A model car is made to a scale of 1:50 (model: real). If the model has a length of 10 cm, calculate the length of the real car (answer in meters).

Answers

Answer 1

Answer:

5 m

Step-by-step explanation:

A model car is made to a scale of 1:50 (model: real).

If the model has a length of 10 cm, calculate the length of the real car (answer in meters).

We have a scale of :

model: real = 1:50

The model has a length of 10cm

Hence:

1 cm = 50 cm

10 cm = x cm

Cross Multiply

x cm × 1cm = 10 cm × 50 cm

x cm = 10 cm × 50 cm/1cm

x cm = 500 cm

The length of the real car is 500cm

Converting the length of the real car to meters

100cm = 1 m

500 cm = x m

Cross Multiply

100cm × x m = 500 cm × 1 m

x m = 500 cm × 1 m/100 cm

x m = 5 m

The Length of the real car in meters is 5m


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Step-by-step explanation:

For this question, you have to first find out whether you are using Sin, Cos or Tan.

To help you find out which one you are using you can use SOH CAH TOA to help you:

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To get the answer you would have to put this in your calculator.

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x = 35, y = 18

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Since both triangles are similar, their sides must be proportional with means all of them have a common ratio.

If NM = 16, and KJ = 40. 40/16 is the ratio from ∆NML to ∆JKL. The reciprocal(numerator and denominator flip, the product of a number and it's reciprocal is 1) of this is true from ∆JKL to ∆NML.

Now to find the missing sides you multiply a side by the common ratio to find it's corresponding side length.

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16/40 can be reduced to 2/5 or 0.4 as a decimal.

Since the scale of ∆JKL is greater than ∆NML, you multiply by 5/2 to get the corresponding side of ∆JKL from ∆NML.

Since the scale of ∆NML is less than ∆JKL, you multiply by 2/5 to get the corresponding side of ∆NNL from ∆JKL.

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The temperature of chicken soup is 192.7°F. As it cools, the temperature of the soup decreases 2.3°F per minute. What is the temperature in degrees Fahrenheit of the soup after 25 minutes?

Answers

Answer: 135.2 °F

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The temperature decreases at a rate of 2.3 °F per minute.

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