Answer:
5.06*10^9
Explanation:
EA = σ(πr²)/εo, where area of the wall A = 2πr², on substituting we have
E(2πr²) = σ(πr^2)/εo
E = σ/(2εo)
What we then do is substitute the values from the question into this formula
E = (8.95*10^-6 C/cm^2)(100^2 cm^2 / m^2) / (2*8.85e-12 C^2/N-m^2)
E = 5.06*10^9 N/C
Therefore, the electric field is calculated to be 5.06*10^9 N/C
A) The electric field in front of the wall is 5.05 * 10⁹ N/C, Away from the wall
B) No the result does not change as distance from wall varies
C) The electric field in front of the conducting wall is : 10.11 * 10⁹ N/C , Away from the wall
Given data :
uniform density of nonconducting thin layer = 8.95 µC/cm² = 8.95 * 10⁻² C/m²
A) Determine the electric field 7.55 cm in front of the wallE = [tex]\frac{\alpha }{2*\beta }[/tex] --- ( 1 )
where : [tex]\alpha[/tex] = 8.95 * 10⁻² C/m², [tex]\beta[/tex]= 8.85 * 10⁻¹² N-m²/C²
back to equation ( 1 )
E = ( 8.95 * 10⁻² ) / ( 8.85 * 10⁻¹² ) * [tex]\frac{1}{2}[/tex]
= 5.05 * 10⁹ N/C,
B) The result from part A does not change as the distance from the wall varies. ( No )
C) When the nonconducting wall is replaced by thick conducting wall
Determining the electric field strength for the conducting wall
E = [tex]\frac{\alpha }{\beta }[/tex] ----- ( 2 )
where : [tex]\alpha[/tex] = 8.95 * 10⁻² C/m², [tex]\beta[/tex] = 8.85 * 10⁻¹² N-m²/C²
E = ( 8.95 * 10⁻² ) / ( 8.85 * 10⁻¹² )
= 10.11 * 10⁹ N/C
Hence we can conclude that; The electric field in front of the wall is 5.05 * 10⁹ N/C, Away from the wall. No the result does not change as distance from wall varies, and The electric field in front of the conducting wall is : 10.11 * 10⁹ N/C , Away from the wall.
Learn more about electric field calculations : https://brainly.com/question/14372859
a glass beaker has a mass of 50g. a liquid of density 1.8g/cm3 is poured into the beaker until it reaches the 200cm3 mark. calculate the total mass of the beaker and its contents
Answer:
total mass = 410 g
Explanation:
density = 1.8 g/cm³
volume = 200 cm³
density = mass / volume
mass (of liquid) = density x volume
= 1.8 x 200
= 360 g
total mass (beaker + liquid) = 50 + 360 = 410 g [Ans]
Hope this helps!
A monk is sitting atop a mountain in complete rest in meditation. What is the Kinetic
Energy of the monk? (assume mass of 65 kg and the mountain's height was 1000 m)
4,225,000
No Kinetic Energy - because there is no movement
637,000
65.000
Answer:
No kinetic energy-because there is no movement
Explanation:
It states that the monk is at complete rest so there is no movement.
Consider a length of pipe bent into a U-shape. The inside diameter of the pipe is 0.5 m. Air enters one leg of the pipe at a mean velocity of 100 m/s and exits the other leg at the same magnitude of velocity, but moving in the opposite direction. The pressure of the flow at the inlet and exit is the ambient pressure of the surroundings. Calculate the magnitude and direction of the force exerted on the pipe by the airflow. The air density is 1.23 kg/m3 .
Answer:
The magnitude of the force exerted on the pipe by the air is 4830 N and it acts horizontally
Explanation:
Given the data in the question;
from the Newton's second law of motion;
F = ma
where m is the mass, a is acceleration and F is the force exerted on the pipe due to the airflow in it
now in terns of mass flow;
F = [tex]m^{"}[/tex]V
where [tex]m^{"}[/tex] is the mass flow rate, V is the velocity(
so
[tex]m^{"}[/tex] = pAV
[tex]m^{"}[/tex] = p × ([tex]\frac{\pi }{4}[/tex] d² ) × V
where d is the diameter of the pipe( 0.5 m)
p is the density( 1.23 kg/m³ )
velocity v is 100 m/s
so we substitute
[tex]m^{"}[/tex] = 1.23 × ([tex]\frac{\pi }{4}[/tex] (0.5)² ) × 100
[tex]m^{"}[/tex] = 30.75 × [tex]\frac{\pi }{4}[/tex]
[tex]m^{"}[/tex] = 24.15 kg/s
Now lets write the equation for the force exerted on the pipe by the airflow
F = [tex]m^{"}[/tex]( V₁ - V₂)
where V₁ is velocity at inlet ( 100 m/s )
V₂ is velocity at exit ( - 100 m/s )
so we substitute
F = 24.15 ( 100 - (-100))
F = 24.15 × 200
F = 4830 N
The pipe is symmetric about horizontal axis so the force should also b acting only in the horizontal direction since any force component in the vertical direction is nullified due to this symmetry
Therefore, The magnitude of the force exerted on the pipe by the air is 4830 N and it acts horizontally
Which of the following best defines effective listening?
Answer:
The following seems to be the summary including its given phrase.
Explanation:
The willingness to adequately consider the knowledge another speaker provides as well as show interest throughout the subject covered constitutes skills of effective listening. Truly wonderful hearing skills require an individual just to listen fully to the information such that a relevant reading of the information or a piece of evidence can be done.
A high frequency sound will have a ?
Answer:
The frequency of a sound wave is what your ear understands as pitch. A higher frequency sound has a higher pitch and the lower the period
Answer:
High-frequency sound waves produce high-pitched sounds, and low-frequency sound waves produce low-pitched sounds.
Calculate the mass of air in a room 5 m by 4 m by 3 m the density of air is 1.3 kg/m3
Answer:
Explanation:
density (d) = 1.3 kg/m³
volume of the room (v)
= 5 m * 4m * 3 m
= 60 m³
mass(m) =?
now we know density is defined as mass per unit volume so
d = m / v
1.3 = m / 60
m = 78 kg
Calculate the momentum of a 6 kg ball thrown at 20 m/s by a 3 newton
force. *
Answer:
momentum = mass × velocity = 6× 20 =120 kg.ms-1
Explanation:
not sure if this is right
The starter motor of a car engine draws an electric current of 110 A from the battery. The copper wire to the motor is 4.20 mm in diameter and 1.73 m long. The starter motor runs for 0.95 s before the car engine starts up.
How much electric charge passes through the starter motor?
________
What is the current density in the wire?
_________
How far does an electron travel along the wire while the starter motor is on? (The density of conduction electrons in copper is n = 8.50×1028 1/m3.)
________
Answer:
a. 104.5 C b. 7.94 × 10⁶ A/m² c. 5.83 × 10⁻⁴ m/s
Explanation:
a. How much electric charge passes through the starter motor?
Using Q = It where Q = electric charge passing through the starter motor, I = current = 110 A and t = time = 0.95 s
So, Q = It = 110 A × 0.95 s = 104.5 C
b. What is the current density in the wire?
The current density, J = I/A where I = current = 110 A and A = cross-sectional area = πd²/4 where d = diameter of copper wire = 4.20 mm = 4.20 × 10⁻³ m
So, J = I/A
= I/πd²/4
= 4I/πd²
= 4 × 110 A/π(4.20 × 10⁻³ m)²
= 440 A/55.42 × 10⁻⁶ m²
= 7.94 × 10⁶ A/m²
c. How far does an electron travel along the wire while the starter motor is on? (The density of conduction electrons in copper is n = 8.50×1028 1/m3.)
To find how far the electron travels, we need to find the electron drift velocity from
J = nev where J = current density = 7.94 × 10⁶ A/m², n = electron density = 8.50 × 10²⁸ m⁻³, e = electron charge = 1.602 × 10⁻¹⁹ C, v = drift velocity of electrons and A = cross-sectional area of wire = πd²/4 where d = diameter of copper wire = 4.20 mm = 4.20 × 10⁻³ m
So, v = J/ne
Substituting the values of the variables into the equation, we have
v = 7.94 × 10⁶ A/m² ÷ (8.50 × 10²⁸ m⁻³ × 1.602 × 10⁻¹⁹ C)
v = 7.94 × 10⁶ A/m² ÷ (13.617 × 10⁹ Cm⁻³)
v = 0.583 × 10⁻³ m/s
v = 5.83 × 10⁻⁴ m/s
URGENT HELP !! The coefficients of static and kinetic frictions for plastic on wood are 0.53 and 0.40, respectively. How much horizontal force would you need to apply to a 34.4 kg object to start it moving from rest?
Answer:
43.83 N
Explanation:
Given that,
The mass of an object, m = 34.4 kg
The coefficients of static and kinetic frictions for plastic on wood are 0.53 and 0.40, respectively.
The force of static friction,
[tex]F_s=\mu_smg\\\\F_s=0.53\times 34.4\times 9.8\\\\F_s=178.67\ N[/tex]
The force of kinetic friction,
[tex]F_k=\mu_kmg\\\\F_k=0.40\times 34.4\times 9.8\\\\F_k=134.84\ N[/tex]
Net force acting on the object is :
F = 178.67-134.84
= 43.83 N
Hence, this is the required solution.
can someone please answer this for me ❤️
Answer:
I don't understand the question
Explanation:
sorry I cant help because I am just a first former
Ken Warby holds the world record speed
on water. If he drove his motorboat a
distance of 1000.0 m in 7.045 s, how fast
was his boat moving?
Know
Find
Equation
Solve
Answer:
141.9m/s
Explanation:
know:
distance = 1000.0m
time = 7.045s
find:
speed = ?
equation:
v = d/t
solve:
v = d/t
= 1000.0m/7.045s
= 141.9m/s
therefore, his boat was moving 141.9m/s
Research all three options: diet, exercise, combination of diet and exercise, Write a one page, typed, double-spaced summary of which you think is better and why.
Answer:
EXERCISE
It is very useful than diet and better than diet. All cannot do diet also exercise some of them will do but if we do exercise it is very helpful for health but diet is not much helps regular exercise helps body fitness and health it will burn fat fast if we do regularly or else no and if we do exercise even our face glows naturally. Morning exercise helps to refresh our mind and our full day will be active.For me EXERCISE is better than diet
Find the moment of 300N force about B
Answer:
300
Explanation Hope I'm not wrong.
A boy kicks a ball away in a football field.
Which of the following is true about his work done?
a. The energy is dissipated in the air.
b. The energy has transferred from one object to another.
C. The boy does not perform any work.
d. The work done produces twice the amount of heat energy.
b. cause boy transfer his energy from his foot to move the object.
A boy kicks a ball away in a football field,work done is cause boy transfer his energy from his foot to move the object.
What is energy?
Energy is the ability or capability to do tasks, such as the ability to move an item (of a certain mass) by exerting force. Energy can exist in many different forms, including electrical, mechanical, chemical, thermal, or nuclear, and it can change its form.
The energy an object has as a result of motion is known as kinetic energy. A force must be applied to ball in order to accelerate it. We must put in effort in order to apply a force. Following work, energy is transmitted to the item, which causes it to move at a new, constant speed. An ball will store energy as the result of its position is potential energy.
A boy kicks a ball away in a football field,work done is cause boy transfer his energy from his foot to move the object.
To learn more about energy refer to the link:
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A polycondensation reaction takes place between 1.2 moles of a dicarboxylic acid, 0.4 moles of glycerol (a triol) and 0.6 moles of ethylene glycol (a diol). A.Calculate the critical extents of reaction for gelation using (i) the statistical theory of Flory and (ii) the Carothers theory.B.Comment on the observation that the measured value of the critical extent of reaction is 0.866.
Answer:
A) i) using statistical theory of floxy
(Pa)c = 0.816
(Pb)c = 0.816
ii) using Carothers theory
( Pc ) = 0.917
B) To Obtain the measured value of critical extent of reaction ( 0.866) 1 mol of Glycerol will react with 1 mol of dicarboxylic acid, but the same can not be applied to our obtained value because our stoichiometry is different
Explanation:
Given data :
Polycondensation reaction takes place between : 1.2 moles of dicarboxylic acid , 0.4 moles of glycerol and 0.6 moles of ethylene glycol
A) Calculate the critical extents of reaction for gelation
i) using statistical theory of floxy
(Pa)c = 0.816
(Pb)c = 0.816
ii) using Carothers theory
( Pc ) = 0.917
attached below is the detailed solution
B) To Obtain the measured value of critical extent of reaction ( 0.866) 1 mol of Glycerol will react with 1 mol of dicarboxylic acid, but the same can not be applied to our obtained value because our stoichiometry is different
Question 7 of 10
What is cos(22")?
O A. 0.93
B. 0.22
C. 0.37
O D. 0.40
Answer:
A. 0.93
Explanation:
The manufacturer of a 9V dry-cell flashlight battery says that the battery will deliver 20 mA for 80 continuous hours. During that time the voltage will drop from 9 V to 6 V. Assume the drop in voltage is linear with time. How much energy does the battery deliver in this 80 h interval
Answer:
17280 J or 17.28 kJ
Explanation:
Given that the voltage drop,
U = U2 - U1
U = 9 - 6
U = 3V
Also, we're told that the current, I is equal to 20 mA with the discharge time, t being 80 hrs.
Converting the time from h oi urs to seconds, we have
t = 80 * 3600
t = 288000
Now, to find the energy needed, we're going to use the formula
w = pt, where p = U * I
p = 3 * 20*10^-3
p = 60*10^-3
w = 60*10^-3 * 288000
w = 17280 J or 17.28 kJ
Therefore, the total energy the battery delivers in the 80 hrs is 17.28 kJ
I need help on how to start my essay on the 3 laws of motion
Answer:
for the first paragraph introduce the definition. for the second paragraph write about the first law, for the third paragraph write about the 2nd for the fourth paragraph write about the 3rd law. for the last paragraph do a brief summary of what you wrote and a conclusion about the laws.
i hope this helps a bit
Answer:
You can start off with the first law of motion (newtons first law), talk about what it is or what it does, give examples.
A motor has a rotor (with armature) of moment of inertia ????m . The rotor is attached to a gear box of gear ratio G > 1. The output of the gearbox is attached to a mass whose moment of inertia is ????. What will be the moment of inertia ‘felt’ by the motor? What will be the moment of inertial ‘felt’ by someone who is rotating the mass ???? by hand, to turn the motor? Which of the two is large
Answer:
hello your question is incomplete attached below is the complete question
answer : The moment of inertial felt by someone ( J ) is greater that the moment of inertia felt by the motor i.e. J > Jm
Explanation:
Gear ratio G > 1
a) Determine the moment of inertia felt by the motor
moment of inertia felt by Motor = moment of Inertia at the armature
b) Determine the moment of inertial felt by someone who is rotating the mass by hand
moment of inertia felt by someone is = J
The moment of inertial felt by someone ( J ) is greater that the moment of inertia felt by the motor
attached below is a detailed solution
Help me please I wrote some but I am still stuck
Answer:
write something like after the spacecraft launched all of the potential energy transformed into kinetic energy causing the spacecraft to go at an abnormal spped.
Explanation:
0.55 kg mouse moving E at 60m s or a 900 kg elephant moving E at 0.03m Which has the most momentum?
Answer:
the mouse
Explanation:
the mouse has a momentum of 33 m kg/s
while the elephant has a momentum of 27 m kg/s
i found this out using p=mv
all of the following elements will form ions by losing electrons except
aluminum
iron
sodium
oxygen
What is the difference between inertia and momentum?
Is inertia a force (will give brainleist for first answer)
Answer:
Yes.
Explanation:
Answer:
I do believe it is. (more characters for character limit)
the centre of mass of a metre rule is at the 50cm mark. state what is meant by Centre of mass
Answer:
Centre of mass of any body is a point where all mass of a body is supposed to be concentrated
it lies in geometrical centre....
A square metal plate of edge length 12 cm and negligible thickness has a total charge of 5.6 × 10-6 C. (a) Estimate the magnitude E of the electric field just off the center of the plate (at, say, a distance of 0.49 mm from the center) by assuming that the charge is spread uniformly over the two faces of the plate. (b) Estimate E at a distance of 29 m (large relative to the plate size) by assuming that the plate is a charged particle.
Answer:
a) 2.2*10^7 N/C
b) 60 N/C
Explanation:
To start with, we say that the
Area charge of the plate, σ = q/2A
σ = 5.6*10^-6 / 2(12*10^-2)²
σ = 5.6*10^-6 / 0.0288
σ = 1.944*10^-4 C²/m
Next, we find the electric field
Electric field, E = σ/Eo
Electric field, E = 1.944*10^-4 / 8.85*10^-12
Electric field, E = 2.2*10^7 N/C
b)
E = kq/r²
E = [8.99*10^9 * 5.6*10^-6] / 29²
E = 50344 / 841
E = 60 N/C
This means that the E at a distance of 29 m is 60 N/C
How far can you get away from your little
brother with the squirt gun filled with
paint if you can travel at 3 m/s and you
have 15s before he sees you?
Know
Find
Equation
Solve
spray him in the eyes and you have until he washes it put
Is light from a fire matter
Answer:
Is fire matter? Matter is anything that has mass and occupies space. The flame itself is a mixture of gases (vaporized fuel, oxygen, carbon dioxide, carbon monoxide, water vapor, and many other things) and so is matter. The light produced by the flame is energy, not matter.
How long must a 0.54-mm-diameter aluminum wire be to have a 0.42 A current when connected to the terminals of a 1.5 V flashlight battery
Answer:
L = 30.85 m
Explanation:
First, we calculate the resistance of the wire by using Ohm's Law:
V = IR
where,
V = Potential Difference = 1.5 V
I = Current = 0.42 A
R = Resistance of Wire = ?
Therefore,
[tex]R = \frac{1.5\ V}{0.42\ A}\\\\R = 3.57\ Ohms[/tex]
Now, the cross-sectional area of wire will be:
[tex]Area = A = \frac{\pi d^{2}}{4}\\\\A = \frac{\pi (0.00054\ m)^{2}}{4}\\\\A = 2.29\ x\ 10^{-7}\ m^{2}[/tex]
Now, the resistance of the wire is given as:
[tex]R = \frac{\rho L}{A}\\\\L = \frac{RA}{\rho}[/tex]
where,
L = Length of Wire = ?
ρ = resistivity of aluminum = 2.65×10⁻⁸ Ohm.m
Therefore,
[tex]L = \frac{(3.57\ Ohms)(2.29\ x\ 10^{-7}\ m^{2})}{2.65\ x\ 10^{-8}\ Ohm.m}[/tex]
L = 30.85 m
Consider the following three concentric systems two thick shells and a solid sphere all conductors The radii in the increasing order are a b c d and e The small sphere is given an excess charge of 3 C and the smaller shell is given an excess charge of 7 C The larger shell is electrically neutral The system quickly comes to electrostatic equilibrium state a Note that there are 5 conducting surfaces What are the electric charges values and signs on the each of them Are these charges distributed uniformly
Answer:
Explanation:
From the given question, the small sphere was provided with an excess charge of +3 C, while the smaller shell was given an excess of -7 C, it should be -7 C and not 7 C.
So, in light of that, to determine the electric charges values & signs on each of them, we have:
on a = +3 C
on b = -7 C
on c = -7 C
on d = +3 C
on e = -7 C