A resistor and an initially uncharged capacitor are connected in series with battery. A long time after the circuit is connected , which of the following is true? O The voltage across the resistor is at its maximum: O The voltage across the capacitor is at its minimum: O The charge on the capacitor is at its minimum. O The current in the circuit is at its maximum; O The current in the circuit is Zero.

Answers

Answer 1

The current in the circuit is Zero is true

Define current

An electrical charge carrier flow known as current often involves electrons or atoms lacking in electrons. negative to positive points are crossed by current.

The maximum voltage across the resistor is the first choice. This choice is incorrect because, after a considerable amount of time, the capacity is fully charged and the circuit's current "I" will be equal to zero. Moreover, because current is 0 It will now be equal to zero for the voltage courses resistive "IR."

The next option claims that the voltage across the capacitor is at its lowest. Additionally, this is incorrect because charge across a capacitor reaches its maximum over time. In addition to being maximum, voltage will be maximum and equivalent to charge upon capabilities.

No The capacitor is only partially charged, according to the next option. This is incorrect since it takes a while for the charge to reach its maximum level before the maximum current is claimed. . Which is also incorrect because once the capacitor is fully charged, current eventually zeroes out.

Since the capacitor's charge did not change at all after it reached full charge, the fact that the circuit's current is zero is accurate. Because the charge has achieved its maximum value, the rate of change of charge will be zero, and the current will also be zero.

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Related Questions

how does the total mechanical energy of the two block system after the collision comapre to the total mechanical energy of the two block system before te collision

Answers

The total mechanical energy before the collision of the block system will remain the same to the total mechanical energy after the collision.

In the field of science, mechanical energy can be described as the kind of energy that is present at the time of motion or at the time of rest.

Hence when two block systems collide, the mechanical energy can change from one form to another but the total energy will remain the same.

This is because, according to Newton, energy can change form from one form to another but the total energy remains the same.

Hence, in the block system, the mechanical energy will remain the same after collision.

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1.how high will the station have to above the normal train track be for 100,000 kg train going 100 km/hr to come to a stop?

Answers

The station should be above 39.34m the normal train track.

mass = 10⁵kg

v=100 km/hr

v=27.77 m/s

using energy conservation

1/2m(v)²=mgh

h=(v)²/2g

h=(27.77)²/2×9.8

h=39.34

Mass, in physics, quantitative measure of inertia, an essential property of all dependents. It's far, in effect, the resistance that a frame of count number gives to a change in its speed or position upon the application of pressure. The more the mass of a frame, the smaller the alternate produced with the aid of a carried-out force.

The unit of mass within the worldwide machine of gadgets (SI) is the kilogram, which is defined in terms of Planck's regular, which is described as equal to 6.62607015 × 10-34 joule 2d squared.

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. A rock is thrown vertically upwards at 67 km/h. Find the height at which the rock is
going 23 km/h [down]. (DON'T FORGET UNITS CONVERSION)

Answers

The height at which the rock is going 23 km/h downwards be 15.59 m.

What is law of conservation of energy?

Energy cannot be created or destroyed, according to the rule of conservation of energy. However, it is capable of change from one form to another. An isolated system's total energy is constant regardless of the types of energy present. The law of energy conservation is adhered to by all energy forms.

The law of conservation of energy essentially says that: The total energy of the system is conserved in a closed system, also known as an isolated system.

Given that: A rock is thrown vertically upwards at 67 km/h = 18.6111 m/s.

We have to find its height, when downwards velocity is 23 km/h = 6.389 m/s.

Let the mass of the rock be m and using law of conservation of energy:

1/2 m (18.6111)² = mgh + 1/2m(6.389)²

⇒ h = (18.611² - 6.389²)/(2×9.8) m = 15.59 m.

Hence, the height at which the rock is going 23 km/h downwards be 15.59 m.

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An electromagnetic wave transfers energy as it travels. During this process, what is the relationship between the magnetic and electric fields along its path?.

Answers

An electromagnetic wave transfers energy as it travels, then electric and magnetic fields in an EM wave are perpendicular to each other and also perpendicular to the direction of wave propagation.

What is electromagnetic wave?

Waves that move through space and carry electromagnetic radiant energy is termed the electromagnetic waves.  They include radio waves and microwaves and others.

During the transfer of energy, they are the sinusoidal movement that are perpendicular to each other in the direction of wave motion. They also show synchronized oscillations.

A changing magnetic field induces changing electric field and vice-versa as the two are linked. Changing fields form electromagnetic waves.

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a long straight conductor has a circular cross section of radius r and carries a current i. inside the conductor, there is a cylindrical hole of radius a whose axis is parallel to the axis of the conductor and at a distance b from it.

Answers

When current is straight, it means the current is passing through a straight conductor, the magnetic field produced due to current through a straight conductor is in the form of concentric circle and are in a plane perpendicular to the plane of linear conductor. It means the magnetic field is circular.

What is straight line conductor?

a straight conductor is a wire having magnetic field lines centre on it.

When a current in a circular loop is?

Electric current in a circular loop creates a magnetic field which is more concentrated in the center of the loop than outside the loop. Stacking multiple loops concentrates the field even more into what is called a solenoid.

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light of intensity so and polarized horizontally passes through three polarizes. the first and third are horizontal, but the second is oriented 0.62832 rad to the horizontal. in terms of so , what is the intensity of the light that passes through the set of polarizers?

Answers

The Light Intensity that passes through the set of polarizers is 9.99939871 W/m

It takes complicated mechanisms to control how light moves through media. As an electromagnetic wave, light interacts with the electric charge that permeates all matter. The oscillatory motion of electric charges along a single dimension can actually be significantly restricted by creating a solid substance.As a result, charges respond to electric fields in one direction—or more specifically, to their individual components in one direction—while not responding in the opposite direction.

[tex]I=icos\alpha[/tex]

I=10 cos 0.62832

=9.99939871 W/m

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suppose you have a diffraction grating which has 300. lines/mm and you shine light with a wavelength of 589 nm through it. what is the angle at which you will observe the second order (m

Answers

The answer indicates that the range about which you will see the second order (m=2) brilliant fringe is 17.76°.

What distinguishes a diffraction grating from a grating?

Diffraction gratings could really separate kaleidoscopic light in with its constituent wavelengths, so even though transmission vertical slats are an a kind of interferometer that includes diffraction of light at various angles to produce a diffraction pattern. This is a main distinction between the two types of gratings.

Briefing:

As we know that,

300 lines/mm = 1/d

d = 0.00333E-3 m

now use

m λ = d sin θ

θ = arc sin( 2*508E-9/0.00333E-3) = 17.76°

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The complete question is-

Suppose you have a diffraction grating which has 300. lines/mm and you shine light with a wavelength of 589 nm through it. What is the angle at which you will observe the second order (m=2) bright fringe?

a diode laser emits at a wavelength of 987 nm. (a) in what portion of the electromagnetic spectrum is this radiation found? (b) all of its output energy is absorbed in a detector that measures a total energy of 0.52 j over a period of 32 s. how many photons per second are being emitted by the laser?

Answers

Answer: A

Explanation:

I took the test

what is the kinetic energy of the object on the spring when the spring is compressed 3.2 cm from its equilibrium position? express your answer in joules using three significant figures.

Answers

The kinetic energy K of the toy when the spring is compressed 3.2 cm from its equilibrium position if the maximum velocity achieved by the toy is 3.2 m/s is 0.19 J

KE = 1 / 2 m ( ω √ ( A² - x² ) ²

KE = Kinetic energy

m = Mass

A = Amplitude

x = Displacement of spring

ω = Angular velocity

ω = v / A

m = 50 g = 0.05 kg

v = 3.2 m / s

A = 6 cm = 0.06 m

x = 3.2 cm = 0.032 m

KE = 1 / 2 m ( v / A √ ( A² - x² )²

KE = 1 / 2 * 0.05 ( 3.2 / 0.06 √ ( 0.06² - 0.032² )²

KE = 0.025 * ( 53.33 * 0.051 )²

KE = 0.025 * 7.39

KE = 0.19 J

Therefore, the kinetic energy is 0.19 J

The given question is incomplete. The complete question is:

A child's toy consists of a spherical object of mass 50 g attached to a spring. One end of the spring is fixed to the side of the baby's crib so that when the baby pulls on the toy and lets go, the object oscillates horizontally with a simple harmonic motion. The amplitude of the oscillation is 6 cm and the maximum velocity achieved by the toy is 3.2 m/s . What is the kinetic energy K of the toy when the spring is compressed 3.2 cm from its equilibrium position?

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a 500 kg motorcycle accelerates from rest to 25 m/s over a time interval of 5.5 s. find the force exerted on the motorcycle by the road due to friction. group of answer choices 2273 n 1800 n 1500 n 2500 n

Answers

The force exerted on the motorcycle by the road due to friction is 2273n.

Solution:

m = 500 kg

v = 25 m/s

u = 0 m/s

t = 5.5 s

F = 500(25-0)/5.5

F = 2272.72 N

Friction offsets the weight to keep the motorcycle moving on the loop at a constant speed. Both weights and normals point down towards the center of the loop. The net force is the centripetal force. Dry friction always opposes sliding between surfaces and can react or act on bodies in motion. This motorcycle creates dry friction between the tires and the road surface.

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A rocket launched vertically rises with a constant speed for 60 s to a height of 10000 m. If the mass of the rocket is 1000 kg (and assume mass is constant), what is the power of the engine? (use g

Answers

The power of the rocket has a mass of 1000 kg is 16,33,333.33 Watt

The mass of the rocket = 1000 kg

The rocket travels at a constant speed for 60 s

The displacement of the rocket = 10000 m

The formula to find the power of the rocket engine is

               P = F x v

where F is the force and

          v is the velocity

           

Thus  P = (m x g x d)/t

where m is the mass of the rocket

           g is the acceleration due to gravity

           d is the displacement

           t is the time taken

Let us substitute the known values in the above equation, we get

               P = ( 1000 x 9.8 x 10000 ) / 60

                  = 98000000 / 60

                  = 1633333.33

Therefore, the power of the rocket is 16,33,333.33 W

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if the pressure reading of your pitot tube is 12.0 mm hg at a speed of 210 km/h, what will it be at 830 km/h at the same altitude? assume the density of air at sea level.

Answers

47.4 mm hg is the pressure  at 830 km/h at the same altitude

Bernoulli's principle refers to this inverse relationship between pressure and speed at a particular point in a fluid. Principle of Bernoulli

P1=12 mm hg

v1=210 km/h

v2=830 km/h

p2=?

P1/V1=P2/V2

P2=P1V2/V1

P2=12×830÷210

P2=47.4 mm hg

The definition of pressure is force/area. Divide the weight of the snow by the surface area of the roof to show the pressure that snow puts on it. In physics, gases are a common source of pressure. The lack of pressure is referred to as a "vacuum". Since "nature abhors a vacuum," people have long believed that vacuums are improbably uncommon and unnatural. This is not actually the case.

The quantity of pressure units is absurd. The torr or mmHg units are frequently used. The height of a mercury column is the only topic of discussion. There are 760 torr, or mmHg, in the atmosphere. You might also take a look at mmH2O, which employs a related concept.

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A nonrelativistic electron and a nonrelativistic proton have the same de Broglie wavelength. Which of the following statements about these particles are accurate? (There may be more than one correct choice.)A) Both particles have the same speed.B) The electron has more momentum than the proton.C) The electron has more kinetic energy than the proton.D) Both particles have the same kinetic energy.E) Both particles have the same momentum.

Answers

The de Broglie wavelength of a nonrelativistic electron and a nonrelativistic proton is the same, they both have the same momentum, and the electron has higher kinetic energy than the proton.

A subatomic particle having a poor standard electric charge is the electron. Because they lack any discernible additives or substructure, electrons are considered to be fundamental particles and belong to the main technology of the lepton particle's own family. The radius of the electron is predicted to be around 2 10-10 cm using the best values for the wavelength and the scattering by a tough X-ray and?-ray matter.

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the temperature of an object is 172°c. what is the peak wavelength (in µm) of the radiation emitted by the object at this temperature?

Answers

Peak wavelength of the object is 6.49 µm.

Peak wavelength is the wavelength at which the line is brightest.

At optical wavelengths, a spectrograph can measure the amount of light emitted by stars.The wavelength of the peak emission depends on the temperature of the object emitting the radiation.Mathematically, T = 2.89 * [tex]10^{-3}[/tex] / λmaxA higher temperature causes the wavelength of the peak emission to be at a shorter wavelength. As the temperature increases, the amount of energy emitted (radiation) increases, while the wavelength of the peak emission decreases.

Temperature of the object = 172°c

Temperature in kelvin = 172 + 273 = 445 K

λmax = 2.89 * [tex]10^{-3}[/tex] / T

λmax =2.89 * [tex]10^{-3}[/tex] / 445

λmax = 6.49 *   [tex]10^{-6}[/tex] m

λmax = 6.49 µm

The peak wavelength of the radiation emitted by the object at temperature 172°c is 6.49 µm.

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Two trains emit 516-Hz whistles. One train is stationary. The conductor on the stationary train hears a 3.5-Hz beat frequency when the other train approaches. What is the speed of the moving train? b = beat f'_b = 3.5 Hz f = 516 Hz

Answers

The speed of the moving train is 2.31 m/s

What is called speed?

Speed is described as. the rate at which an object's position changes in any direction. Speed is defined as the distance traveled divided by the travel time. Speed is a scalar quantity because it only has a direction and no magnitude.

Speed is calculated as follows: speed = distance/time. Knowing the units for distance and time is necessary to calculate the units for speed.

According to the given information:

[tex]f=\frac{v}{s} *f_{0}[/tex]  

s = speed in air,

v is the speed of the train,

f₀ is the frequency of the siren,

f₀ = 516 Hzs = 340.29 m/s

f = 3.5 Hz

v = (3.5 / 516) × 340.29 = 2.31 m/s.

So, the speed of the moving train is 2.31 m/s

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A descending elevator of mass 1,000 kg is uniformly decelerated to rest over a distance of 8 m by a cable in which the tension is 11,000 N. The speed v_1 of the elevator at the beginning of the 8 m descent is most nearly (A)4 m/s (B) 10 m/s (C) 13 m/s (D) 16 m/s E) 21 m/s

Answers

The speed  [tex]V_{i}[/tex] of the elevator at the beginning of the 8 m descent is nearly 4 m/s. Hence, option A is the correct answer.

We are given that-

the mass of the elevator (m) = 1000 kg ;

the distance the elevator decelerated to be y = 8m ;

the tension is T = 11000 N;

let us determine the acceleration 'a' by using Newton's second law of motion.

∑Fy = ma

W - T = ma

(1000kg x 9.8 m/s² ) - 11000N = 1000 kg x a

9800 - 11000 = 1000

a = - 1.2 m/s²

Using the equation of kinematics to determine the initial velocity.

[tex]V_{f}[/tex] ² = [tex]V_{i}[/tex]² + 2ay

[tex]V_{i}[/tex] = √ ( 2 x 1.2m/s² x 8 m )

[tex]V_{i}[/tex] = √19.2 m²/s²

[tex]V_{i}[/tex] = 4.38 m/s   ≈ 4 m/s

Hence, the initial velocity of the elevator is 4m/s.

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during an isothermal compression of an ideal gas, 200 j of heat must be removed from the gas to maintain constant temperature. how much work is done by the gas during the process?

Answers

Work done by the gas during the process is -200J.

Work done can be defined as the product of force and distance travelled by the force.

For an isothermal process, temperature is constant and thus the heat transfer into and out of the system happens slowly so that the system is in thermal equilibrium.

Also, from the first law of thermodynamics, the change in internal energy (ΔU) of a closed system is equal to the sum of the heat transferred (Q) and the work done (W) by the system. i.e

ΔU = W + Q    

The internal energy is dependent on the temperature of the system and since this temperature is constant the change in internal energy is zero (0).

i.e

ΔU = 0

putting the values in the equation of FLOT

⇒ 0 = W + Q

⇒ W = -Q  

Therefore, for such process, the work done is the negative of the heat transferred (heat removed in this case).

Q = 200J

W = -200J

Therefore, the work done is -200 J

The value is negative to show that the process is a compression meaning that work is done by the surrounding on the gas.

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a 50.0-kg skater is traveling due east at a speed of 3.00 m/s. a 70.0-kg skater is moving due south at a speed of 7.00 m/s. they collide and hold on to each other after the collision, managing to move off at an angle θ south of east, with a speed of vf. find (a)the angle θ and (b)the speed vf, assuming that friction can be ignored.

Answers

a 50.0-kg skater is traveling due east at a speed of 3.00 m/s. a 70.0-kg skater is moving due south at a speed of 7.00 m/s. they collide and hold on to each other after the collision, managing to move off at an angle θ south of east, with a speed of vf. find

(a)the angle θ and

(b)the speed vf, assuming that friction can be ignored.   4.28 m/s

I used tan theta=(opposite/adjacent) but I got 66.8 degrees as my answer with 7 as the opposite and 3 as the adjacent, whereas my answer booklet says 73.0 degrees. I thought velocities could be treated as vectors.

someone who skates. same as skateboarderSee skateboarder. British informal a young man or woman who usually wears saggy garments and spends lots of time skateboarding.

travel is the motion of human beings among distant geographical places. journey can be performed by using foot, bicycle, vehicle, educate, boat, bus, airplane, ship or other approach, with or without baggage, and can be one way or spherical ride.

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what is the difference between the average temperatures of venus and mercury? 1 kelvin 1 degree celsius 178 degrees celsius 274 kelvin

Answers

The difference between the average temperatures of venus and mercury : Mercury - 333°F (167°C) Venus - 867°F (464°C)

Is Venus hotter than Mercury?The hottest planet in our solar system is Venus, despite Mercury being closest to the Sun. There are sulfuric acid clouds and a lot of carbon dioxide in its dense atmosphere. The atmosphere absorbs heat, giving the surface the impression of being in a furnace.It is known that the sunny side may become as hot as 750 to 800 degrees Fahrenheit, while the temperature at night can get as low as -330 degrees. Mercury's ambient temperature is a pleasant 354 degrees Fahrenheit.It seems that the surface temperature on Venus varies between 820 and over 900 degrees Fahrenheit. Lead can melt at temperatures as high as 847 degrees Fahrenheit on the average surface.

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t is 165 cm from your eyes to your toes. you are standing 200 cm in front of a tall mirror. how far is it from your eyes to the image of your toes?

Answers

The calculated total distance from the eyes to the toes is given by 432.7 cm.

Given:

Distance, x = 200 cm

Horizontal distance, h = 165 cm

We can use the idea of virtual images created by mirrors to calculate the distance between your eyes and the image of your toes in the mirror.

When you stare at a mirror, light rays from your eyes reflect off of it and give the impression that they are coming from behind the mirror. The virtual reflection created by the mirror appears to be at the same height as you are in front of it.

The horizontal distance is:

d = 2x

d = 2 × 200

d = 400 cm

The total distance from eyes to toes is:

D = √(d² + h²)

D = √(400² + 165²)

D = 432.7 cm

Hence, the calculated distance from the eyes to the toes is given by 432.7 cm.

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calculate the charge on the maximum capacitor if a battery of potential difference 1.5 volts is placed across the plates.

Answers

If a battery with a potential difference of 1.5 volts is placed across the plates, the maximum capacitor will have a charge of 36 V.

What possible variations are there in a 1.5 volt battery?

1 V is, by definition, a potential energy differential between two places equal to one joule for every coulomb of charge. Your query is resolved by that. Between the sites where that potential difference is measured, 1.5V denotes a potential energy differential of 1.5 joules per coulomb.

How do you determine the difference in potential energy?

ΔV=VB−VA=ΔPEq. By dividing the potential energy of a charge q that has been transported from point A to point B by the charge, we may define the potential difference between points A and B as VBVA. The joules per coulomb, sometimes known as volts (V) in honor of Alessandro Volta, are the units of potential difference.

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A pulse is created on a spring with a fixed end. What happens to the wave after it hits the fixed end? a. It reflects, remains upright, and maintains the same velocity. B. It reflects, inverts, and maintains the same velocity. C. It reflects, remains upright, and changes velocity. D. It reflects, inverts, and changes velocity.

Answers

It reflects, inverts, and maintains the same velocity.

What is velocity?

The direction of a body or object's movement is defined by its velocity. In its basic form, speed is a scalar number. In essence, velocity is a vector quantity. It is the speed at which distance changes. It is the displacement change rate.

"It reflects , reverts and maintains the same velocity" is the one among the following that describes what happens to the wave after it hits the fixed end. The correct option among all the options that are given in the question is the second option or option "b". I hope the answer has come to your help.

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a runner moving at a speed of 8.8 m/s rounds a bend with a radius of 25 m. what is the centripetal acceleration of the runner, and what agent exerts force on the runner?

Answers

The force on the runner is equal to the mass of the runner multiplied by the acceleration due to gravity, which is the force of gravity acting on the runner.

What is centripetal force?
A force that causes a body to follow a curved path is known as a centripetal force. It always moves in a direction that is the opposite of the body's motion and in the direction of the instantaneous centre of curvature of the path. It is "a force through which bodies are attracted or impelled, or in any other way tend, toward that point in relation to a centre," according to Isaac Newton. Gravity is the centripetal force that drives astronomical orbits according to Newtonian mechanics. A common illustration of centripetal force is when a body moves uniformly fast in a circular motion. The centripetal force is applied towards the center of the circle path both along the radius and at sharp angles to the motion. Dutch physicist Christiaan Huygens developed the mathematical description in 1659.

The centripetal acceleration of the runner can be calculated using the formula a = v²/r, where a is the centripetal acceleration, v is the speed of the runner, and r is the radius of the bend.

Therefore, the centripetal acceleration of the runner is:
a = (8.8 m/s)²/25 m
= 4.6 m/s²

The agent that exerts force on the runner is gravity, which acts downwards on the runner and produces the centripetal force needed to accelerate the runner around the bend. This can be demonstrated mathematically using the equation F = ma, where F is the force, m is the mass of the runner, and a is the centripetal acceleration.
F = m*(v²/r)
= m*4.6 m/s²
= m*g
Therefore, the force on the runner is equal to the mass of the runner multiplied by the acceleration due to gravity, which is the force of gravity acting on the runner.

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how does the image distance (the distance from the lens to the focused image) change with the object distance (the distance from psy to the lens?)

Answers

The image distance (the distance from the lens to the focused image) change with the object distance (the distance from object to the lens) due to the lens formula.

Lens formula is defined as the relationship between object distance (u), image-distance (v) and the focal length (f). Following is the mathematical representation of lens formula:

Lens Formula : 1/f = 1/v - 1/u

Where f = focal length

           v = image distance

           u = object distance

The lens is a transparent material which is bound by two surfaces. It has a principal axis, principal focus, centre of curvature of lens, aperture and optical centre.The images obtained from these lenses can be either a real image or a virtual image.

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Which statement best describes the relationship between changes in air pressure and wind speeds?

Responses


When a high- and a low-pressure air mass are far apart, air moves quickly from high to low pressure.


When a high- and a low-pressure air mass are far apart, air moves slowly from high to low pressure.


When a high- and a low-pressure air mass are close together, air moves slowly from high to low pressure.


When a high- and a low-pressure air mass are far apart, air moves quickly from low to high pressure.

Answers

The best statement that best describes the relationship between changes in air pressure and wind speeds is when a high- and a low-pressure air mass are far apart, air moves quickly from high to low pressure.

The greater the increase or decrease in pressure, the faster the winds move. When a high- and a low-pressure air mass are far apart, air moves slowly from high to low pressure. When a high- and a low-pressure air mass are close, the air moves slowly from a point of high to low pressure. When a high- and a low-pressure air are far apart, the air moves rapidly from a region of high pressure to a region of low pressure.

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A luge and its rider, with a total mass of 85 kg, emerge from a downhill track on to a horizontal straight track with an initial speed of 37 m/s. If a force slows them to a stop at a constant rate of 2.0 m/s 2
, (a) what magnitude F is required for the force, (b) what distanced do they travel while slowing, and (c) what work W is done on them by the force? What are (d) F, (e) d, and (f) W if they, instead,slow at 4.0 m/s 2
?

Answers

Force required is: -170N for the distance of 342.25m.

a) F=ma

F= - 85×2.0 = - 170

b) using energy

5×85×37²=170×d

d = 342.25 m

c) The work done would be given by

W= F×d

W  =(−1.7×10²N)×(3.4×10²)

W=−5.8 × [tex]10^{4}[/tex] J

d) The net force on the mass would be

F = ma

F = -340 NF

-ve sign indicates that the force acts opposite to the direction of motion.

e) Using the kinematic equation

v²= u² + 2ad

d= 1.7 × 10² m

f) The work done would be given by

W= F×d

W= -5.8 × [tex]10^{4}[/tex] J

-ve sign indicates that the energy of the rider decreases by the force

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What type of outlet is recommended for installation in any area where water and electricity could come into contact?.

Answers

A special kind of outlet known as a Ground Fault Circuit Interrupter (GFCI) should be installed in area where water and electricity could come into contact. GFCIs are typical electrical safety devices which trips electrical circuits as soon as they detect ground faults or leakage of current.

What is Ground Fault Circuit Interrupt?

Installing GFCIs, or ground fault circuit interrupters, is a unique type of outlet that should be used in locations where electrical items may come into contact with water. A GFCI is made to trip before a potentially fatal electrical shock occurs.

Anybody who enters the path of a leakage current will receive a fatal shock or be electrocuted. These outlets guard against fatal shock by immediately cutting off power to the circuit if the electricity entering the circuit and returning to it differ by even a little amount.

Any indoor or outdoor space where water might come into contact with electrical equipment should have a GFCI installed. GFCIs are currently required to be used in all kitchens, baths, garages, and outdoor areas according to the National Electrical Code.

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A current-carrying ohmic metal wire has a cross sectional area that gradually becomes smaller from one end of the wire to the other. The current has the same value for each section of the wire, so charge does not accumulate at any one point. How does the resistance per unit length vary along the wire as the area becomes smaller?.

Answers

The cross-sectional area decreases, so the resistance per unit length,  increases

What is resistance ?

The limitation of current flow in an electrical circuit is measured in terms of resistance. The ohm, or the Greek letter omega, stands for the unit of measurement for resistance.

According to the given information

We know that

Resistance of the wire is directly proportional to length of the wire and inversely proportional to the area of the wire

So,

R ∝ [tex]\frac{L}{A}[/tex]

Proportionality constant ρ = resistivity constant

R = ρ[tex]\frac{L}{A}[/tex]

So If the cross sectional area decreases , Resistance per unit length increases

brainly a child on a swing set swings back and forth with a period of 3.3 s and an amplitude of 25°. what is the maximum speed of the child as she swings?

Answers

Maximum speed of the child as she swings is  2.23 m/s.

Step by Step Calculation:

T=3.3 s is the oscillation's time period.

The swing's greatest angle is 25° (max).

The swing's bottom will have the following kinetic energy:

k=12mv2...........(1)

The mass in this situation is m, and the speed is v.

The potential energy change is expressed as,

∆U=mgL1-cosθmax...............(2)

Here, L is a string's length and g is the acceleration caused by gravity. L is given as,

L=gT24π2

Combine equation (1) with (2)

12mv2=mgL1-cos, maxv=2g, maxv=gT24, maxv=g2T22, maxv=9.8 m/s

22.33 m/s, 22.31 s22.31 cos25°

Therefore, the child's top speed is 2.23 m/s.

What is Oscillation ?The process of any quantity or measure fluctuating repeatedly about its equilibrium value in time is known as oscillation.A periodic change in a substance's value between two values or around its central value is another way to define oscillation.

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a 915 kg car goes over a hill of circular arc. if the radius of the curve is 43 m, how fast can the car travel without leaving the road at the top of the arc?

Answers

The car can travel at 20.5 m/s (74 km/hr). Any faster, and it will leave the road.

What is speed?

Velocity is the pace and direction of an object's movement, whereas speed is the time rate at which an object travels along a path. In other words, velocity is a vector, whereas speed is a scalar value.

According to the question:

Two forces—gravity and the normal force of the road—are acting on the car as it crests the hill. These combined exert a net centripetal force, which will cause the car to travel in a circular arc.

[tex]$$\vec{F}_c=\vec{F}_g+\vec{F}_N$$[/tex]

Next, realize that "without leaving the road" actually refers to "just at the point where the car is going to leave the road" and that this corresponds to the condition FN = 0.

This means that our equation becomes

[tex]$$F_c=F_g$$[/tex]

and that gravity alone will determine the radius of the path the car will follow.

Substituting [tex]$F_c=\frac{m v^2}{r}$[/tex] and [tex]$F_g=m g$[/tex], we get

[tex]$$\frac{m v^2}{r}=m g$$[/tex]

Since we don't observe small, light automobiles flying airborne more frequently than larger ones, we can cancel the mass, which means that all cars traveling at this speed will follow the same course regardless of mass.

[tex]$$\begin{aligned}& \frac{v^2}{r}=g \\& v=\sqrt{g r}\end{aligned}$$[/tex]

After Substituting the values:

[tex]$$v=\sqrt{(9.8)(43)}=20.5 m/s}$$[/tex]

So, the car can travel at 20.5 m/s (74 km/hr).

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