A mole of a substance has a mass in grams that is equal to the molecular mass. For example, a carbon atom has a mass of 12.01 u. A mole of carbon has a mass of 12.01 g. Based on their molar masses, list the GFM of each substance.

Answer:

13896g

Explanation:

volume = 4.50×8.00×20.00 = 720 cm³

mass = density × volume

mass= 19.3 × 720 = 13896g

Answer:

Batteries hold chemical energy

Explanation:

The battery acid in a battery leads to chemical energy.

Answer:

Extreme heat

Explanation:

Because when matter is heated up The molecules move faster.

Answer:

I think it's extreme heat

Answer:

66.5753 amu

Explanation:

From the question given above, the following data were obtained:

Isotope A (⁶⁵X):

Mass of A = 65.0457 amu

Abundance of A = 20.53%

Isotope B (⁶⁷X):

Mass of B = 66.9704 amu

Abundance of B = 79.47%

Atomic mass of X =?

The atomic mass of X can be obtained as follow:

Atomic mass = [(mass of A × A%)/100] + [(mass of B × B%)/100]

= [(65.0457 × 20.53)/100] + [(66.9704 × 79.47)/100]

= 13.3539 + 53.2214

= 66.5753 amu

Therefore, the atomic mass of X is 66.5753 amu.

Element X, with an atomic mass of 66.58 amu, has 2 naturally occurring isotopes, ⁶⁵X (65.0457 amu, 20.53%) and ⁶⁷X (66.9704 amu,  79.47%).

The average atomic mass (atomic mass) of an element is the sum of the masses of its isotopes, each multiplied by its natural abundance.

Element X has 2 isotopes:

We can calculate the average atomic mass of X using the following expression.

mX = m⁶⁵X × ab⁶⁵X + m⁶⁷X × ab⁶⁷X

mX = 65.0457 amu × 0.2053 + 66.9704 amu × 0.7947

mX = 66.58 amu

Element X, with an atomic mass of 66.58 amu, has 2 naturally occurring isotopes, ⁶⁵X (65.0457 amu, 20.53%) and ⁶⁷X (66.9704 amu,  79.47%).

Learn more about atomic mass here: https://brainly.com/question/6200158

Answer:

H+ (aq)  +    ClO- (aq)  --->   HClO(aq)  

Explanation:

The net ionic reaction equation is a chemical equation that explicitly shows only the particular ions that undergo a chemical change in the course of a given reaction.

In this particular reaction, the molecular reaction equation is shown as follows;

HNO3(aq) + NaOCl(aq) -----------> NaNO3(aq) + HOCl(aq)

Ionically;

H+ (aq)  +    ClO- (aq)  --->   HClO(aq)

Answer:

the answer is B:) have a good day

Answer:

c. the amount of fossil fuels being burned increased

Explanation:

Carbon dioxide gas concentration increased over the time due to burning of fossil fuels increased. Fossil fuels are organic compounds which releases carbondioxide gas as a result of burning of fossil fuels in the engines of vehicles and industries. With the passage of time, number of vehicles increases in the world which needs more fossil fuels and due to burning of that fossil fuels, more carbondioxide gas is released.

Answer:

[tex]M_{C_9H_{13}NO_3}=183.23g/mol[/tex]

Explanation:

Hello!

In this case, since the molar mass of a chemical compound is computed by averaging the atomic mass of each element in the molecule and the amount of atoms; which in this case there are 9 carbon atoms, 13 hydrogen atoms, 1 nitrogen atom and 3 oxygen atoms; thus, we compute the average as shown below:

[tex]M_{C_9H_{13}NO_3}=m_C*9+m_H*13+m_N+m_O*3[/tex]

Now, we plug in the atomic masses to obtain:

[tex]M_{C_9H_{13}NO_3}=12.01*9+1.01*13+14.01+16.00*3\\\\M_{C_9H_{13}NO_3}=183.23g/mol[/tex]

Best regards!

Answer:

Option C. 24 days / 4 grams

Explanation:

From the question given above, the following data were obtained:

Days Elapsed >>>> Mass Remaining

0 >>>>>>>>>>>>>>> 16

12 >>>>>>>>>>>>>>> 11

24 >>>>>>>>>>>>>>> 8

36 >>>>>>>>>>>>>>> 6

A. Determination of the half-life of Thorium-234.

To determine the half-life, it is important to know the definition of half life.

Half-life is defined as the time taken for a substance to reduce to half its original mass.

From the table given above, we can see that the original mass of the isotope is 16 g (i.e at 0 day). By day 24, the mass of the isotope is 8 g (i.e half the original mass). Thus, the half-life of the isotope is 24 days.

B. Determination of the mass of the isotope remaining after 2 half lives.

Original amount (N₀) = 16 g

Number of half-lives (n) = 2

Amount remaining (N) =?

N = 1/2ⁿ × N₀

N = 1/2² × 16

N = 1/4 × 16

N = 4 g

Thus, 4 g of the isotope is remaining after 2 half lives.

Summay:

Half-life = 24 days

Amount remaining after 2 half-lives = 4 g

Option C gives the correct answer to the question.

The phases of nitrogen in order of increasing density is solid, liquid, and gas.

In conclusion, the correct option is D.

Read related link on:

https://brainly.com/question/24615770

Answer:

I think the answer is b

Explanation:

the paragraph states, that it is an experiment to see if there is any oxygen in the water

Answer:

See explanation below (Brainlist please)

Explanation:

First of all, we need to understand what is an acidic hydrogen.

An acidic hydrogen, is the atom of hydrogen which is more propense to undergo an acid base reaction, and form a stable ion or molecule in the process.

In other words, is the hydrogen that is more vulnerable to get substracted in an acid base reaction to form another compound.

Knowing this information, gives us an idea of how a molecule can be formed and which kind of compound is formed.

Now, in this question, we have 5 molecules. Each of them is either a ketone or aldehyde, so this mean that we have the carbonile group (C = O), which means that is easier to identify the acidic hydrogen. This is because the Carbonile group is an attractor group, so, it will attract the charges by inductive effect (in some cases by resonance), and the molecule is more stable.

This can be shown by drawing the enolate ion that is formed once the molecule undergo the acid base reaction. As it's an enolate form that we are looking for, then it means that the ketone or aldehyde is undergoing an electrofilic attack with a base. This base will substract the most acidic hydrogen to form a better and stable enolate. The acidic hydrogen and the enolate form can be seen in the attached picture.

a) In the case of acetaldehyde, the most acidic will be the hydrogen of carbon 2, because the hydrogen from the carbonile, once it's substracted, the charge of the carbon cannot be stabilized by resonance. Carbon 2 hydrogens, can do this job easily.

b) Propanal happens something similar to acetaldehyde, the terminal hydrogen cannot be substracted, and carbon 3, once the hydrogen is gone, the negative charge cannot be stabilized by resonance, so hydrogens of carbon 2 can do this.

c) in the case of acetone, is easier to look because we only have the C = O between two methyl group, so you can use either carbon 1 or 3 to do the job.

d) 4 heptanone the most acidic hydrogen would be carbon 3 or 5, because they are closer to the C=O and the ion can be stabilized by resonance.

e) Finally in ciclopentanone, the most acidic hydrogen would be carbon 2 or 5.

See picture for a better understanding.

Hope it helps.

Answer:

[tex]n_{Al}=6.00molAl\\\\n_{S}=9.00molS\\\\n_{O}=36.0molO[/tex]

Explanation:

Hello!

In this case, when analyzing the moles of an element inside a compound, we need to keep in mind that a mole ratio should be set up; thus, for aluminum sulfate, we have the following ones:

[tex]\frac{2molAl}{1molAl_2(SO_4)_3} \\\\\frac{3molS}{1molAl_2(SO_4)_3} \\\\\frac{12molO}{1mol1molAl_2(SO_4)_3}[/tex]

Thus, starting by 3.00 moles of aluminum sulfate, the moles of each element turn out:

[tex]n_{Al}=3.00molAl_2(SO_4)_3*\frac{2molAl}{1molAl_2(SO_4)_3} =6.00molAl\\\\n_{S}=3.00molAl_2(SO_4)_3*\frac{3molS}{1molAl_2(SO_4)_3} =9.00molS\\\\n_{O}=3.00molAl_2(SO_4)_3*\frac{12molO}{1molAl_2(SO_4)_3}=36.0molO[/tex]

Best regards!

Answer: 5.77 * 10¹⁴s⁻¹

Explanation:

Speed = Frequency * Wavelength

Frequency = Speed/ Wavelength

Speed of light = 3 * 10⁸ m/s

Frequency =  (3 * 10⁸ m/s) / (5.20 x 10⁻⁷m)

= 5.77 * 10¹⁴hz

= 5.77 * 10¹⁴s⁻¹

Answer:

11

Explanation:

Moles of KOH = [tex]10^{-2}[/tex]

Volume of water = 10 liters

Concentration of KOH is given by

[tex][KOH]=\dfrac{10^{-2}}{10}\\\Rightarrow [KOH]=10^{-3}\ \text{M}[/tex]

[tex][KOH][/tex] is strong base so we have the following relation

[tex][KOH]=[OH^{-}]=10^{-3}\ \text{M}[/tex]

[tex]pOH=-\log [OH^{-}]=-\log10^{-3}[/tex]

[tex]\Rightarrow pH=14-3=11[/tex]

So, pH of the solution is 11