A pumpkin is thrown horizontally off of a building at a speed of 2.5 m/s and travels a horizontal distance of 12 m before hitting the ground.
What was the initial height of the pumpkin?
What was the final vertical velocity of the pumpkin?

Answers

Answer 1

Answer:

-47.04

Explanation:

Divide 12 m by 2.5 m/s which equals 4.8s

And then use 4.8s to multiply it with -9.8

4.8(-9.8)= -47.04 m/s

Hope this helped!! :)

Answer 2

The initial height of the pumpkin is 23.52m and the final vertical velocity of the pumpkin is 47.04 m/s.

Laws of motion:

Initial horizontal speed, u = 2.5 m/s

horizontal distance covered , d = 12m

So the time taken is:

t = d/u

t = 12/2.5 s

t = 4.8s

Now, the initial vertical speed, v = 0

So the vertical distance traveled by the pumpkin will be equal to the initial height of the pumpkin:

s = vt + ¹/₂gt²

s = 0.5 × 9.8 × 4.8 m

s = 23.52m

Final vertical velocity:

v' = v + gt

v' = 9.8 × 4.8 m/s

v' = 47.04 m/s

Learn more about laws of motion:

https://brainly.com/question/26083484?referrer=searchResults


Related Questions

How does Health & Physical Education relate to any other subject you now study in
school?

Answers

Answer:

Health relates to science because

in science you study, research, and knowledge in this case, health science, which helps you under stand more about how humans and animals function. And Physical education relates to science because , you study the way of human movement, think of push-ups as a example.

I hope I helped U ´꓃ ` U

what do electrons move from

Answers

Answer:

Negatively charged, to positively charged parts

Explanation:

Electrons are negative, negative is attracted to positive.

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