Answer:
A graph with a slope of -1, and a y-intercept (crosses the y-axis) at 3
I NEED HELP ASAP choose one of the multiple choice
Answer:
B. Square both sides of the equation.
Step-by-step explanation:
You cannot do anything to the equation unless you square both sides to eliminate the square root on the left (squaring each individual term of the equation does not help; you need to square the entire square root to eliminate it).
Hope this helps!
A new cola company is testing to see what proportion of their cans contain at least 12 oz. If they want to be within 3% of the actual percentage, how many cans should they measure to be 90% confident
Answer: 752
Step-by-step explanation:
Given that,
Margin of error = 3% = 0.03
confidence level = 90% = 0.90
therefore from the z-table
z = 1.645
Now since no prior estimate of p is given, so we say p = 0.5
Sample size required will be
n = 1.645² × 0.5 ×(1-0.5) / 0.03² = 751.67
n = 751.67 ≈ 752
You are tossing a coin, then rolling a die, then drawing a card from a deck of cards. What is the probability that you will get: a tail AND an even number on the die AND a card less than 5 (assume the ace is equal to 1) from the deck?
[tex]|\Omega|=2\cdot6\cdot52=624\\|A|=1\cdot3\cdot16=48\\\\P(A)=\dfrac{48}{624}=\dfrac{1}{13}[/tex]
Answer:
1/13
Step-by-step explanation:
20 points! Brainliest will be given!
Answer:
I always factor out the -1 so my leading coefficient is 1
Step-by-step explanation:
-x^2 + 10x -24
I always factor out the -1 so my leading coefficient is 1
-1 ( x^2 -10x +24)
Then what 2 terms multiply to 24 and add to -10
-6*-4 = 24
-6+-4 = -10
-1( x-6)(x-4)
An appliance company determines that in order to sell x dishwashers, the price per dishwasher must be p = 420 - 0.3x. It also determines that the total cost of producing x dishwashers is given by C(x) = 5000 + 0.3x2. How many dishwashers must the company produce and sell in order to maximize profit? g
The company must produce and sell 350 dishwashers in order to maximize profit.
How to determine the number of dishwashersTo determine the number of dishwashers the company must produce and sell in order to maximize profit, we need to find the value of x that corresponds to the maximum point of the profit function.
The profit (P) is given by the equation:
P(x) = Revenue - Cost
The revenue is calculated by multiplying the price per dishwasher (p) by the number of dishwashers sold (x):
Revenue = p * x
The cost is given by the function C(x):
Cost = C(x)
Therefore, the profit function can be expressed as:
P(x) = p * x - C(x)
Substituting the given expressions for p and C(x):
P(x) = (420 - 0.3x) * x - (5000 + 0.3x²)
Expanding and simplifying the equation:
P(x) = 420x - 0.3x² - 5000 - 0.3x²
Combining like terms:
P(x) = -0.6x² + 420x - 5000
To find the value of x that maximizes profit, we need to find the vertex of the quadratic function. The x-coordinate of the vertex can be determined using the formula:
x = -b / (2a)
In our case, a = -0.6 and b = 420:
x = -420 / (2 * -0.6)
x = -420 / (-1.2)
x = 350
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350 dishwashers must the company produce and sell in order to maximize profit.
Maxima means a point at which the function attains the maximum value.
Given the following information:
Price per dishwasher, p = 420 - 0.3x
Total cost of producing x dishwashers, C(x) = 5000 + 0.3x2
Profit= Total Selling price- Total Cost Price
Total Selling price of x dishwasher, S.P= xp
S.P=x(420 - 0.3x)
S.P=420x - 0.3x²
Profit= 420x - 0.3x² - ( 5000 + 0.3x²)
Profit= 420x - 0.3x² - 5000 - 0.3x²
Profit= -0.6x²+420x-5000
So, profit, f(x)=-0.6x²+420x-5000
To determine the value of x so that maximum profit is possible:
1. Calculate the first derivative of profit function and calculate the value of x by equating it to zero.
2. Select that value of x for which the profit function attains the maximum value, to check the maxima calculate 2nd derivative, if it gives a negative value for the value of x. Then, x is the point of maxima for the given function.
[tex]f(x)=-0.6x^2+420x-5000\\f\prime(x)=-1.2x+420\\f\prime(x)=0\\-1.2x+420=0[/tex]
Calculating the value of x by transposing,
x=420/1.2
x=350
To check maxima, calculating second derivative.
[tex]f\prime(x)=-1.2x+420=0\\f\prime\prime(x)=-1.2[/tex]
2nd derivative is negative, it means that x=350 is the point of maxima.
Thus, a company must produce and sell 350 dishwashers in order to maximize profit.
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The owner of a music store gathered data from several schools about the number of students in their concert and marching bands. The scatter plot shows the data she gathered and the line of best fit. The equation of the line of best fit is y = 0.677x + 1.77. Based on the line of best fit, approximately how many students are predicted to be in the marching band at a school with 35 students in the concert band?
Answer:
25 students
Step-by-step explanation:
Given the equation of the best line of fit, [tex] y = 0.677x + 1.77 [/tex] , the number of students predicted to be in the matching band, if we have 35 students in the concert band, can be approximated by plugging in 35 as "x" in the equation of the best line of fit, and solve for "y". y would give us the predicted number of students to expect in the marching band.
[tex] y = 0.677(35) + 1.77 [/tex]
[tex] y = 23.695 + 1.77 [/tex]
[tex] y = 25.465 [/tex]
The approximated number of to be in the marching band, with 35 students in the concert band is roughly 25 students.
Answer:25 students
Step-by-step explanation:
4x + 12 = 20y Solve for x.
Answer:
x=5y-3
Step-by-step explanation:
[tex]4x+12=20y\\4x=20y-12\\x=\frac{20y-12}{4} \\x=\frac{20y}{4}- \frac{12}{4} \\x=5y-3[/tex]
help i will give you brailenst
Please help I am doing test ! A woman borrows $4,000 at 9% compounded monthly, which is to be amortized over 3 years in equal monthly payments. for tax purposes, she needs to know the amount of interest paid during each year of the loan. find the interest paid during the first year, the second year, and the third year of the loan. [hint: find the unpaid balance after 12 payments and after 24 payments.
Answer:
Monthly Loan Payment
Loan Amount (P) = $6,000
Monthly Interest Rate (n) = 0.75% per month [9.00% / 12 Months]
Number of months (n) = 36 Months [3 Years x 12 months]
Monthly Loan Payment = [P x {r (1+r)n} ] / [( 1+r)n – 1]
= [$6,000 x {0.0075 x (1 + 0.0075)36}] / [(1 + 0.0075)36 – 1]
= [$6,000 x {0.0075 x 1.308645}] / [1.308645 – 1]
= [$6,000 x 0.009815] / 0.308645
= $58.89 / 0.308645
= $190.80
Monthly Loan Amortization Schedule
“Therefore, the total interest paid during the first year will be $465.99”
HOPE this example helps
What expression be used to add 3/4 + 1/6
Answer:
11 / 12 or 0.9167
Step-by-step explanation:
Given:
3/4 + 1/6
Find:
Value with expression
Computation:
"3/4 added to number 1/6"
3/4 + 1/6
By taking LCM
[9 + 2] / 12
11 / 12 or 0.9167
A housepainter mixed 3 1/2 pints of blue paint in a bucket with 1 1/6 pints of white paint. How much paint was in the bucket? The answer should be written as a proper mixed number and should be simplified, if possible.
Answer:
4 2/3 :)
Step-by-step explanation:
The total paint in the bucket in the simplified mixed fraction is [tex]6\frac{2}{3}[/tex] pints.
What is a fraction?A fraction is written in the form of p/q, where q ≠ 0.
Fractions are of two types they are proper fractions in which the numerator is smaller than the denominator and improper fractions where the numerator is greater than the denominator.
Given, A housepainter mixed [tex]3\frac{1}{2}[/tex] pints of blue paint in a bucket with [tex]1\frac{1}{6}[/tex] pints of white paint.
So, The total paint in the bucket is the sum of the pints of both paints which
is, = [tex](3\frac{1}{2} + 1\frac{1}{6})[/tex] pints.
[tex]= (\frac{7}{2} + \frac{7}{6})[/tex] pints.
[tex]= \frac{21 + 7}{6}[/tex] pints.
[tex]= \frac{28}{6}[/tex] pints.
[tex]= 6\frac{2}{3}[/tex] pints.
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Which presents a quadratic function
Answer:
The answer is option 2.
Step-by-step explanation:
Quadratic function is always written in the form of ax² + bx + c where the highest power of x is 2.
In the options above :
Option 1 is Cubic function.
Option 2 is Quadratic function.
Option 3 and 4 are Linear function.
Answer:
I guess....
Step-by-step explanation:
option 2............
A firm has the marginal-demand function Upper D prime (x )equalsStartFraction negative 1200 x Over StartRoot 25 minus x squared EndRoot EndFraction . Find the demand function given that Dequals16 comma 000 when x equals $ 4 per unit.
Answer:
The demand function is [tex]\mathbf{D(x) = 1200(\sqrt{25-x^2})+ 124000}[/tex]
Step-by-step explanation:
A firm has the marginal-demand function [tex]D' x = \dfrac{-1200}{\sqrt{25-x^2 } }[/tex].
Find the demand function given that D = 16,000 when x = $4 per unit.
What we are required to do is to find the demand function D(x);
If we integrate D'(x) with respect to x ; we have :
[tex]\int\limits \ D'(x) \, dx = \int\limits{\dfrac{-1200 x}{\sqrt{25-x^2}} } \, dx[/tex]
[tex]D(x) = \int\limits{\dfrac{-1200 x}{\sqrt{25-x^2}} } \, dx[/tex]
Let represent t with [tex]\sqrt{25-x^2}}[/tex]
The differential of t with respect to x is :
[tex]\dfrac{dt}{dx}= \dfrac{1}{2 \sqrt{25-x^2}}}(-2x)[/tex]
[tex]\dfrac{dt}{dx}= \dfrac{-x}{ \sqrt{25-x^2}}}[/tex]
[tex]{dt}= \dfrac{-xdx}{ \sqrt{25-x^2}}}[/tex]
replacing the value of [tex]\dfrac{-xdx}{ \sqrt{25-x^2}}}[/tex] for dt in [tex]D(x) = \int\limits{\dfrac{-1200 x}{\sqrt{25-x^2}} } \, dx[/tex]
So; we can say :
[tex]D(x) = \int\limits{\dfrac{-1200 x}{\sqrt{25-x^2}} } \, dx[/tex]
[tex]D(x) = 1200\int\limits{\dfrac{- x}{\sqrt{25-x^2}} } \, dx[/tex]
[tex]D(x) = 1200\int\limits \ dt[/tex]
[tex]D(x) = 1200t+ C[/tex]
Let's Recall that :
t = [tex]\sqrt{25-x^2}}[/tex]
Now;
[tex]\mathbf{D(x) = 1200(\sqrt{25-x^2}})+ C}[/tex]
GIven that:
D = 16,000 when x = $4 per unit.
i.e
D(4) = 16000
SO;
[tex]D(x) = 1200(\sqrt{25-x^2}})+ C[/tex]
[tex]D(4) = 1200(\sqrt{25-4^2}})+ C[/tex]
[tex]D(4) = 1200(\sqrt{25-16}})+ C[/tex]
[tex]D(4) = 1200(\sqrt{9}})+ C[/tex]
[tex]D(4) = 1200(3}})+ C[/tex]
16000 = 1200 (3) + C
16000 = 3600 + C
16000 - 3600 = C
C = 12400
replacing the value of C = 12400 into [tex]\mathbf{D(x) = 1200(\sqrt{25-x^2}})+ C}[/tex], we have:
[tex]\mathbf{D(x) = 1200(\sqrt{25-x^2})+ 124000}[/tex]
∴ The demand function is [tex]\mathbf{D(x) = 1200(\sqrt{25-x^2})+ 124000}[/tex]
f(x)=2x+1 and g(x)=3x2+4, find (f∘g)(−2) and (g∘f)(−2).
Answer:
Step-by-step explanation:
Fog=2(g)+1
2(3x+2+4)+1
2{3x+6)+1
6x+12+1
=6x+13
Fog(-2)=6(-2)+13
-12+13
=1
Gof=3(f)+2+4
=3(2x+1)+6
6x+3+6
=6x+9
Gof(-2)=6(-2)+9
-12+9
=-3
A casino offers a game wherein a player can roll one six sided die. If the player rolls a 1or 2, they
win. If the player rolls a 3, 4, 5, or 6, they lose. If a player bets $2.00 and wins, they will be paid out
an additional $3.00. If they lose, they lose their initial $2.00. Find the expected value of the $2.00
bet.
Enter your answer rounded to the nearest cent and don't forget, expected values can be negative!
Answer:
Expected Value of $2:
Expected Value of $2:
Win, 0.3333 x $3 = $1
Plus
Loss, 0.6667 x -$2 = -$1.33
Expected value = ($0.33)
Step-by-step explanation:
Probability of a win = 2/6 = 0.3333
Probability of a loss = 4/6 = 0.6667
Expected Value of $2:
Win, 0.3333 x $3 = $1
Plus
Loss, 0.6667 x -$2 = -$1.33
Expected value = ($0.33)
The casino game player's expected value is computed by multiplying each of the possible outcomes by the likelihood (probability) of each outcome and then adding up the values. The sum of the values is the expected value, which amounts to a loss of $0.33.
A committee consists of 8 men and 11 women. In how many ways can a subcommittee of 3 men and 5 women be chosen?
Answer:
25872 ways
Step-by-step explanation:
We're choosing 5 women from a group of 11 and 3 men from a group of 8. We don't care about what order they are picked and so we'll use the combination formula, which is:
n!/(k!)(n-k)! with n as population and k as picks.
We'll multiply the results together. (8! / (3!)(8-3)!) * (11! / (5!)(11-5)!)
That equals: (8! / (3!)(5!) ) * (11! / (5!)(6!)) = 40320/(6x120) * 39916800/ (120x720)
56 * 462 = 25872
Which of the following equations is equivalent to 4/5a - 8 = 1/5?
Answer:
a = 10 1/4
Step-by-step explanation:
So with the following equation,
4/5a - 8 = 1/5,
we need to use the commutative property.
Which is the moving of whole numbers or variables.
So we add 8 to both sides.
4/5a = 41/5
Divide 4/5 by both sides
a = 10 1/4
So on of the equations could look like a = 10 1/4
Thus,
a = 10 1/4 could be one of the equations given which are equal to 4/5a - 8 = 1/5.
Hope this helps :)
Answer:
[tex]\huge\boxed{a=\dfrac{41}{4}=10\dfrac{1}{4}=10.25}[/tex]
Step-by-step explanation:
[tex]\dfrac{4}{5}a-8=\dfrac{1}{5}\qquad\text{multiply both sides by 5}\\\\5\!\!\!\!\diagup\cdot\dfrac{4}{5\!\!\!\!\diagup}a-(5)(8)=5\!\!\!\!\diagup\cdot\dfrac{1}{5\!\!\!\!\diagup}\\\\4a-40=1\qquad\text{add 40 to both sides}\\\\4a-40+40=1+40\\\\4a=41\qquad\text{divide both sides by 4}\\\\\dfrac{4a}{4}=\dfrac{41}{4}\\\\a=10.25[/tex]
A special tool manufacturer has 50 customer orders to fulfill. Each order requires one special part that is purchased from a supplier. However, typically there are 2% defective parts. The components can be assumed to be independent. If the manufacturer stocks 52 parts, what is the probability that all orders can be filled without reordering parts
Answer:
0.65463
Step-by-step explanation:
From the given question:
It is stated that 2% of the parts are defective (D) out of 50 parts
Therefore the probability of the defectives;
i.e p(defectives) = [tex]\dfrac{N(D)}{N(S)}[/tex]
p(defectives) = [tex]\dfrac{2}{50}[/tex]
p(defectives) = 0.04
The probability of the failure is the P(Non-defectives)
p(Non-defectives) = 1 - P(defectives)
p(Non-defectives) = 1 - 0.04
p(Non-defectives) = 0.96
Also , Let Y be the number of non -defective out of the 52 stock parts.
and we need Y ≥ 50
P( Y ≥ 50) , n = 52 , p = 0.96
P( Y ≥ 50) = P(50 ≤ Y ≤ 52) = P(Y = 50, 51, 52)
= P(Y = 50) + P(Y =51) + P(Y=52) (disjoint events)
P(Y = 50) = [tex](^{52}_{50}) ( 0.96)^{50}(1-0.96)^2[/tex]
[tex]P(Y = 50) = 1326 (0.96)^{50}(0.04)^2[/tex]
P(Y = 50) = 0.27557
P(Y = 51) =[tex](^{52}_{51}) ( 0.96)^{51}(1-0.96)^1[/tex]
[tex]P(Y = 51) = 52(0.96)^{51}(0.04)^1[/tex]
P(Y = 51) = 0.25936
(Y = 52) =[tex](^{52}_{52}) ( 0.96)^{52}(1-0.96)^0[/tex]
[tex]P(Y = 52) = 1*(0.96)^{52}(0.04)^0[/tex]
P(Y = 52) = 0.1197
∴
P(Y = 50) + P(Y =51) + P(Y=52) = 0.27557 + 0.25936 + 0.1197
P(Y = 50) + P(Y =51) + P(Y=52) = 0.65463
Shawn has 25 coins, all nickels and dimes. The total value is $2.00. How many of each coin does he have ?
Answer:
[tex]\boxed{15 \ dime \ and \ 10 \ nickel \ coins}[/tex]
Step-by-step explanation:
1 dime = 10 cents
1 nickel = 5 cents
So,
If there are 15 dimes
=> 15 dimes = 15*10 cents
=> 15 dimes = 150 cents
=> 15 dimes = $1.5
Rest is $0.5
So, for $0.5 we have 10 nickels coins
=> 10 nickels = 10*5
=> 10 nickels = 50 cents
=> 10 nickel coins = $0.5
Together it makes $2.00
Find the area of the shaded region.
Answer:
The answer would be 27π
Step-by-step explanation:
the area is 36pi and the shaded region is 3/4 of the circle, as a 90 degree angle is 1/4 of a 360 degree circle. 3/4 of 36pi is 27pi
Answer:
27π
Step-by-step explanation:
Imagine that this circle was complete. As you can see, only 3 / 4th of the circle remains, with respect to this whole circle. This is not an assumption, though it does appear so. The portion missing forms a right angle with the radii, and thus by definition, that portion is a quarter of a circle.
________
The simplest approach is to assume this circle to be complete, and solve for that area - provided the radii being 6 inches. Afterward we can take 3 / 4th of this area, solving for the area of the shaded region. After all, this circle is 3 / 4ths of our " complete circle. "
Area of an Imaginary " Complete Circle " = π[tex]r^2[/tex] = π[tex](6)^2[/tex] = 36π,
Area of Shaded Region ( 3 / 4th of the " Complete Circle " ) = [tex]\frac{3}{4}[/tex]( 36π ) = 27π
27π is the exact area of the shaded region. If you want an approximated area, take π as 3.14, or a similar quantity to that.
Tabitha wants to hang a painting in a gallery. The painting and frame must have an area of 58 square feet. The painting is 7 feet wide by 8 feet long. Which quadratic equation can be used to determine the thickness of the frame, x? (5 points)
Answer:
4x² + 30x - 2 = 0
Step-by-step explanation:
Given:
Area = 58 square feet
Width = 7 feet
Length = 8 feet
Since the area is 58, writing the equation, we have:
(8 + 2x)(7 + 2x) = 58
Now expand the equation:
56 + 16x + 14x + 4x² = 58
56 + 30x + 4x² = 58
Collect like terms:
30x + 4x² + 56 - 58 = 0
30x + 4x² - 2 = 0
Rearrange the equation to a proper quadratic equation:
4x² + 30x - 2 = 0
The quadratic equation that can be used to determine the thickness of the frame, x is 4x² + 30x - 2 = 0
The height of a cylinder is 9.5 cm. The diameter is 1.5 cm longer than the height. Which is closest to the volume of the cylinder?
Answer:
853.8cm^3
Step-by-step explanation:
[tex]h = 9.5cm\\d = 1.5cm + 9.5 = 10.7\\r =d/2=10.7/2=5.35\\\\V = \pi r^2 h\\V = 3.14 \times (5.35)^2 \times 9.5\\\\V =853.8 cm^3[/tex]
A word is anything of seven letters of the alphabet(26 letters) (no space in between). Repeated lettersare allowed. How many words are there?
Answer:
26^7=8 031 810 176
Step-by-step explanation:
The word has 7 letters. So the word have 7 places where any of 26 letters can be placed.
Any of 26 letters can stay at 1st place
Any of 26 letters can stay at 2-nd place (because letters can be repeated)
Any of 26 letters can stay at 3rd place
Any of 26 letters can stay at 4th place
Any of 26 letters can stay at 5th place
Any of 26 letters can stay at 6th place
Any of 26 letters can stay at 7th place
So N= 26*26*26*26*26*26*26=26^7=8 031 810 176
Intelligence quotients (IQs) measured on the Stanford Revision of the Binet Simon Intelligence Scale are normally distributed with a mean of 100 and a standard deviation of 16. Determine the percentage of people who have an IQ between 115 and 140.
Answer:
the percentage of people who have an IQ between 115 and 140 is 16.79%
Step-by-step explanation:
From the information given:
We are to determine the percentage of people who have an IQ between 115 and 140.
i.e
P(115 < X < 140) = P( X ≤ 140) - P( X ≤ 115)
[tex]P(115 < X < 140) = P( \dfrac{X-100}{\sigma}\leq \dfrac{140-100}{16})-P( \dfrac{X-100}{\sigma}\leq \dfrac{115-100}{16})[/tex]
[tex]P(115 < X < 140) = P( Z\leq \dfrac{140-100}{16})-P( Z\leq \dfrac{115-100}{16})[/tex]
[tex]P(115 < X < 140) = P( Z\leq \dfrac{40}{16})-P( Z\leq \dfrac{15}{16})[/tex]
[tex]P(115 < X < 140) = P( Z\leq 2.5)-P( Z\leq 0.9375)[/tex]
[tex]P(115 < X < 140) = P( Z\leq 2.5)-P( Z\leq 0.938)[/tex]
From Z tables :
[tex]P(115 < X < 140) = 0.9938-0.8259[/tex]
[tex]P(115 < X < 140) = 0.1679[/tex]
Thus; we can conclude that the percentage of people who have an IQ between 115 and 140 is 16.79%
Using the normal distribution, it is found that 82.02% of people who have an IQ between 115 and 140.
Normal Probability DistributionIn a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
It measures how many standard deviations the measure is from the mean. After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.In this problem:
The mean is of [tex]\mu = 100[/tex].The standard deviation is of [tex]\sigma = 15[/tex].The proportion of people who have an IQ between 115 and 140 is the p-value of Z when X = 140 subtracted by the p-value of Z when X = 115, hence:
X = 140:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{140 - 100}{16}[/tex]
[tex]Z = 2.5[/tex]
[tex]Z = 2.5[/tex] has a p-value of 0.9938.
X = 115:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{115 - 100}{16}[/tex]
[tex]Z = -0.94[/tex]
[tex]Z = -0.94[/tex] has a p-value of 0.1736.
0.9938 - 0.1736 = 0.8202.
0.8202 = 82.02% of people who have an IQ between 115 and 140.
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The number of times a player has golfed in one's
lifetime is compared to the number of strokes it takes
the player to complete 18 holes. The correlation
coefficient relating the two variables is 0.26.
Which best describes the strength of the correlation,
and what is true about the causation between the
variables?
It is a weak negative correlation, and it is not likely
causal.
O It is a weak negative correlation, and it is likely
causal.
O It is a strong negative correlation, and it is not likely
causal.
O It is a strong negative correlation, and it is likely
causal.
Answer:
It is a weak negative correlation, and it is likely causal.
Step-by-step explanation:
Correlation coefficient can be said to be a statistical value that shows the relationship between two variables.
Here, the correlation coefficient is 0.26 which means that the magnitude of correlation is low and it causes a weak correlation.
Here, since one variable increases as the other variable decreases, the correlation is said to be negative and weak. We can see that the more a player golf's, the lower the number to required strokes. This would result in a negative slope.
Therefore, It is a weak negative correlation, and it is likely
causal.
Answer:
The correct answer is B on edge 2020.
Step-by-step explanation:
ANZ Corporation manufactures a product available in two models: ABC, and PQR. Despite the growing popularity of the PQR model, company profits have been declining steadily, and management is beginning to think there might be a problem with their costing system. Material and Labour costs are given below:
ABC PQR
Sales demand 30000 15000
Direct material cost/unit $45 $60
Direct labour cost/unit $30 $40
Production overheads are $600,000 each month.
These are absorbed on a sales demand basis.
Calculate the full production costs for ABC and PQR, using traditional costing method
Answer:
The full production costs are:
ABC = $22,900,000
PQR = $1,700,000
Step-by-step explanation:
Traditional costing method is a costing method that allocates or applies overhead based on a particular metric determined by a company. It therefore add both direct cost of production and production overheads absorbed to obtain the full cost of production.
Since production overheads in this question is absorbed on demand sales basis, the full production costs for ABC and PQR can be computed as follows:
ANZ Corporation
Computation of Full Production Costs
Particulars ABC PQR
Sales demand 30,000 15,000
Cost $ $
Direct cost:
Direct materials cost (w.1) 1,350,000 900,000
Direct labor cost (w.2) 900,000 600,000
Total direct cost 22,500,000 1,500,000
Indirect cost:
Production overhead (w.3) 400,000 200,000
Full production cost 22,900,000 1,700,000
Workings:
w.1: Computation of direct material cost
Direct material cost = Direct material cost per unit * Sales demand
Therefore;
ABC Direct material cost = $45 * 30,000 = $1,350,000
PQR Direct material cost = $60 * 15,000 = $900,000
w.2: Computation of direct labor cost
Direct labor cost = Direct labor cost per unit * Sales demand
Therefore;
ABC Direct material cost = $30 * 30,000 = $900,000
PQR Direct material cost = $40 * 15,000 = $600,000
w.3: Allocation of production overhead
Production overheads allocated to a model = Production overheads * (Model's Sales Demand / Total Sales demand)
Total Sales demand = 30,000 + 15,000 = 45,000
Therefore, we have:
Production overhead allocated to ABC = $600,000 * (30,000 / 45,000) = $400,000
Production overhead allocated to PQR = $600,000 * (15,000 / 45,000) = $200,000
what is a supplementary angle of 750
Answer:
105°
Step-by-step explanation:
Supplementary angle of 75° = 180° - 75° = 105°
Answer:
105°
Step-by-step explanation:
angle given is 75°
= 180° - 75°
= 105°
A movie theater has a seating capacity of 235. The theater charges $5.00 for children, $7.00 for students, and $12.00 of adults. There are half as many adults as there are children. If the total ticket sales was $ 1704, How many children, students, and adults attended?
Hey there! :)
Answer:
118 children
58 students
59 adults
Step-by-step explanation:
We can solve this problem by setting up a system of equations:
Let a = adults
2a = children (since double the # of adults were children), and
s = students
Set up the equations:
1704 = 5(2a) + 7s + 12(a)
1704 = 10a + 7s + 12a
235 = 2a + a + s
Simplify the equations:
1704 = 22a + 7s
235 = 3a + s
Subtract the bottom equation from the top by multiplying the bottom equation by 7 to eliminate the 's' variable:
1704 = 22a + 7s
7(235 = 3a + s)
1704 = 22a + 7s
1645 = 21a + 7s
---------------------- (Subtract)
59 = a
This is the number of adults. Substitute this number into an equation to solve for the number of students:
235 = 3(59) + s
235 = 177 + s
s = 58.
Since the number of children is equivalent to 2a, solve:
2(59) = 118 children.
Therefore, the values for each group are:
118 children
59 adults
58 students.
Answer:
adults: 59, students:58 and children 118
Step-by-step explanation:
let A for adults, and C = children and S for students
There are half as many adults as there are children=
A=C/2 , C=2A
A+C+S=235 or
A+2A+S=235 first equation
3A+S=235
12A+5C+7S =1704 or
12A+10A+7S=1704
22A + 7S=1704 second equation
3A+S=235 first
solve by addition and elimination
22A+7S=1704
21 A+7S=1645 subtract two equations
A=59 adults
C=2A=2(59)=118
substitute in :A+S+C=235
S=235-(118+59)=58
check: 5C+7S+12A=1704
5(118)+7(58)+12(59)=1704
Now find the product (2+ sqrt 5)(2- sqrt 5). The product is ...
the answer is -1
Answer:
-1
Step-by-step explanation:
Thanks
The product of expression (2 + √5) (2 - √5) is,
⇒ (2 + √5) (2 - √5) = - 1
We have to given that,
An expression to simplify,
⇒ (2 + √5) (2 - √5)
Now, We can simplify it by using formula,
⇒ (a - b) (a + b) = a² - b²
Hence, We get;
⇒ (2 + √5) (2 - √5)
⇒ (2² - √5²)
⇒ 4 - 5
⇒ - 1
Therefore, The product of expression (2 + √5) (2 - √5) is,
⇒ (2 + √5) (2 - √5) = - 1
Learn more about the multiplication visit:
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These two polygons are similar.
Answer:
[tex]\huge\boxed{z=3}[/tex]
Step-by-step explanation:
If two polygons are similar, then corresponding sides are in proportion.
The corresponding sides:
4 → x
y → 15
3 → w
2 → 6
z → 9
therefore:
[tex]\dfrac{z}{9}=\dfrac{2}{6}[/tex] cross multiply
[tex](z)(6)=(9)(2)[/tex]
[tex]6z=18[/tex] divide both sides by 6
[tex]z=3[/tex]
Answer:
Step-by-step explanation: