A prism and two nets are shown below:


Image of a right triangular prism and 2 nets. The triangle bases have base 4, height 3, and diagonal side 5. The length of the prism from the bases is 9.4. Net A has 3 rectangles in a row. The middle one has sides AC and CD. This middle one has triangle ABC on top and identical triangle below. Net B is the same except that the triangle base ABC is on top of the last rectangle which has sides AC and CD. Units are in inches.


Part A: Which is the correct net for the prism? Explain your answer.


Part B: Write the measurements of Sides AB, BC, and CD of the correct net.

Part C: What is the surface area of the prism? Show your work.

Part A: The correct net for the prism is net A.

Part B: AB = 3 in, BC = 5 in, CD = 9.4 in.

Part C: The surface area of the prism is 124.8 square inches.

A triangular Prism is a pentahedron. It is a 3-D shape with two identical faces in the shape of a triangle connected by three rectangular faces. The edges and vertices of the bases are joined with each other via three rectangular sides.

For the given situation,

The diagram shows the triangular Prism and the 2 nets for it.

Part A:

The correct net for the prism is net A. Net A suits the triangular Prism and it is fold-able along the net.

Part B:

The measurements of sides of the net are

[tex]AB, h=3in[/tex]

[tex]BC, S=5in[/tex]

[tex]CD,l =9.4in[/tex]

Part C:

Base of the triangular prism,b = 4 in

The three sides of the triangle is S1,S2,S3 = 3, 4, 5 inches.

The surface area of the prism is

[tex]A = bh+(s1+s2+s3) l[/tex]

On substituting the above values,

⇒ [tex]A = (4)(3)+(3+4+5) (9.4)[/tex]

⇒ [tex]A=12+(12)(9.4)[/tex]

⇒ [tex]A=12+112.8[/tex]

⇒ [tex]A=124.8[/tex]

Hence we can conclude that

Part A: The correct net for the prism is net A.

Part B: AB = 3 in, BC = 5 in, CD = 9.4 in.

Part C: The surface area of the prism is 124.8 square inches.

Learn more about triangular prism here

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Answer:

For part A the answer is net A

Step-by-step explanation:

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