A restaurant offers a catering service which costs $25.00 per person with a $119.50 service charge. For parties of 50 or more people, a group discount applies, and the cost is $20.00 per person along with the service charge dropping to $59.00. (a) Write a piecewise-defined linear function which calculates the total cost T of the catering service which serves n people.

Answer:

[tex]y = x +2[/tex]

Step-by-step explanation:

Given

The attached table

Required

Determine the equation

First, calculate the slope (m)

[tex]m = \frac{y_2 - y_1}{x_2 - x_1}[/tex]

Where

[tex](x_1,y_1) = (-3,-1)[/tex]

[tex](x_2,y_2) = (1,3)[/tex]

So, we have:

[tex]m = \frac{3 - (-1)}{1 - (-3)}[/tex]

[tex]m = \frac{3 +1}{1 +3}[/tex]

[tex]m = \frac{4}{4}[/tex]

[tex]m =1[/tex]

The equation in slope intercept form is calculated using

[tex]y = m(x - x_1) + y_1[/tex]

This gives:

[tex]y = 1(x - (-3)) -1[/tex]

[tex]y = 1(x +3) -1[/tex]

[tex]y = x +3 -1[/tex]

[tex]y = x +2[/tex]

Answer:

[tex]3(t - 3) \\ 3t - 9[/tex]

this is your answer

Answer:

The proportion of measurements between 25 and 55

P( 25 ≤ X≤ 55) = 0.6826

Step-by-step explanation:

Step(i):-

Given that the mean of the Population = 40

Given that standard deviation of the Population = 15

Let 'x' be the random variable in normal distribution

Let 'X' = 25

[tex]Z = \frac{x-mean}{S.D} = \frac{25-40}{15} = -1[/tex]

Let 'X' = 55

[tex]Z = \frac{x-mean}{S.D} = \frac{55-40}{15} = 1[/tex]

Step(ii):-

The probability that between 25 and 55

P( 25 ≤ X≤ 55) = P( -1≤z≤1)

                       = A(1) - A(-1)

                      = A(1) + A(1)

                     = 2 × A(1)

                    = 2× 0.3413

                   = 0.6826

The proportion of measurements between 25 and 55

P( 25 ≤ X≤ 55) = 0.6826

Final answer:-

The proportion of measurements between 25 and 55

P( 25 ≤ X≤ 55) = 0.6826

Step-by-step explanation:

a³+a²b+ab²+a³b+a²b²-a²b-ab²-b³-a²b²+ab³ = 2/3 ... plus 3Y is equal to 11 find the point where it presented by the equation cuts Y and X axis.

1 answer

Answer:

0.30

Step-by-step explanation:

Probability of stopping at first signal = 0.36 ;

P(stop 1) = P(x) = 0.36

Probability of stopping at second signal = 0.54;

P(stop 2) = P(y) = 0.54

Probability of stopping at atleast one of the two signals:

P(x U y) = 0.6

Stopping at both signals :

P(xny) = p(x) + p(y) - p(xUy)

P(xny) = 0.36 + 0.54 - 0.6

P(xny) = 0.3

Stopping at x but not y

P(x n y') = P(x) - P(xny) = 0.36 - 0.3 = 0.06

Stopping at y but not x

P(y n x') = P(y) - P(xny) = 0.54 - 0.3 = 0.24

Probability of stopping at exactly 1 signal :

P(x n y') or P(y n x') = 0.06 + 0.24 = 0.30

Answer:

3.25 or 3 1/4

Step-by-step explanation:

Remove the parentheses first: 3/4 + (1/3 / 1/6) - (-1/2)

1/3 / 1/6 turns into 1/3 * 6

Reduce the numbers:

3/4 + (1/3 * 6) + 1/2

cross multiplication, 6 divided by 3 = 2.

So the new equation is 3/4 + 2 + 1/2

Then you calculate.

3/4 + 2 + 1/2 = 13/4

13/4 reduced is 3 1/4 or 3.25

Answer:

1..........................

Answer:

Andre scored 14 points.

Step-by-step explanation:

set up expressions with the info given:

Diego's points: a –9

Andre's points: 2d. and

n = 2d

Noah's points = 10

Use the expressions to set up equations to solve.

To find a, Andre's points, we can work backwards.

Substitute the 10 from the last expression for n in the equation n=2d, and solve for d:

10 = 2d. Divide both sides by 2

5 = d

Substitute the value of d, Diego's points, to make an equation using the first expression:

5 = a –9 Add 9 to both sides.

5 + 9 = a a = 14

Andre scored 14 points

Answer:

its 0.5

Step-by-step explanation:

just subtract 2.1 and 1.6

Answer:

They are 10 units away from the treasure

Step-by-step explanation:

Notice that the points (9, -7) and (9, 3) are both located at the same x-value (9) while their y-values are in one case 3 units above the x-axis, and in the other 7 units BELOW the x-axis. Therefore thy differ by 3 - (-7) units , which totals 10 units.

Answer:

Step-by-step explanation:

For the first digit, there are 8 numbers to choose from (2, 3, ..., 9).

For each remaining digits, there are 10 numbers to choose from (0, 1, ..., 9).

Choose 6 of them. Repetition is allowed, and order matters.

There are 10⁶ possible choices.

There are 8×10⁶ possible phone numbers.

Answer: I think you’re right??

Step-by-step explanation:

Answer:

Step-by-step explanation:

-5.25+2.25         - 3

1-0.5                 = 0.5

=-6 =m

y=-6x

Answer:

x=7.5

Step-by-step explanation:

Since AD II EH, ∠CBD=∠BFH (alternate angles)

2x+60=10x

8x=60

x=7.5

Answer:

x = 7.5

each angle measures 75°

Step-by-step explanation:

the two angles are corresponding, meaning they are equal

10x = 2x + 60

8x = 60

x = 7.5

Answer:

a = 3.333... (3 repeating) or 3 1/3

Step-by-step explanation:

Solve for a by simplifying both sides of the equation, then isolating the variable.

Answer:

-5a-4

Step-by-step explanation:

7a-8-12a+4

7a-12a-8+4

=-5a-4

Answer:

90,56,7867,45,89,45,24,67

Answer:

x=3

Step-by-step explanation:

Subtract 5 from both sides:

2x=6

Divide both sides by 2:

x=3

Answer:

3

Step-by-step explanation:

2x+5=11

subtract 5 from both sides of the equation

Then divide by two to both sides of the equation

Answer:

Step-by-step explanation:

Property of the kite: diagonals are perpendicular

Perimeter is the sum of the side lengths:

Answer:

40

Step-by-step explanation:

Answer:

x = -2

Step-by-step explanation:

Isolate the variable by dividing each side by factors that don't contain the variable.

Answer: 27 ounces of chicken.

Step-by-step explanation:

Sara has 2 pounds of chicken.

She uses 5 ounces of chicken.

So now, she has:

(2 pounds - 5 ounces ) of chicken.

To perform this subtraction, we first need to write bot quantities in the same units.

First, we know that:

1 pound = 16 ounces.

Then we can rewrite 2 pounds, this is equal to 2 times 16 ounces.

2 pounds = 2*16 ounces = 32 ounces.

Then initially she has 32 ounces, and she uses 5 ounces.

Now she has:

(32 ounces - 5 ounces) = 27 ounces of chicken

Answer:

(x=0, y=11)

(x=2, y=9)

Step-by-step explanation:

first equation substitution for x first.

y=11-x

plug into 2nd equation

(x+2)^2+(11-x-7)^2=20

this should lead you into a quadratics equation.

you get x=0, x=2.

do the same for y value this time, subbing in the x value

(11-y+2)^2+(y-7)^2=20

this also leads into a quad equation

solve and you get y=11, and y=9

Answer:

-1

Step-by-step explanation:

12 + -13 = -1

Answer:

x = -2, y = 21

Step-by-step explanation:

Let 4x + y = 13 to be equation1 {eqn1}

and let 5x - y = 5 to be equation2 {eqn2}

Using elimination method, you would try to make sure a particular unknown has the same value in both equation 1 and 2. This would make it easy for you to subtract one equation from the other.

Notice how the value of y is the same in both equations. That's a good sign.

But the signs aren't the same. Meaning y in eqn1 has a value of +1, and y in eqn2 has a value of -1. We need to make them similar.

So, we multiply the value of y in eqn1 by all the terms in eqn2. And, do pretty much the same thing by multiplying the value of y in eqn2 by all the terms in eqn1.

You would have:

-1 * (4x + y = 13)

+1 * (5x - y = 5)

This would result in;

-4x -  y = -13 (eqn3)

5x - y = 5 (eqn4)

So, just subtract eqn3 from 4

You would have;

(5x - -4x) + (-y -- y) = (-13 - 5)

9x + 0 = -18

x = -18/9 = -2

and to find y;

just substitute the value of x into any of the 4 equations. let's try equation 1

Therefore;

4(-2) + y = 13

-8 + y = 13

y = 13 + 8 = 21

Answer:

[tex]Radius = 1.997\ in[/tex] and [tex]Height = 7.987\ in[/tex]

[tex]Cost = \$1.05[/tex]

Step-by-step explanation:

Given

[tex]Volume = 100in^3[/tex]

[tex]Cost =\$0.014[/tex] -- Top and Bottom

[tex]Cost =\$0.007[/tex] --- Sides

Required

What dimension of the cylinder minimizes the cost

The volume (V) of a cylinder is:

[tex]V = \pi r^2h[/tex]

Substitute 100 for V

[tex]100 = \pi r^2h[/tex]

Make h the subject

[tex]h = \frac{100 }{\pi r^2}[/tex]

The surface area (A) of a cylinder is:

[tex]A = 2\pi r^2 + 2\pi rh[/tex]

Where

[tex]Top\ and\ bottom = 2\pi r^2[/tex]

[tex]Sides = 2\pi rh[/tex]

So, the cost of the surface area is:

[tex]C = 2\pi r^2 * 0.014+ 2\pi rh * 0.007[/tex]

[tex]C = 2\pi r(r * 0.014+ h * 0.007)[/tex]

[tex]C = 2\pi r(0.014r+ 0.007h)[/tex]

Substitute [tex]h = \frac{100 }{\pi r^2}[/tex]

[tex]C = 2\pi r(0.014r+ 0.007*\frac{100 }{\pi r^2})[/tex]

[tex]C = 2\pi r(0.014r+ \frac{0.007*100 }{\pi r^2})[/tex]

[tex]C = 2\pi r(0.014r+ \frac{0.7}{\pi r^2})[/tex]

[tex]C = 2\pi (0.014r^2+ \frac{0.7}{\pi r})[/tex]

Open bracket

[tex]C = 2\pi *0.014r^2+ 2\pi *\frac{0.7}{\pi r}[/tex]

[tex]C = 0.028\pi *r^2+ \frac{2\pi *0.7}{\pi r}[/tex]

[tex]C = 0.028\pi *r^2+ \frac{2 *0.7}{r}[/tex]

[tex]C = 0.028\pi *r^2+ \frac{1.4}{r}[/tex]

[tex]C = 0.028\pi r^2+ \frac{1.4}{r}[/tex]

To minimize, we differentiate C w.r.t r and set the result to 0

[tex]C' = 0.056\pi r - \frac{1.4}{r^2}[/tex]

Set to 0

[tex]0 = 0.056\pi r - \frac{1.4}{r^2}[/tex]

Collect Like Terms

[tex]0.056\pi r = \frac{1.4}{r^2}[/tex]

Cross Multiply

[tex]0.056\pi r *r^2= 1.4[/tex]

[tex]0.056\pi r^3= 1.4[/tex]

Make [tex]r^3[/tex] the subject

[tex]r^3= \frac{1.4}{0.056\pi }[/tex]

[tex]r^3= \frac{1.4}{0.056 * 3.14}[/tex]

[tex]r^3= \frac{1.4}{0.17584}[/tex]

[tex]r^3= 7.96178343949[/tex]

Take cube roots of both sides

[tex]r= \sqrt[3]{7.96178343949}[/tex]

[tex]r= 1.997[/tex]

Recall that:

[tex]h = \frac{100 }{\pi r^2}[/tex]

[tex]h = \frac{100 }{3.14 * 1.997^2}[/tex]

[tex]h = \frac{100 }{12.52}[/tex]

[tex]h = 7.987[/tex]

Hence, the dimensions that minimizes the cost are:

[tex]Radius = 1.997\ in[/tex] and [tex]Height = 7.987\ in[/tex]

To calculate the cost, we have:

[tex]C = 2\pi r(0.014r+ 0.007h)[/tex]

[tex]C = 2* 3.14 * 1.997 * (0.014*1.997+ 0.007*7.987)[/tex]

[tex]Cost = \$1.05[/tex]

Answer:

Which of the following sets of possible side lengths forms a right triangle?

6, 12, and 13

9, 40, and 45

12, 35, and 38

Step-by-step explanation:

[tex] \sqrt{ {11}^{2} + {60}^{2} } \\ = \sqrt{121 + 3600} \\ = \sqrt{3721} \\ = \sqrt{ {61}^{2} } \\ = 61[/tex]

Answer:

d?.............................