A normally distributed population of package weights has a mean of 63.5 g and a standard deviation of 12.2 g. XN(63.5,12.2) a. What percentage of this population weighs 66 g or more

Answer:

The period is of [tex]\frac{\pi}{3}[/tex] units.

The horizontal shift is of 30 units to the left.

Step-by-step explanation:

The secant function has the following general format:

[tex]y = A\sec{(Bx + C)}[/tex]

A represents the vertical shift.

C represents the horizontal shift. If C is positive, the shift is to the right. If it is negative, it is to the left.

The period is [tex]P = \frac{2\pi}{B}[/tex]

In this question:

[tex]y = 7\sec{6x - 30}[/tex]

So [tex]B = 6, C = -30[/tex]

Then [tex]P = \frac{2\pi}{6} = \frac{\pi}{3}[/tex]

The period is of [tex]\frac{\pi}{3}[/tex] units.

The horizontal shift is of 30 units to the left.

Answer:

Correct option: C.

Step-by-step explanation:

(Assuming the correct function is R(x) = 2x^2 + 3x + 5)

To find the input value that gives the value of R(x) = 19, we just need to use this output value (R(x) = 19) in the equation and then find the value of x:

[tex]R(x) = 2x^2 + 3x + 5[/tex]

[tex]19 = 2x^2 + 3x + 5[/tex]

[tex]2x^2 + 3x -14 = 0[/tex]

Solving this quadratic function using the Bhaskara's formula (a = 2, b = 3 and c = -14), we have:

[tex]\Delta = b^2 - 4ac = 9 + 112 = 121[/tex]

[tex]x_1 = (-b + \sqrt{\Delta})/2a = (-3 + 11)/4 = 2[/tex]

[tex]x_2 = (-b - \sqrt{\Delta})/2a = (-3 - 11)/4 = -3.5[/tex]

So looking at the options, the input to the function is x = 2

Correct option: C.

Answer:

3.15 dollars

Step-by-step explanation:

The sales tax rate is 7% = 0.07

So, we need to multiply the listed price and the sales tax rate.

= 45 * 0.07 = 3.150 (3.15)

Hope this helps and please mark as the brainliest

The mass of the lamina is 6 units.

The center of mass of the lamina is (X,Y) = (-3/2, 9/2).

Here,

To find the mass and center of mass of the lamina, we need to integrate the density function ρ(x, y) over the triangular region D.

The mass (M) of the lamina is given by the double integral of the density function over the region D:

M = ∬_D ρ(x, y) dA

where dA represents the differential area element.

The center of mass (X,Y) of the lamina can be calculated using the following formulas:

X = (1/M) ∬_D xρ(x, y) dA

Y = (1/M) ∬_D yρ(x, y) dA

Now, let's proceed with the calculations:

The triangular region D has vertices (0, 0), (2, 1), and (0, 3). We can define the limits of integration for x and y as follows:

0 ≤ x ≤ 2

0 ≤ y ≤ 3 - (3/2)x

Now, let's calculate the mass (M):

M = ∬_D ρ(x, y) dA

M = ∬_D 2(x + y) dA

We need to set up the double integral over the region D:

M = ∫[0 to 2] ∫[0 to 3 - (3/2)x] 2(x + y) dy dx

Now, integrate with respect to y first:

M = ∫[0 to 2] [x(y²/2 + y)] | [0 to 3 - (3/2)x] dx

M = ∫[0 to 2] [x((3 - (3/2)x)²/2 + (3 - (3/2)x))] dx

M = ∫[0 to 2] [(3x - (3/2)x²)²/2 + (3x - (3/2)x²)] dx

Now, integrate with respect to x:

[tex]M = [(x^3 - (1/2)x^4)^2/6 + (3/2)x^2 - (1/4)x^3)] | [0 to 2]\\M = [(2^3 - (1/2)(2^4))^2/6 + (3/2)(2^2) - (1/4)(2^3)] - [(0^3 - (1/2)(0^4))^2/6 + (3/2)(0^2) - (1/4)(0^3)]\\M = [(8 - 8)^2/6 + 6 - 0] - [0]\\M = 6[/tex]

So, the mass of the lamina is 6 units.

Next, let's calculate the center of mass (X,Y):

X = (1/M) ∬_D xρ(x, y) dA

X = (1/6) ∬_D x * 2(x + y) dA

We need to set up the double integral over the region D:

X = (1/6) ∫[0 to 2] ∫[0 to 3 - (3/2)x] x * 2(x + y) dy dx

Now, integrate with respect to y first:

X = (1/6) ∫[0 to 2] [x(y² + 2xy)] | [0 to 3 - (3/2)x] dx

X = (1/6) ∫[0 to 2] [x((3 - (3/2)x)² + 2x(3 - (3/2)x))] dx

X = (1/6) ∫[0 to 2] [x(9 - 9x + (9/4)x² + 6x - (3/2)x²)] dx

X = (1/6) ∫[0 to 2] [(9/4)x³ - (3/2)x⁴ + 15x - (3/2)x³] dx

Now, integrate with respect to x:

[tex]X = [(9/16)x^4 - (3/8)x^5 + (15/2)x^2 - (3/8)x^4] | [0 to 2]\\X = [(9/16)(2)^4 - (3/8)(2)^5 + (15/2)(2)^2 - (3/8)(2)^4] - [(9/16)(0)^4 - (3/8)(0)^5 + (15/2)(0)^2 - (3/8)(0)^4]\\X = [9/2 - 12 + 15 - 0] - [0]\\X = 15/2 - 12\\X = -3/2[/tex]

Next, let's calculate Y:

Y = (1/M) ∬_D yρ(x, y) dA

Y = (1/6) ∬_D y * 2(x + y) dA

We need to set up the double integral over the region D:

Y = (1/6) ∫[0 to 2] ∫[0 to 3 - (3/2)x] y * 2(x + y) dy dx

Now, integrate with respect to y first:

Y = (1/6) ∫[0 to 2] [(xy² + 2y²)] | [0 to 3 - (3/2)x] dx

Y = (1/6) ∫[0 to 2] [x((3 - (3/2)x)²) + 2((3 - (3/2)x)²)] dx

Y= (1/6) ∫[0 to 2] [x(9 - 9x + (9/4)x²) + 2(9 - 9x + (9/4)x²)] dx

Y = (1/6) ∫[0 to 2] [(9x - 9x² + (9/4)x³) + (18 - 18x + (9/2)x²)] dx

Now, integrate with respect to x:

[tex]Y= [(9/2)x^2 - 3x^3 + (9/16)x^4) + (18x - 9x^2 + (9/6)x^3)] | [0 to 2]\\Y = [(9/2)(2)^2 - 3(2)^3 + (9/16)(2)^4) + (18(2) - 9(2)^2 + (9/6)(2)^3)] - [(9/2)(0)^2 - 3(0)^3 + (9/16)(0)^4) + (18(0) - 9(0)^2 + (9/6)(0)^3)]\\Y = [18 - 24 + 9/2 + 36 - 36 + 12] - [0]\\Y= 9/2[/tex]

So, the center of mass of the lamina is (X,Y) = (-3/2, 9/2).

Learn more about mass here

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Answer:

(4b)•(0.5a) = (4•0.5)(a)(b) = 2ab

Step-by-step explanation:

Answer:

y = [tex]\frac{1}{2}[/tex] x + 3

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = [tex]\frac{1}{2}[/tex] x + 7 ← is in slope- intercept form

with slope m = [tex]\frac{1}{2}[/tex]

Parallel lines have equal slopes

line M crosses the y- axis at (0, 3) ⇒ c = 3

y = [tex]\frac{1}{2}[/tex] x + 3 ← equation of line M

Answer:

E = { x l x is a perfect square <36}

And we can rewrite it taking in count the list of all the perfect squares less than 36 and we have:

1= 1*1

4= 2*2

9 = 3*3

16 =4*4

25= 5*5

And we can rewrite the set on this way:

E= {1,4,9,16,25}

Step-by-step explanation:

For this problem we have the following set:

E = { x l x is a perfect square <36}

And we can rewrite it taking in count the list of all the perfect squares less than 36 and we have:

1= 1*1

4= 2*2

9 = 3*3

16 =4*4

25= 5*5

And we can rewrite the set on this way:

E= {1,4,9,16,25}

Answer:

Yes, it contradict this prior belief as there is enough evidence to support the claim that the true average escape time is significantly higher than 6 minutes.

Test statistic t=2.238>tc=1.708.

The null hypothesis is rejected.

Step-by-step explanation:

This is a hypothesis test for the population mean.

The claim is that the true average escape time is significantly higher than 6 minutes (360 seconds).

Then, the null and alternative hypothesis are:

[tex]H_0: \mu=360\\\\H_a:\mu> 360[/tex]

The significance level is 0.05.

The sample has a size n=26.

The sample mean is M=370.69.

As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=24.36.

The estimated standard error of the mean is computed using the formula:

[tex]s_M=\dfrac{s}{\sqrt{n}}=\dfrac{24.36}{\sqrt{26}}=4.777[/tex]

Then, we can calculate the t-statistic as:

[tex]t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{370.69-360}{4.777}=\dfrac{10.69}{4.777}=2.238[/tex]

The degrees of freedom for this sample size are:

[tex]df=n-1=26-1=25[/tex]

The critical value for a  right-tailed test with a significance level of 0.05 and 25 degrees of freedom is tc=1.708. If the test statistic is bigger than 1.708, it falls in the rejection region and the null hypothesis is rejected.

As the test statistic t=2.238 is bigger than the critical value t=1.708, the effect is significant.  The null hypothesis is rejected.

There is enough evidence to support the claim that the true average escape time is significantly higher than 6 minutes (360 seconds).

Answer:

the answer is A

Step-by-step explanation:

Answer:

between 108-110?

Step-by-step explanation:

60% or 200 = 120 people

90% of 120 = 108

question doesnt look complete so this is the best I could come up with...‍♀️

Answer: 484m²

Step-by-step explanation: This is a question on solid shape.

The surface area of a cone is the same thing as the perimeter of the cone ie, the materials required to construct the cone.

Formula for the surface area of the cone = πrl + πr², ( the circular base )

From.the diagram,

r = 7.1m , l = 14.6m, π = 3.142

Now substitute for those values in.the formula above

SA = πrl + πr²

= 3.142 × 7.1 × 14.6 + 3.142 × 7.1²

= 325.6997 + 158.388

= 484.09

Now to the nearest tenth meter,

SA = 484m²

Answer:

56% shaded

Step-by-step explanation:

if there are 100 boxes, then every box it 1%

5 rows (50%) + 6 extra boxes (6%) = 56%

Answer:

a. In the butter market, the monthly equilibrium quantity is 95 million pounds and the equilibrium price is $1.2 per pound.

b. The correct option is zero.

c. See the attached excel file for the new supply schedule.

d. The monthly surplus created by the price support program is 18 million pounds given the new supply of butter.

Step-by-step explanation:

Note: This question is not complete. A complete question is therefore provided in the attached Microsoft word file.

a. In the butter market, the monthly equilibrium quantity is million pounds and the equilibrium price is $ per pound.

At equilibrium, quantity demanded must be equal with the quantity supplied.

In this question, equilibrium occurs at the price of $1.20 per pound and quantity of 95 million pounds.

Therefore, in the butter market, the monthly equilibrium quantity is 95 million pounds and the equilibrium price is $1.2 per pound.

b. What is the monthly surplus created in the wholesale butter market due to the price support (price floor) program?

Price floor refers to a government price control on the lowest price that can be charged for a commodity.

It should be noted that for a price floor to be binding, it has to be fixed above the equilibrium price.

Since the price floor of $1 per pound is lower than the equilibrium price of $1.2 per pound, the price floor will therefore not be binding. As a result, the market will still be at the equilibrium point and the monthly surplus created in the wholesale butter market due to the price support (price floor) program will be zero.

Therefore, the correct option is zero.

c. Fill in the new supply schedule given the change in the cost of feeding cows.

Since a decrease in the cost of feeding cows shifts the supply schedule to the right by 40 million pounds at every price, this implies that there will be an increase in supply by 40 million at each price.

Note: Find attached the excel file for the new supply schedule.

d. Given the new supply of butter, what is the monthly surplus of butter created by the price support program?

Since the price floor has been fixed at $1 per pound by the price support program, we can observe that the quantity demanded is 101 million pounds and quantity supplied is 119 million pounds at this price floor of $1. The surplus created is then the difference between the quantity demanded and quantity supplied as follows:

Surplus created = Quantity supplied - Quantity demanded = 119 - 101 = 18 million pounds

Therefore, the monthly surplus created by the price support program is 18 million pounds given the new supply of butter.

Answer:

largets area is 32 feet cubed

Step-by-step explanation:

8=4  foot 2 for each  side w and e and 32feet n and s  16 each side

Answer:

Options (D), (E) and (F) are the correct options.

Step-by-step explanation:

From the figure attached,

1). Angle 4 is the exterior angle of the given triangle having interior angles 1, 2 and 3.

Therefore, by the property of exterior angle,

∠4 = ∠1 + ∠2

2). Since ∠4 = ∠1 + ∠2,

Therefore, ∠4 will be greater than ∠1

 Similarly, ∠4 will be greater than ∠2

Therefore, Options (D), (E) and (F) are the correct options.

Answer:

9π or 28.3 units²

Step-by-step explanation:

A = πr²

A = π(3)²

A = 9π

or

A= 28.3 units²

Hope this helps. :)

Answer: (d) 88/ 2π

Step-by-step explanation:

Perimeter = 88m

Perimeter of a circle = 2πr

88 = 2π x r

r = 88 / 2π

Answer:

88/2π​ = r

Step-by-step explanation:

The circumference is 88 m

The circumference is given by

C = 2*pi*r

88 = 2 * pi *r

Divide each side by 2 pi

88 / 2pi = 2 * pi *r / 2 * pi

88 / 2 pi = r

Answer:

E. The parameter is μmale - μfemale and the statistic is xmale - xfemale.

Step-by-step explanation:

The sample statistic is a piece of information about the individuals or objects that were selected from a given population. The sample is just a fraction of the total population. Since it is a herculean task studying an entire population, the sample forms a manageable size that allows us to have an insight into the entire population. The sample statistics are now the piece of information about the sample being studied such as the average, mean, median, or mode.  The sample statistics have to be as specific as possible of the factors being measured. In the question, we would have to obtain the mean of both the male and female genders. This gives us an insight into the population under study.

The parameter, on the other hand, is a description of the entire population being studied. For example, we might want to determine the population mean. That is the factor we seek to measure. It is represented by the sign mu (μ).  

Answer:

Step-by-step explanation:

First we must first find the LCM

The LCM of x² + 3x + 2 and (x + 2)(x + 1 ) is

x² + 3x + 2

So we have

[tex] \frac{x}{ {x}^{2} + 3x + 2 } - \frac{1}{(x + 2)(x + 1)} \\ \\ = \frac{x - 1}{ {x}^{2} + 3x + 2 } [/tex]

Hope this helps you

Answer:

The answer is OPTION D!

Step-by-step explanation:

HoPe ThIs HeLpS!

Answer:

[tex]\frac{d}{dy}(-3x^{2} -12) = -6x[/tex]

0 = -6x

0 = x

[tex]-3(0)^{2} -12 = -12[/tex]

(0,-12)

Step-by-step explanation:

Answer:

Step-by-step explanation:

Given the expression [tex]log_81000 = log_210[/tex], to prove this expression is true using the properties of logarithm, we will follow the following steps.

Starting from the Left Hand Side:

Answer:

1. Test statistic t=1.581.

2. The null hypothesis H0 failed to be rejected.

There is not enough evidence to support the claim that the mean number of calls per salesperson per week is significantly more than 41.

NOTE: if the null hypothesis is µ = 40, there is enough evidence to support the claim that the mean number of calls per salesperson per week is significantly more than 40 (test statistic t=3.161).

Step-by-step explanation:

This is a hypothesis test for the population mean.

The claim is that the mean number of calls per salesperson per week is significantly more than 41.

Then, the null and alternative hypothesis are:

[tex]H_0: \mu=41\\\\H_a:\mu> 41[/tex]

The significance level is 0.025.

The sample has a size n=38.

The sample mean is M=42.

As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=3.9.

The estimated standard error of the mean is computed using the formula:

[tex]s_M=\dfrac{s}{\sqrt{n}}=\dfrac{3.9}{\sqrt{38}}=0.633[/tex]

Then, we can calculate the t-statistic as:

[tex]t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{42-41}{0.633}=\dfrac{1}{0.633}=1.581[/tex]

The degrees of freedom for this sample size are:

[tex]df=n-1=38-1=37[/tex]

This test is a right-tailed test, with 37 degrees of freedom and t=1.581, so the P-value for this test is calculated as (using a t-table):

[tex]\text{P-value}=P(t>1.581)=0.061[/tex]

As the P-value (0.061) is bigger than the significance level (0.025), the effect is not significant.

The null hypothesis failed to be rejected.

There is not enough evidence to support the claim that the mean number of calls per salesperson per week is significantly more than 41.

For µ = 40:

This is a hypothesis test for the population mean.

The claim is that the mean number of calls per salesperson per week is significantly more than 40.

Then, the null and alternative hypothesis are:

[tex]H_0: \mu=40\\\\H_a:\mu> 40[/tex]

The significance level is 0.025.

The sample has a size n=38.

The sample mean is M=42.

As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=3.9.

The estimated standard error of the mean is computed using the formula:

[tex]s_M=\dfrac{s}{\sqrt{n}}=\dfrac{3.9}{\sqrt{38}}=0.633[/tex]

Then, we can calculate the t-statistic as:

[tex]t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{42-40}{0.633}=\dfrac{2}{0.633}=3.161[/tex]

The degrees of freedom for this sample size are:

[tex]df=n-1=38-1=37[/tex]

This test is a right-tailed test, with 37 degrees of freedom and t=3.161, so the P-value for this test is calculated as (using a t-table):

[tex]\text{P-value}=P(t>3.161)=0.002[/tex]

As the P-value (0.002) is smaller than the significance level (0.025), the effect is significant.

The null hypothesis is rejected.

There is enough evidence to support the claim that the mean number of calls per salesperson per week is significantly more than 40.  

Answer:

123454321

Step-by-step explanation:

it's a palendrome, made out of a number of numbers in the sqquence.

Answer:

about 10

Step-by-step explanation:

62.8 = 2 pi r/2

62.8/2 = pi r

31.4/pi = pi r/pi

about 10 = r

Answer:

Step-by-step explanation:

Hello friend

The answer is 5:15 in 12 hour clock

Answer:

5:15 PM

Step-by-step explanation:

12:00 + 5:00

17:00 in 12 hour clock is 5:00 PM.

15 minutes + 5:00 PM

⇒ 5:15 PM

Answer:

P(X < 80) = 0.89435.

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

[tex]\mu = 60, \sigma = 16[/tex]

P(X < 80)

This is the pvalue of Z when X = 80. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{80 - 60}{16}[/tex]

[tex]Z = 1.25[/tex]

[tex]Z = 1.25[/tex] has a pvalue of 0.89435.

So

P(X < 80) = 0.89435.

Answer:

Step-by-step explanation:

The complete statement would be "if a line is perpendicular to one of two parallel lines, then it is also perpendicular to the other".

The reason for this is because parallel lines have the same slope, that's the condition. On the other hand, parallel lines have opposite and reciprocal slopes.

So, if you think this through, if a line is perpendicular to another, then it's going to be perpendicular to all different lines which are parallel to the first one, because all their slopes are equivalent, and they will fulfill the perpendicularity condition.

Answer:

Parallel line

Step-by-step explanation:

Hope It Helps

Answer:

P10 = 27.4

P90 = 22.0

It helps the producer to know the higher (P10) and lower estimates (P90) for the amount of chocolate chips per cookie.

Step-by-step explanation:

In P10 and P90 the P stands for "percentile".

In the case of P10, indicates the value X of the random variable for which 10% of the observed values will be above this value X.

In the case of P90, this percentage is 90%.

In this case, we can calculate from the z-values for each of the percentiles in the standard normal distribution.

For P10 we have:

[tex]P(z>z_{P10})=0.1\\\\z_{P10}=1.2816[/tex]

For P90 we have:

[tex]P(z>z_{P90})=0.9\\\\z_{P90}=-1.2816[/tex]

Then, we can convert this values to our normal distribution as:

[tex]P10=\mu+z\cdot\sigma=24.7+1.2816\cdot 2.1=24.7+2.7=27.4 \\\\P90=\mu+z\cdot\sigma=24.7-1.2816\cdot 2.1=24.7-2.7=22.0[/tex]

Answer:

z-Axis. The axis in three-dimensional Cartesian coordinates which is usually oriented vertically. Cylindrical coordinates are defined such that the -axis is the axis about which the azimuth coordinate. is measured.

Step-by-step explanation:

Answer:

Where is the table because I dont see it up here?