A particle is moving with the given data. Find the position of the particle. a(t) = 13 sin(t) + 3 cos(t), s(0) = 0, s(2π) = 12

Answer:

he additive inverse of:

a)  [tex]-6x^2-x-2[/tex] is : [tex]6x^2+x+2[/tex]

b)  [tex]6x^2-x+2[/tex]  is :  [tex]-6x^2+x-2[/tex]

c)  [tex]6x^2+x-2[/tex]  is :  [tex]-6x^2-x+2[/tex]

d)  [tex]6x^2+x+2[/tex]  is :  [tex]-6x^2-x-2[/tex]

Step-by-step explanation:

You need to consider that the additive inverse of a polynomial is that polynomial that consists of the opposite of each term of the polynomial given.

Then, the additive inverse of:

a)  [tex]-6x^2-x-2[/tex] is :  [tex]6x^2+x+2[/tex]

b)  [tex]6x^2-x+2[/tex]  is :  [tex]-6x^2+x-2[/tex]

c)  [tex]6x^2+x-2[/tex]  is :  [tex]-6x^2-x+2[/tex]

d)  [tex]6x^2+x+2[/tex]  is :  [tex]-6x^2-x-2[/tex]

Answer:

Step-by-step explanation:

Given:

  c/2 -5 = 7

  Step 1: c/2 -5 +5 = 7 +5

  Step 2: c/2 +0 = 12

  Step 3: c/2 = 12

  Step 4: 2(c/2) = 12(2)

  Step 5: c = 24

Find:

  The property that justifies each step of the solution.

Solution:

  Step 1: addition property of equality (lets you add the same to both sides)

  Step 2: integers are closed to addition

  Step 3: identity property of addition (adding 0 changes nothing)

  Step 4: multiplication property of equality

  Step 5: closure of real numbers to multiplication; identity property of multiplication

_____

It is hard to say what "property" you want to claim when you simplify an arithmetic expression. Above, we have used the property that the sets of integers and real numbers are closed to addition and multiplication. That is, adding or multiplying real numbers gives a real number.

In Step 5, we can rearrange 2(c/2) to c(2/2) using the commutative property of multiplication. 2/2=1, and c×1 = c. The latter is due to the identity element for multiplication: multiplying by 1 changes nothing.

Apart from the arithmetic, the other properties used are properties of equality.  Those let you perform any operation on an equation, as long as you do it to both sides of the equation. The operations we have performed in this fashion are adding 5 and multiplying by 2.

Answer:

Step 1 ~ addition property of equality

Step 2 ~ additive inverses

Step 3 ~ additive identity

Step 4 ~ multiplication property of equality

Explanation:

Addition property of equality means that If two expressions are equal to each other, and you add the same value to both sides of the equation, the equation will remain equal. In this problem, they added 5 to both sides to make the equation balanced.

Additive inverses means what you add to a number to get zero.  The negative of a number. -5 + 5 = 0.

Additive identity means that the sum of a number and 0 is that number.

Multiplication property of equality states that when you multiply both sides of an equation by the same number, the two sides remain equal. In this problem, they multiplied 2 to both sides to get rid of the denominator in the fraction.

Answer:

Step-by-step explanation:

Probability is the likelihood or chance that an event will occur.

Probability = expected outcome/total outcome

Since a six-sided die is rolled, the total outcome will be the total number of possible siedes a die contain {1, 2, 3, 4, 5, 6} i.e 6 elements

If a number less than 2 is gotten, the expected outcome will be {1} i.e 1 element.

Probability of getting a number less than 2 = 1/6

If a prime number is gotten, the outcome will be the elements {2, 3, 5} i.e 3 elements.

The probability of getting a prime number = 3/6 = 1/2

The probability of getting a number less than 2 OR a prime number upon rolling a six-sided die will be 1/6*1/2 = 1/18

Answer:

Step-by-step explanation:

On a six-sided die, there is only one way to get a number less than 2, which is by rolling a 1.  So the probability of getting a number less than 2 is:

P left parenthesis l e s s space t h a n space 2 right parenthesis equals 1 over 6

There are three primes numbers when rolling a six-sided die, which are {2, 3, 5}.  So the probability of getting a prime number is:

P left parenthesis p r i m e right parenthesis equals 3 over 6

Since there is no overlap between these two events, the probability of getting a number less than 2 OR a prime number is:

P left parenthesis l e s s space t h a n space 2 space o r space p r i m e right parenthesis equals P left parenthesis l e s s space t h a n space 2 right parenthesis plus P left parenthesis p r i m e right parenthesis equals 1 over 6 plus 3 over 6 equals 4 over 6 equals 2 over 3

Answer is 2/3

Answer:

0.65

Step-by-step explanation:

There are 65 student that do sports as 20+20+25=65. In total there are 100 student and you find this by adding up all the values. Now all you do is divide 65/100 and get 0.65 and that is the probability a random student plays sports.

Answer:

The answer is 1/1296

Step-by-step explanation:

6^-4 can be written as 1/6⁴

And

1/6⁴ = 1/1296

Hope this helps you.

Answer:

a

The Null hypothesis represented as

     [tex]H_0: \mu_1 - \mu_2 = 0[/tex]

The Alternative hypothesis represented as

     [tex]H_a: \mu_1 - \mu_2 < 0[/tex]

b

p-value =  P(Z <  -3.37  )  = 0.000376

c

There is insufficient evidence to conclude that graduate students score higher, on average, on the HPI than undergraduate students

Step-by-step explanation:

From the question we are told that

   The population size is  [tex]n= 650[/tex]

    The  sample size for graduates is  [tex]n_1 = 300[/tex]

     The sample  mean for graduates is [tex]\= x _1 = 148[/tex]

      The sample  standard deviation for graduates is [tex]\sigma_1 = 16[/tex]

    The  sample size for under-graduates is [tex]n _2 = 350[/tex]

         The sample  mean for under-graduates is [tex]\= x _2 = 153[/tex]

         The sample  standard deviation for graduates is [tex]\sigma_2 = 21[/tex]

The Null hypothesis represented as

     [tex]H_0: \mu_1 - \mu_2 = 0[/tex]

The Alternative hypothesis represented as

     [tex]H_a: \mu_1 - \mu_2 < 0[/tex]

Where [tex]\mu_1 \ and \ \mu_2[/tex] are the population mean

  Now the test statistic is mathematically represented as

          [tex]t = \frac{(\= x_1 - \= x_2 ) }{ \sqrt{ \frac{ (n_1 - 1 )\sigma_1 ^2 + (n_2 - 1)\sigma_2^2}{n_1 +n_2 -2} } * \sqrt{ \frac{1}{n_1} + \frac{1}{n_2} } }[/tex]

substituting values

       [tex]t = \frac{(148 - 153 ) }{ \sqrt{ \frac{ (300- 1 )16 ^2 + (350 - 1) 21^2}{300 +350 -2} } * \sqrt{ \frac{1}{300} + \frac{1}{350} } }[/tex]

      [tex]t = -3.37[/tex]

The p-values is mathematically evaluated as

     p-value =  P(Z <  -3.37  )  = 0.000376

The above answer is gotten using a p-value calculator  at (0.05) level of significance

     Looking the p-value we see that it is less than the level of significance (0.05)  so Null hypothesis is rejected

Hence there is insufficient evidence to conclude that graduate students score higher, on average, on the HPI than undergraduate students

Following are the two-Sample of the T-Test and CI:

[tex]\boxed{\boxed{\begin{matrix}Sample& N &Mean& StDev& SEMean\\ 1 &350 &153.0& 21.0 &1.1 \\ 2& 300& 148.0& 16.0& 0.92\end{matrix}}}[/tex]

Calculating the difference:

[tex]= \mu (1) - \mu (2)\\\\[/tex]

The estimated difference: [tex]5.00[/tex]

When the [tex]95\%[/tex] of CI so, the difference:[tex](2.09, 7.91)[/tex]

Therefore the T-Test difference value = 0

[tex]\to (vs \neq): T-Value = 3.37 \\\\\to P-Value = 0.001 \\\\\to DF = 648[/tex]

When the both use Pooled so, the StDev = 18.8583

Therefore, the final value of t is "3.37".

Learn more:

brainly.com/question/16380581

Answer:

Given,

X=2

y=-2

z=3

Now,

[tex]3x + y - z \\ = 3 \times 2 + ( - 2) - 3 \\ = 6 + ( - 2) - 3 \\ = 6 - 2 - 3 \\ = 4 - 3 \\ = 1[/tex]

Hope this helps...

Good luck on your assignment..

Answer:

1

Step-by-step explanation:

3X+Y-Z

Where X = 2, Y = -2 amd Z = 3

=> 3(2)+(-2)-(3)

=> 6-2-3

=> 4-3

=> 1

Answer:

Domain : (-∞, ∞)

Range : (-∞, ∞)

Step-by-step explanation:

Parent function (y = [tex]\sqrt[3]{x}[/tex] ) of the given function y = -[tex]\sqrt[3]{x}[/tex] has been shown as the dotted line on the graph.

Solid curve represents the function,

y = [tex]-\sqrt[3]{x}[/tex]

Therefore, Domain of this function will be (-∞, ∞) Or x ∈ set of all real numbers.

And Range of the function will be (-∞, ∞) Or y ∈ set of all real numbers

Answer: the distance from home to father's ofgice is 2km and 950 m.

hope its what you are searching for..

Step-by-step explanation:

here,

31 cup of milk require 41 cup of water.

1 cup of milk require 41/31 cup of water.

so, 41/31 cup of water is required for 1 cup of milk.

hope u get it..

Answer:

Option (3)

Step-by-step explanation:

Given question is incomplete; here is the complete question.

The function f(x) = –x2 – 4x + 5 is shown on the graph. Which statement about the function is true?

The domain of the function is all real numbers less than or equal to −2.

The domain of the function is all real numbers less than or equal to 9.

The range of the function is all real numbers less than or equal to −2.

The range of the function is all real numbers less than or equal to 9

By using a graph tool we get a parabola opening downwards.

Since domain of a function is represented by x-values and range by y-values.

Domain of the given function will be (-∞, ∞)

Range of the function will be (-∞, 9] Or a set of all real numbers less thn equal to 9.

Therefore, Option (3) will be the answer.

Answer:

  a = 324

Step-by-step explanation:

The last entry in the table can be multiplied by 3:

  3(27/2, 108) = (81/2, 324)

Apparently, ...

  a = 324

Answer:

(190-5a)°

Step-by-step explanation:

Sum of internal angles of a triangle equals to 180°

If the third angle is x, then we have:

The third angle is: (190-5a)°

Answer:

A 90% confidence interval for the mean weight is [21.78 ounces, 21.98 ounces].

Step-by-step explanation:

We are given the weights, in the ounces, of a sample of 12 boxes below;

Weights (X): 21.88, 21.76, 22.14, 21.63, 21.81, 22.12, 21.97, 21.57, 21.75, 21.96, 22.20, 21.80.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

                         P.Q.  =  [tex]\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }[/tex]  ~ [tex]t_n_-_1[/tex]

where, [tex]\bar X[/tex] = sample mean weight = [tex]\frac{\sum X}{n}[/tex] = 21.88 ounces

            s = sample standard deviation = [tex]\sqrt{\frac{\sum (X-\bar X)^{2} }{n-1} }[/tex]  = 0.201 ounces

            n = sample of boxes = 12

            [tex]\mu[/tex] = population mean weight

Here for constructing a 90% confidence interval we have used a One-sample t-test statistics because we don't know about population standard deviation.

So, 90% confidence interval for the population mean, [tex]\mu[/tex] is ;

P(-1.796 < [tex]t_1_1[/tex] < 1.796) = 0.90  {As the critical value of t at 11 degrees of

                                                  freedom are -1.796 & 1.796 with P = 5%}  

P(-1.796 < [tex]\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }[/tex] < 1.796) = 0.90

P( [tex]-1.796 \times {\frac{s}{\sqrt{n} } }[/tex] < [tex]{\bar X-\mu}[/tex] < [tex]1.796 \times {\frac{s}{\sqrt{n} } }[/tex] ) = 0.90

P( [tex]\bar X-1.796 \times {\frac{s}{\sqrt{n} } }[/tex] < [tex]\mu[/tex] < [tex]\bar X+1.796 \times {\frac{s}{\sqrt{n} } }[/tex] ) = 0.90

90% confidence interval for [tex]\mu[/tex] = [ [tex]\bar X-1.796 \times {\frac{s}{\sqrt{n} } }[/tex] , [tex]\bar X+1.796 \times {\frac{s}{\sqrt{n} } }[/tex] ]

                                        = [ [tex]21.88-1.796 \times {\frac{0.201}{\sqrt{12} } }[/tex] , [tex]21.88+1.796 \times {\frac{0.201}{\sqrt{12} } }[/tex] ]

                                        = [21.78, 21.98]

Therefore, a 90% confidence interval for the mean weight is [21.78 ounces, 21.98 ounces].

Answer:

1/7

Step-by-step explanation:

There are 7 cards, 1 of which is less than 2. Therefore, P (less then 2) = 1/7

Answer:

1/7

Step-by-step explanation:

The number from the list that is less than 2 is 1.

1 number out of a total of 7 numbers.

= 1/7

Answer:

Do you have an image because I'm a bit confused with you just asking the measure of PSQ.

Step-by-step explanation:

Answers:

A ' = (-2, -3)

B ' = (0, -3)

C ' = (-1, 1)

=======================================================

Explanation:

To apply an x axis reflection, we simply change the sign of the y coordinate from positive to negative, or vice versa. The x coordinate stays as is.

Algebraically, the reflection rule used can be written as [tex](x,y) \to (x,-y)[/tex]

Applying this rule to the three given points will mean....

The diagram is provided below.

Side note: Any points on the x axis will stay where they are. That isn't the case here, but its for any future problem where it may come up. This only applies to x axis reflections.

Answer:

(-2,-3)...(0,-3)...(-1,1)

Step-by-step explanation:

Answer:

What I would conclude when a random sample of 23 time intervals between eruptions has a larger mean longer than 108 minutes is that there must be an error that occurred somewhere while computing the result.

Step-by-step explanation:

Technically error can be explained as the estimated difference between the real value or calculated value and an observed value of a certain quantity.

basically we have three types of error which are;

1. systematic errors.

2.random errors.

3.Bluders.

Answer:

D 7

Step-by-step explanation:

Total no. of bulb= 5

no. of defected bulb= 3

no. of not defected bulb=2

Total no. of bulb combination = 5C2

=5!/2!(5-2)!

= 5!/2!3!

= 5×4×3×2×1/2×1×3×2×1

=120/12

=10

( since a room can be lighted with one bulb also)

total no. of bulb combination when room shall not light = 3C2

3!/2!(3-2)!

= 3!/2! 1!

= 3×2×1/2×1×1

= 6/2

=3

Now,

Total no. of trial when room shall light

=10-3

=7

Hence, number of trial when the room shall be lighted is 7 which is option d

Answer:

if you would travel 50km/h then the time will be 2.4hours

Step-by-step explanation:

speed=v1=60km/h

time=t1=2h

speed=v2=50km/h

time=t2=?

as we know that

v1×t1=v2×t2

evaluating the expression

(v1×t1)/v2=t2

putting values

[tex]\frac{60km/h*2h}{50km/h}=t2[/tex]

[tex]\frac{120km/h^2}{50km/h}=t2[/tex]

2.4hours=t2

i hope this will help you :)

Answer:

xy-19x+3y-57

Step-by-step explanation:

Once again, FOIL is the way to go!

First, Outside, Inside, Last

xy-19x+3y-57

Answer:

xy-19x+3y-57

Step-by-step explanation:

(x+3)(y-19)

FOIL

first: xy

outer: -19x

inner 3y

last  -57

Add them together

xy-19x+3y-57

Answer:

Answer: $2,000

Step-by-step explanation:

-Use form 2441 on the IRS website for 2019.

-Wages earned=$45,000, therefore, it would be between "over 43,000 but not over 'No Limit' " which is 20% (.20)

-$10,000(paid in daycare) × .20 = $2,000

Answer:

area = 36 ft²

Step-by-step explanation:

no figure has been given ..

therefore,  area of a triangle = 1/2 * b * h

assume b = 6 ft

assume h = 12 ft

area = 1/2 * 6 * 12

area = 36 ft²

Answer:

a) P(A∩B) = 0.29

b) P1 = 0.1

c) P = 0.35

Step-by-step explanation:

Let's call A the event that the motorist stop at the first signal, and B the event that the motorist stop at the second signal.

From the question we know:

P(A) = 0.39

P(B) = 0.54

P(A∪B) = 0.64

Where P(A∪B) is the probability that he stop in the first, the second or both signals. Additionally, P(A∪B) can be calculated as:

P(A∪B)  = P(A) + P(B) - P(A∩B)

Where P(A∩B) is the probability that he stops at both signals.

So, replacing the values and solving for P(A∩B), we get:

0.64 = 0.39 + 0.54 - P(A∩B)

P(A∩B) = 0.29

Then, the probability P1 that he just stop at the first signal can be calculated as:

P1 = P(A) - P(A∩B) = 0.39 - 0.29 = 0.1

At the same way, the probability P2 that he just stop at the second signal can be calculated as:

P2 = P(B) - P(A∩B) = 0.54 - 0.29 = 0.25

Finally, the probability P that he stops at exactly one signal is:

P = P1 + P2 = 0.1 + 0.25 = 0.35

Answer:

The 95% confidence interval for the proportion of all shoppers during the year whose visit was because of a coupon they'd received in the mail is (0.2016, 0.2694)

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of [tex]\pi[/tex], and a confidence level of [tex]1-\alpha[/tex], we have the following confidence interval of proportions.

[tex]\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

In which

z is the zscore that has a pvalue of [tex]1 - \frac{\alpha}{2}[/tex].

For this problem, we have that:

[tex]n = 603, \pi = \frac{142}{603} = 0.2355[/tex]

95% confidence level

So [tex]\alpha = 0.05[/tex], z is the value of Z that has a pvalue of [tex]1 - \frac{0.05}{2} = 0.975[/tex], so [tex]Z = 1.96[/tex].

The lower limit of this interval is:

[tex]\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2355 - 1.96\sqrt{\frac{0.2355*0.7645}{603}} = 0.2016[/tex]

The upper limit of this interval is:

[tex]\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2355 + 1.96\sqrt{\frac{0.2355*0.7645}{603}} = 0.2694[/tex]

The 95% confidence interval for the proportion of all shoppers during the year whose visit was because of a coupon they'd received in the mail is (0.2016, 0.2694)

Answer:

a) 16xy³

Step-by-step explanation:

For a binomial expansion (a + b)ⁿ, the r+1 term is:

nCr aⁿ⁻ʳ bʳ

Here, a = 4x, b = y, and n = 4.

For the fourth term, r = 3.

₄C₃ (4x)⁴⁻³ (y)³

4 (4x) (y)³

16xy³

Answer:

Step-by-step explanation:

Given the Total revenue R(x) = 2x

Cost C(x) = 0.01x²+0.3x+30 where;

x = 30 and dx/dt = 9units per day.

Rate of change of revenue dR/dt = dR/dx • dx/dt

dR/dt = 2dx/dt

dR/dt = 2(9) = $18

Rate of change of revenue with respect to time is 18dollars/day.

Rate of change of cost dC/dt = dC/dx • dx/dt

dC/dt = (0.02x+0.3)dx/dt

dC/dt at x = 30 and dx/dt = 9 will give;

dC/dt = {0.02(30)+0.3}×9

dC/dt = (0.6+0.3) × 9

dC/dt = 0.9×9

dC/dt = $8.1

Rate of change of cost with respect to time is 8.1dollars/day

Profit = Revenue - Cost

Profit = 18-8.1

Daily Profit = $9.9

Answer: P(t) = 1.25.sin([tex]\frac{\pi}{3}[/tex].t) + 5.65

Step-by-step explanation: A motion repeating itself in a fixed time period is a periodic motion and can be modeled by the functions:

y = A.sin(B.t - C) + D or y = Acos(B.t - C) + D

where:

A is amplitude A=|A|

B is related to the period by: T = [tex]\frac{2.\pi}{B}[/tex]

C is the phase shift or horizontal shift: [tex]\frac{C}{B}[/tex]

D is the vertical shift

In this question, the motion of Pluto is modeled by a sine function and doesn't have phase shift, C = 0.

Amplitude:

a = [tex]\frac{largest - smallest}{2}[/tex]

At t=0, Pluto is the farthest from the sun, a distance 6.9 billions km away. At t=66, it is closest to the star, P(66) = 4.4 billions km. Then:

a = [tex]\frac{6.9-4.4}{2}[/tex]

a = 1.25

b

A time period for Pluto is T=66 years:

66 = [tex]\frac{2.\pi}{b}[/tex]

b = [tex]\frac{\pi}{33}[/tex]

Vertical Shift

It can be calculated as:

d = [tex]\frac{largest+smallest}{2}[/tex]

d = [tex]\frac{6.9+4.4}{2}[/tex]

d = 5.65

Knowing a, b and d, substitute in the equivalent positions and find P(t).

P(t) = a.sin(b.t) + d

P(t) = 1.25.sin([tex]\frac{\pi}{3}[/tex].t) + 5.65

The Pluto's distance from the sun as a function of time is

P(t) = 1.25.sin([tex]\frac{\pi}{3}[/tex].t) + 5.65

Answer:

P(t) = 1.25.sin(.t) + 5.65

Step-by-step explanation:

Step-by-step explanation:

yeah,when 15-7=8

the number is 8