Physics College

A pair of slits, separated by 0.150 mm, are illuminated by light with a wavelength of 643 nm. An interference pattern is observed on a screen at 140 cm from the slits. Consider a point seen on the screen that is located 1.80 cm to the right of the central bright fringe. Will the point be a minimum (destructive) point, a maximum (constructive) point or somewhere in between

Answers

Answer 1

Answer:

Explanation:

slit separation d = .15 mm

screen distance D = 1.4 m

wavelength of light used λ= 643 x 10⁻⁹ m

position of n th bright fringe x

x = n x λ D / d

1.8 x 10⁻² = n x 643 x 10⁻⁹ x 1.4 / .15 x 10⁻³

1.8 x 10⁻² = n x 6 x 10⁻³

n = 3

So 3 rd bright fringe will be formed at a point 1.8 cm from the central bright fringe .

Related Questions

if the reading of a mercury barometer is 75.58cm at the base of a mountain and 66.37cm at the summit,what is the height of the mountain? (density of mercury= 13600kg/m³, average density of air=1.25kg/m³

Answers

Answer:

Explanation:

What are the benefits of 3D design and 3D printing software?

The height of the mountain is 1002.048 m.

What is pressure?

The perpendicular force per unit area, or the stress at a point within a confined fluid, is referred to as pressure in the physical sciences.

Atmospheric pressure is the force of the atmosphere pressing down on each square meter of Earth's surface. Pascals are used to express pressure in SI units; one pascal is equivalent to one newton per square meter.

Given parameters:

at the base of a mountain, the reading of a mercury barometer is = 75.58cm = 0.7558 m.

at the summit of a mountain, the reading of a mercury barometer is = 66.37cm = 0.6637 m.

Let the height of the mountain = h.

Then,

h × density of air × g = ( 0.7558 - 0.6637) m × density of mercury × g

⇒ h × 1.25kg/m³ = 0.0921 m × 13600kg/m³

⇒ h = 1002.048 m.

Hence, the height of the mountain is 1002.048 m.

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The diagram shows two
charged objects, X and Y.
Based on the field lines, what are the charges of the
objects?
X: positive
Y: negative
O X: negative
Y: positive
O x: negative
Y: negative
O x: positive
Y: positive

Answers

Answer:

X: positive

Y: positive

Explanation:

The electrical field lines have a specified direction based upon the sign of the charge. The electrical field lines have a direction coming out of the charge if the sign of the charge is positive. While the electrical field lines have a direction going inside the charge if the sign of the charge of negative.

It can be clearly seen in the diagram that the electric field lines are coming out of both charges. Therefore, both the charges are positive.

Hence, the correct option is:

X: positive

Y: positive

A 9-V battery is hooked up to a 330-Ω resistor. What current is flowing through this circuit?
Group of answer choices

0.027 A

2970 A

36.6 A

6 A

Answers

Answer:

option a 0.027 A

Explanation:

I = V/R

-> 9/330 = 0.027

The maximum allowable resistance for an underwater cable is one hundredth of an ohm per
meter and the resistivity of copper is 1.54 x 10-80m.
a) Calculate the smallest cross sectional area of copper cable that could be used.

Answers

Answer:

A = 1.54 x 10⁻⁵ m² = 15.4 mm²

Explanation:

The resistance of a wire can be given by the following formula:

[tex]R = \frac{\rho L}{A}\\\\A = \frac{\rho L}{R} = \frac{\rho}{\frac{R}{L} }[/tex]

where,

A = smallest cross-sectional area = ?

ρ = resistivity of copper = 1.54 x 10⁻⁸ Ωm

[tex]\frac{R}{L}[/tex] = resistance per unit length of wire = 0.001 Ω/m

Therefore,

[tex]A = \frac{1.54\ x\ 10^{-8}\ \Omega m}{0.001\ \Omega/m}[/tex]

A = 1.54 x 10⁻⁵ m² = 15.4 mm²

A heat engine operating between a pair of hot and cold reservoirs with respective temperatures of 500 K and 200 K will have what maximum efficiency?
A) 60%
B) 50%
C) 40%
D) 30%

Answers

Answer:

The maximum efficiency of the heat engine is 60%.

Explanation:

Given that,

The temperature of hot reservoir = 500 K

The temperature of cold reservoir = 200 K

We need to find the maximum efficiency. The formula for the efficiency of heat engine is given by :

[tex]\eta=1-\dfrac{T_c}{T_H}[/tex]

Put all the values,

[tex]\eta=1-\dfrac{200}{500}\\\\\eta=0.6[/tex]

[tex]\eta=60\%[/tex]

So, the maximum efficiency of the heat engine is 60%.

PLEASE HELP I need help bad
66. Which of the following results of correlational
studies implies that environment contributes to
the determination of IQ?
(A) Correlations are higher for identical twins
than for fraternal twins.
(B) Correlations are higher for children and their
biological parents than for children and their
adoptive parents.
(C) Correlations are higher for parents and their
children than for husbands and wives.
(D) Correlations for two children in the same
family are lower when one of the children is
adopted than when both are the biological
offspring of the parents.
(E) Correlations for children and their adoptive
parents are statistically significant and
positive.

Answers

i think the answer is B.

i believe this because the child’s brain development is proven to have changed based off separation from their biological parents, presenting a change in their environment

i hope this helps ! ♡

Correlational study involves a non-experimental study of the relationship between two variables using statistical study in the evaluation of our result.

The association between environment and IQ in the options given is best identified by the statistical significance shown in the association between children and their adoptive parent.

Correlational study involves the establishment of statistical pattern or trend using methods such as Analysis of variance. Statistical evaluation is key in establishing the outcome of a correlational study or evaluation. Since the method by which the correlation between the variables in the other options aren't stated, the best option is E.

Therefore, correlation between adoptive parent and children showing positive statistical significance implies a correlational study.

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A torsional pendulum has a centroidal mass moment of inertia of 0.40 kg·m2 and when given an initial twist and released is found to have a frequency of oscillation of 200 rpm. Knowing that when this pendulum is immersed in oil and given the same initial condition it is found to have a frequency of oscillation of 180 rpm, determine the damping constant for the oil. The damping constant for the oil is

Answers

0.00246914 come to the damping of the constant for the oil

Knowing that when this pendulum is immersed in oil and given the same initial condition it is found to have a frequency of oscillation of 180 rpm,0.00246914 come to the damping of the constant for the oil

what is frequency ?

The frequency can be defined as the number of oscillation per unit time which is used for defining the cyclic process like rotation, oscillation, wave etc.

The SI unit of the frequency is denoted as Hertz and the symbol λ represents it where one hertz means the wave completed one cycle in one second.

The frequency which explains the phenomenon of oscillatory and vibration like the mechanical vibration, sound signals, light, frequency waves etc. The “period” represented as the time required by the wave for one oscillation, i.e., it is inversely proportional to the frequency.

If the flashes, then the period is the time between the two flashes. And the frequency is the total number of flashes per second.

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Sodium and ice a physical or chemical reaction

Answers

Answer:

physical change uwu owo hope this helps you uwu silly goose

It’s physical reaction

A house is advertised as having 1460 square feet under roof. What is the area of this house in square meters?

Answers

Answer: 131.92 m

Explanation: The problem give above is a conversion problem. To convert any measurement from one unit to another, we need a relation for the original units to that of the desired unit. This relation is called the conversion factor. It is used by multiplying or dividing the factor depending on what is the unit of the original measurement. For this case, we need to convert from ft^2 to m^2. The conversion factor would be 1 foot is equal to 0.3048 m. So, we would be getting the square of the factor and then multiply to the original value.

1420 ft^2 ( 0.3048 m / 1 ft)^2 = 131.92 m

What would happen if I removed the battery from the circuit?

Answers

Answer:

The current would stop

Explanation:

Electric currents are interesting because they carry little to no momentum. As soon as you remove a power source, the whole current halts.

In A. C. motor capacitor is used
p.Can dicouly [BPKIHS 2000
to reduce ripples b. to decrease A. C.
c. to increase A. C. d. to decrease D. C.
a.
34

Answers

Answer:

d. to decrease D. C.

Explanation:

d. to decrease D. C.

Starting from rest, a car takes 2.4 s to travel the first 15 m. Assuming a constant acceleration, how long will it take the car to travel the next 15 m?

Answers

Answer:

The time it will take the car to travel the next 15 m is 1 s.

Explanation:

Given;

initial velocity of the car, u = 0

time of motion, t = 2.4 s

initial distance traveled, d = 15 m

determine the constant acceleration of the car;

d = ut + ¹/₂at²

15 = 0 + (0.5 x 2.4²)a

15 = 2.88a

a = 15 / 2.88

a = 5.21 m/s²

The velocity of the car at the end of the first 15 m

v - u + at

v = 0 + 5.21 x 2.4

v = 12.5 m/s

The time to cover the next 15 m;

d₂ = vt + ¹/₂at²

15 = 12.5t + (0.5 x 5.21)t²

15 = 12.5t + 2.61t²

0 = 2.61t² + 12.5t - 15

Use the formula method to solve the above quadratic equation.

a = 2.61

b = 12.5

c = -15

[tex]t = \frac{-b \ \ +/- \ \ \sqrt{b^2 - 4ac} }{2a} \\\\t = \frac{-12.5 \ \ +/- \ \ \sqrt{12.5^2 - (4\times 2.61 \times -15)} }{2\times 2.61}\\\\t = 0.9937 \ s \ \ \ or \ \ \ -5.78 \ s\\\\time \ can \ only \ be \ positive;\\\\t \approx \ 1\ s[/tex]

Therefore, the time it will take the car to travel the next 15 m is 1 s.

please help meeeee :((((((((((

Answers

Answer:

hello me

Explanation:

help me thisanswer

1 pts
Harry spent his summer playing guitar on the corner trying to earn some extra money. He would keep his guitar
case open for people to drop extra change into. Sometimes people would put money in the case and sometimes
people would be rude. Putting money in the hat is a to Harry's behavior.
Tir
Atte
1M
Negative reinforcement
Positive reinforcement
O Negative punishment
Positive punishment
Question 2
1 pts
O
SIC
acer

Answers

Answer:

Positive reinforcement

Will award brainliest and upvote if you can help answer!

Answers

Answer:

Omqnp

Explanation:

I have done this before and got it correct

A truck contains both hydraulic brakes (reliability 0.96) and mechanical brakes (reliability 0.99). What is the probability of stopping the truck (i) while moving at a high speed, assuming both systems must work to avoid hitting a vehicle stalled in the roadway, and (ii) while moving at a low speed, assuming either system will stop the truck in time if they function properly

Answers

Answer:

i) 0.9504

ii) 0.0452

Explanation:

Given data: reliability of hydraulic brakes= 0.96

reliability of mechanical brakes = 0.99

So the probability of stopping the truck = 0.96×0.99= 0.9504

At low speed

case: A works and B does not

= 0.96×(1-0.99) = 0.0096

case2 : B works and A does not

= 0.99×(1-0.96) = 0.0396

Therefore, probality of stopping = 0.0096+0.0396 = 0.0492

Photons with the highest frequency have the lowest _____.
A. wavelength
B. speed
C. color
D. energy

Answers

Answer:

a wavelength

Explanation:

Kendra wonders how she ended up with brown hair, hazel eyes, and is right handed. Using the terms amino acids, genes, proteins, and traits, explain how she ended up with these features.

Answers

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We know the mass and luminosity of the star. We also know the mass of the spacecraft and the area of its stellar sail. We must find the net force exerted on the spacecraft, as well as the direction of its acceleration. We are asked to find both the net force exerted on the spacecraft and the direction of the acceleration. Which principle is best used to find the direction of the acceleration once the net force has been found

Answers

Answer:

Newton's principle of force, the variation of the momentum and the acceleration have the same direction

Explanation:

To find the force exerted by the star on the sail of the ship, the expression of the momentum of the radiation is used, which in the case of a total reflection

p = [tex]\frac{2U}{c}[/tex]

where p is the momentum and U the incident energy and c the speed of light.

The strength I could get from

F = [tex]\frac{dp}{dt}[/tex]

the direction of the acceleration is the direction of the momentum, therefore the principle to find the acceleration of is Newton's principle of force, the variation of the momentum and the acceleration have the same direction.

When oxygen in water interacts with iron it results in O A rust forming O B) a chemical change C) oxidation O D) all of the above

Answers

correct answer is D, all of the above. Rust forming is a chemical change which is classified as oxidation

A car comes to a stop six seconds after the driver applies the brakes. While the brakes are on, the following velocities are recorded:
Time since brakes applied (sec) 0 2 4 6
Velocity (ft/s) 87 44 16 0
Give lower and upper estimates (using all of the available data) for the distance the car traveled after the brakes were applied.

Answers

Answer:

Explanation:

deceleration during first 2 s = (87 - 44) / 2 =21.5 m /s²

deceleration during next 2 s = (44 - 16) / 2 =14 m /s²

deceleration during last 2 s = (16 - 0) / 2 = 8 m /s²

If we assume the acceleration to be uniform during 3 readings

distance travelled during first 2 s

v² - u² = 2 a s

87² - 44² = 2 x 21.5 x s

s = 7569 - 1936 / 43

= 176 m

distance travelled during next 2 s

44² - 16² = 2 x 14 x s

s = 1936 - 256 / 28

= 60 m

distance travelled during last 2 s

16² - 0² = 2 x 8 x s

s = 256 / 16

= 16 m

Total distance travelled = 176 + 60 + 16 = 252 m

If we assume the acceleration as non- uniform , we first calculate average acceleration as follows .

average acceleration = (87 - 0)/ 6 = 14.5 m /s²

v² - u² = 2 a s

87² - 0² = 2 x 14.5 x s

s = 7569 / 29

= 261 m

Hence lower estimate of distance travelled = 252 m ; upper estimate of distance travelled = 261 m .

a car travels a distance of 1600km in 24hr .what was it's speed

Answers

Answer:

66.66 or 66.67

Explanation:

Two identical thermally insulated spherical tanks, A and B, are connected by a valve. Initially tank A contains 20mol of an ideal diatomic gas, tank B is evacuated, and the valve is closed.
If the valve is opened and the gas expands isothermally fromA to B, what is the change in the entropy of the gas?

Answers

Answer:

Explanation:

Volume of gas is doubled isothermally . Let the temperature of the gas be T .Work done by the gas

W = 2.303 nRT log 2 V / V

Since expansion is isothermal , Δ E = 0

Q = ΔE + W

Q = W

Q = 2.303 nRT log 2 V / V

Q / T = 2.303 n R log 2

Change in entropy = ΔS = Q / T = 2.303 n R log 2

= 2.303 x 20 x 8.3 x .3010 J T⁻¹.

= 115 J T⁻¹.

The required change in the entropy of the gas is 115 J/K.

Given data:

The number of moles of diatomic gas in tank A is, n = 20 mol.

The expansion takes place isothermally, which means the volume is doubled at the constant temperature. Therefore, work done during the isothermal expansion is,

W = 2.303 nRT log 2 V / V

Since expansion is isothermal , Δ E = 0. Then by using the first law of thermodynamics as,

Q = ΔE + W

Q = W

Q = 2.303 nRT log 2 V / V

Q / T = 2.303 n R log 2

Also, we that the expression for the change in Entropy is,

ΔS = Q / T = 2.303 n R log 2

Solving as,

ΔS = 2.303 x 20 x 8.3 x .3010

ΔS = 115 J/K

Thus, we can conclude that the required change in the entropy of the gas is 115 J/K.

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How much stronger is the electric force between two
protons than the gravitational force between them?

Answers

Answer:

Explanation:

The electric force between two protons is 10^36 times stronger than the gravitational force between them.

Answer:

Electric force is 1.23 x 10³⁶ times stronger than gravitational force.

Explanation:

First, we will calculate the gravitational force using Newton's Law:

[tex]F_G = \frac{Gm^2}{r^2}\\\\[/tex]

where,

F_G = Gravitational Force = ?

G = Gravitational Constant = 6.67 x 10⁻¹¹ Nm²/kg²

m = mass of proton = 1.67 x 10⁻²⁷ kg

r = distance between protons

Therefore,

[tex]F_G = \frac{(6.67\ x\ 10^{-11}\ Nm^2/kg^2)(1.67\ x\ 10^{-27}\ kg)^2}{r^2}\\\\F_G = \frac{1.86\ x\ 10^{-64}\ Nm^2}{r^2}\\\\[/tex]

Now, we will calculate the electrostatic force using Colomb's Law:

[tex]F_E = \frac{kq^2}{r^2}\\\\[/tex]

where,

F_E = Electrostatic Force = ?

k = Colomb's Constant = 9 x 10⁹ Nm²/C²

q = charge of proton = 1.6 x 10⁻¹⁹ C

r = distance between protons

Therefore,

[tex]F_E = \frac{(9\ x\ 10^{9}\ Nm^2/kg^2)(1.6\ x\ 10^{-19}\ C)^2}{r^2}\\\\F_E = \frac{2.3\ x\ 10^{-28}\ Nm^2}{r^2}\\\\[/tex]

Dividing both forces:

[tex]\frac{F_E}{F_G} = \frac{2.3\ x\ 10^{-28}}{1.86\ x\ 10^{-64}}[/tex]

F_E = 1.23 x 10³⁶ F_G

Therefore, electric force is 1.23 x 10³⁶ times stronger than gravitational force.

help PLEASEEEEEEEEEEE

Answers

The answer is a

Explanation : a

the answer for this one is A

describe los ejercicios que caliente las extremidades superiores del cuerpo

Answers

Answer:

todas las cosas que la cuerda de salto hará

Explanation:

1. Mueva suavemente las muñecas y prepárese para levantar la parte superior del cuerpo.

2.Activa tus hombros sin presionarlos.

3. Calienta todo tu cuerpo elevando tu frecuencia cardíaca y cebando para la coordinación de todo el cuerpo que necesitas para el entrenamiento de la parte superior del cuerpo.

The block A and attached rod have a combined mass of 50 kg and are confined to move along the guide under the action of the 796-N applied force. The uniform horizontal rod has a mass of 15 kg and is welded to the block at B. Friction in the guide is negligible.

Required:
Compute the bending moment M exerted by the weld on the rod at B. The bending moment is positive if counterclockwise, negative if clockwise.

Answers

Answer:

The bending moment is 459.16 N.m

Explanation:

From the given information;

Let's assume that the angle is 66°

Then, the free body diagram is draw and attached in the file below.

Now, the calculation of the acceleration from the first part of the free body diagram is:

[tex]\sum F_x = ma_x \\ \\ 796 - 50(9.81) sin 66=50a \\ \\ 796 - 448.094 = 50 a \\ \\ a = \dfrac{347.906}{50} \\ \\ a = 6.96 \ m/s^2[/tex]

Bending moment M:

From the second part of the diagram:

[tex]\sum M_B = mad \\ \\ M - (15 \times 9.81) (1.5) = (25 \times 6.96)(1.5 sin 66) \\ \\ M - 220.725 = 238.435 \\ \\ M = 238.435 + 220.725 \\ \\ \mathbf{M = 459.16 \ N.m}[/tex]

Four 15 Ω resistors are connected in series with a 45 V battery. What is the current in the circuit?

Answers

Answer:

Explanation:

Resistance=R=15

Voltage=45volts

we know that

[tex]\boxed{\sf Current=\dfrac{Voltage}{Resistance}}[/tex]

[tex]\\ \tt \mapsto \:Current=\dfrac{45}{15}[/tex]

[tex]\\ \tt \mapsto \:Current=\dfrac{3A}[/tex]

The current of the circuit is 0.75 amps

The first step is to write out the parameters

Four resistors of 15 in series

15+15+15+15

= 60

voltage= 45

Current= 45/60

= 0.75

Hence the current is 0.75 amps

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The chart shows the masses of selected particles.
Particle
Mass
2350
137 9 u
6
92
138
Ba
K:
on
94.9u
1.0 u
In the equation u + Ön – 133Ba + K+ + 36n+E , the energy E is equivalent to a mass of

1.
0.2 u
2.
2.0 u
3.
2.2 u
4.
0.0 u

Answers

Answer: 0.2 u

Explanation:

The atomic mass of nuclide is written as a superscript. On the left (reactants) aide of the nuclear equation shown, the total atomic mass is 235.0 + 1.0 u = 236 u. On the right (products) side reaction, the total atomic mass is 137.9u + 94.9u + 3 x 1.0u = 235.8 u. Therefore, 0.2 mass units must have been converted into energy.

A 100-turn, 7.0-cm-diameter coil is made of 0.50-mm-diameter copper wire. A magnetic field is perpendicular to the coil. At what rate must B increase to induce a 2.0 A current in the coil?

Answers

Answer:

The rate of increase of the magnetic field is 0.0311 T/s.

Explanation:

Given;

number of turns of the coil, N = 100 turn

diameter of the coil, D = 7.0 cm = 0.07 m

diameter of the copper wire, d = 0.5 mm = 0.5 x 10⁻³ m

induced current, I = 2.0 A

The induced emf is calculated as;

[tex]emf = IR = NA\frac{dB}{dt}\\\\\frac{dB}{dt} = \frac{IR}{NA} \\\\Where; A \ is \ area \ of \ the \ coil = \frac{\pi D^2}{4}\\\\[/tex]

[tex]\frac{dB}{dt}[/tex] is the rate of increase of the magnetic field, B

R is the resistance of the copper wire

[tex]R = \frac{\rho L}{A} = \frac{\rho D}{A}= \frac{\rho D}{\frac{\pi d^2}{4} }[/tex]

Where; ρ is the resistivity of copper wire = 1.68 x 10⁻⁸ Ωm

[tex]R = \frac{(1.68 \times 10^{-8})(0.07)}{\frac{\pi (0.5\times 10^{-3})^2}{4} } \\\\R = 5.989 \times 10^{-3} \ ohms[/tex]

[tex]\frac{dB}{dt} = \frac{(2)(5.989 \times 10^{-3})}{(100)(\frac{\pi \times (0.07)^2}{4} )} \\\\\frac{dB}{dt} =0.0311 \ T/s[/tex]

Therefore, the rate of increase of the magnetic field is 0.0311 T/s.

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