A new soft drink is being market tested. It is estimated that 60% of consumers will like the new drink. A sample of 96 taste tested the new drink. a) Determine the standard error of the proportion b) What is the probability that more than 75% of consumers will indicate they like the drink

Answers

Answer 1

Answer:

a

  [tex]S.E = 0.05[/tex]

b

 [tex]P(P > 0.75) = 0.0013499[/tex]

Step-by-step explanation:

From the question we are told that

      The population  [tex]p = 0.60[/tex]

       The  sample size is  [tex]n = 96[/tex]

       The  sample proportion is  [tex]\r p = 0.75[/tex]

       

Generally the standard error is mathematically represented as

      [tex]S.E = \sqrt{ \frac{p(1-p)}{n } }[/tex]

substituting values    

       [tex]S.E = \sqrt{ \frac{0.60 (1-0.60 )}{96 } }[/tex]

       [tex]S.E = 0.05[/tex]

The  probability that  more  than  75% of consumers will indicate they like the drink is mathematically represented as

       [tex]P(P > 0.75) = P(\frac{\r P - p }{\sqrt{\frac{p(1-p)}{n} } } > \frac{\r p - p }{\sqrt{\frac{p(1-p)}{n} } } )[/tex]

 The  z-score is  evaluated as

              [tex]z = \frac{\r p - p }{\sqrt{\frac{p(1-p)}{n} } }[/tex]

So  

         [tex]P(P > 0.75) = P(Z > \frac{0.75 - 0.60 }{0.05} )[/tex]

         [tex]P(P > 0.75) = P(Z > 3)[/tex]

         [tex]P(P > 0.75) = 0.0013499[/tex]

This value above is obtained from the z-table  

   


Related Questions

M angle D=? What is the degree of the angle?

Answers

Answer:

80°

Step-by-step explanation:

In ACB and ECD

AC =~ CE [ Given ]

BC =~ CD [ Given ]

<ACD =~ <ECD [ Vertical angles ]

Hence, ∆ ACB =~ ECD by SAS congruency of triangles.

Then, <B = <D

In ∆ABC , sum of all three angles must be 180°

<A + <B + <C = 180°

plug the values

[tex] 30 + < d \: + 70 = 180[/tex]

Add the numbers

[tex]100 + < d = 180[/tex]

Move constant to R.H.S and change it's sign

[tex] < d = 180 - 110[/tex]

Subtract the numbers

[tex] < d = 80[/tex] °

Hope this helps..

Best regards!!

A simple random sample of 20 third-grade children from a certain school district is selected, and each is given a test to measure his/her reading ability. You are interested in calculating a 95% confidence interval for the population mean score. In the sample, the mean score is 64 points, and the standard deviation is 12 points. What is the margin of error associated with the confidence interval

Answers

Answer:

Margin of Error = ME =± 5.2592

Step-by-step explanation:

In the given question n= 20 < 30

Then according to the central limit theorem z test will be applied in which the standard error will be  σ/√n.

Sample Mean = μ = 64

Standard Deviation= S= σ = 12

Confidence Interval = 95 %

α= 0.05

Critical Value for two tailed test for ∝= 0.05 = ±1.96

Margin of Error = ME = Standard Error *Critical Value

ME = 12/√20( ±1.96)=

ME    = 2.6833*( ±1.96)= ± 5.2592

The standard error for this test is σ/√n

=12/√20

=2.6833

what is 1.8÷0.004? using long division

Answers

The answer for this problem is 4,500

Answer:

Hi! Answer will be below.

Step-by-step explanation:

The answer is 450.

If you divide 1.8 and 0.004 the answer you should get is 450.

Below I attached a picture of how to do long division...the picture is an example.

Hope this helps!:)

⭐️Have a wonderful day!⭐️

Families USA, a monthly magazine that discusses issues related to health and health costs, survey 19 of its subscribers. It found that the annual health insurance premiums for a family with coverage through an employer averaged $10,800. The standard deviation of the sample was $1095.

A. Based on the sample information, develop a 99% confidence interval for the population mean yearly premium

B. How large a sample is needed to find the population mean within $225 at 90% confidence? (Round up your answer to the next whole number.)

Answers

Answer:

a

   $10,151   [tex]< \mu <[/tex]  $11448.12

b

  [tex]n = 158[/tex]

Step-by-step explanation:

From the question we are told that

    The  sample size is  n  =  19

    The  sample mean is  [tex]\= x =[/tex]$10,800

     The  standard deviation is  [tex]\sigma =[/tex]$1095  

    The  population mean is  [tex]\mu =[/tex]$225

     

Given that the confidence level is 99%  the level of significance is mathematically represented as

       [tex]\alpha = 100 -99[/tex]

      [tex]\alpha = 1[/tex]%

=>    [tex]\alpha = 0.01[/tex]

Now the critical values of [tex]\alpha = Z_{\frac{\alpha }{2} }[/tex] is obtained from the normal distribution table as

        [tex]Z_{\frac{0.01}{2} } = 2.58[/tex]

The reason we are obtaining values for [tex]\frac{\alpha }{2}[/tex] is because [tex]\alpha[/tex] is the area under the normal distribution curve for both the left and right tail where the 99% interval did not cover while [tex]\frac{\alpha }{2}[/tex]  is the area under the normal distribution curve for just one tail and we need the  value for one tail in order to calculate the confidence interval

Now the margin of error is obtained as

     [tex]MOE = Z_{\frac{\alpha }{2} } * \frac{\sigma }{\sqrt{n} }[/tex]

substituting values

    [tex]MOE = 2.58* \frac{1095 }{\sqrt{19} }[/tex]

     [tex]MOE = 648.12[/tex]

The  99% confidence interval for the population mean yearly premium is mathematically represented as

    [tex]\= x -MOE < \mu < \= x +MOE[/tex]

substituting values

   [tex]10800 -648.12 < \mu < 10800 + 648.12[/tex]

    [tex]10800 -648.12 < \mu < 10800 + 648.12[/tex]

   $10,151   [tex]< \mu <[/tex]  $11448.12

The  largest sample needed is mathematically evaluated as

      [tex]n = [\frac{Z_{\frac{\alpha }{2} } * \sigma }{\mu} ][/tex]

substituting values

       [tex]n = [ \frac{ 2.58 * 1095}{225} ]^2[/tex]

      [tex]n = 158[/tex]

I bought a tv for 532.50 including the 6%sales tax. What was the original price of the tv without the sales tax?

Answers

Step-by-step explanation:

Hey, there !!!

According to your question,

total c.p = 532.50

tax rate =6%

let original price be x.

now,

total c.p = x + tax rate of x.

or, 532.50= x+ (6/100) × x

or, 532.50 = 106x/100

or, 53200 = 106x

or, x= 53200/106

Therefore, the original price was 501.88.

Hope it helps...

Which graph best models the inequality y<_ -2/5x+2

Answers

Answer:

Step-by-step explanation:

Simplify each term.

y ≤ −2x/5 + 2

Find the slope and the y-intercept for the boundary line.

Slope: -2/5

Y-intercept: 2

Graph a solid line, then shade the area below the boundary line since

y is less than -2x/5 + 2

y ≤ −2x/5 + 2

Hope this can help

7.
The area of this parallelogram is 120 ft. Find the value of h.
1
20 ft
12 ft
3 ft
15 ft
6 ft

Answers

6ft

the area = base x height
120ft = 20ft x height
height = 120/20 = 6ft

Answer:

h = 6 ft.

Step-by-step explanation:

area = base x height

where base = 20 ft.

        height = ?

           area = 120 ft²

plugin values into the formula

120 = 20 x height

height = 120  

               20

height = 6 ft.

Data on the weights (lb) of the contents of cans of diet soda versus the contents of cans of the regular version of the soda is summarized to the right. Assume that the two samples are independent simple random samples selected from normally distributed populations, and do not assume that the population standard deviations are equal. Complete parts (a) and (b) below. Use a 0.01 significance level for both parts.
Diet Regular
μ μ1 μ2
n 20 20
x 0.78062lb 0.81645 lb
s 0.00444 lb 0.00745 lb
A. Test the claim that the contents of cans of diet soda have weights with a mean that is less than the mean for the regular soda.
What are the null and alternative and hypotheses?
B. What is the test statistic? (Round to two decimal places as needed.)
C. What is the P-value? (Round to three decimal places as needed.)
State the conclusion for the test.
A. Reject the null hypothesis. There is sufficient evidence to support the claim that the cans of diet soda have mean weights that are lower than the mean weight for the regular soda.
B. Fail to reject the null hypothesis. There is sufficient evidence to support the claim that the cans of diet soda have mean weights that are lower than the mean weight for the regular soda.
C. Fail to reject the null hypothesis. There is not sufficient evidence to support the claim that the cans of diet soda have mean weights that are lower than the mean weight for the regular soda.
D. Reject the null hypothesis. There is not sufficient evidence to support the claim that the cans of diet soda have mean weights that are lower than the mean weight for the regular soda.
b. Construct a confidence interval appropriate for the hypothesis test in part (a).
___lb < u1 - u2 < ___lb (Round to three decimal places as needed.)
Does the confidence interval support the conclusion found with the hypothesis test?
(No/Yes) because the confidence interval contains (zero/only positives values/ only negative values)

Answers

Answer:

(A) Null Hypothesis, [tex]H_0[/tex] : [tex]\mu_1 \geq \mu_2[/tex]    

     Alternate Hypothesis, [tex]H_A[/tex] : [tex]\mu_1<\mu_2[/tex]  

(B) The value of t-test statistics is -18.48.

(C) The P-value is Less than 0.005%.

(D) Reject the null hypothesis. There is sufficient evidence to support the claim that the cans of diet soda have mean weights that are lower than the mean weight for the regular soda.

Step-by-step explanation:

We are given that the Data on the weights (lb) of the contents of cans of diet soda versus the contents of cans of the regular version of the soda is summarized to the right;

Diet Regular

μ μ1 μ2

n 20 20

x 0.78062lb 0.81645 lb

s 0.00444 lb 0.00745 lb

Let [tex]\mu_1[/tex] = mean weight of contents of cans of diet soda.

[tex]\mu_2[/tex] = mean weight of contents of cans of regular soda.

So, Null Hypothesis, [tex]H_0[/tex] : [tex]\mu_1 \geq \mu_2[/tex]      {means that the contents of cans of diet soda have weights with a mean that is more than or equal to the mean for the regular soda}

Alternate Hypothesis, [tex]H_A[/tex] : [tex]\mu_1<\mu_2[/tex]     {means that the contents of cans of diet soda have weights with a mean that is less than the mean for the regular soda}

The test statistics that will be used here is Two-sample t-test statistics because we don't know about population standard deviations;

                    T.S.  =  [tex]\frac{(\bar X_1 -\bar X_2)-(\mu_1- \mu_2)}{s_p \times \sqrt{\frac{1}{n_1}+\frac{1}{n_2} } }[/tex]  ~  [tex]t__n_1_+_n_2_-_2[/tex]

where, [tex]\bar X_1[/tex] = sample mean weight of cans of diet soda = 0.78062 lb

[tex]\bar X_2[/tex] = sample mean weight of cans of regular soda = 0.81645 lb

[tex]s_1[/tex] = sample standard deviation of cans of diet soda = 0.00444 lb

[tex]s_2[/tex] = sample standard deviation of cans of regular soda = 0.00745 lb

[tex]n_1[/tex] = sample of cans of diet soda = 20

[tex]n_2[/tex] = sample of cans of diet soda = 20

Also,  [tex]s_p =\sqrt{\frac{(n_1-1)s_1^{2}+ (n_2-1)s_2^{2}}{n_1+n_2-2} }[/tex] = [tex]\sqrt{\frac{(20-1)\times 0.00444^{2}+ (20-1)\times 0.00745^{2}}{20+20-2} }[/tex] = 0.00613

So, the test statistics =  [tex]\frac{(0.78062-0.81645)-(0)}{0.00613 \times \sqrt{\frac{1}{20}+\frac{1}{20} } }[/tex]  ~  [tex]t_3_8[/tex]

                                    =  -18.48

The value of t-test statistics is -18.48.

Also, the P-value of the test statistics is given by;

              P-value = P( [tex]t_3_8[/tex] < -18.48) = Less than 0.005%

Now, at a 0.01 level of significance, the t table gives a critical value of -2.429 at 38 degrees of freedom for the left-tailed test.

Since the value of our test statistics is less than the critical value of t as -18.48 < -2.429, so we have sufficient evidence to reject our null hypothesis as it will not fall in the rejection region.

Therefore, we conclude that the contents of cans of diet soda have weights with a mean that is less than the mean for the regular soda.

For the functions f(x)=4x−3 and g(x)=3x2+4x, find (f∘g)(x) and (g∘f)(x).

Answers

Answer:

(16x + 21) and (16x - 6)

Step-by-step explanation:

f(g(x)) = f(6 + 4x)

Applying the f(x) function on (6 + 4x) gives

4(6 + 4x) - 3

Which equals 16x + 24 - 3

= 16x + 21

g(f(x)) = g(4x - 3)

Applying the g(x) function on (4x - 3) gives

6 + 4(4x - 3)

Which equals 6 + 16x - 12

= 16x - 6

Answer:

(g∘f)(x)=48x2+48x+10

(g∘f)(x)=12x^2-6

Step-by-step explanation:

To find (f∘g)(x), use the definition of (f∘g)(x),

(f∘g)(x)=f(g(x))

Substituting 3x2−2 for g(x) gives

(f∘g)(x)=f(3x2−2)

Find f(3x2−2), where f(x)=4x+2, and simplify to get

(f∘g)(x)(f∘g)(x)(f∘g)(x)=4(3x2−2)+2=12x2−8+2=12x2−6

To find (g∘f)(x), use the definition of (g∘f)(x),

(g∘f)(x)=g(f(x))

Substituting 4x+2 for f(x) gives

(g∘f)(x)=g(4x+2)

Find g(4x+2), where g(x)=3x2−2, and simplify to get

(g∘f)(x)=3(4x+2)^2−2

(g∘f)(x)=48x2+48x+12−2

(g∘f)(x)=48x2+48x+10

Various studies indicate that approximately 11% of the world's population is left handed. You think this number is actually higher. You take an SRS of 225 people and find that 31 of them are left handed. Test your claim at the 5% significance level.
A. State your null and alternative hypotheses.
B. Sketch the rejection region.
C. Calculate the test statistic.
D. Determine the P-value for your test.

Answers

Answer:

a. H0 : p ≤ 0.11 Ha : p >0.11 ( one tailed test )

d. z= 1.3322

Step-by-step explanation:

We formulate our hypothesis as

a. H0 : p ≤ 0.11 Ha : p >0.11 ( one tailed test )

According to the given conditions

p`= 31/225= 0.1378

np`= 225 > 5

n q` = n (1-p`) = 225 ( 1- 31/225)= 193.995> 5

p = 0.4 x= 31 and n 225

c. Using the test statistic

z=  p`- p / √pq/n

d. Putting the values

z= 0.1378- 0.11/ √0.11*0.89/225

z= 0.1378- 0.11/ √0.0979/225

z= 0.1378- 0.11/ 0.02085

z= 1.3322

at 5% significance level the z- value is ± 1.645 for one tailed test

The calculated value falls in the critical region so we reject our null hypothesis H0 : p ≤ 0.11 and accept  Ha : p >0.11 and  conclude that the data indicates that the 11% of the world's population is left-handed.

The rejection region is attached.

The P- value is calculated by finding the corresponding value of the probability of z from the z - table and subtracting it from 1.

which appears to be 0.95 and subtracting from 1 gives 0.04998

The price of a boat that Arthur wants is $29,450. Arthur finances this by paying $6000 down and monthly payment of $792.22 for 36 months.
a. Determine the amount to be financed.​​​​​​​15a. _______________

b. Determine the installment price.​​​​​​​​b. _________________

c. Determine the finance charge.​​​​​​​​c. _________________

Answers

Answer:

see details below

Step-by-step explanation:

The price of a boat that Arthur wants is $29,450. Arthur finances this by paying $6000 down and monthly payment of $792.22 for 36 months.

a. Determine the amount to be financed.​​​​​​​15a. ___$23450____________

29450 - 6000 = 23450

b. Determine the installment price.​​​​​​​​b. ___$792,22______________

"monthly payment of $792.22"

c. Determine the finance charge.​​​​​​​​c. __$5069.92_______________

A = 792.22

n = 36

finance charge = total paid - amount to be financed

= 36*792.22 - 23450

= 5069.92

What is the quotient? StartFraction 7 Superscript negative 4 Over 7 Superscript negative 9 EndFraction

Answers

Answer:

19

Step-by-step explanation:

7 supersricpt 8

Over the last three evenings, Melissa received a total of 126 phone calls at the call center. The first evening, she received 6 more calls than the third evening. The second evening, she received 4 times as many calls as the third evening. How many phone calls did she receive each evening? Number of phone calls the first evening: Number of phone calls the second evening: Number of phone calls the third evening:

Answers

Answer:

calls first evening = 26

calls second evening  = 80

calls third evening = 20

Step-by-step explanation:

Let x = calls third evening

x+6 = calls first evening

4x = calls second evening

x+6 + 4x + x = total calls = 126

Combine like terms

6x+6 = 126

Subtract 6 from each side

6x =120

Divide by 6

6x/6 =120/6

x = 20

x+6 = calls first evening = 20+6 = 26

4x = calls second evening = 4*20 = 80

Let x = calls third evening = 20


Find the value of n such that 540n is perfect cube.​

Answers

Answer:

1.35

Step-by-step explanation:

next cube above 540 is 729

to get to 729: 729 / 540 = 1.35

n = 1.35

In a random sample of 400 residents of Boston, 320 residents indicated that they voted for Obama in the last presidential election. Develop a 95% confidence interval estimate for the proportion of all Boston residents who voted for Obama.

Answers

Answer:

C.I =  0.7608   ≤ p ≤   0.8392

Step-by-step explanation:

Given that:

Let consider a  random sample n = 400 candidates where  320 residents indicated that they voted for Obama

probability [tex]\hat p = \dfrac{320}{400}[/tex]

= 0.8

Level of significance ∝ = 100 -95%

= 5%

= 0.05

The objective is to  develop a 95% confidence interval estimate for the proportion of all Boston residents who voted for Obama.

The confidence internal can be computed as:

[tex]=\hat p \pm Z_{\alpha/2} \sqrt{\dfrac{ p(1-p)}{n } }[/tex]

where;

[tex]Z_{0.05/2}[/tex] = [tex]Z_{0.025}[/tex] = 1.960

SO;

[tex]=0.8 \pm 1.960 \sqrt{\dfrac{ 0.8(1-0.8)}{400 } }[/tex]

[tex]=0.8 \pm 1.960 \sqrt{\dfrac{ 0.8(0.2)}{400 } }[/tex]

[tex]=0.8 \pm 1.960 \sqrt{\dfrac{ 0.16}{400 } }[/tex]

[tex]=0.8 \pm 1.960 \sqrt{4 \times 10^{-4}}[/tex]

[tex]=0.8 \pm 1.960 \times 0.02}[/tex]

[tex]=0.8 \pm 0.0392[/tex]

= 0.8 - 0.0392     OR   0.8 + 0.0392  

= 0.7608    OR    0.8392

Thus; C.I =  0.7608   ≤ p ≤   0.8392

A= 63°
C = 7.75 inch
B = 47°
Oblique Triangle
4. Refer to the oblique triangle shown. What's the size of angle C?
O A. 60°
B. 125°
O C. 45°
O D. 70°

Answers

Answer:

Option D is correct.

Angle C = 70°

Step-by-step explanation:

The sum of angles in a triangle = 180°

So,

(Angle A) + (Angle B) + (Angle C) = 180°

(Angle A) = 67°

(Angle B) = 43°

(Angle C) = ?

67° + 43° + (Angle C) = 180°

Angle C = 180 - 67 - 43 = 70°

Angle C = 70°

Hope this Helps!!!

HELPPPPPP !!!!!!!!!!!!
! 25 ~! points

Answers

The correct answer is 76

Step by step

Is

Below

Need answers ASAP!!!!! (due today)

Answers

Answer:

15) 2.08m

Step-by-step explanation:

We kow tanA= p/b

Here, A=33°

b=3.2m

Then,

tan33°=p/3.2

0.65=p/3.2

p=0.65*3.2

p=2.08

So, The height of tree is 2.08m

14) 59.58ft

tan50°=p/b

1.19=p/50

p=59.58ft

So, The height of signpost is 59.58ft

In both of these problems, we will be using trigonometry! Remember, SOH-CAH-TOA.

14. x = 13.5950 ft

Visualization of the problem is attached below.

We want to find out the opposite side to the angle, and we know the adjacent side. Therefore, we should use the tangent function.

tan(50) = x / 50

x = tan(50) * 50

x = 13.5950 ft (round off wherever you need)

15. x = 241.0016 m

The visualization of the problem is already given. We know the same information as we need in the previous problems, an angle and an adjacent side, and we want to find the opposite side. Therefore, we should use the tangent function.

tan(33) = x / 3.2

x = tan(33) * 3.2

x = 241.0016 (round off wherever you need)

Hope this helps!! :)

What will happen to the median height of the outlier is removed?
{75, 63, 58, 59, 63, 62, 56, 59)

Answers

Answer:

The meadian decreases by 1.5 when the outlier is removed.

Step-by-step explanation:

Well first we need to find the median of the following data set,

(75, 63, 58, 59, 63, 62, 56, 59)

So we order the set from least to greatest,

56, 58, 59, 59, 62, 63, 63, 75

Then we cross all the side numbers,

Which gets us 59 and 62.

59 + 62 = 121.

121 / 2 = 60.5

So 65 is the median before the outlier is removed.

Now when we remove the outlier which is 75.

Then we order it again,

56, 58, 59, 59, 62, 63, 63

Which gets us 59 as the median.

Thus,

the median height decreases by 1.5 units when the outlier is removed.

Hope this helps :)

Someone please explain this!!!!

Answers

Answer:

23) x ≥ -140.

24) k > -9.

25) v ≥ 9.

26) m > 16.

Step-by-step explanation:

23) -14 ≤ [tex]\frac{x}{10}[/tex]

[tex]\frac{x}{10}[/tex] ≥ -14

x ≥ -140

Since it is a ≥ sign, you will put a shaded circle at -140, and the line will stretch infinitely to the right of the circle.

24) -20 < k - 11

k - 11 > -20

k > -9

Since it is a > sign, you will put a non-shaded circle at -9, and the line will stretch infinitely to the right of the circle.

25) -6v ≤ 54

6v ≥ 54

v ≥ 9

Since it is a ≥ sign, you will put a shaded circle at 9, and the line will stretch infinitely to the right of the circle.

26) 8 < [tex]\frac{m}{2}[/tex]

[tex]\frac{m}{2}[/tex] > 8

m > 16

Since it is a > sign, you will put a non-shaded circle at 16, and the line will stretch infinitely to the right of the circle.

Hope this helps!

What is the inequality

Answers

Answer:

x ≥ 4

Step-by-step explanation:

Well to find the inequality we need to single out x,

4x - 1 ≥ 15

+1 to both sides

4x ≥ 16

Divide 4 by both sides

x ≥ 4

Thus,

x is greater than or equal to 4.

Hope this helps :)


A father is 60 years old and his son is half his age. How old was the boy when his father was four times his age?

Answers

Hey there! I'm happy to help!

We see that the father is 60 years old, and the son is half of that age, so this means that the son is 30 years old.

We want to see the age the son was at when the father was four times his age. We know that the father is thirty years older than him, so we can write this equation with s representing the age of the son.

s+30=4s   (30 years older than the son is equal to to four times the son's age at the time)

We subtract 30 from both sides.

s=4s-30

We subtract 4s from both sides.

-3s=-30

We divide both sides by -3.

s=10

Therefore, the boy was 10 when his father was four times his age. This is because his father would have been 40 because that is 30 more years than 10, and it is four times ten!

Have a wonderful day! :D

Whal value of x is in the solution set of 9(2x + 1) < 9x - 18?
A: -4
B: -3
C: -2
D: -1

Answers

Answer:

A:-4

Step-by-step explanation:

If you simplify 9(2x+1)<9x-18 you will get 9x<-27. That will mean x<-3 and the only answer for something less than -3 is -4.

If the answer was right, please put 5 stars.

Answer:

The answer would be-4

Step-by-step explanation:

Here,

9(2x+1) < 9x-18

or, 18x+9 < 9x-18

or, 18x-9x<-18-9

or, 9x<-27

or, x= -27/9

Therefore, the value of x is -4.

Hope it helps...

For what value of k are the roots of the quadratic equation kx (x-2)+6=0 equal?​

Answers

Answer:

[tex]\boxed{\sf k=6}[/tex]

Step-by-step explanation:

[tex]\sf kx (x-2)+6=0[/tex]

Expand brackets.

[tex]\sf kx^2 -2kx+6=0[/tex]

This is in quadratic form.

[tex]\sf ax^2 +bx+c=0[/tex]

Since this is for equal roots:

[tex]\sf b^2 -4ac=0[/tex]

[tex]\sf a=k\\b=-2k\\c=6[/tex]

[tex]\sf (-2k)^2 -4(k)(6)=0[/tex]

[tex]\sf 4k^2-24k=0[/tex]

[tex]\sf 4k(k-6)=0[/tex]

[tex]\sf 4k=0\\k=0[/tex]

[tex]\sf k-6=0\\k=6[/tex]

Plug k as 0 to check.

[tex]\sf \sf 0x^2 -2(0)x+6=0\\6=0[/tex]

False.

So that means k must equal 6.

A hospital found that a lower outside temperature indicates a higher number of patient visits. What can we determine from this
Information?

Answers

Answer:

Second Answer

Step-by-step explanation:

by what number 7whole 2/3be divided to get 4whole1/3​

Answers

Answer: 1 30/39

Step-by-step explanation:

Because y/x=z and y/z=x are true with the same values, simply do 7 2/3 divided by 4 1/3 to get 69/39.

Hope it helps <3

What are the dimensions of the rectangle? PLEASE HELP!!

Answers

Answer:

2(x^2 + 8x -55)

Step-by-step explanation:

Well to do the box method we first need to simplify the given equation further to,

[tex]2x^2 + 16x - 110\\[/tex],

For this quadratic the box method doesn't work so we can divide everything by 2 make make it

2(x^2 + 8x -55)

Thus,

[tex]2x^2 + 16x - 110\\[/tex] factored is 2(x^2 + 8x -55).

Hope this helps :)

determining the probability of events. please help :)​

Answers

Answer:

C. 1/8

Step-by-step explanation:

Probability of shooting a goal on a throw is 2/4 = 1/2.

Probability of 3 in a row is (1/2)³ = 1/8.

A tool rental store charges a flat fee of $10.00 to rent a chain saw, and $4.25 for each day, including the first. Write an equation that expresses the cost y of renting this saw if it is rented for x days.

Answers

Answer:

y= 4.25x + $10

Step-by-step explanation:

A tool rental shop charges a flat fee of $10.00 to rent out their chain saw

An amount of $4.25 is charged for each of the days

Let x represent the amount that is charged for each day

Let y represent the total cost of the chain saw

Since the rental fee for each day is given as $4.25 and the flat fee is given as $10 then, the equation can be expressed as

y= $4.25x + $10

Hence the equation that expresses the cost y of renting this saw if it is rented for x days is y= $4.25x + $10

What is the degree of the polynomial?​

Answers

Answer:

2

Step-by-step explanation:

The degree of this polynomial is 2, since a parabola is drawn. A parabola is a graph of a quadratic equation which has the highest degree of 2.

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