Answer:
563.86 N
Explanation:
We know the buoyant force F = weight of air displaced by the balloon.
F = ρgV where ρ = density of air = 1.29 kg/m³, g = acceleration due to gravity = 9.8 m/s² and V = volume of balloon = 4πr/3 (since it is a sphere) where r = radius of balloon = 2.20 m
So, F = ρgV = ρg4πr³/3
substituting the values of the variables into the equation, we have
F = 1.29 kg/m³ × 9.8 m/s² × 4π × (2.20 m)³/3
= 1691.58 N/3
= 563.86 N
Which sentence accurately uses the homophones “they’re,” “there,” or “their”?
Many of the students left there backpacks on the bus.
They’re going to come home as soon as the movie is over.
I think I left the bags of groceries on the floor over their.
These dogs bark at everyone, but there not dangerous at all.
Answer:
They're going to come home as soon as the movie is over.
Answer:
B: They're going to come home as soon as the movie is over.
Explanation:
a u-shaped valley is most often formed by
Answer:
formed by the process of glaciation.
Explanation:
What is the force of gravity between two 40.0kg masses that are separated by 3.00m?
Answer:
[tex]f = g \times \frac{m1 \times m2}{ {d}^{2} } [/tex]
[tex]f = 6.67 \times {10}^{ - 11} \times \frac{40 \times 40}{9} [/tex]
F=1.2x 10^-8Question 2 of 15
When the source of a sound is moving, its speed increases.
A. True
B. False
what force would be required ....
Answer:
Foot
Explanation:
Big toes
Please help I have no idea how to do this
Answer:
So an object with mass is attracted to another object with mass, and the gravitational force is directly proportional to the masses of the two objects, and inversely proportional to the square of the distance between the two objects.
If distance were to increase, than the gravitational force would decrease. If mass were to increase, so would the gravitational force.
Explanation:
Explanation:
Lets take gravitational force(F) and mass(m) and distance (r)
now for a body in contact with the surface of the earth, its mass is also considered(m‘),now the mass of the earth(m") is also considered,then the distance from the body to the center of the earth (r).ie it r because its practically the radius of the earth. is also considered
So by using dimensional analysis ....
we get F a m'•m"/r² ,where a is proportional to.
now since F is directly increaseproportional to m ie. F a m, then an increase in mass of the body increases it's gravitational force(and clearly that makes sense because the bigger you are the stronger you get pulled to the ground)
then we also see that F is inversely proportional to r ie.F a 1/r ,then an increase in the distance between the ground an the object decrease it's gravitational force ( meaning as any object on earth keeps on moving away from the ground the gravitational force between the object and the center of the earth is weak, when it reaches space then the force becomes virtually negligible!)
So to answer the second question, we clearly see that doubling the mass of the body increases the gravitational force between it and the earth
and doubling the distance on the other hand will decrease the attraction between the body and the earth
So a body forcefully projected into the air fights against gravity but its easier as it keeps on getting higher, If it has a greater mass like that of a trail or truck , it will not even probably stay in the air for long , unless its projected with a very high velocity
I hope this helps, and you can ask me any question concerning this via the comments platform.
an ice skater is moving across a flat and level skating rink and is speeding up. which one of the following statement is true of the ice skater
Answer:
where are the statements
Explanation:
What causes coastal erosion
La erosión costera es la pérdida o desplazamiento de tierra, o la remoción a largo plazo de sedimentos y rocas a lo largo de la costa debido a la acción de olas, corrientes, mareas, agua impulsada por el viento, hielo transportado por el agua u otros impactos de marejadas ciclónicas.
a) The velocity with which the basketball is thrown and its time to reach the basket if thrown at angle of 45 degrees.
b) The velocity with which the basketball is thrown and its time to reach the basket if thrown at angle of 60 degrees.
c) The velocity with which the basketball is thrown and its time to reach the basket if thrown at angle of 30 degrees.
Please list the given, find, equations used, and steps to solve.
Answer: I think the answer is b
Explanation:
The total charge a battery can supply is rated in mA⋅hmA⋅h, the product of the current (in mA) and the time (in h) that the battery can provide this current. A battery rated at 1000mA⋅h can supply a current of 1000 mA for 1.0 h, 500 mA current for 2.0 h, and so on. A typical AA rechargeable battery has a voltage of 1.2 V and a rating of 1800mA⋅h. For how long could this battery drive current through a long, thin wire of resistance22Ω?
Answer:
118800 seconds
Explanation:
Given :
Voltage, V = 1.2 V
Resistance, R = 22 Ω
Applying Ohm's law, we get
Voltage, V = IR
Current [tex]$I=\frac{V}{R}$[/tex]
[tex]$I=\frac{1.2}{22}$[/tex]
I = 0.0545 A
Rate = 1800 mAh
Time taken, [tex]$t=\frac{1800 \times 10^{-3}}{0.0545}$[/tex]
= 33 hr
= 118800 s
Two identical R = 6.77 ohm light bulbs are is series circuit
with a 17.8 volt battery. What is the power (watt) of both
glowing bulbs?
Answer:
the power of the two light bulbs is 23.4 W
Explanation:
Given;
the resistance of the two identical light bulbs in series, R₁ and R₂ = 6.77 ohms and 6.77 ohms respectively
battery voltage , V = 17.8 V
The equivalent resistance of the two light bulbs, R = R₁ + R₂
R = 6.77 + 6.77
R = 13.54 ohms
The power of the two light bulbs is calculated as follows;
[tex]P = IV = (\frac{V}{R} )V = \frac{V^2}{R} = \frac{17.8^2}{13.54} = 23.4 \ W[/tex]
Therefore, the power of the two light bulbs is 23.4 W
Suppose a mad scientist went back in time to the beginning of the solar system and caused the newly formed Mars and Venus to switch places. So now there is a Venus-sized planet where Mars was (let's call it Venus 2), and a Mars-sized planet where Venus was (let's call it Mars 2). How would these hypothetical new planets, Mars 2 and Venus 2, turn out in this alternate time line
Answer:
Mars2 illuminated side of the planet is very heat, dark side very cool
Venus 2 a warm planet with a constant temperature across the entire surface
Explanation:
For this hypothetical case, when changing the planets they are changed with their current characteristics.
Case of Mars2
In this case, there is a planet with a very thin atmosphere, so the solar radiation reaches the ground without damping it, causing a lot of noise, so the illuminated side of the planet is very heat and when the dark side turns due to the little atmosphere it loses everything the heat for which it is very cold.
This thermal stress between the two sides of the planet continues constantly creating possible fruit trees in its rocky systems.
Case of Venus 2
The planet has a high atmospheric density, but it is very far from the sun, so the amount of radiation that arrives slightly warms the planet, but due to the thin atmosphere the losses for the dark period are very small, so the entire planet it is heated until it reaches an almost uniform temperature over its entire surface.
In this case we have a warm planet with a constant temperature across the entire surface, regardless of which side is lit.
is this correct and why
Answer:
correct ooooooooooooo
Chromosomes are a form of blood cells.
True
False
............................
(hi if u want brainlist's answer this question then ask another random question on your page so u can give me brainlist back, also i need to people to answer so i can chose one of you guys to give the brainlist's to, deal or no?)
Answer:
false im just trying to get it if you'd like to give it to me
The answer is false :)
T=
Circumference of the earth
Speed/Velocity
.. a =
R
r
Where R = radius of the earth taken as 6.3
above the surface of the earth, g = accelera
acceleration du
velocity of the satellite.
Mv2
y2 v2
= Ma
5) The velocity of light is 3x108m/s. How long does it take a
reach the earth from the sun, which is 1.5x10 m away?
The radius of the moon is (3.65) of the radius of the earth
the acceleration due to gravity of the moon is of that one
earth's surface. Calculate the mass of the moon. (Ans
7.46x1022kg)
Calculate the escape velocity of a satellite from the earth's surface
(G = 6.7x10-11Nm?kg-?, mass of the earth = 6x1024kg and i the
earth's radius = 6.4x10ºm)
A centripetal force of 1N is used to keep a 0.1kg yoyo moving in
horizontal circle of radius 0.7m. What is the yoyo's velocity?
6
Answer:
ummm what the hell
Explanation:
Which of the following is NOT true about a space-based internet system? * Data is transmitted in the form of electromagnetic radiation. Signals travel faster through space than through fiber-optic cables. No ground equipment is needed to access the internet. The network is made of many satellites organized in a grid pattern
Answer:
A Data is transmitted in the form of electromagnetic radiation.
B Signals travel faster through space than through fiber-optic cables.
C No ground equipment is needed to access the internet.
D The network is made of many satellites organized in a grid pattern.
Explanation:
THose are the options
Answer:
B
Explanation:
Which of the following describes an electric conductor?
How much power is required to carry a 35N
package a vertical distance of 18 m if the work on
the package is accomplished in 30 s?
Explanation:
force=35
distance=18
time=30
power=f×d/t
p=35×18/30
p=21
A 175-kg roller coaster car starts from rest at the top of an 18.0-m hill and rolls down the hill, then up a second hill that has a height of 8.0 m. When the car reaches the top of the second hill, its speed is 11 m/s. Determine the work done by non-conservative forces on the car as it travels from the top of the first hill to the top of the second hill.
Answer:
The work done by non-conservative forces on the car from the top of the first hill to the top of the second hill is 6574.75 joules.
Explanation:
By Principle of Energy Conservation and Work-Energy Theorem we present the equations that describe the situation of the roller coaster car on each top of the hill. Let consider that bottom has a height of zero meters.
From top of the first hill to the bottom
[tex]m\cdot g \cdot h_{1} = \frac{1}{2}\cdot m\cdot v_{1}^{2} +W_{1, loss}[/tex] (1)
From the bottom to the top of the second hill
[tex]\frac{1}{2}\cdot m\cdot v_{1}^{2} = m\cdot g \cdot h_{2} + \frac{1}{2}\cdot m \cdot v_{2}^{2}+W_{2,loss}[/tex] (2)
Where:
[tex]m[/tex] - Mass of the roller coaster car, in kilograms.
[tex]v_{1}[/tex] - Speed of the roller coaster car at the bottom between the two hills, in meters per second.
[tex]g[/tex] - Gravitational acceleration, in meters per square second.
[tex]h_{1}[/tex] - Height of the first top of the hill with respect to the bottom, in meters.
[tex]W_{1, loss}[/tex] - Work done by non-conservative forces on the car between the top of the first hill and the bottom, in joules.
[tex]v_{2}[/tex] - Speed of the roller coaster car at the top of the second hill, in meters per seconds.
[tex]h_{2}[/tex] - Height of the second top of the hill with respect to the bottom, in meters.
[tex]W_{2, loss}[/tex] - Work done by non-conservative forces on the car bewteen the bottom between the two hills and the top of the second hill, in joules.
By using (1) and (2), we reduce the system of equation into a sole expression:
[tex]m\cdot g\cdot h_{1} = m\cdot g\cdot h_{2} + \frac{1}{2}\cdot m \cdot v_{2}^{2} + W_{loss}[/tex] (3)
Where [tex]W_{loss}[/tex] is the work done by non-conservative forces on the car from the top of the first hill to the top of the second hill, in joules.
If we know that [tex]m = 175\,kg[/tex], [tex]g = 9.807\,\frac{m}{s^{2}}[/tex], [tex]h_{1} = 18\,m[/tex], [tex]h_{2} = 8\,m[/tex] and [tex]v_{2} = 11\,\frac{m}{s}[/tex], then the work done by non-conservative force is:
[tex]W_{loss} = m\cdot\left[ g\cdot \left(h_{1}-h_{2}\right)-\frac{1}{2}\cdot v_{2}^{2} \right][/tex]
[tex]W_{loss} = 6574.75\,J[/tex]
The work done by non-conservative forces on the car from the top of the first hill to the top of the second hill is 6574.75 joules.
D
If you increase the
frequency of a
wave, what
happens to the
speed?
G
A. It decreases.
B. It stays the same.
C. It increases.
D. It can increase or decrease.
Answer:
D
Explanation:
I think you got it right
0. What is centripetal accleration?Derive relation for it
Answer:
Centripetal acceleration is defined as the property of the motion of an object, traversing a circular path. Any object that is moving in a circle and has an acceleration vector pointed towards the center of that circle is known as Centripetal acceleration. ... Centripetal means towards the center.
Please Help!!!!!
Belinda observes that the reaction 2H2O+O2=2H2O2 appears to have stopped, because the concentrations of reactants and products are not changing. Which statement is true at this point in the reaction
A P E X
Answer: Molecules of H202, H20 and 02 are still forming. ( A P E X )
Explanation: I know this is late but for anyone looking at this later
The above question is incomplete, I think the original question is
Belinda observes that the reaction 2H20+02 2H2O2 appears to have stopped because the concentrations of reactants and products are not changing. Which statement is true at this point in the reaction?
A. Molecules of H₂O₂ are formed only when the reaction vessel is disturbed.
B. Molecules of H2O2 have stopped forming.
C. Molecules of H20 and O₂ have stopped forming.
D. Molecules of H2O2, H2O, and O2 are still forming.
At this point in the reaction, the system has reached a state of equilibrium i.e there is no net change in the concentrations of reactants and products. So the Molecules of H2O2 have stopped forming. The correct option is B.
What is the state of equilibrium?In chemistry, a state of equilibrium refers to a situation where the concentrations of reactants and products in a chemical reaction are no longer changing over time.
This occurs when the rates of the forward and reverse reactions are equal, and there is no net change in the concentrations of reactants and products.
At equilibrium, the system is in a dynamic state, where the forward and reverse reactions continue to occur, but at the same rate, resulting in no overall change in the concentrations of the species involved in the reaction. The equilibrium state is typically characterized by the equilibrium constant, which is a measure of the relative concentrations of reactants and products at equilibrium for a given reaction under specific conditions of temperature, pressure, and concentration.
Here in this question,
The molecules of H2O2 have stopped forming. This means that the forward reaction (2H2O + O2 → 2H2O2) and the reverse reaction (2H2O2 → 2H2O + O2) are occurring at the same rate, resulting in no net change in the concentration of H2O2. However, molecules of H2O and O2 are still being consumed and produced as they are involved in the reaction, but their concentrations are not changing because they are being replenished at the same rate that they are being consumed.
Therefore, the correct answer is B i.e Molecules of H2O2 have stopped forming.
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5. Widely spaced isobars indicate
high winds
winds oriented north to south
light winds
variable winds
Answer:
Light Winds
Explanation:
What is the magnitude of the gravitational force of attraction be-
tween two asteroids in space, each with a mass of 50,000 kg,
separated by a distance of 3800 m?
You are comparing the beam waste for two different situations with the goal of using the smallest beam waste possible. A Nd-YAG laser system emits light at 532 nm and the beam is 8 mm in diameter. You also have a Ti-sapphire laser that emits at 855 nm and has a beam diameter of 6 mm. Compare the beam waist for both laser systems using a focusing lens with a focal length of 10 mm. Assume the light fills the lenses in each case
Answer:
comparing the beam waist for both lasers ( ratio of the beam waists )
4.536 μm / 2.117 μm = 2.14
Explanation:
Nd-YAG laser system : emits at 532 nm , beam diameter = 8 mm
Ti-sapphire laser system : emits at 855 nm , Beam diameter = 6mm
Comparing the beam waist for both lase systems using a focusing lens
Focal length = 10 mm
assumption : light fills lenses in each laser system
Beam waist radius ( W ) = [tex](\frac{2\beta }{\pi } )(\frac{F}{D} )[/tex]
β = wavelength , D = diameter illuminated , F = focal length
For
Nd-YAG laser system
β = 532 mm , D = 8 mm
hence ( Wn ) = [tex](\frac{2\beta }{\pi } )(\frac{F}{D} )[/tex] = ( 2*532 / π ) ( 10 / 8 ) = 2.117 μm
For
Ti-sapphire laser
β = 855 nm , D = 6 mm
hence ( Wt ) [tex](\frac{2\beta }{\pi } )(\frac{F}{D} )[/tex] = ( 2* 855 ) / π ) ( 50 / 6 ) = 4.536 μm
comparing the beam waist for both lasers ( ratio of the beam waists )
4.536 μm / 2.117 μm = 2.14
Imagine you are a crime scene investigator. You are called to investigate a crime scene in a wooded area where a missing person’s body is discovered. When you arrive at the scene, you find that the body is located near a rocky area where the footing in unstable. You also notice that the victim has a large head wound. A particular medium size rock near the body has dried blood on it. Also, a water bottle lies ten feet away from the victim. Write a paragraph about how you would carry out the search for evidence. What evidence would you collect from the crime scene?
Answer:
First I would look for fingerprints on the rock and the water bottle than I would look for footprints and DNA (blood) from the murderer.
Thats aall I could think of ;-;
Answer:
Explanation:
Since the crime scene is located in a wooded area, I would request several more investigators to do a search of the area. These investigators have to spread out to do a line pattern search. While looking for evidence, I would first determine whether the body was moved. I would look for marks on the ground that would suggest that the body was dragged to where it was found. I would collect fingerprint evidence from the water bottle to determine if it was the victim’s or if another person was with the victim. I would also take samples from the clothing to determine if there is any trace evidence, such as hair, foreign fibers, or skin cells. I would collect several rocks from the area, including one with blood on it, as evidence. They would help me determine if the blood-covered rock had been moved, or if it had been used as a weapon.
1. An electron travels 4.82 meters in 0.00360 seconds. What is its average speed?
Answer:
speed =distance /time
speed =4.82/0.00360
speed =1338.8m/s
determine the number of milliliters in a volume of 2.81 fluid ounces
Imagine you have three flashlights. One has a blue light, one has a green light and
one is red. If you were to shine each of those lights in the same spot, what color do
you think you would see? Explain.
Imagine you have three flashlights. One has a blue light, one has a green light and one is red. If you were to shine each of those lights in the same spot, I think i would see white color.
What is the visible spectrum?
At one end of the electromagnetic wave line, which has the group of the visible spectrum. This has been referred to as the visible light of the spectrum. The visible light with the shortest of the wavelength has the blue light and the one with the longest has the red light.
The primary colors of the light has been the spectrum are red, blue, and green. The combination of these colors will form other as well as the colors which has been referred to as the secondary colors. The combination of the beam of the red light and the beam of green light will form yellow color.
Therefore, Imagine you have three flashlights. One has a blue light, one has a green light and one is red. If you were to shine each of those lights in the same spot, I think i would see white color.
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our battery has died and your friends push your vehicle so you can kick-start the engine. You and the vehicle have a combined mass of 1600 kg. If your friends do 6000 J of work and one-third of that is dissipated by friction, how fast is your vehicle traveling?
Answer:2.23 m/s
Explanation:
Given
Mass of person and vehicle is [tex]m=1600\ kg[/tex]
Total work done is [tex]W_t=6000\ J[/tex]
Friction consumes one-third of the energy
The remaining two-third is consumed to increase the kinetic energy
[tex]\Rightarrow \dfrac{2}{3}\times 6000=\dfrac{1}{2}\times 1600\times v^2\\\\\Rightarrow 4000\times 2=1600\times v^2\\\\\Rightarrow v=\sqrt{5}\ \approx 2.23\ m/s[/tex]