[tex]\purple{ \longrightarrow \bf{h_m = \dfrac{ {v}^{2} \: {sin}^{2} \theta }{2g} }} [/tex]
Projectile is thrown with a velocity = v Angle of projection = θVelocity of projectile at a height half of the maximum height covered be [tex] \sf{v_0}[/tex][tex]\qquad[/tex]______________________________
Then –
[tex]\qquad[/tex] [tex]\pink{ \longrightarrow \bf{ \dfrac{h_m}{2} = \dfrac{ {v_0}^{2} \: {sin}^{2} \theta }{2g} }}[/tex]
[tex]\qquad[/tex] [tex] \longrightarrow \sf{ \dfrac{ {v}^{2} \: {sin}^{2} \theta }{2g} \times \dfrac{1}{2} = \dfrac{ {v_0}^{2} \: {sin}^{2} \theta }{2g} }[/tex]
[tex]\qquad[/tex][tex]\longrightarrow \sf{ \dfrac{ {v}^{2} \: {sin}^{2} \theta }{4g} = \dfrac{ {v_0}^{2} \: {sin}^{2} \theta }{2g} }[/tex]
[tex]\qquad[/tex][tex]\longrightarrow \sf{ \dfrac{ {v}^{2} \: {sin}^{2} \theta }{2} = {v_0}^{2} \: {sin}^{2} \theta }[/tex]
[tex]\qquad[/tex][tex] \longrightarrow \sf{ \dfrac{ {v}^{2} }{2} = {v_0}^{2} }[/tex]
[tex]\qquad[/tex][tex] \longrightarrow \bf{v_0 = \sqrt{ \dfrac{ {v}^{2} }{2} } = \dfrac{v}{ \sqrt{2} } }[/tex]
Now, the vertical component of velocity of projectile at the height half of [tex] \sf{h_m}[/tex] will be –[tex]\qquad[/tex] [tex]\longrightarrow \bf{v_{(y)}=v_0 \: sin \theta }[/tex]
[tex]\qquad[/tex] [tex] \longrightarrow \bf{v_{(y)} = \dfrac{v}{ \sqrt{2} } \: sin \theta = \dfrac{v \: sin \: \theta}{ \sqrt{2} } }[/tex]
Therefore, the vertical component of velocity of projectile at this height will be–
☀️[tex]\qquad[/tex][tex] \pink {\bf{ \dfrac{v \: sin \: \theta}{ \sqrt{2} }} }[/tex]
Answer:
A projectile is thrown with velocity v at an angle θ with horizontal. When the projectile is at a height equal to half of the maximum height, the vertical component of the velocity of projectile is v sintheta / √2
Explain why pumice floats and why ironwood sinks
Answer:
A quick way of describing density is to describe an object as heavy or light for its size. Pumice stone, unlike regular rock, does not sink in water because it has a low density. An ironwood branch is very dense and sinks in water.
Hope that helps. x
Answer:
Pumice is trapped in gas when the temperature is warm, but as the temp drops, it becomes dense, due to air bubbles. Iron wood is denser than water, thus making it sink.
Explanation:
Hi sweeties.. I want 5 solving questions about (Fluid Pressure and Temperature) and (Archimedes' Principle) may u help me?!
Answer:
1) A 1L bottle, with a height of 30cm, full of water is emptied. The bottle is filled with oil (density = 920 kg/m^3). Calculate the change in pressure of the bottom of the first bottle. If you decide to put potatoes (assume its density is 1,8 kg/m^3), each one of a volume V = 10 cm^3, will they float?
2) The fusion temperature of the Nitrogen is -210°C and its boiling temperature is 77K. Calculate the difference between the fusion temperature and the boiling temperature.
jamal is playing with magnetic toy vehicles. He has two identical magnetic vehicles (purple and green) on different sides of a center magnet that cannot move. His friend Simone challenges him to move one vehicle one space to the left or the right in order to get the largest increase in potential energy. That means Jamal can move the purple car to point A or point B, or he can move the green car to point C or point D. Explain which movement Jamal should make (which car and which point), and why that movement will result in the largest increase in potential energy. Describe the magnetic force that will act on the vehicle he moves.
Answer:
Since potential energy increases with increase in the separation distance, Jamal should move the toy car that will create the largest separation distance. The magnetic force that will act on the vehicles as he moves the cars away from each other will decrease because magnetic force is inversely proportional to the separating distance between the cars.
Explanation:
Since potential energy increases with increase in the separation distance, Jamal should move the toy car that will create the largest separation distance.The magnetic force that will act on the vehicles as he moves the cars away from each other will decrease because magnetic force is inversely proportional to the separating distance between the cars.
Please help me! I don't understand how to do this!
Part 1: A 6 kg shopping cart goes from a velocity of 0.9 m/s to a velocity of 6 m/s over the course of 2.0 seconds. What is the cart's acceleration?
Part 2: What is the net force acting on the shopping cart during that time? You will need your answer from the previous part.
From the information in the question, the acceleration of the cart is 2.55 ms-2.
We can find the acceleration using the following information from the question;
u = 0.9 m/s
v = 6 m/s
a = 2.0 seconds
But;
a = v - u/t
v = final velocity
u = initial velocity
t = time
a = 6 - 0.9/2 = 2.55 ms-2
Force= ma
m = mass
a = acceleration
F = 6 kg × 2.55 ms-2
F = 15.3 N
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Record your observations. Include the data table you created for the lab and a graph based on the data table. Type your answer here:
To create a graph of the data you collected during the lab, first, organize the data, then select the best type of graph, and finally create the graph.
One of the steps you need to complete after an experiment is to graph your results. This implies organizing the data and creating a diagram to visually represent your findings.
These are the steps you can follow to complete this task:
Organize the data: The first thing you need to do is to understand what were the main factors for example if your experiment measured temperature changes this is the main factor you need to consider. Then try to organize this data in a chart so you can visualize it.Select the type of graph: There are different types of graphs such as:Bar graph.Pie chart.Scatter plot.Among others.Each of these graphs focuses on specific types of data, and therefore you need to select the one that best fits the data you collected.
Create the graph: Finally, you can create the graph to do this, there are programs like excel that help you create the graph only by entering the data.Learn more about graphs in: https://brainly.com/question/16192791
5. A ball is shot directly into the air vertically with an
initial velocity of 49.7 m/s. What is the velocity of the
ball after 3 seconds?
a. 3.4 m/s
b. 20.3 m/s
c. 12.4 m/s
d. 202.0 m/s
is it possible for an object moving around a circular path to have both centripetal and tangential acceleration?
Answer:
A major difference between tangential acceleration and centripetal acceleration is their direction. Centripetal means “center seeking”. ... Tangential acceleration results from the change in magnitude of the tangential velocity of an object. An object can move in a circle and not have any tangential acceleration.
The direction of acceleration is a key distinction between tangential acceleration and centripetal acceleration. Centripetal is defined as "center-seeking." The amount of an object's tangential velocity changes, which causes tangential acceleration. Without experiencing any tangential acceleration, an item can move in a circle.
What is Acceleration?Acceleration is the rate at which the speed and orientation of a moving object change over time. When a spot or object moves faster or slower along a straight line, it is said to be accelerated. Even though the speed is constant, motion on a circle accelerates so because the direction is always shifting. Both by and to acceleration for all other types of motion.
It is a vector quantity because it has both magnitude and direction.
Any object's rotation experiences tangential acceleration, which is the speed at which the tangential velocity fluctuates. When an object is moving, it behaves in a tangential direction. An object moving in a circle will also experience the very same tangential velocity action.
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a 74 kg man jumps from a window 1.6 m above a sidewalk. the acceleration of gravity is 9.81 m/s 2 . a) what is his speed just before his feet strike the pavement? answer in units of m/s
Answer:
5.60 m/s
Explanation:
His initial potential energy is equal to his final kinetic energy.
mgh = 1/2mv^2
2gh = v^2 . . . . . . . multiply by 2/m
v = √(2gh) = √(2(9.81 m/s²)(1.6 m)) = √(31.392 m²/s²)
v ≈ 5.60 m/s
_____
Additional comment
The mass is irrelevant in the equations we typically use for this purpose.
What does 'has no fixed volume' mean??
Answer:
the volume changes overtime
sometimes because of weather, temperature ...
Explanation:
What is the force applied to a baseball that has a mass of 142kg and has a acceleration of 30m/s to the power of 2
Using Newton's second law
[tex]\\ \sf\Rrightarrow F=ma[/tex]
[tex]\\ \sf\Rrightarrow F=142(30)[/tex]
[tex]\\ \sf\Rrightarrow F=4260N[/tex]
A roller coaster
produces acceleration due
to changes in both speed
and direction. Applying
Concepts Describe the
acceleration occuring at this
instant on the
rollercoaster ride.
Answer:
the answer is the rollar coster
Explanation:
because the rollar coster is
two forces act concurrently on an object on a horizontal frictionless surface. their resultatn force has the largest magnitude when the angle between the forces is
Answer:
54
Explanation:4
4
4
Answer:
30d
Explanation:
30d
HELP!!!!
Which statement describes earthquakes?
They release energy.
They are caused by reduced stress in rocks.
They begin at the epicenter.
They result from movement on Earth’s surface.
Answer:
A
Explanation:
earthquakes release energy
Answer:
i think it begins at the epicenter
Explanation:
i can remember
pls give brainleist
how to determine my slope in physics graph
Answer:
Determine the coordinates of two points on the line. Calculate the difference between these two locations' y-coordinates (rise). Calculate the x-coordinate difference between these two places (run). Divide the y-coordinate difference by the x-coordinate difference (rise/run or slope).
How did the Agricultural Revolution impact humans? In your opinion, were those changes good or bad? Why?
Answer:
The Agricultural Revolution of the 18th century paved the way for the Industrial Revolution in Britain. New farming techniques and improved livestock breeding led to amplified food production. This allowed a spike in population and increased health. The new farming techniques also led to an enclosure movement
what is q if 28.6 g of water is heated from 22.0°c to 78.3°c? the specific heat of water is 4.184 j/g·°c.
Answer:
6736 J
Explanation:
Knowing that Q = cmΔT:
Q = 4.184 J/(g·°C) · 28.6g · (78.3 °C - 22.0 °C) = 6736 J.
Which statement describes ionic compounds?
A) ionic compounds are positively charged
B) ionic compounds are neutral
C) ionic compounds are negatively charged
Answer:the answer is b
Explanation:
This is because in an ionic bond negative and positive bonds are present
What is the gravitational force between two objects of masses 20kg and 50kg separated by a distance of
4m?
Answer:
4.16875×10^-9
Explanation:
given,
mass(M1)=20kg
mass(M2)= 50kg
distance(d)=4m
gravitational constant value (G)=6.67×10^-11
we know,
gravitational force=(Gm1m2)÷d^2
=(6.67×10^-11×20×50)÷4^2
=(6.67×10^-8)÷16
= 4.16875×10^-9
I have two questions. I hope anyone can help me <3 Question 8 & Question 9.
Answer:
i have not study it till now
Explanation:
sorry i don't know
which planet should punch travel to if his goal is to weigh in at 118 lb? refer to the table of planetary masses and radii given to determine your answer.
The planet that Punch should travel to in order to weigh 118 lb is Pentune.
The given parameters:Weight of Punch on Earth = 236 lbDesired weight = 118 lbThe mass of Punch will be constant in every planet;
[tex]W = mg\\\\m = \frac{W}{g}\\\\m = \frac{236}{g}[/tex]
The acceleration due to gravity of each planet with respect to Earth is calculated by using the following relationship;
[tex]F = mg = \frac{GmM}{R^2} \\\\g = \frac{GM}{R^2}[/tex]
where;
M is the mass of Earth = 5.972 x 10²⁴ kgR is the Radius of Earth = 6,371 kmFor Planet Tehar;
[tex]g_T =\frac{G \times 2.1M}{(0.8R)^2} \\\\g_T = 3.28(\frac{GM}{R^2} )\\\\g_T = 3.28 g[/tex]
For planet Loput:
[tex]g_L =\frac{G \times 5.6M}{(1.7R)^2} \\\\g_L = 1.94(\frac{GM}{R^2} )\\\\g_L = 1.94g[/tex]
For planet Cremury:
[tex]g_C =\frac{G \times 0.36M}{(0.3R)^2} \\\\g_C = 4(\frac{GM}{R^2} )\\\\g_C = 4 g[/tex]
For Planet Suven:
[tex]g_s =\frac{G \times 12M}{(2.8R)^2} \\\\g_s = 1.53(\frac{GM}{R^2} )\\\\g_s = 1.53 g[/tex]
For Planet Pentune;
[tex]g_P =\frac{G \times 8.3 }{(4.1R)^2} \\\\g_P = 0.5(\frac{GM}{R^2} )\\\\g_P = 0.5 g[/tex]
For Planet Rams;
[tex]g_R =\frac{G \times 9.3M}{(4R)^2} \\\\g_R = 0.58(\frac{GM}{R^2} )\\\\g_R = 0.58 g[/tex]
The weight Punch on Each Planet at a constant mass is calculated as follows;
[tex]W = mg\\\\W_T = mg_T\\\\W_T = \frac{236}{g} \times 3.28g = 774.08 \ lb\\\\W_L = \frac{236}{g} \times 1.94g =457.84 \ lb\\\\ W_C = \frac{236}{g}\times 4g = 944 \ lb \\\\ W_S = \frac{236}{g} \times 1.53g = 361.08 \ lb\\\\W_P = \frac{236}{g} \times 0.5 g = 118 \ lb\\\\W_R = \frac{236}{g} \times 0.58 g = 136.88 \ lb[/tex]
Thus, the planet that Punch should travel to in order to weigh 118 lb is Pentune.
The complete question is below:
Which planet should Punch travel to if his goal is to weigh in at 118 lb? Refer to the table of planetary masses and radii given to determine your answer.
Punch Taut is a down-on-his-luck heavyweight boxer. One day, he steps on the bathroom scale and "weighs in" at 236 lb. Unhappy with his recent bouts, Punch decides to go to a different planet where he would weigh in at 118 lb so that he can compete with the bantamweights who are not allowed to exceed 118 lb. His plan is to travel to Xobing, a newly discovered star with a planetary system. Here is a table listing the planets in that system (find the image attached).
In the table, the mass and the radius of each planet are given in terms of the corresponding properties of the earth. For instance, Tehar has a mass equal to 2.1 earth masses and a radius equal to 0.80 earth radii.
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Cart 1 has a mass of 1 kg. Cart 2 has a mass of 2 kg. They are pushed apart by a spring. The spring exerts 2N of force into cart 1. How much force is exerted into cart 2? Explain.
The force exerted on the cart 2 during the collision is 2 N.
The given parameters:
Mass of cart 1 = m1 = 1 kgMass of cart 2 = m2 = 2kgForce applied on cart 1 = 2 NAccording to Newton's third law of motion, action and reaction are equal and opposite. The force exerted on cart 1 is equal in magnitude to the force exerted on cart 2 but in opposite direction.
[tex]F_1 = -F_2[/tex]
[tex]F_2 = -F_1\\\\F_2 = -2 \ N\\\\|F_2| = 2 \ N[/tex]
Thus, the force exerted on the cart 2 during the collision is 2 N.
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When dribbling a ball, the ______________ should control the direction and downward motion of the ball.
Answer:
gravity
Explanation:
keeps the ball down on the surface
When dribbling a ball, the gravity should control the direction and downward motion of the ball.
What is projectile motion?When a particle is hurled obliquely near the surface of the earth, it travels along a curved path while accelerating continuously in the direction of the planet's centre (we assume the particle stays close to the surface of the globe). Such a particle's motion is known as projectile motion, and its route is referred to as a projectile.
Two distinct rectilinear motions occur simultaneously in a projectile motion:
Uniform velocity along the x-axis is what causes the particle to move horizontally (ahead).Uniform acceleration along the y-axis is what causes the particle to move vertically (downwards).When a ball is sent into the air at a certain speed, the only force acting on it is the acceleration caused by gravity (g).
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Which of the following rivers flows north in eastern Florida?
St. James
St. Johns
Mississippi
Hudson
St. John’s
_________
o0o0o0o0o0
The momentum of a system is conserved:
I. when no net external force act on the system
II. when no internal forces act on the system
III. always
Answer:
I. when no net external force act on the system
Explanation:
Suppose you are exerting an external force F on an object, it's velocity keeps increasing. Which means its momentum = velocity * mass is also increasing. In this case the initial momentum of that object is not preserved (but increased).
Given that 1 pound is equal to 4.45 newton’s what is the weight of a 500N child in pounds?
Answer:
112.36 pounds
Explanation:
Since 1 pound = 4.45 Newtons, a 500N child in pounds = 500÷4.45 = 112.36 pounds (approximately).
What would happen to a 100N gravitational force if both masses were doubled and the radius were
doubled
The force winds up unchanged, at 100 N.
PLEASE HELP-I LITERALLY NEED THIS RIGHT NOW!!! I'LL GIVE BRAINLIEST AND 5 STARS!!!!!!!!!!!!!!!!
why has the number of islands in hawaii increased over the last 100 million years
Answer: oceanic crust moved over the hot spot, each recently formed volcano was carried away from the hot spot toward the northwest, cutting off its source of lava. Meanwhile, a new island was forming so that over time a chain of islands was produced extending away from the hot spot.ANSWER HERE: This mean that volcanos are producing these new islands and it is creating a chain of different islands all over Hawaii.
Answer:
Oceanic crust moved over the hot spot, each recently formed volcano was carried away from the hot spot toward the northwest, cutting off its source of lava. Meanwhile, a new island was forming so that over time a chain of islands was produced extending away from the hot spot.
A wave has frequency of 5 Hz and a speed of 25 m/s. What is the wavelength of the wave?
I need the Formula,Known,Substitute & Solve Answer with Units
Answer:
This is the answer that I got.
Explanation:
Just check over it once.
The Sun has a mass of 1.99 x 10^30kg [^30 is an exponent] and is 1.5 x 10^11m [^11 is an exponent] from the earth. The planet Earth is 5.98 x 10^24kg [^24 is an exponent]. What is the gravitational attraction between the sun and the earth? G=6.67×10^-11 (-11 is an exponent)
We are given –
Mass of earth,m = 5.98×10²⁴ kgMass of sun, M= 1.99×10³⁰ kgDistance between Earth andSun, r= 1.5×10¹¹ m
G = 6.67×10⁻¹¹ Nm²/kg²We are asked to find the gravitational attraction between the sun and the earth.
By Universal Law of Gravitation, we know that –[tex]\qquad[/tex] [tex]\pink{\twoheadrightarrow\sf F = \dfrac{GMm}{r²}}[/tex]
Substituting values, we get –
[tex]\qquad[/tex] [tex]\twoheadrightarrow\bf F = \dfrac{6.67×10^{-11}\times 5.98×10^{24}\times 1.99×10^{30}}{(1.5×10^{11})^2}[/tex]
[tex]\qquad[/tex] [tex]\twoheadrightarrow\bf F = \dfrac{6.67×10^{-11}×5.98×10^{24}×1.99×10^{30}}{2.25×10^{22}}[/tex]
[tex]\qquad[/tex] [tex]\twoheadrightarrow\bf F = 35.27×10^{21}[/tex]
[tex]\qquad[/tex] [tex]\pink{\twoheadrightarrow\bf F = 3.53×10^{22} N}[/tex]
Henceforth ,gravitational attraction between the sun and the earth. is 3.53×10²²N .______________________________________________
how to calculate velocity with acceleration and time
Answer:
Multiply the acceleration by time to obtain the velocity change:
Example:
Velocity change = 6.95 * 4 = 27.8 m/s . Since the initial velocity was zero, the final velocity is equal to the change of speed. You can convert units to km/h by multiplying the result by 3.6: 27.8 * 3.6 ≈ 100 km/h