Answer:
1.5 Ampere
Explanation:
The formula is V=IR
so now we can derive out the formula which is
I =V
R
I = 6
4
I = 1.5 Ampere
The harder a gas pedal in a car is pressed the faster the car's velocity increases. Which phrase best describes the relationship between how hard the gas pedal is pressed and the acceleration of the car?
A. There is both a negative correlation and causation
B. There is a positive correlation but no causation.
C. There is a negative correlation but no causation.
D. There is both a positive correlation and causation.
Answer:
D
There is both a positive correlation and causation
The relationship between how hard the gas pedal is pressed and the acceleration of the car is positive correlation and causation.
From the given statement the relationship between the cause (pedal) and the effect (velocity) can be described as direct relationship.
In direct proportionality, the outcome of one variable produces similar effect to the other variable.The harder the gas pedal in a car is pressed, the velocity increases. This shows that as the force applied to the gas pedal increases (the cause of the action), the greater the velocity of the car (the effect of the cause).
Thus, we can conclude that the relationship between how hard the gas pedal is pressed and the acceleration of the car is positive correlation and causation.
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A kitten runs 24 x 10⁻² m away from its master in a straight line in 12.6 s, and then run halfway back in one-third the time. Calculate its average velocity.
Answer:
1.43 × 10^-2 m/s
Explanation:
Given the following :
Distance covered away from it's master = D1 = 24×10^-2 m
Time taken to cover the distance = t1 = 12.6s
Then runs halfway back D2 =
D1/ 2 = (24× 10^-2m) / 2 = 12 ×10^-2m
Time taken =T2 = T1/3 = 12.6/3 = 4.2s
Since the kitten ran in a straight line, the it is linear :
Average speed
Linear Average Velocity:
Change in distance / change in time
(D1 - D2) / (T2 - T1)
(24 - 12)×10^-2 / (12.6 - 4.2)
(12 × 10^-2)m / 8.4s
1.4285 × 10^-2
= 1.43 × 10^-2m/s
As the frequency of the ac voltage across an inductor approaches zero, the inductive reactance of that coil Group of answer choices
Answer:
The inductive reactance also approaches zero
Explanation:
This is because from the relation
XL = 2πfL
Meaning frequency f and inductive reactance XL are directly proportional so as one approaches zero so does the other
To whom does the vha provide care for today ?
Answer:
The Veterans Health Administration (VHA) is the largest integrated health
care system in the United States, providing care at 1,255 health care
facilities, including 170 VA Medical Centers and 1,074 outpatient sites of care
of varying complexity ( VHA outpatient clinics) to over 9 million Veterans
enrolled in the VA .
If a baseball travels a distance of 4 meters in 5 seconds, what is its average speed
Answer:
speed=d/t.
s=4/5=0.8m/s.
If you were to drop a rock from a tall building, assuming that it had not yet hit the ground, and neglecting air resistance, after 10 s: How fast (speed) would it be traveling (in m/s)
Answer:
Explanation:
Using the equation of motion v = u + at to get the speed at which the object would be travelling.
v is the final speed (in m/s)
u is the initial velocity (in m/s)
a is the acceleration (in m/s²)
t is the time taken (in secs)
Given parameters
u = 0m/s
t = 10s
a = g = 9.8m/s²
Substituting this values into the formula;
v = 0+9.8(10)
v = 0+ 98
v = 98m/s
Hence the rock will be travelling at a speed of 98m/s.
Calculate the kinetic energy of an 88-kg scooter moving at 12 m/s .
Answer:
kinetic energy = 1/2 X m(v)^2
= 1/2 X 88 X 12
= 528 j
Your question has been heard loud and clear.
Kinetic energy formula= 1/2mv^2
Mass = 88kg (convert to grams because velocity is in m/s)
Mass in grams = 88000g or 88*10^3 g
Velocity= 12m/s
Now kinetic energy = 1/2 * 88000*12*12= 6336 joules
Kinetic energy = 6336 Joules or 6.336 Kilo joules
Thank you.
A 7600 kg satellite is in a circular orbit around Earth at a height of 2300 km above Earth's surface. What is this satellite's speed
Answer:
6779.7m/s
Explanation:
Using
GMm/(Re +h)² = mv²/ (Re+h)
So making v subject we have
V= √GM/Re+h
So
V = √ 6.67*10^-11 x 5.97*10^24/(6371+2300)*10^3
V= 6779.7m/s
Note h = height of satellite
Re= radius of the earth
M = mass of the earth
If a proton and an electron are released when they are 7.00×10−10 m apart (typical atomic distances), find the initial acceleration of each of them. aelectron = nothing m/s2
Answer:
The acceleration of the proton is 2.823 x 10¹⁷ m/s²
The acceleration of the electron is 5.175 x 10²⁰ m/s²
Explanation:
Given;
distance between the electron and proton, r = 7 x 10⁻¹⁰ m
mass of proton, [tex]m_p[/tex] = 1.67 x 10⁻²⁷ kg
mass of electron, [tex]m_e[/tex] = 9.11 x 10⁻³¹ kg
The attractive force between the two charges is given by Coulomb's law;
[tex]F = \frac{k(q_p)(q_e)}{r^2}[/tex]
where;
k is Coulomb's constant = 9 x 10⁹ Nm²/c²
[tex]F = \frac{k(q_p)(q_e)}{r^2} \\\\F = \frac{(9*10^9)(1.602*10^{-19})(1.602*10^{-19})}{(7*10^{-10})^2} \\\\F = 4.714 *10^{-10} \ N[/tex]
Acceleration of proton is given by;
F = ma
[tex]F = m_pa_p\\\\a_p = \frac{F}{m_p}\\\\a_p = \frac{4.714*10^{-10}}{1.67*10^{-27}}\\\\a_p = 2.823 *10^{17} \ m/s^2[/tex]
Acceleration of the electron is given by;
[tex]F = m_ea_e\\\\a_e = \frac{F}{m_e}\\\\a_e = \frac{4.714*10^{-10}}{9.11*10^{-31}}\\\\a_e = 5.175 *10^{20} \ m/s^2[/tex]
Given:
Mass of proton, [tex]m_p = 1.67\times 10^{-27} \ kg[/tex]Mass of electron, [tex]m_e = 9.11\times 10^{-31 } \ kg[/tex]Distance between electron & proton, [tex]r = 7\times 10^{-10} \ m[/tex]By using Coulomb's law, the attractive force will be:
→ [tex]F = \frac{k(q_p) (q_e)}{r^2}[/tex]
By substituting the values, we get
[tex]= \frac{(9\times 10^9)(1.602\times 10^{-19}) (1.602\times 10^{-19})}{(7\times 10^{-10})^2}[/tex]
[tex]= 4.714\times 10^{-10} \ N[/tex]
Now,
The acceleration of proton will be:
→ [tex]F = ma[/tex]
[tex]= m_p a_p[/tex]
or,
→ [tex]a_p = \frac{F}{m_p}[/tex]
[tex]= \frac{4.714\times 10^{-10}}{1.67\times 10^{-27}}[/tex]
[tex]= 2.823\times 10^{17} \ m/s^2[/tex]
and,
The acceleration of electron will be:
→ [tex]F = m_c a_c[/tex]
or,
→ [tex]a_e = \frac{F}{m_e}[/tex]
[tex]= \frac{4.714\times 10^{-10}}{9.11\times 10^{-31}}[/tex]
[tex]= 5.175\times 10^{20} \ m/s^2[/tex]
Thus the above answer is correct.
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When a circuit is arranged in parallel
A. There are multiple paths that electrons can take through the circuit, and it is possible for the electron to pass through one circuit component but not another.
B. There is only one path the electrons can take through the circuit, and they must pass through all circuit components
Answer:
A. There are multiple paths that electrons can take through the circuit, and it is possible for the electron to pass through one circuit component but not another.
Explanation:
Parallel arrangement of components in an electric circuit puts different parts of the circuit on different branches. In a parallel connection, there are multiple paths for the electrons to take, and it is possible for electrons to pass through on circuit component without going through another. This is the reason why If there is a break in one branch of the circuit, electrons can still flow in other branches, and the same reason why one bulb going off in your home does prevent the other components in your home from coming on (your home is wired in a parallel electric circuit).
You want to create an electric field vector E = < 0, 5 104, 0> N/C at location < 0, 0, 0>. Where would you place a proton to produce this field at the origin?
Answer:
1.696 × 10^(-7) m on the y axis.
Explanation:
We are given the electric field as;
E = < 0, 5 × 10⁴, 0> N/C
This is written in (x, y, z) co-ordinates. So it means that it lies on the y-axis.
So,
E = 5 × 10⁴ N/C in the y direction.
Formula for Electric field is;
E = kq/r²
where;
k is a constant with a value of 8.99 x 10^(9) N.m²/C²
q is charge on the proton = 1.6 × 10^(-19) C
r is the distance
Thus, making r the subject gives;
r = √(kq/E)
Plugging in the relevant values gives;
r = √(8.99 × 10^(9) × 1.6 × 10^(-19)/(5 × 10⁴))
r = 1.696 × 10^(-7) m on the y axis.
The proton to produce this field at the origin should be put on [tex]1.696 \times 10^{(-7)} [/tex]m on the y axis.
The calculation is as follows:We are given the electric field as;
[tex]E = < 0, 5 \times 10^{4}, 0> N/C[/tex]
This is written in (x, y, z) co-ordinates. So it means that it lies on the y-axis.
So,
[tex]E = 5 \times 10^{4} N/C[/tex] in the y direction.
The Formula for Electric field is;
E = kq/r²
where;
k is a constant with a value of 8.99 x 10^(9) N.m²/C²
q is charge on the proton = 1.6 × 10^(-19) C
r is the distance
Thus, making r the subject gives;
r = √(kq/E)
Now Plugging in the relevant values gives;
r = √(8.99 × 10^(9) × 1.6 × 10^(-19)/(5 × 10⁴))
r = 1.696 × 10^(-7) m on the y axis.
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Tim can type 2,000 words at a speed of 50 words per min.
Bob's typing speed is 80 words per min. How much less time
did Bob take than Tim to type 2000 words?
min
h
Answer: the awnser to this question is 15
Explanation:
First you will divide the typing speed and the total number of words by the speed 2000 ÷ 50
Then divide bobs typing speed by 2000 equation 2000÷80 once you get the total both you will subtract the 2 totals together and get 15 as your awnser.
Hoped this helped!
A car traveling at 7 m/s accelerates at a rate of -0.8 m/s for an interval of 2 seconds.
Find the final velocity.
The nosition of a ninewood derhucar a ohraniodaturi
Answer:
6.2m/s
Explanation:
v=u+at
v=7+(-0.8/2)(2)
v=7-0.8
v=6.2m/s
"If we increase the amplitude of transverse waves on a string, what happens to the speed of a wave along the string?"
Answer:
It is increased
Explanation:
If the amplitude of a transverse wave in a string is increased, then also, the speed of that wave along the string also increases.
In transverse waves, the particles of the medium does move vertically, m either up or down and also moves at right angles to the direction of the wave. It should be noted also, that the wave amplitude of a transverse wave is defined as the difference in height between the crest(high) and the resting position(low).
The highest point particles of the medium reach is often tagged as the crest, while the lowest point is tagged as the resting position. The higher the height of the crests are, the greater the amplitude of the wave will be.
Why are experimental investigations the best type of scientific investigation o demonstrat cause-and-effect relationships?
Answer:
Isolation of Variables.
Explanation:
I am just taking a guess but Experimental investigations allow you to isolate variables (making most variables constant, allowing only the independent variable to have an impact on the dependent variable). With other scientific investigations, if they don't isolate the variables it is very possible that an unknown third variable could be skewing the results (which will result in correlation but not causation).
Answer:
Experimental investigations are the best type of scientific investigation to demonstrate cause-and-effect relationships because they allow the investigator to actively manipulate variables and control conditions. The independent variable can be isolated and manipulated, producing a change (or no change) in the dependent variable. This change can be measured to gather evidence to support or refute the cause-and-effect relationship. Experimental investigations also use a control group (a group that does not receive the factor being tested) for comparison.
Explanation:
Automated-response....it's right
In the absence of government, what would determine the way people act towards each other?
Answer:
In the absence of government, what would determine the way people act towards each other is the need to acquire means of survival such as food or shelter.
Thus, since the government regulates the rights and obligations of citizens to guarantee equal access to essential services and goods for life, in the event of the disappearance of the state as a form of social organization, people would tend to act selfishly. to provide itself with those goods and services.
Society would then return to a state of nature, where man competes with his peers for access to resources. So the need for those resources would ultimately determine the way humans relate to each other.
Throughout the absence of regulation, the necessity to gain means of subsistence, which includes extra help, would decide how individuals interact with one another.
Absence of Government:
As a consequence, while the organization governs individuals' rights and duties purpose of providing equitable access to vital services and products for life, if the community as more than just a form of social organization disappears, individuals might likely behave selfishly to offer such commodities.
The community would therefore revert to its natural condition, with man competing with equal fellows for distribution of wealth. As a result, the necessity for such resources would eventually decide how humans interact with one another.Thus the response above is right.
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Which of these equations is dimensionally correct?
I. mv/ t= F
II. xv^2= Fx^3/ x^2
III. xt= vt^2+at^3
Answer: first and third.
Explanation:
An equation is dimensionally correct if the units are the same in both sides of the equation.
first, let's define the units used:
{m} = kg
{v} = m/s
{F} = kg*m/s^2
{x} = m
{t} = s
{a} = m/s^2
Now, let's analyze each option:
1) m*v/t = F
in the left side the units are:
{m}*{v}/{t} = kg*(m/s)*(1/s) = kg*m/s^2
And as is written above, these are the units of F, so this is correct.
2) x*v^2 = F*(x^3/x^2)
This is more trivial, in the right side we can see an F, that has mass units (kg) and in the left side we have x and v, and we know that none of these have mass units, so this expression is not correct.
3) xt= vt^2+at^3
the units in the right side are:
{x}*{t] = m*s
in the right side are:
{v}*{t}^2 + {a}*{t}^2 = (m/s)*s^2 + (m/s^2)*s^3 = m*s + m*s
So in both sides of the equation we have the same units, then this equation is dimensionally correct.
The electric flux through a spherical surface is 1.4 ✕ 105 N · m2/C. What is the net charge (in C) enclosed by the surface?
Answer:
The value is [tex]Q_{net} = 1.239 *10^{-6} \ C[/tex]
Explanation:
From the question we are told that
The electric flux is [tex]\Phi = 1.4*10^{5} \ N\cdot m^2/C[/tex]
Generally the net charge is mathematically represented as
[tex]Q_{net} = \Phi * \epsilon_o[/tex]
Here [tex]\epsilon_o[/tex] is the permetivity of free space with value
[tex]\epsilon_o = 8.85*10^{-12} \ \ m^{-3} \cdot kg^{-1}\cdot s^4 \cdot A^2[/tex]
So
[tex]Q_{net} = 1.4*10^5 * 8.85*10^{-12}[/tex]
=> [tex]Q_{net} = 1.239 *10^{-6} \ C[/tex]
What is the power in D of the eyes of a woman who can see an object clearly at a distance of only 9.5 cm
Answer:
Explanation:
It is the far point an myopic person . For it she uses concave lens . For her ,
object distance u = infinity
image v = - 9.5 cm
f = ?
form the lens formula
[tex]\frac{1}{f} = \frac{1}{v} - \frac{1}{u} \\[/tex]
[tex]\frac{1}{f} = \frac{1}{-9.5} - 0 \\[/tex]
f = - 9.5 cm = - 9.5 / 100 m
P = 1 /f = - 100 / 9.5 = - 10.52 D .
Unless indicated otherwise, assume the speed of sound in air to be v = 344 m/s. You blow across the open mouth of an empty test tube and produce the fundamental standing wave of the air column inside the test tube. The speed of sound in air is 344 m/s and the test tube acts as a stopped pipe. Required:a. If the length of the air column in the test tube is 14.0 cm, what is the frequency of this standing wave? b. What is the frequency of the fundamental standing wave in the air column if the test tube is half filled with water?
Answer:
a
[tex]f = 614.3 \ Hz[/tex]
b
[tex]f_h = 1229 \ Hz[/tex]
Explanation:
From the question we are told that
The speed of sound in the air is [tex]v_s = 344 \ m/s[/tex]
The length of the test tube is [tex]l = 14.0\ cm = 0.14 \ m[/tex]
Since the test tube is closed at on end the frequency is mathematically represented as
[tex]f = \frac{v_s}{ 4 l }[/tex]
=> [tex]f = \frac{344}{ 4 * 0.14 }[/tex]
=> [tex]f = 614.3 \ Hz[/tex]
From the part B the column of the test tube is half filled with water so the frequency becomes
[tex]f_h = \frac{v_s}{ 2 l }[/tex]
[tex]f_h = \frac{344}{ 2 * 0.14}[/tex]
[tex]f_h = 1229 \ Hz[/tex]
To conduct a study on depression, you ask people to rate their depression on
a scale of 1 to 10. Their responses are a(n) ___ in your study.
A. discrete variable
B. hidden variable
C. variable
D. observation
Answer:
The answer is C variable. Just took the quiz.
Explanation:
Answer:
C. variable
Explanation:
a net external force of 100.0 N acts on an object of mass 20.0 kg whose initial speed is 10.0 m/s. The force acts in the opposite direction from the objects motion, and it acts for 1.00 s. what is the objects final speed in m/s
Explanation:
We know that :
[tex]F = m\frac{(v - u)}{t} [/tex]
[tex]100 = 20 \frac{(v - 10)}{1} [/tex]
[tex]v(final \: velocity) = 15 \: m \: sec^{ - 1} [/tex]
A graph of x vs. t2 is linear, and intercepts the vertical axis at 12 m and the horizontal axis at 4 s2. What is the function?
Answer:
x = -3t² + 12
Explanation:
x vs t² is a line.
x = at² + b
The y intercept is 12.
x = at² + 12
At t² = 4s², x = 0.
0 = a(4) + 12
a = -3
Therefore, the function is:
x = -3t² + 12
Find the value of x in the triangle shown below.
9
C
3
A spaceship is traveling through deep space to a space station and needs to make a course correction to go around a nebula. The captain orders the ship to travel 2.3 106 kilometers before turning 70° and traveling 1.5 106 kilometers to reach the space station. If the captain had not ordered a course correction, what would have been the magnitude and direction of the path of the spaceship if it had traveled to the space station through the nebula?
Answer:
Explanation:
Using the given values
Let
Px= 2.3 x 10^6, Py=0, Qx=1.5x10^6cos(70),
Qy= 1.5x10^6sin(70)
So let
Hx= Px+Qx=2.813 x 10^6, Hy=Py+Qy=1.401 x 10^6
Magnitude = √ ((2.813 x 10^6)^2+(1.401 x 10^6)^2)= 3.14 x 10^6
To find direction
tan စ = Hy/Hx = 1.401/2.813= 0.4980
စ = 26.5°
The magnitude and direction of the path of the spaceship if it had traveled to the space station through the nebula are 3.14 x 10⁶ m and 26.5°.
What is nebula?A nebula is a huge cloud consisting of dust and gas in space. Some nebula come from the gas and dust thrown out by the explosion of a dying star known as a supernova.
The captain orders the ship to travel in horizontal direction, Px= 2.3 x 10⁶ m, Py=0,
After turning 70° and it travels to reach the space station, Qx = 1.5x10⁶ x cos70° in horizontal direction.
and Qy= 1.5x10⁶sin70°
So, total horizontal distance moved is
Hx= Px+Qx = 2.813 x 10⁶
Total vertical distance moved is
Hy=Py+Qy = 1.401 x10⁶
Magnitude of the path = sq rt [(2.813 x 10⁶)²+(1.401 x 10⁶)²]
Path = 3.14 x 10⁶ m
Direction of the path,
tan α = Hy/Hx
tan α = 1.401/2.813
tan α = 0.4980
α = 26.5°
Thus, the magnitude and direction of the path of spaceship is 3.14 x 10⁶ m and 26.5°.
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when would a swimmer have the most potential energy due to her position
Answer: A
Explanation:
A swimmer have the most potential energy due to her position.When he is sitting on the highest diving board at the pool.
What is potential energy?The potential energy is the due to the virtue of the position and the height. The unit for the potential energy is joule.
The potential energy is found as;
[tex]\rm PE = mgh[/tex]
The potential energy is mainly depending upon the height of the object.
When the swimmer is at the highest position, the height is maximum. Therefore, the potential energy is also maximum.
Hence, a swimmer have the most potential energy due to her position.When he is sitting on the highest diving board at the pool.
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State two precautions each that you will take while performing refractive index of a glass box experiment
Answer:
light should be direct
glass should not be cracked
pins should be pointed carefully
Explanation:
which component of health related fitness is developed by performing a wall sit
Answer:
it develop isometric strength and endurance in glutes calves quadriceps,hamstring and adductor muscle
Identify two types of motion where an object's speed remains the same while it continues to change direction.
Answer:
circular motionmotion of light (photons) on a non-linear pathExplanation:
Velocity is a vector with speed and direction components. If the speed does not change, then the direction must. In order to change the direction of a velocity vector, there must be some acceleration, and it must be orthogonal to the direction of motion.
Circular motion is motion that has a constant acceleration perpendicular to the direction of travel.
__
Another kind of motion that meets the requirement is the motion of light. Light travels at a constant speed, regardless. If light changes direction (as in a gravitational field or when reflected), its direction will change, but its speed will not.
What is the momentum of a tiger that has a mass of 81 kg and runs with a velocity of 5.4 m/s to the east
Given :
Mass of tiger , m = 81 kg .
Velocity of tiger , v = 5.4 m/s .
To Find :
The momentum of tiger .
Solution :
We know , momentum of a body is given by the product of its mass and velocity .
[tex]P=m\times v[/tex]
Now , putting value of m and v in above equation , we get :
[tex]P=m\times v\\\\P=81\times 5.4 \ kg\ m/s\\\\P=437.4 \ kg\ m/s[/tex]
Therefore , the momentum of tiger is 437.4 kg m/s .
Hence , this is the required solution .
Answer:
437.4
Explanation: did the math