A massless string connects a 1.00 kg mass to a 3.00 kg cart which is resting on a frictionless horizontal surface. The mass hangs over a
frictionless pulley. When the mass is released, the cartaccelerates to the right
2.45 m/s2
4.90 m/s
9.80 m/s?
19.6 m/s

Answer:

Multiply the acceleration by time to obtain the velocity change:

Example:

Velocity change = 6.95 * 4 = 27.8 m/s . Since the initial velocity was zero, the final velocity is equal to the change of speed. You can convert units to km/h by multiplying the result by 3.6: 27.8 * 3.6 ≈ 100 km/h

Answer: oceanic crust moved over the hot spot, each recently formed volcano was carried away from the hot spot toward the northwest, cutting off its source of lava. Meanwhile, a new island was forming so that over time a chain of islands was produced extending away from the hot spot.ANSWER HERE: This mean that volcanos are producing these new islands and it is creating a chain of different islands all over Hawaii.

Answer:

Oceanic crust moved over the hot spot, each recently formed volcano was carried away from the hot spot toward the northwest, cutting off its source of lava. Meanwhile, a new island was forming so that over time a chain of islands was produced extending away from the hot spot.

Answer:

54

Explanation:4

4

4

Answer:

30d

Explanation:

30d

Answer:

i have not study it till now

Explanation:

sorry i don't know

Answer:

I. when no net external force act on the system

Explanation:

Suppose you are exerting an external force F on an object, it's velocity keeps increasing. Which means its momentum = velocity * mass is also increasing. In this case the initial momentum of that object is not preserved (but increased).

The planet that Punch should travel to in order to weigh 118 lb is Pentune.

The mass of Punch will be constant in every planet;

[tex]W = mg\\\\m = \frac{W}{g}\\\\m = \frac{236}{g}[/tex]

The acceleration due to gravity of each planet with respect to Earth is calculated by using the following relationship;

[tex]F = mg = \frac{GmM}{R^2} \\\\g = \frac{GM}{R^2}[/tex]

where;

For Planet Tehar;

[tex]g_T =\frac{G \times 2.1M}{(0.8R)^2} \\\\g_T = 3.28(\frac{GM}{R^2} )\\\\g_T = 3.28 g[/tex]

For planet Loput:

[tex]g_L =\frac{G \times 5.6M}{(1.7R)^2} \\\\g_L = 1.94(\frac{GM}{R^2} )\\\\g_L = 1.94g[/tex]

For planet Cremury:

[tex]g_C =\frac{G \times 0.36M}{(0.3R)^2} \\\\g_C = 4(\frac{GM}{R^2} )\\\\g_C = 4 g[/tex]

For Planet Suven:

[tex]g_s =\frac{G \times 12M}{(2.8R)^2} \\\\g_s = 1.53(\frac{GM}{R^2} )\\\\g_s = 1.53 g[/tex]

For Planet Pentune;

[tex]g_P =\frac{G \times 8.3 }{(4.1R)^2} \\\\g_P = 0.5(\frac{GM}{R^2} )\\\\g_P = 0.5 g[/tex]

For Planet Rams;

[tex]g_R =\frac{G \times 9.3M}{(4R)^2} \\\\g_R = 0.58(\frac{GM}{R^2} )\\\\g_R = 0.58 g[/tex]

The weight Punch on Each Planet at a constant mass is calculated as follows;

[tex]W = mg\\\\W_T = mg_T\\\\W_T = \frac{236}{g} \times 3.28g = 774.08 \ lb\\\\W_L = \frac{236}{g} \times 1.94g =457.84 \ lb\\\\ W_C = \frac{236}{g}\times 4g = 944 \ lb \\\\ W_S = \frac{236}{g} \times 1.53g = 361.08 \ lb\\\\W_P = \frac{236}{g} \times 0.5 g = 118 \ lb\\\\W_R = \frac{236}{g} \times 0.58 g = 136.88 \ lb[/tex]

Thus, the planet that Punch should travel to in order to weigh 118 lb is Pentune.

The complete question is below:

Which planet should Punch travel to if his goal is to weigh in at 118 lb? Refer to the table of planetary masses and radii given to determine your answer.

Punch Taut is a down-on-his-luck heavyweight boxer. One day, he steps on the bathroom scale and "weighs in" at 236 lb. Unhappy with his recent bouts, Punch decides to go to a different planet where he would weigh in at 118 lb so that he can compete with the bantamweights who are not allowed to exceed 118 lb. His plan is to travel to Xobing, a newly discovered star with a planetary system. Here is a table listing the planets in that system (find the image attached).

In the table, the mass and the radius of each planet are given in terms of the corresponding properties of the earth. For instance, Tehar has a mass equal to 2.1 earth masses and a radius equal to 0.80 earth radii.

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St. John’s

_________

o0o0o0o0o0

Using Newton's second law

[tex]\\ \sf\Rrightarrow F=ma[/tex]

[tex]\\ \sf\Rrightarrow F=142(30)[/tex]

[tex]\\ \sf\Rrightarrow F=4260N[/tex]

Answer:

1) A 1L bottle, with a height of 30cm, full of water is emptied. The bottle is filled with oil (density = 920 kg/m^3). Calculate the change in pressure of the bottom of the first bottle. If you decide to put potatoes (assume its density is  1,8 kg/m^3), each one of a volume V = 10 cm^3, will they float?

2) The fusion temperature of the Nitrogen is -210°C and its boiling temperature is 77K. Calculate the difference between the fusion temperature and the boiling temperature.

To create a graph of the data you collected during the lab, first, organize the data, then select the best type of graph, and finally create the graph.

One of the steps you need to complete after an experiment is to graph your results. This implies organizing the data and creating a diagram to visually represent your findings.

These are the steps you can follow to complete this task:

Each of these graphs focuses on specific types of data, and therefore you need to select the one that best fits the data you collected.

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The force exerted on the cart 2 during the collision is 2 N.

The given parameters:

According to Newton's third law of motion, action and reaction are equal and opposite. The force exerted on cart 1 is equal in magnitude to the force exerted on cart 2 but in opposite direction.

[tex]F_1 = -F_2[/tex]

[tex]F_2 = -F_1\\\\F_2 = -2 \ N\\\\|F_2| = 2 \ N[/tex]

Thus, the force exerted on the cart 2 during the collision is 2 N.

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We are given –

Sun, r= 1.5×10¹¹ m

We are asked to find the gravitational attraction between the sun and the earth.

[tex]\qquad[/tex] [tex]\pink{\twoheadrightarrow\sf F = \dfrac{GMm}{r²}}[/tex]

Substituting values, we get –

[tex]\qquad[/tex] [tex]\twoheadrightarrow\bf F = \dfrac{6.67×10^{-11}\times 5.98×10^{24}\times 1.99×10^{30}}{(1.5×10^{11})^2}[/tex]

[tex]\qquad[/tex] [tex]\twoheadrightarrow\bf F = \dfrac{6.67×10^{-11}×5.98×10^{24}×1.99×10^{30}}{2.25×10^{22}}[/tex]

[tex]\qquad[/tex] [tex]\twoheadrightarrow\bf F = 35.27×10^{21}[/tex]

[tex]\qquad[/tex] [tex]\pink{\twoheadrightarrow\bf F = 3.53×10^{22} N}[/tex]

______________________________________________

Answer:

the volume changes overtime

sometimes because of weather, temperature ...

Explanation:

Answer:the answer is b

Explanation:

This is because in an ionic bond negative and positive bonds are present

Answer:

the answer is the rollar coster

Explanation:

because the rollar coster is

Answer:

Determine the coordinates of two points on the line. Calculate the difference between these two locations' y-coordinates (rise). Calculate the x-coordinate difference between these two places (run). Divide the y-coordinate difference by the x-coordinate difference (rise/run or slope).

Answer:

The Agricultural Revolution of the 18th century paved the way for the Industrial Revolution in Britain. New farming techniques and improved livestock breeding led to amplified food production. This allowed a spike in population and increased health. The new farming techniques also led to an enclosure movement

Answer:

4.16875×10^-9

Explanation:

given,

mass(M1)=20kg

mass(M2)= 50kg

distance(d)=4m

gravitational constant value (G)=6.67×10^-11

we know,

gravitational force=(Gm1m2)÷d^2

=(6.67×10^-11×20×50)÷4^2

=(6.67×10^-8)÷16

= 4.16875×10^-9

The force winds up unchanged, at 100 N.

Answer:

A quick way of describing density is to describe an object as heavy or light for its size. Pumice stone, unlike regular rock, does not sink in water because it has a low density. An ironwood branch is very dense and sinks in water.

Hope that helps. x

Answer:

Pumice is trapped in gas when the temperature is warm, but as the temp drops, it becomes dense, due to air bubbles. Iron wood is denser than water, thus making it sink.

Explanation:

Answer:

This is the answer that I got.

Explanation:

Just check over it once.

Answer:

A major difference between tangential acceleration and centripetal acceleration is their direction. Centripetal means “center seeking”. ... Tangential acceleration results from the change in magnitude of the tangential velocity of an object. An object can move in a circle and not have any tangential acceleration.

The direction of acceleration is a key distinction between tangential acceleration and centripetal acceleration. Centripetal is defined as "center-seeking." The amount of an object's tangential velocity changes, which causes tangential acceleration. Without experiencing any tangential acceleration, an item can move in a circle.

Acceleration is the rate at which the speed and orientation of a moving object change over time. When a spot or object moves faster or slower along a straight line, it is said to be accelerated. Even though the speed is constant, motion on a circle accelerates so because the direction is always shifting. Both by and to acceleration for all other types of motion.

It is a vector quantity because it has both magnitude and direction.

Any object's rotation experiences tangential acceleration, which is the speed at which the tangential velocity fluctuates. When an object is moving, it behaves in a tangential direction. An object moving in a circle will also experience the very same tangential velocity action.

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Answer:

gravity

Explanation:

keeps the ball down on the surface

When dribbling a ball, the gravity should control the direction and downward motion of the ball.

When a particle is hurled obliquely near the surface of the earth, it travels along a curved path while accelerating continuously in the direction of the planet's centre (we assume the particle stays close to the surface of the globe). Such a particle's motion is known as projectile motion, and its route is referred to as a projectile.

Two distinct rectilinear motions occur simultaneously in a projectile motion:

When a ball is sent into the air at a certain speed, the only force acting on it is the acceleration caused by gravity (g).

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Answer:

6736 J

Explanation:

Knowing that Q = cmΔT:

Q = 4.184 J/(g·°C) · 28.6g · (78.3 °C - 22.0 °C) = 6736 J.

Answer:

Since potential energy increases with increase in the separation distance, Jamal should move the toy car that will create the largest separation distance.  The magnetic force that will act on the vehicles as he moves the cars away from each other will decrease because magnetic force is inversely proportional to the separating distance between the cars.

Explanation:

Since potential energy increases with increase in the separation distance, Jamal should move the toy car that will create the largest separation distance.The magnetic force that will act on the vehicles as he moves the cars away from each other will decrease because magnetic force is inversely proportional to the separating distance between the cars.

Answer:

  5.60 m/s

Explanation:

His initial potential energy is equal to his final kinetic energy.

  mgh = 1/2mv^2

  2gh = v^2 . . . . . . . multiply by 2/m

  v = √(2gh) = √(2(9.81 m/s²)(1.6 m)) = √(31.392 m²/s²)

  v ≈ 5.60 m/s

_____

Additional comment

The mass is irrelevant in the equations we typically use for this purpose.

From the information in the question, the acceleration of the cart is 2.55 ms-2.

We can find the acceleration using the following information from the question;

u = 0.9 m/s

v = 6 m/s

a =  2.0 seconds

But;

a = v - u/t

v = final velocity

u = initial velocity

t = time

a = 6 - 0.9/2 = 2.55 ms-2

Force= ma

m = mass

a = acceleration

F = 6 kg × 2.55 ms-2

F = 15.3 N

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Answer:

112.36 pounds

Explanation:

Since 1 pound = 4.45 Newtons, a 500N child in pounds = 500÷4.45 = 112.36 pounds (approximately).

Answer:

A

Explanation:

earthquakes release energy

Answer:

i think it begins at the epicenter

Explanation:

i can remember

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