A machine is used to fill several bags each of 20-ounces of spicey
chips. After each bag is filled, another machine weighs them. If the
bag weighs .25 less or more than the desired weight, the bag is
rejected. Write an equation to represent the maximum weight for a
bag of chips that the machine will approve.

The operator used in the statement a > b is a comparison operator. In this case, true will be returned if the value of a is greater than the value of b, whereas false if the value of a is less than the value of b.

Code decisions require comparison operators. Comparison operators are used in the statement a > b. Using a and b as variables, it compares their values, returning true if a is greater than b, and false otherwise.

By comparing the values of two variables, the program can make decisions. Coders should understand how comparison operators work since they are used frequently in programming.

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As per the question, the following presumptions need to be true in order to run the binomial test for a population proportion:

a) A simple random sample (SRS) drawn from the population of interest must be used to gather the data. The sample's observations must be unrelated to one another. A binary answer variable is required (i.e., it can only take on two possible values, such as "success" and "failure").

The Central Limit Theorem must be applicable, hence the sample size must be sufficient (i.e., np and nq must both be greater than 5, where p is the proportion of successes in the population and q is the proportion of failures in the population).

From the facts given, it is unclear whether these presumptions are true. In example, it is unclear whether the observations are independent or whether the data was gathered from a straightforward random sample.

b) For this test, the following alternative and null hypotheses are presented:

The actual percentage of female students at ACME University is 0.64, which is null. Alternately, the actual percentage of female students at ACME University is less than 0.64.

c) The p-value must be determined before the binomial test can be run at the = 7% significance level. A statistical software program or a binomial test calculator can be used for this.

The p-value for this test is 0.05309 assuming the binomial test assumptions are met. This suggests that there is a 5.3% chance of generating a sample proportion as little as or smaller than the one seen in the survey if the null hypothesis is true (i.e., the true proportion of women among ACME University students is 0.64).

We can reject the null hypothesis in favor of the alternative hypothesis because the p-value is smaller than the significant level (0.05309 0.07). In other words, we can infer that the actual percentage of female students at ACME University is less than 0.64.

d) Our findings would remain unchanged if the significance criterion was raised to 5%. Because the p-value is still below the significance level (0.05309 0.05), the alternative hypothesis would still be accepted instead of the null hypothesis.

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The 95% confidence interval for the mean tip percentage is (3.49, 4.22)

Confidence interval is the two-sided limit consisting of the lower limit and the upper limit and the value between the two limits is the parameter value.

For this question, we have given a graph of the data, so we only need to see the data and interpret that to answer the question.

First, since confidence interval is 95% so we must see 2.5% limit for two side or equal to 0.025.

For the lower limit, see upper value of dot plot then see separate lowest 0.025 of data is 3.491 or 3.49.

For the upper limit, see lower value of dot plot then see separate highest 0.025 of data is 4.224 or 4.22.

Thus, the 95% confidence interval is (3.49, 4.22) for the mean tip percentage.

Your question is incomplete, but most probably your full question was (image attached)

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please look in down below all in there

Answer: The answer is 27

Answer:

27

Step-by-step explanation:

I hope its helpful to you.

The Arrhenius plot can be used to determine the value of the pre-exponential factor.

The slope of the Arrhenius plot can be used to find the activation energy. The Arrhenius plot can also be used by extrapolating the line back to the y-intercept to obtain the pre-exponential factor. The Arrhenius equation is     k = Ae^(-Ea/RT), where A is the frequency or pre-exponential factor and  e^(-Ea/RT) represents the fraction of collisions that have enough energy to overcome the activation barrier at temperature T.

In chemical kinetics, the pre-exponential factor is the pre-exponential constant in the Arrhenius equation, an empiorical relationship between temperature and rate coefficient. The pre-exponential factor is a constant that can be derived experimentally or numerically. It is also called frequency factor.

In chemical kinetics, an Arrhenius plot displays the logarithm of a reaction rate constant, plotted against reciprocal of the temperature. Arrhenius plots are often used to analyze the effect of temperature on the rates of chemical reactions. Arrhenius plots show that reaction rates are inversely proportional to temperature changes.

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In order to estimate the population proportion within 5%, a sample size of at least 384 is needed.

The number of individuals or observations included in a study is referred to as the sample size. Two statistical properties are influenced by the sample size: 1) The accuracy of our estimates, and 2) The ability to draw conclusions from the study.

This can be calculated using the formula:

n = (z^2 * p * (1-p)) / (e^2)

where z is the z-score corresponding to a 95% confidence level, p is the estimated proportion of people in favor of legalizing marijuana, and e is the margin of error (5%).

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the dimensions will minimize the amount of paper used is with length 4 inch and a width 12 inch.

What is the area of the rectangle?

The area of a rectangle (A) is the product of its length 'a' and width or breadth 'b'. So, Area of Rectangle = (a × b) square units.

We have given

Johnny is designing a rectangular poster to contain 12 in² of printing with a 1-in margin at the top and bottom and a 3-in margin at each side.

Let,

l be the length and w be the width.

Area is A = l * w

Johnny is designing a rectangular poster to contain 12 in² of printing

i.e. Area of the inner printed section 12 = lw  .........(1)

A 1-in margin at the top and bottom and a 3-in margin at each side.

i.e. l'=l+2 and w'=w+6

The total Area of the Poster is

A = (l+2) + (w+6) ...........(2)

Substitute the value of l from (1) in (2),

A = (12/w + 2) (w + 6)

A = 12 + 72/w + 2w + 12

A = 24 + 72/w + 2w

Differentiate w.r.t w,

A' = -72/w² + 2

For critical value put A'=0,

-72/w² + 2 = 0

2 = 72/w²  

w² = 72/2

w² = 36

w = 6

Differentiate again w.r.t w,

A''(w) = 2(72/w²)

A''(6) = 2(72/(6)²)

A''(6) = 2(72/36)

A''(w) = 2*2 = 4>0

It is minimum at w=6.

Substitute in (1),

12 = lw  

l = 2

The dimensions required are

l' = l + 2

= 2+2

= 4 inch

w'=w + 6

= 6 + 6

= 12 inch

Hence, the dimensions will minimize the amount of paper used is with a length 4 inch and a width 12 inch.

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The number of defectives follows binomial distribution with parameters (n,p) and if n>30 then binomial distribution goes to the Normal' approximation.

Given that,

We have to find which of the following approximation approaches is adequate in a test of the equality of the percent defectives from two populations when the sample sizes are big (> 30).

We know that,

The normal curve is roughly followed by the sample distribution of averages or proportions from numerous independent experiments. The population value that corresponds to a sample proportion or average is its expectation.

Therefore, the number of defectives follows binomial distribution with parameters (n,p) and if n>30 then binomial distribution goes to the Normal' approximation.

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The correct options are: Polygon P is similar to polygon P′ and The angle measurements of polygon P are equal to the corresponding angle measurements of polygon P′

The dilation of a figure is enlargement or reduction of its original image to final image by a certain scale factor.

Given that, Polygon P is dilated from the origin by a scale factor other than 1 to create polygon P′

We know that, in dilation, both figures are similar not congruent, because they get enhanced or reduced by a certain scale factor, if scale factor is 1 then they can be congruent also.

Since, both figure are similar, therefore, their corresponding angles are congruent.

Hence, correct options are ; Polygon P is similar to polygon P′ and The angle measurements of polygon P are equal to the corresponding angle measurements of polygon P′.

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No, this sample is not representative of all high school seniors in the US as the sample is selected by an optional web survey, which is not a good sampling technique as non-response bias is introduced.

90% confidence interval for a population proportion.

= 0.55 ± 1.645 *  √0.55(1-0, 55)/1509

= 0.55 ± 0.0211

= (0.5289, 0.5711)

We are 90% confident the true proportion of high school seniors who are fairly certain they will participate in a study abroad program in college lies between 52.89% to 57.11%b

90% confidence means if we select 100 samples, 90 of them will have their sample statistic within the 90% confidence interval. Or otherwise, we can be 90% certain that the population parameter will fall within the 90% confidence interval.

Yes, as the lower limit of the confidence interval is greater than 50%, there is strong evidence to support the claim that the majority of high school seniors are fairly certain that they will participate in a study abroad program in college.

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If f is continous on [a,b], then f attains an absolute maximum value f(c) and absolute minimum value f(d) at some numbers c and d in [a,b] then it is a true statement

What is an absolute maximum?

An absolute maximum point is a point where the function obtains its greatest possible value. Similarly, an absolute minimum point is a point where the function obtains its least possible value.

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According to the image, if U is simply connected, then so V is also simply connected as U and V are conformally equivalent.

If an analytic map f: U V is 1-1 and onto, then two open sets U and V in C are said to be conformally comparable. A conformal equivalence between U and V is the name given to such a f. The conformal equivalence between V and U is then f1(w). A function called conformal mapping, which is defined on the complex plane, changes a given curve or set of points on a plane while keeping each of the curve's angles. For resolving physics and engineering issues with awkward geometries that may be described as functions of a complex variable, conformal mappings are useful. The analyst can change the awkward geometry into a lot more useful one by selecting the right mapping.

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Answer:

O Your friend. If f is a function, then the line is not vertical.

Step-by-step explanation:

If you are given that the equation is a linear function, it can't have any undefined values.

Answer:

Your friend. If ƒ is a function, then the line is not vertical.

Step-by-step explanation:

I just had this question, and I solved it and got it right, see the picture

Answer:

c) 2 2 over 5 = 2 2/5

Step-by-step explanation:

Forming the equation,

→ (1/3)b = 4/5

Now the value of b will be,

→ (1/3)b = 4/5

→ b = (4/5) ÷ (1/3)

→ b = (4/5) × (3/1)

→ b = (4 × 3)/(5 × 1)

→ b = 12/5

→ [ b = 2 2/5 ]

Hence, value of b is 12/5.

A graph which best represents the polynomial function f(x) = (x + 1)(x − 1)(x − 4) is: D. Graph of a cubic polynomial that falls to the left and rises to the right with x intercepts negative 1, 1, and 4. The graph intersects the y axis at a point between 0 and 5.

In Mathematics, a polynomial function can be defined as a mathematical expression which comprises intermediates (variables), constants, and whole number exponents with different numerical value, that are typically combined by using mathematical operations.

This ultimately implies that, a polynomial graph touches the x-axis at zeros, roots, solutions, x-intercepts, and factors with even multiplicities.

In this context, we can reasonably and logically deduce that the zeros of a polynomial function are all of the values (x-intercepts) on the x-coordinate that makes this polynomial function equal to zero and these include the following on a graph:

Zeros = (-1, 0)

Zeros = (1, 0)

Zeros = (4, 0)

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The 4 different types of items will be selected.

What is the combination?

Combinations are mathematical operations that count the number of possible configurations for a set of items where the order of the selection is irrelevant. In combinations, you can select the items in any order.

[tex]nCr = \frac{n!}{(n - r)! \ r!}[/tex]

This formula to find the number of combinations by using r objects from the n objects is also referred as the ncr formula.

so, we have 4 items and a person randomly selects 3.

[tex]nCr = (n, r) = (4, 3)[/tex]

[tex]= \frac{4!}{3!(4 - 3)!}[/tex]

= 4! / 3!

= 4

Hence, The 4 different types of items will be selected.

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The new position of the anchor is 7 1/5 below the surface of the ocean

Initially the anchor is located 15 3/5 m below the surface of the ocean, this is same as = -15 3/5 m

The anchor is further lowered and the position now is

=   -15 3/5 m - 4 1/5 m

= -99 /5 m

Then the anchor is pulled up 12 3/5 m  the new position now is

= -99 /5 m + 12 3/5 m

= -36/5

= -7 1/5

= -7.2

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Answer:

y ≈ 15.9 cm

Step-by-step explanation:

using the tangent ratio in the right triangle

tan53° = [tex]\frac{opposite}{adjacent}[/tex] = [tex]\frac{y}{12}[/tex] ( multiply both sides by 12 )

12 × tan53° = x , that is

x ≈ 15.9 (to 1 decimal place )

If the R is an equivalence relation then for every a and b in set R , if a = b then aRb exists.

If R is an equivalence relation on set A, a and b are in A and [a]=[b]

By the definition of the equivalence relation we can say that R is reflexive

Hence aRa and so by definition of equivalence class a ∈ [a] .

Since [a] = [b] and a ∈ [a] we can say that a ∈ [b] by the definition of set equality.

Now we will use the definition of equivalent class we can say that aRb .

An equivalence relation is a reflexive, symmetric, transitive binary link. The relationship of equipollence between line segments in geometry is one example of an equivalence relation.

Each equivalence relation separates the underlying set into distinct equivalence classes. Two items in the given set are only comparable to one another if and when they belong to the same equivalence class.

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The first is an ordered list of integers, the second is an ordered list of integers, and the third is an unsorted list of texts in JAVA. (Refer to the coding shown below.)

In order to have as few implementation dependencies as feasible, Java is a high-level, class-based, object-oriented programming language.

Java is an object-oriented, cross-platform programming language (OOP).

JavaScript, a scripting language used to build dynamic web pages, should not be confused with it.

Java is one of the most widely used programming languages in the world because of its dependability and simplicity.

So, the generic class needed to compare any kind of data structure is created by the Java code that follows.

Both integers and strings were employed in three different test situations.

The first is a list of integers in ascending order, the second is a list of integers in descending order, and the third is a list of texts that are not sorted.

The image below that is attached shows the results.

import java.util.Scanner;

class Brainly {

  public static void main(String[] args) {

      Scanner in = new Scanner(System.in);

      System.out.println("Order: " + checkOrder(10, 22, 51, 53));

      System.out.println("Order: " + checkOrder(55, 44, 33, 22));

      System.out.println("Order: " + checkOrder("John", " Gabriel", "Daniela", "Zendaya"));

  }

  public static <E extends Comparable<E>> int checkOrder(E var1, E var2, E var3, E var4) {

      E prevVar = var1;

      if (var2.compareTo(prevVar) > 0) {

          prevVar = var2;

      } else {

          if (var3.compareTo(prevVar) < 0) {

              prevVar = var3;

          } else {

              return 0;

          }

          if (var4.compareTo(prevVar) < 0) {

              return 1;

          }  else {

              return 0;

          }

      }

      if (var3.compareTo(prevVar) > 0) {

          prevVar = var3;

      }

      if (var4.compareTo(prevVar) > 0) {

          return -1;

      }

      return 0;

  }

}

Therefore, the first is an ordered list of integers, the second is an ordered list of integers, and the third is an unsorted list of texts in JAVA. (Refer to the coding shown below.)

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A test's standard deviation is 5 and its mean is 85. scores is within one standard deviation of the mean is 25/n^12.

The square root of the variance of a random variable, sample, mean ,statistical population, data set, or probability distribution is that variable's standard deviation. Although less robust in practice, it is algebraically simpler than the average absolute deviation.The fact that the standard deviation is expressed in the same unit as the data, as opposed to the variance, is a useful characteristic of the statistic.

variance = 5^2 = 25

standard deviation of the mean = ( variance / n )^1/2

= (25/n)^1/2

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The percentage error is 8.3%

A percentage is a portion of a whole expressed as a number between 0 and 100 rather than as a fraction.

Given that, Akira is redecorating her bedroom. She misread the markings on her ruler and thought a picture frame she bought was 5.2 centimetres wide. The frame's actual width was 4.8 centimetres.

Percentage Error = ((Estimated Number – Actual Number)/ Actual number) x 100.

= (5.2-4.8)/4.8x100 = 8.3%

Hence, The percentage error is 8.3%

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The system of equation - 7x + y = 19 and - 2x + 3y = - 9 have solution at

(-101/9, -3318/19).

If a system of equations only contains two linear equations with two variables, the system's equation can be graphed, the graph will have two straight lines, and the intersection point(s) of those lines will be the system's solution.

There are only three matching forms of solution for a given system of equations because there are only three different ways that two straight lines in the plane can graph.

Given, A system of equations - 7x + y = 19 and - 2x + 3y = - 9.

Now, multiplying eqn(i) by 2 and eqn(ii) by 7 we get,

- 14x + 2y = 38...(iii) and - 14x + 21y = - 63...(iv)

Now, subtracting eqn(iii) from eqn(iv) we get,

 (- 14x + 21y = - 63)

- (- 14x + 2y = 38)

_______________

           19y = - 101.

               y = - 101/19

and putting the value of y in eqn(iv) we get x = - 3318/19.

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The expression that has a value of 40 when x = 10.8. is (C) (x² ÷ 18) + 33.52

The complete question is added at the end of this solution

From the question, we have the following expressions that can be used in our computation:

A 4,320 ÷ x

B 288/x + 16

C (x² ÷ 18) + 33.52

D (1,752 ÷ x) – 162/29

F x/12 + 36

The value of x is given as

x = 10.8

So, we evaluate the expressions at this value of x

Expression A: 4,320 ÷ x

4,320 ÷ 10.8 = 400 --- false

Expression B 288/x + 16:

288/10.8 + 16 = 42.7 --- false

Expression C (x² ÷ 18) + 33.52:

(10.8² ÷ 18) + 33.52 = 40 --- true

Expression D (1,752 ÷ x) – 162/29:

(1,752 ÷ 10.8) – 162/29 = 156.6 --- false

Expression F x/12 + 36:

10.8/12 + 36 = 36.9 --- false

Hence, the only expression is (x² ÷ 18) + 33.52

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Complete question

Select all the expressions that have a value of 40 when x = 10.8.

A 4,320 ÷ x

B 288/x + 16

C (x² ÷ 18) + 33.52

D (1,752 ÷ x) – 162/29

F x/12 + 36

The correct answer for the question that is being presented above is this one: "D.The distributions are somewhat similar; C.The distributions are similar." Data Set 1 has a mean of 84 and a MAD of 6. Data Set 2 has a mean of 78 and a MAD of 8. You conclude about the two distributions: .The distributions are somewhat similar; The distributions are similar.

Answer:

Step-by-step explanation:

(3, 12721) and (5,10835)

(10835 -12721) - (5-3)

-1886/2 = -943

Answer:

It would be the third option, because the square root of 85 is 9.22, and 28/3 is 9.33 repeated.

Hope this helps, have a great day! :D

Step-by-step explanation:

The hose will take 28.27 minutes to fill the second aquarium.

Given,

Rectangular Aquarium - 1

Length = 12 inches

Width = 13 inches

Height = 14 inches

Time taken by a hose to fill the aquarium = 3 minutes

Rectangular Aquarium - 2

Length = 21 inches

Width = 28 inches

Height = 35 inches

We have to find the time taken by the same hose to fill the aquarium 2.

Volume of Aquarium 1 = length × width × height

= 12 × 13 × 14 = 2184 inch³

To fill 2184 inch³, the hose will take 3 minutes.

Now,

Volume of Aquarium 2 = length × width × height

= 21 × 28 × 35 = 20580 inch³

Here,

The time taken by the hose to fill a volume of 20580 inch³;

= 3 × 20580 / 2184 = 28.27 minutes

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Answer: 11.9 pounds

Step-by-step explanation:

142.5 - 130.6 = 11.9