Answer:
C = 93.4m
Ф₃= 54°
Explanation:
if Ф₁ =21° and Ф₃ = 11°
The new landowner has a triangular piece of flat land, and she wishes to fence. The length and orientation of the third side are 92.3 meters, with an orientation of 53.7°.
What is the Vector law of Algebra?Numerous algebraic operations involving vectors are carried out using vector algebra. The Latin word for the carrier is a vector. Points A and B are transported by vectors. The magnitude of the vector is the length of the line connecting the two points A and B, and the vector's direction is the movement from point A to point B. Other names for vectors are Euclidean vectors and spatial vectors. In many different domains, including mathematics, physics, engineering, and others, vectors are used.
Now, according to the question :
Let the given vector is R, and it makes an angle of θ then its components will be :
[tex]R_x[/tex] = R cos θ
[tex]R_y[/tex] = R sin θ
As we know that A + B + C =0
A is given as 80 m with direction 21° below the x-axis and,
B is 105 meters, with a direction of 11° counterclockwise from the positive y-axis.
[tex]A_x\\[/tex] = 80 cos 21°
[tex]A_y[/tex] = -80 sin 21°
similarly,
[tex]B_x\\[/tex] = 105 cos 101°
[tex]B_y[/tex] = -105 sin 101°
C = -(A+B)
C = -( 80 cos 21° + 105 cos 101°) i - (-80 sin 21°+105 sin 101°) j
C = 54.65 i -74.40 j
So the magnitude vector of C will be :
|C| = [tex]\sqrt{Cx^2+Cy^2}[/tex]
|C| = 92.3 m
Now direction will be :
θ = arc tan (Cy/Cx)
θ = 53.7°
Hence, the orientation of the third side will be 53.7° and the length will be 92.3 meters.
To get more information about Vector law of algebra :
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A heart beats 10 times in 10 seconds.
How many times does it beat in 1 minute?
Answer:
60
Explanation:
60secs = 1 minute
if you want to show you work further then
10 divided by 10 = 1
so each second is 1 heart beat
so then just 60 divided by 10 equals 6
so then just do 6 times 10 equals 60 beats
which two elements define a story's setting?
geographical location
character description
weather conditions
plot structure
dialogue and action
Reset
Next
Answer:
Geographical location, and time and weather conditions
Answer:
Georgraphical location and weather conditions
Explanation:
Setting is where the story takes place so the location would be vital and same with weather conditions because it determines what the character(s) do
Supriya has a pre-paid electricity connection at home. On a sultry Sunday afternoon, she checks that she only has ₹9 left in the balance. She wants to use the air conditioner (AC), rated at 1.2 kW. The price of electricity is ₹10 /unit in her area. How long can she run the AC before her balance is over and the power runs out?
Answer: 0.75 hour(s) or 45 minutes
Explanation:
1 unit of electricity = 1kwh
Amount of energy consumed by 1kw load in one hour
Price per unit = ₹10
Air conditioner rating(power) = 1.2Kw
Given that balance = ₹9
Therefore, supriya's total energy cost = energy balance = ₹9
Total energy cost = power in kilowatt × time of operation (in hour) × cost per unit
₹9 = 1.2kw × time × ₹10
₹9 = 12 × time
Time = 9 / 12
Time = 0.75 hours
0.75 × 60 = 45 minutes
I NEED HELP PLEASE, THANKS!
Find or draw at least two pictures that illustrates Newtons Second Law. Write a paragraph describing how each of the pictures you choose illustrates the law.
Answer:
The second law of motion states that the force of an object is equal to its mass times its
acceleration.
o A change in motion occurs only if a net force is exerted on an object.
o A net force changes the velocity of the object, and causes it to accelerate.
o If an object is acted upon by a net force, the change in velocity will be in the
direction of the net force.
o The acceleration of an object depends on its mass.
o The more mass an object has or the more inertia it has, the harder it is to
accelerate.
o More mass means less acceleration if the force acting on the objects is the same.
Explanation:
Explanation:
The force exerted by the earth on a falling baseball is smaller than the force exerted by the earth on a falling bowling ball. However, since the baseball has less mass than the bowling ball, the two accelerate at the same rate. This is known as Galileo's gravity experiment, but it also demonstrates Newton's second law.
When a bowling ball hits a pin, the pin pushes back with equal and opposite force. Because the bowling ball has a large mass, the acceleration caused by the force is small. Since the pin has a small mass, the acceleration caused by the force is large.
A car is running with a velocity of 29 m/s.How far does is it go in 2 minute?
Answer:
Distance = 3480m/s²
Explanation:
[tex]d = vt \\ v = 29 \\ t = 2 \: min= 120 seconds \\ d = 29 \times 120 \\ d = 3480[/tex]
speed = distance ÷ time
29=distance ×2
2×29= distance
58= distance
so,
distance is 58 meters
A plane mirror is useful for seeing:
They are used to see round dangerous bends
2. Fill in the blanks with appropriate words.
a. The force which acts towards the centre is called .......
force.
Answer:
centripetal force
Explanation:
because this force always compels the body to move in circle
How much net force is required to keep a 3-kg object moving to the right with a constant speed of
6.0 m/s?
Answer:
Explanation:
Here,
m = 3 Kg
a = 0 m/s^2 (velocity is constant so the acceleration is zero)
We have,
F = ma
or, F = 3 x 0
or, F = 0 N
Constant velocity can always be associated with a zero net force.
What is the advantage of using multiple cylinders in an engine?
Answer:
Temperature stresses are reduced as the multi-cylinder engine has more cooling surface area due to smaller cylinder bore. The intensity of vibration is sufficiently reduced as the primary and secondary forces are balanced. More power strokes per revolution giving smooth torque output.
Explanation:
What is the speed of a bus if it
covers 1.5km in 30 seconds?
a. 50km/Hr
b. 500m/s
c. 50m/s
d. 1500m/s
[tex]answer \\ = 50 \: m / s \\ solution \\ distance \: travelled\: by \: bus = 1.5 \: km \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 1.5 \times 1000 \: m \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 1500 \: m \\ time \: = 30 \: seconds \\ speed = \frac{distance}{time} \\ \: \: \: \: \: \: \: \: \: \: = \frac{1500m}{30s } \\ \: \: \: \: \: \: \: \: \: \: \: \: \: = 50 \: m/s \\ hope \: it \: helps[/tex]
Answer:
C. 50 m/s
Explanation:
Given:
Distance = 1.5 km = 1500 m
Time = 30 sec
Required:
Speed = ?
Formula
Speed = Distance / Time
Solution:
Putting the given in the formula
Speed = 1500/30
Speed = 50 m/s
I NEED HELP PLEASE, THANKS! Describe each Newton Law. :)
Explanation:
Newton's first law: Inertia
"An object in motion stays in motion, and an object at rest stays at rest, until acted upon by an unbalanced force."
This means that an object does not speed up, slow down, or change direction, unless the forces acting on it are unbalanced.
Newton's second law: Net force
∑F = ma
The net force (the sum of the forces acting on an object) is equal to the object's mass times its acceleration.
Newton's third law: Action/reaction
"For every action, there is an opposite and equal reaction."
This means that when one object pushes on another object (action), the second object pushes back with an equal and opposite force (reaction).
What is the energy of a photon with a frequency of 2.2 x 1016 Hz? Planck's constant is 6.63 x 10-34 Jos.
O 1.5 x 10-17
8.8 x 10-17
O 1.5 10-16
O 8.8 10-16
Answer: 1.5 × 10^-17
Explanation:
Given the following :
Frequency(f) = 2.2 × 10^16 Hz
Planck's constant(h) = 6.63 × 10^-34
The energy of a photon 'E' is given as the product of frequency and the planck's constant
E = hf
E = (6.63 × 10^-34) × (2.2 × 10^16)
E = 6.63 × 2.2 × 10^(-34 +16)
E = 14.586 × 10^-18
E = 1.4586 × 10^-17
E = 1.5 × 10-17 (2 S. F)
Answer:
C. 1.5 × 10–16 J
Explanation:
Question: A swimmer has a swimming speed of 5.75 m/s in still water. When she
heads directly across the river, she ends up travelling downstream at an angle of 40°
(with respect to a line perpendicular to the shore).
(a) What is the speed of the current?
(b) What heading would the swimmer need to have in order to reach a point directly
across the river?
(c) If the river is 15 m wide, how long would a trip directly across the river take?
Answer:
(a) 4.82 m/s
(b) The simmer need to head 57.05° upstream of the river to reach a point directly opposite the river
(c) 4.024 seconds
Explanation:
The parameters given are;
The speed of the swimmer = 5.75 m/s
The direction of the resultant motion = 40° downstream
The speed of the current = x m/s
Therefore in a given second, we have that the swimmer moves 5.75 meters across the river while the current moves x meters downstream
Which gives;
[tex]tan(40^{\circ}) = \dfrac{x}{5.75}[/tex]
x = 5.75 × tan(40°) = 4.82 m/s
The speed of the current = 4.82 m/s
(b) If the swimmer swims at a direction θ to reach a point, p, directly opposite the river, we have;
The resultant speed across the river will be the swimmer's swimming speed which is 5.75 m/s
5.75² = y² + 4.82²
y = √(5.75² - 4.82²) = √9.78
tan(θ) = 4.82/(√9.78) = 1.54
θ = tan⁻¹(1.54) = 57.05°
The simmer need to swim 57.05° upstream to reach a point directly opposite the river
(c) If the river is 15 m wide, we have;
Time (t) = Distance/speed
The component of the swimmer's speed directly across the river = 5.75/(tan(57.05°)
The component of the swimmer's speed directly across the river = 3.73 m/s
The time, t, to cross the river is therefore;
t = 15/3.73 = 4.024 seconds
Hence, the force of gravitation between Earth and Jupiter is 8.16 * 10 N
Enample 5: An apple with the mass of 200 g falls from a tree. What is the acceleration
of the apple towards the earth? What is the acceleration of the earth towards the apple?
(Given: mass of the earth = 6*10kg radius of the earth 6.4 10 m, G=6.67 * 10 " Nm
kg and neglecting height of the tree).
Answer:
Acceleration of the apple towards the earth is: 9.7705 m/s2.
Acceleration produced on earth towards the apple
[tex]0.325*10^{-24} \ \ m/s2.[/tex]
Explanation:
Given :
[tex]m = 200 g[/tex]
We have to convert into the kg ,
so
[tex]m=0.2 kg[/tex]
M=[tex]6*10^{24}[/tex] kg
[tex]R=6.4*10^{6} m[/tex]
[tex]G= 6.67*10^{-11} \ Nm^{2} kg-2[/tex]
As the gravitational force is existing among the earth and the apple
so
[tex]F=\frac{GMm}{R^{2} }[/tex]
Putting the value of G,M,m and [tex]R^{2}[/tex], we get
[tex]\frac{6.67*10^{-11} *6*10^{24} *0.2 }{(6.4*10^{6} )^{2} } \\\\F= 1.9541\ N[/tex]
Consider a1 and a2 be a acceleration due to the gravitational force of earth attraction created on the apples
F= a1 *m
[tex]a1\ =\ \frac{F}{m}[/tex]
a1=[tex]\frac{1.9541}{0.2}[/tex]
[tex]a1=9.7705 \ m/s2[/tex]
Acceleration of the apple towards the earth is: 9.7705 m/s2.
again
[tex]F= a2 *M[/tex]
a2=[tex]\frac{F}{M}[/tex]
[tex]a2=\frac{ 1.9541}{6**10^{24} } \\a2=0.325* 10^{-24}\ m/s2[/tex]
So, Acceleration produced on earth towards the apple
[tex]0.325*10^{-24} \ \ m/s2.[/tex]
A transformer has 500 turns of the primary winding and 10 turns of the secondary winding. a) Determine the secondary voltage if the secondary circuit is open and the primary voltage is 120 V
Answer:
First we use the fact that the ratio of the voltage on the secondary and on the primary will be the same as the ratio of the number of turns of both coils,
u=u^2/U^1 = N^2/N^1
we evaluate the unkown secondary voltage
u^ 2=N^2/N^1 u1
We substitute the given values -
u^2= 10/500 * 120v = 2.4v
Hence, the answer is 2.4v.
Physics students study a piano being pulled across a room on a rug. They know that when it is at rest, it experiences a gravitational force of 2200 N. When it is being pulled with 1200 N it is sliding across the room in equilibrium, but the students feel like they had to pull harder than 1200 N at first to begin motion.
Answer:
4
Explanation:
hope this helps
Answer:
The static frictional force is greater than the kinetic frictional force, so the static frictional force is greater than 1200 N.
Explanation:
Edge 2021
The estimated distance of the earth from the sun is 149000000km. The speed of the light is 300000km/s. What is the time taken for the light to travel from the sun to the earth
Answer:
The time taken for the light to travel from the earth to the sun = 496.67 seconds
Explanation:
Estimated distance of the earth to the sun = 149000000km
Speed of light = 300000km/s
Time taken for the light to travel from the sun to the earth = ?
Speed = Distance/time
time = Distance/speed
time = 149000000/300000
time = 496.67 s
The time taken for the light to travel from the earth to the sun = 496.67 seconds
As important as it is to plan ahead,sometimes you
Answer:
B. Cant stop things from going wrong.
Explanation:
To me it's the only reasonable answer...
A ball is falling at terminal velocity. Terminal velocity occurs when the ball is in equilibrium and the forces are balanced. Which free body diagram shows the ball falling at terminal velocity? A free body diagram with one force pointing downward labeled F Subscript g Baseline 20 N. A free body diagram with 2 forces: the first pointing downward labeled F Subscript g Baseline 20 N and the second pointing upward labeled F Subscript air Baseline 20 N. A free body diagram with 2 forces. The first pointing downward labeled F Subscript g Baseline 20 N and the second pointing upward labeled F Subscript air Baseline 5 N. A free body diagram with 2 forces: the first pointing downward labeled F Subscript g Baseline 20 N and the second pointing upward labeled F Subscript air Baseline 30 N.
Answer:
A free body diagram with 2 forces: the first pointing downward labeled F Subscript g Baseline 20 N and the second pointing upward labeled F Subscript air Baseline 20 N.
Explanation:
This is because at terminal velocity, the ball stops accelerating and the net force on the ball is zero. For the net force to be zero, equal and opposite forces must act on the ball, so that their resultant force is zero. That is F₁ + F₂ = 0 ⇒ F₁ = -F₂
Since F₁ = 20 N, then F₂ = -F₁ = -20 N
So, if F₁ points upwards since it is positive, then F₂ points downwards since it is negative.
So, a free body diagram with 2 forces: the first pointing downward labeled F Subscript g Baseline 20 N and the second pointing upward labeled F Subscript air Baseline 20 N best describes the ball falling at terminal velocity.
Answer:
b
Explanation:
To break a chemical bond, particles need to collide with a certain amount of a]energy. b]atoms. c]molecules. d]chemicals.
Answer:
Energy
Explanation:
The stronger the force it has the more quickly the bonds will break
As there will be more energy they will vibrate more and the bonds will separate easily..
Define distance and displacement with illustration
Answer:
DistanceThe length of the actual path travelled by a body is called distance travelled by a body.It is a scalar Quantity.It is measured in meter(m) in SI system.
DisplacementThe shortest distance from initial position to the final position of a body is called displacement of the body.It is a vector Quantity.It is measured in meter(m) in SI system..
Please see the attached picture...
It is the example of distance and displacement....
Hope this helps...
Good luck on your assignment...
mass of a body is 10 kg what does it mean
Answer:
Explanation:
MASS of a body indicates the quantity or amount of matter contained in it.S.I, unit of mass is kg
A 2-kg object is moving 6 m/s in a horizontal direction.
How much net force is required for this object to continue its state of motion?
Α. Ο Ν
B.
2N
C.
3 N
12 N
Answer: A) O N
Explanation:
An object in motion will maintain its state of motion. The presence of an unbalanced force changes the velocity of the object.
Elements in the same periodic table group have the same___
Answer:
elements in the same periodic table group have the same valence electrons
Need Help !
A 1500 kg car on flat ground is
moving 5.25 m/s. Its engine
creates a 1250 N forward force as the car moves 42.8 m. What is its final velocity?
Answer: 5.96m/s
Explanation:
Given the following :
Mass of car (m) = 1500kg
Velocity (V) = 5.25m/s
Forward force of engine = 1250N
Diatance moved = 4.8m
Final Velocity =?
Final kinetic energy = Initial kinetic energy + work done by engine
Initial kinetic energy = 0.5 × mass × velocity^2
Initial kinetic energy = 0.5 × 1500 × 5.25^2
Initial kinetic energy = 20671.875 J
Work done by engine = Force × distance
Work done by engine = 1250 × 4.8 = 6000J
Final kinetic energy = (20671.875 + 6000) J
= 26671.875 J
From kinetic energy = 0.5mv^2
26671.875 = 1/2 × 1500 × v^2
53343.75 = 1500v^2
v^2 = 35.5625
v = sqrt(35.5625)
v = 5.96m/s
What are the units of impulse
Answer:
Newton Second
Explanation:
The SI unit of impulse in Newton Second (N.s)
what are the fundamental units used in physics?
Answer:
Metre, kilogram, second, ampere, kelvin, candela, and mole
Explanation:
A base unit (also referred to as a fundamental unit) is a unit adopted for measurement of a base quantity
I NEED HELP PLEASE, THANKS! :)
Explain how the diffraction of light shows that light behaves like a wave.
Answer:
Diffraction of light shows that light behaves like a wave. It involves the change in the direction of waves while passing through any obstacle. Diffracted light can produce fringes of light, dark or colored bands (Just like the rainbow which is also a light wave). Diffracted light has certain wavelength, amplitude , frequency and speed which are the basic characteristics of being a wave which shows that light actually behaves like a wave.
Un bombero alejado d = 31.0 m de un edificio en llamas dirige un chorro de agua desde una manguera contra incendios a nivel del suelo con un ángulo de θi = 33.0° arriba de la horizontal como se muestra en la figura siguiente. Si la rapidez del chorro cuando sale de la manguera es vi = 40.0 m/s, ¿a qué altura (en m) golpeará el edificio? m
Answer:
El chorro golpea el edificio a una altura de 15.943 metros con respecto al suelo.
Explanation:
El chorro de agua exhibe un movimiento parabólico, dado que este tiene una inclinación inicial y la única aceleración es debida a la gravitación terrestre. Las ecuaciones cinemáticas que modelan el fenómeno son:
Distancia horizontal (en metros)
[tex]x = x_{o} + v_{o}\cdot t \cdot \cos \theta[/tex]
Donde:
[tex]x_{o}[/tex] - Posición horizontal inicial, medida en metros.
[tex]t[/tex] - Tiempo, medido en segundos.
[tex]v_{o}[/tex] - Velocidad inicial, medida en metros por segundo.
[tex]\theta[/tex] - Angulo de inclinación del chorro de agua, medido en grados sexagesimales.
Distancia vertical (en metros)
[tex]y = y_{o} + v_{o}\cdot t \cdot \sin \theta + \frac{1}{2}\cdot g \cdot t^{2}[/tex]
Donde:
[tex]y_{o}[/tex] - Posición vertical inicial, medida en metros.
[tex]g[/tex] - Constante gravitacional, medida en metros por segundo al cuadrado.
Partiendo de la primera ecuación, se despeja el tiempo:
[tex]t = \frac{x - x_{o}}{v_{o}\cdot \cos \theta}[/tex]
Si [tex]x = 31\,m[/tex], [tex]x_{o} = 0\,m[/tex], [tex]v_{o} = 40\,\frac{m}{s}[/tex] and [tex]\theta = 33^{\circ}[/tex], entonces:
[tex]t = \frac{31\,m-0\,m}{\left(40\,\frac{m}{s} \right)\cdot \cos 33^{\circ}}[/tex]
[tex]t = 0.924\,s[/tex]
La altura máxima se calcula por sustitución directa de términos en la segunda ecuación. Si [tex]y_{o} = 0\,m[/tex], [tex]v_{o} = 40\,\frac{m}{s}[/tex], [tex]t = 0.924\,s[/tex] y [tex]g = -9.807\,\frac{m}{s^{2}}[/tex], entonces:
[tex]y = 0\,m + \left(40\,\frac{m}{s} \right)\cdot (0.924\,s)\cdot \sin 33^{\circ} + \frac{1}{2}\cdot \left(-9.807\,\frac{m}{s^{2}} \right) \cdot (0.924\,s)^{2}[/tex]
[tex]y = 15.943\,m[/tex]
El chorro golpea el edificio a una altura de 15.943 metros con respecto al suelo.
A block of mass m is placed on a smooth wedge of inclination θ . The whole system is accelerated horizontally so that the block does not slip on the wedge. The force exerted by the wedge on the block has a magnitude: (A) mg tan θ (B) mg sin θ (C) mg cos θ (D) mg sec θ
Answer: mg/Cosθ
Explanation:
Taking horizontal acceleration of wedge as 'a'
FCosΘ = FsinΘ
F = mass(m) × acceleration(a) = ma
For horizontal resolution g = 0
Therefore,
Horizontal = Vertical
maCosΘ = mgSinΘ
aCosΘ = gSinΘ
a = gSinΘ/CosΘ
Recall from trigonometry :
SinΘ/Cosθ = tanΘ
Therefore,
a = gtanΘ
Normal force acing on the wedge:
mgCosΘ + maSinΘ - - - - (y)
Substitute a = gtanΘ into (y)
mgCosΘ + mgtanΘsinΘ
tanΘ = sinΘ/cosΘ
mgCosΘ + mgsinΘ/cosΘsinΘ
mgCosΘ + mgsin^2Θ/cosΘ
Factorizing
mg(Cosθ + sin^2Θ/cosΘ)
Taking the L. C. M
mg[(Cos^2θ + sin^2Θ) /Cosθ]
Recall: Cos^2θ + sin^2Θ = 1
mg[ 1 /Cosθ]
mg/Cosθ