for an hour (the same time duration for both). Hence, the temperature of the air inside the box will only be affected by the type of material the box is made of since the boxes have the same size and were subjected to sunlight for the same duration.

From the options provided, the best description for this experiment is; to relate the type of box material to the temperature of the air within the box.

2. The question is incomplete. The value for speed/velocity needed to calculate the average time is missing.

However, the formula needed here is velocity = distance ÷ time

3. There are two variables in this experiment; distance and time

The type of graph that shows two variables on it (of the options provided) is the scatterplot.

Answer:

This type of a behavior is known as oscillation, a periodic movement between two points. ... Amplitude: The distance from the center of motion to either extreme. Period: The amount of time it takes for one complete cycle of motion.

Explanation:

Amplitude (a):- The maximum displacement of particle from its mean position on either side is called amplitude.  

Periodic time:- The time taken by a wave to complete one oscillation is called periodic time.

Now

[tex]\\ \sf\longmapsto 20cm[/tex]

[tex]\\ \sf\longmapsto 2\times 10^{-1}[/tex]

[tex]\\ \sf\longmapsto 0.1m[/tex]

Answer: Helium=4 is the answer

Explanation:

took the test and got it right that'

s the answer.

Answer:

It's b

Explanation:

I took the quiz on EDGE and got it right.

Explanation:

Water does expand with heat (and contract with cooling), but the amount of expansion is pretty small. So when you boil a can filled with water and seal it, the water will contract slightly as it cools. The can may kink slightly, but that will be it. Actually, most likely the only things you will be able to see is then top and bottom will be sucked in and go concave. Just like a commercial can of beans.

Now if you have a can with a little water and a big air space, things are completely different.

As the water boils, water vapour is given off. Steam. Let it boils for a minute just to make sure (nearly) all the air is expelled and the can is filled with steam.

Now when you put the lid on and cool the can, that steam condenses back to water, and goes from filling the can to a few drops of water. The can is now filled (if that is the right word) with a near vacuum, The air pressure, 15 lbs/square inch, will be pressing on every surface of the can, with nothing inside the can to resist it.

The can will crumple before your eyes.

Answer:

Normal force

Explanation:

Calculating :-

We know

[tex]\boxed{\sf F_c=\dfrac{mv^2}{r}}[/tex]

[tex]\\ \sf\longmapsto F_c=\dfrac{20(10)^2}{4}[/tex]

[tex]\\ \sf\longmapsto F_c=\dfrac{20(100)}{4}[/tex]

[tex]\\ \sf\longmapsto F_c=\dfrac{2000}{4}[/tex]

[tex]\\ \sf\longmapsto F_c=500N[/tex]

Answer:

Those units which are independent of each other are called fundamental unite. there are seven fundamental unite of seven fundamental quantities

Answer:

maximum  point  y= 2R

 vₓ = wR ,  v_{y} = 0, aₓ = 0,  a{y} = - Rw²

minimum point   y=R

vₓ = wR , v_{y} = - R w,  aₓ = - R w²,  a_{y} = 0

Explanation:

The definition of velocity is

        v = dr / dt

        vₓ = dx / dt

        [tex]v_{y}[/tex] = dy / dt

        vₓ = Rw cos wt + wR

        v_{y} = -Rw sin wt

acceleration is defined by

         a = dv / dt

         aₓ = -Rw² sin wt

         a_{y} = - R w² cos wt

these are the general expressions for velocity and acceleration, to find the explicit values ​​for the maximum and minimum y points, let's find these points and substitute

maximum  point

         y = R cos wt + R

the heat is maximum when the cosine is worth 1

         y_max = 2R

at this point the speed is

         vₓ = wR

         v_{y} = 0

the acceleration is

         aₓ = 0

         a_{y} = - Rw²

minimum point

        this occurs when the cosine is zero

        y = R

speed is

       vₓ = wR

       v_{y} = - R w

acceleration is

        aₓ = - R w²

        a_{y} = 0