A. No, because it fails the vertical line test.
B. Yes, because it passes the vertical line test.
C. Yes, because it passes the horizontal line test.
D. No, because it is not a straight line.​

Answer:

x=5  x=-3

Step-by-step explanation:

x^2 − 2x − 15 =0

Factor

What two numbers multiply to -15 and add to -2

-5*3 = -15

-5+3 =-2

(x-5) (x+3)=0

Using the zero product property

x-5 =0   x+3 =0

x=5  x=-3

Answer:

x^2 - 2x - 15 = 0

(x - 5) (x + 3) = 0

x - 5 = 0

x = 5

x + 3 = 0

x = -3

Answer:

The sampled populations have equal variances

Step-by-step explanation:

ANOVA which is fully known as Analysis of variances can be defined as the collection of statistical models as well as their associated estimation procedures which enables easily and effectively analyzis of the differences among various group means in a sample reason been that ANOVA is a total variance in which the observed variance in a specific variable is been separated into components which are attributable to various sources of variation which is why ANOVA help to provides a statistical test to check whether two or more population means are equal.

Therefore the required condition for using an ANOVA procedure on data from several populations for mean comparison is that THE SAMPLED POPULATION HAVE EQUAL VARIANCE.

Answer:

Ans) 42.7%

Step-by-step explanation:

For a continuous probability distribution, a curve known as probability density function contains information about these probabilities.

in the given range -

The probability that a continuous random variable = equal to the area under the probability density function curve

The probability that the value of a random variable is equal to 'something' is 1.

As per the diagram,

Weight of chocolate bar between 4 ounces and 7 ounces is highlighted in the blue part. That area is said to be 0.42739 and the total area under the curve is 1.

Hence required probability

=0.42739/1=0.42739

Ans) 42.7%

Round to nearest tenth of a percent

Answer:

a. True

Step-by-step explanation:

The frequency distribution is a summary of the gathered data set, in which the interval of values is divided into classes.

A requirement for a frequency distribution is for the classes to be mutually exclusive and exhaustive. That is, each individual, object, or measurement in the data set must belong to one and only one class.

Then, we can conclude that each individual, object, or measurement must appear in at least one (in fact, only in one) category or class.

Answer:

[tex]153.86 \: {units}^{2} [/tex]

Step-by-step explanation:

[tex]area = \pi {r}^{2} \\ = 3.14 \times 7 \times 7 \\ = 3.14 \times 49 \\ = 153.86 \: {units}^{2} [/tex]

Answer:

153.86 [tex]units^{2}[/tex]

Step-by-step explanation:

Areaof a circle = πr^2

[tex]\pi = 3.14[/tex](in this case)

[tex]r^{2} =7[/tex]

A = πr^2

= 49(3.14)

= 153.86

Answer:

The answer is

Step-by-step explanation:

For an nth term in an arithmetic sequence

[tex]U(n) = a + (n - 1)d[/tex]

where n is the number of terms

a is the first term

d is the common difference

From the question

a = 15

d = 24 - 15 = 9

n = 61

So the 61st term of the arithmetic sequence is

U(61) = 15 + (61-1)9

= 15 + 9(60)

= 15 + 540

= 555

Hope this helps you.

Let's solve the first equation and see if both -6−6minus, 6 and 666 are possible values of ccc.

Hint #22 / 4

\begin{aligned} c^2&=36\\\\ \sqrt{c^2}&=\sqrt{36}&\\\\ c &=\pm 6 \end{aligned}

c

2

c

2

​

c

​

=36

=

36

​

=±6

​

​

Yes, both -6−6minus, 6 and 666 are possible values of ccc for the first equation!

Hint #33 / 4

Let's do the same for the second equation.

\begin{aligned} c^3&=216\\\\ \sqrt[\scriptstyle 3]{c^3}&=\sqrt[\scriptstyle 3]{216}&\\\\ c &=6 \end{aligned}

c

3

3

c

3

​

c

​

=216

=

3

216

​

=6

​

​

No, both -6−6minus, 6 and 666 are not possible values of ccc for the second equation.

Hint #44 / 4

The following equation has both -6−6minus, 6 and 666 as possible values of ccc:

c^2 = 36c

2

=36

The equation that has both -6 and 6 as possible values is c² = 36.

Option A is the correct answer.

An equation contains one or more terms with variables connected by an equal sign.

Example:

2x + 4y = 9 is an equation.

2x = 8 is an equation.

We have,

If c is a possible value of 6, then c - 6 = 0.

Similarly, if c is a possible value of -6, then c + 6 = 0.

A)

c² = 36

We can factor this equation as c² - 36 = 0, which gives us (c - 6) (c + 6) = 0. Therefore, both c = 6 and c = -6 are solutions to this equation.

B)

c³ = 216

We can factor 216 as 6³, so c³ - 6³ = (c - 6) (c² + 6c + 36) = 0.

The quadratic factor c² + 6c + 36 does not have any real roots, so the only solution to this equation is c = 6.

Therefore, -6 is not a possible solution to this equation.

Thus,

The equation that has both -6 and 6 as possible values is c² = 36.

Learn more about equations here:

https://brainly.com/question/17194269

#SPJ3

Answer:

8

Step-by-step explanation:

Because it is equal to the 4 side

Answer:

a) Null and alternative hypothesis:

[tex]H_0: \pi=0.1\\\\H_a:\pi>0.1[/tex]

b) A Type I error is made when a true null hypothesis is rejected. In this case, it would mean a conclusion that the proportion is significantly bigger than 10%, when in fact it is not.

c) The consequences would be that they would be more optimistic than they should about the result of the investment, expecting a proportion of students that is bigger than the true population proportion.

d) A Type II error is made when a false null hypothesis is failed to be rejected. This would mean that, although the proportion is significantly bigger than 10%, there is no enough evidence and it is concluded erroneously that the proportion is not significantly bigger than 10%

e) The consequences would be that the investment may not be made, even when the results would have been more positive than expected from the conclusion of the hypothesis test.

Step-by-step explanation:

a) The hypothesis should be carried to test if the proportion of students that would eat there at least once a week is significantly higher than 10%.

Then, the alternative or spectulative hypothesis will state this claim: that the population proportion is significantly bigger than 10%.

On the contrary, the null hypothesis will state that this proportion is not significantly higher than 10%.

This can be written as:

[tex]H_0: \pi=0.1\\\\H_a:\pi>0.1[/tex]

Answer:Sqrt(8^2 + 3^2)

Step-by-step explanation:

Answer:

95.44% probability that the sample proportion will differ from the population proportion by less than 0.03.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

When the distribution is normal, we use the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean [tex]\mu = p[/tex] and standard deviation [tex]s = \sqrt{\frac{p(1-p)}{n}}[/tex]

In this question:

[tex]p = 0.05, n = 212, \mu = 0.05, s = \sqrt{\frac{0.05*0.95}{212}} = 0.015[/tex]

What is the probability that the sample proportion will differ from the population proportion by less than 0.03?

This is the pvalue of Z when X = 0.03 + 0.05 = 0.08 subtracted by the pvalue of Z when X = 0.05 - 0.03 = 0.02. So

X = 0.08

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

By the Central Limit Theorem

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]Z = \frac{0.08 - 0.05}{0.015}[/tex]

[tex]Z = 2[/tex]

[tex]Z = 2[/tex] has a pvalue of 0.9772

X = 0.02

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]Z = \frac{0.02 - 0.05}{0.015}[/tex]

[tex]Z = -2[/tex]

[tex]Z = -2[/tex] has a pvalue of 0.0228

0.9772 - 0.0228 = 0.9544

95.44% probability that the sample proportion will differ from the population proportion by less than 0.03.

Answer:

-6, -3

3, 8

Step-by-step explanation:

In order to find the number that are solutions to the compound inequalities, you first solve fr x on each inequality.

First inequality:

[tex]4(x+3)\leq 0\\\\4x+12\leq0\\\\4x\leq-12\\\\x\leq-3[/tex]  interval = (-∞ , -3]

Second inequality:

[tex]x+1>3\\\\x>2[/tex]   interval = (2 , ∞)

The interval solution is (-∞ , -3] U (2 , ∞)

The number that are included in the previous interval are:

-6, -3

or

3, 8

Answer: any except 0

Step-by-step explanation:

Answer:

The standard error for the difference in proportions of males and females who use public transportation every working day is 0.015.

The conditions are met.

Step-by-step explanation:

The sample 1 (males), of size n1=2570 has a proportion of p1=0.389.

[tex]p_1=X_1/n_1=1000/2570=0.389[/tex]

The sample 2 (females), of size n2=2055 has a proportion of p2=0.745.

[tex]p_2=X_2/n_2=1532/2055=0.745[/tex]

The difference between proportions is (p1-p2)=-0.356.

[tex]p_d=p_1-p_2=0.389-0.745=-0.356[/tex]

The pooled proportion, needed to calculate the standard error, is:

[tex]p=\dfrac{X_1+X_2}{n_1+n_2}=\dfrac{1000+1532}{2570+2055}=\dfrac{2532}{4625}=0.547[/tex]

The estimated standard error of the difference between means is computed using the formula:

[tex]s_{p1-p2}=\sqrt{\dfrac{p(1-p)}{n_1}+\dfrac{p(1-p)}{n_2}}=\sqrt{\dfrac{0.547*0.453}{2570}+\dfrac{0.547*0.453}{2055}}\\\\\\s_{p1-p2}=\sqrt{0.000096+0.000121}=\sqrt{0.000217}=0.015[/tex]

Conditions for a normal distribution approximation:

The expected number of "failures" or "successes", whichever is smaller, has to be larger than 10.

For the males sample, we have p=0.389 and (1-p)=0.611. The sample size is n=2570, so we take the smallest proportion and chek the condition:

[tex]n\cdot p=2570\cdot 0.389=999>10[/tex]

For the females sample, we have p=0.745 and (1-p)=0.255. The sample size is n=2055, so we take the smallest proportion and chek the condition:

[tex]n\cdot (1-p)=2055\cdot 0.255=524>10[/tex]

The conditions are met.

Answer:

-2x + y = -1.

Step-by-step explanation:

The slope of the line = rise / run

= (11-9) / (6-5) = 2.

The point-slope form of the line is

y - y1 = 2(x - x1) where (x1, y1) is a point on the line so we have:

y - 11 = 2(x - 6)     ( using the point  (6, 11)

y = 2x - 12 + 11

y = 2x - 1

Convert to standard form:

-2x + y = -1.

Answer:

D

Step-by-step explanation:

The numbers that are less than 0 are negative. Negative numbers have the "-" sign in front of them so the answer is D.

Answer:

d

Step-by-step explanation:

The other ones will always be positive four

Answer: 111=11

Step-by-step explanation: PEMDAS

(55.5 times 2)=5+13-7

(111)=5+13-7

(111)=18-7

111=11

Answer:

Sides:

Angles:

Step-by-step explanation:

Apply the law of sines to find the sine of [tex]\angle A[/tex]:

[tex]\displaystyle \frac{\sin{A}}{\sin{C}} = \frac{a}{c}[/tex].

[tex]\displaystyle\sin A = \frac{a}{c} \cdot \sin{C} = \frac{103}{159} \times \left(\sin{104^{\circ}}\right) \approx 0.628556[/tex].

Therefore:

[tex]\angle A = \displaystyle\arcsin (\sin A) \approx \arcsin(0.628556) \approx 38.9^\circ[/tex].

The three internal angles of a triangle should add up to [tex]180^\circ[/tex]. In other words:

[tex]\angle A + \angle B + \angle C = 180^\circ[/tex].

The measures of both [tex]\angle A[/tex] and [tex]\angle C[/tex] are now available. Therefore:

[tex]\angle B = 180^\circ - \angle A - \angle C \approx 37.1^\circ[/tex].

Apply the law of sines (again) to find the length of side [tex]b[/tex]:

[tex]\displaystyle\frac{b}{c} = \frac{\sin \angle B}{\sin \angle C}[/tex].

[tex]\displaystyle b = c \cdot \left(\frac{\sin \angle B}{\sin \angle C}\right) \approx 159\times \frac{\sin \left(37.1^\circ\right)}{\sin\left(104^\circ\right)} \approx 98.8[/tex].

Answer:

Option 4

Step-by-step explanation:

The central angles are "Angles in the center"

So,

Central Angles are <AOB, <BOC and <AOC

Answer:

<AOB, <BOC and < AOC

Step-by-step explanation:

There are 3 angles at center O . The largest is <AOC ( = 180 degrees). Thn you have 2 more each equal to 90 degrees.

Answer:

The probability of spending between 4 and 7 days in recovery

P(4≤x≤7) = 0.5445

Step-by-step explanation:

Step(i):-

Given mean of the Population μ = 5.3 days

Given standard deviation of the population 'σ' = 2 days

Let 'X' be the random variable in normal distribution

Let    x₁ = 4

[tex]Z_{1} = \frac{x_{1}-mean }{S.D} = \frac{4-5.3}{2} = -0.65[/tex]

Let    x₂ = 7

[tex]Z_{2} = \frac{x_{2}-mean }{S.D} = \frac{7-5.3}{2} = 0.85[/tex]

Step(ii):-

The probability of spending between 4 and 7 days in recovery

P(4≤x≤7) = P(-0.65≤Z≤0.85)

             =  P(Z≤0.85) - P(Z≤-0.65)

            = 0.5 + A( 0.85) - ( 0.5 - A(-0.65)

            = 0.5 + A( 0.85) -  0.5 +A(0.65)   ( ∵A(-0.65) = A(0.65)

           =   A(0.85) + A(0.65)

          = 0.3023 + 0.2422

         = 0.5445

Final answer:-

The probability of spending between 4 and 7 days in recovery

P(4≤x≤7) = 0.5445

Answer:

488p - 244

Step-by-step explanation:

Step 1: Add

61(8p - 4)

Step 2: Distribute

488p - 244

Answer:

see below

Step-by-step explanation:

Slope intercept form is y = mx+b where m is the slope and b is the y intercept

4x - 3y = 12

Solve for y

Subtract 4x from each side

4x-4x - 3y =-4x+ 12

-3y = -4x+12

Divide by -3

-3y/-3 = -4x/-3 + 12/-3

y = 4/3x -4

The slope is 4/3 and the y intercept is -4

The slope is Positive

Answer:

The minimum value of the bill that is greater than 95% of the bills is $37.87.

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

[tex]\mu = 28, \sigma = 6[/tex]

What are the minimum value of the bill that is greater than 95% of the bills?

This is the 95th percentile, which is X when Z has a pvalue of 0.95. So X when Z = 1.645.

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]1.645 = \frac{X - 28}{6}[/tex]

[tex]X - 28 = 6*1.645[/tex]

[tex]X = 37.87[/tex]

The minimum value of the bill that is greater than 95% of the bills is $37.87.

Answer:

5! = 120

Step-by-step explanation:

5! is basically 5(4)(3)(2)(1).

This question was not properly written, hence it is incomplete. The complete question is written below:

Complete Question:

Abigail and Liza work as carpenters for different companies. Abigail earns $20 per hour at her company and Liza earns $25 per hour at her company. Last week, Abigail and Liza worked for a total of 30 hours and together earned a total of $690. How many hours did Liza work last week?

Answer:

Lisa worked for 18 hours last week

Step-by-step explanation:

Let the number of hours Abigail worked last week = A

Let the number of hours Liza worked last week = B

Abigail earns = $20 per hour at her company

Liza earns = $25 per hour at her company

A + B = 30 ........... Equation 1

B = 30 - A

20 × A + 25 × B = 690

20A + 25B = 690 ............... Equation 2

Substitute 30 - A for B in Equation 2

Hence, we have:

20A + 25(30 - A) = 690

20A + 750 - 25A = 690

Collect like terms

20A - 25A = 690 - 750

-5A = -60

A = -60/-5

A = 12

Since A represents the number of hours Abigail worked, Abigail worked for 12 hours last week.

Substitute 12 for A in Equation 1

A + B = 30

12 + B = 30

B = 30 - 12

B = 18

Since B represents the number of hours Liza worked, therefore, Liza worked for 18 hours last week.

Answer:

  5 feet

Step-by-step explanation:

"Twice as tall" means "2 times as tall".

  2 × (2 1/2 ft) = (2 × 2 ft) +(2 × (1/2 ft)) = 4 ft + 1 ft = 5 ft

The child's mother is 5 feet tall.

Answer:

The mother is 5ft tall

Step-by-step explanation:

2 1/2 + 2 1/2 = 5ft

2ft+2ft = 4ft

1/2+1/2= 1ft

4ft+1ft = 5ft

Answer:

(a)$29.95

(b)A

Step-by-step explanation:

The​ cost, in​ dollars, of producing x cellphone cases is given by:

[tex]C(x)=-0.05 x^2+55 x.[/tex]

We are required to evaluate: [tex]\dfrac{C(251)-C(250)}{251-250}[/tex]

[tex]C(251)=-0.05(251)^2+55(251)=10654.95\\C(250)=-0.05(250)^2+55(250)=10625\\\text{Therefore:}\\\\\dfrac{10654.95-10625}{251-250}=29.95[/tex]

[tex]\dfrac{C(251)-C(250)}{251-250}=\$29.95[/tex]

The value calculated above represents the additional cost to produce one more item after making 250 items.

Answer:

Each table is $6 and each chair is $2.50

Step-by-step explanation:

Answer:

X = 2

Step-by-step explanation:

[tex]if \: {x}^{3} + {3}^{x} = 17 \: we \: can \: conclude \: that \: x \: is \: equal \: to \: two \\ {2}^{3} + {3}^{2} = 8 + 9 = 17[/tex]