A plate falls to the floor. When is its potential energy
the lowest?
1.in mid-fall
2.Immediately after it begins to fall
3.When its kinetic energy is the highest
4.Before it falls

Answer:

think it's b

Explanation:

cuz

Answer:

This relationship is from Newtons Second Law of Motion

Newton's second law shows that there is a direct relationship between force and acceleration. The greater the force that is applied to an object of a given mass, the more the object will accelerate.

Its expressed as

F=ma

Answer:

you calculate a specific type of run for example 100m and it takes 20 seconds to finish and calculate the time it takes them to finish

hope this helps

have a good day :)

Explanation:

You need th information about the time period she ran and the distance she covered in that time period to analyze her speed.

The total distance covered by any object per unit of time is known as speed. It depends only on the magnitude of the moving object. The unit of speed is a meter/second.

The generally considered unit for speed is a meter per second.

Your friend wants to join the school track team and has asked for your help to determine how fast she can run the data of her time and the length of the distance she covered in that period of time because the only way to know how fast she runs is to analyze her speed by using the distance and the time.

Thus , you need information about the time period she ran and the distance she covered in that time period to analyze her speed.

Learn more about speed from here, refer to the link;

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[tex] \mathfrak{\huge{ \mathfrak{  \underline{ Answer }}}\:  ✓ }[/tex]

We know, hot water has more energy than the cold water , so when cold water is added in the beaker then heat transfer occurs from hot water to cold water to balance the Energy, causing the drop of temperature from 70° C to 40° C.

Note : Heat transfers occurs from hotter object to cooler one.

_____________________________

[tex] \mathrm{ \#TeeNForeveR}[/tex]

Answer:

The bird and the arrow are 84.621 meters far from the hunter.

Explanation:

The arrow experiments of a parabolic motion, which is the combination of horizontal motion at constant velocity and vertical uniform accelerated motion. The arrow strikes the bird when it reaches its maximum height. First, we determined the time taken by the arrow before striking the bird:

[tex]v = v_{o}\cdot \sin \theta + g\cdot t[/tex] (1)

Where:

[tex]v_{o}[/tex] - Initial speed of the arrow, in meters per second.

[tex]v[/tex] - Final speed of the arrow, in meters per second.

[tex]\theta[/tex] - Launch angle, in sexagesimal degrees.

[tex]g[/tex] - Gravitational acceleration, in meters per square second.

[tex]t[/tex] - Time, in seconds.

If we know that [tex]v_{o} = 40\,\frac{m}{s}[/tex], [tex]\theta = 30^{\circ}[/tex], [tex]g = -9.807\,\frac{m}{s^{2}}[/tex], [tex]v = 0\,\frac{m}{s}[/tex], then the time taken by the arrow is:

[tex]t = \frac{v-v_{o}\cdot \sin \theta}{g}[/tex]

[tex]t = \frac{0\,\frac{m}{s}-\left(40\,\frac{m}{s}\right)\cdot \sin 30^{\circ} }{-9.807\,\frac{m}{s^{2}} }[/tex]

[tex]t = 2.039\,s[/tex]

And the initial horizontal distance of the arrow ([tex]x_{i}[/tex]) is determined by this kinematic formula:

[tex]x_{i} = (v_{o}\cdot \cos \theta)\cdot t[/tex] (2)

If we know that [tex]v_{o} = 40\,\frac{m}{s}[/tex], [tex]\theta = 30^{\circ}[/tex] and [tex]t = 2.039\,s[/tex], then the initial horizontal distance is:

[tex]x_{i} = \left[\left(40\,\frac{m}{s} \right)\cdot \cos 30^{\circ}\right]\cdot (2.039\,s)[/tex]

[tex]x_{i} = 70.633\,m[/tex]

There is an inelastic collision between the arrow and the bird, the initial velocity of the bird-arrow system is:

[tex]v = \frac{m_{A}\cdot v_{o}\cdot \cos \theta}{m_{A}+m_{B}}[/tex] (3)

Where:

[tex]v[/tex] - Initial velocity of the bird-arrow system, in meters per second.

[tex]m_{A}[/tex] - Mass of the arrow, in kilograms.

[tex]m_{B}[/tex] - Mass of the bird, in kilograms.

If we know that [tex]m_{A} = 0.5\,kg[/tex], [tex]m_{B} = 2\,kg[/tex], [tex]v_{o} = 40\,\frac{m}{s}[/tex] and [tex]\theta = 30^{\circ}[/tex], then the initial velocity of the bird-arrow system is:

[tex]v = \frac{(0.5\,kg)\cdot \left(40\,\frac{m}{s} \right)\cdot \cos 30^{\circ}}{0.5\,kg + 2\,kg}[/tex]

[tex]v = 6.928\,\frac{m}{s}[/tex]

And the maximum height reached by the arrow ([tex]y[/tex]), in meters, is:

[tex]y = y_{o} + (v_{o}\cdot \sin \theta)\cdot t +\frac{1}{2}\cdot g\cdot t^{2}[/tex] (4)

Where [tex]y_{o}[/tex] is the initial height of the arrow, in meters.

If we know that [tex]y_{o} = 0\,m[/tex], [tex]v_{o} = 40\,\frac{m}{s}[/tex], [tex]\theta = 30^{\circ}[/tex],  [tex]g = -9.807\,\frac{m}{s^{2}}[/tex] and [tex]t = 2.039\,s[/tex], then the maximum height reached by the arrow is:

[tex]y = 0\,m + \left(40\,\frac{m}{s} \right)\cdot (2.039\,s)\cdot \sin 30^{\circ} +\frac{1}{2}\cdot \left(-9.807\,\frac{m}{s^{2}}\right)\cdot (2.039\,s)^{2}[/tex]

[tex]y = 20.394\,m[/tex]

Time needed by the bird-arrow system to land is determined by this expression based on (4):

[tex]y = y_{o} + (v_{o,y})\cdot t +\frac{1}{2}\cdot g\cdot t^{2}[/tex]

If we know that [tex]y_{o} = 20.394\,m[/tex], [tex]y = 0\,m[/tex], [tex]v_{o,y} = 0\,\frac{m}{s}[/tex] and [tex]g = -9.807\,\frac{m}{s^{2}}[/tex], then the time needed to land is:

[tex]0\,m = 20\,m + \left(0\,\frac{m}{s} \right)\cdot t + \frac{1}{2}\cdot \left(-9.807\,\frac{m}{s^{2}} \right)\cdot t^{2}[/tex]

[tex]t = 2.019\,s[/tex]

And the horizontal distance travelled by the bird-arrow system ([tex]x_{ii}[/tex]), in meters, is calculated from a formula based on (2):

[tex]x_{ii} = v_{o, x}\cdot t[/tex]

If we know that [tex]v_{o,x} = 6.928\,\frac{m}{s}[/tex] and [tex]t = 2.019\,s[/tex], then the distance travelled by the bird-arrow system is:

[tex]x_{ii} = \left(6.928\,\frac{m}{s} \right)\cdot (2.019\,s)[/tex]

[tex]x_{ii} = 13.988\,m[/tex]

The final distance of the bird-arrow system from the hunter is:

[tex]x = x_{i} + x_{ii}[/tex]

[tex]x = 70.633\,m + 13.988\,m[/tex]

[tex]x = 84.621\,m[/tex]

The bird and the arrow are 84.621 meters far from the hunter.

Answer:

C. Particles that make up a nucleus

Explanation:

A P E X

Answer:

D. elliptical galaxy

Explanation:

Hope this helps :)

Answer:

kE=1/2mv^2

Explanation:

here

KE= 15000j

velocity =20m/s

mass=?

now

mass=

15000×2= (m)20^2

30000=m ×400

30000÷400=m

Mass (m)= 75

therefore mass is 75kilogram

Answer:

[tex] y_{t} = 253.94 m [/tex]

Explanation:

Para resolver este problema debemos contemplar dos tramos.

En el primer tramo, la fuerza aplicada impulsa al cuerpo a subir una altura dada debido a la aceleración que genera esa fuerza.

[tex] \Sigma F = ma [/tex]

[tex] F - P = ma [/tex]

[tex] F - mg = ma [/tex]

En donde:

F: es la fuerza aplicada = 60 N

P: es el peso del cuerpo = mg

m: es la masa del cuerpo = 4 kg

g: es la aceleración debido a la gravedad = 9.81 m/s²

a: es la aceleración

Entonces, la aceleración generada por la fuerza aplicada es:

[tex] a = \frac{F - mg}{m} = \frac{60 N - 4kg*9.81 m/s^{2}}{4 kg} = 5.19 m/s^{2} [/tex]

Ahora, debemos calcular la altura recorrida mientras el cuerpo está acelerado hacia arriba:

[tex] y_{{1}} = y_{0} + v_{0}t + \frac{1}{2}at^{2} [/tex]  

En donde:

[tex] y_{1}[/tex]: es la altura final del tramo 1 =?                                                                          [tex] y_{0}[/tex]: es la altura inicial = 0  

[tex] v_{0}[/tex]: es la velocidad inicial = 0 (parte del reposo)  

t: es el tiempo = 8 s

[tex] y_{1} = 0 + 0 + \frac{1}{2}5.19 m/s^{2}*(8 s)^{2} = 166.08 m [/tex]  

Por lo tanto, mientras el cuerpo está acelerado (durante los 8 s) recorre 166.08 metros.  

Ahora, en el segundo tramo el cuerpo sigue subiendo hasta alcanzar una altura máxima para luego comenzar a descender. Podemos usar la siguiente ecuación para calcular la altura recorrida.  

[tex] v_{f}^{2} = v_{0}^{2} - 2gy_{2} [/tex]  

En donde:    

[tex] v_{f}[/tex]: es la velocidad final = 0 (en la altura máxima)

[tex] v_{0}[/tex]: es la velocidad inicial

Primero debemos encontrar la velocidad inicial en el segundo tramo, que es igual a la velocidad final del primer tramo:

[tex] v_{f} = \sqrt{v_{0} + 2ay_{1}} = \sqrt{0 + 2*5.19 m/s^{2}*166.08 m} = 41.52 m/s [/tex]    

Entonces, la altura recorrida en el segundo tramo es:

[tex] y_{2} = \frac{v_{0}^{2} - v_{f}^{2}}{2g} = \frac{(41.52 m/s)^{2} - 0}{2*9.81 m/s^{2}} = 87.86 m [/tex]

Finalmente, la altura máxima es:

[tex]y_{t} = y_{1} + y_{2} = 166.08 m + 87.86 m = 253.94 m[/tex]

Espero que te sea de utilidad!

Answer:

the distance should be changed by a factor of √2

Explanation:

The attractive force between the couples can be given by Newton's Law of Gravitation:

[tex]F =\frac{Gm_1m_2}{r^2}[/tex]

where,

F = Attractive Force

G = Universal Gravitational Constant

m₁ = mass of the first person

m₂ = mass of the second person

r = distance between them

Now, if we want to halve the force without changing masses, hen:

[tex]F' = \frac{1}{2} F = \frac{1}{2} \frac{Gm_1m_2}{r^2}\\\\F' = \frac{1}{2} F = \frac{Gm_1m_2}{(\sqrt{2}r)^2}[/tex]

Hence, it is clear that the distance should be changed by a factor of √2

Answer:

2

Explanation:

Answer:

Resistors restrict current flow through a circuit.

(The electrons don't easily get from one side to the other)

High voltage is actually needed for to send power over long distances because if you use high current, a lot of the power is lost to the resistance in the wires.

Explanation:

hope it helps <3

Explanation:

8. Real and inverted

9. Concave mirror

Answer:

1. A

2. C

3. A

Explanation:

I'm so sorry if I am wrong

Answer:

the answer is refraction, btw could u

say which grades question this is

Venn diagram should be titled traditional physics

Based on the Venn Diagram, Title 1 should be Quantum Mechanics, and Title 2 should be Traditional Physics.

A Venn Diagram is a diagram which shows the similarities as well as differences between two or more items.

Overlapping points show similarities while non-overlapping points show differences.

The Venn Diagram above illustrates Traditional physics and quantum mechanics.

Title 1 is quantum mechanics and Title 2 is Traditional physics.

Therefore, the Venn Diagram illustrates the difference and similarities between quantum physics and traditional physics.

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Answer: [tex]12.82\ m/s[/tex]

Explanation:

Given

Mass of car [tex]m=991\ kg[/tex]

Force applied [tex]F=31,770\ N[/tex]

time period [tex]t=0.4\ s[/tex]

Acceleration associated with car

[tex]\Rightarrow a=\dfrac{F}{m}\\\\\Rightarrow a=\dfrac{31770}{991}\\\\\Rightarrow a=32.05\ m/s^2[/tex]

Acceleration is the change in velocity w.r.t time

[tex]\Rightarrow a=\dfrac{\Delta v}{\Delta t}\\\\\Rightarrow 32.05=\dfrac{\Delta v}{0.4}\\\\\Rightarrow \Delta v=12.82\ m/s[/tex]

thus, the change in velocity is [tex]12.82\ m/s[/tex]

1/do + 1/di = 1/f

blah blah blah why does the answer have to be 20 characters long

Answer:

Its D

Explanation:

The lamp and the ice bag were at the same place.  

Sounds like the experiment was intended to show on a small scale ocean currents from the poles to the equator and back to the poles. The bag of ice would simulate the cold at the poles while the lamp would simulate the heat provided by the sun near the equator. With that in mind, let's look at the possible flaws and see what is likely.  

Not enough ink was added

Answer:

Refraction is the correct option

Answer: refraction

Explanation: it is the bending of light rays as it moves from one medium to another.

Answer:

False

Explanation:

It is also tall.

Genotype is a way to describe the combination of alleles that an individual has for a certain gene (Table below). For each gene, an organism has two alleles, one on each chromosome of a homologous pair of chromosomes (think of it as one allele from Mom, one allele from Dad). The genotype is represented by letter combinations, such as TT, Tt, and tt.

Answer:

The answer is D.) 90

Explanation:

the electromagnetic wave is a transverse wave. the electric field makes an angle of 90° with the magnetic field. both these fields, in turn, make an angle of 90° with the direction of movement of the wave.

Answer: 1.38 km/h

Explanation: Mass divided by Force

Answer:

10 m/s

Explanation:

Applying,

Kentic energy of the pelllet = Spring elestic energy

1/2(mv²) = 1/2ke²

mv² = ke²...................... Equation 1

Where m = mass of the pellet, v = velocity of the pellet, k = force constant of the spring, e = extension of the spring

make v the subject of the equation

v = √(ke²/m)................. Equation 2

From the question,

Given: k = 50 N/m, e = 2 m, m = 2.0 kg

Substitute these values into equation 2

v = √(50×2²/2)

v = √(50×2)

v = √(100)

v = 10 m/s

Answer:

The correct answer is - oxygen.

Explanation:

Cardiovascular endurance is the ability to do physical activity or exercise without affecting or being tired for a longer time period. Aerobic exercise or activity can help to increase cardiovascular endurance.

Improving the cardiovascular system helps in delivering oxygen as per the demands with the help of the heart that pumps the oxygen-rich blood to different organs of an individual and lungs by inhaling enough oxygen.

P = 5 watt

Explanation:

P = VI

= (10 volt)(0.5 A)

= 5 watt

The electric power developed by the lamp will be 5 watts. Electric power is found by the multiplication of voltage and electric current.

Electric power is the product of the voltage and current. Its unit is the watt.

The given data in the problem is;

The voltage is,V = 10 volt (V)

The electric current is,I = 0.5 ampere (A)

The formula for the power is given as;

[tex]\rm P= V I \\\\\ P= 10 \times 0.5 \\\\ P= 5 \ watt[/tex]

Hence electric power developed by the lamp will be 5 watts.

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