Answer:
Speed of lighter particle = -21.53 m/s
Speed of other particle = 3.8 m/s
Explanation:
Let mass of the lighter object be m
Thus mass of heavier object = 4m
Speed of lighter particle = 19 m/s
Speed of second particle with opposite direction = - ⅓(19) m/s = -19/3 m/s
Now, from the formulas of momentum before collision = momentum after collision, and also kinetic energy before collision = Kinetic Energy after collision, we have;
v_bf = [2m_a/(m_a + m_b)]v_ai + [(m_b - m_a)/(m_a + m_b)]v_bi
Now, in this question;
m_a = m
m_b = 4m
v_ai = 19
v_bi = -19/3 m/s
Thus;
v_bf = [2m/(m + 4m)]19 + [(4m - m)/(m + 4m)](-19/3)
Simplifying to get;
v_bf = 19(2m/5m) - (19/3)(3m/5m)
>> v_bf = 38/5 - 19/5
>> v_bf = 19/5 m/s
>> v_bf = 3.8 m/s
Similarly;
v_af = [(m_a - m_b)/(m_a + m_b)]v_ai + [2m_b/(m_a + m_b)]v_bi
v_af = 19((m - 4m)/(m + 4m)) - (19/3)((2 × 4m)/(m + 4m))
This gives;
v_af = 19(-3m/5m) - (19/3)(8m/5m)
v_af = -(57/5) - (152/15)
v_af = -323/15
v_af = -21.53 m/s
The following statements are related to the force of a magnetic field on a current-carrying wire. Indicate whether each statement is true or false.
1) The magnetic force on the wire is independent of the direction of the current.
A) True
B) False
2) The force on the wire is directed perpendicular to both the wire and the magnetic field.
A) True
B) False
3) The force takes its largest value when the magnetic field is parallel to the wire.
A) True
B) False
Answer:
1) B: False
2) A: True
3) B: False
Explanation:
1) Statement is false because the force is not independent of the current but rather depends on the direction of the field and current.
2) Statement is true as per right hand thumb rule.
3) The statement is false because force takes its largest value when the magnetic field direction and electric current direction are perpendicular to each other.
A pinball machine uses a spring that is compressed 4.0 cm to launch a
ball. If the spring constant is 13 N/m, what is the force on the ball at the
moment the spring is released?
Answer: 0.52N
Explanation:
Formula
F=ke
Givens
e= 4.0cm>>>0.04m
k=13N/m
Plug givens into formula
F= (13N/m)(0.04m)
F=0.52N
The force on the ball at the moment the spring is released will be F =0.52N
What is a spring force ?When a spring is stretched or compressed , it displaces from equilibrium position . As a result , a restoring force will act ( which act opposite to the direction of force applied on the string ) and tends to retract the spring back to its original position . The force is called spring force
Given
x = 4cm = 0.04 m
spring constant is(k) = 13 N/m
F( spring force on the ball ) = ?
F = -k x
F = -(13)(.04)
F ( spring force) = - 0.52N
The force on the ball at the moment the spring is released will be F =0.52N
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You use 350 W of power to move a 7.0 N object 5 m.
How long did it take?
Answer:
0.1 second
Explanation:
We are given;
Power; P = 350 W
Force; F = 7 N
Distance; d = 5 m
Formula for power is;
P = workdone/time taken
Workdone = F × d
Thus;
350 = (7 × 5)/t
t = 35/350
t = 0.1 second
a toy of mass 600 is whirled by a child in a horizontal circle using a string of length 2m with a linear speed of 5 m/s determine the centripetal force experience by the toy?
there you go, 15N. I hope this helps
A student made the claim that a 4 gram paintball fired from a paintball gun at 90 m/s could have about the same kinetic energy as a 1 gram BB pellet fired from a BB gun at 180 m/s. Do you agree or disagree with the student's claim? Use evidence and mathematical reasoning to support your response.
Answer:
I do agree with the student. Because imagene you have a tissue and a stick. And you throw them at the same speed , the stick will go farther because it' s heavier but the tissue would just blow around and not go forward because it is not heavy enought.
Explanation:
Hope this is correct have a terrific day.
Rebecca was deciding what color to paint her room. She was deciding between sky blue, sea green, or canary yellow. While thinking about which color would be best, she wondered why things had color at all, such as the sky being blue. What makes the sky appear to be blue?
A. Only blue light can pass through the atmosphere without hitting particles.
B. The particles in the atmosphere are naturally blue.
C. Only blue light is absorbed by the particles in the atmosphere.
D. Only blue light is reflected by the particles in the atmosphere.
Answer:D
Explanation:
The reason behind the sky appear to be blue is that only blue light is reflected by the particles in the atmosphere. Hence, option D is correct.
What is Refraction?Refraction is the process by which a wave changes direction while transitioning from one material to another in physics. As an illustration, waves move more quickly in water depths than in shallow.
A wave will loop around till it is moving perpendicular to the beach if it is approaching a beach at such an angle because the wave's outer portion goes quicker than its inner portion. In warm air compared to cold, sound waves move more quickly.
A lake's surface starts to cool at night, and any sound waves which ascend are bent downward by the warmer upper layers of the atmosphere.
Therefore, it concludes that option D is correct.
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An old mining tunnel disappears into a hillside. You would like to know how long the tunnel is, but it's too dangerous to go inside. Recalling your recent physics class, you decide to try setting up standing-wave resonances inside the tunnel. Using your subsonic amplifier and loudspeaker, you find resonances at 5.0 Hz and 6.4 Hz , and at no frequencies between these. It's rather chilly inside the tunnel, so you estimate the sound speed to be 333 m/s .
Answer:
L = 116.6 m
Explanation:
For this exercise we approximate the tunnel as a tube with one end open and the other closed, at the open end there is a belly and at the closed end a node, therefore the resonances occur at
λ = 4L 1st harmonic
λ = 4L / 3 third harmonic
λ = 4L / 5 fifth harmonic
General term
λ = 4L / n n = 1, 3, 5,... odd
n = (2n + 1) n are all integers
They indicate that two consecutive resonant frequencies were found, the speed of the wave is related to the wavelength and its frequency
v = λ f
λ = v / f
we substitute
[tex]\frac{v}{f} = \frac{4L}{n}[/tex]
L = [tex]n \frac{ v}{4f}[/tex]
for the first resonance n = n
L = (2n + 1) [tex]\frac{v}{4f_1}[/tex]
for the second resonance n = n + 1
L = (2n + 3) [tex]\frac{v}{4f_2}[/tex]
we have two equations with two unknowns, let's solve by equating
(2n + 1) \frac{v}{4f_1}= (2n + 3) \frac{v}{4f_2}
(2n + 1) f₂ = (2n +3) f₁
2n + 1 = (2n + 3) [tex]\frac{f_1}{f_2}[/tex]
2n (1 - \frac{f_1}{f_2}) = 3 \frac{f_1}{f_2} -1
we substitute the values
2n (1- [tex]\frac{5}{6.4}[/tex]) = 3 [tex]\frac{5}{6.4}[/tex] -1
2n 0.21875 = 1.34375
n = 1.34375 / 2 0.21875
n = 3
remember that n must be an integer.
We use one of the equations to find the length of the Tunal
L = (2n + 1) \frac{v}{4f_1}
L = (2 3 + 1) [tex]\frac{333}{4 \ 5.0}[/tex]
L = 116.55 m
The idea that John Marshall, the first Chief Justice of the Supreme Court, singularly established the principle of judicial review in Marbury v. Madison(1803)
a. Was an idea created and supported by James Madison and his friend Marbury.b. Is ridiculous because the US Supreme Court had made constitutional rulings well before Marbury v. Madison.c. Was an idea created and supported by Congress.d. Is a well established in the historical record and the papers of John Marshall
Answer:
c. Was an idea created and supported by Congress.
Explanation:
The idea that John Marshall, the first Chief Justice of the Supreme Court, singularly established the principle of judicial review in Marbury v. Madison(1803) was an idea created and supported by Congress.
PLEASE HELP !!!!!
What is the independent variable in the following testable question? Does changing the height of a ramp affect how far a car will travel?
Question 1 options:
the type of car
height of the ramp
how far the car will travel
the type of material the ramp is made out of
Answer:
Height of the ramp
Explanation:
The independent variable is always what the person doing the experiment can change or modify. So if the question is about whether the height of the ramp with effect the car, that is indeed what they are changing or modifying in the experiment.
Equipotential lines are usually shown in a manner similar to topographical contour lines, in which the difference in the value of consecutive lines is constant. Clear the equipotential lines using the Clear button on the voltage tool. Place the first equipotential line 1 m\rm m away from the charge. It should have a value of roughly 9 V\rm V. Now, produce several additional equipotential lines, increasing and decreasing by an interval of 3 V\rm V (e.g., one with 12 V\rm V, one with 15 V\rm V, and one with 6 V\rm V). Don�t worry about getting these exact values. You can be off by a few tenths of a volt.Which statement best describes the distribution of the equipotential lines?1-The equipotential lines are closer together in regions where the electric field is weaker.2-The equipotential lines are closer together in regions where the electric field is stronger.3-The equipotential lines are equally spaced. The distance between each line is the same for all adjacent lines.
Answer:
the correct one is 2. the equipotential lines must be closer together where the field has more intensity
Explanation:
The equipotential line concept is a line or surface where a test charge can move without doing work, therefore the potential in this line is constant and they are perpendicular to the electric field lines.
In this exercise we have a charge and a series of equipotential lines, if this is a point charge the lines are circles around the charge, where the potential is given by
V = k q / r
also the electric field and the electuary potential are related
E = [tex]- \frac{dV}{dr}[/tex]
therefore the equipotential lines must be closer together where the field has more intensity
When checking the answers, the correct one is 2
An angry physics student releases a wrecking ball as shown. The wrecking ball is just about to hit the building at the final time. Neglect loss. Identify the energy types present at each time for the highlighted object or system relative to the reference
level shown. Also identify if loss occurs and/or work is done by a non-conservative force between each time
(if necessary).
Answer:
the force between the building and the ball is non-conservative (friction-type force)
Explanation
Explanation:For this exercise the student must create an impulse to move the ball towards the building, in this part he performs positive work since the applied force and the displacement are in the same direction.
When the ball moves it has a kinetic energy and if its height increases or decreases its potential energy also changes, but the sum of being must be equal to the initial work.
When the ball arrives and collides with the building, non-conservative forces, of various kinds; rubbing, breaking, etc. It transforms this energy into a part of heat and another in mechanical energy that the building must absorb, let us destroy its wall
Consequently, the force between the building and the ball is non-conservative (friction-type force
A wave has a wavelength of 1.5 meters and frequency of 125 Hz. What is the wave speed?
g A 4-foot spring is elongated167feet long after a mass weighing 16 pounds is attached to it. The medium throughwhich the mass moves offers a damping force numerically equivalent to92times the instantaneous velocity.(a) Find the equation of motion if the mass is initially released from the equilibrium position with a downwardvelocity of 2 ft/s. (Use the convention that displacements measured below the equilibrium position are positive).(b) What is the velocity of the mass whent
Answer: hello question b is incomplete attached below is the missing question
a) attached below
b) V = 0.336 ft/s
Explanation:
Elongation ( Xo) = 16/ 7 feet
mass attached to 4-foot spring = 16 pounds
medium has 9/2 times instanteous velocity
a) Find the equation of motion if the mass is initially released from the equilibrium position with a downward velocity of 2 ft/s
The motion is an underdamped motion because the value of β < Wo
Wo = 3.741 s^-1
attached below is a detailed solution of the question
. An object 8.5 cm high is placed 28 cm from a converging lens. The focal length of the lens is 12 cm. Calculate the image distance, di. Calculate the image height, hi.
The converging lens is also called a concave lens. The height of the image formed by the lens is 2.55 cm.
Using the lens formula;
1/f = 1/u + 1/v
f = focal length of the lens
u = object distance
v = image distance
Note that the focal length of a converging lens is positive
Substituting values;
1/12 = 1/28 + 1/v
1/v = 1/12 - 1/28
v = 8.4 cm
Magnification= image height/object height = image distance/object distance
image height = ?
object height = 8.5 cm
image distance = 8.4 cm
object distance = 28 cm
So
image height/8.5 = 8.4/28
image height = 8.5 × 8.4/28
image height = 2.55 cm
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What is a target ceiling ?
Answer:
Target ceiling. the upper limit of your physical activity. Target fitness zone. Above the threshold of training and below the target ceiling.
Hope this helps. Can u give me brainliest
Explanation:
Which waves can be seen by people?
O radio waves
O microwaves
O visible light waves
O gamma rays
Answer:
Visible light waves
Explanation:
A wet towel spread out and hung outside on a day without wind dries faster than an identical wet towel left rolled up in a plastic bag.
Explain why.
Even without wind the sun help evaporate the water so it would dry faster. The other towel is in a bag so the moist and water has nowhere to go, therefor staying in the towel.
22. What force is necessary to accelerate a 2500kg car from rest to 20m/s over 10s?
(6 Points)
2N
250N
5000N
50000N
Answer:
50000N
Explanation:
Force = mass × acceleration
= 2500 × 20
= 50000N
PLEASE HELP ME I WILL GIVE BRAINLY
Select five short rope exercises and describe how they are done.
Answer:
Jumping battle slams - just move the rope up and down
Alternating jump wave - jump and move the rope side to side
Alternating wide circles - move the rope in a circle position
Jumping jacks
Squat to sholder
Explanation:
The guy above me is correct give him Brainliest
Please help! Due in 5 min! I will pick brainiest! Thanks! YOU ROCK!
The resistance of an electric stove burner element is 11 ohms. What current flows through this
element when it runs off a 220 volt line?
Answer:
Current flow I = 20 ampere
Explanation:
Given:
Resistance R = 11 ohms
Voltage V = 220 volts
Find:
Current flow I
Computation:
Current flow I = V / R
Current flow I = 220 / 11
Current flow I = 20 ampere
The amount of current flow through the element is of 20 A.
Given data:
The magnitude of resistance of Electric stove is, R = 11 ohms.
The magnitude of potential difference in a line is, V' = 220 V.
Here we can simple go for Ohm's law. As per the Ohm's law, the potential difference across the element is proportional to the current flow and the resistance of the element.
The expression is,
V' = I × R
here, I is the amount of current flowing through the element.
Solving as,
220 = I × 11
I = 20 A
Thus, we can conclude that the amount of current flow through the element is of 20 A.
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12. An organ pipe that is 1.75 m long and open at both ends produces sound of
frequency 303 Hz when resonating in its second overtone. What is the speed of
sound in the room?
295 m/s
328 m/s
354 m/s
389 m/s
401 m/s
Answer:
354 m/s
Explanation:
For the second overtune (Third harmonic) of an open pipe,
λ = 2L/3................................ Equation 1
Where L = Length of the open pipe, λ = Wave length.
Given: L = 1.75 m.
Substitute into equation 1
λ = 2(1.75)/3
λ = 1.17 m.
From the question,
V = λf.......................... Equation 2
V = speed of sound in the room, f = frequency
Given: f = 303 Hz.
Substitute into equation 2
V = 1.17(303)
V = 353.5
V ≈ 354 m/s
Hence the right answer is 354 m/s
This is one popular brand of exercise machine for a crossword puzzle
Answer:
Aerobics I think.
Explanation:
A 5kg object accelerates from 3m/s to 7m/s in 5 seconds. Calculate the force required
to provide this acceleration.
Answer:
4N
Explanation:
a = (7-3)/5 = 0.8m/s^2
F = ma = (5)(0.8) = 4 Newtons
What is the kinetic energy of a 10kg object that is moving with a speed of 60m/s.
The answer is 18000 J
I hope this helps!^^ , if you need the work to be shown please tell me, I hope you have a great day!^^
A plane takes off at St. Louis, flies straight to Denver, and then returns the same way. The plane flies at the same speed with respect to the ground during the entire flight, and there are no head winds or tail winds. Since the earth revolves around its axis once a day, you might expect that the times for the outbound trip and the return trip differ, depending on whether the plane flies against the earth's rotation or with it. Is this expectation true or false
Answer:
In the Both time
Explanation:
A plane takes off at St.Louis, flies straight to Denver, and then returns the same way. The plane flies at the same speed with respect to the ground during ...
Depending on whether the plane flies against the earth's rotation or with it. Is this expectation is true statement.
What is Plane?Physical quantities such as work, temperature, and distance can all be completely represented in daily life by their magnitude. The laws of arithmetic can, however, be used to explain how these physical values relate to one another.
Motion in two dimensions is another name for motion in a plane. For instance, a projectile moving in a circle. The origin, along with the two coordinate axes X and Y, will serve as the reference point for the investigation of this kind of motion.
Therefore, Depending on whether the plane flies against the earth's rotation or with it. Is this expectation is true statement.
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A single-phase 60-Hz overhead power line is symmetrically supported on a horizontal cross arm. Spacing between the centers of the conductors acing between the centers of the conductors (say, a and b) is 2.5 m. A telephone line is also symmetrically supported on a horizontal cross arm 1.8 m directly below the power line. Spacing between the centers of these conductors (say, c and d) is 1.0 m.
4 x 10^7 ln âDad. Dln/Dnk. Dtet
where, for example, Dud denotes the distance in meters between conductors a and.
a. Hence, compute the mutual inductance per kilometer between the power line and the telephone line.
b. Find the GO-Hz voltage per kilometer induced in the telephone line when the power line carries 150 A.
Complete question is;
A single-phase 60-Hz overhead power line is symmetrically supported on a horizontal cross arm. Spacing between the centers of the conductors acing between the centers of the conductors (say, a and b) is 2.5 m. A telephone line is also symmetrically supported on a horizontal cross arm 1.8 m directly below the power line. Spacing between the centers of these conductors (say, c and d) is 1.0 m.
The mutual inductance per unit length between circuit a-b and circuit c-d is given as 4 x 10^(-7) ln √((D_ad × D_bc)/(D_ac × D_bd)) H/m
where, for example, D_ad denotes the distance in meters between conductors a and d.
a. Hence, compute the mutual inductance per kilometer between the power line and the telephone line.
b. Find the 60-Hz voltage per kilometer induced in the telephone line when the power line carries 150 A
Answer:
A) M = 1.01 × 10^(-4) H/km
B) v_cd = 5.712 V/km
Explanation:
A) From the distances given in the question, we can deduce that;
D_ac = √(((2.5/2) - (1/2))² + 1.8²)
D_ac = 1.95 m
Also;
D_ad = √(((2.5/2) + (1/2))² + 1.8²)
D_ad = 2.51 m
I_a and I_b are put of phase by 180°. Thus, due to a and b, the flux linkages to c and d is given as;
φ_cd = 4 x 10^(-7)I_a( ln (2.51/1.95))
Mutual inductance per km is given as;
M = φ_cd/I_a
Thus;
M = 4 x 10^(-7)( ln (2.51/1.95))
M = 1.01 × 10^(-7) H/m
Per km;
M = 1.01 × 10^(-7) × 1000
M = 1.01 × 10^(-4) H/km
B) voltage per km is gotten by;
v_cd = ωMI
Now, ω = 2πf = 2π × 60 = 377 rad/s
Thus;
v_cd = 377 × 1.01 × 10^(-4) × 150
v_cd = 5.712 V/km
what is the quantum and its types?
Answer:
It is the physics that explains how everything works, the nature of the particles that make up matter and the forces with which they interact.
Its types: Electromagnetism, the strong nuclear force, and the weak nuclear force.
Hope this help :)
a ford explorer traveled 100 miles the next day for 5 hours. What was the average speed of this vehicle?
Answer:
25 miles per hour
Explanation:
It was 20 miles per hour the next day. We don't have enough information to calculate the average speed for the whole trip.
A truck moving at 6.0 m/s applies the brakes and stops after skidding 12.0 m.
(a) Find the uniform deceleration. (20 pts)
(b) Find the time it takes for the truck to stop. (20 pts)
Answer:
a) a= -1.5 m/s²
b) t = 4.0 s
Explanation:
a)
Since we are told that the deceleration is uniform, we can use the following kinematic equation:[tex]v_{f} ^{2} - v_{o} ^{2} = 2*a*\Delta X (1)[/tex]
Since the truck finally stops, this means that vf = 0.Replacing the values of v₀, and Δx in (1), we can solve for a, as follows:[tex]a =\frac{-(v_{o}^{2})}{2*\Delta X} = \frac{-(6.0m/s)^{2} }{2* 12.0m} = -1.5 m/s2 (2)[/tex]
b)
Since we know the value of the initial and final velocity, and the value of the acceleration also, we can apply the definition of acceleration, solving for time t, as follows:[tex]\Delta t = \frac{-v_{o}}{a} = \frac{-6.0m/s}{-1.5m/s2} = 4.0 s (2)[/tex]
Suppose that you'd like to find out if a distant star is moving relative to the earth. The star is much too far away to detect any change in its brightness as it moves toward or away from the earth. Instead we can use the Doppler effect to determine its relative speed. For this problem we are going to look at the spectral lines from hydrogen, specifically the one with a wavelength of 656.46 nm.
The hydrogen atoms in a star are also moving at high velocity because of the random motions caused by their high temperature. As a result, each atom is Doppler shifted a little bit differently, leading to a finite width of each spectral line, such as the 656.46-nm line we were just discussing. For a star like our sun, this leads to a finite width of the spectral lines of roughly Δλ=0.04nm.
If our instruments can only resolve to this accuracy, what is the lowest speed V, greater than 0, that we can measure a star to be moving?
Answer:
The answer is "[tex]\bold{18 \ \frac{km}{s}}[/tex]"
Explanation:
Its concern is not whether star speed is significantly lower than the light speed. Taking into consideration the relativistic tempo (small speed star)
[tex]\to \frac{\Delta \lambda}{\lambda} = \frac{v}{c}\\\\\to v = \frac{\Delta \lambda}{\lambda} \left (c \right ) \\\\[/tex]
[tex]= \left ( \frac{0.04}{656.46} \right ) (3 \times 10^8)\\\\ = 18280 \ \frac{m}{s} \approx 18 \ \frac{km}{s}[/tex]