i think its c im not sure
A reaction is moving most slowly when its reactant/product mix is 90% product, 10% reactant. Hence Option (A) is correct.
What is Rate of reaction ?
The reaction rate or rate of reaction is the speed at which a chemical reaction takes place, defined as proportional to the increase in the concentration of a product per unit time and to the decrease in the concentration of a reactant per unit time.
Therefore, A reaction is moving most slowly when its reactant/product mix is 90% product, 10% reactant. Hence Option (A) is correct.
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Suppose that you add 27.6 g of an unknown molecular compound to 0.250 kg of benzene, which has a K f of 5.12 oC/m. With the added solute, you find that there is a freezing point depression of 3.69 oC compared to pure benzene. What is the molar mass of the unknown compound
Answer:
The molar mass of the unknown compound is 153.3 g/mol
Explanation:
Step 1: Data given
Mass of an unknown molecular compound = 27.6 grams
Mass of benzene = 0.250 kg
Kf of benzene = 5.12 °C/m
freezing point depression of 3.69 °C
Step 2: Calculate molality
ΔT = i*Kf*m
⇒with ΔT = reezing point depression of 3.69 °C
⇒with i = the van't Hoff factor of Benzene = 1
⇒with Kf = 5.12 °C/m
⇒ with m = molality = moles unknown compound / mass of benzene
3.69 = 1 * 5.12 * m
m = 0.72 molal
Step 3: Calculate moles of the unknown compound
molality = moles / mass benzene
0.72 molal = moles / 0.250 kg
Moles = 0.72 m * 0.250 kg
Moles = 0.18 moles
Step 4: Calculate molar mass of the unknown compound
molar mass = mass / moles
Molar mass = 27.6 grams / 0.18 moles
Molar mass = 153.3 g/mol
The molar mass of the unknown compound is 153.3 g/mol
Molar mass is the mass of the one mole of substance. The molar mass of the given unknown compound is 153.3 g/mol.
Molality of the compound can be calculated using
ΔT = i Kf m
Where,
ΔT = freezing point depression = 3.69 °C
i = Van't Hoff factor of Benzene = 1
Kf = constant of freezing = 5.12 °C/m
m = molality = ?
Put the values in the equation,
3.69 = 1 x 5.12 x m
m = 0.72 molal
Number of moles of the compound,
[tex]\bold {molality =\dfrac { moles} { mass\ benzene}}\\\\\bold {0.72\ molal = \dfrac {moles }{0.250\ kg}}\\\\\bold {Moles = 0.72\ m \times 0.250\ kg}\\\\\bold {Moles = 0.18}[/tex]
So, molar mass of the unknown compound,
[tex]\bold {Molar\ mass =\dfrac { mass}{ moles}}\\\\\bold {Molar\ mass = \dfrac {27.6\ grams }{0.18\ moles}}\\\\\bold {Molar\ mass = 153.3 g/mol}[/tex]
The molar mass of the given unknown compound is 153.3 g/mol.
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A solution is prepared by mixing 5.00 mL of 0.100 M HCl and 2.00 mL of 0.200 M NaCl. What is the molarity of chloride ion in this solution?
Answer:
0.129 M
Explanation:
0.100 M HCl = 0.100 mol/L solution HCl
5.00 mL = 0.00500 L solution HCl
0.100 mol/L HCl * 0.00500 L = 0.000500 mol HCl
HCl ------> H+ + Cl-
1 mol 1 mol
0.000500 mol 0.000500 mol
0.200 M NaCl = 0.200 mol/L solution NaCl
2.00 mL = 0.00200 L solution NaCl
0.200 mol/L NaCl*0.00200 L = 0.000400 mol NaCl
NaCl ------> Na+ + Cl-
1 mol 1 mol
0.000400 mol 0.000400 mol
Chloride ion altogether (0.000500 mol + 0.000400 mol) =0.000900 mol
Solution altogether (0.00500 L+0.00200 L) = 0.00700L
Molarity (Cl-)= solute/solution = 0.000900 mol/0.00700L = 0.129 mol/L=
= 0.129 M
A chemist prepares a solution of aluminum chloride by measuring out of aluminum chloride into a volumetric flask and filling the flask to the mark with water. Calculate the concentration in of the chemist's aluminum chloride solution. Be sure your answer has the correct number of significant digits.
Answer:
0.15M
Explanation:
Molar Concentration = [tex]\frac{mass}{molar mass}[/tex]
Assuming 20g of the unadulterated aluminium chloride was weighed into the volumetric flask, and given molar mass of AlCl3 = 133.34g/mol
∴ Molarity = [tex]\frac{20}{133.34}[/tex]
= 0.14999 ≈ 0.15M (to 2 significant figures)
I hope this solution is clear. The same can be calculated from concentration by volume.
A certain element consists of two stable isotopes. The first has a mass of 62.9 amu and a percent natural abundance of 69.1 %. The second has a mass of 64.9 amu and a percent natural abundance of 30.9 %. What is the atomic weight of the element?
Answer:
63.518
Explanation:
The following data were obtained from the question:
Mass of Isotope A = 62.9 amu
Abundance of isotope A (A%) = 69.1%
Mass of isotope B = 64.9 amu
Abundance of isotope B (B%) = 30.9%
Atomic weight of the element =..?
The atomic weight of the element can be obtained as follow:
Atomic weight = [(Mass of A x A%)/100] + [(Mass of B x B%) /100]
Atomic weight = [(62.9 x 69.1)/100] + [(64.9 x 30.9)/100]
Atomic weight = 43.4639 + 20.0541
Atomic weight = 63.518
Therefore, the atomic weight of the element is 63.518.
The diagram below shows that the periodic table is divided into different blocks.
A periodic table is shown. The main table consists of seven rows; two additional rows are shown below. In each block, the first column is labeled and the remaining columns are empty. The s-block is shaded in yellow and comprises the first two columns, plus one cell at the far side of the table. The first column has seven rows with entries 1 s, 2 s, 3 s, 4 s, 5 s, 6 s, and 7 s. A lone cell labeled 1 s appears at the top far right corner, aligned with the 1 s cell in the first column. The d-block is shaded in blue and contains 10 columns and 3 or 4 rows. The first column is directly to the right of the s-block. The first entry in the first d-block column aligns with the 4 s block, and is labeled 3d; further entries in that column are 4 d, 5 d, and 6 d. The first three columns in the block are four entries long; the remaining columns are three entries long, losing the bottom entry. The p-block is shaded in orange, and has 6 columns and 5 rows. The top row aligns with the 2 s block; entrie
Elements that have complete valence electron shells are mostly found in the
s block.
d block.
p block.
Answer:
p block.
Explanation:
jus took the test
Answer:
c p block
Explanation:
The atomic mass of gallium is 69.72 . The density of iron is 7.87 . The atomic mass of iron is 55.847 . Calculate the number of gallium atoms in one ton (2000 pounds) of gallium. (Enter your answer to three significant figures.)
Answer:
the atomic mass of any elemet contains avogardo numberof atoms
In case of Gallium,
69.72 gram is atomic mass and it cotnains around 6.023*10^23 atoms of Gallium
but, 2000 punds = 907184.7 grams
907184.7 gram of gallium contains= 6.023*10^23* 907184/69.72
= 79 *10^26 atoms
Explanation:
am i correct if not correct me please
Answer:
D. Hund's rule
Explanation:
Not sure, but I would go with Hund's since it talks about filing electrons in each orbital before you can pair them up. The reason sulfur has lower ionization is because it has one set of paired electrons which makes the orbital unstable whereas phosphorus has 3 unpaired e's which means it is more stable. Thus it is easier to remove electron from sulfur hence lower ionization energy.
What are 3 characteristics of chemical reactions
Answer:
Evolution of gas.
Formation of a precipitate.
Change in color.
Explanation:
Enter your answer in the provided box. On a cool, rainy day, the barometric pressure is 739 mmHg. Calculate the barometric pressure in centimeters of water (cmH2O) (d of Hg = 13.5 g/mL; d of H2O = 1.00 g/mL).
Answer:
997.65cmH2O
Explanation:
Barometric pressure = 739 mmHg
density of Hg = 13.5 g/ml
density of water (H2O) = 1.00 g/ml
Calculate Barometric pressure in centimetres of water ( cmH20)
equate the barometric pressure of Hg and water
739 * 13.5 * 9.8 = x * 1 * 9.81
x ( barometric pressure of water in mmH2O ) = 739 *13.5 / 1 = 9976.5mmH2O
in cmH2O = 997.65cmH2O
A solution of benzene in methanol has a transmittance of 93.0 % in a 1.00 cm cell at a wavelength of 254 nm. Only the benzene absorbs light at this wavelength, not the methanol. What will the solution's transmittance be if it is placed in a 10.00 cm long pathlength cell
Answer:
T = 48.39%
Explanation:
In this case we need to apply the Beer law which is the following:
A = CεL (1)
Where:
A: Absorbance of solution
C: Concentration of solution
ε: Molar Absortivity (Constant)
L: Length of the cell
Now according to the given data, we have transmittance of 93% or 0.93. We can calculate absorbance using the following expression:
A = -logT (2)
Applying this expression, let's calculate the Absorbance:
A = -log(0.93)
A = 0.03152
Now that we have the absorbance, let's calculate the concentration of the solution, using expression (1).
A = CεL
C = A / εL
Replacing:
C = 0.03152 / 1 *ε (3)
Now, we want to know the transmittance of the solution with a length of 10 cm. so:
A = CεL
Concentration and ε are constant, so:
A = (0.03152 / ε) * ε * 10
A = 0.3152
Now that we have the new absorbance, we can calculate the new transmittace:
T = 10^(-A)
T = 0.4839 ----> 48.39%
The compound gallium phosphide () is a compound semiconductor having mixed ionic and covalent bonding. The electronegativities for and are 1.6 and 2.1 respectively. Calculate the fraction of the bonding that is ionic.
Answer:
[tex]0.08875[/tex]
Explanation:
Hello,
In this case, the first step is to compute the difference in the electronegativity for the formed bond between gallium and phosphorous by:
[tex]\Delta E=2.1-1.6\\\\\Delta E=0.5[/tex]
Thus, we can compute the percentage of ionic character by:
[tex]\%\ ionic\ character=16\Delta E +3.5 (\Delta E)^2\\\\\%\ ionic\ character=16*0.5+3.5*0.5^2\\\\\%\ ionic\ character=8.875\%[/tex]
So the fraction is just:
[tex]\frac{8.875}{100}=0.08875[/tex]
Which has sense since gallium phosphide is a non-polar compound.
Regards.
A solution that is 0.135 M is diluted to make 500.0 mL of a 0.0851 M solution. How many milliliters of the original solution were required? View Available Hint(s) A solution that is 0.135 M is diluted to make 500.0 mL of a 0.0851 M solution. How many milliliters of the original solution were required? 5.74 mL 0.315 mL 793 mL 315 mL
Answer:
315mL
Explanation:
Data obtained from the question include the following:
Molarity of stock solution (M1) = 0.135 M
Volume of stock solution needed (V1) =?
Molarity of diluted solution (M2) = 0.0851 M
Volume of diluted solution (V2) = 500mL
The volume of the stock solution needed can be obtain as follow:
M1V1 = M2V2
0.135 x V1 = 0.0851 x 500
Divide both side by 0.135
V1 = (0.0851 x 500) / 0.135
V1 = 315mL
Therefore, the volume of the stock solution needed is 315mL
Which scenario describes an interaction between two of Earth's spheres?
Water flows from a stream to a lake.
Gravity moves rocks to another location.
Lions use energy to catch other animals for food.
Bears dig big holes in the ground to protect their young.
The correct answer is D. Bears dig big holes in the ground to protect their young
Explanation:
The Earth spheres include the biosphere (life in the Earth), the hydrosphere (water bodies), the geosphere (rocks and other elements that compose land and soil), and the atmosphere (gases that compose the air). In this context, there is an interaction between two spheres: the biosphere and the geosphere, when a bear digs holes in the ground because a living organism that is part of the biosphere is modifying the structure and shape of superficial soil, which is part of the geosphere.
Answer: D
Explanation:
the reaction below is at equilibrium. What would happen if more carbon were added ?
Answer:
B
Explanation:
If more carbon were added, the equilibrium position would shift to produce more products.
What is equilibrium?In a chemical reaction chemical equilibrium is defined as the state at which there is no further change in concentration of reactants and products.
If the concentration of one (or more) of the reactants or products is increased the equilibrium will shift to decrease the concentration.
Or if the temperature is decreased the equilibrium will shift to increase the temperature by favouring the exothermic reaction.
Hence, if more carbon were added, the equilibrium position would shift to produce more products.
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hno3 express your answer using four significant figures
Answer:
[tex]M=63.02g/mol[/tex]
Explanation:
Hello,
In this case, for the calculation of the molar mass of nitric acid, we should employ the following formula, knowing that there is one hydrogen atom, one nitrogen atom and three oxygen atoms:
[tex]M=m_H+m_N+3*m_O[/tex]
Now, we use the atomic mass of each atom to compute the total molar mass:
[tex]M=1.008g/mol+14.01g/mol+3*16.00g/mol\\\\M=63.02g/mol[/tex]
Best regards.
g The atomic mass of an element is equal to ________. The atomic mass of an element is equal to ________. its mass number one-twelfth of the mass of a carbon-12 atom a weighted average mass of all of the naturally occurring isotopes of the element its atomic number the average mass of all of the naturally occurring isotopes of the element
Answer:
Total numbe of protons and neutrons in a single atom of that element
Explanation:
Hello,
I'll answer the question by filling in the blank spaces
"The atomic mass of an element is equal to the total number of proton and neutron in a particular atom of the element. The atomic mass of an element is equal to the atomic weight. Its mass number one-twelfth of the mass of carbon-12 atom a weighted mass of all naturally occurring isotopes of the elements. Its atomic mass is the average mass of all the naturally occurring isotopes of the element."
The atomic mass of an element is the total number of protons and neutrons in a single atom of that element.
The atomic mass of an element is equal to a weighted average mass of all of the naturally occurring isotopes of the element. The correct answer is option 2.
Isotopes are elements with the same number of protons (atomic number) but differing numbers of neutrons (mass number).
Most elements exist in nature as a mixture of isotopes, each with a different mass number and abundance. The atomic mass of an element is computed by adding the masses of all isotopes, multiplying by their relative abundance, and dividing by the total abundance of all isotopes.
This gives a weighted average mass that corresponds to the normal mass of an element's atom in nature.
Therefore, the correct answer is option 2. to a weighted average mass of all of the naturally occurring isotopes of the element.
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what’s the SI unit of time ?
Answer:
The answer is A
Explanation:
A sample of krypton gas occupies a volume of 9.87 L at 51°C and 0.565 atm. If it is desired to decrease the volume of the gas sample to 8.05 L, while increasing its pressure to 0.678 atm, the temperature of the gas sample at the new volume and pressure must be___________ °C.
Answer:
44.1°C
Explanation:
Step 1:
Data obtained from the question include:
Initial volume (V1) = 9.87 L
Initial temperature (T1) = 51°C = 51°C + 273 = 324K
Initial pressure (P1) = 0.565 atm
Final volume (V2) = 8.05 L
Final pressure (P2) = 0.678 atm
Final temperature (T2) =..?
Step 2:
Determination of the new temperature of the gas.
The new temperature of the gas can be obtained by using the general gas equation as shown below:
P1V1 /T1 = P2V2 /T2
0.565 x 9.87/324 = 0.678 x 8.05/T2
Cross multiply
0.565 x 9.87 x T2 = 324 x 0.678 x 8.05
Divide both side by 0.565 x 9.87
T2 = (324 x 0.678 x 8.05)/(0.565 x 9.87)
T2 = 317.1K
Step 3:
Conversion of 317.1K to decree celsius.
This is illustrated below:
T (°C) = T(K) – 273
T (K) = 317.1K
T (°C) = 317.1 – 273
T (°C) = 44.1°C
Therefore, the new temperature of the gas is 44.1°C
"Strike anywhere matches contain the compound tetraphosphorus trisulfide, which burns to form tetraphosphorus decaoxide and sulfur dioxide gas. How many milliliters of sulfur dioxide, measured at 751 torr and 21.0°C, can be produced from burning 0.869 g of tetraphosphorus trisulfide?"
Answer:
Can be produced 288mL of SO₂
Explanation:
Based in the reaction:
P₄S₃ + 8O₂ → P₄O₁₀ + 3SO₂
Where 1 mole of tetraphosphorus trisulfide reacts producing 3 moles of sulfur dioxide gas.
0.869g of tetraphosphorus trisulfide (Molar mass of P₄S₃: 220.09g/mol) are:
0.869g P₄S₃ ₓ (1mol / 220.09g) = 3.948x10⁻³ moles of P₄S₃
As 3 moles of SO₂ are produced per mole of P₄S₃:
3.948x10⁻³ moles of P₄S₃ ₓ (3 moles SO₂ / 1 mole P₄S₃) = 0.0118 moles SO₂
Using PV = nRT
V = nRT / P
Where n are 0.0118 moles, R gas constant (0.082atmL/molK), T absolute temperature (21.0°C + 273.15K = 294.15K), and P pressure (751torr / 760 = 0.988atm).
Replacing:
V = 0.0118molₓ0.082atmL/molKₓ294.15K / 0.988atm
V = 0.288L = 288mL
What is the Lewis structure for *OPCl3 and AlCl6^3-? What are their electron/molecular geometry and Ideal Bond Angle ?
Answer:
Here's what I get
Explanation:
1. POCl₃
(a) Lewis structure
Set P as the central atom, with O and Cl atoms directly attached to it.
Electrons available = P + O + 3Cl = 5 + 6 + 3×7 = 11 + 21 = 32
Arrange these electrons to give every atom an octet. Put a double bond between P and O.
You get the structure shown below.
(b) Geometry
There are four bond pairs and no lone pairs about the P atom.
Electron pair geometry — tetrahedral
Molecular geometry — tetrahedral
(c) Ideal bond angles
Tetrahedral bond angle = 109.5°
2. AlCl₆³⁻
(a) Lewis structure
Set Al as the central atom, with the Cl atoms directly attached to it.
Electrons available = Al + 6Cl + 3(-) = 3 + 6×6 +3 = 6 + 36 = 42
Arrange these electrons to give every atom an octet. Assign formal charges.
You get the structure shown below.
(b) Geometry
There are six bond pairs and no lone pairs about the Al.
Electron pair geometry — octahedral
Molecular geometry — octahedral
(c) Ideal bond angles
Axial-equatorial = 90°
Equatorial-equatorial = 120°
Axial-axial = 180°
Assuming constant pressure, rank these reactions from most energy released by the system to most energy absorbed by the system, based on the following descriptions: 1. Surroundings get colder and the system decreases in volume. 2. Surroundings get hotter and the system expands in volume. 3. Surroundings get hotter and the system decreases in volume. 4. Surroundings get hotter and the system does not change in volume. 5. Also assume that the magnitude of the volume and temperature changes are similar among the reactions. 6. Rank from most energy released to most energy absorbed. To rank items as equivalent, overlap them. A mole of X reacts at a constant pressure of 43.0 atm via the reaction X(g)+4Y(g)→2Z(g), ΔH∘=−75.0 kJBefore the reaction, the volume of the gaseous mixture was 5.00 L. After the reaction, the volume was 2.00 L. Calculate the value of the total energy change, ΔE, in kilojoules.
Answer: The order from the Most energy released to most Energy Absorbed Is given as 2---> 4--->,3-->---> 1
B)-61.9 kJ
Explanation:
The change in the internal energy of a system is positive if the reaction absorbs energy and negative if the reaction releases energy. For a system to cause an increase in volume, it must have very high energy built up to be released.
1. Surroundings get colder and the system decreases in volume. Here, the surrounding absorbs energy resulting in positive ΔE
2. Surroundings get hotter and the system expands in volume. Here energy is released causing the system to be negative
3. Surroundings get hotter and the system decreases in volume. Although there is a decreased volume, the system is negative because it releases energy
4. Surroundings get hotter and the system does not change in volume. System is negative because it releases energy even thgoygh there is no change in volume
Therefore the order from the Most energy released to most Energy Absorbed Is given as 2---> 4--->,3-->---> 1
b) Using
ΔE = q+ w from 1st law of thermodynamics
ΔE= ΔH - P ΔV
gIven
ΔH = -75.0KJ
volume= A change from 5.0L TO 2.0L = Final volume - initial volume = 2-5= -3.00L
P= 43.0atm
ΔE= ΔH - P ΔV
P ΔV = 43 atm x -3 = -129L.atm
We first convert L-atm to Joules.
1 L-atm = 101.325 Joules.
129L.atm = 129 x 101.325 = - 13071 J
to KJ becomes
13071/1000 = - 13.071KJ
Recall ΔE= ΔH - P ΔV and putting values
ΔE = -75.0 - (-13.071 KJ)= -75.0 kJ + 13.071 kJ = -61.9 kJ
Enter an equation for the formation of C2H5OH(l) from its elements in their standard states. Enter any reference to carbon as C(s). Express your answer as a chemical equation. Identify all of the phases in your answer.
Answer:
C(s) + 3 H₂(g) + 1/2 O₂(g) ⇒C₂H₅OH(l)
Explanation:
Ethanol (C₂H₅OH) is an alcohol and it is formed by carbon (C), H (hydrogen) and O (oxygen) atoms. These elements in their standard states are:
C: C(s), it is solid, could be graphite, diamond, among others.
H: H₂(g), it is a diatomic gas.
O: O₂(g), it is a diatomic gas.
So, we can write the equation for the formation of C₂H₅OH from C(s), H₂ and O₂ as follows:
C(s) + H₂(g) + O₂(g) ⇒C₂H₅OH(l)
Finally, we have to balance the equation by adding the estequiometrical coefficients:
C(s) + 3 H₂(g) + 1/2 O₂(g) ⇒C₂H₅OH(l)
2C(s)+3[tex]H_{2} [/tex](g)+[tex]\frac{1}{2} [/tex][tex]O_{2} [/tex](g)→[tex]C_{2} [/tex][tex]H_{5} [/tex]OH(l)
Explanation:
Standard state of carbon: C(s)
Standard state of oxygen: [tex]O_{2} [/tex](g)
Standard State of Hydrogen: [tex]H_{2} [/tex](g)
Then balance the equation C2H5OH(l) to get 2C(s)+3[tex]H_{2} [/tex](g)+[tex]\frac{1}{2} [/tex][tex]O_{2} [/tex](g)→[tex]C_{2} [/tex][tex]H_{5} [/tex]OH(l).
Describe the buffer capacity of the acetic acid buffer solution in relation to the addition of both concentrated and dilute acids and bases.
Answer:
The answer is in the explanation
Explanation:
Acetic acid, CH₃COOH, is a weak acid that will produce a buffer when its conjugate base, CH₃COO⁻, acetate ion, is added to the solution.
That is because a buffer is the mixture of a weak acid and its conjugate base or vice versa.
When an acid (HX) is added to the solution, the acetate ion will react producing acetic acid, thus:
CH₃COO⁻ + HX → CH₃COOH + X⁻
For this reason, the pH doesn't change abruptly because H⁺ ions are not produced.
Now, if a base (BOH) is added to the buffer, CH₃COOH will react producing acetate ion and water, thus:
CH₃COOH + BOH → CH₃COO⁻ + H₂O + B⁺.
In the same way, there are not produced free OH⁻ and the pH doesn't change significantly.
Carbon dioxide and water vapor are variable gases because _____.
Answer: their amounts vary throughout the atmosphere
Explanation:
There is very little that travels over the atmosphere
Vary=very little
Hope that helps
The reaction of 15 moles carbon with 30 moles O2 will
result in a theoretical yield of moles CO2.
Answer:
The amount of Co2 generated is 15 moles
Explanation:
It bears the same ratio with Carbon meaning oxygen was used in excess
18. Investigue por qué en el bloque "d" se aplica la fórmula n-1 y en el bloque "f" n-2.
Answer:
La razón de esto es porque los elementos en el bloque d tienen sus electrones d en la capa (n-1) (penúltima capa) y puede usar electrones de la capa (n-1) (penúltima capa) para formar enlaces químicos.
Los elementos en el bloque f tienen sus electrones f en sus capas (n-2) y pueden llegar a usar electrones de la capa (n-2) (capa antes de la penúltima capa) para enlaces químicos.
Explanation:
Para explicar esto, comencemos con los elementos de bloque syp; Los elementos de bloque syp usan electrones que tienen el mismo número cuántico principal para enlaces químicos. Por ejemplo, el aluminio utiliza los electrones 3s más externos y el carbono los electrones 2s y 2p cuando forman enlaces químicos. A pesar de que el carbono (bloque p) utiliza electrones de dos conjuntos de orbitales (2s, 2p) para la unión covalente, su número cuántico principal es el mismo (2) ya que todavía provienen de la misma capa.
Pero, los metales de transición (elementos de bloque d) usan electrones del orbital "s" de la capa más externa y los orbitales "d" de la penúltima capa forman enlaces químicos. Por ejemplo, los elementos de la primera serie de transición como el manganeso, el cobre y el hierro pueden usar los electrones 4s más externos y los electrones 3d de la penúltima capa, con diferentes números cuánticos principales (4 y 3). Eso significa que los metales de transición pueden usar tanto el orbital ‘ns’ más externo como los orbitales d (n-1) de la penúltima caparazón.
Luego, para los metales de transición internos (elementos de bloque f), tienen sus electrones f en sus capas (n-2) y pueden llegar a usar electrones de la capa (n-2) (capa antes de la penúltima capa) para enlaces químicos.
¡¡¡Espero que esto ayude!!!
El ejemplo más claro para definir una cadena de electricidad es una red de pesca, si fuera posible identificar una sola partícula representativa de esta fuerza , ¿ Cuál partícula se identificaría? *
Bosón W
Fotón
Glúon
Leptón
Answer:
Leptón
Explanation:
Lepton son partículas elementales de espín de medio entero (espín 1⁄2), y se sabe que no experimentan interacciones fuertes. Los leptones se clasifican en leptones cargados (los leptones similares a los electrones) y leptones neutros (conocidos como neutrinos). Un electrón es un leptón. Los leptones cargados pueden combinarse con otras partículas para formar átomos compuestos de partículas y positronio, mientras que los neutrinos rara vez interactúan con algo, lo que los hace raros de observar.
Dado que la electricidad es el resultado del movimiento o flujo de electrones, la única partícula representativa de esta fuerza es el leptón.
Give the characteristic of a zero order reaction having only one reactant. a. The rate of the reaction is not proportional to the concentration of the reactant. b. The rate of the reaction is proportional to the square of the concentration of the reactant. c. The rate of the reaction is proportional to the square root of the concentration of the reactant. d. The rate of the reaction is proportional to the natural logarithm of t
Answer:
a. The rate of the reaction is not proportional to the concentration of the reactant.
Explanation:
The rate expression for a zero order reaction is given as;
A → Product
Rate = k[A]⁰
[A]⁰ = 1
Rate = K
GGoing through the options;
a) This is correct because in the final form of the rate expression, the rate is independent of the concentration.
b) This option is wrong
c) This option is also wrong
d) Like options b and c this is also wrong becaus ethere is no relationship between either the concentration or t.
How many moles of CO2 can be produced by the complete reaction of 1.0 g of lithium carbonate with excess hydrochloric acid (balanced chemical reaction is given below)? Li2CO3(s) + 2HCl(aq) --> 2LiCl(aq) + H2O(l) + CO2(g) Question 1 options: 1.7 g 1.1 g 0.60 040 g
Answer:Mass of CO2 = 0.60g
Explanation:
Given the chemical rection
Li2CO3(s) + 2HCl(aq) --> 2LiCl(aq) + H2O(l) + CO2(g
No of moles = mass / molar mass
molar mass Li2CO3 = Molecular mass calculation: 6.941 x 2 + 12.0107 + 15.9994 x 3 =
= 73.8909 g/mol
therefore Number of moles Li2CO3 = 1.0g / 73.89 g/mol
= 0.0135 moles Li2CO3
From our given Balanced equation, shows that
Li2CO3(s) + 2HCl(aq) --> 2LiCl(aq) + H2O(l) + CO2(g
1 mole Li2CO3 produces 1 mole CO2
therefore 0.0135 mol Li2CO3 will produce 0.0135 moles of CO2
Also
No of moles = mass / molar mass
Mass = No of moles x molar mass
molar mass of CO2=12.0107 + 15.9994 x 2=44.0095 g/mol
Mass of CO2= 0.0135 X 44.0095 g/mol =0.594≈0.60g
When comparing the two chair conformations for a monosubstituted cyclohexane ring, which type of substituent shows the greatest preference for occupying an equatorial position rather than an axial position
Answer:
See the explanation
Explanation:
In this case, we have to keep in mind that in the monosubstituted product we only have to replace 1 hydrogen with another group. In this case, we are going to use the methyl group [tex]CH_3[/tex].
In the axial position, we have a more steric hindrance because we have two hydrogens near to the [tex]CH_3[/tex] group. If we have more steric hindrance the molecule would be more unstable. In the equatorial positions, we don't any interactions because the [tex]CH_3[/tex] group is pointing out. If we don't have any steric hindrance the molecule will be more stable, that's why the molecule will the equatorial position.
See figure 1
I hope it helps!