A rock is thrown straight up with an initial speed of 22 m/s. How long will it be in the air before it returns to the thrower?

Answers

Answer 1

Answer:

The time spent in air by the rock before it returns to the thrower is 4.5 s

Explanation:

Given;

initial velocity of the rock, u = 22 m/s

Neglecting air resistance, the time it takes the rock to go up equals the time it takes it to return to the thrower. This is also called time of flight.

The time to go up is calculated as;

v = u - gt

where;

v is the final velocity at the maximum height

0 = u - gt

gt = u

t = u / g

t = 22 / 9.8

t = 2.245 s

thus time to go up = 2.245 s

and time to return to the thrower = 2.245s

The total time spent in air by the rock before it returns to the thrower

 = 2.245 s + 2.245s

 = 4.5 s


Related Questions

1. You are hired to lift 25 kg crates a vertically 1.0 m from the ground onto a truck. How many crates would you have to load onto the truck in 1 minute for your average power output in lifting the crates to be 110 W

Answers

Answer:

The number of crate to be lifted is 27

Explanation:

Given;

mass of the crates, m = 25 kg

height in which the crate is lifted, h = 1.0 m

power output, P = 110 W

time to complete the task, t = 1 minutes = 60 s

The input energy is equal to the gravitational energy due to height the crate is lifted is given as;

E(input) = mgh

E(input)  = 25 x 9.8 x 1

E(input)  = 245 J

Output energy is given as;

E(output) = P x t

E(output) = 110 x 60

E(output) = 6600 J

Let the number of crate to be lifted = n

n x E(input)  = E(output)

n x 245 = 6600

n = 6600 / 245

n = 27 crates

A woman walks 5 meters due east in 12 seconds and then back 2 meters in 7 seconds due west. Determine the person’s velocities for the 5 meters, the 2 meters and the person’s average velocity for the whole walk.

Answers

Answer:

Due east - 0.42mps

Due west - 0.29mps

Explanation:

So for the 5 meters 12s

and 2 meters 7s

for the first one we will do 12/5 = 2.4

for the second one 7/2 = 3.5

that is the amount of seconds per meter but we want meters per seconds so

5/12 = 0.42mps

2/7 = 0.29mps

Is electricity matter?

EXPLAIN.

Answers

Answer:

Yes it is matter

Explanation:

In physics, usually the word "electricity" isn't really used. "Electric current" is more common, and is defined as the flow of charges, where the charges are held by particles (electrons). Electrons have mass, so they are definitely matter.

What is the purpose of a resistor

Answers

Answer:

So we can have energy  for electronics. It limits the flow of electric current

Explanation:

It’s in the answer!

Answer:

Basically, the function of a resistor is always to oppose the flow of current through it and the strength of this opposition is termed as its resistance.

What causes the magnetic field around the wire?
Magnetic field
O A. An electric current
O B. An electric field
PREVIOUS

Answers

An electric current causes the magnetic field around the wire. The correct answer is A.

The magnetic field around a wire is caused by the flow of electric current through the wire. When an electric current passes through a wire, it generates a magnetic field that forms circular lines of magnetic flux around the wire. This phenomenon is described by Ampere's law, which states that a magnetic field is produced by an electric current and its strength is directly proportional to the magnitude of the current.

The relationship between the electric current and the magnetic field can be understood using the right-hand rule. If you wrap your right hand around the wire with your thumb pointing in the direction of the current, the curled fingers indicate the direction of the magnetic field lines.

Therefore, an electric field is generated by an electric charge, not by an electric current. While an electric field can exist around a wire if there is a potential difference (voltage) applied across it, it is the flow of electric current that primarily generates the magnetic field.

To learn more about the electric field click:

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A ball is thrown horizontally at a height of 1.5 meters at a velocity of 70 m/s. Assume no air resistance. How long until the ball reaches the ground?
0.25 s
0.38 s
0.55 s
0.67 s

Answers

Answer:

[tex]t = 0.55[/tex]

Explanation:

Given

[tex]Height, s = 1.5m[/tex]

[tex]Velocity, v = 70m/s[/tex]

Required

Determine the time to hit the ground

Using free fall formula:

[tex]S = \frac{1}{2}gt^2[/tex]

Take g as 9.8 and substitute value for S

[tex]1.5 = \frac{1}{2} * 9.8 * t^2[/tex]

[tex]1.5 = 4.9 * t^2[/tex]

Make t^2 the subject

[tex]t^2 = \frac{1.5}{4.9}[/tex]

[tex]t^2 = 0.30612244898[/tex]

Solve for t

[tex]t = \sqrt{0.30612244898[/tex]

[tex]t = 0.55[/tex] -- approximated

Which one of the following statements contain a simile?

Answers

do u have the statements ?

Answer:

I don't know if its just me, but I don't see the statements so I'm not sure how to help answer your question.

Two wave pulses pass each other on a string. The pulse traveling toward the right has positive amplitude, whereas the pulse traveling toward the left has equal amplitude in the negative direction. What happens when they occupy the same region of space at the same time?
a. constructive interference occurs
b. destructive interference occurs.
c. a standing wave is produced.
d. a traveling wave is produced.
e. a wave pulse is produced.

Answers

Answer:

destructive interference occurs

If earth squeezed to the size of moon.Calculate the weight of 100kg mass in the squeezed earth.​

Answers

Answer:

833.9kg that's the answer

what are the different intensity of an earthquake

Answers

Ranking Earthquake Intensity

Magnitude Average number per year Modified Mercalli Intensity

2.0 – 2.9 >1 million I

3.0 – 3.9 about 100,000 II – III

4.0 – 4.9 about 10,000 IV – V

5.0 – 5.9 about 1,000 VI – VII

Explanation:

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a 16-slug mass is raised by 10 ft. the PE of the mass increased by?

Answers

Answer:

The PE of the mass increased by 6,972.95 J

Explanation:

Gravitational Potential Energy

It's the energy stored in an object because of its vertical position or height in a gravitational field.

It can be calculated with the equation:

U=m.g.h

Where m is the mass of the object, h is the height with respect to a fixed reference, and g is the acceleration of gravity or 9.8 m/s^2.

We are given the mass of m=16 slug raised by a height h=10 ft. Both units will be converted to SI standard:

1 slug = 14.59 Kg, thus

16 slug = 16*14.59 Kg=233.44 Kg

1 ft = 0.3048 m, thus:

10 ft = 10*0.3048 m = 3.048 m

Thus, the PE of the mass increased by:

U = 233.44 * 9.8 * 3.048 = 6,972.95 J

the PE of the mass increased by 6,972.95 J

The potential energy will be "5120 ft.lb".

According to the question,

Mass,

m = 16 slugs

Height,

h = 10 ft

As we know the formula,

→ [tex]U = mgh[/tex]

By substituting the values, we get

→     [tex]= 16\times 32\times 10[/tex]

→     [tex]= 5120 \ ft.lb[/tex]

Thus the response above is correct.

Learn more:

https://brainly.com/question/13347447

What is the period of an object that makes 6 revolutions a minute?

Answers

Answer:

T = 10 s

Explanation:

First, we need to find the frequency of the object as follows:

[tex]Frequency = f = \frac{Speed\ in\ rpm}{60}[/tex]

where,

Speed = Angular Speed = 6 rpm

Therefore,

[tex]f = \frac{6\ rpm}{60}\\\\f = 0.1\ Hz[/tex]

Now, for time period (T):

[tex]Time\ Period = T = \frac{1}{f}\\\\T = \frac{1}{0.1\ Hz}\\\\[/tex]

T = 10 s

HELP right awayyy !!!

Answers

Answer:

Question 4 is actually Acceleration

4 is actually acceleration

An object 2.7 cmtall is placed12 cmin front of a mirror. •What type of mirror and what radius of curvature are needed to createan upright image that is 5.4 cm in height? •What is the magnification of the image?

Answers

Answer:

a. Concave mirror, radius of curvature = 16 cm b. magnification = 2

Explanation:

a. Since the image is upright and larger than the object, we need a concave mirror.

We know image height, h'/object height, h = -image distance, d'/object distance, d

h'/h = -d'/d

Using the real is positive convention,

h'= + 5.4 cm, h = + 2.7 cm and d = + 12 cm.

So, + 5.4 cm/+ 2.7 cm = -d'/+ 12 cm

2 = -d'/12

d' = -2 × 12 cm

= -24 cm

Using the mirror formula 1/d + 1/d' = 2/r where r = radius of curvature of the mirror

1/+12 + 1/- 24 = 2/r

1/12(1 - 1/2) = 2/r

1/12(1/2) = 2/r

1/24 = 2/r

r/2 = 24

r = 2 × 24

r = 48 cm

b.

magnification = image height, h'/object height,h = + 5.4 cm/+ 2.7 cm = 2

A ball is thrown with a velocity of 10 m/s at a 25º from the horizontal. How far does the ball travel?

Answers

Answer:

use a=v-u/t formula it will be correct

A nearsighted person has a far point of 40cm. What power spectacle lens is needed if the lens is 2cm from the eye

Answers

Answer:

The value is [tex]p = - 2.63 \ Diopters[/tex]

Explanation:

From the question we are told that  

      The value of the far point is  [tex]a = 40 \ cm = 0.4 \ m[/tex]

      The distance of the lens to the eye is  [tex]b = 2 \ cm = 0.02[/tex]

Generally

        [tex]1 Diopter = > 1 m^{-1}[/tex]

Generally the power spectacle lens needed is mathematically represented as

           [tex]p = \frac{1}{d_o } + \frac{1}{d_i}[/tex]

Here [tex]d_o[/tex] is the object distance which for a near sighted person is [tex]d_o = \infty[/tex]

And  [tex]d_i[/tex] is the image distance which is evaluated as

        [tex]d_i = b - a[/tex]

=>     [tex]d_i = 0.02 - 0.4[/tex]

=>     [tex]d_i = -0.38 \ m[/tex]

So

         [tex]p = \frac{1}{\infty } + \frac{1}{-0.38}[/tex]

=>      [tex]p = 0 - 2.63[/tex]

=>      [tex]p = - 2.63 \ Diopters[/tex]

A 4-kg object is moving with a speed of 5 m/s at a height of 2 m. The kinetic
energy of the object is approximately _J.

Answers

Hello!

[tex]\large\boxed{KE = 50J}[/tex]

Use the formula for kinetic energy:

[tex]KE = \frac{1}{2}mv^{2}[/tex]

Plug in the given mass and velocity:

[tex]KE = \frac{1}{2} (4)5^{2}[/tex]

Simplify:

[tex]KE = \frac{1}{2} (100)\\\\KE = 50 J[/tex]

are aliens real in 2020

Answers

Yes, they look exactly like newborn babies

Answer:

i believe that they are or there's something out there

Explanation:

:)

Plz help will give brainliest
Assignment: 02.03 Conservation of Mass
Details
Submit the assignment following the instructions in the lesson.
Due Date
N/A
20
Points Possible
20
Course Contribution
3
Submissions Allowed
0
Submission Number

Answers

The law of conservation of mass states that mass in an isolated system is neither created nor destroyed by chemical reactions or physical transformations. According to the law of conservation of mass, the mass of the products in a chemical reaction must equal the mass of the reactants.

Answer:

Steel Wool + Oxygen, Steel wool has a hard texture but is a grayish color. It looks like it's a powder, and also that it was rusted steel wool and then broken apart converted into a powder. So Iron oxide is 7 grams and combined steel wool is 7 grams, so you may assume that the mass has been retained. Yeah, it is a chemical change since the corrosion and rust in steel wool is a chemical process, but iron oxide is triggered by a physical change.

Egg + Heat, In the center, the egg has a yellow yolk while at the edge of the egg there is a kind of liquid, but it is visible, the heat becomes hot but clear The egg transformed into a delicious food called an omelet, which was yolk staid as a liquid but got a little harder, It was retained because the eggshell was 4 grams and the fried egg is 41 grams, but the clear border around it changed color. It is a chemical transition, and it results in the creation of new particles and the chemical bonds split apart and new ones are formed

Water + Heat, Water is a clear liquid, while the heat is very hot yet transparent. Once 5 g of liquid is a gas, it'll become 5 g of water vapor. Water + Heat Water is really a clear liquid. The mass of the liquid water is simply transformed into mass of the water vapor that is freshly created. There was no chemical process although water vapor can also be converted back to water, but it only shifted from a liquid to a gas and the structure did not change.

Zinc + Hydrogen Chloride Zinc, a metal white/silver solid. A clear, colorless liquid fluid with a really low pH in hydrogen chloride In hydrogen chloride, zinc is “dissolved” while releasing a colorless vapor. The liquid, possibly still having a low pH from the remaining acid, stays a colorless liquid.As sparked with a burning wooden splint, the colorless gas gathered in a tube provides a loud bang, because it is neither air trapped in the zinc, nor absorbed in hydropower acids. Well, even if the zinc is 12 grams and not 15 grams, the gas released was 3 grams and, as we all know, 3 + 12 is 15, so you could claim also that volume has also been saved.

Sodium Hydroxide + Copper, Sulfate Sodium hydroxide is a turbid solution and bright blue crystals are formed from copper sulfate A pale blue powder of basic copper hydroxide a solution of neutral salt sulfuric acid would be produced when their solutions are mixed with each other. The combined sodium hydroxide and copper sulfate make a total of 67 grams and the product is split because the sodium sulfate is 47 grams and the copper hydroxide is 20 grams, but all together it is still 67 grams, and you could assume that now the mass has been conserved. The evidence of a response was its image of royal blue basic copper hydroxide precipitates and a neutral salt sodium solution

Explanation:

. Emily pushes a 38.8 kg grocery cart of groceries by exerting a 76.0 N force on the handle inclined at 40.0 degrees below the horizontal. What are:
a. The horizontal and vertical components of Emily’s force






b. The acceleration of the cart?

Answers

Answer:

a) [tex]F_{x} = 58.2 N[/tex]

[tex] F_{y} = 48.9 N [/tex]

b) a = 1.5 m/s²

Explanation:

a) The horizontal and vertical components of Emily's force can be found knowing the angle and the exerted force.

Since the handle is inclined at 40.0° below the horizontal we have:

[tex] F_{x} = |F|*cos(\theta) = 76.0 N*cos(40) = 58.2 N [/tex]

[tex] F_{y} = |F|*sin(\theta) = 76.0 N*sin(40) = 48.9 N [/tex]

b) The acceleration of the car can be calculated as follows:

[tex] F_{x} = ma [/tex]        

We used the horizontal component of the force because the cart is moving in that direction.

[tex] a = \frac{F_{x}}{m} = \frac{58.2 N}{38.8 kg} = 1.5 m/s^{2} [/tex]

Hence, the acceleration of the car is 1.5 m/s².    

I hope it helps you!

What fraction of an iceberg is submerged? (ρice = 917 kg/m3, ,ρsea = 1030 kg/m3.)

Answers

Answer:

Choice d. Approximately [tex]89\%[/tex] of the volume of this iceberg would be submerged.

Explanation:

Let [tex]V_\text{ice}[/tex] denote the total volume of this iceberg. Let [tex]V_\text{submerged}[/tex] denote the volume of the portion that is under the liquid.

The mass of that iceberg would be [tex]\rho_\text{ice} \cdot V_\text{ice}[/tex]. Let [tex]g[/tex] denote the gravitational field strength ([tex]g \approx 9.81\; \rm N \cdot kg^{-1}[/tex] near the surface of the earth.) The weight of that iceberg would be: [tex]\rho_\text{ice} \cdot V_\text{ice} \cdot g[/tex].

If the iceberg is going to be lifted out of the sea, it would take water with volume [tex]V_\text{submerged}[/tex] to fill the space that the iceberg has previously taken. The mass of that much sea water would be [tex]\rho_\text{sea} \cdot V_\text{submerged}[/tex].

Archimedes' Principle suggests that the weight of that much water will be exactly equal to the buoyancy on the iceberg. By Archimedes' Principle:

[tex]\text{buoyancy} = \rho_\text{sea} \cdot V_\text{submerged} \cdot g[/tex].

The buoyancy on the iceberg should balance the weight of this iceberg. In other words:

[tex]\underbrace{\rho_\text{ice} \cdot V_\text{ice} \cdot g}_\text{weight of iceberg} = \underbrace{\rho_\text{sea} \cdot V_\text{submerged} \cdot g}_\text{buoyancy on iceberg}[/tex].

Rearrange this equation to find the ratio between [tex]V_\text{submerged}[/tex] and [tex]V_\text{ice}[/tex]:

[tex]\begin{aligned} &\frac{V_\text{submerged}}{V_\text{ice}} \\&= \frac{\rho_\text{ice} \cdot g}{\rho_\text{sea} \cdot g}\\ &= \frac{\rho_\text{ice}}{\rho_\text{sea}}\ = \frac{917\; \rm kg \cdot m^{-3}}{1030\; \rm kg \cdot m^{-3}} \approx 0.89 \end{aligned}[/tex].

In other words, [tex]89\%[/tex] of the volume of this iceberg would have been submerged for buoyancy to balance the weight of this iceberg.

12 ounces of beer plus 12 ounces of wine plus 3 ounces of liquor = how
many "drinks"?
6 drinks
7 drinks
12 drinks

PLS HURRY

Answers

Answer:

12 ounces of beer plus 12 ounces of wine plus 3 ounces of liquor are equivalent to 6 drinks.

Explanation:

In the United States, a standard "drink" of beer has 12 ounces, a standard "drink" of wine has 5 ounces and standard drink of liquor has 1.5 ounces. Then, we obtain the quantity of drinks by dividing the total volume of each drink by its respective unit volume and summing each term. That is:

[tex]N = \frac{12\,oz}{12\,\frac{oz}{dr} }+\frac{12\,oz}{5\,\frac{oz}{dr} }+\frac{3\,oz}{1.5\,\frac{oz}{dr} }[/tex]

[tex]N = 1\,dr+2.4\,dr+2\,dr[/tex]

[tex]N = 5.4\,dr[/tex]

[tex]N = 6\,dr[/tex]

12 ounces of beer plus 12 ounces of wine plus 3 ounces of liquor are equivalent to 6 drinks.

The scientific method can easily be misinterpreted as ___________. Question 1 options: a great magical trick, or slide of hands, rather than factual an "auto mechanics" guide to Science Investigation a "cookbook" recipe for performing scientific investigations the perfect method for finding the answers to all questions

Answers

Answer:

I think the answer is  

a "cookbook" recipe for performing scientific investigations

Explanation:

If a marble is dropped from a cliff, how fast is the marble going after falling for 3.6 seconds?
PLEEEEAAASSSEEEEEE HELPPPP MEEEE>

Answers

Answer:

35.28m/s

Explanation:

Given

Time t = 3.6secs

Required

Final speed v

Using the equation of motion;

v = u + gt

Substitute;

v = 0 + 9.8(3.6)

v = 0 + 35.28

v = 35.28m/s

Hence the speed of the marble is 35.28m/s

what is the main cause of seafloor spreading?​

Answers

Answer:

As tectonic plates slowly move away from each other, heat from the mantle's convection currents makes the crust more plastic and less dense.

Explanation:

Answer: The main cause of sea floor spreading are the directions and force of the moving tectonic plates.

Explanation:

Energy stored because of an object's height above the Earth's surface is_____energy.

nuclear

gravitational

electrical or chemical​

Answers

gravitational potential energy

if a certain car, going with speed v1, rounds a level curve with a radius r1, it is just on the verge of skidding. if its speed is now doubled, the radius of the tightest curve on the same road that it can round without skidding is:

Answers

Answer:

The correct answer is 4R1

Explanation:

According to the given scenario ,the radius of the tightest curve on the same road without skidding is as follows:

As we know that

Centeripetal Acceleration is

= v^2 ÷ r

In the case when velocity becomes 2 times so the r would be 4 times

So, the radius of the  tightest curve on the same road without skidding is 4R1

if a block weight 60N and is lying on a side with area 2m by 3m. what is the pressure exerted on the surface?​

Answers

Answer:

10 Pa

Explanation:

Pressure is defined as force per unit area.

Mathematically, P= F/A where  P is pressure, F is force and A is area.

Force, F = 60 N

Area, A = 2*3 = 6m²

P = 60/6 = 10 Pa

A 1.15 kg book is at rest on the table. What is the magnitude of the normal force that the table is exerting on the book?

Answers

Answer:

11.27N

Explanation:

Given parameters:

Mass of the book  = 1.15kg

Unknown:

Magnitude of the normal force  = ?

Solution:

The normal force is the vertical force exerted by a body on an object.

It can be described as the weight of an object.

 Normal force  = mass x acceleration due to gravity

 Normal force  = 1.15 x 9.8  = 11.27N

A particular engine has a power output of 5 kW and an efficiency of 30%. If the engine expels 6464 J of thermal energy in each cycle, find the heat absorbed in each cycle. Answer in units of J.

Answers

Answer:

The heat absorbed in each cycle is 9,234.286 J

Explanation:

Given;

power output, P = 5 kW = 5,000 W

efficiency of the engine, e = 30 % = 0.3

thermal heat expelled, [tex]Q_c[/tex] = 6464 J

let the heat absorbed = [tex]Q_h[/tex]

The efficiency of the engine is given as;

[tex]e = \frac{W}{Q_h} = \frac{Q_h-Q_c}{Q_h} = \frac{Q_h}{Q_h} - \frac{Q_c}{Q_h} = 1-\frac{Q_c}{Q_h}\\\\e = 1-\frac{Q_c}{Q_h}\\\\0.3 = 1-\frac{Q_c}{Q_h}\\\\\frac{Q_c}{Q_h} = 1-0.3\\\\\frac{Q_c}{Q_h} = 0.7\\\\Q_h = \frac{Q_c}{0.7} \\\\Q_h = \frac{6464}{0.7} = 9,234.286 \ J.[/tex]

Therefore, the heat absorbed in each cycle is 9,234.286 J.

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