Answer:
F = 200 N
Explanation:
Given that,
The mass suspended from the rope, m = 20 kg
We need to find the resultant force acting on the rope. The resultant force on the rope is equal to its weight such that,
F = mg
Where
g is acceleration due to gravity
Put all the values,
F = 20 kg × 10 m/s²
F = 200 N
So, the resultant force on the mass is 200 N.
Eroded debris that is dropped at the glaciers farthest extent when ice melts at the front of the glacier as seen in the image is called
A. Terminal Moraines
B. Lateral Moraines
c. Gradient
D. Striations
Answer:
A) terminal moraines
Explanation:
Moraines are the rocks and sediments deposited by moving glaciers. Terminal means the end, the furthest the glacier travels. Lateral means what's deposited along the sides of the moving glacier.
Describe how to determine the thickness of a sheet of a paper without a caliper.
Answer:
Divide the total measurement of the stack/ream of paper by the number of sheets. For example: 2 inches/100 pages = 0.01-inches sheets.
In case you measured the stack, and it gave you less than an inch, then you need to do the same. For example: 0.5-inches/100 sheets = 0.005-inches per sheet.
Answer:
Divide the total measurement of the stack/ream of paper by the number of sheets. For example: 2 inches/100 pages = 0.01-inches sheets.
In case you measured the stack, and it gave you less than an inch, then you need to do the same. For example: 0.5-inches/100 sheets = 0.005-inches per sheet.
Explanation:
I WILL MARK YOU THE BRAINLIEST
What is the net force acting on the airplane?
740 N right -->
700 N right -->
100 N left <--
760 N right -->
Explanation:
700N right
to get the net force
you gotta let one direction be the negative ( the smaller force)
so the total force towards the left is 100N ( 60 + 40= 100)
which is smaller than the right force which is 800 N so you let 100 N be negative
so without even calculating , you can know that it will be moving towards the right because right force > left force
your add both forces ( remember 100 N is negative)
so 800N + ( - 100N)
= 700N
towards the right
hope this helps
this is just one method that helped me understand
please mark it brainliest
why doesn't the arrow fly forever
Because gravity pulls it down
A 56.6-kg crate rests on a level floor at a shipping dock. The coefficients of static and kinetic friction are 0.517 and 0.260, respectively. What horizontal pushing force is required to (a) just start the crate moving and (b) slide the crate across the dock at a constant speed
Answer:
Explanation:
Magnitude of frictional force = μ mg
μ is either static or kinetic friction.
To start the crate moving , static friction is calculated .
a ) To start crate moving , force required = μ mg where μ is coefficient of static friction .
force required =.517 x 56.6 x 9.8 = 286.76 N .
b ) to slide the crate across the dock at a constant speed , force required
= μ mg where μ is coefficient of kinetic friction , where μ is kinetic friction
= .26 x 56.6 x 9.8 = 144.21 N .
Usami Bolt has a mass of 85kg and is running at a steady speed of 10m/s how much kinetic energy does he have
Answer:
Ek = 4250 J
Explanation:
Data:
m = 85 kgv = 10 m/sEk = ?Formula:
[tex]\boxed{\bold{Ek=\frac{m*(v)^{2}}{2}}}[/tex]Replace and solve:
[tex]\boxed{\bold{Ek=\frac{85\ kg*(10\frac{m}{s})^{2}}{2}}}[/tex][tex]\boxed{\bold{Ek=\frac{85\ kg*100\frac{m^{2}}{s^{2}}}{2}}}[/tex][tex]\boxed{\bold{Ek=\frac{8500\ J}{2}}}[/tex][tex]\boxed{\boxed{\bold{Ek=4250\ J}}}[/tex]It has 4250 Joules of Kinetic Energy.
Greetings.
Solve for resistance. I do not get it. Pls help
Answer: I think a
Explanation:
Pop up spring Lab
Describe the energy conversion that took place. What energy was present just before the jump? What energy is present at its maximum height? What happens in between?
Draw bar charts of energy before the jump, while the spring toy is compressed and after the jump at the maximum height of its jump. Be sure to label each type of energy.
Answer:
I honestly don't know but that thing looks cool lol
A bus travels to and from a school that is located 10 km to the west. What is the distance? What is the displacement?
20 km
Hope this helps Have a good day
A spring with a spring constant of 2.5 N/m is stretched by 0.2 m. What is the potential energy in the spring
Answer:
Explanation:
PE = [tex]\frac{1}{2}k[/tex](Δ[tex]x^2[/tex])
where k is the spring constant and Δx is the displacement of the spring when an object is hung from it. Plugging in:
[tex]PE=\frac{1}{2}(2.5)(.2^2)[/tex] which gives us
PE = .05 J
A tire has a tread pattern with a crevice every 2.20 cm. Each crevice makes a single vibration as the tire moves. What is the frequency of these vibrations if the car moves at 38.0 m/s
Answer:
17.27 Hz
Explanation:
Applying
v = λf................ Equation 1
Where v = speed of the car, λ = Distance between successive crevice, f = number of crevice moved in 1 seconds(Frequency of the vibration)
make f the subject of the equation
f = v/λ............. Equation 2
From the question,
Given: v = 38 m/s, λ = 2.2 m
Substitute these values into equation 2
f = 38/2.2
f = 17.27 Hz
what is the dimension formula of power and pressure
Answer:
Power = ML²T⁻³
Pressure = ML⁻¹T⁻²
Explanation:
Applying,
Power(P) = Work(W)/Time(t)
P = W/t..................... Equation 1
But
W = Fd............. Equation 2
Where F = force, d = distance
Also,
F = ma.............. Equation 3
Where m = mass, a = acceleration.
Also,
a = v/t................ Equation 4
Where v = velocity
Also,
v = d/t............... Equation 5
Where d = distance
Substitute equation 5 into equation 4
a = d/t²................. Equation 6
Substitute equation 6 into equation 3
F = m(d/t²)........... Equation 7
Susbtitute equation 7 into equation 2
W = m(d/t²)×d
W = md²/t²........... Equation 8
Substitute equation 8 into equation 1
P = (md²/t²)/t
P = md²/t³............ Equation 9
In dimension,
mass(m) = M, distance(d) = L, time(t) = T
Substitute into equation 9
P = ML²/T³
P = ML²T⁻³
And
Pressure(R) = Force(F)/Area(A)
R = F/A................ Equation 10
F = md/t²,
A = d²
Susbtitute into equation 10
R = (md/t²)/d²
R = m/t²d
Therefore,
R = ML⁻¹T⁻²
A physical science test book has a mass of 2.2 kg what is the weight on the earth
Answer:
21.582 Newtons
Explanation:
The weight of an object on Earth is equal to W=9.81M where M is the mass of the object and the acceleration due to gravity is 9.81 m/s^2. Therefore, the weight of the book on the earth is W=9.81(2.2)=21.582N, or 21.582 Newtons
difference between acceleration due to gravity and gravity
Answer:
The gravitational force between earth and any object is known as gravity.
...
G.P.E = weight (n) x height (m). 2 identical twins are skiing down 2 different slopes. one is 1000m high, the other is 1500 m high. the twin at 1000m weighs 150 N. the other twin weighs 100 N. which twin has the most P.E before they begin skiing?
Answer:
I don't know i really I'm sorry I wish I could help
Suppose that Joe and Jim are twins and :
________________________________
Joe :
Height = 1000 m
==》 PE = 150 × 1000
Weight = 150 N
==》 PE = 150,000 j
_________________________________
Jim :
Height = 1500 m
==》PE = 100 × 1500
Weight = 100 N
==》PE = 150,000 j
______________________________
As u can see Joe and Jim has equal PE before they begin skiing .
Two forces of 8N and 10N CANNOT give a resultant of
a. 1 N
b. 2 N
c. 9 N
d. 18 N
Answer:
I believe it is D
forgive me if I'm wrong
Calculate their speed between points A and B. Include the units.
What was their average speed for this ride? Include the units.
= Total Distance/Total time
= 30/3
= 10 km/h
Average speed for this rideAverage speed = Total distance travelled/time taken
= 50/6
= 8.3 km/h
the magnetic field 0.100 m from a wire is 4.20x10^-5 T. what is the field 0.200 m from the wire
Answer:
Your answer is given below:
Explanation:
A student uses the circuit shown to determine the resistance of two identical resistors.
H--
А.
V
The voltmeter reading is 2.2V and the ammeter reading is 0.25A.
What is the resistance of each resistor?
A 0.2752
B
0.552
C 4.4Ω
D
8.82
Answer:
B. 0.552
Explanation:
To find the resistance in the circuit above, u simply divide the current in the circuit by the voltage to get the resistance.
A blow-dryer and a vacuum cleaner each operate with a voltage of 120 V. The current rating of the blow-dryer is 14 A, while that of the vacuum cleaner is 4.2 A. Determine the power consumed by (a) the blow-dryer and (b) the vacuum cleaner. (c) Determine the ratio of the energy used by the blow-dryer in 16 minutes to the energy used by the vacuum cleaner in 43 minutes.
Answer:
The correct solution is:
(a) 1680 W
(b) 504 W
(c) 1.240
Explanation:
The given values are:
Voltage,
V = 120 V
Current of blow dryer,
I₁ = 14 A
Current of vacuum cleaner,
I₂ = 4.2 A
Time,
t₁ = 16 min
t₂ = 43 min
As we know,
⇒ [tex]Power (P) = VI[/tex]
(a)
For blow dryer:
⇒ [tex]P_1=V\times I_1[/tex]
[tex]=120\times 14[/tex]
[tex]=1680 \ W[/tex]
(b)
For Vacuum cleaner:
⇒ [tex]P_2=V\times I_2[/tex]
[tex]=120\times 4.2[/tex]
[tex]=504 \ W[/tex]
(c)
The ratio will be:
= [tex]\frac{Blow \ dryer \ energy}{Vacuum \ cleaner \ energy}[/tex]
= [tex]\frac{P_1\times t_1}{P_1\times t_2}[/tex]
= [tex]\frac{1680\times 16}{504\times 43}[/tex]
= [tex]\frac{26880}{21672}[/tex]
= [tex]1.240[/tex]
58
74
3 points
A hummingbird beats its wings up and down with a frequency of 100 Hz. What is the period of the hummingbirds flaps? (D
YOUR ANSWER)
59
Answer:
T = 0.01 s
Explanation:
Given that,
The frequency of the beats of a hummingbird, f = 100 Hz
We need to find the period of the hummingbirds flaps. Let the time is t. We know that the relation between frequency and time period is given by :
T = 1/f
Put all the values,
T = 1/100 = 0.01 s
So, the time period of the humming bird is 0.01 s.
A TV has a power of 65 watts and an efficiency of 70 percent. How much
power is wasted as heat?
A. 19.5 W
B. 2.2 W
C. 0.9 W
D. 45.5 W
Power of TV = 65Watt
If Efficiency = 70%, then the percentage of energy wasted is 30%
So, the amount of energy getting wasted:
= 30/100 × 65
= 1950/100
= 195/10
= 19.5 W
1
The distance between objects, along with the masses of the object, affect the gravitational force between the objects. Which
statement is TRUE according to Newton's law of universal gravitation?
O When the masses of objects increase, gravitational force decrease
O When the distance between objects increases, gravitational force decreases.
O When distances between objects decreases, gravitational force decreases
O When the masses of objects decrease, the distance between objects decreases.
Every object in the universe attracts every other object with a force along a line joining them. The force is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centers of mass.
A skipper on a boat notices wave crests passing the anchor chain every 6.0 seconds. The skipper estimates the distance between crests at 30.0
m. What is the speed of the water waves?
Explanation:
given Time Period = 5 Sec
Amplitude = 1m, Wave length = 15 m
using time period = 1/ frequency , Frequency = 1/5 cycles per sec = 0.2 sec = 12 per min
wave speed= Frequency * Wave length
speed = 0.2*15 = 3m/s
An argon gas occupies 56.2 L at 760 torr. If the volume of gas dereases to 1/4 of the original volume ,calculate its final pressure
Answer:
3040 torr
Explanation:
Applying,
PV = P'V'..................... Equation 1
Where P = Initial Pressure, V = Initial volume, P' = Final pressure, V' = Final volume.
Make P' the subject of the equation
P' = PV/V'................. Equation 2
From the question,
Given: P = 760 torr, V = 56.2 L, V' = 56.2/4 = 14.05 L
Substitute these values into equation 2
P' = (56.2×760)/14.05
P' = 3040 torr
Una esfera de aluminio de 250 g a una temperatura de 230 °C se introduce en 450 g de alcohol a una temperatura de 18 °C. Determine la temperatura de equilibrio del sistema. El calor específico del aluminio es 911 J kg-1 °C-1 y para el alcohol 2100 J kg-1 °C-1.
Answer:
La temperatura de equilibrio del sistema es de aproximadamente 59,17 °C
Explanation:
La masa de la esfera de aluminio, m₁ = 250 g
La temperatura inicial de la esfera de aluminio, T₁ = 230 °C
La capacidad calorífica específica del aluminio, c₁ = 911 J / (kg·°C)
La masa del alcohol, m₂ = 450 g
La temperatura inicial del alcohol, T₂ = 18 ° C
La capacidad calorífica específica del alcohol, c₂ = 2,100 J/(kg·°C)
Observamos que el punto de ebullición del alcohol ≈ 78,37°C
Sea 'T' la temperatura de equilibrio del sistema, obtenemos;
ΔQ₁ = ΔQ₂
ΔQ₁ = Calor transferido desde el aluminio = m₁ · c₁ · (T₁ - T)
ΔQ₂ = Calor transferido al alcohol = m₂ · c₂ · (T - T₂)
∴ m₁ · c₁ · (T₁ - T) = m₂ · c₂ · (T - T₂)
Por lo tanto, por sustitución, obtenemos
250 × 911 × (230 - T) = 450 × 2100 × (T - 18)
Usando una calculadora gráfica, tenemos;
T = 277570/4691 °C ≈ 59,17 °C
La temperatura de equilibrio del sistema, T ≈ 59.17 °C
An iron nail having threads along its cylindrical surface is
Answer:
A screw is a mechanism that converts rotational motion to linear motion, and a torque (rotational force) to a linear force.[1] It is one of the six classical simple machines. The most common form consists of a cylindrical shaft with helical grooves or ridges called threads around the outside.[2][3] The screw passes through a hole in another object or medium, with threads on the inside of the hole that mesh with the screw's threads. When the shaft of the screw is rotated relative to the stationary threads, the screw moves along its axis relative to the medium surrounding it; for example rotating a wood screw forces it into wood. In screw mechanisms, either the screw shaft can rotate through a threaded hole in a stationary object, or a threaded collar such as a nut can rotate around a stationary screw shaft.[4][5] Geometrically, a screw can be viewed as a narrow inclined plane wrapped around a cylinder.
Explanation:
Which statement best describes the Sun Earth-Moon system?
Answer:
A
Explanation:
A. The Moon orbits the Earth, and the Earth-Moon system orbits the Sun
B. The Earth and Moon both orbit the Sun separately
C. The Sun orbits the Earth-Moon system
D. The Moon revolves around Earth but not the Sun
PLEASE HELP WILL MARK BRAINLIEST *
In an electric circuit, 40 C of electric charge pass a point in 5.0 s.
What is the current in the circuit?
A 0.13A
B
8.0A
C 45A
D
200 A
Answer:
Explanation:
current=amount of charge/time taken
=40/5
=8 ampere(A)
The current flowing in the circuit is 8 A.
The correct answer to the question is Option B. 8 A.
Quantity of electricity, current and time are related by the following equation:
Q = ItWhereQ is the quality of electricity.
I is the current.
t is the time.
With the above formula, we can obtain the current in the circuit as illustrated below:Quantity of electricity (Q) = 40 C
Time (t) = 5 s
Current (I) =?Q = It
40 = I × 5
Divide both side by 5
I = 40 / 5
I = 8 AThus, the current in the circuit is 8 A.
The correct answer to the question is Option B. 8 A
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