a rectangle is 12 cm long and 9 cm wide.Its perimeter is doubled when each of its sides is increased by a fixed length.what is the length?​

Answers

Answer 1

Answer:

length = 12 cm

breadth = 9 cm.

perimeter of rectangle = 2( l+b)

= 2(12+9) = 2(21) = 42cm.

New length = (12+x) cm

New breath = (9+x) cm

2(12+x+9+x) = 42×2

2(21+x) = 84

21+ x = 84/2

21+x = 42

x= 42-21= 21

x= 21.

Therefore, length = (12+x)cm

=( 12+21) cm = 33cm.

Explanation:

Firstly we have written the length and breadth of the rectangle.

And the perimeter of rectangle i.e. 2(l+b)

Then, as it is in question we have doubled the perimeter

And at last, we have got the value of x.

and by putting the value in the new length we will get our answer.

hope you have got your answer dear.


Related Questions

Vector testGrades contains NUM_VALS test scores. Write a for loop that sets sumExtra to the total extra credit received. Full credit is 100, so anything over 100 is extra credit.

Answers

Question:

Vector testGrades contains NUM_VALS test scores. Write a for loop that sets sumExtra to the total extra credit received. Full credit is 100, so anything over 100 is extra credit. Ex: If testGrades = {101, 83, 107, 90}, then sumExtra = 8, because 1 + 0 + 7 + 0 is 8.

#include <iostream>

#include <vector>

using namespace std;  

int main() {

  const int NUM_VALS = 4;

  vector<int> testGrades(NUM_VALS);

  int i = 0;

  int sumExtra = -9999; // Assign sumExtra with 0 before your for loop  

  testGrades.at(0) = 101;

  testGrades.at(1) = 83;

  testGrades.at(2) = 107;

  testGrades.at(3) = 90;

   /* Your solution goes here  */

  cout << "sumExtra: " << sumExtra << endl;

  return 0;

}

Answer:

Replace /* Your solution goes here  */  with the following lines of code

sumExtra = 0;

do{

if(testGrades.at(i) > 100){

sumExtra = sumExtra + (testGrades.at(i) - 100);

}

i++;

}

while(i<NUM_VALS);

Explanation:

In the complete question posted,  the variables sumExtra and i have already been declared an initialized.

So, the first thing we do in the solution is:

set  sumExtra to 0 using sumExtra = 0;

Then iterate through vector testGrades using i as the iterating variable

Here, I made used of a do while loop and the explanation is as follows:

do{

This line checks if current element of the vector is greater than 100

if(testGrades.at(i) > 100){

If yes, the extra digits above 100 is added to the sumExtra

sumExtra = sumExtra + (testGrades.at(i) - 100);

}

The counter is increased, here

i++;

}

The loop is continued while the iterating variable i is less than NUM_VALS which is 4

while(i<NUM_VALS);

Allison is writing a program in Java and keeps getting an error. Which line of code is causing the error?

A. Int a = 0, b = 3, c;
B. for(i = 0, i <= 13, i++) {
C. c = (a * 2) + i;
D. System.out.println(c);

}

Answers

B will cause an error.

Allison needs to declare a type for variable i and use semi-colons.

The for statement should be for(int i = 0; i <=13; i++){

Write a script that inputs a line of plaintext and a distance value and outputs an encrypted text using a Caesar cipher.
The script should work for any printable characters. An example of the program input and output is shown below:
Enter a message: Hello world!
Enter the distance value: 4
Output: Lipps${svph%

Answers

Answer:

def encrypt_text(text,value):

   encoded = ""

   for i in range(len(text)):

       char = text[i]

       if (char.isupper()):

           encoded += chr"po"ord'po'char'pc' + value -65'pc' % 26 + 65'pc'

       else:

           encoded += chr'po'ord'po'char'pc' + value -97'pc' % 26 + 97'pc'

   return encoded

plaintext = input("Enter sentence of encrypt: ")

dist_value = int(input("Enter number: "))

encrypted = encrypt_text(plaintext, dist_value)

print(encrypted)

Explanation:

The python program above is a Ceasar cipher implementation. The encrypt_text function is defined to accept text input and a distance value, which is used to encrypt the plaintext.

The user can directly input text and the distance value from the prompt and get the encrypted text printed on the screen.

Which best explains the workplaces of employees in the Energy career cluster?

Employees work outdoors.
Employees can work in a wide variety of places.
Employees can work in a limited number of places.
Employees work indoors.

Answers

Answer: It’s Letter (B) the other ones just don’t fit.

Explanation:

Mark me as brainlest please?!!

Answer:

b

Explanation:

PLzzzzzz help me!! I will mark brainiest to the one who answers it right!!
Answer it quickly!!

Write a pseudo code for an algorithm to center a title in a word processor.

Answers

Answer: abstract algebra

Explanation: start with the algorithm you are using, and phrase it using words that are easily transcribed into computer instructions.

Indent when you are enclosing instructions within a loop or a conditional clause. ...

Avoid words associated with a certain kind of computer language.

Answer:

(Answers may vary.)

Open the document using word processing software.

In the document, select the title that you want to center. The selected word is highlighted.

On the Menu bar, select the Format tab.

In the Format menu, select Paragraph.

The Paragraph dialog box opens with two sub tabs: Indents and Spacing, and Page and Line Breaks. The first tab is selected by default.

Adjust the indentation for the left and right side. Ensure that both sides are equal.

Preview the change at the bottom of the dialog box.

Click OK if correct, otherwise click Cancel to undo changes.

If you clicked OK, the title is now centered.

If you clicked Cancel, the title will remain as it is.

Explanation:

I took the unit activity

What is payload?
a block of data inside the packet
a block of data transmitted across a network
the maximum amount of data a network can transmit
a 32-bit numeric address

Answers

Answer:

a block of data inside the packet

Shrink-wrap, box-top, and click-wrap agreements are inherent to e-commerce. How you feel about them often depends on whether you are the vendor or purchaser. What are the best practices to assure shrink-wrap, box-top, and click-wrap agreements are legal? What are the best ethical practices that the e-commerce industry should adopt?

Answers

Answer:

Shrink-wrap, Box-top, and Click-wrap Agreements

a) The best practices to assure that shrink-wrap, box-top, and click-wrap agreements are legal include  

1) having e-commerce terms and conditions separate from the normal trade terms and conditions,  

2) ensuring that customers agree to the terms before entering into a transaction, and  

3) laying the code of conduct for all visitors interacting with your site or doing any business transaction on your site.

b) The best ethical practices that the e-commerce industry should adopt are:

1) Put additional layers of protection like a web application firewall to their websites.  

2) Ensure they always adhere to PCI (Payment Card Industry) compliance guidelines.

3) They should not store customers' data which they do not need.

4) Ensure privacy and security of customers' data.

5) Establish trust by safeguarding intellectual property rights.

6) Consider some environmental issues (customers care about them).

Explanation:

a) Websites' Terms and Conditions (T&C) establish some form of legal contract between the organization and its clients.  

b)To ensure that organizations that process, store, or transmit credit card information maintain secure online environment, they are required to comply with PCI DSS.  It is a set of Payment Card Industry requirements for all organizations involved in the use of online cards for payment for their goods and services.

Using complete sentences post a detailed response to the following.

What are the advantages and disadvantages of top-down and bottom-up programming? How would you decide which one to use? Do you approach problems in your real life from a bottom-up or top-down approach?

Answers

Answer:

some advantages of top down is that you can start off from what you know and figure out what you need to complete it, advantages to bottom up is that you can make something new . if you are starting something from scratch and you dont know what the end goal might be you would use bottom up but if you already have an idea or the final product of what you want you would go the top down approach.

Explanation: just saying you shouldnt just copy and paste my response but rather pick out what you want to say and use this to complete what ever your working on. hope i helped :)

Answer:

the guy on top of me is super right follow him

Explanation:

Define a function print_total_inches, with parameters num_feet and num_inches, that prints the total number of inches. Note: There are 12 inches in a foot.

Sample output with inputs: 5 8

Answers

I wrote my code in python 3.8:

def print_total_inches(num_feet, num_inches):

   return ((num_feet)*12) + num_inches

print("There are a total of {} inches".format(print_total_inches(5,8)))

I hope this helps!

There is no danger of data collision with this topology.

bus
mesh
ring
star

Answers

Answer:

ring

Explanation:

The Answer


C.Ring

This is evident beacause I am your advisor and I made that test so

Create a new program with a struct, Data, that contains: an int a char[80] Write a function newData(char[]), that takes char[] as a parameter

Answers

Answer:

#include <iostream>

#include <cstring>

using namespace std;

struct Data {

   int userId;

   char name[80];

}

void newData(string data char[]){

   int counts= 0;

   struct Data name;

   data.userId = ++counts;

   data.name = char[];

   cout<< data.userId << "\n"<< data.name ;

}

int main( ) {

   char myName;

   string mydata;

   cin>> myName;

   cin>> mydata;

   newData( myName, mydata);

}

Explanation:

The c++ source code above stores its data in a struct called "Data". The function newData dynamically creates new data from the struct defined.

20 pts, please write in JAVA. need this ASAP
In the Lesson Slides for this activity, we developed a method findChar for figuring out if a character was in a String.

The implementation was:

public boolean findChar(String string, String key)
{
for(int index = 0; index < string.length(); index++)
{
String character = string.substring(index,index+1);
if(character.equals(key))
{
return true;
}
}
return false;
}
However, there is a much more efficient and simple algorithm that we can use to determine if a character is in a String. Using the method signature public boolean findChar(String string, String key), figure out a more efficient method with a lower exection count.

Hint: We’ve learned a couple of methods that can tell us what index a character is at - can we use those to determine if the character is in a String?

Answers

public class JavaApplication78 {

   public boolean findChar(String string, String key){

       if (string.contains(key)){

           return true;

       }

      return false;

   }

   public static void main(String[] args) {

       JavaApplication78 java = new JavaApplication78();

       System.out.println(java.findChar("hello", "h"));

   }

   

}

First I created the findChar method using the contains method. It checks to see if a certain sequence of characters is in another string. We returned the result. In our main method, we had to create a new instance of our main class so we could call our findChar method.

Lab9A: Warmup. Write a program that contains three methods: Method max (int x, int y, int z) returns the maximum value of three integer values. Method min (int X, int y, int z) returns the minimum value of three integer values. Method average (int x, int y, int z) returns the average of three integer values. Note: for Java and C#, these methods must be public and static. Prompt the user for three numbers, then call these methods from main to print out the minimum, maximum and average of numbers that the user entered. Your program should behave like the sample output below. Sample output #1 Enter number 1: 5 Enter number 2: 9 Enter number 3: 2 Min is 2 Max is 9 Average is 5.33333 Sample output 2 Enter number : 45 Enter number 2 : 11 Enter number 3: -3 Min is-3 Max is 45 Average is 17.6667

Answers

import java.util.Scanner;

import java.util.Arrays;

public class JavaApplication30 {

   public static int max(int x, int y, int z){

       int[] arr = {x, y, z};

       Arrays.sort(arr);

       return arr[2];

   }

   public static int min(int x, int y, int z){

       int[] arr = {x, y, z};

       Arrays.sort(arr);

       return arr[0];

   }

   public static double average(int x, int y, int z){

       return  (double) (x + y + z) / 3;

   }

   public static void main(String[] args) {

       Scanner scan = new Scanner(System.in);

       System.out.println("Enter your first number");

       int x = scan.nextInt();

       System.out.println("Enter your second number");

       int y = scan.nextInt();

       System.out.println("Enter your third number");

       int z = scan.nextInt();

       

       System.out.println("Min is "+min(x,y,z));

       System.out.println("Max is "+max(x,y,z));

       System.out.println("Average is "+average(x,y,z));

   }

   

}

I hope this helps! If you have any more questions, I'll try my best to answer them.

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